the figure show, the length between P and T and the length between T and Q, are equal.
so we can say PT=TQ
PT= 3x+2 and TQ=5x-6
so we can replace:
3x+2=5x-6
now we solve
2+6=5x-3x
8=2x
8/2=x=4
and finally, to find PT we replace x by 4
PT=3*4+2=14
So the answer is: PT=14
Compare A and B in three ways, where A = 51527 is the number of deaths due to a deadly disease in the United States in 2005 and B = 17241 is the number of deaths due to the same disease in the United States in 2009. a. Find the ratio of A to B. b. Find the ratio of B to A. c. Complete the sentence: A is ____ percent of B.
ANSWER
Ratio of A to B = 2.99 (to 2 decimal places)
Ratio of B to A = 0.33 (to 2 decimal places)
A is 299% of B (to nearest integer)
STEP BY STEP EXPLANATION
for ratio of A to B:
[tex]\begin{gathered} \frac{A}{B}\text{ = }\frac{51527}{17241}\text{ = }2.98863 \\ \text{ = 2.99 (to 2 decimal places)} \end{gathered}[/tex]for ratio of B to A:
[tex]\begin{gathered} \frac{B}{A}\text{ = }\frac{17241}{51527}\text{ = 0.33460 } \\ \text{ = 0.33 (to 2 decimal places)} \end{gathered}[/tex]A is x % of B:
[tex]\begin{gathered} A\text{ = }\frac{x}{100}\times B \\ x\text{ = }\frac{100\text{ }\times A}{B} \\ x\text{ = }\frac{100\text{ }\times\text{ 51527}}{17241}\text{ = 298.86} \\ x\text{ = 299\% (to nearest integer)} \end{gathered}[/tex]Hence, the ratio of A to B = 2.99 (to 2 decimal places), B to A = 0.33 (to 2 decimal places) and A is 299% of B (to nearest integer).
what is the effect on the graph of the function f(x) = x² when f(x) is changed to f(x + 8) ?A) shifted up B) shifted left C) shifted right D) shifted down
Solution
- In order to solve the question, we need to understand the rules guiding the translation of graphs. This rule is given below:
[tex]\begin{gathered} f(x)\to f(x+h) \\ \text{ If h is positive, then, the graph is shifted to the left} \\ \text{ If h is negative, then, the graph is shifted to the right} \end{gathered}[/tex]- The question given to us has h = 8. This means that h is positive, therefore, the graph of f(x) must be shifted to the left by 8 units
Final Answer
The answer is "Shifted Left" (OPTION B)
12.Work backwards to write a quadratic equation that will have solutions of x = -1/2 and x = 4. (Your equation must only have integer coefficients, meaning no fractions or decimals.)
In general, a quadratic equation can be written in terms of its solutions:
[tex]y=(x-a)(x-b).[/tex]Now, notice that:
[tex]x+\frac{1}{2}=0\text{ }[/tex]when x= -1/2, and it is equivalent to:
[tex]2x+1=0.[/tex]Therefore, you can write the quadratic equation as:
[tex]y=(2x+1)(x-4).[/tex]Computing the above multiplication, you get:
[tex]y=2x^2-8x+x-4.[/tex]Simplifying the above equation you get:
[tex]y=2x^2-7x-4.[/tex]Answer: [tex]y=2x^{2}-7x-4[/tex]80% of _ = 20?4-4-4-
Let
x -----> the missing number
we know that
80%=80/100=0.80
so
0.80x=20
solve the linear equation for x
Divide by 0.80 both sides
x=20/0.80
x=25
the answer is 25
diameter = 10.5in.we are learning something about area of circle.
Use the formula for the area of a circle:
[tex]A=\pi\cdot r^2[/tex]First, we need to find the radius r. Since the radius is half the diameter, then:
[tex]\begin{gathered} r=\frac{10.5\text{ in}}{2} \\ \therefore r=5.25in \end{gathered}[/tex]Substitute the value for r in the formula for the area of the circle:
[tex]\begin{gathered} A=\pi\cdot(5.25in)^2 \\ \approx86.6in^2 \end{gathered}[/tex]Therefore, the area of a circle of diameter 10.5 in is approximately 86.6 squared inches.
