What are the domain and range of y = cot x? Select onechoice for domain and one for range.
Answers
ANSWER:
A. Domain: x ≠ n
D. Range: All real numbers
STEP-BY-STEP EXPLANATION:
We have the following function:
[tex]y=\cot\left(x\right)[/tex]The domain of a function is the interval of input values, that is, the interval of x while the range is the interval of output values, that is, the interval of y.
In the cotangent function, x cannot take the value of radians (nor its multiples), since it is not defined, while the range is continuous on all real numbers.
That means the correct options are:
A. Domain: x ≠ n
D. Range: All real numbers
Related Questions
Find the measure of each angle in the triangle. F R 6x 15x 15x O 02
Answers
Answer:
R = 75
O = 75
F = 30
Step-by-step explanation:
15x + 15x + 6x = 180
add like terms
36x = 180
divide
x = 5
The measure of angle P is 30°, angle R is 75° and angle O is 75° in triangle POR.
What is angle sum property of a triangle?Angle sum property of triangle states that the sum of interior angles of a triangle is 180°.
From the given triangle POR, ∠R=15x, ∠O=15x and ∠P=6x.
By using angle sum property, we get
∠P+∠O+∠R=180°
6x+15x+15x=180
36x=180
x=180/36
x=5
So, ∠R=15x=75°, ∠O=15x=75° and ∠P=6x=30°
Therefore, the measure of angle P is 30°, angle R is 75° and angle O is 75° in triangle POR.
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Use a truth table to determine whether the two statements are equivalent.
Answers
The answer is option(b) i.e,the given statements are not equivalent.
What is Truth table?
A truth table is a breakdown of a logic function by listing all possible values the function can attain. Such a table typically contains several rows and columns, with the top row representing the logical variables and combinations, in increasing complexity leading up to the final function.
Let's proof it by using truth table :
p q (~q → ~p) (~p → ~q)
F F T T
F T T F
T F F T
T T T T
As you've seen in truth table (~q → ~p) ≠ (~p → ~q)
Therefore, the answer is option(b) i.e,the given statements are not equivalent.
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Determine whether the lines are parallel, intersect, or coincideY = 4x - 53x + 4y = 7
Answers
Answer:
Explanation:
Given:
y=4x-5
3x+4y=7
We can check if the lines are parallel, intersect, or coincide by graphing. To graph, we plug in any values for x to determine the y values.
The graph of the lines is shown below:
So based on the graph, the lines intersect at a point.
Therefore, the lines intersect.
Just do all 25 points If can show how it works it will be better thanks
Answers
a) Given:
The length of the side of a square is,
[tex]\frac{1}{5}cm[/tex]To find:
The area of the square.
Explanation:
Using the formula of the area of the square,
[tex]\begin{gathered} A=a^2 \\ A=(\frac{1}{5})^2 \\ A=\frac{1}{25}cm^2 \\ A=0.04cm^2 \end{gathered}[/tex]Final answer:
The area of the square is,
[tex]0.04cm^2[/tex]Solve the system of two linear inequalities graphically,4x + 6y < 24(x22Step 1 of 3 : Graph the solution set of the first linear inequality.AnswerKeypadKeyboard ShortcutsThe line will be drawn once all required data is provided and will update whenever a value is updated. The regions will be added once the line is drawn.Enable Zoom/PanChoose the type of boundary line:Solid (-) Dashed (--)Enter two points on the boundary line:10-5Select the region you wish to be shaded:
Answers
Answer:
To solve the system of two linear inequalities graphically,
[tex]\begin{gathered} 4x+6y<24 \\ x\ge2 \end{gathered}[/tex]For step 1,
Draw a line 4x+6y=24
Since the given equation has less than sign, the required region will not include the line, Hence we draw the dashed line for the line 4x+6y=24.
Since we required redion is 4x+6y<24, the points bellows the line satisfies the condition hence the required region is below the line,
Similarly for the inequality,
[tex]x\ge2[/tex]It covers the region right side of the line x=2,
we get the siolution region as the intersecting region of both inequality which defined in the graph as,
Dark blue shaded region is the required solution set for the given inequalities.
