Using the priority list T1, T6, T2, T7, T8, T5, T4, T3, Tg, schedule the project below with two processors.Tasks that must be completed firstTime Required34TaskT1T2T3T4T5T6T7T8T9423481111T1, T2T2T2, T3T4, T5T5, T6T6Task 6 is done by Select an answer starting at timeTask 8 is done by Select an answer starting at timeThe finishing time for the schedule is

Answers

Answer 1

Firstly, let's make a diagram of prerequisites:

Comment: The number within parenthesis denotes the time required to complete the corresponding task.

Now, let's make our schedule based upon the priority list:

[tex]T_1,T_6,T_2,T_7,T_8,T_5,T_4,T_3,T_9[/tex]

First, we need to know which are the ready tasks (tasks without prerequisites). By the diagram is clear that they are T_1, T_2, and T_3. Then, we need to look at their priority in the priority list. Between them, T_1 has the greatest urgency; this implies that it must be the first in processor 1 (P1). Now, in terms of urgency, T_2 follows T_1; let's assign it to the second processor (P2).

Comment: In the priority list, T_6 is before T_2, but we can't assign it now for it has prerequisites that have not been completed.

After three seconds, the first processor will be free. Let's check the (new) ready tasks having completed T_1. Note that T_1 doesn't unlock any task by itself. Then, the unique ready task now is T_3; let's assign it to the first processor. By similar reasoning, after four seconds the second processor will be free, and we're going to assign T_5 to it... AND SO ON.

I'm going to finish the schedule following these reasonings, and after that, we're going to discuss the answer to the questions.

Using The Priority List T1, T6, T2, T7, T8, T5, T4, T3, Tg, Schedule The Project Below With Two Processors.Tasks
Using The Priority List T1, T6, T2, T7, T8, T5, T4, T3, Tg, Schedule The Project Below With Two Processors.Tasks

Related Questions

1
Pratap Puri rowed 26 miles down a river in 2 hours, but the return trip took him 6; hours. Find the rate Pratap can row
in still water and find the rate of the current. Let x=rate Pratap can row in still water and y = rate of the current.
What is the rate that Pratap rows in still water?
Pratap can row at a rate of
(Type an integer or a decimal.)
in still water.

Answers

The speed of current will be "4.5 mph" and the rate Pratap can row in still water will be "8.5 mph".

What does "speed" mean in mathematics?

Speed is what it means. the speed of a change in an object's location in any direction. Speed is defined as the ratio of distance to the amount of time it took to cover that distance. Speed is a scalar quantity because it just has a direction and no magnitude.

Given:

Distance "26 miles" in time "2 hours".

Let,

Speed of water = y

Pratap speed when rowing in still water = x

As we know,

      Speed = distance/time

then,

  x + y = 26/2

  x + y = 13

 x = 13 - y

In return trip took him time "6.5 hours",

       x - y = 26/6.5

      x - y = 4

By substituting the value of "x", we get

 13 - y - y = 4

  13 - 2y = 4

     2y = 13 - 4

        2y = 9

          y = 9/4 = 4.5 mph (Rate of the current)

By substituting the value of "y", we get

    x = 13 - a

   x = 13 - 4. 5 = 8.5 mph (Pratap can row in still water)

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what is the surface area of the rectangular prism? 1.8 ft 2/5 ft 1/2 ft

Answers

Each face of a rectangular prism has a rectangle shape. To calculate the surface area we need to calculate the area of all the faces. Each face appears twice on the prism, on opposite sides so we only need to make three calculations. These are done using the formulas below:

[tex]\begin{gathered} A_1=height\cdot width_{} \\ A_2=length\cdot width_{} \\ A_3=length\cdot height_{} \end{gathered}[/tex]

Using the data from the problem we can calculate these areas.

[tex]\begin{gathered} A_1=\text{ 1.8}\cdot\frac{2}{5}=0.72\text{ square ft} \\ A_2=\frac{1}{2}\cdot\frac{2}{5}=0.2\text{ square ft} \\ A_3=1.8\cdot\frac{1}{2}=0.9\text{ square ft} \end{gathered}[/tex]

The surface area of the prism is the sum of the areas above multiplied by two.

