What are some assumptions and observations of this map, relating to the use of relations and polynomials?

We have to find the molarity of a solution of Magnesium Fluoride. The definition of molarity is:

Molarity = moles of solute/Volume of solution in L

Our solute is MgF₂:

Molarity = moles of MgF₂ / L of solution

From the problem we know that the volume of the solution that the chemist prepared is 250. mL, we will have to convert that into L.

We know that there are 1000 mL in 1 L. So:

1 L = 1000 mL

250. mL = 250. mL * 1 L/1000 mL = 0.250 L

Volume of solution in L = 0.250 L

Now we have to find the number of moles of MgF₂ that the chemist added. From the problem we know the mass of MgF₂ added. Let's convert it to g:

1000 mg = 1 g

mass of MgF₂ = 6-73 mg

6.73 mg = 6.73 mg * 1 g/1000 mg = 0.00673 g

mass of MgF₂ = 0.00673 g

When we want to find the number of moles that we ave in a certain amount of a compound, we have to use the molar mass. Let's find the molar mass of MgF₂.

According to the periodic table the atomic mass of Mg is 24.3 amu and the atomic mass of F is 19 amu. So the molar mass of MgF₂ is:

molar mass of MgF₂ = 24.3 + 2 * 19 = 62.3 g/mol

molar mass of MgF₂ = 62.3 g/mol

Using the molar mass we can find the number of moles that we have in 6.73 mg or 0.00673 g of MgF₂:

moles of MgF₂ = 0.00673 g/(62.3 g/mol)

moles of MgF₂ = 1.08 * 10^-4 moles

So the chemist added 1.08 * 10^-4 moles of MgF₂ in 0.250 L of solution. Then the molarity of the solution is:

Molarity = moles of solute/Volume of solution in L

Molarity = 1.08 * 10^-4 moles/0.250 L

Molarity = 4.32 * 10^-4 M

So the answer to our problem is 4.32 * 10^-4 M

The number of grams of calcium fluoride in 1.5 moles of calcium fluoride is 88.5grams.

The mass of a substance or compound can be calculated by multiplying the number of moles of the substance by its molar mass as follows:

mass = no of moles × molar mass

According to this question, there are 1.5 moles of calcium fluoride (CaF). The molar mass of calcium fluoride can be calculated as follows:

CaF = 40g/mol + 19g/mol = 59g/mol

mass = 59g/mol × 1.5mol

mass = 88.5grams.

Therefore, 88.5grams of calcium fluoride is present in 1.5 moles of the compound.

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the heat energy required to take it to the melting point is 420J.

The heat capacity, abbreviated Cp, is the amount of heat needed to elevate a mole of a substance's heat content by precisely one degree Celsius.

A material has more thermal energy the hotter it is, says basic thermodynamics. Additionally, when a chemical is present in greater concentrations at a particular temperature, it will have a higher total thermal energy.

Mathematically,

Q = mc∆T

Where,

Q = quantity of heat absorbed by a body

m = mass of the body

∆t = Rise in temperature

C = Specific heat capacity of a substance depends on the nature of the material of the substance.

S.I unit of specific heat is J kg-1 K-1.

Given,

An ice cube of mass = m=25g

initial temperature = T1 = -8°C

final temperature = T2 = 0°C

Heat capacity for solid water = c = 2.1J/g°C

According to heat energy required to take it to the melting point,

Q = mc∆T

Q = 25g×2.1J/g°C × (0+8) °C

Q = (25×2.1×8) J

Q = 420J

Hence, the heat energy required to take it to the melting point is 420J.

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In this question, we have to find the total pressure in the container that has 758 mmHg of pressure of cyclopropane, and 0.483 atm of pressure of Oxygen, the answer must be provided in torr:

First thing we need to do is to transform mmHg of cyclopropane to atm

1 atm = 760 mmHg

x atm = 758 mmHg

x = 0.997 atm of pressure of cyclopropane

Now that we have both pressures in atm, we can add them and then we will find the total pressure:

Ptotal = PO2 + Pcyclo

Ptotal = 0.483 + 0.997

Ptotal = 1.48 atm of total pressure

To transform to torr:

1 atm = 760 torr

1.48 atm = x torr

x = 760 * 1.48

x = 1125 torr of pressure is the total pressure

Answer

mass of oxygen = 22.54 g

Explanation

Given:

4 Fe + 3 O2 = 2 Fe2O3

Mass of Fe203 = 75 g

Required: Mass of O2

We know:

Molar mass of Fe2O3 = 159,69 g/mol

Molar mass of O2 = 31.998 g/mol

Solution:

Step 1: Calculate the moles of Fe2O3

n = m/M where n is the moles, m is the mass and M is the molar mass

n = 75g/159,69 g/mol

n = 0.469 mol

Step 2: Use the stoichiometry to find the moles of O2

The molar ratio between Fe2O3 and O2 is 2:3

Therefore moles of O2 = 0.469 mol x (3/2) = 0.704 mol

Step 3: Find the mass of O2

m = n x M

m = 0.704 mol x 31.998 g/mol

m = 22.54 g

A sample will likely affect a criminal case because this evidence will provide a nearly exact match to the suspect’s hair (Option D).

