A. ∆H° = -1238.8 kJ/mol. This reaction is endothermic, meaning that heat is absorbed in order for the reaction to occur.
What is reaction?Reaction is an action in response to a stimulus. It is an immediate response to a situation or event that occurs.
The heat of formation for CaO (s) is -635.7 kJ/mol, HCl (g) is -92.3 kJ/mol, CaCl2 (s) is -790.3 kJ/mol, and H2O (g) is -241.8 kJ/mol. To calculate the ∆H°, we need to use the equation ∆H° = Σ (ΔHf products) - Σ (ΔHf reactants). Plugging in the values, we get ∆H° = (-790.3 + -241.8) - (-635.7 + -92.3) = -1238.8 kJ/mol.
b. ∆H° = -1115.8 kJ/mol
This reaction is exothermic, meaning that heat is released when the reaction occurs. The heat of formation for FeO (s) is -824.3 kJ/mol, O2 (g) is 0 kJ/mol, and Fe2O3 (g) is -1290.1 kJ/mol. To calculate the ∆H°, we need to use the equation ∆H° = Σ (ΔHf products) - Σ (ΔHf reactants). Plugging in the values, we get ∆H° = (-1290.1) - (-824.3 + 0) = -1115.8 kJ/mol.
c. ∆H° = -250.3 kJ/mol
This reaction is endothermic, meaning that heat is absorbed in order for the reaction to occur. The heat of formation for CuO (s) is -157.4 kJ/mol, NO (g) is 90.2 kJ/mol, Cu2O (s) is -167.9 kJ/mol, and NO2 (g) is 33.3 kJ/mol. To calculate the ∆H°, we need to use the equation ∆H° = Σ (ΔHf products) - Σ (ΔHf reactants). Plugging in the values, we get ∆H° = (-167.9 + 33.3) - (-157.4 + 90.2) = -250.3 kJ/mol.
d. ∆H° = -907.2 kJ/mol
This reaction is exothermic, meaning that heat is released when the reaction occurs. The heat of formation for NH3 (g) is -45.9 kJ/mol, O2 (g) is 0 kJ/mol, N2H4 (g) is -208.6 kJ/mol, and H2O (l) is -285.8 kJ/mol. To calculate the ∆H°, we need to use the equation ∆H° = Σ (ΔHf products) - Σ (ΔHf reactants). Plugging in the values, we get ∆H° = (-208.6 + -285.8) - (-45.9 + 0) = -907.2 kJ/mol.
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12. If a lab experiment is not completed, you should... A. Discuss the issue with your instructor. B. Sneak in after school and work alone. C. Come in during lunch and finish while eating. D. Make up some results. • 13. You are heating a substance in a test tube. Always point the open end of the tube.... A Towed yourself B. Toward your lab partner. C. Toward another classmate. D. Away from all people. . 14. You are heating a piece of glass and now want to pick it up. You should... A. Use a rag or paper towels. B. Pick up the end that looks cooler. C. Use Tongs. D. Ask someone else to pick it up . 15. You have been injured in the laboratory (cut, burn, etc.). First you should... A. Visit the nurse after class. B. See a doctor after school. C. Tell the Lab Instructor at once. D. Apply first aid yourself. • 16. When using glassware and equipment for an experiment, you should... A. Read all directions carefully to know what equipment is necessary. B. Examine all glassware to check for chips or cracks. C. Clean any glassware that appears dirty. D. All of the above. • 17. If a piece of equipment is not working properly, stop, turn it off, and tell... A. The cleaning helper. B. Your lab partner. C. Your best friend in the class. D. The Lab Instructor. . 18. If an acid is splashed on your skin, wash at once with... A Soap. B. Oil. C. Weak base. D. Plenty of water.
Laboratory environments can be dangerous because of the existence of explosive compounds, potentially toxic microbes, volatile solvents, high pressure gases, and hazardous and caustic substances.
What is safety in the laboratory?The presence of hazardous and caustic substances, volatile solvents, high pressure gases, explosive compounds, and potentially harmful bacteria in a laboratory raises safety concerns. Mistakes in the lab can be avoided with a little caution and respect to established safety requirements.
Make sure you are protected from any splashes by covering up any exposed skin with clothing and footwear. Keep long hair, jewellery, and other anything that could get caught in gear in a ponytail. Never use cosmetics (including lip balm) or contact lenses in a lab setting, and never eat, drink, chew gum, or consume liquids.
Suitable facilities and equipment, suitable training, PPE, chemical management, standard operating procedures, waste disposal, signage, proper laboratory practices, and secure working conditions are all part of good laboratory safety measures.
Therefore, the answers are:
12. a)discuss the issue with your instructor.