[tex]\begin{gathered} A_{\text{surface}}=2\cdot(A_1+A_2+A_3) \\ A_{\text{surface}}=2\cdot(0.72+0.2+0.9)=2\cdot1.82=3.64\text{ square ft} \end{gathered}[/tex]


Use any strategy to determine a combination of apples

and pineapples that will balance the scale.
Explain how you know it will balance.

Answers

1 Pine- apple equal to 9 Apples.

What is Ratio proportion?

The divisional comparison of two quantities yields a ratio, and the equality of two ratios yields a proportion.

A ratio is commonly written as "x: y," though it can also be read as "x is to y" or "x/y."

In terms of comparison, a proportional equation says that two ratios are equal.

When x: y: z: w is used to represent a ratio, it is understood to mean that x is to y as z is to w.

In this case, w and Y are not equal to 0, therefore x/y Equals z/w.

6 Apples = 4 Pomegranates

6 Pomegranates = 1 Pine- apple

1 Pine- apple = 9 Apples.

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Write an exponential function in the form y = ab that goes through points (0,18) and (3,6174).

Answers

Using the first point given in the statement you can find a, like this

[tex]\begin{gathered} y=ab^x \\ \text{ Replace x = 0 and y = 18} \\ 18=ab^0 \\ 18=a\cdot1 \\ 18=a \end{gathered}[/tex]

Now, since you already have the value of a, you can find the value of b using the second point, like this

[tex]\begin{gathered} y=ab^x \\ \text{ Replace x = 3 and y = 6174} \\ 6174=18\cdot b^3 \\ \text{ Divide by 18 into both sides of the equation} \\ \frac{6174}{18}=\frac{18\cdot b^3}{18} \\ 343=b^3 \\ \text{ Apply cube root to both sides of the equation} \\ \sqrt[3]{343}=\sqrt[3]{b^3} \\ 7=b \end{gathered}[/tex]

Therefore, the exponential function that passes through the points (0,18) and (3,6174) is

[tex]y=18\cdot7^x[/tex]

u(x) = 4x - 2 w(x) = - 5x + 3The functions u and w are defined as follows.Find the value of u(w(- 3)) .

Answers

Solution

- We are given the two functions below:

[tex]\begin{gathered} u(x)=4x-2 \\ \\ w(x)=-5x+3 \end{gathered}[/tex]

- We are asked to find u(w(-3)).

- In order to find u(w(-3)), we need to first find u(w(x)) and then we can substitute x = -3.

- Since we have been given u(x), then, it means that we can find u(w) as follows:

[tex]\begin{gathered} u(x)=4x-2 \\ u(w),\text{ can be gotten by substituting w for x} \\ \\ u(w)=4w-2 \end{gathered}[/tex]

- But we have an expression for w in terms of x. This means that we can say:

[tex]\begin{gathered} u(w)=4w-2 \\ \\ w(x)=-5x+3 \\ \\ \therefore u(w(x))=4(-5x+3)-2 \\ \\ u(w(x))=-20x+12-2 \\ \\ \therefore u(w(x))=-20x+10 \end{gathered}[/tex]

- Now that we have an expression for u(w(x)), we can proceed to find u(w(-3)) as follows:

[tex]\begin{gathered} u(w(x))=-20x+10 \\ put\text{ }x=-3 \\ \\ u(w(-3))=-20(-3)+10 \\ \\ u(w(-3))=60+10=70 \end{gathered}[/tex]

Final Answer

The answer is

[tex]u(w(-3))=70[/tex]

38. A right rectangular prism has a volume of 5 cubic meters. The length ofthe rectangular prism is 8 meters, and the width of the rectangular prismis a meter.What is the height, in meters, of the prism?Niu4© 30 10

Answers

It's important to know that the volume formula for a rectangular prism is

[tex]V=l\cdot w\cdot h[/tex]

Where V = 5, l = 8, and w = 1. Let's use these values and find h

[tex]\begin{gathered} 5m^3=8m\cdot1m\cdot h \\ h=\frac{5m^3}{8m^2} \\ h=0.625m \end{gathered}[/tex]Hence, the height of the prism is 0.625 meters.

