Water waves are waves because the wave moves up and down. transverse longitudinal​

Answers

Answer 1

Answer:

it is transverse because longitudinal run lengthwise rather than across

hoped this helped lmk if it did

Water Waves Are Waves Because The Wave Moves Up And Down. Transverse Longitudinal

Related Questions

In the Compton effect, the wavelength of the scattered photon is __________ the wavelength of the incident photon.

Answers

Answer:

he wavelength is different (greater) than the wavelength of the incident photon

Explanation:

The Compton effect is the scattering of a photon by an electron, this process is analyzed using the conservation of momentum, in which we assume that initially the electron is at rest and after the collision it recedes, therefore the energy of the incident photon decreases and consequently its wavelength changes

To complete the sentence we use the wavelength is different (greater) than the wavelength of the incident photon

Fire trucks have the word FIRE written two ways, as seen here, on the front of the truck. Why is that?

Answers

Answer:

b.

Explanation:

In a thin film experiment, a wedge of air is used between two glass plates. If the wavelength of the incident light in air is 480 nm, how much thicker is the air wedge at the 16th dark fringe than it is at the 6th dark fringe

Answers

Answer:

The thickness is  [tex]\Delta y = 2.4 *10^{-6} \ m[/tex]

Explanation:

From the question we are told that

   The wavelength is  [tex]\lambda = 480 \ nm = 480*10^{-9} \ m[/tex]

    The first order of the dark  fringe is  [tex]m_1 = 16[/tex]

     The second order of dark fringe considered is  [tex]m_2 = 6[/tex]

Generally the condition for destructive interference is mathematically represented as

        [tex]y = \frac{m \lambda}{2}[/tex]

Here y is the path difference between the central maxima(i.e the origin) and any dark fringe

So  the path difference between the 16th dark fringe and the 6th dark fringe is mathematically represented as

      [tex]y_1 - y_2 = \Delta y = \frac{m_1 \lambda}{2} - \frac{m_2 \lambda}{2}[/tex]

=>  [tex]y_1 - y_2 = \Delta y = \frac{16 *480*10^{-9}}{2} - \frac{6 *480*10^{-9}}{2}[/tex]

=>  [tex]y_1 - y_2 = \Delta y = 5 (480*10^{-9})[/tex]

=>  [tex]\Delta y = 2.4 *10^{-6} \ m[/tex]

he mass of the moon is 1/81 of the mass of the earth. Compared to the gravitational force that the earth exerts on the moon, the gravitational force that the moon exerts on the earth is

Answers

Answer:

It is the same in magnitude and opposite in direction.

Explanation:

According Newton's Universal Law of Gravitation, the force that any mass exerts on any other one, is proportional to the product of their masses, inversely proportional tho the square of the distance between their centers, and acts along the line that joins both points.At the same time, this force is part of a action-reaction pair, according to Newton's 3rd Law, that states that for a force that one body exerts upon another, there exists an equal and opposite force exerted by the other body on the former one.So, we conclude that the gravitational force that the earth exerts on the moon is equal in magnitude and opposite in direction to the one that the moon exerts on the earth.

The gravitational force the moon and the earth exert on each other are equal.

According to Newton's third law of motion, action and reaction are equal and opposite.

The gravitational force the earth exerts on the moon is equal in magnitude but opposite in direction to the gravitational force the moon exerts on the earth.

The magnitude of the gravitational force between the moon and the earth is calculated as follows;

[tex]F = \frac{GM_e M_m}{R^2}[/tex]

Thus, the gravitational force the moon and the earth exert on each other are equal.

Learn more about  gravitational force here: https://brainly.com/question/17301500

Calculate the magnitude of the normal force acting on a 20 kg block the block is resting on the surface of an elevator accelerating 2.5m/s

Answers

Answer:

Fn = 246.2 N

Explanation:

I assume you meant meters per second squared for acceleration of the elevator.  All you have to after your picture/free-body diagram is made is add the forces together.  You could do this by finding them separately like I did or use Fn = m(Fg + Fe). I just calculated magnitude and didn't worry about signs.

A train traveling at 27.5 accelerates to 42.4 m s over 75.0 s What is the displacement of the train in this time period A train traveling at 27.5 m/s accelerates to 42.4 m/s over 75.0 s. What is the displacement of the train in this time period

Answers

Answer:

The displacement of the train in this time period is 2,616.86 m.

