Answer:
16
Step-by-step explanation:
6!3!
-------
2!5!
(1 × 2 × 3 × 4 × 5 × 6)(1 × 2 × 3)
--------------------------------------------
(1 × 2)(1 × 2 × 3 × 4 × 5)
(720)(6)
-------------------
(2)(120)
4320
------------ = 18
240
I hope this helps!
-14.4 + x = -8.2what does x equal?I NEED ANSWERS ASAPi will give brainliest
the given expression is,
-14.4 + x = -8.2
x = 14.4 - 8.2
x = 6.2
thus, the answer is x = 6.2
I need help with this practice I am new to this subject of mathematics (algebra) Can you show me how to solve this STEP-BY-STEP?
Given:
[tex]4+x+8=24[/tex]Required:
To find the correct one.
Explanation:
The given quation is:
4 + x +8 =24
Subtract 8 on both sides
4 + x +8 - 8 = 24 -8
4 + x = 16
Final Answer:
Thus the first option is the correct answer.
The following table represents C, an appliance repairman’s charges based on t, the hours it takes to make a repair.Which of the following equations could be used to determine the repairman’s charges for a repair?A: C=27t +3B: C=27tC: C=35tD: C=35t + 2
Given the table below
To find the equation of the values of the table, we will first calculate the rate of change, then use a point and the rate of change calculated fo find the equation for the repairman's charges for the repair
To find the rate of change we have
[tex]\text{ Point 1}\Rightarrow(1,62)\Rightarrow t_1=1,c_1=62[/tex][tex]\text{ Point 2}\Rightarrow(3,116)\Rightarrow t_2=3,c_2=116[/tex]The rate of change formula is
[tex]m=\frac{c_2-c_1}{t_2-t_1}=\frac{116-62}{3-1}=\frac{54}{2}=27[/tex]Having calculated the rate, we can use slope and one point form equation of a line to get the desired equation. This is given below:
[tex]c-c_1=m(t-t_1)[/tex]Substitute the given values of t and c and the rate in the formula above
[tex]\begin{gathered} c-62=27(t-1) \\ c-62=27t-27 \\ c=27t-27+62 \\ c=27t+35 \end{gathered}[/tex]Hence, the repairman's charges for a repair is given as C = 27t + 35
Solve for u-6u+3(u-3)=12
Answer: u=7
Given:
[tex]-6u+3(u-3)=12[/tex]- Distribute 3(u-3):
[tex]\begin{gathered} -6u+3(u-3)=12 \\ \Rightarrow-6u+3u-9=12 \end{gathered}[/tex]- Combine like terms:
[tex]\begin{gathered} \begin{equation*} -6u+3u-9=12 \end{equation*} \\ \Rightarrow-6u+3u=12+9 \\ \Rightarrow-3u=21 \end{gathered}[/tex]- Divide both sides by -3:
[tex]\begin{gathered} \begin{equation*} -3u=21 \end{equation*} \\ \Rightarrow\frac{-3u}{-3}=\frac{21}{-3} \\ \Rightarrow u=7 \end{gathered}[/tex]Therefore, u=7.
f(x) =-x² + 2x + 6
Find f(-7)
how is the metric system important to a pharmacy Technician?
The metric system is a system of decimals in which all the measurements are taken as multiples or divisions based on a factor of 10. We have to convert between different units of measurements while working in a pharmacy. Metric system helps to make fast and easy conversions of units of measurements. Therefore, metric system is important to a pharmacy technician.
has overdrawn his bank account Jim has overdrawn his bank account and has a balance of -$3.47.he received a paycheck of $292.54 he deposits $163.93 of his paycheck into his account how much does Jim have in his bank account after the deposit is made
Since Jim deposits $ 163.93 of his paycheck into his account and there has a balance of - $ 3.47, then he has in his account:
[tex]\text{\$}$163.93$-\text{\$}3.47=\text{ \$}160.46[/tex]Therefore, Jim has $ 160.46 in his bank account after the deposit is made.
