what is 2^-3 as a fraction

Answers

Answer 1

Answer:

Solution below.

Step-by-step explanation:

The question tests on the concept of indices.

We know the following indices rule:

[tex] {x}^{ - y} \\ = \frac{1}{ {x}^{y} } [/tex]

Which means by inversing the power, we will multiply the power by -1.

So in the case of this question, we can:

[tex] {2}^{ - 3} = \frac{1}{ {2}^{3} } \\ = \frac{1}{8} [/tex]


Related Questions

Circumference of a circleThe radius of a circle measures 16 m. What is the circumference of the circle?Use 3.14 for, and do not round your answer. Be sure to include the correct unit in your answer.

Answers

Solution:

Given:

[tex]\text{radius of a circle, r = 16m}[/tex]

The circumference (C) of a circle is given by;

[tex]\begin{gathered} C=2\pi r \\ \text{where;} \\ C\text{ is the circumference of the circle} \\ r\text{ is the radius} \end{gathered}[/tex]

Hence,

[tex]\begin{gathered} r=16m \\ \pi=3.14 \\ C=\text{?} \end{gathered}[/tex]

Thus,

[tex]\begin{gathered} C=2\pi r \\ C=2\times3.14\times16 \\ C=100.48m \end{gathered}[/tex]

Therefore, the circumference of the circle is 100.48m

i need help with this question... it's about special right triangles. The answer should not be a decimal.

Answers

4) The given triangle is a right angle triangle. Taking 30 degrees as the reference angle,

hypotenuse = 34

adjacent side = x

opposite side = y

We would find x by applying the Cosine trigonometric ratio which is expressed as

Cos# = adjacent side/hypotenuse

Cos 30 = x/34

Recall,

[tex]\begin{gathered} \cos 30\text{ = }\frac{\sqrt[]{3}}{2} \\ \text{Thus, } \\ \frac{\sqrt[]{3}}{2}\text{ =}\frac{x}{34} \\ 2x=34\sqrt[]{3} \\ x\text{ = }\frac{34\sqrt[]{3}}{2} \\ x\text{ = 17}\sqrt[]{3} \end{gathered}[/tex]

To find y, we would apply the Sine trigonometric ratio. It is expressed as

Sin# = opposite side/hypotenuse

Sin30 y/34

Recall, Sin30 = 0.5. Thus

0.5 = y/34

y = 0.5 * 34

y = 17

You got 84 of 100 questions on the test correct. What percent did you get correct?Answer: 84%100%16%8.4%11/100 is equal to what percent?Answer: 110%10%89%11%3 out of 4 students in your class are girls. What percent of the class are girls?Answer: 3%4%75%25%

Answers

[tex]\begin{gathered} \text{To get the percentage of divide the number of correct items in test} \\ \text{by the number of total test items} \\ \text{correct test items}=84 \\ \text{total test items}=100 \\ 84\div100=0.84 \\ \text{after, multiply it by }100\%\text{ to get the percentage} \\ 0.84\times100\%=84\% \end{gathered}[/tex]

in the diagram segment AD and AB are tangent to circle C solve for x

Answers

A property ostates that if two lines that are tangent to the circle intersect in an external point, they are congruent, i.e. they have the same length.

[tex]\begin{gathered} AD=AB \\ x^2+2=11 \end{gathered}[/tex]

From this expression we can determine the possible values of x. The first step is to equal the expression to zero

[tex]\begin{gathered} x^2+2-11=11-11 \\ x^2+2-11=0 \\ x^2-9 \end{gathered}[/tex]

The expression obtained is a quadratic equation, using the queadratic formula we can determine the possible values of x:

[tex]\begin{gathered} f(x)=ax^2+bx+c \\ x=\frac{-b\pm\sqrt[]{b^2-4ac}}{2a} \end{gathered}[/tex]

For our expression

[tex]x^2+0x+-9[/tex]