A plumber charges $14 for transportation and $30 per hour for repairs. Complete the expression that can be used to find the cost in dollars for a repair that takes h hours.An expression that can be used to find the cost in dollars for a repair that takes h hours is ____ + ____h.
Answers
A plumber charges $14 for transportation and $30 per hour for repairs.
Complete the expression that can be used to find the cost in dollars for a repair that takes h hours.
An expression that can be used to find the cost in dollars for a repair that takes h hours is ____ + ____h.
_______________________________________________________________________
Charges
14 + 30* h
________________________________
Answer
An expression that can be used to find the cost in dollars for a repair that takes h hours is _14___ + _30___h.
____________________________________________
30 per hour, if it's two hours then 60 for example
Identify the postulate illustrated by the statement: Line ST connects pointS and point T
Answers
We have two points known to be ( S ) and ( T ). A line connects two points.
The minimum number of points that are required to form a straight line in a cartesian coordinate system are ( two ).
The minimum number of points that are required to form a plane in a cartesian coordinate system are ( three ) which will form two vectors i.e it requires two lines formed with a common point.
Two planes always intersect at exactly one point with direction normal to the two plane normal vectors.
Hence, the only possible postulate that relates two points is the formation of a line between two points; hence, the correct postulate for the given statement is:
[tex]\text{\textcolor{#FF7968}{Through any two points there is exactly one line}}[/tex]
Find the quotient of these complex numbers.(4 + 4i) (5 + 4i) =A.B.C.D.
Answers
Find the quotient given below:
[tex]\frac{4+4i}{5+4i}[/tex]When managing complex numbers, we must recall:
[tex]\begin{gathered} i^2=-1 \\ \text{ Or, equivalently:} \\ i=\sqrt{-1} \end{gathered}[/tex]Multiply and divide the expression by the conjugate of the denominator:
[tex]\frac{4+4i}{5+4i}\cdot\frac{5-4i}{5-4i}[/tex]Multiply the expressions in the numerator and in the denominator. We can apply the special product formula in the denominator:
[tex](a+b)(a-b)=a^2-b^2[/tex]Operating:
[tex]\frac{(4+4i)(5-4i)}{5^2-(4i)^2}[/tex]Operate and simplify:
[tex]\frac{20-16i+20i-16i^2}{25-16i^2}[/tex]Applying the property mentioned above:
[tex]\frac{20-16i+20i+16}{25+16}[/tex]Simplifying:
[tex]\frac{36+4i}{41}[/tex]if the area of polygon A is 72 and Q is a scaled copy and the area of Q is 5 what scale factor got 72 to 5
Answers
A area= 72
Q area =5
So, if we multiply the A area by the square of the scale factor ( since they are areas) we obtain area Q:
72 x^2 = 5
Solving for x:
x^2 = 5/72
x = √(5/72)
x= 0.26
Use the given conditions to write an equation for the line.Passing through (−7,6) and parallel to the line whose equation is 2x-5y-8=0
Answers
For a line to be parallel to another line, the slope will be the same
1st equation:
[tex]\begin{gathered} 2x\text{ - 5y - 8 = 0} \\ \text{making y the subject of formula:} \\ 2x\text{ - 8 = 5y} \\ y\text{ = }\frac{2x\text{ - 8}}{5} \\ y\text{ = }\frac{2x}{5}\text{ - }\frac{8}{5} \end{gathered}[/tex][tex]\begin{gathered} \text{equation of line:} \\ y\text{ = mx + b} \\ m\text{ = slope, b = y-intercept} \end{gathered}[/tex][tex]\begin{gathered} \text{comparing the given equation and equation of line:} \\ y\text{ = y} \\ m\text{ = 2/5} \\ b\text{ = -8/5} \end{gathered}[/tex]Since the slope of the first line = 2/5, the slope of the second line will also be 2/5