Write problem as a single radical using the smallest possible root. 20
Answer::
[tex]\sqrt[30]{r^{29}}[/tex]Explanation:
Given the expression:
[tex]\sqrt[5]{r^4}\sqrt[6]{r}[/tex]First, rewrite the expression using the fractional index law:
[tex]\begin{gathered} \sqrt[n]{x}=x^{\frac{1}{n}} \\ \implies\sqrt[5]{r^4}=r^{\frac{4}{5}};\text{ and} \\ \sqrt[6]{r}=r^{\frac{1}{6}} \end{gathered}[/tex]Therefore:
[tex]\sqrt[5]{r^4}\times\sqrt[6]{r}=r^{\frac{4}{5}}\times r^{\frac{1}{6}}[/tex]Use the multiplication law of exponents:
[tex]\begin{gathered} a^x\times a^y=a^{x+y} \\ \implies r^{\frac{4}{5}}\times r^{\frac{1}{6}}=r^{\frac{4}{5}+\frac{1}{6}} \\ \frac{4}{5}+\frac{1}{6}=\frac{24+5}{30}=\frac{29}{30} \\ \operatorname{\implies}r^{\frac{4}{5}}\times r^{\frac{1}{6}}=r^{\frac{4}{5}+\frac{1}{6}}=r^{\frac{29}{30}} \end{gathered}[/tex]The resulting expression can be rewrittem further:
[tex]\begin{gathered} r^{\frac{29}{30}}=(r^{29})^{\frac{1}{30}} \\ =\sqrt[30]{r^{29}} \end{gathered}[/tex]The single radical is:
[tex]\sqrt[30]{r^{29}}[/tex]the table below shows an inspectors measurement of the lengths of four bridges
Given
Table which ahows an inspectors measurement of the lengths of four bridges
Find
Order from shortest to longest lengths of bridges.
Explanation
First we convert the lengths of Bridges in improper form , then in decimal form.
[tex]\begin{gathered} M=1\frac{49}{60}=\frac{109}{60}=1.817 \\ \\ N=1\frac{79}{100}=\frac{179}{100}=1.79 \\ \\ O=1\frac{52}{75}=\frac{127}{75}=1.693 \\ \\ P=1\frac{97}{120}=\frac{217}{120}=1.80 \end{gathered}[/tex]so , O has shortest length and M has longest length.
Final Answer
Therefore ,
the order from shortest to longest is
Bridge O , Bridge N , Bridge P and Bridge M , so the correct option is 1
I need help with this and it is delivered at 3:30 pm and sadly I did not understand almost anything and I am confused.Problem 1
Reflection across the y-axis transforms the point (x,y) into (-x, y)
Applying this rule to points A, B, and C, we get:
A(-5, 6) → A'(5, 6)
B(3, 6) → B'(-3, 6)
C(-3, 2) → C'(3, 2)
Given that figure ABC was reflected, then figure A'B'C' is congruent with figure ABC
f(x) = x^3- 9x^2 + 10.c ) list the x values of all the inflection points of F
To find the inflection points the first step we have to follow is to find the second and third derivatives of the function:
[tex]\begin{gathered} f\mleft(x\mright)=x^3-9x^2+10 \\ f^{\prime}\left(x\right)=3x^2-18x \\ f^{\prime}^{\prime}\left(x\right)=6x-18 \\ f^{\prime}^{\prime}^{\prime}\left(x\right)=6 \end{gathered}[/tex]Now, find the values of x for which the second derivative is 0:
[tex]\begin{gathered} 0=6x-18 \\ 18=6x \\ x=\frac{18}{6} \\ x=3 \end{gathered}[/tex]Evaluate the third derivative at this values of x, if the third derivative is different from 0, then that value is an inflection point:
[tex]f^{\prime}^{\prime}^{\prime}\left(3\right)=6[/tex]It means that there is an inflection point at x=3.
Pls help & also give an easy explanation thank youuuuu
Given
A digital picture frame with a border of 3 cm. The actual length of the frame is x
Answer
a) The actual side of the picture is x-3
Area of picture
[tex]=(side)^2=(x-3)^2[/tex]b) Area of frame
[tex]x^2[/tex]c) Area of border = Area of frame - area of picture
[tex]x^2-(x-3)^2[/tex]8) Use the graph to determine the independent variable. Money Saved 240 210 180 A Number of Weeks 150 120 Amount of Money ($) B) The Amount of Money 90 © Money Saved 60 30 0 1 2 6 7 8 3 4 5 Number of Weeks
Generally equations are in the form:
y = mx + b
Where
x is the independent variable, you can choose any value for x
y is the dependent variable. The value of y depends on x.