DNA testing refers to the techniques used to obtain DNA from samples that can be used to identify an individual in a police case. A sample of hair may be used for DNA testing because it contains cells and therefore also contains DNA.

Therefore, with this data, we can see that DNA testing allow us to identify individuals for which we need to obtain a sample with cells.

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The molecular equation of the reaction of sulfuric acid and aqueous potassium hydroxide:

H₂SO₄ (aq)  + 2 KOH (aq)  →   K₂SO₄ (aq)  +  2H₂O (l)  

The net ionic equation is:

2H⁺ (aq)  +  2OH⁻ (aq) [tex]\longrightarrow[/tex] 2H₂O (l)

The net ionic equation of a reaction can be described as an equation that expresses only those elements, compounds, or ions that directly contributed in that chemical reaction.

The balanced chemical equation reaction of sulfuric acid and aqueous potassium hydroxide:

H₂SO₄ (aq)  + 2 KOH (aq)  →   K₂SO₄ (aq)  +  2H₂O (l)  

The complete ionic equation for the above reaction can be written as follows:

2H⁺ (aq) + SO²₄⁻ (aq)  +  2K⁺(aq)  + 2OH⁻ →  2K⁺ (aq) + SO₄²⁻ (aq)  + 2H₂O (l)

In the ionic equation, the potassium and sulfate ions appear unchanged on both sides of the equation. When we mix the two solutions, the potassium and sulfate ions do not participate in the reaction. So potassium and sulfate ions can be eliminated from the ionic equation.

2H⁺ (aq)  +  2OH⁻ (aq) [tex]\longrightarrow[/tex] 2H₂O (l)

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Answer:

288 g.

Explanation:

Measurements => Density.

Density is the ratio of the mass of an object to its volume:

where D is density, m is mass, and V is volume.

We have two data: the volume (32.1 mL) and the density (8.96 g/mL) and we need to find the mass.

We can solve for 'm' in the given equation and replace the given data, as follows:

The answer would be that the mass is 288 g.

The answer is -2219.9 kJ/mol

The rate constant ( k )= 9.2 x 10⁻³ s⁻¹The half life  (t1/2 )= 75.3 s

It is given that the reaction is 46% complete in 45 s

The relation between rate constant and the half life can be shown as:

For first order reaction:

ln[A]=−kt+ln[A]o

46% complete, 54% remains

A = 0.54

Ao = 1

Put the value of given data in the formula:

ln A = -kt + ln Ao

ln 0.54 = -k.45 + ln 1

-0.616=-k.45

k = 13.6 x 10⁻³ s⁻¹

The half life can be determined by using the formula:

t1/2 = (ln 2) / k

t1/2 = 0.693 / 13.6 x 10⁻³

t1/2 = 0.0509 ×10⁻³ s.

t1/2 = 5.09 ×[tex]10^{5}[/tex] s.

Therefore, the rate constant for the first order reaction will be 13.6 x 10⁻³ s⁻¹ and half life will be 5.09 ×[tex]10^{5}[/tex] s.

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The percentage of the sample of As-81 remaining undecayed after 43.2 seconds is 40.6%

We'll beging by calculating the number of half lives that has elapsed. This can be obtained as follow

The following data were obtained from the question:

n = t / t½

n = 43.2 / 33

n = 1.3

Finally, we shall determine the percentage remaining undecayed. This is shown below:

N = N₀ / 2ⁿ

N = 100 / 2^1.3

N = 40.6%

Thus, we can conclude that the percenatge undecayed is 40.6%

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The electron releases energy in the form of light.

Hope this helps!

Answer:

149 M

Explanation:

Answer: 13 O2 instead of 12 O2

Explanation:

Answer:

Explanation:

C

Answer:

I think the answer to your question is option A.

2. Which is the volume of 3.20 moles of O₂?

We are told that at STP one mol of any gas occupies 22.4 L. We will use that relationship to find the volume occupied by 3.20 moles of O₂.