The bank requires that customers select a PIN (personal identification number) so ATM’s can be accessed. The PIN must be 3 digits followed by one letter. How many different PIN numbers can be selected if the first digit cannot be zero?

Answers

Answer:

A lot

Step-by-step explanation:

use random numbers from 1 to 9 and or 0, after the first natural number. And different letters, so there is no specific amount to say that can be used.

f (x+2) - 3o vertical shiftvertical stretchhorizontal reflectionhorizontal shiftvertical compressionhorizontal stretchhorizontal compressionvertical reflection

Answers

ANSWER:

[tex]\begin{gathered} (5x+3)\cdot(x+4) \\ x=-\frac{3}{5}\text{ and }x=-4 \end{gathered}[/tex]

STEP-BY-STEP EXPLANATION:

We have the following function:

[tex]5x^2+23x+12[/tex]

we factor and calculate the roots like this:

[tex]\begin{gathered} (5x+3)\cdot(x+4) \\ (5x+3)=0\rightarrow x=-\frac{3}{5} \\ (x+4)=0\rightarrow x=-4 \end{gathered}[/tex]

Therefore the factored form would be

[tex](5x+3)\cdot(x+4)[/tex]

And the roots of the functions are - 3/5 and -4

The mean amount of time it takes a kidney stone to pass is 16 days and the standard deviation is 5 days. Suppose that one individual is randomly chosen. Let X = time to pass the kidney stone. Round all answers to 4 decimal places where possible.a. What is the distribution of X? X ~ N(16Correct,5Correct) b. Find the probability that a randomly selected person with a kidney stone will take longer than 17 days to pass it. 0.2Incorrectc. Find the minimum number for the upper quarter of the time to pass a kidney stone. 0.8Incorrect days.

Answers

Answer:

• (a)X ~ N(16, 5)

,

• (b)0.4207

,

• (c)19.37 days

Explanation:

(a)

• The mean amount of time = 16 days

,

• The standard deviation = 5 days.

Therefore, the distribution of X is:

[tex]X\sim N(16,5)[/tex]

(b)P(X>17)

To find the required probabability, recall the z-score formula:

[tex]z=\frac{X-\mu}{\sigma}[/tex]

When X=17

[tex]z=\frac{17-16}{5}=\frac{1}{5}=0.2[/tex]

Next, find the probability, P(x>0.2) from the z-score table:

[tex]P(x>0.2)=0.4207[/tex]

The probability that a randomly selected person with a kidney stone will take longer than 17 days to pass it is 0.4207.

(c)The upper quarter is the value under which 75% of data points are found.

The z-score associated with the 75th percentile = 0.674.

We want to find the value of X when z=0.674.

[tex]\begin{gathered} z=\frac{X-\mu}{\sigma} \\ 0.674=\frac{X-16}{5} \\ \text{ Cross multiply} \\ X-16=5\times0.674 \\ X=16+(5\times0.674) \\ X=19.37 \end{gathered}[/tex]

The minimum number for the upper quarter of the time to pass a kidney stone is 19.37 days.

Solve for "x":3x - 5 < -14 or 2x - 1 > 7

Answers

We are given the following inequalities:

[tex]\begin{gathered} 3x-5<-14,(1)\text{ or} \\ 2x-1>7,(2) \end{gathered}[/tex]

First, we will solve for inequality 1. To do that we will add 5 to both sides:

[tex]3x-5+5<-14+5[/tex]

Solving the operations:

[tex]3x<-9[/tex]

Now we divide both sides by 3:

[tex]\frac{3x}{3}<-\frac{9}{3}[/tex]

Solving the operations:

[tex]x<-3[/tex]

Now we solve for "x" in inequality (2). To do this we will add 1 to both sides:

[tex]2x-1+1>7+1[/tex]

Solving the operations:

[tex]2x>8[/tex]

Now we divide both sides by 2:

[tex]\frac{2x}{2}>\frac{8}{2}[/tex]

Solving the operations:

[tex]x>4[/tex]

Therefore, the solution to the system is:

[tex]x<-3\text{ or x > 4}[/tex]

Find the perimeter and area for each figure.
10.
6 in.
P =
A =
3 in.
6 in.
2 in.
5 in.
11.
7 in.
P =
A =
6 in.
(each side is 6 in.)