We would insert the slope and the given point into equation of line to get y-intercept of the second line:
[tex]\begin{gathered} \text{given point: (-7, 6) = (x, y)} \\ y\text{ = mx + b} \\ 6\text{ = }\frac{2}{5}(-7)\text{ + b} \\ 6\text{ = }\frac{-14}{5}\text{ + b} \\ 6\text{ + }\frac{14}{5}\text{ = b} \\ \frac{6(5)\text{ + 14}}{5}\text{ = b} \\ b\text{ = }\frac{44}{5} \end{gathered}[/tex]The equation for the line that passes through (-7, 6) and parallel to line 2x - 5y - 8 = 0:
[tex]\begin{gathered} y\text{ = mx + b} \\ y\text{ = }\frac{2}{5}x\text{ + }\frac{44}{5} \end{gathered}[/tex]find a slope of the line that passes through (8,8) and (1,9)
Answers
The slope formula is
[tex]m=\frac{y_2-y_1}{x_2-x_1}[/tex]we can use this formula by introducing the values of the given points. In our case
[tex]\begin{gathered} (x_1,y_1)=(8,8) \\ (x_2,y_2)=(1,9) \end{gathered}[/tex]Hence, we have
[tex]m=\frac{9-8}{1-8}[/tex]It yields,
[tex]m=\frac{1}{-7}[/tex]hence, the answer is
[tex]m=-\frac{1}{7}[/tex]10. Find the area of ABC. (A) 84 (B) 168 (C) 170 (D) 48 (E) 56A: 10B: 17C: 21Right angle: 8
Answers
we know that
the area of triangle ABC is equal to the area of two right triangles
so
triangle ABD and triangle BDC
D is a point between point A and point C
step 1
Find the length of segment AD
Applying Pythagorean Theorem in the right triangle ABD
10^2=AD^2+8^2
100=AD^2+64
AD^2=100-64
AD^2=36
AD=6
Find teh area of triangle ABD
A=AD*BD/2
A=6*8/2
A=24 units^2
step 2
Find the area of triangle BDC
A=DC*DB/2
DC=21-6=15 units
A=15*8/2
A=60 units^2
step 3
Find teh area of triangle ABC
Adds the areas
A=24+60=84 units^2
therefore
the answer is the option A 84 units^2I need help to do these composition of functions. I have a photo if needed.h(a)=4a+1g(a)=2a-5Find (h×g)(-9)
Answers
The composition of two functions is defined as follows:
[tex](h\circ g)(x)=h(g(x))[/tex]Use the given rules of correspondence of h and g to find the composition of those two functions. Then, evaluate the composition at -9:
[tex]\begin{gathered} h(a)=4a+1 \\ \Rightarrow h(g(a))=4\cdot g(a)+1 \end{gathered}[/tex][tex]\begin{gathered} g(a)=2a-5 \\ \Rightarrow4\cdot g(a)+1=4\cdot(2a-5)+1 \\ =8a-20+1 \\ =8a-19 \end{gathered}[/tex]Then:
[tex]\begin{gathered} (h\circ g)(a)=h(g(a)) \\ =4\cdot g(a)+1 \\ =8a-19 \\ \\ \therefore(h\circ g)(a)=8a-19 \end{gathered}[/tex]Evaluate the composition of h and g at a=-9:
[tex]\begin{gathered} (h\circ g)(-9)=8(-9)-19 \\ =-72-19 \\ =-91 \end{gathered}[/tex]Therefore:
[tex](h\circ g)(-9)=-91[/tex]Given that sin(0)= 10/ 13 and 0 is in Quadrant II, what is cos(20)? Give an exact answer in the form of a fraction. ,
Answers
SOLUTION
Given the image in the question tab, the following are the solution steps to the answer
Step 1: Write out the function
[tex]\begin{gathered} \sin \theta=\frac{10}{13} \\ \text{since }\sin \theta=\frac{opp}{hyp} \\ \therefore opp=10,\text{ hyp=13} \end{gathered}[/tex]Step 2: Solve for the adjacent using the pythagoras theorem
[tex]\begin{gathered} \text{hyp}^2=opp^2+adj^2 \\ 13^2=10^2+adj^2 \\ \text{adj}^2=13^2-10^2 \\ \text{adj}=\sqrt[]{169-100} \\ \text{adj}=\sqrt[]{69} \end{gathered}[/tex]Step 3: Calculate the value of cos2Ф
[tex]\begin{gathered} cos2\theta=\cos ^2\theta-\sin ^2\theta \\ \cos 2\theta=(\frac{\text{adj}}{\text{hyp}})^2-(\frac{opp}{hyp})^2 \\ \cos 2\theta=(\frac{\sqrt[]{69}}{13})^2-(\frac{10}{13})^2 \\ \cos 2\theta=\frac{69}{169}-\frac{100}{169} \\ \cos 2\theta=-\frac{31}{169} \end{gathered}[/tex]Hence, the value of cos2Ф is -31/169.
