Waves that hit a fixed boundary return to the starting point on the____
side that it began

A.Opposite

B.same

Answer:

the conflict in this passage is

Tony worries about how to fight Felix without hurting him.

it right i just took the test

The conflict sentence in the passage is, Tony worries about how to fight Felix without hurting him.

    Conflict can be meant as clash happened between one another of different individuals and they used to arise out for one's own process, their way of understanding and their interests and also it depends upon everyone's perception. Also, conflicts leads to physical abuse.

In the given sentences,

A. Tony worries about how to fight Felix without hurting him.

    Here, there is a point to thinking  about no physical abuses and loss of peace and harmony.

B. Tony cannot figure out how to get down from the roof.

   In the above sentence Tony was just thinking an idea about how to come down from the roof. There will not be any clashes.

C. Tony no longer wants to be friends with Felix.

    The above sentence was only about the relationship of Tony and Felix.

D. Tony wants to figure out a way for both of them to win.

    This sentence is completely in the positive approach to attain success.

So, the correct answer is option A.

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Answer:

-929.5Joules

Explanation:

To get the work done by sam, we will calculate the kinetic energy of sam expressed as;

KE = 1/2mv²

m is the mass = 1100kg

v is the velocity = 1.3m/s

KE = 1/2(1100)(1.3)²

KE = 550(1.69)

KE = 929.5Joules

Since Sam is opposing the direction of movement, work done by him will be a negative work i.e -929.5Joules

Answer:

it will burn up in the Earth's atmosphere.

Explanation:

The structure of the Earth's atmosphere protects the surface from frequent meteoroid strikes. As a meteoroid enters the atmosphere from outer space, it moves at very high speeds. At such speeds, intense amounts of friction and heat result. This process usually causes small meteoroids to burn up in the Earth's atmosphere before ever reaching the surface.

Answer:

[tex]V_1= 3.4*10^7m/s[/tex]

Explanation:

From the question we are told that

Nucleus diameter [tex]d=5.50-fm[/tex]

a 12C nucleus

Required kinetic energy [tex]K=2.30 MeV[/tex]

Generally initial speed of proton must be determined,applying the law of conservation of energy we have

            [tex]K_2 +U_2=K_1+U_1[/tex]

where

[tex]K_1[/tex] =initial kinetic energy

[tex]K_2[/tex] =final kinetic energy

[tex]U_1[/tex] =initial electric potential

[tex]U_2[/tex] =final electric potential

mathematically

   [tex]U_2 = \frac{Kq_pq_c}{r_2}[/tex]

where

[tex]r_f[/tex]=distance b/w charges

[tex]q_c[/tex]=nucleus charge [tex]=6(1.6*10^-^1^9C)[/tex]

[tex]K[/tex]=constant

[tex]q_p[/tex]=proton charge

Generally kinetic energy is know as

         [tex]K=\frac{1}{2} mv^2[/tex]

Therefore

         [tex]U_2 = \frac{Kq_pq_c}{r_2} + K_2=\frac{1}{2} mv_1^2 +U_1[/tex]

Generally equation for radius is [tex]d/2[/tex]

Mathematically solving for radius of nucleus

         [tex]R=(\frac{5.50}{2}) (\frac{1*10^-^1^5m}{1fm})[/tex]

         [tex]R=2.75*10^-^1^5m[/tex]

Generally we can easily solving mathematically substitute into v_1

   [tex]q_p[/tex][tex]=6(1.6*10^-^1^9C)[/tex]

   [tex]K_1=9.0*10^9 N-m^2/C^2[/tex]

   [tex]U_1= 0[/tex]

   [tex]R=2.75*10^-^1^5m[/tex]

   [tex]K=2.30 MeV[/tex]

   [tex]m= 1.67*10^-^2^7kg[/tex]

   [tex]V_1= (\frac{2}{1.67*10^-^2^7kg})^1^/^2 (\frac{(9.0*10^9 N-m^2/C^2)*(6(1.6*10^-^1^9C)(1.6*10^-^1^9C)}{2.75*10^-^1^5m+2.30 MeV(\frac{1.6*10^-^1^3 J}{1 MeV}) }[/tex]

    [tex]V_1= 3.4*10^7m/s[/tex]

Therefore the proton must be fired out with a speed of [tex]V_1= 3.4*10^7m/s[/tex]

Answer:

what is 30 + 40 add

Answer:

Explanation:

The work done by an object can be found by using the formula

workdone = force × distance

From the question we have

workdone = 9 × 11

We have the final answer as

Hope this helps you

A blue "H" means a center of high pressure (usually calm, sunny weather). A red "L" means low pressure (which can mean storminess). Most fronts extend from low-pressure centers.