The coefficients are

a=1

b=0

c=-9

Replace them in the formula

[tex]\begin{gathered} x=\frac{-0\pm\sqrt[]{0^2-4\cdot1\cdot(-9)}}{2\cdot1} \\ x=\frac{0\pm\sqrt[]{36}}{2} \\ x=\frac{0\pm6}{2} \end{gathered}[/tex]

Now calculate both possible values:

Positive:

[tex]\begin{gathered} x=\frac{+6}{2} \\ x=3 \end{gathered}[/tex]

Negative:

[tex]\begin{gathered} x=\frac{-6}{2} \\ x=-3 \end{gathered}[/tex]

The possible values of x are 3 and -3

Quadrilateral OPQR is dilated by a scale factor of 2/3 to form quadrilateral O'P'Q'R'. What is the measure of side RO?

Answers

Divide side R'O' (8) by th scale factor (2/3)

8 : 2/3= 12

30-28-25-21-16 next number

Answers

Answer:

10

Step-by-step explanation:

30 -2

28 -3

25 -4

21 -5

16 -6

= 10

Answer:

  10

Step-by-step explanation:

Given the sequence 30, 28, 25, 21, 16, you want to know the next number.

Differences

First differences between successive terms are ...

  28 -30 = -2

  25 -28 = -3

  21 -25 = -4

  16 -21 = -5

These are not constant, so this is not an arithmetic sequence. However, we notice the second differences are constant:

  -3 -(-2) = -1

  -4 -(-3) = -1

  -5 -(-4) = -1

Application

This observation tells us the next second difference is ...

  -5 +(-1) = -6

And the next number in sequence is ...

  16 +(-6) = 10

The next number is 10.

__

Additional comment

When a sequence of numbers is described by a polynomial or exponential, looking at differences (and their differences) can help determine the degree of the polynomial, or the common ratio of the exponential.

Here, the second differences are constant, so a second-degree (quadratic) polynomial will describe the sequence. The polynomial describing this sequence is ...

  a(n) = 31 -(n)(n+1)/2

how the position of the decimal point changes in a q u o t i e n t as you divide by Precinct power of 10.

Answers

When we divide a number by a power of 10, the decimal point changes its position. Specifically, the decimal points will move to the left according to the exponent of the power. For example, let's say we have the following division.

[tex]\frac{542}{10^3}[/tex]

As we said before, we just have to move the decimal point to the left. In this case, we have to move it to 3 spots.

[tex]\frac{542}{10^3}=0.542[/tex]

Hence, the division is equivalent to 0.542.

That's how the division works when you divide by a power of 10.

Is 7.787887888... a rational number?Highlight the correct answer below.a) Yes; it has a pattern which is repeatingb) Yes; it has a pattern which isterminatingc) No; it has a pattern which isterminatingd) No; it has a pattern which is repeating

Answers

A)

If This number 7.787887888... could be written as a ratio

[tex]\frac{a}{b}[/tex]

Then it is called rational.

Since it has 7.78788788788... is an infinite number, with a repeating pattern notice it in bold. Then the only possible answer is:

Yes, it as a rational number, with a repeating pattern.

A.

Find the missing factor. x2 - 11x + 18 = (x - 2)( .) Enter the correct answer. 000 DONE Clear all DOO

Answers

we have the second degree polynomial

[tex]x^2-11x+18[/tex]

we must find two numbers a,b such that

[tex]\begin{gathered} x^2-11x+18=(x+a)(x+b)\text{ and} \\ a+b=11 \\ ab=18 \end{gathered}[/tex]

We can see that, a=-2 and b=-9 fulfill the above conditions. Therefore, we have

[tex]x^2-11x+18=(x-2)(x-9)\text{ }[/tex]

Which statement explains whether x=5 is the solution to 5x + 2 = 27? a. Yes, because 5x means x=5.b. No, because 5x doesn't mean x=5.c. No, because when x is replaced by 5 the equation is false. d. Yes, because when x is replaced by 5 the equation is true.

Answers

Given

x = 5

5x + 2 = 27

Procedure

d. Yes, because when x is replaced by 5 the equation is true. ​

Silvergrove Hardware kept an inventory of 517,110 lawnmowers in the past. With a change inmanagement, the hardware store now keeps an inventory of 70% more lawnmowers. Howmany lawnmowers is that?