Daniel's family raises honey bees and sells the honey at the farmers' market. To get ready for market day, Daniel fills 24 equal sized jars with honey. He brings a total of 16 cups of honey to sell at the farmers' market.
Use an equation to find the amount of honey each jar holds.
To write a fraction, use a slash ( / ) to separate the numerator and denominator.
Answers
The fraction for the amount of honey each jar holds is 2/3.
What is an equation?A mathematical equation is the statement that illustrates that the variables given. In this case, two or more components are taken into consideration to describe the scenario.
From the information, Daniel fills 24 equal sized jars with honey and he brings a total of 16 cups of honey to sell at the farmers' market.
The amount of honey will be:
= Number of cups / Number of jars
= 16 / 24
= 2/3
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Use the Distibutive Property: Expand -3(x + 3)
Answers
The distributive property of multiplication states the following:
[tex]a(b+c)=a\cdot b+a\cdot c[/tex]So, for the given expression, we have:
[tex]-3(x+3)=(-3)\cdot x+(-3)\cdot3=-3x-9[/tex]Harold Hill borrowed $16,400 to pay for his child's education at Riverside Community College. Harold must repay the loan at the end of 15 months in one payment with 3 3/4 % of interest.
A. How much interest must Harold pay? (Round answer to the nearest cent.)
B. What is the maturity value? (Round answer to the nearest cent.)
Answers
The interest that Harold pay is $768.75 and his maturity value is $17168.75.
Harold Hill borrowed $16,400
Harold must repay the loan at the end of 15 months in one payment with 3 3/4 % of interest
First we need to calculate the interest amount
= loan amount x rate of interest x number of months
interest = (16400 x 3 3/4 x 15/12)/100
interest = $768.75
The maturity value = loan amount + interest
= 16400 + 768.75
= 17168.75
Therefore, the interest that Harold pay is $768.75 and his maturity value is $17168.75.
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13. Puppies have 28 teeth and most adult dogs have 42 teeth. Find the primefactorization of each number. Write the result using exponents. (Example 5)
Answers
To solve our question, first we need to know that a prime factorization is a way to represent a number by a sequence of prime numbers that multiplied together gives us the original number.
So let's calculate our first prime factorization:
As we can see, we divide our number by the smallest prime number and then the factor we follow the same rule until we get "1" (for all divisions we just have integers).
Now, for the second number we have:
And both prime factorizations are our final answers.
Suppose that the edge lengths x, y, z of a closed rectangular box are changing at the following rates: dx/dt= 1m/s, dy/dt= -2 m/s, and dz/dt= 0.5 m/s.
At the instant x= 2m, y= 3m, z= 5m, find the rates of change:
a) volume of the box
b) surface area of the box
c) diagonal of the box
Answers
a) The rate of change of the volume of the box is 8m³/s.
b) The rate of change of the surface area of the box is -19m²/s.
c) The rate of change of the diagonal of the box is 1m/s.