1 mol of O₂ = 22.4 L

volume of O₂ = 3.20 moles of O₂ * 22.4 L/(1 mol of O₂)

volume of O₂ = 71.7 L

Answer: 3.20 moles of O₂ occupies 71.7 L

7. Which is the volume of 100. g of O₂?

In this case we will use the same relationship, but we are given grams instead of moles. So first we have to convert the mass in grams into moles. To do that we use the molar mass of O₂.

atomic mass of O = 16.00 amu

molar mass of O₂ = 2 * 16.00

molar mass of O₂ = 32.00 g/mol

Once that we know that the mass of 1 mol of O₂ is 32.00 g, we can find the number of moles that we have in 100. g of it.

moles of O₂ = mass of O₂ /(molar mass of O₂)

moles of O₂ = 100. g/(32.00 g/mol)

moles of O₂ = 3.13 moles

Finally we can find the volume that 3.13 moles of O₂ occupies (remember that 1 mol of any gas occupies 22.4 L at STP).

volume of O₂ = 3.13 moles * 22.4 L/(1 mol)

volume of O₂ = 70.1 L

Answer: 100. g of O₂ occupies 70.1 L

Answer:

To find a process more fingerprints (A uv imaging is used to capture and detect substances such as sweat which prints on a surface)

The number of blocks that can be lifted through this height is 11563 blocks.

We know that we define the term energy as the ability to do work, Now we have to consider the fact that we are told that one serving provides 185 kcal. Then we are told that  all of this energy is used to lift 1.0-kg blocks through a distance of  7.0 meters.

Given that the energy exerted in lifting each block is;

mgh

m = mass of the block

g = acceleration due to gravity

h = height lifted through

E = 1.0-kg * 9.8 m/s^2 * 7.0 meters = 68.6 J or 0.016 kcal

The number of blocks that can be lifted =  185 kcal/ 0.016 kcal

= 11563 blocks

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"A buffer solution's pH remains constant, even with small additions of acid or base."

Buffer solutions can react with minor additions of acid or base without changing the concentration of hydrogen ions in the solution. As a result, buffer solutions aid in maintaining a steady pH level throughout chemical reactions.

A weak acid and its conjugate base, or a weak base and its conjugate acid, are mixed together to form a solution called a buffer solution, which is based on water as the solvent. They do not change in pH when diluted or when modest amounts of acid or alkali are added to them.

An illustration would be a buffer created from a weak acid and its salt. It is a solution of acetic acid and sodium acetate CH3COOH + CH3COONa. A mixture of ammonia and ammonium chloride, or NH3aq + NH4Cl aq, is an illustration of a buffer made up of a weak base and its salt.

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1) Molar mass of Allicin.

1.1- Write the formula.

1.2- Look for the molar mass of each element in the formula.

C: 12.011 g/mol

H: 1.008 g/mol

O: 15.999 g/mol

S: 32.06 g/mol

1.3- Count how many atoms are there in the formula.

C: 6

H: 10

O: 1

S: 2

1.4- Set the equation.

Plug in the known values.

The molar mass (MM) of Allicin (C6H10OS2) is 162.265 g/mol.

2) Moles of Allicin in the sample.

Allicin sample: 4.20 mg

The molar mass of Allicin (C6H10OS2) is 162.265 g/mol.

2.1- Convert mg to g.

1g = 1000 mg

2.2- Convert grams to moles.

The molar mass of Allicin (C6H10OS2) is 162.265 g/mol.

Allicin sample: 0.00420 g

There are 0.00002588 moles of Allicin (C6H10OS2) in 4.20 mg of substance.

The result can also be expressed as 2.588*10^(-5) mol.

3) Molecules of Allicin in the sample.

The Avogadro's number is 6.022*10^(23).

1 mol C6H10OS2 = 6.022*10^(23) molecules C6H10OS2

Allicin sample: 0.00002588 mol.

There are 1.558*10^(19) molecules in the sample.

4) C atoms in the sample of Allicin.

The ratio of carbon in one molecule of Allicin is 6 C atoms: 1 molecule of Allicin.

Allicin sample: 1.558*10^(19) molecules C6H10OS2.

There are 9.35*10^(19) C atoms in the sample.

Lithium nitride is an ionic compound and the chemical formula of lithium nitride is Li₃N and the charges on the ions is Li⁺¹N³⁻ 3 valence electron in lithium and 5 valence electron in nitrogen

Ionic compound is the ion compound these ions are atom that gain or lose electron resulting in a net positive and negative charges and lithium nitride is an ionic compound and in that Li⁺¹N³⁻ is the ion and the arrangement of the valency (outer shell) electrons are 3 valence electron in lithium and 5 valence electron in nitrogen

X = 3 electron

O = 7 electron

And that's why lithium nitride has 10 electron

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By using an appropriate conversion factor, the size of this popular car's engine is equal to 356.78 cubic inches.

A conversion factor simply refers to a number that is typically used to convert a number in one (1) set of units to another, either by dividing or multiplying.