Explanation:

A Uniformly Varied Rectilinear Motion is Rectilinear because the mobile moves in a straight line, Uniformly because of there is a magnitude that remains constant (in this case the acceleration) and Varied because the speed varies, the final speed being different from the initial one.

In other words, a motion is uniformly varied rectilinear when the trajectory of the mobile is a straight line and its speed varies the same amount in each unit of time (the speed is constant and the acceleration is variable).

An independent equation of useful time in this type of movement is:

[tex]vf^{2} =vi^{2} +2*a*d[/tex] Expression A

where:

vf = final velocity vi = initial velocity a = acceleration d = distance

The equation of velocity as a function of time in this type of movement is:

vf=vi + a*t

So the velocity can be calculated as: [tex]a=\frac{vf-vi}{t}[/tex]

In this case:

vf=42.4 m/svi=27.5 m/st=75 s

Replacing in the definition of acceleration:  [tex]a=\frac{42.4 m/s-27.5 m/s}{75 s}[/tex]

a=0.199 m/s²

Now, replacing in expression A:

[tex](42.4 m/s)^{2} =(27.5 m/s)^{2} +2*(0.199 m/s^{2}) *d[/tex]

Solving:

[tex]d= \frac{(42.4 m/s)^{2} - (27.5 m/s)^{2} }{2*(0.199 m/s^{2}) }[/tex]

d= 2,616.86 m

The displacement of the train in this time period is 2,616.86 m.

If the equal tensions T in the pulley cable are 300 N, express in vector notation the force R exerted on the pulley by the two tensions. Determine the magnitude of R.

Answers

Answer:

[tex]R=519.61N[/tex]

Explanation:

From the question we are told that

Tension T on a cable are T=300N

Generally the tensions on a pulley is

       [tex]\sum f_x=T+T*cos(\theta)[/tex]

Therefore

      [tex]\sum f_x=300+300*cos(60)[/tex]

      [tex]\sum f_x=300 *1.5[/tex]

      [tex]\sum f_x=450N[/tex]

Hence

      [tex]T*sin(60) = 259.81N[/tex]

     [tex]R= 450\=i +259.81\=i[/tex]

     [tex]R=\sqrt{450^2+259.8^2}[/tex]

     [tex]R=519.61N[/tex]

Callisto is a moon of Jupiter (mass = 1.90 x 1027 kg), which orbits the planet with a period of 16.9 days. What is the radius of its orbit?​

Answers

The radius of its orbit = 8.27 x 10¹³ m

Further explanation

Given

mass Jupiter=1.9 x 10²⁷ kg

T = 16.9 days=1.46 x 10⁶ s

Required

the radius =r

Solution

To hold the moon in its orbit, the gravitational force between two objects (jupiter and moon) will be equal to the centripetal force

[tex]\tt G\dfrac{M.m}{r^2}=m.\dfrac{v^2}{r}\rightarrow v=\dfrac{2.\pi.r}{T}\\\\M=\dfrac{r^3.4\pi^2}{T^2.G}\rightarrow r^3=\dfrac{GMT^2}{4\pi^2}[/tex]

G = 6.67 x 10⁻¹¹ N/m²kg²

Input the value :

[tex]\tt r^3=\dfrac{6.67\times 10^{-11}\times 1.9\times 10^{27}\times (1.46\times 10^6)^2}{4\pi^2}\\\\r^3=6.85\times 10^{27}\rightarrow r=8.27\times 10^{13}[/tex]

Answer:

1.9 x [tex]10^{9}[/tex]

Explanation:

I WILL NEVER USE THIS APPP AGAIN I JUST GOT A 63 PPERCENT OFF PEOPLES ANSWERS AND GOT A 63% WHAT IS THAT

Answers

Answer:

You should still use the app if you need it, but you definitely shouldn't rely on it. It's really good for what it is, but it's not an alternative to actually taking the test, just imagine what you would have gotten if you didn't use this

Explanation:

I don't understand your statement but, are you saying that you just got 63% positive rating of your answer to people's answers? Maybe you answer is either correct or somehow incorrect or maybe others answer is more applicable answer compared to yours BUT thanks for the free points! Btw could you mark this as brainliest? Thanks

how was fibre optics made​

Answers

The first working fiber-optic data transmission system was demonstrated by German physicist Manfred Börner at Telefunken Research Labs in Ulm in 1965, which was followed by the first patent application for this technology in 1966. In 1968, NASA used fiber optics in the television cameras that were sent to the moon.