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BRAINLIEST!!!!! AND 100 POINTS!!!
See if anybody can answer this. A concession stand sells lemonade for $2 each and sports drinks for $3 each. The concession stand sells 54 cups of lemonade and sport drinks. The total money collected for these items is $204. How much money was collected on sports drinks?
you own a pet store that sells fish tank you brought a fish tank for $35 and are going to mark it up 20% what is the selling price going to be on the fish tank
If you're marking the fish tank up by 20%, it means you're looking to sell it at 120% of its original value.
Now, let's use a rule of three to calculate such percentage:
Thereby,
[tex]x=\frac{120\cdot35}{100}\rightarrow x=42[/tex]The selling price would be $42
Write a relation consisting of five ordered pairs that satisfies the following conditions. The relation is a function. Switching the x- and y-coordinates of each ordered pair results in a relation that is not a function.
Answer:
Step-by-step explanation:
If each value of x only has one corresponding value of y, it is a function. You can test this just by eye or by graphing and doing the vertical line test by rolling a pencil or other straight object across to make sure only one point is on the line at a time
8. A boy owns 6 pairs of pants, 8 shirts, 2 ties, and 3 jackets. How many outfits can he wear to school if he must wear one of each item?
It is given that the boy owns 6 pairs of pants, 8 shirts, 2 ties, and 3 jackets.
It is also given that he must wear one of each item.
Recall the Fundamental Counting Principle:
The same is valid for any number of events following after each other.
Hence, the number of different outfits he can wear by the counting principle is:
[tex]6\times8\times2\times3[/tex]Evaluate the product:
[tex]6\times8\times2\times3=288[/tex]The number of different outfits he can wear is 288.
The diameter of circle is 20 inches. find the circumference in terms of pi
The below formula is used to find the circumference of a circle;
[tex]C=2\pi r[/tex]But we know that the diameter of a circle is expressed as;
[tex]d=2r[/tex]Let's replace 2r with d in the 1st equation, we'll then have;
[tex]C=\pi d[/tex]We've been told that the diameter of the circle is 20inches, if we substitute this value into our equation, we'll have;
[tex]C=20\pi[/tex]I got the last question right that was similar so I’m unsure what I’m doing wrong for this one
Solve x:
[tex][/tex]The highly temperature one day was -3 the low temperature was -7 what was the difference
Solve 2/3 (6w+12) this equation
Answer:
4w+8
Step-by-step explanation:
x + y = 5 y - 2x = -4
x = 3, y = 2
Explanations:The equations are:
x + y = 5......................(1)
y - 2x = -4...................(2)
Make x the subject of the the formula
x = 5 - y...............(3)
Substitute equation (3) into equation (2)
y - 2(5 - y) = -4
y - 10 + 2y = -4
3y = -4 + 10
3y = 6
y = 6 / 3
y = 2
Substitute the value of y into equation (3)
x = 5 - 2
x = 3
What is 175% of 48? Show work.
Let 175% of 48 be y.
This implies that
[tex]\frac{175}{100}\times48=y[/tex]To evaluate y,
[tex]\begin{gathered} \frac{175}{100}\times48=y \\ \Rightarrow\frac{175\times48}{100}=y \\ \frac{8400}{100}=y \\ \Rightarrow y=84 \end{gathered}[/tex]Hence, 175% of 48 is 84.
3. Trapezoid JKLM with vertices J(-4, 3), K(-2, 7),L(2,7), and M(3, 3) in the line y = 1.what would the reflection coordinates be
First, we graph the trapezoid and the line
If we reflect the figure across the line y = 1, then we get the following figure
As you can observe in the graph, the vertices would be J'(-4,-1), K'(-2,-5), L'(2,-5), and M'(3,-1).
Conner plans to plow a field in one day. Before lunch he plows 15 acres, which is 30% of the field. Howmany acres will he have to plow after lunch in order to finish the field?
Solution:
Let the total field to plow be 100 %
According to the question,
The field plowed before lunch is shown below:
15 acres field = 30%
30 % field = 15 acres
1 % field = 15/30 acres
The field plow after lunch is 70%.