The weather symbol blue 'H' represents high pressure while red 'L' represents Low pressure.

Weather symbols can be described as symbols with which meteorologists indicate various atmospheric and natural conditions on special weather maps such as temperature, pressure, precipitation, wind, or the percentage of cloud coverage in the sky. These maps can be used to be paper maps or digital.

Warm fronts can be described as indicated by curved red lines with red semicircles. Cold fronts can be curved blue lines with blue triangles. Stationary fronts exhibit alternating red curves with semicircles and blue curves with triangles. There are 99 present weather symbols used in meteorology.

The eight elements observed by meteorologists for creating weather forecasts are air temperature, humidity, wind speed, wind direction, visibility, clouds, precipitation, and atmospheric pressure.

On weather maps, readings are represented as a red “L” for low pressure or a blue “H” for high pressure.

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Answer:

applied force

Explanation:

I think that's right

Answer:

I believe it is C, Potential

Explanation:

Google, since all types are either kinetic or potential, so it wouldn't make sense if kinetic was itself. I also know for a fact it isn't Chemical

Answer:

The correct option is C: 0.31 s.

Explanation:

When the mass is then suddenly released we have:

[tex] F = k\Delta y [/tex]

Where:

F is the force

k: is the spring constant

Δy: is the spring displacement

Since the tension in the spring is zero, the force is the weight:

[tex] F = mg [/tex]

Where:

m is the mass of the object

g is the gravity

[tex] mg = k\Delta y [/tex]    (1)

The oscillation period of the spring is given by:

[tex] T = 2\pi \sqrt{\frac{m}{k}} [/tex]    (2)

By solving equation (1) for "k" and entering into equation (2) we have:

[tex] T = 2\pi \sqrt{\frac{m}{\frac{mg}{\Delta y}}} [/tex]

[tex]T = 2\pi \sqrt{\frac{\Delta y}{g}}[/tex]

Since the spring will osclliates in a position between the initial position (when it is at rest) and the final position (when the mass is released and reaches the bottom), we have Δy = 2.5 cm = 0.025 m:

[tex] T = 2\pi \sqrt{\frac{0.025 m}{10 m/s^{2}}} = 0.31 s [/tex]                   

Hence, the oscillation period is 0.31 s.

The correct option is C: 0.31s.

I hope it helps you!                                                                                                      

Answer:    

Two ways carbon can get from the ocean to the lithosphere is through the marine plants + animals (in the ocean) , sediments, petroleum then to the lithosphere.

Hope that helps!

Answer:

Muscular energy

Explanation:

Hope it helps!!!!

Answer:

A. The core makes up the majority of Earth's volume.

Explanation:

Although the core and mantle are about equal in thickness, the core actually forms only 15% of earth's volume whereas the mantle takes up 84%

Answer:

Compression- a region in a longitudinal (sound) wave where the particles are closest together. Rarefaction- a region in a longitudinal (sound) wave where the particles are furthest apart.

Answer:

please mark as brainliest!!!!

Explanation:

Compression- a region in a longitudinal (sound) wave where the particles are closest together.

Rarefaction- a region in a longitudinal (sound) wave where the particles are furthest apart.

Answer:A road sign gives drivers informaton about traffic on busy highways. One sign shows 15 miles in 20 minutes. What is this speed in miles per hour?

Explanation:

Complete Question

What is the minimum number of 20-amp 277-volt branch circuits required where 810 incandescent luminaries are to be installed?The  lamps to be installed are rated 75 watts at 277 volts. This is NOT a continuous load so each circuit can carry 20 amps maximum

Answer:

The number is  [tex]k = 11[/tex]

Explanation:

From the question we are told that

     The current is  [tex]I = 20 \ A[/tex]

     The voltage is  [tex]V = 277 \ volt[/tex]

     The power rating of each bulb is  [tex]P = 75 \ W[/tex]

      The total number of  incandescent luminaries is [tex]n = 810[/tex]

Generally the amount of current each lamp takes is mathematically represented as

       [tex]I_e = \frac{P}{ V}[/tex]