13. D)away from all people.
14. c)use tongs.
15. You were hurt in the laboratory (cut, burn, etc.) Visit the school nurse after class as your first course of action. after school, visit a doctor.
16. a) Read all directions carefully to know what equipment is necessary.
17. d) The Lab instructor.
18. d) Plenty of water.
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which structure represents the most stable conformation of cis-1-tert-butyl-4-methylcyclohexane?
The most stable conformation of cis-1-tert-butyl-4-methylcyclohexane is a chair conformation. In this conformation, the tert-butyl group and a methyl group are located on opposite sides of the ring, and the two groups are staggered.
This conformation minimizes the steric repulsions between the two groups and is the most energetically favorable conformation. In this conformation, the four methylene groups of the tert-butyl group and the methyl group are aligned in a chair-like structure.
The two methyl groups are axial and the tert-butyl group is equatorial. This conformation is favored because it minimizes the steric repulsions between the two groups and the other substituents on the ring. The axial positions of the two methyl groups also help to minimize the steric interactions, as they are further away from the other substituents.
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Draw structures for the following 4-Isopropyl-3-methylheptane 2, 3-Dimethyl-6 -(2-methylpropyl)decane
The structure of the following are given below :
1) 4-Isopropyl-3-methylheptane :
CH₃ - CH₂ - CH₂ - CH(C₂H₆) - CH(CH₃) - CH₂ - CH₃
2) 2, 3-Dimethyl-6 -(2-methylpropyl) decane :
CH₃ - CH(CH₃) - CH(CH₃) - CH₂ - CH₂ - CH - CH₂ CH₂ - CH₂ - CH₃
|
CH₂ - CH(CH₃) - CH₃
The structure for given molecules are given as :
1) 4-Isopropyl-3-methylheptane :
CH₃ - CH₂ - CH₂ - CH(C₂H₆) - CH(CH₃) - CH₂ - CH₃
H H H C₂H₆ H H
| | | | | |
H - C - C - C - CH - CH - C - C - H
| | | | | |
H H H CH₃ H H
2) 2, 3-Dimethyl-6 -(2-methylpropyl)decane :
CH₃ - CH(CH₃) - CH(CH₃) - CH₂ - CH₂ - CH - CH₂ CH₂ - CH₂ - CH₃
|
CH₂ - CH(CH₃) - CH₃
CH₃ - CH - CH - CH₂ - CH₂ - CH - CH₂ CH₂ - CH₂ - CH₃
| | |
CH₃ CH₃ CH₂ - CH - CH₃
|
CH₃
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The equilibrium concentrations for the reaction between SO2 and O2 to form
SO3 at a certain temperature are given in the table below. Determine the
equilibrium constant and whether the reaction favors reactants, products, or
neither at this temperature.
O₂(g) +2SO₂(g) 2SQ(g)
1.3 M
[0₂]
0.46 M
[s0₂]
A. K= 3.8 x 10-3; product favored
OB. K= 260; product favored
OC. K= 3.8 x 10-3; reactant favored
OD. K= 260; reactant favored
8.5 M
[S03]
K = 1.3104 based on the provided data and because K is high and positive, the reaction is in the product's favor.
What does the term "equilibrium" mean in chemistry?Equilibrium point is the condition where there is no overall change in the amount of either reactants or products throughout a reversible chemical reaction.
Given data :
O2(g) + 2SO2(g) ↔ 2SO3(g)
Concentration of O2 is [O2] = 0.024 M
Concentration of SO2 is [SO2] = 0.015 M
Concentration of SO3 is [SO3] = 0.26 M
Equilibrium constant, K =..?
Equilibrium constant for the given reaction is -
K = [SO3]² / [O2] [SO2]²
Putting the values of [SO3], [O2] and [SO2] the equilibrium constant, K become:
K = [SO3]² / [O2] [SO2]²
K = 0.26² / 0.024 × 0.015²
K = 1.3×10⁴
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Benedict College E360 xG The number of second o x The cis isomer of the 1.3-diethyl cyclobutane is: CHyCH2 CH CH CH CHy CH CHs OA ?? oc Which is more stable,cis-1-ethyl-3-methylcyclohexane or trons-1-ethyl-3-methylcyclohexane? O cis trans The number of second degree (2") hydrogens in the structure below is ViewSonic
A cyclic diallylamine called 1-ethyl-3-methylcyclohexane is a feedstock used to create methicillin-resistant Staphylococcus aureus (MRSA).