Answers

The perimeter and the area of a rectangle of dimensions 15 cm and 8 cm is given as follows:

Perimeter: 46 cm.Area: 120 cm².

What are the area and the perimeter of a rectangle?

Considering a rectangle of length l and width w, we have that the area and the perimeter are given, respectively, by these following equations:

Area: A = lw.Perimeter: = 2(l + w).

In the context of this problem, the dimensions are given/supposed as follows:

l = 15 cm, w = 8 cm.

Applying the rule, the area, in cm², as the variables are multiplied, is given as follows:

A = 15 x 8 = 120 cm².

The perimeter, in cm, as the measures are added, is given as follows:

P = 2 x (15 + 8) = 2 x 23 = 46 cm.

Missing information

This problem is incomplete and could not be found on any search engine, hence we suppose that it is a rectangle of dimensions 15 cm and 8 cm.

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O DESCRIPTIVE STATISTICInterpreting relative frequency-histogramsStudents at a major university in Southern California are complaining about a serious housing crunch. Many of the university's students, they complain, have tocommute too far to school because there is not enough housing near campus. The university officials' response is to perform a study. The study, reported in theschool newspaper, contains the following histogram summarizing the commute distances for a sample of 100 students at the university:Relative frequencyCommute distance (in miles)Based on the histogram, find the proportion of commute distances in the sample that are at least 16 miles. Write your answer as a decimal, and do not roundyour answer

Answers

Since the graph gives us the relative frequency we just have to add those who are more or equal to 16; in this case we have to add 0.11 and 0.06, therefore the proportion in this case is 0.17

Collinear points are two or more points that lie on the sameA. planeB. angleC. lineD. space

Answers

Collinear points are two or more points that lie on the same line.

For Example:

Point A, B and C

A plane flies from Oahu and back. Flying to Oahu the plane is flying against the wind and the trip takes 6 hours. On the way back the plane flies with the wind and it takes 5 hours. If the distance one way is 900 miles, what is the speed of the plane in still air and the speed of the wind?

Answers

Answer:

Plane: 165 miles per hour

Wind: 15 miles per hour

Explanation:

Let's call x the speed of the plane in still air and y the speed of the wind.

Additionally, the velocity is equal to distances over time. So, when the plane is flying against the wind, we can write the following equation:

[tex]\begin{gathered} x-y=\frac{\text{distance}}{\text{time}} \\ x-y=\frac{900\text{ miles}}{6\text{ hours}} \\ x-y=150 \end{gathered}[/tex]

Because x - y is the total velocity of the plane when it is flying against the wind.

On the other hand, when the plane flies with the wind, we get:

[tex]\begin{gathered} x+y=\frac{900\text{ miles}}{5\text{ hours}} \\ x+y=180 \end{gathered}[/tex]

So, we have the following system of equations:

x - y = 150

x + y = 180

Adding both equations, we get:

x - y = 150

x + y = 180

2x + 0 = 330

Solving for x:

2x = 330

2x/2 = 330/2

x = 165

Finally, Replace x by 165 on the second equation and solve for y as:

x + y = 180

165 + y = 180

165 + y - 165 = 180 - 165

y = 15

Therefore, the speed of the plane in still air is 165 miles per hour and the speed of the air is 15 miles per hour.

Amtrak's annual passenger revenue for the years 1985 - 1995 is modeled approximately by the formulaR = -60|x- 11| +962where R is the annual revenue in millions of dollars and x is the number of years after 1980. In what year was the passenger revenue $722 million?In the years ____ and ___, the passenger revenue was $722 million.

Answers

ANSWER

1987 and 1995

EXPLANATION

The revenue is modeled by:

[tex]R=-60|x-11|+962[/tex]

To find the years that the revenue was $722 million, we have to solve for x when R is 722.