A 2.0 m conductor is formed into a square and placed in the horizontal A magnetic field is oriented above the horizontal with a strength of 1.0 T. What is the magnetic flux through the conductor

Answers

Answer:

4.0Wb/m²

Explanation:

Magnetic flux Ф is expressed using the formula;

Ф = BA

B is magnetic field

A is the area of the square conductor

Given

B = 1.0T

A =L²

Area A = 2.0² = 4.0m²

Get the magnetic flux

Ф = 1.0 * 4.0m²

Ф = 4.0Wb/m²

Hence the magnetic flux through the conductor is 4.0Wb/m²

It takes 80 J to push a large box 8 m across a floor. Assuming the push is in the same direction as the move, what is the magnitude of the force on the box?

Answers

Answer:

10 N

Explanation:

The magnitude of the force on the box can be found by using the formula

[tex]f = \frac{w}{d} \\ [/tex]

w is the workdone

d is the distance

From the question we have

[tex]f = \frac{80}{8} \\ [/tex]

We have the final answer as

10 N

Hope this helps you

Answer:

10

Explanation:

80 divided 8 =10

What is the velocity of a sound wave that has a frequency of 300 Hz and a wavelength of 10
m?

Answers

Answer:

3000 m/s

Explanation:

We can use the equation velocity of a wave equals wavelength times  frequency.  Therefore, v = wavelength*f = (10 m)(300 Hz) = 3000 m/s

I hope this helps! :)

Which of these quantities impact centripetal force?
A.mass and speed only
B.mass and radius only
C.speed and radius only
D.mass, speed, and radius all impact centripetal force

Answers

Answer: D) Mass, speed and radius all impact the centripetal force

Explanation:

If we change either the mass, speed, and/or radius, then the centripetal force will be different. Though on rare occasions we could change the variables together in a way to have the centripetal forces line up, but in general the before and after forces will likely be different. Changing one variable at a time only will definitely result in a different centripetal force.

This is because the centripetal force F is determined by the formula

F = (m*v^2)/r

where,

m = mass

v = velocity

r = radius

A plane is flying horizontally with speed
162 m/s at a height 3970 m above the ground,
when a package is dropped from the plane.
2
Neglecting air resistance, when the package hits the ground, the plane will be
1. directly above the package. 2. ahead of the package.
3. behind the package.

Answers

Answer:

2. ahead of the package.

Explanation:

Using y' - y = ut - 1/2gt², we find the time, t it takes the package to hit the ground. So, u = initial vertical velocity of package = 0 m/s, y = initial position of package = 3970 m, y' = final position of package = 0 m, g = acceleration due to gravity = 9.8 m/s².

Substituting the variables into the equation, we have

y' - y = ut - 1/2gt²

0 m - 3970 m = 0t - 1/2 × (9.8 m/s²)t²

-3970 m = -(4.9m/s²)t²

t² = -3970 m ÷ -4.9 m/s²

t² = 810.2 s²

t = √810.2 s²

t = 28.5 s

Using v = u' + at, we find the horizontal acceleration of the plane. Since the initial horizontal velocity of the package is that of the plane, u' = 162 m/s, v = 0 m/s since the package stops and t = 28.5 s when the package stops.

So, a = (v - u')/t

a = (0 m/s - 162 m/s)/28.5 s

a = -162 m/s/28.5 s

a = -5.68 m/s²

Using v² = u'² + 2as, we find the horizontal distance ,s where the package stops.

So, s =  (v² - u'²)/2a

Substituting the values of the variables, we have

s =  ((0 m/s)² - (162 m/s)²)/(2 × -5.68 m/s²)

= - 162 m²/s²/(-11.36 m/s²)

= 14.26 m

The horizontal distance d the plane moves after releasing the package is d = u't = 162 m/s × 28.5 s = 4617 m

Since d = 4617 m > s = 14.26 m, the plane would be ahead of the package when the package hits the ground.

Which is a source of thermal energy for a heat pump?
•air
•fire
•sunlight
•coal

Answers

Answer:

its air

give me thanks

Answer:

Air

Explanation:

give me a thanks its 100% right

what is Newton's Laws

Answers

Answer:

Explanation:

Newton's laws of motion are three physical laws that, together, laid the foundation for classical mechanics. They describe the relationship between a body and the forces acting upon it, and its motion in response to those forces. “

n a double-slit experiment, the slit separation is 6.03x10-5 meters. The slits are illuminated with a laser beam of wavelength 5.37x10-7 meters. A screen is located 2.14 m from the slits. Calculate the distance on the screen from the first dark fringe on one side of the central maximum to the second dark fringe on the other side.

