The figure formed will be hexagonal
According to the Florida Agency for Workforce, the monthly average number of unemployment claims in a certain county is given by () = 22.16^2 − 238.5 + 2005, where t is the number of years after 1990. a) During what years did the number of claims decrease? b) Find the relative extrema and interpret it.
SOLUTION
(a) Now from the question, we want to find during what years the number of claims decrease. Let us make the graph of the function to help us answer this
[tex]N(t)=22.16^2-238.5t+2005[/tex]We have
From the graph above, we can see that the function decreased at between x = 0 to x = 5.381
Hence the number of claims decreased between 1990 to 1995, that is 1990, 1991, 1992, 1993, 1994 and 1995
Note that 1990 was taken as zero
(b) The relative extrema from the graph is at 5.381, which represents 1995.
Hence the interpretation is that it is at 1995 that the minimum number of claims is approximately 1363.
Note that 1363 is approximately the y-value 1363.278
9. SAILING The sail on Milton's schooner is the shape of a 30°-60°-90°triangle. The length of the hypotenuse is 45 feet. Find the lengths of thelegs. Round to the nearest tenth.
The triangle is shown below:
Notice how this is an isosceles triangle.
We can find the lengths of the hypotenuse by using the trigonometric functions:
[tex]\sin \theta=\frac{\text{opp}}{\text{hyp}}[/tex]Then we have:
[tex]\begin{gathered} \sin 45=\frac{21}{hyp} \\ \text{hyp}=\frac{21}{\sin 45} \\ \text{hyp}=29.7 \end{gathered}[/tex]Therefore the hypotenuse is 29.7 ft.
Fill in the table using this function rule. y = 2x+4
The complete table using the given linear equation is x y
-4 -4
-2 0
0 4
2 8
What are linear equations?A linear equation is one that has the form Ax+By=C. This definition comes from mathematics. It consists of two variables combined with a constant value that exists in each of them.
The values of the variables will be obtained when the system of linear equations is solved; this is referred to as the solution of a linear equation.
Given the linear equation y = 2x + 4
If x = -4
y =2(-4) + 4
y = -4
If x = -2
y =2(-2) + 4
y = 0
If x = 0
y =2(0) + 4
y = 4
If x = 2
y =2(2) + 4
y = 8
Hence the complete table using the function is
x y
-4 -4
-2 0
0 4
2 8
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Complete question
Fill in the table using this function rule. y=2x -4
x y
-4 ?
-2 ?
0 ?
2 ?
Match the number with the correct description.
PLEASE HELP
Answer:
Answers on attached image
Step-by-step explanation:
Hey I just need someone to check my work and see what else i might need to add on. This is algebra 2
To answer this question we will use the following property of sets:
[tex]|A\cup B|=|A|+|B|-|A\cap B|[/tex](a) Since Ash has 153 cards in his collection (without any duplicates), Brock has 207 cards in his collection (also without any duplicates) and they have 91 cards in common, then:
[tex]\begin{gathered} |AshCards\cup BrockCards|=|AshCards|+|BrockCards|-|AshCards\cap BrockCards| \\ =153+207-91. \end{gathered}[/tex]Simplifying the above result we get:
[tex]|AshCards\cup BrockCards|=269.[/tex](b) Expressing the above result using set notations:
[tex]|A\cup B|=269.[/tex]Answer:
(a) There are 269 unique cards in between them.
(b)
[tex]|A\cup B|=269.[/tex]
Miss Taylor drove 30 miles in March she drove 9 times as many miles in May as she did in March she drove 2 times as many miles in April as she did in May how many miles did Miss Taylor Drive in April.
then we use the statement to solve
Miss Taylor drove 30 miles in March
[tex]March=30[/tex]she drove 9 times as many miles in May as she did in March
[tex]\begin{gathered} May=9\text{March} \\ May=9\times30=270 \end{gathered}[/tex]she drove 2 times as many miles in April as she did in May
[tex]\begin{gathered} April=2May \\ April=2\times270=540 \end{gathered}[/tex]Taylor Drove 540 Miles in April
Which answer shows how to solve the given equation using the quadratic formula? 22 - 3. - 4= 0 3+, 22-4(2)(-4) 2(2) -(-3)=1/(-3)2-4(2)(-4) 2(2) 4+/(-3) -4(2)(-4) 2 3+1/32-4(-3)(-4) 2(2)
hello
the question here is a given quadratic equation and we're required to use quadratic formula to solve it.
[tex]2x^2-3x-4=0[/tex]now, to solve this, let's bring out quadratic formula first
[tex]x=-b\pm\frac{\sqrt[]{b^2-4ac}}{2a}[/tex]now from our equation given, we can easily identify a, b and c.