In the graph, the x-axis is number of weeks and y-axis is amount.
Amount depends on the number of weeks, which is the independent variable, here in this graph.
To produce a textbook, suppose the publisher spent $110,000 for typesetting and $7.50 per book for printingand binding. The total cost to produce and print n books can be written asC = 110,000+ 7.51a. Suppose the number of books printed in the first printing is 10,000. What is the total cost?The total cost is $b. If the average cost is the total cost divided by the number of books printed, find the average cost of producing10,000 textbooks.The average cost of producing 10,000 textbooks is $c. Find the cost to produce one more textbook when you have already produced 10,000 textbooks.If you have already produced 10,000 textbooks, it'll cost you $ to produce one more.
The given equation is
[tex]C=110000+7.5n[/tex]a)
The number of books=10000
Substitute n=10000 in the given equation, we get
[tex]C=110000+7.5\times10000[/tex][tex]C=185000[/tex]The total cost is $185,000.
b)
[tex]\text{Average cost =}\frac{185000}{10000}=18.5[/tex]The average cost of producing 10,000 textbooks is $18.5.
c)
If we need to produce one more after producing 10000 books.
substitute n=10001 in the given equation, we get
[tex]C=110000+7.5(10001)=185007.5[/tex][tex]\text{One book cost after printed 10000 book=cost of 10000 books-cost of 10001 books}[/tex][tex]\text{One book cost after printed 10000 book=1}85000-185007.5=7.5[/tex]
If you have already produced 10,000 textbooks, it'll cost you $7.5 to produce one more.
Check each answer to see whether the students evaluated the expression correctly. If the answer is incorrect cross out the answer and write the correct answer. 8(x+2)when x= 68(6+2) = 48 +2 = 50
The answer is not correct. There is a mistake applying the distributive property.
The distributive property says:
[tex]a(b+c)=ab+ac[/tex]But in this case, the 8 only multiplies the 6, and not the 2. The correct procedure is:
[tex]8(6+2)=8\cdot6+8\cdot2=48+16=64[/tex]The correct answer is 64
The Entertainment Center accumulates the following cost and net realizable value (NRV) data at December 31.
Inventory
Cost
Categories Data
Camera
Camcorders
DVDs
$11,600 $10,100
8,500
8,000
Market
Data
13,500
12,900
What is the lower-of-cost-or-net-realizable-value of the inventory?
Lower-of-cost-or-net-realizable-value $
The lower-of-cost-or-net-realizable-value of the inventory is $31000.
Define net-realizable-value.An asset's worth is often assessed using the net realizable value (NRV) approach for inventory accounting. It is discovered by calculating the difference between the asset's anticipated selling price and all of the expenses related to the asset's eventual sale. The cash sum that a corporation anticipates receiving is known as net realizable value (NRV). Consequently, net realizable value is also known as cash realizable value. The terms "net realizable value" and "current assets" are frequently used in relation to inventory and accounts receivable.
Given,
Camera
Cost = 11600
Market value = 10100
(Market value is less. so 10100.)
Camcorders
Cost = 8500
Market value = 8000
( Market value is less so 8000)
DVD
Cost = 13500
Market value = 12900
(Market value is less, so 12900)
the lower-of-cost-or-net-realizable-value of the inventory:
= 10100 + 8000 + 12900
= 31000
The lower-of-cost-or-net-realizable-value of the inventory is $31000.
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4. A survey explored the relationship between gender and video game play. Which is not a reasonable interpretation of the data? Play Daily Do Not Play Daily Total Boys 45 5 50 Girls 12 38 50 Total 57 43 100 O A) More boys surveyed play video game daily than girls. TO B) Ignoring gender, a little more than half of the students surveyed play video games daily. Of the boys surveyed, 5% do not play video games daily. OD) Of the girls surveyed, exactly 24% play video games daily.
Answer:
C.
Explanation:
Let's analyze each answer option:
Option A.
Taking into account the table, we can say that 45 boys play video games daily and 12 girls play video games daily, so more boys play video games daily than girls because 45 is greater than 12.
Option B.
In the same way, there is a total of 57 students that play video games daily and 43 that don't. Since 57 is a little higher than 50 (half of the 100 students surveyed), we can say that a little more than a half of the students surveyed play video games daily.