=>    [tex]I_e = \frac{75}{ 277}[/tex]

=>    [tex]I_e = 0.270 \ A[/tex]

Generally the number of bulb fitting(i.e bulbs )  a  20 A current can supply (i.e the bulbs the branch ) to is

                    [tex]N = \frac{I}{I_e}[/tex]

=>                 [tex]N = \frac{20 }{ 0.270 }[/tex]

=>                 [tex]N = 73.86[/tex]

Generally the number of 20-amp 277-volt branch circuits required is mathematically represented as

          [tex]k = \frac{n}{N}[/tex]

=>       [tex]k = \frac{810}{73.86}[/tex]

=>       [tex]k = 11[/tex]

Answer: Ain't its because how light the feather is ? It's not as heavy.

Explanation: With air resistance, acceleration throughout a fall gets less than gravity (g) because air resistance affects the movement of the falling object by slowing it down. ... Usually, resistance is not very high at low speed or for small or sharp objects (Google Source if needed to prove yours answer)

Answer:

83.168 Nm

Explanation:

I=mass of bat* ( length )^2 /3

Moment of inertia from one end = 2.2 * (0.96)^2 / 3.

Ang. acc. = 2.2×2 pi / 0.2 = 22pi

Torque =  2.3 * (0.96)^2 / 3 * 22 pi = 83.168 Nm SI units

Unless you have a diagram to include or any other additional info, I'll assume the block is being pulled by two opposing forces along the horizontal surface.

Horizontally, the block is under the influence of

• one rope pulling in one direction with magnitude 15 N,

• the other rope pulling in the opposite direction with mag. 5 N, and

• friction, opposing the direction of the block's motion, with mag. 3 N.

It stands to reason that the block is accelerating in the direction of the larger pulling force.

(A) By Newton's second law, we have

15 N + (-5 N) + (-3 N) = m (1 m/s²)

where m is the mass of the block. Solve for m :

7 N = m (1 m/s²)

m = (7 N) / (1 m/s²)

m = 7 kg

(B) The friction force is proportional to the normal force, so that if f is the mag. of friction and n is the mag. of the normal force, then f = µ n where µ is the coefficient of friction.

The block does not bounce up and down, so its vertical forces are balanced, which means the normal force and the block's weight (mag. w) cancel out:

n + (-w) = 0

n = w

n = m g

where g = 9.8 m/s² is the mag. of the acceleration due to gravity.

n = (7 kg) (9.8 m/s²)

n = 68.6 N

Then

3 N = µ (68.6 N)

µ = (3 N) / (68.6 N)

µ ≈ 0.044

Answer:

0.3 seconds

Explanation:

When we walk, our legs alternatively swing forward about the hip joint as a pivot. In this motion the leg is acting approximately as a physical pendulum. Treating the leg as a thin uniform rod of length 0.80 m,

To find the time it takes for the leg to swing forward, where g = 9.8 m/s^2

Let's use the simple pendulum formula which says that:

T = 2π( sqrt ( L/g))

T = 2π[sqrt (0.8/9.8)]

T = 2π × 0.082

T = 0.5129

For the leg to swing forward only, the number of complete oscillations will be half.

Period T = time t ÷ number of complete oscillations. That is,

T = t ÷ 1/2

0.5129 = t ÷ 1/2

t = 0.5129 × 1/2

Time t = 0.256 seconds.

Therefore, the time it takes for the leg to swing forward is 0.3 seconds approximately

Answer:

B. Q/2

Explanation:

Given;

charge of the two particles, = -Q

distance between the two charges, r = L

the net force experienced by each charge = F

Apply coulomb's force between two charged particles;

[tex]F = \frac{KQ^2}{r^2} = \frac{kQ^2}{L^2}[/tex]

when

+q is introduced midway between the charges, the net force is reduced by 2

[tex]\frac{F}{2} = \frac{kQq}{L^2} \\\\ \frac{1}{2}(\frac{kQ^2}{L^2} ) = \frac{kQq}{L^2}\\\\\frac{kQ^2}{2L^2} =\frac{kQq}{L^2} \\\\\frac{Q}{2} = q[/tex]

Thus, The value of q is Q/2

The value of q is Q/2, when the net electric force experienced by each negatively charged particle is reduced to F/2.