Answers

879,087.

EXPLANATION

To find the number of lawnmowers, we need to first find 70% of the number of lawnmowers that was kept in the past. Then add the to the number of lawnmowers kept in the past.

From the given question;

Number of lawnmowers kept in the past = 517, 110.

70% of lawnmowers kept in the past = 70% of 517 110

[tex]\begin{gathered} =\frac{70}{100}\times517\text{ 110} \\ \\ =361\text{ 977} \end{gathered}[/tex]

Number of lawnmowers now kept in store = number of lawnmowers kept in the past + 70% of lawnmowers kept in the past

= 517 110 + 361 977

= 879,087.

A parallelogram has an 9 inch base. if the parallelogram has an area of 54 square inches, find the height of the parallelogram.

Answers

In order to find the height of the parallelogram, we can use the following formula for its area:

[tex]A=b\cdot h[/tex]

Where A is the area, b is the base and h is the height of the parallelogram.

Using A = 54 and b = 9, we can solve the equation for h:

[tex]\begin{gathered} 54=9\cdot h \\ h=\frac{54}{9} \\ h=6 \end{gathered}[/tex]

So the height of the parallelogram is 6 inches.

Bryce drew a rectangle and labeled five of the angles, as shown. He knew these factsWHOabout the angles:• The measurements of angles 1 and 3 are the same.The measurement of angle 2 equals 110°.• The measurements of angles 3 and 5 are the same.Part A Based on these facts, what is the sum of the measurements of angle 1and angle 2? Show your work or explain your answer.Part B What is the measurement of angle 4? Show your work or explain your answer.

Answers

The given figure is;

It is given that :

The measurements of angles 1 and 3 are the same.

The measurement of angle 2 equals 110°.

PART A:

Since, angle 1 , 2 and 3 are lie at the same point on the same line

Thus, from the property of angle on a line

Sum of all angles on a strainght line at a point is equal to 180 degree

thus;

Angle1 + Angle2 + Angle 3 = 180

Angle 1 + Angle 2 + Angle1 = 180 {Angle1 = Angle 3, given}

2(Angle 1) + Angle 2 = 180

2 (angle 1) + 110 = 180 {Angle 2 = 110, given}

2(Angle 1) = 180 -110

2(Angle 1) = 70

Angle 1 = 70/2

Angle 1 = 35

Since, angle 2 = 110

The sum of angle 1 and 2 is 110 + 35

Sum of angle 1 and 2 = 145

PART B:

From the properties of the rectangle;

All the angles of a rectangle are 90°

In the given rectangle;

Thus, in the triangle form by the angle3, 4 and the right angle

Sum of all angles in a triangle is equal to 180

Angle 3 + Angle 4 + 90 = 180

35 + Angle 4 + 90 = 180

Angle 4 + 125 = 180

Angle 4 = 180 - 125

Angle 4 = 55

.....

PR and SU are parallel lines. Which angles are corresponding angles?

Answers

Given

PR and SU are parallel lines.

To find the pair of corressponding angles.

Explanation:

From, the figure,

Since PR and SU are parallel and the corressponding angles lie in the same corner.

Then,

[tex]\begin{gathered} \angle PQO,\angle STQ \\ \text{are corressponding angles.} \end{gathered}[/tex]

Hence, the answer is Option c).

Segment RS is translated by (x+1, y-2) and then reflected over the x-axis. The resulting segment R" S" has coordinates R" (7,3) and
S" (2,7). What are the coordinates of the segment RS?

can someone pls help meee

Answers

Answers:

R = (6, -1)

S = (1, -5)

==========================================================

Explanation:

R'' is located at (7,3)

Reflect this over the x axis to get R'(7,-3). We flip the sign of the y coordinate while keeping the x coordinate the same. The rule is [tex](x,y) \to (x,-y)[/tex]

Then we apply the inverse of (x+1, y-2) which is (x-1, y+2). Notice the sign flips.

