What atom matches this electron configuration?
1s22s22p63s2 3p64s23d104p65s24d105p66s24f145d9


Mercury


Thallium


Gold


Platinum

8.70 g of carbon dioxide are generated by the reaction of octane.

Let's compile all the data in one location since we are aware that we will require a balanced equation with masses and molar masses.

M_r:                    32.00      44.01

             2C₈H₁₈ + 25O₂ ⟶ 16CO₂ + 18H₂O

  m/g:                    9.88

(a) Calculate the moles of O₂

n = 9.88 g O₂ ×1 mol O₂ /32.00 g O₂

n = 0.3088 mol O₂.

(b) Calculate the moles of CO₂

(16 mol CO2 to 25 mol O2) is the molar ratio.

n = 0.3088 mol O₂ × (16 mol CO₂/25 mol O₂)

n = 0.1976 mol CO₂

(c) Calculate the mass of CO₂

Mass of CO₂ = 0.1976 mol CO₂ × (44.01 g CO₂/1 mol CO₂)

Mass of CO₂ = 8.70 g CO₂

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We have to calculate the moles of PCl₅ in the given gram. divide the gram by molar mass. the number of moles is 0.267 moles

What is mole?

The mole is the amount of substance of a system which contains as many elementary entities as there are atoms in 0.012 kilogram of carbon 12.

To find out the number of moles using the following formula.

mole = mass/molarmass

The molar mass of the PCl₅ = molar mass of phasphorus+ 5x molar mass of chlorine.
The molar mass of the PCl₅= 208.24 g/mol
mole = 55.7g÷208.24g/mol =0.267 moles

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Mole measure the number of elementary entities of a given substance that are present in a given sample. mass. The number of moles in 55.7 g of PCl₅ is 0.26 mole.

The SI unit of amount of substance in chemistry is mole. The mole is used to measure the quantity or amount of substance. We know one mole of any element contains 6.022×10²³ atoms which is also called Avogadro number.

Mathematically,

mole =given mass ÷ molar mass

Molar mass of PCl₅= 208.24 g/mol

Given mass of PCl₅=  55.7 g

Substituting the given values we get

mole =55.7 g ÷208.24 g/mol

number of moles=0.26 mole

Therefore,  the number of moles in 55.7 g of PCl₅ is 0.26 mole.

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We need to understand that reactions can happen at different speeds depending on the conditions to develop methods for production improvement.

The rate of any chemical reaction depends upon the nature of the reacting substances.  Under the same conditions , reactions that appear similar have different rates of reaction. Chemical reaction proceeds in different speeds, depend on the various factors such as type of chemical transformation , temperature and other factors. the information about the speed of reaction is useful in large scale production.

Thus, We need to understand that reactions can happen at different speeds depending on the conditions to develop methods for production improvement.

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Answer: Physical - Color, density, boiling/melting point, magnetism, texture, and odor

Chemical - reactivity, combustibility, color change, and temperature change

Explanation:

Physical properties are changes to a substance that can be reversed and refer to its state at the time. Chemical properties are properties that are observable during or after a chemical reaction and cannot be reversed since the reaction has changed the state of the substance.

Answer:

Explanation

Finally, we can calculate the surface-area-to-volume ratio of the nanoparticle by dividing 4750 nanometers squared by 18750 nanometers cubed. It is important to place the surface area first because that is what the problem is asking us to compare.

Explanation:

A. Even though CH3F has a tetrahedral geometry, the molecule is not symmetric due to the presence of the fluorine atom in the structure resulting in the molecule being polar.

B. None of the above gives a valid explanation.

C. Even though CH3F has a tetrahedral geometry, the carbon atom in the molecule, being the central atom, is more electronegative than the hydrogen and fluorine atoms in the molecule resulting in the molecule being polar.

D. Even though CH3F has a tetrahedral geometry, the fluorine atom in the molecule, being the central atom, is more electronegative than the hydrogen and carbon atoms in the molecule resulting in the molecule being polar.

E. Even though CH3F has a tetrahedral geometry, the hydrogen atoms in the molecule are more electronegative than the fluorine resulting in the molecule being polar.

What occurs when copper sulfate solution is combined with a piece of silver metal?

If the reaction happens, you should also write the chemical equation in balance.

Reactions to displacement as a first option

A more reactive metal can displace a less reactive metal from a solution in a displacement reaction. The reactivity series of metals can be used to forecast the end products of a displacement process. The metals are arranged according to their reactivity with diluted acids in the reactivity series. A specific metal in the reactivity series may be displaced by metals positioned above it.