Let the rate of change of the edge length x, y, and z of a closed rectangular box are:
dx/dt= 1m/s
dy/dt= -2 m/s
dz/dt= 0.5 m/s
a) The volume of the box
From the formula of the volume,
V=xyz
Then,
differentiate w.r.t t
[tex]\frac{dV}{dt} = xy\frac{dz}{dt} + yz\frac{dx}{dt} +xz\frac{dy}{dt}[/tex]
[tex]\frac{dV}{dt} = xy(0.5)+ yz(1)+xz(-2)[/tex]
put the value of x, y, z , then we get
[tex]\frac{dV}{dt} = 2.3.(0.5)+ 3.5.(1)+2.5.(-2)[/tex]
[tex]\frac{dV}{dt} = 3+ 15 - 10[/tex]
[tex]\frac{dV}{dt} = 8m^3/s[/tex]
The rate of change of the volume of the box is 8m³/s.
b) surface area of the box
surface area of the rectangular box is
s = 2xy + 2yz + 2zx
differentiate w.r.t t
[tex]\frac{ds}{dt} = 2(y + z)\frac{dx}{dt} + 2(z + x)\frac{dy}{dt} +2(x + y)\frac{dz}{dt}[/tex]
[tex]\frac{ds}{dt} = 2(y + z)(1) + 2(z + x)(-2)+2(x + y)(0.5)[/tex]
[tex]\frac{ds}{dt} = 2(3 + 5)(1) + 2(5 + 2)(-2)+2(2 + 3)(0.5)[/tex]
[tex]\frac{ds}{dt} = 16 -40 + 5[/tex]
[tex]\frac{ds}{dt} = -19m^2/s[/tex]
The rate of change of the surface area of the box is -19m²/s.
c) diagonal of the box
lengths of the boxes for the diagonal is
s = 2x² + y² + z²
differentiate equation w.r.t t
[tex]\frac{ds}{dt} = 4x\frac{dx}{dt} + 2y\frac{dy}{dt} +2z\frac{dz}{dt}[/tex]
[tex]\frac{ds}{dt} = 4.2.1+ 2.3.(-2) +2.5.(0.5)[/tex]
[tex]\frac{ds}{dt} = 8 -12 + 5[/tex]
[tex]\frac{ds}{dt} =1m/s[/tex]
The rate of change of the diagonal of the box is 1m/s.
a) The rate of change of the volume of the box is 8m³/s.
b) The rate of change of the surface area of the box is -19m²/s.
c) The rate of change of the diagonal of the box is 1m/s.
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Find the value or measure. assume all lines that appear to be tangent are tangent.JK=
Answers
In this problem we have that
mso
the formula to calculate the interior angle is equal to
msubstitute the given values
m
therefore
the answer is mExplain how to find the point equidistant from all three vertices in the given triangle. Choose the correct answer below. A. Find the intersection of the perpendicular bisectors of each side of the triangle B. Find the intersection of all of the midsegments of the triangle, C. Find the intersection of the angle bisectors of each angle of the triangle, D. Find the midpoint of the line segment that bisects Angle B.
Answers
ANSWER:
The correct option is the following:
C. Find the intersection of the angle bisectors of each angle of the triangle,
EXPLANATION:
The point that equidistant is the point at which the three bisectors of the internal angles of the triangle intersect, and it is the center of the circumference inscribed in the triangle and equidistant from its three sides.
IMPORTANT NOTE:
Any point on the bisector of an angle of a triangle equidistant from the sides that define that angle.
y 4 7(x-6)
x-intercept:
y-intercept:
PLEASE ANSWER FAST.
Answers
Answer: y-4=7(x-6)
x-intercept(s): (38/7,0)
y-intercept(s): (0,−38)
I believe this is right hope this helps
Step-by-step explanation:
What is the image of (-5,1) after a dilation by a scale factor of 5 centered at the origin?