Describe trons-1-ethyl-3-methylcyclohexane or methylcyclohexane.An organic substance with the chemical formula CH3C6H11 is methylcyclohexane. It is a white liquid with a little odor that is categorized as a saturated hydrocarbon.As a solvent, methylcyclohexane is employed. Toluene is the principal product of its conversion in naphtha reformers. [4] Some correction fluids (like White-Out) also use methylcyclohexane as a solvent.Because one methyl group is attached to one carbon of the cyclohexane ring, methylcyclohexane is a monosubstituted cyclohexane.This monosubstituted methylcyclohexane has the lowest energy form when the methyl group is located equatorially as opposed to axially.The idea of A value embodies this equilibrium. Because there are axial hydrogen atoms on the same side of the ring while the methyl group is in the axial position, there is steric crowding (steric strain) experienced by the methyl group (known as the 1,3-diaxial interactions).To know more about methylcyclohexane visit:
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Match the following definitions to the most appropriate term: a substance that donates one proton when dissolved in water [ Choose] a substance that donates two protons when dissolved in water [ Choose ]
a substance that donates three protons when dissolved in water any ionic compound whose cation comes from a base and whose anion comes from an acid [Choose] the solution in the buret [ Choose] the solution in the flask [Choose]
Monoprotic and diprotic substances are those that donate one proton and two protons, respectively, when dissolved in water.
Any acid that contains two hydrogen atoms and can release or ionise in water, such as carbonic acid and sulphuric acid.Diprotic acids have two acidic hydrogen atoms and include sulfuric acid (H2SO4), carbonic acid (H2CO3), hydrogen sulphide (H2S), chromic acid (H2CrO4), and oxalic acid (H2C2O4).
One hydrogen atom or proton can be given away by monoprotic acids to their aqueous solution.Since mono means "one," a monoprotic acid is an acid that will only donate one proton. One hydrogen ion or multiple hydrogen ions may exist in a monoprotic acid. However, only one will be given as a response.
Monoprotic acids include benzoic acid (C6H5CO2H), acetic acid (CH3CO2H or HOAc), nitric acid (HNO3), and hydrochloric acid (HCl).
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Determine the molecular geometry IBr−4 and make a sketch
IBr4 has square planar geometry and its hybridization is sp3d2.
Iodine and bromine make up the two different halogen atoms that make up the inter-halogen compound IBr4-. It only partially dissolves in benzene and ether. The central Iodine atom of the IBr4-Lewis structure, which has a -1 formal charge and is covalently bonded to four Bromine atoms, is present. The IBr4-Lewis structure has a square planar shape. The central iodine atom is surrounded by two lone pairs of electrons on either side, four bonding electron pairs on one plane, and four bonding electron pairs arranged in a square pattern. This molecule has the generic formula AX4E2 according to VSEPR theory.Sp3d2 hybridization is present in the IBr4-molecule. One electron from the central iodine atom's 5s and 5p orbitals is promoted to the 5d orbital, where it combines with another electron to form a 6 sp3d2 hybrid orbital with the same energy. Each sp3d2 hybrid orbital combines with a bromine atom's 4p orbital to form an I-Br bond.
The attached image shows structure of IBr-4
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Draw a structural formula for 3-propyl-1-hexene. . You do not have to consider stereochemistry . You do not have to explicitly draw H atoms. .(//>//. 000-ie CHỈ CnemDcodio Submit Answrer Try Anothor Morslon 3 item attempts remaining
The structural formula for 3-propyl-1-hexene would be:
H3C |CH2-CH-CH2-CH2-CH-CH2 |CH3
It is an alkene with a propyl group (CH3-CH2-) attached to the third carbon atom. And the alkene carbon atoms are connected in hexane backbone.
An alkene with a propyl group is a hydrocarbon molecule that contains a carbon-carbon double bond (alkene) and a propyl group, which is a three-carbon chain (CH3-CH2-CH2-) attached to the alkene. The alkene carbon atoms are connected in a chain of varying length. These molecules are important in the chemical industry as they can be used to produce a wide range of products, such as polymers, fuels, and pharmaceuticals, through various chemical reactions such as polymerization and oxidation. They also have a reactive functional group which allow them to participate in different chemical reactions. They are also known as propyl alkenes or propenyl alkenes.
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Why is it necessary to calibrate the spectroscope used in this experiment?
a. The spectroscope has to be calibrated so the wavelength reading on the spectroscope scale can be converted into an angular reading.
b. The spectroscope has to be calibrated so the degrees on the spectroscope scale can be converted into wavelength.
c. The spectroscope has to be calibrated so you can physically see the emission spectrum of helium.
d. The spectroscope has to be calibrated so you can physically see the emission spectrum of hydrogen.
It necessary to calibrate the spectroscope used in this experiment because The spectroscope has to be calibrated so the degrees on the spectroscope scale can be converted into wavelength.