In the reactivity series, some of the elements above hydrogen (H) are potassium (K), sodium (Na), magnesium (Mg), zinc (Zn), and others. Several of the metals in the reactivity sequence below hydrogen

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Answer: Fe is the element that is being oxidized (oxidation number changes from +2 to +3) while Cl is the element that is reduced (oxidation number changes from +5 to -1) in the given reaction.

Explanation:

The question requires us to find the element that is oxidized and the one reduced in the following chemical reaction:

To solve this problem, we need to determine the oxidation number of all elements in the reactants and products sides, and then identify the elements that had their oxidation number increased (oxidized species) and decreased (reduced species).

To identify the oxidation numbers, we'll need to remember a few points:

- K is an alkali metal (part of group 1 in the periodic table), and it usually assumes the oxidation number +1;

- O usually presents oxidation number -2, except in a few specific cases;

- the anion (SO4) presents total charge -2 (in this anion, S presents oxidation number +6 and O, -2);

- H usually presents oxidation number +1.

Next, let's identify the oxidation number of all elements involved in the reaction, on both sides of the chemical equation. Since all compounds are neutral (i.e., they do not present charge), the sum of all oxidation numbers must be 0:

(note that the oxidation number of each element is indicated in red, above the respective element, while the contribution of this element to the molecule charge, considering the number of atoms, is represented in blue below the element).

In the image above, we can see that Cl has its oxidation number changing from +5 in KClO3 to -1 in KCl (highlighted in purple), while Fe has its oxidation number changing from +2 in FeSO4 to +3 in Fe2(SO4)3 (highlighted in green).

Therefore, we can say that Fe is the element that is being oxidized while Cl is the element that is reduced in the given reaction.

The conjugate base of a compound is what this compound will be after donating a H⁺.

The comopund in question is H₂BO₃⁻. After it loses 1 H⁺, it will have one less H atom and its charge decrease by one. Its charge is only with a "-" sign, which means its chargeis 1-. After decreasing by one, the charge becomes 2-.

So, the conjugate base will be HBO₃²⁻

Answer:

This is NOT a CUBE..

now Considering that one side of one small block is equal to 1 unit.

Then

Length = 3 units

Width = 3 units

Height = 4 units

Please tell me if this is correct

Length would be 3 units, Height is 4 units, and Width is I want to say 5 or 6 not truly sure

Answer:

Explanation:

A negatively charged core nucleus and one or more orbiting electrons make up an atom. There may be the positively charged, somewhat massive protons and neutrons that make up the nucleus. Atoms are the basic building blocks of stuff.

In a neutral atom, there are exactly as many electrons as protons. The total number of protons and neutrons in the atom's nucleus is equal to the mass number (M) of the atom. The difference between the atomic number and the mass number of the atom (M) is equal to the amount of neutrons (Z).

Absorption is the process by which an atom transitions from its ground state to an excited state by absorbing energy from its environment. After absorbing the energy, the electron advances to a higher energy state. Up the opposite process, called emission, the electron releases the excess energy it had taken in and goes back to its ground state.

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Dr. Peterson performed an experiment in order to research the growth rate of mice. He had two groups of mice and he fed one group a type of food with added chemical which results in increasing the growth rate and fed same group of food to another batch without adding any chemicals. His research conveyed that chemical A increased the growth rate of mice by approximately 30%. He performed the same experiment 4 times and got the same result every time. Dr. Peterson concluded that the chemical A results in increase of growth rate of mice. The Interpretation of Dr. Peterson's experiment was supported by the evidence received from his experiment. Therefore, option C is correct.

In his experiment, Dr. Peterson found out that chemical A results in increasing the growth rate of mice by 30% and to make sure that the result obtained is valid and evidential, he performed the same experiment 4 times. Since every time the experiment was repeated, the result came out to be same, the closing statement from his experimental study can be accepted because they are backed by evidence.

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The kilojoules of heat released per gram of the compound reacted with oxygen is -72.052 kj/g

The standard enthalpy of formation is a measure of the strength launched or fed on while one mole of a substance is created under trendy situations from its natural elements. The symbol of the standard enthalpy of formation is ΔH f. = A degree means that it's a fashionable enthalpy change.

Enthalpy of a formation refers to the trade in enthalpy for the formation of one mole of a substance from the maximum solid form of its constituent factors. change in enthalpy is symbolized by means of delta H and the f stands for formation.