Let's apply this inverse transformation to determine the coordinates of point R.

[tex](\text{x},\text{y})\to(\text{x}-1,\text{y}+2)\\\\(7,-3)\to(7-1,-3+2)\\\\(7,-3)\to(6,-1)\\\\[/tex]

Therefore, point R is located at (6, -1)

-------------------

Point S'' is at (2,7)

It reflects over the x axis to get to (2,-7)

Then we apply that inverse transformation to get

[tex](\text{x},\text{y})\to(\text{x}-1,\text{y}+2)\\\\(2,-7)\to(2-1,-7+2)\\\\(2,-7)\to(1,-5)\\\\[/tex]

Point S would be located at (1, -5)

Solve the triangle for the missing sides and angles. Round all side lengths to the nearest hundredth. (Triangle not to scale.)

Answers

The Law of Cosines

Let a,b, and c be the length of the sides of a given triangle, and x the included angle between sides a and b, then the following relation applies:

[tex]c^2=a^2+b^2-2ab\cos x[/tex]

The triangle shown in the figure has two side lengths of a=4 and b=5. The included angle between them is x=100°. We can find the side length c by substituting the given values in the formula:

[tex]c^2=4^2+5^2-2\cdot4\cdot5\cos 100^o[/tex]

Calculating:

[tex]c^2=16+25-40\cdot(-0.17365)[/tex][tex]\begin{gathered} c^2=47.946 \\ c=\sqrt[]{47.946}=6.92 \end{gathered}[/tex]

Now we can apply the law of the sines:

[tex]\frac{4}{\sin A}=\frac{5}{\sin B}=\frac{c}{\sin 100^o}[/tex]

Combining the first and the last part of the expression above:

[tex]\begin{gathered} \frac{4}{\sin A}=\frac{c}{\sin100^o} \\ \text{Solving for sin A:} \\ \sin A=\frac{4\sin100^o}{c} \end{gathered}[/tex]

Substituting the known values:

[tex]\begin{gathered} \sin A=0.57 \\ A=\arcsin 0.57=34.7^o \end{gathered}[/tex]

The last angle can be ob

Recipe A calls for 2 cups of sugar and makes 48 cookles. Recipe B calls for 3 cups of sugar and makes 54 of the same sized cookies. Determine which recipe contains more sugar in each cookle. Use complete sentences to explain your reasoning.

Answers

we are given two recipes for cookies and we are asked which of the two contains more sugar. To do that we need to find the amount of sugar per cookie for each recipe.

For recipe A we have:

[tex]2cups\rightarrow48cookies[/tex]

This means:

[tex]\frac{2cups}{48cookies}=\frac{1}{24}\frac{cups}{cookies}[/tex]

For recipe B we have:

[tex]3cups\rightarrow54\text{cookies}[/tex]

This means:

[tex]\frac{3\text{cups}}{54\text{cookies}}=\frac{1}{18}(\frac{cups}{cookies})[/tex]

Since 1/18 is greater than 1/24, this means that there is more sugar per cookie in recipe B than in recipe A.

4 ft 12 ft The pitch of the roof is

Answers

As shown : in the figure

The pitch of the roof is the angle between the roof and the horizontal line

As shown we have a right angle triangle

The opposite side to the angle = 4 ft

And the adjacent side to the angle = 12 ft

According to the given sides, we will calculate the angle using tan function

So, let the angle = x

So,

[tex]\begin{gathered} \tan x=\frac{opposite}{adjacent} \\ \\ \tan x=\frac{4}{12}=\frac{1}{3} \\ \\ x=\tan ^{-1}\frac{1}{3}\approx18.435^o \end{gathered}[/tex]

So, the pitch angle of the roof = 18.435

instead of writing the angle , just we will write the slope = rise/run

So, the pitch of the roof = 1/3

The sides of an equilateral triangle are 8 units long. What is the length of the altitude of the triangle? N O svē units O 4/3 units 10,5 units O 165 units M

Answers

The all the sided of the equlatral triangle have the same lentgth. All the angles of the triangles are 60 degrees.