Option C.
There are 50 boys surveyed and from them 5 do not play video games daily, so the percentage of boys that don't play video games daily is:
[tex]\frac{5}{50}\times100=0.1\times100=10\text{ \%}[/tex]Option D.
In the same way, there are 50 girls surveyed, and 12 play video games daily, so the percentage of girls that play video games daily is:
[tex]\frac{12}{50}\times100=0.24\times100=24\text{ \%}[/tex]Therefore, the only option that is not a reasonable interpretation of the data is C. because the percentage of boys that don't play video games daily is 10% instead of 5%
I am going to have to send you a photo of the problem during the session because it is to large to crop here.
Direct variations have an special characteristic: they can be represented on a plane by a line paassing through the origin (0,0).
The equation of a line has the following shape:
[tex]y=mx+b[/tex]Where x is the slope, and b is the y intercept.
For direct variations, the line passes through the origin; then, the y intercept is 0, therefore b=0.
For direct variations, we can have an associated line with the following shape:
[tex]y=mx[/tex]We can find the value for m knowing 2 points of the line and calculating the slope. One point is (-1,-4); and the other is the origin (0,0).
Now we can calculate the slope by dividing y distance of the points by the x distance of the points:
[tex]m=\frac{0-(-4)}{0-(-1)}=\frac{0+4}{0+1}=\frac{4}{1}=4[/tex]We have calculated the slope to be 4, then the equation representing the direct variation is:
[tex]y=4x[/tex]Any pair of points x,y that satisfy the equation will an element of the direct variation.
Now, we can try each:
With 8,0:
[tex]\begin{gathered} 0=4\cdot8 \\ 0=16 \end{gathered}[/tex]8,0 does not satisfy, therefore it is not an element of the direct variation.
2,8:
[tex]\begin{gathered} 8=4\cdot2 \\ 8=8 \end{gathered}[/tex]2,8 is element of the dierct variation
-2,0:
[tex]\begin{gathered} 0=4\cdot(-2) \\ 0=-8 \end{gathered}[/tex]-2,0 is not part
4,-1:
[tex]\begin{gathered} -1=4\cdot4 \\ -1=16 \end{gathered}[/tex]4,-1 is not part
8,-1:
[tex]\begin{gathered} -1=4\cdot8 \\ -1=32 \end{gathered}[/tex]8,-1 is not part
-2,-8:
[tex]\begin{gathered} -8=4\cdot(-2) \\ -8=-8 \end{gathered}[/tex]-2,-8 is part.
Finally, we can say points (-4,-1), (2,8) and (-2,-8) are part of the direct variation.
Which of the following systems of equations is an example of one where elimination is the best method?A) {y=27x+11 {3x−4y=−24 B) {4x+5y=20 {−4x+6y=24 C) {y=13x+15 {2x−2y=18 D) {x = 11 {y = -8
Answer:
Explanation:
When solving a system of equations, the elimination method is best used when the system is given in such a way that the coefficients of one variable can be eliminated by addition or subtraction.
Of the given system of equations, the example of where elimination is the best method is:
[tex]\begin{gathered} 4x+5y=20 \\ -4x+6y=24 \end{gathered}[/tex]In this example, we see that the variable 'x' can be directly eliminated by adding the two equations.
The correct option is B.
Ashlynn is trying a low-carbohydrate diet. She would like to keep the amount of carbs consumed in grams between the levels shown in the following compound inequality:460 < 2x + 10 and 2x + 10 < 660Solve for x in the inequality, and explain what the answer represents
To find:
The value of x.
Solution:
The given compound inequalities are 460 < 2x + 10 and 2x + 10 < 660. Solve each separately to get the interval in which the value of x lies.
[tex]\begin{gathered} 460<2x+10 \\ 460-10<2x \\ 450<2x \\ 225225 \end{gathered}[/tex][tex]\begin{gathered} 2x+10<660 \\ 2x<650 \\ x<325 \end{gathered}[/tex]So, from the above calculation, we have obtained that x is greater than 225 and less than 325. So, the answer is (225, 325).
The answer represents that the amount of carbs is between 225 grams and 325 grams.
If 200 is added to a positive integer I, the result is a square number. If 276 is added to to the same integer I, another square number is obtained. Find I.