About Spectrometer, Spectroscope, and SpectrographA spectrometer is any instrument used to probe a property of light as a function of its portion of the electromagnetic spectrum, typically its wavelength, frequency, or energy. The property being measured is usually intensity of light, but other variables like polarization can also be measured. Technically, a spectrometer can function over any range of light, but most operate in a particular region of the electromagnetic spectrum.
A spectroscope is a device that measures the spectrum of light. Early versions had a slit, a prism, and a screen with markings to indicate various wavelengths or frequencies; later versions were calibrated to electronic detectors. Although the apparatus Isaac Newton used in his work on the spectrum of light can be considered a crude spectroscope, it is generally recognized that the spectroscope was invented by Gustav Kirchhoff and Robert Bunsen around 1860.
A spectrograph is an instrument that separates incoming light by its wavelength or frequency and records the resulting spectrum in some kind of multichannel detector, like a photographic plate. Many astronomical observations use telescopes as, essentially, spectrographs.
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Which of the following compounds is insoluble in water? O NH4Cl O KCI O CoCl2 O PbCl2 O Licl
PbCl2 is insoluble in water.
Which of the following compounds is insoluble in water?PbCl2 is insoluble in water. PbCl2, also known as lead chloride, has a low solubility in water, with a solubility of 0.2 g/L at 25°C.This is due to the strong ionic bond between the lead and chlorine atoms, forming a stable ionic lattice which is difficult to break apart.The ionic bond is much stronger than the hydrogen bonds between water molecules, thus preventing the lead chloride from dissolving.Additionally, the large size of the lead cation and the strong attractive forces between the chloride anions and water molecules further contribute to the insolubility of lead chloride in water.In contrast, the other compounds listed are all soluble in water.Ammonium chloride, potassium chloride, and cobalt chloride all have relatively low ionic bond strengths, and their ions are small enough to be separated by the water molecules.Lithium chloride is also soluble in water due to the presence of the small lithium cation.To learn more about PbCl2 is insoluble in water refer to:
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Calculate the Ecell∘ for each of the following balanced redox reactions.
1) 2Cu(s)+Mn2+(aq)→2Cu+(aq)+Mn(s). Determine whether the reaction is spontaneous as it is written.
2) MnO2(s)+4H+(aq)+Zn(s)→Mn2+(aq)+2H2O(l)+Zn2+(aq). Determine whether the reaction is spontaneous as it is written.
3) Cl2(g)+2F−(aq)→F2(g)+2Cl−(aq). Determine whether the reaction is spontaneous as it is written.
Ecell for each of the following reactions i.e. (1, 2, 3) reactions are (-1.52 V, non-spontaneous); (1.99 V, spontaneous); (1.51 V, spontaneous) respectively.
1) 2Cu(s)+Mn2+(aq)→2Cu+(aq)+Mn(s).
To calculate the Ecell∘ for this reaction, we need to know the standard reduction potentials (E0) of the half reactions.
Cu2+(aq) + 2e- → Cu(s) E0 = +0.34 V
Mn2+(aq) + 2e- → Mn(s) E0 = -1.18 V
Ecell = E0 (products) - E0 (reactants)
Ecell = (-1.18 V) - (+0.34 V) = -1.52 V
Since the Ecell value is negative, this means that the reaction is not spontaneous as written (it is non-spontaneous or endothermic) and it would require an input of energy to occur.
2) MnO2(s)+4H+(aq)+Zn(s)→Mn2+(aq)+2H2O(l)+Zn2+(aq)
To calculate the Ecell∘ for this reaction, we need to know the standard reduction potentials (E0) of the half-reactions.
MnO2(s) + 4H+ + 2e- → Mn2+ + 2H2O(l) E0 = +1.23 V
Zn(s) + 2e- → Zn2+(aq) E0 = -0.76 V
Ecell = E0 (products) - E0 (reactants)
Ecell = (+1.23 V) - (-0.76 V) = 1.99 V
Since the Ecell value is positive, this means that the reaction is spontaneous as written (it is exothermic) and it would release energy as it occurs.
3) Cl2(g)+2F−(aq)→F2(g)+2Cl−(aq)
To calculate the Ecell∘ for this reaction, we need to know the standard reduction potentials (E0) of the half-reactions.
Cl2(g) + 2e- → 2Cl-(aq) E0 = +1.36 V
2F-(aq) + 2e- → F2(g) E0 = +2.87 V
Ecell = E0 (products) - E0 (reactants)
Ecell = (+2.87 V) - (+1.36 V) = 1.51 V
Since the Ecell value is positive, this means that the reaction is spontaneous as written (it is exothermic) and it would release energy as it occurs.