The expression for the hight of a equlatral triangle is,

[tex]\sin (60^0)=\frac{h}{l}_{}[/tex]

Here, ''

Which of the following ordered pairs is a solution to the graph of the system of inequalities? Select all that apply(5.2)(-3,-4)(0.-3)(0.1)(-4,1)

Answers

For this type of question, we should draw a graph and find the area of the common solutions

[tex]\begin{gathered} \because-2x-3\leq y \\ \therefore y\ge-2x-3 \end{gathered}[/tex][tex]\begin{gathered} \because y-1<\frac{1}{2}x \\ \therefore y-1+1<\frac{1}{2}x+1 \\ \therefore y<\frac{1}{2}x+1 \end{gathered}[/tex]

Now we can draw the graphs of them

The red line represents the first inequality

The blue line represents the second inequality

The area of the two colors represents the area of the solutions,

Let us check the given points which one lies in this area

Point (5, -2) lies on the area of the solutions

(5, -2) is a solution

Point (-3, -4) lies in the blue area only

∴ (-3, -4) not a solution

Point (0, -3) lies in the red line and the red line is solid, which means any point on it will be on the area of the solutions

(0, -3) is a solution

Point (0, 1) lies in the blue line and the blue line is dashed, which means any point that lies on it not belong to the area of the solutions

∴ (0, 1) is not a solution

Point (-4, 1) lies on the area of the solutions

(-4, 1) is a solution

The solutions are (5, -2), (0, -3), and (-4, 1)

the width of a rectangle is 8 inches less than its length, and the area is 9 square inches. what are the length and width of the rectangle?

Answers

The given situation can be written in an algebraic way:

Say x the width of the rectangle and y its height.

- The width of a rectangle is 8 inches less than its length:

x = y - 8

- The area of the rectangle is 9 square inches:

xy = 9

In order to find the values of y and x, you first replace the expression

x = y - 8 into the expression xy = 9, just as follow:

[tex]\begin{gathered} xy=9 \\ (y-8)y=9 \end{gathered}[/tex]

you apply distribution property, and order the equation in such a way that you obtain the general form of a quadratic equation:

[tex]\begin{gathered} (y-8)y=9 \\ y^2-8y=9 \\ y^2-8y-9=0 \end{gathered}[/tex]

Next, you use the quadratic formula to solve the previous equation for y:

[tex]y=\frac{-b\pm\sqrt[]{b^2-4ac}}{2a}[/tex]

here you have a = 1, b = -8 and c = 9. By replacing these values you obtain:

[tex]\begin{gathered} y=\frac{-(-8)\pm\sqrt[]{(-8)^2-4(1)(-9)}}{2(1)}=\frac{8\pm\sqrt[]{64+36}}{2} \\ y=\frac{8\pm\sqrt[]{100}}{2}=\frac{8\pm10}{2}=\frac{8}{2}\pm\frac{10}{2}=4\pm5 \end{gathered}[/tex]

Hence, you have two solutions for y:

y1 = 4 + 5 = 9

y2 = 4 - 5 = -1

You select only the positive solution, because negative lengths do not exist in real life. Hence, you have y = 9.

Finally, you replace the value of y into the expression x = y - 8 to obtain x:

[tex]\begin{gathered} x=y-8 \\ x=9-8 \\ x=1 \end{gathered}[/tex]

Hence, the width and length of the given recgtangle are:

width = 1 in

length = 9 in

A company needs to take 10 sample sensor readings if the sensor collects data at 1/3 of a sample per second how long will it take the company to take all 10 samples

Answers

Given:

Sample space = 10

Rate = 1/3 per second

v+1.6>-5.5
nnnnnnnnnnnn

Answers

Answer:

v > -7.1

Step-by-step explanation:

At an appliance store, if 63 stereos were sold during a one-month period, which of the following must be true?A. At least one stereo was sold on each day of the monthB. Exactly two stereos were sold on the same day during the monthC. At least one stereo was sold on either Monday, Wednesday, or Friday during the monthD. At least three stereos were sold on one day of the month.