That is:

[tex]\begin{gathered} 722=-60|x-11|+962 \\ \Rightarrow722-962=-60|x-11| \\ -240=-60|x-11| \\ \Rightarrow|x-11|=\frac{-240}{-60} \\ |x-11|=4 \end{gathered}[/tex]

We can split the absolute value equation into two different equations because the term in the absolute value is equal to both the positive and the negative of the term on the other side of the equality.

That is:

[tex]\begin{gathered} x-11=4 \\ x-11=-4 \end{gathered}[/tex]

Solve for x in both:

[tex]\begin{gathered} x=11+4 \\ \Rightarrow x=15 \\ x=11-4 \\ \Rightarrow x=7 \end{gathered}[/tex]

That is to say 7 and 15 years after 1980.

Therefore, in the years 1987 and 1995, the revenue was $722 million.

Explain if the triangles are similar using SAS-. If they are similar, which angles are congruent and how do you know? (Explain your reasoning using evidence like a paragraph proof NOT a rigid motion proof!)

Answers

We have two triangles GBL and XYL.

From the picture we notice that the GL=39 and BL=34. We also notice that XL=30 and YL=27.

The SAS theorem states that if two sides in one triangle are proportional to two sides in another triangle and the included angle in both are congruent, then the two triangles are similar.

This means that we need that:

[tex]\frac{GL}{XL}=\frac{BL}{YL}[/tex]

and that the angle between them is the same.

It is clear that the angle L is the same for both triangles, hence we only need to proof tha the sides are congruent, but in this case:

[tex]\frac{39}{30}\ne\frac{34}{27}[/tex]

since the sides are not proportional, we conclude that triangles are not congruent.

a 14-member board used for admitted

Answers

Using the Borda's method, when one person is ranked as 1st, he/she gets 3 points, if he/she is ranked 2nd, get 2 points, also, if he/she is ranked as 3rd get 1 point, and finally, 0 points if she/he is ranked as 4th

so, let's detemine how many points got each one

Cardona: Was selected 1st by 6 people, 2nd by 2 people, 3rd by 4 people and 4th by 2 people

[tex]C=3*6+2*2+1*4=26[/tex]

So, that's a total of 26 points

Pitts-Jones: Was selected as: #1 by 4 people, #2 by 3 people, #3 by 6 people and 4th by 1 person

[tex]P=3*4+2*3+1*6=24[/tex]

So, that's 24 points for Pitts-Jones,

De Plata: Was ranked #1 by 2 people, #2 by 8 people, #3 by 1 person and #4 by 3 people

[tex]D=3*2+2*8+1*1=23[/tex]

That's 23 points for De Plata

Vincent: Was ranked as #1 by 2 people, #2 by 1 person, #3 by 3 people and #4 by 8 people

[tex]V=3*2+2*1+1*3=11[/tex]

that's 11 points for Vincent,

Answer: From the above, we can conclude that the winner using Borda's method is Cardona

Select the similarity transformation(s) that make ABC similar to EDC.

Answers

Given the triangles ABC and EDC

We will find the transformation that makes the triangles are similar

As shown: the triangles are reflected over the y-axis

the rule of the reflection over the y-axis will be as follows:

[tex](x,y)\rightarrow(-x,y)[/tex]

And as shown, the length of the side AB = 3 units

And the length of the side ED = 1 units

So,

[tex]ED=\frac{1}{3}AB[/tex]

So, the answer will be:

D) (x,y) ⇒ (-x, y)

E) (x,y) ⇒ (1/3 x, 1/3 y)

Melissa works as a tutor for S12 an hour and as a waitress for S11 an hour. This month, she worked a combined total of 105 hoursat her two jobs.Lett be the number of hours Melissa worked as a tutor this month. Write an expression for the combined total dollar amount sheearned this month.

Answers

From the question

Melissa earns $12 an hour as a tutor

And $11 an hour as a waitress

Also,

This month, she worked a combined total of 105 hours

at her two jobs.