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Convert each Fischer projection to a perspective formula Part A CH,CH Draw the molecule on the canvas by choosing buttons from the Tools (for bonds), Atoms, and Advanced Template toolbars, including charges where needed. The single bond is active by default. Show the appropriate stereochemistry by choosing the dashed or wedged buttons and then clicking a bond on the canvas. ileini Cl Marvin JS Br Submit Previous Answers Request Answer
The perspective formula for Part A is: (R)-3-chloro-2-methylpentane.
Converting a Fischer projection to a perspective formulaThe Fischer projection of Part A, CH2CH2, is a linear molecule with two carbon atoms and four hydrogen atoms.In the perspective formula, this molecule is represented as CH3CH3.The two carbon atoms are connected by a single bond, and each carbon atom is bonded to three hydrogen atoms.The perspective formula shows that this molecule is an alkane with a straight-chain structure.Each carbon atom has four bonds, two of which are single bonds to hydrogen atoms and two of which are double bonds to other carbon atoms.This molecule is non-polar, as the carbon atoms are equally bonded to the hydrogen atoms and thus the molecule has no overall charge.Part A: The Fischer projection of CH,CH can be converted to the perspective formula ileini Cl. The molecule shown in the Fischer projection is a chiral molecule with two distinct stereocenters. It can be drawn in a perspective formula as shown in the image below.The two chiral centers are labeled with the letter ‘R’ to denote the right-handed configuration and the letter ‘S’ to denote the left-handed configuration.The molecule is composed of four atoms, two methyl groups (CH3) and two chlorine atoms (Cl). The methyl groups are attached to the two stereocenters, while the chlorine atoms are attached to the other two stereocenters. The overall shape of the molecule is a planar, tetrahedral shape.To learn more about converting a Fischer projection to a perspective formula refer to:
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Drag each number to the correct location on the equation. Each number can be used more than once, but not all numbers will be used.Balance the equation with the correct coefficients.
A chemical equation is said to be balanced when there are an equal number of atoms on both the reactant and product sides.
[tex]KCl3 = KCL + O2[/tex]
In this case-
Therefore, we multiply by 2 on the reactant side and by 2 and 3 on the product side of the equation to make it equal. Equal numbers and types of each atom are present on both sides of balanced chemical equations. A balanced equation must have coefficients that are the easiest whole number ratio. Chemical reactions always preserve mass.
These are the atom counts on the reactant side.
K = 1
Cl = 1
O = 3
These are the atom counts on the product side.
K = 1
Cl = 1
O = 2
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two unbalanced half-reactions are given. hno2(aq)→no(g) cu+(aq)→cu2+(aq). Write an overall unbalanced reaction. Express your answer as a chemical equation.
The overall unbalanced reaction can be written as:
HNO₂(aq) + Cu⁺(aq) + e- → NO(g) + Cu²⁺(aq)
An overall unbalanced reaction can be formed by combining two unbalanced half-reactions. In this case, the two unbalanced half-reactions are:
HNO₂(aq) → NO(g)
Cu⁺(aq) → Cu²⁺(aq)
To form an overall unbalanced reaction, we need to balance the number of electrons and the number of atoms on both sides of the equation. This can be achieved by multiplying the half-reactions by appropriate coefficients.
The first half-reaction, HNO₂(aq) → NO(g), involves the gain of one electron from HNO₂ (+3 in N) to form NO (+2 in N).
The second half-reaction, Cu⁺(aq) → Cu²⁺(aq), involves the lose of one electron by Cu⁺ to form Cu²⁺.
The overall unbalanced reaction can be written as:
HNO₂(aq) + Cu⁺(aq) + e- → NO(g) + Cu²⁺(aq)
This overall reaction represents the oxidation of HNO₂ by Cu⁺ to produce NO and Cu²⁺
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hydrogen sulfide (g) + oxygen(g)water (l) + sulfur dioxide(g)
When hydrogen sulphide gas combines with oxygen gas, sulphur dioxide gas and water are produced.
Given,
Hydrogen sulfide (g) + oxygen(g) → sulfur dioxide(g) + water (l)
Equation: H2S(g) + O2(g) → SO2(g) + H2O(l)
Balanced equation: 2H2S(g) + 3O2(g) → 2SO2(g) + 2H2O(l)
H2S is the chemical formula for hydrogen sulphide. It is a colorless chalcogen-hydride gas that is toxic, caustic, and combustible, with tiny levels in the ambient environment emitting a distinct rotten egg stench. The process of balancing all stoichiometric coefficients just on reactants and product sides of a chemical equation.