Given here,  

-Q = charge of the two particles  

r = distance between the two charges = L  

F = net force on each charge  

From coulomb's force between two charged particles;

[tex]\bold{F = \dfrac {KQ^2}{r^2} =\dfrac {kQ^2}{L^2} }[/tex]

If +q is bring at mid point between the charges, the net force is reduced by 2

Thus, q = Q/2

Therefore,   the value of q is Q/2, when the net electric force experienced by each negatively charged particle is reduced to F/2.

Answer:

A) 7kg

B) 0.044

Explanation:

a) Accordimg to Newton's second law

\sum F = ma

Fm - Ff = ma

Fm is moving force =15-5 = 10N

Ff is fictional force = 3N

m is the mass = ?

a Is the acceleration = 1m/s²

Substitute

10-3 = 1m

7 = m

Hence the mass of the body is 7kg

b) coefficient of friction is expressed as;

n = Ff/R

R is the reaction = mg

n =Ff/mg

Substitute

n = 3/7(9.8)

n = 3/68.6

n = 0.044

Hence the coefficient of friction is 0.044

Answer:

B.

Explanation:

Answer:The value of the angle from vertical of the axis of the second polarizing filter is equal to 30.2°

Explanation:

Answer:

true

Explication:

The acceleration of an object depends on the mass of the object, and the amount of force applied

Answer: the absolute value of the phase angle is 28°

Explanation:

taking a look at expression for the instantaneous electric power in an AC circuit;

P = VI -------let this be equation 1

p is power, v is voltage and I is current;

for maximum power

P_max = V_rms × I_rms --------let this be equ 2

where P_max is the maximum power, V_rms is the rms value of voltage and I_rms is the rms value of current.

Also for average electric power in an AC circuit

P_avg = V_rms × I_rms × cos²∅ -------let this be equ 3

where P_avg is the average power and cos∅ is the power factor

now from equation 2;  P_max = V_rms × I_rms

so p_max replaces V_rms × I_rms in equation 3

we now have

P_avg = P_max × cos²∅

so we substitute

expression for the given value of the average power is

P_avg = P_max × 75%

p_avg = P_max.78/100

for the expression of the average electricity in an AC circuit

P_max.78/100 = P_max × cos²∅

78/100 = cos²∅

to get the absolute value of phase angle

∅ = cos⁻¹ ( √(78/100))

∅ =  cos⁻¹ ( 0.8832)

∅ = 27.969 ≈ 28°

Therefore the absolute value of the phase angle is 28°

We have that for the Question "For what absolute value of the phase angle does a source deliver 71 % of the maximum possible power to an RLC circuit"

It can be said that

Power delivered to RLC circuit is given by

[tex]P = \frac{V^2}{Z}cos\theta\\\\P = I^2Zcos\theta[/tex]

Therefore,

[tex]Z = \sqrt{R^2 + (X_L-X_C)^2}[/tex]

Power delivered is maximum, therefore,

[tex]P_{max} = cos\theta\\\\71\% = cos\theta\\\\cos\theta = 0.71\\\\\theta = cos^{-1}0.71\\\\\theta = 44.76^o\\\\approximately 45^o[/tex]

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Answer:

Planets that are close to the sun have shorter years, and planets that are farther have longer years, because of how fast/slow it orbits the sun.

Explanation:

Answer:

a) True

b)False

c)False

• Had to complete the question first.

A block slides at constant speed down a ramp while acted on by three forces: its weight, the normal force, and kinetic friction. Respond to each statement, true or false.

(a) The combined net work done by all three forces on the block equals zero.

(b) Each force does zero work on the block as it slides.

(c) Each force does negative work on the block as it slides.

Explanation:

Net work is the change in kinetic energy, which leads to final kinetic energy - our initial kinetic energy this is the formula for net work. This is the working energy theorem, a theorem that states that the net work on an object induces a change in the object's kinetic energy.

Answer:

α = -0.47 rad/sec²

Explanation:

        [tex]\omega^{2}_{f} - \omega^{2}_o} = 2* \alpha* \Delta \theta (1)[/tex]

       [tex]\omega_{o} = 850 rev/min * \frac{2*\pi rad}{rev} * \frac{1min}{60 sec} = 89 rad/sec (2)[/tex]

      [tex]\Delta \theta = 1350 rev *\frac{2*\pi rad}{1rev} = 8482.3 rad (3)[/tex]

       [tex]\alpha = \frac{-\omega_{o}^{2} }{2*\Delta\theta} = -0.47 rad/sec2 (4)[/tex]