Given,

compound             ΔH°f

B₅H₉                       73.2

B₂O₃                       -1271.94

H₂O                        -285.83

Balanced chemical equation:-

2B₅H₉  (l)  +  12O₂ +(g) => 5B₂O₃  + 9H₂O(l)

From Hess's law

ΔH°min = Σ enthalpies of products - Σ enthalpies of reactants

             = 5× (-1271.94) + 9×( -285.83) - 2(73.2) kj/mol

ΔH°min = -9078.59 kj/mol

It is seen that 2 moles of B₅H₉    react with O₂ is  -9078.59 kj/mol

For 1 mole = -9078.59 kj/mol/2

                 = 4539.295 KJ/mol

The energy released per gram = energy released per mol/molar mass of B₅H₉

                                            = 4539.295 kj/mol/63 g/mol

energy released per gram = -72.052 kj/g

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Respiration, which releases the energy in food molecules, usually involves energy and enzymes.

Respiration is the process by which cells obtain chemical energy by the consumption of oxygen and the release of carbon dioxide.

Respiration is the major process through which living organisms obtain their energy. They do this by breaking down food ingested.

Cellular respiration combines glucose and oxygen to synthesise carbondioxide and water as products. This process synthesize a large amount of energy, however, it utilizes energy as well.

Therefore, energy and enzymes are used up in the process of cellular respiration.

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Answer: An ionic bond.

Explanation:An ionic bond is the force of attraction that holds together positive and negative ions. It forms when atoms of a metallic element give up electrons to atoms of a nonmetallic element. Ionic bonds form only between metals and nonmetals

The rate of a reaction indicates how fast the products are formed or how fast the reactants are consumed. Option A.

The reaction rate or rate of reaction is the rate at which a chemical reaction occurs and is defined as proportional to the increase in the concentration of products per unit of time and the decrease in the concentration of reactants per unit of time. Reaction rates vary greatly. The reaction rate is the rate at which a reaction reaches equilibrium.

In enzyme-catalyzed reactions, the rate is usually expressed as the amount of product produced per minute. The reaction rate is determined by the energy barrier between the reaction and the products. Reaction rate indicates the speed of reaction. That is how quickly reactants are consumed, how quickly products are formed, or how quickly energy is absorbed or released. Reaction speed is a powerful diagnostic tool. By understanding the speed at which products are made and the causes of slow reactions.

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Energy was lost by substance A to the environment is the statement which best supports the data in the table and is denoted as option D.

This is referred to as the processes which is characterized by the movement of energy from one system to another an an example is heat energy transfer which have different techniques such as conduction, convection etc.

Temperature on the other hand is the measure of the degree of hotness or coldness of a substance and is influenced by heat energy.

From the graph, we can deduce that substance has a temperature which was decreasing with time while substance B has a temperature which was constant throughout.

This therefore means that Energy was lost by substance A to the environment hence ,the reason why option D was chosen as the correct choice.

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The d  block elements differ from the main group elements in the nature of the ions that they form. Also, the group number is related to the number of electrons in the valence sell of an atom.

The D block elements are those elements that are found to have d orbitals as the orbitals that has the highest energy in the atom. The d block elements are called the transition metals and they have an incompletely filled d - level.

Owing to the fact that d - level is incompletely filled they do exhibit variable oxidation states and are colored. On the other hand, the main group elements do not exhibit a variable oxidation states and the ions that they form are not colored.

Secondly, for each of the main group elements, the group number shows the number of valence electrons that are present in the outermost shell of the atoms in the elements of the groups.

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The general period and group trends among the main-group elements with respect to each of the following properties are as follows:

Periodic trends are the trends followed by the properties of the elements going down a group or across a period in the periodic table.

The properties of elements that show periodic trends include:

a. atomic radii - the size of an atom of an element

b. first ionization energy - the energy required to remove a valence electron

c. electron affinity - the energy required to add an electron to a neutral atom

d. ionic radii - the size of the ion of an element

e. electronegativity - the ability to attract electrons

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The pKa of the weak acid, based on the titration results, is 4.24.

Only the half-equivalence pH is needed to answer this.

At the half-equivalence point of the titration, half of the monoprotic acid HA has been neutralized and converted to the appropriate salt. That means that the concentration of the acid [HA] is equal to the concentration of its anion [A⁻]. Now, we can consult the Henderson-Hasselbalch equation:

[tex]pH = pKa + log\frac{[A^{-} ]}{[HA]}[/tex]

Because [A⁻] = [HA], that means that:

[A⁻]/[HA] = 1

log(1) = 0

pH = pKa

So, at the half-equivalence point in the titration of the weak acid the pH value of the solution is equal to the pKa value of the weak acid, so pKa = 4.24

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According to the balanced chemical equation, 2 moles of potassium permanganate produces 5 moles or oxidizes 5 moles of sulphite to sulphate ions. As a result, there are 0.639 moles of potassium.