[tex]\begin{gathered} 70\text{ \% of field = }\frac{15}{30}\times70 \\ =35\text{ acres} \end{gathered}[/tex]Final Answer:
Therefore, the field to plow after lunch in order to finish the field is 35 acres.
Help on math question precalculus ChoicesVertical shift Period DomainRange Phase shift Amplitude
All the x-values that satisfy the function - Domain
Translating the sine or cosine curve up or down - Vertical shift
How long a given function takes to repeat itself - Period.
A horizontal shift of a sine or cosine function- Phase shift
All the y-values that satisfy the function- Range
Distance from the horizontal axis or midline to the maximum and minimum points - Amplitude
Is x = -2 the linear equation that matches this table of ordered pairs?Explain why or why not.Xy-2 7-2 1-2 -5(x, y)(-2,7)(-2, 1)(-2,-5)
Answer:
All the points given (-2,7) (-2,1) (-2,-5) have the x-coordinate of -2, then those points lie in the x=-2, so it matches the table.
L Pretest: Unit 2Question 5 of 21Which of the following represents the factorization of the polynomial functiongraphed below? (Assume it has no constant factor.)55
1) The best way to tackle questions like this is to locate the x-intercepts. Since according to the options the leading coefficient is 1, we just need to locate the zeroes and plug them into the quadratic equation form, in its factored form.
2) So now, let's write out the factored form and plug the zeroes into them:
[tex]\begin{gathered} y=a(x-x_1)(x-x_2) \\ y=1(x-1)(x-3) \\ y=(x-1)(x-3) \end{gathered}[/tex]find the slope of #1 y = 2x - 3#2 (-2,-4) (-1,-2)#3 y = 1/3x - 4# 4 (4,0) (4,1)
1. slope= 2
2. slope=2
3. slope= 1/3
4. slope indefinite, vertical line
Explanation
Step 1
[tex]\begin{gathered} y=\text{ 2x-3} \\ \end{gathered}[/tex]the equation is given in slope(m) - intercept(b)
[tex]\begin{gathered} y=\text{ mx+b} \\ \text{then} \\ mx+b=2x-3 \\ m=2 \\ \text{slope}=2 \end{gathered}[/tex]Step 2
when you have two points of a line, P1 and P2 the slope is given by:
[tex]\begin{gathered} \text{slope}=\frac{y_2-y_1}{x_2-x_1} \\ \text{where} \\ P1(x_1,y_1)andP2(x_2,y_2) \end{gathered}[/tex]Let
P1(-2,-4) P2(-1,-2)
replace
[tex]\begin{gathered} \text{slope}=\frac{y_2-y_1}{x_2-x_1} \\ \text{slope}=\frac{-2-(-4)}{-1-(-2)} \\ \text{slope}=\frac{-2+4}{-1+2}=\frac{2}{1}=2 \\ \text{slope}=2 \end{gathered}[/tex]Step 3
[tex]y=\frac{1}{3}x-4[/tex]similar to the #1. ,the equation is given in slope(m) - intercept(b)
[tex]\text{the slope = }\frac{1}{3}[/tex]Step 4
let
[tex]P1(4,0)\text{ and P2(4,1)}[/tex][tex]\begin{gathered} \text{slope}=\frac{y_2-y_1}{x_2-x_1} \\ \text{slope}=\frac{1-0}{4-4}=\frac{1}{0}=\text{indefined} \\ it\text{ means the line is vertical} \end{gathered}[/tex]Sara spent 35 minutes on math homework and 20 minutes on reading homework. Mia spent a total of 40
minutes on reading and math homework. How much longer did Sara spend on her homework than Mia?
Sara spent 15 minutes longer than (the difference is 15 min) Mia in her homework.
According to the question,
We have the following information:
Sara spent 35 minutes on math homework and 20 minutes on reading homework. Mia spent a total of 40 minutes on reading and math homework.
So, it means that the total time spent by Sara in her homework is:
35+20 minutes
55 minutes
So, the differences between their time spent in her homework (will give us the more time taken by Sara) is:
Time spent by Sara in her homework-time spent by Mia in her homework
(55-40) minutes
15 minutes
Hence, Sara spent 15 more minutes than Mia.