Answers

Answer:

D = 3.81 x 10⁻² m = 3.81 cm

Explanation:

We can use the formula of fringe spacing from Young's Double Slit experiment to answer this question:

[tex]\Delta x = \frac{\lambda L}{d}\\[/tex]

where,

Δx = distance between two consecutive dark fringes

λ = wavelength of light beam = 5.37 x 10⁻⁷ m

L = Distance between screen and slits = 2.14 m

d = slit separation = 6.03 x 10⁻⁵ m

But, we need the distance between first dark fringe on 1 side to 2nd dark fringe on other side. It means we need twice the distance between two dark fringes:

[tex]D = 2\Delta x = 2\frac{\lambda L}{d}\\[/tex]

where,

D = distance between first dark fringe on one side and 2nd dark fringe on other side of central maximum = ?

Therefore,

[tex]D = \frac{(2)(5.37\ x\ 10^{-7} m)(2.14\ m)}{6.03\ x\ 10^{-5}\ m }[/tex]

D = 3.81 x 10⁻² m = 3.81 cm

Jill leaves home and rides a distance of 70 km. It took her 2.5 hours. What is her speed?

Answers

the answer is ...
28 km per hour

In the equation for Newton's 2nd Law
of Motion, F = ma, "a" represents
O area
O acceleration
atomic number

Answers

Answer:

In the formula, F = m×a, where a represents acceleration.

Answer:

Force=mass times acceleration

Explanation:

The components of vectors A and B are given as follows:

Ax = 7.6

Bx = -5.1

Ay = -9.2

By = -6.8

What is the magnitude of the vector difference B - À?

Answers

Answer:

|B - A| = 12.92 units

Explanation:

In order to find the magnitude of B-A vector, we first write A and B in Vector Notation:

A = Aₓ i + Ay j

A = 7.6 i - 9.2 j

B = Bₓ i + By j

B = -5.1 i - 6.8 j

So, there difference will be:

B - A = (-5.1 i - 6.8 j) - (7.6 i - 9.2 j)

B - A = -12.7 i + 2.4 j

Now, the magnitude of this vector can be found out by using the formula:

|B - A| = √[(x-component)² + (y-component)²]

|B - A| = √[(-12.7)² + (2.4)²]

|B - A| = 12.92 units

We will see that the magnitude of the difference of the vectors is 12.92

How to get the difference of two vectors?

Here we have two vectors:

A = <7.6, -9.2>

B = <-5.1, -6.8>

To get the difference we just subtract the correspondent components:

B - A = <Bx - Ax, By - Ay> = <-5.1 - 7.6, -6.8 - (-9.2)> = <-12.7, 2.4>

The magnitude of that vector is just:

[tex]M = \sqrt{(2.4)^2 + (-12.7)^2} = 12.92[/tex]

If you want to learn more about vectors, you can read:

https://brainly.com/question/4889980

the maximum value of magnetic in an electric field 3.2 *10^4​

Answers

Answer:

the answer is 12 because if your magnetic value and Electric field is 3.2 the answer will be 12

How do gamma rays use electromagnetic waves to function....PLS HELP

Answers

Answer:

Gamma-rays have the smallest wavelengths and the most energy of any other wave in the electromagnetic spectrum. These waves are generated by radioactive atoms and in nuclear explosions.

Explanation:

Gamma-rays can kill living cells, a fact which medicine uses to its advantage, using gamma-rays to kill cancerous cells.

Hope this helps!

Brain-LIst?

1. Towards the end of a 400m race, Faisal and Edward are leading and are both running at 6m/s. While Faisal is 72m from the finish line Edward is 100m from the finish line. Realising this and to beat Faisal, Edward decides to accelerate uniformly at 0.2 m/s2 until the end of the race while Faisal keeps on the same constant speed. Does Edward succeed in beating Faisal?

Answers

Answer:

  no

Explanation:

Faisal will finish the race in ...

  (72 m)/(6 m/s) = 12 s

In order to beat Faisal, Edward's average speed in those 12 seconds must exceed ...