Answers

Answer:

Alternative D. At least three stereos were sold on one day of the month.

Explanation:

Now, let's evaluate the options:

A. At least one stereo was sold on each day of the month

It is false.

We can not affirm that. For example, all the stereos can be sold on only one day of the month

B. Exactly two stereos were sold on the same day during the month

It is false.

Same explanation as A.

C. At least one stereo was sold on either Monday, Wednesday, or Friday during the month

It is false.

We can not affirm that too. The explanation is the same as for alternative A.

D. At least three stereos were sold on one day of the month.

It is true.

If two stereos are sold every day, for a month of 30 days, 60 stereos are sold. So, on some days 3 or more stereos are sold.

Also, if all the stereos are sold on the same day, more than 3 stereos were also sold.

So, alternative D is correct.

PLEASE HURRY!!!!!

Here is a hanger diagram. With a hanger diagram, when the diagram is balanced, there is equal weight on each side. Write an equation to represent the hanger. (Do NOT put spaces in your answer.)

Answers

Answer:

x = 8

x = 3

x = 2

x = 1

x = 1

x = 2

x + x+ x+ x+ x+ 2 = 17

try any number

Gina want to estimate the total of three bills she has to pay. the bills are for $125,$115,and $138. Gina wants to make sure that she has enough money. she wants the estimate to be greater than the total of the bills. should she round to the nearest ten or hundred

Answers

The bills are:

125

115

138

Since she wants an estimate that is greater than the actual total, she can round these numbers to the nearest ten.

125 will be rounded to the next tens, which is 130

115 will also be rounded to the next tens, which is 120

138 gets bumped to the next tens, that is 140

The total estimate is the sum of the 3 estimates we just made. That is:

130 + 120 + 140 = $390

You need a quarter of a pumpkin
to make a pie. How many pies
can you make with three and a
half pumpkins?

Answers

14 pies with 3.5 pumpkins.

Answer: 14

Step-by-step explanation:

1/4 of a pumpkin is required to make a pie. The easiest way to complete this is to convert 3.5 pumpkins into the same fraction.

1 pumpkin = 4/4

3.5 pumpkins = 14/4

If only 1/4 of a pumpkin is required to make a pie and we have 14/4 then we can make 14 pumpkin pies.

A parent is buying two types of chocolate truffles for the children. The oldest child likes white chocolate (W), the younger two like dark chocolate (D) and the spouse likes white chocolate (W). Four white chocolate truffles (W) cost the same as three dark chocolate truffles (D). If the parent bought 8 white chocolate truffles(W) and 10 dark chocolate truffles (D), and spent $50.00, how much was each dark chocolate truffle?2.422.343.13

Answers

SOLUTION

Given the information on the question tab;

[tex]Let\text{ the price for a white chocolate truffle be W, and the price for a dark chocolate truffle be D;}[/tex][tex]\begin{gathered} From\text{ the statements made in the question;} \\ 4W=3D-----(1) \\ 8W+10D=50----(2) \end{gathered}[/tex]

[tex]\begin{gathered} From\text{ equation \lparen1\rparen;} \\ W=\frac{3D}{4}-----(3) \\ substituting\text{ W=}\frac{3D}{4}\text{ into equation \lparen2\rparen} \end{gathered}[/tex][tex]\begin{gathered} 8\times\frac{3D}{4}+10D=50 \\ 6D+10D=50 \\ 16D=50 \\ D=\frac{50}{16} \\ D=3.125\approx3.13 \end{gathered}[/tex]

Final answer:

Each dark chocolate truffle costs $3.13

What is lim (2x² - x + 3)/(3x² + 5) as x approaches + ∞?

Answers

Given:

lim (2x² - x + 3)/(3x² + 5)

We are to

Solve equation for x. 5x^2 - 4x =6

Answers

Answer:

Step-by-step explanation:

use the quadratic formula

5x^2-4x-6

4+-[tex]\sqrt{16+120}[/tex] all over 10

4+-[tex]2\sqrt{34}[/tex]/10

2+-[tex]\sqrt{34}[/tex]/5

D

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