Solution:
[tex]\begin{gathered} Let\text{ } \\ 200\text{ + I= x}^2----------\left(1\right) \\ 276+I\text{ =y}^2----------\left(11\right) \\ Subtract\text{ equation \lparen1\rparen from equation \lparen11\rparen} \\ 276+1-\left(200_+I\right?=y^2-x^2 \\ 76=\left(y-x\right?\left(y+x\right? \end{gathered}[/tex]Now y+x and y-x differ in 2x.
One of them is even, because their product is even, so the other must be even too.
76=2*2*19 and 19 is prime.
We can assume x,y>=0,
Thus, y+x=2.19, and y-x=2
from here y=20, x=18
Therefore,
[tex]\begin{gathered} 200+1=18^2 \\ 200+I=324 \\ I=324-200 \\ I=124 \end{gathered}[/tex]The answer is I = 124
y=6/5x+9 how would I graph it
To graph this linear function, we can find both intercepts of the function. To achieve this, we need to solve the equation when y = 0 (for this function) (this will be the x-intercept), and then we need to solve the resulting equation for this function when x = 0 (this will be the y-intercept). Then, we will have two points for which we can graph the function - we need to remember that a line is defined by two points.
Then, we can proceed as follows:
1. Finding the x-intercept[tex]y=\frac{6}{5}x+9,y=0\Rightarrow0=\frac{6}{5}x+9[/tex]Then, we have:
a. Add -9 to both sides of the equation:
[tex]\frac{6}{5}x=-9[/tex]b. Multiply both sides of the equation by 5/6:
[tex]\frac{5}{6}\frac{6}{5}x=-9\cdot\frac{5}{6}\Rightarrow x=-\frac{45}{6}=-\frac{15}{2}=-7.5[/tex]Therefore, the x-intercept is (-7.5, 0).
2. Finding the y-interceptWe have that x = 0 in this case. Then, we have:
[tex]y=\frac{6}{5}x+9\Rightarrow y=\frac{6}{5}(0)+9\Rightarrow y=9[/tex]Therefore, the y-intercept is (0, 9).
Now, we have the points (-7.5, 0) and (0, 9), and we can draw both points on the coordinate plane. The line will pass through these two points:
The data below show the number of hits on a website per week over a random sample of five weeks. Compute the followingstatistics.
We have a sample that is:
[tex]115,39,160,240,176[/tex]a) We can find the median by first sorting the sample:
[tex]39,115,160,176,240[/tex]The median is the value that has 50% of the values below its values.
In this case, this value is in the third place of the sorted sample and has a value of 160.
b) We have to find the mean.
We can calculate it as:
[tex]\begin{gathered} \bar{x}=\frac{1}{n}\sum_{n\mathop{=}1}^5x_i \\ \\ \bar{x}=\frac{1}{5}(115+39+160+240+176) \\ \\ \bar{x}=\frac{1}{5}(730) \\ \\ \bar{x}=146 \end{gathered}[/tex]c) We have to calculate the variance. To find its value we will use the mean value we have just calculated:
[tex]\begin{gathered} s^2=\frac{1}{n}\sum_{n\mathop{=}1}^5(x_i-\bar{x})^2 \\ \\ s^2=\frac{1}{5}[(115-146)^2+(39-146)^2+(160-146)^2+(240-146)^2+(176-146)^2] \\ \\ s^2=\frac{1}{5}[(-31)^2+(-107)^2+(14)^2+(94)^2+(30)^2] \\ \\ s^2=\frac{1}{5}(961+11449+196+8836+900) \\ \\ s^2=\frac{1}{5}(22342) \\ \\ s^2=4468.4 \end{gathered}[/tex]d) We have to calculate the standard deviation. As we have already calculated the variance, we can calculate it as:
[tex]\begin{gathered} s=\sqrt{s^2} \\ s=\sqrt{4468.4} \\ s\approx66.85 \end{gathered}[/tex]e) We now have to find the coefficient of variation:
[tex]CV=\frac{s}{\bar{x}}=\frac{66.85}{146}\approx0.457876\cdot100\%\approx46\%[/tex]Answer:
a) 160
b) 146
c) 4468.4
d) 66.85
e) 46%
Fiona is making a banner in the shape of a triangle for a school project. She graphs the banner on a coordinate plane with vertices at P(0, 4) , Q(2, 8) , and R(−3, 6) . She wants to reflect the banner over the line x=1. Identify the image of the banner reflected in the line x=1.