Answers
Explanation
Step 1
when you have a coordinate (x,y) and you want to get the image after a dilationi, make
[tex]\text{new image=(coordinate)}\cdot factor[/tex]then
let
coordinate=(-5,1)
dilation scale=5
now, replace
[tex]\begin{gathered} \text{new image=(coordinate)}\cdot factor \\ \text{new image=(-5,1)}\cdot5 \\ \text{new image=(}-25,5) \end{gathered}[/tex]I hope this helps you
STRUCTURE Quadrilateral DEFG has vertices D(-1, 2), E(-2, 0), F(-1,-1) and G(1, 3). A translation maps quadrilateral DEFG to
quadrilateral D'EFG. The image of D is D'(-2,-2). What are the coordinates of E, F, and G'?
E (
FD
G' (
Answers
The coordinates are;
E' = (-3, -4)F' = (-2, -5)G' = (0, -1)Given,
Quadrilateral DEFG with vertices;
D = (-1, 2)E = (-2, 0)F = (-1,-1) G = (1, 3)We have to find the coordinates of E', F', G'.
A figure is translated when it is moved to the left, right, up, or down.
The original figure's points are all translated (moved) by the same amount and in the same direction.
Here,
Compare the coordinates of D with the coordinates of D' to determine the mapping rule that converts DEFG to D'E'F'G'.
D = (-1, 2)
D' = (-2, -2)
The x-coordinate has be translated 1 unit to the left.
The y-coordinate has been translated 4 units down.
Then,
The mapping rule is:
(x, y) → (x-1, y-4)
To find the coordinates of E', F' and G', apply the mapping rule to the given vertices of the pre-image:
⇒ E' = (-2-1, 0-4) = (-3, -4)
⇒ F' = (-1-1, -1-4) = (-2, -5)
⇒ G' = (1-1, 3-4) = (0, -1)
That is,
The coordinates are;
E' = (-3, -4)F' = (-2, -5)G' = (0, -1)Learn more about translation maps here;
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What is the value of p in the proportion below? 20/6 = p/12O 2 O 10O 40O 72
Answers
20/6 = p/12
cross-multiply
p x 6 = 20 x 12
6p = 240
divide both-side of the equation by 6
p = 240/6
p = 40
Put the following equation of a line into slope-intercept form, simplifying allfractions.2x + 8y = 24
Answers
How would I write an equation in point- slope form with inequalities, slope-intercept form with inequalities and standard form with inequalities with these three sets of points(9,7) (8,5)(2,9) (2,7)(3,5) (5,4)
Answers
a. The point-slope equation is:
[tex]y-y_1=m(x-x_1)[/tex]Where m is the slope and (x1,y1) are the coordinates of one point in the line. Also, you need to write the equation with inequalities, then you need to replace the = sign, for a <, > or <=, >= sign.
Let's start by finding the slope of the first set of points (9,7) (8,5).
The formula for the slope is:
[tex]m=\frac{y_2-y_1}{x_2-x_1_{}}[/tex]By replacing the values you obtain:
[tex]m=\frac{5-7_{}}{8_{}-9}=\frac{-2}{-1}=2[/tex]The slope is 2.
Now, replace this value into the slope-form equation and the values of the first point (9,7):
[tex]y-7_{}>2(x-9)[/tex]I choose the sign > (greater than), but you can choose anyone, the difference will be for the solution of the inequality. When you solve the inequality you will find that the x-values have to be greater than the solution you found, or less than... etc, it will depend on the sign you have in the inequality.
b. The slope-intercept equation is:
[tex]y=mx+b[/tex]Where m is the slope and b the y-intercept.
Let's use the second set of points (2,9) and (2,7)
Start by calculating the slope:
[tex]m=\frac{7-9}{2-2}=\frac{-2}{0}=\text{ undefined}[/tex]As there's no difference in the x-coordinates, the line is a vertical line at x=2.
Also, there's no y-intercept as the line never crosses the y-axis.
I will use the first set again, so you can understand the slope-intercept form.