This is required because the chemical equation follows the principles of mass and momentum conservation. H2S interacts with oxygen (O2) to produce solid sulphur (S) as well as water (H2O). It is a redox process because it involves both the oxidation of hydrogen sulphide towards sulphur and the reduction of oxygen to water.
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A change in momentum from applying a force for a certain time is:
A change in momentum from applying a force for a certain time is called an impulse.
What is in physics the word momentum?In physics, the word momentum can be defined as a type of measurement that indicates mass motion, which is generally denoted by the letter p and can be used to understand the impulse properties of a given compound and or material.
Therefore, with this data, we can see that in physics the word momentum is used to understand the motion of the mass and thus determine the kinetic properties of an element.
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In an experiment, Joseph finds that amount of a chemical needed is directly related to the time of its reaction with a certain catalyst. If he has 12 grams of the chemical and the reaction time was second, what amount of chemical is needed to have a reaction that lasts 3 seconds
72 grams amount of chemical is needed to have a reaction that lasts 3 seconds
y=KX
12= K.1/2
k= 24
y= 24(X)
y=24(3)
y= 72 grams
Thus, a nervous impulse or action potential is an chemical phenomena brought on by alterations in the permeability of the neuron membrane. Ions can traverse the membrane thanks to these changes in permeability. Ions are electrically charged particles, therefore modifications also affect the electric field they produce.
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A tank contains 100 gal of brine made by dissolving 60 lb of salt in water. Saltwater containing 1 lb of salt per gallon runs in at the rate of 2 gal/min and the well-stirred mixture runs out at the rate of 3 gal/min. Find the amount of salt in the tank after 30 minutes.
The presented statement states that 52.5 lbs. of salt had been consumed after 30 minutes.
What three kind of salt are there?Salts come in a variety of forms, such as a double salt, corrosive salt, or basic salt. A salt that forms when a potent acid and a feeble base interact is referred to as a "acidic salt."
There seem to be initially 100 gal with in tank. The amount of salt is 60 lbs. The tank has a salt content of 60/100, or 0.6 pounds per gal.
One pound per gallon of water is coming in.
Because the combination is continually varying, the concentration of the water that comes out is uncertain.
Each minute, the tank is dropping 1 gal. (3-2=1)
Utilize this information to configure three functions for volume, saturation, and salt content: V(t), S(t), and C(t).
V (t) = 100 - t
s (t) = 60 plus 2t - 3t * C (t)
C (t) = s(t)/V(t) = 60 + 2t - 3t * C(t)/ 100 - t
Solve for C with a little mathematics (t)
C (t) = 60 + 2t / 100 + 2t
Now, we are aware of the tank's salt content at all times.
Evaluate at t = 30
C (30) = 60 + 2(30)/100 - 2(30) = 120/160 = 3/4
s(30) = 60 + 2(30) - 3(30)(3/4) = 120 - 90(3/4) = 52.5
Consequently, 52.5 lbs of salt had been consumed within 30 minutes.
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in an equilibrium mixture the partial pressure of s02 and o2 are .135atm and .455 atm, respetively, what is the equilibrim partial pressure of s03 in the mixture>
In an equilibrium mixture the partial pressure of s02 and o2 are .135atm and .455 atm, respectively, 0.135atm is equilibrium partial pressure of SO₃ in mixture.
2SO₂(g) + O₂(g) ⇔ 2SO₃(g)
[tex]K_{p} = \frac{P_{SO_{3} } }{P_{SO_{2} P_{O_{2} } } } = \frac{1}{P_{O_{2} } }[/tex]
Partial pressure of So₃ and SO₂ is same at equilibrium because moles of SO₂ and SO₃ are same at equilibrium.
When the partial pressure of any of the gaseous reactants or of the products is increased, the position of equilibrium is shifted so as to decrease its partial pressure. This is usually achieved by favoring the reaction in which there is decrease in the number of moles of gaseous components.
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calcium silicate reacts with hydrofluoric acid to form calcium fluoride, silicon tetrafluoride and water. if 25.2-g of calcium silicate reacts with 16.0-g of hydrofluoric acid, how many grams of calcium fluoride will be recovered at the end of the reaction?
The mass of calcium fluoride recovered at the end of the reaction is 31.14 g.
What is reaction?Reaction is the response to a stimulus, either physical or mental.
The balanced equation for the reaction between calcium silicate and hydrofluoric acid is as follows:
CaSiO3 + 2 HF → CaF2 + SiF4 + H2O
We can use the given masses of calcium silicate and hydrofluoric acid to calculate the mass of calcium fluoride formed at the end of the reaction. As we can see from the equation, 2 mol of HF are required for every 1 mol of CaSiO3. Thus, the number of moles of HF present is equal to half the number of moles of CaSiO3.