  (100 m)/(12 s) = 8 1/3 m/s

To achieve that average speed, Edward's acceleration must be ...

  (8 1/3 m/s -6 m/s)/(12 s/2) = 7/18 m/s² ≈ 0.3889 m/s²

Accelerating at only 0.2 m/s², Edward will not beat Faisal.

_____

Additional comment

When acceleration is uniform, the average speed is reached halfway through the period of acceleration.

who win tug of war with what net force

Answers

Answer:

The force on rope is equal for both of them at any time.

For winning the game the force on ground is responsible.

Explanation:

I need help! what are some sentences that help me explain Explain the process that creates wind?

Answers

Answer:

Explanation:

Wind is air in motion. It is produced by the uneven heating of the earth's surface by the sun. Since the earth's surface is made of various land and water formations, it absorbs the sun's radiation unevenly. Two factors are necessary to specify wind: speed and direction.

If ball 4 has a mass of 2 kg and it is 5m high, what will be its gravitational potential energy? (g=10 N/kg) *

Answers

Explanation:

Gravitational potential energy

= mgh

= (2kg)(10N/kg)(5m)

= 100J.

Answer:

[tex]\boxed {\boxed {\sf 100 \ Joules}}[/tex]

Explanation:

Gravitational potential energy can be found using the following formula.

[tex]E_p=m*g*h[/tex]

where m is the mass, g is the gravitational acceleration, and h is the height.

The mass of the ball is 2 kilograms, its height is 5 meters, and the acceleration due to gravity is 10 Newtons per kilogram.

[tex]m= 2 \ kg \\h= 5 \ m \\g= 10 \ N/kg[/tex]

Substitute the values into the formula.

[tex]E_p=(2 \ kg)(10 \ N/kg)(5 \ m)[/tex]

Multiply the first 2 numbers. The kilograms (kg) will cancel out when multiplying.

[tex]E_p=(20 \ N)(5 \ m)[/tex]

Multiply again.

[tex]E_p=100 \ N*m[/tex]

1 Newton meter is equal to 1 Joule Therefore, 100 N*m= 100 J

[tex]E_p= 100 \ J[/tex]

The gravitational potential energy of the ball is 100 Joules.

If you drop a toy sheep from the roof of a building 30 m high, how much does the magnitude of the velocity increase each second that it falls? PLEEAAASEEEEE HELP IM TAKING A PHYSICS FINAL AS WE SPEAK

Answers

Answer:

See the explanation below

Explanation:

No matter at what height a body is dropped, the body will always accelerate to the same reason, which corresponds to Earth's gravitational acceleration.

g = 9.81 [m/s²]

That is, in the first second the velocity is 9.81 [m/s] = 9.81 [m/s²] x 1 [s]

Now in the second 2; 19.62 [m/s²] = 9.81 [m/s²] x 2 [s]

And in the third second 29.43 [m/s²] = 9.81 [m/s²] x 3 [s]

And etc.

An auto, moving too fast on a horizontal stretch of mountain road, slides off the road, falling into deep snow 43.9 m below the road and 87.7 m beyond the edge of the road. How fast was it going when it left the road?

Answers

Ok so it is 42.8 because if you - 43.9 by 1.1 by the way don’t listen to any of the I just want point

The speed with which the auto was going when it left the road will be 29.3 m/s.

What is Acceleration?

Acceleration is the rate of change of velocity of an object. Acceleration is a vector quantity as it has both the magnitude and direction. The SI unit of acceleration is meter per second square.

From the given question, we can deduce that the only force which will be acting on the car is the gravitational force and as such the acceleration during free fall of the object will be equal to the acceleration due to gravity acting on the object however, this will be negative since it is towards the ground surface.

Thus, acceleration of the auto = - 9.8 m/s²

The time in which the auto falls will be,

t² = 2 × s/ a

t² = 2 × -43.9/ -9.80

t² = 8.95

t =[tex]\sqrt{8.95}[/tex]

t = 2.99 seconds

The velocity with which the auto will be going when it left the road will be,

Velocity = Displacement/ Time

Velocity = 87.7/ 2.99

Velocity = 29.3 m/s

Therefore, the velocity with which the auto will be moving when it left the road will be 29.3 meters per second.

Learn more about Acceleration here:
https://brainly.com/question/12550364

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Witch force is represented by arrow at c?

Answers

Answer:

did u know there's no such thing as "pear cider."

Explanation:

Other Questions
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