Let t be the number of hours Melissa worked as a tutor this month

Let w be the number of hours Melissa worked as a waitress this month

This implies

[tex]t+w=105[/tex]

Since Melissa worked t hours as a tutor this month then

Total money earned as a tutor = $12t

Also,

Since Melissa worked w hours as a waitress this month then

Total money earned as a waitress this month = $11w

Therefore, the total combined earnings for the month is

[tex]\text{ \$12t }+\text{ \$11w}[/tex]

Please help me ASAP I’ll mark brainly

Answers

1. The scholar made a mistake in the last step

where he said x=3.5

SCHOLA DIVIDED 7 BY 2 INSTEAD OF DIVIDING BY 0.5

[tex]0.5x = 7 \\ \frac{0.5x}{0.5} = \frac{7}{0.5} \\ x = 14

AS A RESULTS GOT WRONG ANSWER . x is supposed to be 14.

If the time to climb the mountain took an hour more than the time to hike down how long was entire hike?

Answers

4.8 mi

Explanation

[tex]\text{time}=\text{ }\frac{\text{distance}}{\text{rate}}[/tex]

Step 1

Set the equations

a) uphill

let

rate1= 1.5 miles per hour

time= unknow= t1

distance = x

b) down hille

rate=4 miles per hour

time=time2=one hour less than the time to climb = t1-1

distance = x

so

replacing

[tex]\begin{gathered} t_1=\frac{x}{1.5\frac{mi}{\text{hour}}}\rightarrow t_1=\frac{x}{1.5}\rightarrow equation(1) \\ t_2=\frac{x}{4\frac{mi}{\text{hour}}} \\ \text{replace t}_2=t_1-1 \\ t_1-1=\frac{x}{4} \\ \text{add 1 in both sides} \\ t_1-1+1=\frac{x}{4}+1 \\ t_1=\frac{x}{4}+1\rightarrow equation(2) \end{gathered}[/tex]

Step 2

solve the equations

[tex]\begin{gathered} t_1=\frac{x}{1.5}\rightarrow equation(1) \\ t_1=\frac{x}{4}+1\rightarrow equation(2) \end{gathered}[/tex]

set t1= t1

[tex]\begin{gathered} t_1=t_1 \\ \frac{x}{1.5}=\frac{x}{4}+1 \\ \frac{x}{1.5}=\frac{x+4}{4} \\ 4x=(x+4)1.5 \\ 4x=1.5x+6 \\ subtract\text{ 1.5 x in both sides} \\ 4x-1.5x=1.5x+6-1.5x \\ 2.5x=6 \\ \text{divide both sides by 2.5} \\ \frac{2.5x}{2.5}=\frac{6}{2.5} \\ x=2.4 \end{gathered}[/tex]

it means the distance to the top of the mountain is 2.4 miles, so the entire hike is twice that amount

total distance=2.4 mi*2

total distance=4.8 miles

Step 3

now, the times

[tex]\begin{gathered} t_1=\frac{x}{1.5} \\ t_1=\frac{2.4}{1.5} \\ t_1=1.6\text{ hours} \\ t_2=t_1-1 \\ t_2=1.6-1=\text{ 0.6 hours} \end{gathered}[/tex]

table

I hope this helps you

Find The measure of the indicated to the nearest angle

Answers

The given figure is a right triangle, then we can apply the sine function to find the missing angle, so:

[tex]\sin\theta=\frac{opposite}{hypotenuse}[/tex]

The opposite side to the angle measures 17, and the hypotenuse measures 19.

By replacing these values, we can find the angle:

[tex]\begin{gathered} \sin\theta=\frac{17}{19} \\ \\ \theta=\sin^{-1}(\frac{17}{19}) \\ \\ \theta=63.47 \\ \theta\approx64\degree \end{gathered}[/tex]

The answer is 64°.