Generally speaking, an appropriate conversion factor to an equal value must be used when it is necessary to perform any mathematical conversion.

Conversion:

1 cubic centimeter = 0.061023744094732 cubic inches.

5,840 cubic centimeter = X cubic inches.

Cross-multiplying, we have:

X = 0.061023744094732 × 5,840

X = 356.78 cubic inches.

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Complete Question:

A popular car has an engine that is reported to have a volume of 5840 cm³. What is the size in cubic inches?

The reaction to produce nitrogen dioxide from nitrogen and oxygen is as follows:

Since all the reactants and products are gases, we can take the coefficients as liters of substance.

Dividing the volumes we have of each reactant by their corresponding coefficient we can determine the limit reagent:

From this we can conclude that the limit reagent is oxygen.

We have to base our calculations on this substance.

According to the given equation, 2 L of O2 produce 2 L of NO2, use this ratio to find the volume of nitrogen dioxide produced:

It means that 60.6 liters of nitrogen dioxide gas are made.

Answer:

Explanation:The given reaction is

It is an example of an oxidation reaction because in the above reaction, is getting oxidized to form .

Also, it is a type of combination reaction because magnesium reacts with oxygen to form a single product i.e. Magnesium oxide.

The final temperature of the solution will be 29.5 °C.

The heat released when 21.5 g of LiCl is dissolved completely in water is determined from the enthalpy change, ∆H of the solution of LiCl as follows;

Moles of LiCl in 21.5 g = mass/ molar mass

molar mas of LiCl = 42.5 g/mol

Moles of LiCl in 21.5 g = 21.5/42.5

Moles of LiCl in 21.5 g = 0.506 moles

Heat released = 0.506 * -37.0 kJ/mol

Heat released = 18.722 kJ or 18722 J

Heat released = heat gained by solution

mass of solution = 450 + 21.5

mass of solution = 471.5 g

Temperature change of the solution = 18722 / (471.5 * 4.184)

Temperature change of the solution = 9.5 °C

Final temperature of the solution = 20 °C + 9.5 °C

Final temperature of the solution =29.5 °C

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b) firstly we nee dto understant that 1 ton = 2831.68 litres

therefore if 16 967.04 Litres needs transporting we simply divide the 16 967.04 by 2831.68 and the answer is 5.99 which is rounded of to 6. therefore 6 trucks will be needed

c) we need to first find out how many gallons of fuels will be needed to complete a 285 mile distance. so we divide 285 by 7.8 to get 36.54 gallons and we know the price of i gallon to be $3.95 therefoe the cost will be

3.95 x 36.54 = 144.33

the cost is $144.33 per day

The following lists consists of ionic compounds except carbon disulfide (CS₂).

Barium hydroxide , Ba(OH)₂ is an ionic compound.

zinc carbonate, ZnCO₃ is an ionic compound.

ammonium sulfate , (NH₄)₂SO₄  is an ionic compound.

calcium chloride, CaCl₂  is an ionic compound.

carbon disulfide, CS₂ is not an ionic compound. In carbon disulfide both the elements are non metallic elements. The bond formed between atoms are by sharing of electron known as covalent bond due to very little difference in electronegativity.

magnesium nitrate, Mg(NO₃)₂  is an ionic compound.

sodium sulfate, Na₂SO₄  is an ionic compound.

copper(II) oxide, CuO  is an ionic compound.

potassium nitride KNO₃  is an ionic compound.

aluminium sulfide, Al₂S₃  is an ionic compound.

sodium sulfite, Na₂S  is an ionic compound.

calcium fluoride, CaF₂  is an ionic compound.

Thus, The following lists consists of ionic compounds except carbon disulfide (CS₂).

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The [OH⁻] of the solution with pH of 8.13 is 1.35 * 10-6 M

pH is the measurement of the acidity or basicity of a compound by measuring [H⁻] ions in the solution. It ranges from 0 to 14 with acidic range from 0 – 7 and basic range from 7-14.

pOH is the measurement of the acidity or basicity of a compound by measuring [OH⁻] ions in the solution.

Thus, pH + pOH = 14

pOH = 14 - pH = 14 – 8.13 = 5.87

pOH = - log ([OH⁻])

- log ([OH⁻]) = 5.87

Log ([OH⁻]) = - 5.87

[OH⁻] = 10 ^ - 5.87   = 0.00000134896

[OH⁻] = 1.35 * 10⁻⁶ M

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Please, look at the next drawing:

Electrolytic cell: Electrical energy is used to drive nonspontaneous redox reactions.

Oxidation half-reaction: Z- => Z + e- (anode)

Reduction half-reaction: Y+ + e- => Y (cathode)

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