The number of moles of CaSiO3 present can be calculated by dividing the given mass of CaSiO3 (25.2 g) by the molar mass of CaSiO3 (136.14 g/mol). This gives us a value of 0.185 mol of CaSiO3.
Since the number of moles of HF present is half the number of moles of CaSiO3, the number of moles of HF present is 0.0925 mol. We can calculate the mass of HF present by multiplying the number of moles of HF (0.0925 mol) by the molar mass of HF (20.01 g/mol). This gives us a value of 1.85 g of HF.
Since the given mass of HF (16.0 g) is greater than the calculated mass of HF (1.85 g), it means that there is excess HF present in the reaction. The excess HF present will result in more calcium fluoride being formed in the reaction.
To calculate the mass of calcium fluoride formed in the reaction, we need to calculate the number of moles of calcium fluoride formed. We can do this by dividing the mass of HF present (16.0 g) by the molar mass of HF (20.01 g/mol). This gives us a value of 0.799 mol of HF. Since 2 mol of HF are required for every 1 mol of CaSiO3, the number of moles of CaF2 present is 0.799/2 = 0.3995 mol.
We can now calculate the mass of calcium fluoride formed by multiplying the number of moles of CaF2 (0.3995 mol) by the molar mass of CaF2 (78.00 g/mol). This gives us a value of 31.14 g of CaF2.
Thus, the mass of calcium fluoride recovered at the end of the reaction is 31.14 g.
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Balanced Chemical Equation: hclo3(aq)+hbr(aq)→hcl(aq)+br2(g)+h2o(l)
The balanced chemical equation of HClO₃ + HBr → HCl + Br₂ + H₂O is HClO₃ + 6HBr → HCl + 3Br₂ + H₂O.
HClO₃ + HBr → HCl + Br₂ + H₂O
To balance number of O atoms
HClO₃ + HBr → HCl + Br₂ + 3H₂O
To balance number of H atoms
HClO₃ + 6HBr → HCl + Br₂ + 3H₂O
To balance number of Br atoms
HClO₃ + 6HBr → HCl + 3Br₂ + H₂O
This is the balanced equation.
It represents the neutralization reaction between hydrochloric acid (HClO3) and hydrobromic acid (HBr) to form hydrochloric acid (HCl), bromine (Br2) and water (H2O).
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Water is a polar solvent and hexane (C6H14) is a nonpolar solvent. Which of the following correctly describes the solubility of the solute?
Option d, NAHCO3, soluble in water, is the appropriate response to this McQuestion.
The family of inorganic compounds known as sodium bicarbonate (also referred to as washing soda, soda ash, and soda crystals) has the formula Na 2CO 3(H 2O)x, where x can be any value between 0 and 10. All forms are white, odourless salts that dissolve in water and produce alkaline solutions. As a result of hydrogen bonding. While Na2CO3 has no hydrogen bond donor sites, NaHCO3 does. One hydrogen bond for every four to five carbons in an organic compound may be sufficient to make it water soluble. AFAIK, the polymer anionic structure of NaHCO3 is held together by hydrogen bonds. A weak base, sodium bicarbonate separates into sodium and bicarbonate ions in water. It is therefore polar; sodium gains a positive charge while bicarbonate gains a negative charge.
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What is the name of the acid whose formula is H2CO3?Spell out the full name of the acid.
The acid whose formula is H2CO3 is called carbonic acid. It is a weak acid that is formed when carbon dioxide (CO2) dissolves in water (H2O).
It is a common acid found in nature and is present in many carbonated beverages, as well as in the human body as a component of blood. Carbonic acid is a weak acid and it forms the bicarbonate ion (HCO3-) when it dissociates in water. It plays an important role in regulating the pH of blood and other body fluids.
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Solid aluminum Aland chlorine Cl2 gas react to form solid aluminum chloride AlCl3. Suppose you have 11.0 mol of Al and 1.0 mol of Cl2 in a reactor. Calculate the largest amount of AlCl3 that could be produced. Round your answer to the nearest 0.1 mol.
The largest amount of AlCl₃ that could be produced from the reaction of solid aluminum Al and chlorine Cl₂ gas = 1.3 mol.
Write the equation that is properly balanced:
2Al(s) + 3Cl₂(g) ===> 2AlCl₃(s)
When both reactants are provided in equal proportions, you must first determine which one, if either, is the limiting one.
Al moles = 11.0
Cl₂ moles = 1.0
Al : Cl₂ has a mole ratio of 2:3, meaning that you require 1.5 times as much Cl₂ as Al.