Two Way Tables, URGENT

Answers

Step-by-step explanation:

a) modal number is 3

b) mean is x = ∑fx/n

= ((5•1)+ (2•10)+(3•15)+(7•4)+(3•5))/(5+10+15+7+3)

= 113/40

= (Decimal: 2.825)

find x..in a right triangle ️ with a height of 10 and hypotenuse of 19

Answers

Since it is a right triangle we can apply the Pythagorean theorem:

c^2 = a^2 + b^2

Where:

c= hypotenuse (the longest side) = 19

a & b = the other 2 legs of the triangle

Replacing:

19^2 = 10^2 + x^2

Solve for x

361 = 100 + x^2

361 - 100 = x^2

261 = x^2

√261 =x

x= 16.16

Nicholas and Jack volunteer to fill gift boxes for soldiers serving overseas. Both work at a constant rate. They work together for 6 hours and fill 126 boxes. Nicholas fills 9 boxes every hour. How many boxes does Jack fill every hour?

Answers

Firstly, we need to know the number of boxes they both filled per hour.

From the question, we are told that 126 boxes were filled in six hours; thus in an hour, the number of boxes filled will be 126/26 = 21 boxes

Now in an hour, Nicholas filled 9 boxes; the number of boxes that will be filled is clearly the remainder of the 21 boxes.

The number of boxes filled by Jack is thus; 21 - 9 = 12 boxes

Jack fills 12 boxes in an hour

Unit 6 lesson3 plsss help

Answers

From the triangles ∠ABC ≅ ∠MNP.

Given we have two triangles ABC and PNM

Both triangles have same shape but different angles.

we need to find ∠ABC ≅ ?

we can notice that :

∠A ≅ ∠M

∠B ≅ ∠N

∠C ≅ ∠P

hence these angles are similar to each other.

So,  ∠ABC ≅ ∠MNP.

Hence we get the answer as ∠ABC ≅ ∠MNP.

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| 5-6x | -12 = 0Solve the absolute. equation for 2 values of x

Answers

Given

[tex]|5-6x|-12=0[/tex]

To solve this equation for both possible values of x, you have to separate it into two calculations.

1) One will be for the case that the values inside the absolute term are multiplied by "+1":

[tex]\begin{gathered} 1\cdot(5-6x)-12=0 \\ 5-6x-12=0 \\ -6x+5-12=0 \\ -6x-7=0 \\ -6x=7 \\ -\frac{6x}{-6}=\frac{7}{-6} \\ x=-\frac{7}{6} \end{gathered}[/tex]

The first value of x is -7/6

2) The second will be the case that the absolute values are negative, that is as if they are multiplied by -1

[tex]\begin{gathered} (-1)(5-6x)-12=0 \\ -5+6x-12=0 \\ 6x-5-12=0 \\ 6x-17=0 \\ 6x=17 \\ \frac{6x}{6}=\frac{17}{6} \\ x=\frac{17}{6} \end{gathered}[/tex]

The second value of x is 17/6

So for this absolute equation, the possible values of x are -7/6 and 17/6

In the diagram below of rhombus ABCD,angle C is 100,what is angle DBC

Answers

Okay, here we have this:

Considering the provided information, that in a rhombus opposite angles are equal, and that the sum of the angles of a triangle is 360 °, we obtain:

360°=100°+100°+4(m∠DBC)

Now, let's clear "m∠DBC":

360°=200°+4(m∠DBC)

4(m∠DBC)=360°-200°

4(m∠DBC)=160°

m∠DBC=160°/4

m∠DBC=40°

Finally we obtain that the correct answer is the option A.

dog brought a new jet ski for $299 down in 14 monthly payments are $57 how much did Doug pay for the jet ski total

Answers

If he paid $57 monthly for 14 months, the total amount paid is:

[tex]57\times14=798[/tex]

He paid $798 in total

gus bought 2/3 pound of turkey and 1/4 pound of ham.The tukey cost 9 dollars per pound, and the ham cost 7 dollars per pound.In all,how much did Gus spend?

Answers

From the information given,

gus bought 2/3 pound of turkey. If tukey costs 9 dollars per pound, it means that the cost of 2/3 pound of turkey is

2/3 x 9 = 6

gus bought 1/4 pound of ham. If ham costs 7 dollars per pound, it means that the cost of 1/4 pound of ham is

1/4 x 7 = 7/4 = 1.75

Total amount spent = amount spent on turkey + amount spent on ham

Total amount = 6 + 1.75

Total amount = $7.75

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