In alkaline solution, KMnO4 reduces to green K₂MnO₄: 4 KMnO₄ + 4 KOH 4 K₂MnO₄ + O₂ + 2 H₂O. This reaction exemplifies hydroxide's uncommon role as a reducing agent. Mn₂O₇ is formed when concentrated sulfuric acid is added to potassium permanganate. One mole of KMnO₄ requires 5 moles of electrons in an acidic medium. Multiply equation (1) by 5 and equation (2) by 3 to balance the number of electrons. In an acidic medium, five moles of ferrous oxalate are oxidized by three moles of KMnO₄.

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.

If you assumed 100 total atoms in a sample, you could relate the % values shown in the sim into a number you could use for your calculation of average atomic mass is

Average atomic mass = ∑ ( isotope mass  × % of abundance )

To calculated the average atomic mass, we have to multiply the isotopes mass of each to the % abundance  then  add .

the formula for the calculation of average atomic mass :

Average atomic mass = ∑ ( isotope mass  × % of abundance )

Thus, If you assumed 100 total atoms in a sample, you could relate the % values shown in the sim into a number you could use for your calculation of average atomic mass is

Average atomic mass = ∑ ( isotope mass  × % of abundance )

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The quantity of Cu deposited at the cathode will be 7.117 grams.

Given,

Current (in Amperes) = 12 A

This will be equal to 12 C/s (in coulombs per second).

Therefore the total charge in 30 minutes will be:

Q = 12C/s × 30 min × 60 seconds/minute

=> Q = 21600 C

Now, the number of moles of copper which are plated out (n) will be :

n = Q / z·F

In the half-cell reaction,

the number of electrons ( for Cu ) will be = 2 (Cu 2+)

F, the Faraday's constant = 96,485 per mole

We have already discussed that,

n = Q / z.F

=> n = 21600 / (2×96485)

=> n = 0.112 mol

So, 0.112 mol of Cu will be equal to:
0.112×63.546 = 7.117 g

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An increase in the surface area of the solid will increase the rate of the reaction.

The reaction rate will be influenced by the solid's surface area if one of the reactants is solid. This is due to the fact that the two kinds of molecules can only collide at the liquid-solid interface, also known as on the surface of the solid. The reaction rate will rise due to a more significant interaction of the surface areas between the two molecules when the solid is pulverized into a gas. If a reactant has a larger surface area: The other reactant is exposed to more particles. Particles are more likely to collide, which results in more successful collisions per second this will influence the reaction speed to increase.

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The molarity of the chemical X is 11.65 M.

To calculate the molarity (c) of the solution, we need the number of moles (n) of substance X and the volume (V) of the solution. We can assume that we have 100 mL = 0.1 L of the solution. Now we have the volume, and we can use it to calculate the mass (m) of the solution using its density (d = 1.18 g/mL):

d = m/V ⇒ m = d * V

m = 1.18 g/mL * 100 mL

m(solution) = 118 g

From this, we can obtain the mass of substance X using the mass percentage (%w = 36% = 0.36):

m(X) = %w * m(solution)

m(X) = 0.36 * 118 g

m(X) = 42.48 g

Now that we have the mass of X, we divide it by its molar mass (M = 36.46 g/mol) to obtain the number of moles:

n = m/M

n = 42.48 g / 36.46 g/mol = 1.165 mol

Finally, we calculate the molarity of the solution:

c = n/V

c = 1.165 mol / 0.1 L = 11.65 M

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From the equation of Graham's law of diffusion of gases, it would take the same number of moles of Ar(g) 23 minutes to effuse through the same membrane.

The rate of diffusion or effusion of gases is affected by temperature, concentration, pressure, and the molecular weight of the gas.

The gas law that describes how the molecular weight or vapor density of a gas affects the rate of diffusion is Graham's law of diffusion of gases.

Mathematically, Graha's law of diffusion of gases is given below as follows:

R₁ / R₂ = √(M₂ / M₁) or T₁ / T₂ = √(M₁ / M₂)

where;

R₁ is the rate of diffusion of gas 1

T₁ is the time of diffusion of gas 1

M₁ is the molecular weight of gas 1

R₂ is the rate of diffusion of gas 2

T₂ is the time of diffusion of gas 2

M₂ is the molecular weight of gas 2

Substituting the values in the second equation:

The molecular weight of Br₂ = 160 g/mol

The molecular weight of Ar = 40 g/mol

46 / T₂ = √(160 / 40)

T₂= 46 / 2

T₂ = 23 mins

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Answer:

d

Explanation:

the group's name is called noble gases. hence they are all gases.

Answer:

density = 5 g/ml

Explanation:

D=m/v. Mass=30g and Volume=6mL

SO solve for D when m = 30 and v = 6

D=m/v

D = 30/6

density = 5 g/ml