To know more about difference here
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The answer is 57.3 provided by my teacher, I need help with the work
Apply the angles sum property in the triangle ABC,
[tex]62+90+\angle ACB=180\Rightarrow\angle ACB=180-152=28^{}[/tex]Similarly, apply the angles sum property in triangle BCD,
[tex]20+90+\angle BCD=180\Rightarrow\angle BCD=180-110=70[/tex]From triangle ABC,
[tex]BC=AC\sin 62=30\sin 62\approx26.5[/tex]From triangle BDC,
[tex]BD=BC\cos 20=26.5\cos 20\approx24.9[/tex]Now, consider that,
[tex]\angle BDE+\angle BDC=180\Rightarrow\angle BDE+90=180\Rightarrow\angle BDE=90[/tex]So the triangle BDE is also a right triangle, and the trigonometric ratios are applicable.
Solve for 'x' as,
[tex]x=\tan ^{-1}(\frac{BD}{DE})=\tan ^{-1}(\frac{24.9}{16})=57.2764\approx57.3[/tex]Thus, the value of the angle 'x' is 57.3 degrees approximately.ang
Faith borrowed $2250 for home repairs. She paid back 24 payments of$132 each. How much did she pay in interest on the loan?a. $87.71b. $2,520c. $918d. $4.38
• We are given that Faith paid $132 for 24 months.
So; 132 * 24 = $3168
• Since we know that Faith initially borrowed $2250
Interest paid = $3168 - $2250
= $918
• Option C is the correct choice.
If f (x)- VX-3, complete the following statement:x + 219) =
Given that;
[tex]f(x)=\frac{3}{x+2}-\sqrt{x-3}[/tex]To get f(19), let's substitute 19 for x in the function f(x);
[tex]\begin{gathered} f(x)=\frac{3}{x+2}-\sqrt{x-3} \\ f(19)=\frac{3}{19+2}-\sqrt{19-3} \\ f(19)=\frac{3}{21}-\sqrt{16} \\ f(19)=\frac{1}{7}-4 \\ f(19)=-3\frac{6}{7} \end{gathered}[/tex]Therefore, the value of f(19) is;
[tex]f(19)=-3\frac{6}{7}[/tex]JUIVE Suppose that the amount in grams of a radioactive substance present at time t (in years) is given by A(t) = 800e 0.86t. Find the rate of change of the quantity present at the time when t = 5. 9.3 grams per year 0 -72.7 grams per year -9.3 grams per year 0 72.7 grams per year
In this case, we'll have to carry out several steps to find the solution.
Step 01:
Data
A(t) = 800e^(-0.86t)
Step 02:
Rate of change
t1 = 0
A(t) = 800e^(-0.86t)
A(t) = 800e^(-0.86*0)
A(0) = 800
t2 = 5
A(t) = 800e^(-0.86t)
A(t) = 800e^(-0.86*5)
A (t) = 800e^(-4.3)
A(5) = 10.85
Step 03:
[tex]\frac{\Delta y}{\Delta x}=\frac{A(5)\text{ - A(0)}}{5-0}[/tex][tex]\frac{\Delta y}{\Delta x}=\frac{10.85-800}{5-0}=\frac{-789.15}{5}=-157.83[/tex]If a girl has 7 skirts, 9 shirts, and 5 pairs of shoes, how many outfits canshe wear?
Okay, here we have a Combination Problem, we need just multiply to get the answer, of this mode:
[tex]C=7\cdot9\cdot5=315[/tex]She can wear 315 outfits.
For which pair of triangles would you use ASA to prove the congruence of the two triangles?
Solution:
Remember that the Angle-Side-Angle Postulate (ASA) states that if two angles and the included side of one triangle are congruent to two angles and the included side of another triangle, then the two triangles are congruent. According to this, the correct answer is:
C.
The following distribution represents the number of credit cards that customers of a bank have. Find the mean number of credit cards.Number of cards X01234Probability P(X)0.140.40.210.160.09
To solve this problem we have a formula at hand: the mean (m) number of credits cards is
[tex]m=\sum ^{}_XX\cdot P(X)[/tex]Then,
[tex]m=0\cdot0.14+1\cdot0.4+2\cdot0.21+3\cdot0.16+4\cdot0.09=1.66[/tex]