The coordinates of the banner after the reflection across x = 1 is P'(2, 4), Q'(0, 8), and R'(5, 6)
How to determine the coordinates of the banner after the reflection?From the question, the coordinates are given as
P(0, 4), Q(2, 8), and R(−3, 6)
The line of reflection is given as
x = 1
The rule of reflection across the line x = 1 is represented as
(x, y) = (-x + 2, y)
When the above rule is applied, we have
P'(2, 4), Q'(0, 8), and R'(5, 6)
This means that the coordinate of the image are P'(2, 4), Q'(0, 8), and R'(5, 6)
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If a number with two places to the right of the decimal place is added to a number with three places to the right of thedecimal place then the answer should be reported as having how many numbers to the right of the decimal place
Let the number with two places to the right of the decimal place be represented as 20.45 and the number with three places to the right of the decimal place be 20.456
Required:
When we add the two numbers, how many numbers to the right of the decimal place is it going to have?
We can know this by adding the two fictitious numbers:
[tex]20.45\text{ + 20.456 = 40.906}[/tex]Here we can see that
Find the mean of the set of data. Round to the nearest tenth if necessary 6.4,6,8, 8.1,5.4, 11.1,6.7 The mean is
Given a set of data:
6.4,6,8, 8.1,5.4, 11.1,6.7
The sum of the given data =
[tex]6.4+6.8+8.1+5.4+11.1+6.7=44.5[/tex]The number of the data = 6
so, the mean =
[tex]\frac{44.5}{6}=7.4166667[/tex]Rounding to the nearest tenth, so, the answer will be:
Mean = 7.4
2.05x0.004 I know the answer is 0.0082 but when I multiply it myself I get 0.08200?
2 . 0 5 0
0 . 0 0 4
---------------------------------
8 2 0 0
+ 0 0 0 0
0 0 0 0
0 0 0 0
------------------------------
0 . 0 0 8 2 0 0 =
-----------------------------
a motorboat travels 456 km in 8 hours going upstream and 783 km in 9 hours going downstream. what is the rate of the boat in still water and what is the rate of current?
Can a triangle be formed with side lengths 17, 9, and 8? Explain.
Yes, because 17 + 9 > 8
Yes, because 17 + 8 < 9
No, because 9 + 8 > 17
No, because 8 + 9 = 17
Answer:
(d) No, because 8 + 9 = 17
Step-by-step explanation:
You want to know if side lengths 8, 9, and 17 can form a triangle.
Triangle inequalityThe triangle inequality requires the sum of the two short sides exceed the length of the longest side. For sides 8, 9, 17, this would require ...
8 + 9 > 17 . . . . . . . not true; no triangle can be formed
The sum is 8+9 = 17, a value that is not greater than 17. The triangle inequality is not satisfied. So, no triangle can be formed.
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Suppose that the distribution for total amounts spent by students vacationing for a week in Florida is normally distributed with a mean of 650 and a standard deviation of 120. Suppose you take a simple random sample (SRS) of 35 students from this distribution.
What is the probability that an SRS of 35 students will spend an average o between 600 and 700 dollars? Round to five decimal places
The probability that an SRS of 35 students will spend an average o between 600 and 700 dollars is 98.61%
Given,
The mean of the normal distribution, μ = 650
Standard deviation of the distribution, σ = 120
n = 35
By using central limit theorem, standard deviation for SRS of n, δ = σ/√n = 120/√35
The z score = (x - μ) / σ
By using central limit theorem,
z score = (x - μ) / δ
Here,
We have to find the probability that an SRS of 35 students will spend an average o between 600 and 700 dollars:
(p value of z score of x = 700) - (p value of z score of x = 600)
z score of x = 700
z = (x - μ) / δ = (700 - 650) /( 120/√35) = (50 × √35) / 120 = 2.46
p value of z score 2.46 is 0.99305
z score of x = 600
z = (x - μ) / δ = (600 - 650) /( 120/√35) = (-50 × √35) / 120 = -2.46
p value of z score -2.46 is 0.0069469
Now,
0.99305 - 0.0069469 = 0.9861031 = 98.61%
That is, the probability that an SRS of 35 students will spend an average o between 600 and 700 dollars is 98.61%
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