Cl₂ is limiting in this situation since it alone will determine how much product is produced because this is NOT the case.
Since the question specifically asks for the quantity of AlCl₃ (in moles), we can simply apply dimensional analysis and stoichiometry to determine the solution:
= (2.0 mol Cl₂ x 2 mol AlCl₃) / (3 mol Cl₂)
= 1.3 mol
So, the largest amount of AlCl₃ that could be produced = 1.3 mol
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Calculate the volume of a gas (in L) at a pressure of 1.00 x 10^2 kPa if its volume at 1.20 x 10^2 kPa is 1.50 x 10^3 ml
Based on the provided information, the volume of a gas (in L) is 1.8L.
Boyle’s law refers to an experimental gas law that describes the relationship between pressure and volume of a confined gas. Boyle's law states that the absolute pressure exerted by a given mass of an ideal gas is inversely proportional to the volume it occupies if the temperature and amount of gas remain unchanged within a closed system. When comparing the same substance under two different sets of conditions, the law can be expressed as:
P1V1 = P2V2
In the given case,
P1 = 1.20 x 10^2 kPa
V1 = 1.50 x 10^3 ml
P2 =1.00 x 10^2 kPa
V2 = ?
(1.20 x 10^2)( 1.50 x 10^3) = (1.00 x 10^2)V2
V2 = 1.8 x 10^3 ml or 1.8L
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London Dispersion of attraction between molecules always decrease with
a. increasing molecular size and increasing distance between the molecules
b. increasing molecular size and decreasing distance between the molecules
c. decreasing molecular size and increasing distance between the molecules
d. decreasing molecular size and decreasing distance between the molecules
Answer:
Therefore, as they are less tightly held and can move easily in order to form temporary dipole, the london dispersion forces between molecules always decreases when we increase the molecular size and decrease the distance between the molecules. Therefore, the correct option is option b.
A buffer solution with pH 4.40 is prepared with 0.78 M NaC2H3O2 and (x)M HC2H3O2. Ka for HC2H30 is 1.8×10^-5. what is the concentration of HC2H3O2 in the buffer?
concentration of HC2H3O2 in the buffer solution is 0.51 M.
xM = 0.51M
To solve for x, we need to first calculate the concentrations of the two species that are present in the buffer solution.
The concentration of NaC2H3O2 is 0.78 M, as given.
The concentration of HC2H3O2 can be calculated from the Henderson-Hasselbalch equation:
pH = pKa + log([HC2H3O2]/[NaC2H3O2])
Rearranging this equation and solving for [HC2H3O2], we get:
[HC2H3O2] = [NaC2H3O2] x 10^(pH - pKa)
Plugging in the given values, we get:
[HC2H3O2] = 0.78 x 10^(4.40 - (-4.7))
[HC2H3O2] = 0.78 x 10^(9.1)
[HC2H3O2] = 0.51 M
Therefore, the concentration of HC2H3O2 in the buffer solution is 0.51 M.
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Draw the Lewis dot structure for Al.
The Lewis dot structure for Al (Aluminium) is attached.
Aluminum is located in Group IIIA of the periodic table, and as a result, it possesses three valence electrons. Al is the symbol that is used to represent it. One atom of aluminium has a total of 13 electrons within it. There are eight electrons in the second orbit, three electrons in the third orbit, and two electrons in the first orbit. As a result, the Lewis structure of it consists of three dots surrounding it. Al is the symbol that is used to represent it. The Lewis dot structure for Al (Aluminium) is attached.
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QUIZ 3: GOLDEN YEARS TO BOHR MODEL quizleConsider the two electron arrangements for neutral atoms A and B. What is the atomic number of A
The atomic number of A is 8, since it has 8 protons. The atomic number of B is 10, since it has 10 protons.
The atomic number of an atom is the number of protons it contains. Protons have a positive charge and are found in the nucleus of the atom. Therefore, atoms with more protons will have higher atomic numbers. In this case, atom A has 8 protons while atom B has 10 protons, so atom A has an atomic number of 8 and atom B has an atomic number of 10.
The atomic number of an atom is determined by the number of protons it has in its nucleus, and atoms with more protons will have higher atomic numbers.
Complete question
Consider the two electron arrangements for neutral atoms A and B. What is the atomic number of A?
A - 1s2, 2s2, 2p6, 3s1
B - 1s2, 2s2, 2p6, 5s1
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One day on her walk home from school, Leann noticed some rust on an old car.
She remembered that chemical equations can summarize what happens in a chemical reaction. What is the name of the two parts found on the left side of the equation below?
4 Fe + 3O2→ 2Fe2O3
A. products
B. reactants
C. scientific notation
D. synthesis
Answer:
B. reactants