From part a) you know that the slope is 2, let's replace it in the equation and use the first pair of coordinates to find b:
[tex]\begin{gathered} 7=2\times9+b \\ 7=18+b \\ 7-18=b \\ b=-11 \end{gathered}[/tex]Thus, the slope-intercept with inequality will be:
[tex]y<2x-11[/tex]c. The standard form equation of a line is:
[tex]ax+by=c[/tex]Let's use the third set of points (3,5) (5,4).
Start by finding the slope:
[tex]m=\frac{4-5}{5-3}=\frac{-1}{2}=-0.5[/tex]Now, you can start with the point-slope form and then convert it into the standard form:
[tex]\begin{gathered} y-5\ge-0.5(x-3) \\ Apply\text{ the distributive property} \\ y-5\ge-0.5x+1.5 \\ y\ge-0.5x+1.5+5 \\ y\ge-0.5x+6.5 \\ 0.5x+y\ge6.5 \end{gathered}[/tex]Where a=0.5, b=1 and c=6.5
The population of a country dropped from 52.5 million in 1995 to 44.2 million in 2007. Assume that P(t), the population, in millions, t years after 1995, is decreasing according to the exponential decay model.a) Find the value of k, and write the equation.b) Estimate the population of the country in 2018.c) After how many years will the population of the country be million, according to this model?
Answers
we have the exponential decay function
[tex]P(t)=52.5(e)^{-0.0143t}[/tex]Part b
Estimate the population of the country in 2018
Remember that
t=0 -----> year 1995
so
t=2018-1995=23 years
substitute in the function above
[tex]\begin{gathered} P(t)=52.5(e)^{-0.0143\cdot23} \\ P(t)=37.8\text{ million} \end{gathered}[/tex]Part c
After how many years will the population of the country be 2 million, according to this model?
For P(t)=2
substitute
[tex]2=52.5(e)^{-0.0143t}[/tex]Solve for t
[tex]\frac{2}{52.5}=(e)^{-0.0143t}[/tex]Apply ln on both sides
[tex]\begin{gathered} \ln (\frac{2}{52.5})=\ln (e)^{-0.0143t} \\ \\ \ln (\frac{2}{52.5})=(-0.0143t)\ln (e)^{} \end{gathered}[/tex][tex]\ln (\frac{2}{52.5})=(-0.0143t)[/tex]t=229 years
Nancy plans to take her cousins to an amusement park. She has a total of $100 to pay for 2 different charges. • $5 admission per person • $3 per ticket for rides Which inequality could Nancy use to determine y, the number of tickets for rides she can buy if she pays the admission for herself and x cousins? A. 5y + 3(x + 1) >= 100 B. 5(x + 1) + 3y > 100 C. 5(x + 1) + 3y =< 100 D. 5y + 3(x + 1) < 100
Answers
ANSWER
[tex]C.5(x\text{ + 1) + 3y }\leq100[/tex]EXPLANATION
Nancy has $100.
The charges are:
=> $5 admission per person. She has x cousins and herself to pay for, this means that she pays $5 for (x + 1) persons.
The admission charge is therefore:
$5 * (x + 1) = $5(x + 1)
=> $3 per ticket for rides. The number of rides she can pay for is y. So the charge for rides is:
$3 * y = $3y
Since she only has $100, everything she pays for can only be less than $100 or equal to $100.
This means that, if we add all the charges, they must be either less than or equal to $100.
That is:
[tex]5(x\text{ + 1) + 3y }\leq100[/tex]That is Option C.
subtract (7u^2+10u+6) from (3u^2_5u+4).
Answers
Given:
[tex]\mleft(3u^2-5u+4\mright)-(7u^2+10u+6)[/tex]The objective is to subtract both the terms.
[tex]\begin{gathered} \mleft(3u^2-5u+4\mright)-(7u^2+10u+6) \\ 3u^2-5u+4-7u^2-10u-6 \\ -4u^2-15u-2 \end{gathered}[/tex]Hence the subtraction of the given term is,
[tex]-4u^2-15u-2[/tex]