[tex]\begin{gathered} 2x^2-3x-4=0 \\ a=2 \\ b=-3 \\ c=-4 \end{gathered}[/tex]next we plug in the variables into the equation and solve
[tex]undefined[/tex]* Use the digits 0, 2, and 5 to write all of the three-digit numbers that fit each
description. You can repeat digits in a number.
multiples of 2
The 3-digit multiples of 2 using 0, 2, and 5 are:
250502520What are multiples?A multiple in science is created by multiplying any number by an integer. In other words, if b = na for some integer n, known as the multiplier, it can be said that b is a multiple of a given two numbers, a and b. This is equivalent to stating that b/a is an integer if an is not zero. In mathematics, multiples are the results of multiplying an integer by a given number. Multiples of 5 include, for instance, 10, 15, 20, 25, 30, etc. Numerous 7s include 14, 21, 28, 35, 42, 49, etc.So, 3-digit multiples of 2 using the digits 0, 2, and 5 are:
3 digits multiples of 2:
250502520Therefore, the 3-digit multiples of 2 using 0, 2, and 5 are:
250502520Know more about multiples here:
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Write the inverse of the given conditional statement.Conditional Statement: "If a shape has four sides, then theshape is a rectangle."Inverse Statement: Ifthen
Given: A conditional statement, "If a shape has four sides, then the
shape is a rectangle."
Required: To write the inverse of the statement.
Explanation: The given statement has two following statements:
[tex]\begin{gathered} p\rightarrow\text{ A shape has four sides} \\ q\rightarrow\text{ The shape is rectangle} \end{gathered}[/tex]The inverse of the statement will be
[tex]\text{ If }∼q\text{ then \thicksim}p[/tex]Hence the inverse statement is
Final Answer: The inverse statement is- "If the shape is not a rectangle, then the shape doesn't has four sides."
Graph the line by plotting any two ordered pairs with integer value coordinates that satisfy the equation.- 21 = 0AnswerKeypadKeyboard ShortcutsPoints can be moved by dragging or using the arrow keys. Any lines or curves will be drawn once allrequired points are plotted and will update whenever a point is moved.10SI10310101
We are given the following equation of a line.
[tex]-2x=0[/tex]Let us first solve the above equation for x.
Divide both sides of the equation by -2
[tex]\begin{gathered} -2x=0 \\ \frac{-2x}{-2}=\frac{0}{-2} \\ x=0 \end{gathered}[/tex]So, the solution is x = 0
This means that the two ordered pairs must contain the x-coordinate 0 and the y-coordinate can be any value you like.
For example:
(0, -5) and (0, 5)
Here the x-coordinate is 0 and the y-coordinate is -5 and 5.
Let us plot these ordered pairs and the line on the given graph.
What is the midpoint of the line segment graphed below?10(5,9)(2-1)-1010- 10O A. (7,8)OB.OC (34)OD (710
ANSWER:
[tex](\frac{7}{2},4)[/tex]STEP-BY-STEP EXPLANATION:
To calculate the value of the midpoint, we use the formula of the midpoint which is the following:
[tex](x_m,y_m)=(\frac{x_1+x_2}{2},\frac{y_1+y_2}{2})[/tex]Replacing and solving the midpoint:
[tex]\begin{gathered} (x_m,y_m)=(\frac{5+2_{}}{2},\frac{9-1_{}}{2}) \\ (x_m,y_m)=(\frac{7_{}}{2},\frac{8_{}}{2})=(\frac{7}{2},4) \end{gathered}[/tex]Which quadrilateral has diagonals that are both congruent and perpendicular?ParallelogramRectangleRhombusSquare
The quadrilateral has diagonals that are both congruent and perpendicular is square.
The correct option is (d)
Answer:
Its A
Step-by-step explanation:
True or False? Every rectangle is a parallelogram. Every rhombus is a parallelogram. Every quadrilateral is a square. Every rectangle with four congruent sides is a square. X S True O False True O False O True False O True O False ?
Given: Different statement relating different quadrilateral
To Determine: If true or false statement
Solution
The image below summarizes the properties of a quadrilateral
From the above, we can conclude that
A family of four went to an amusement park for their vacation. They started the vacation with $426.They spent a total of $198 the first three days.If they divided the remainder of the money evenly between the family members for souvenirs, how much did each person have to spend?
They started the vacation with $426
After spending $198 the first three days, the remainder is $426 - $198 = $228
Given that there are 4 family members, we have to divide this remainder by 4, that is, $228/4 = $57
Each person has $57 to spend
A fisherman drops a fishing line into the sea. The end of the fishing pole is at an elevation of 5 feet. The hook that is in the water is at an elevation of -2 feet.cessmentThe number line shows their heights. Sea level is represented by 0.1. Write an absolute value expression telling how many feet the end of the fishingpole is above sea level. Evaluate the expression.2. Write an absolute value expression telling how many feet the hook is below sealevel. Evaluate the expression. 3. If the fishing line goes straight down into the water, what is the distance betweenthe end of the pole and the hook? Explain how you found this distance.
In this case, we'll have to carry out several steps to find the solution.
Step 01:
Data:
sea level = 0 ft
end of fishing pole = 5 ft
hook = -2 ft
Step 02:
absolute value:
distance between sea level and the end of fishing pole:
| 5 - 0| = | 5 | = 5 ft
distance between hook and sea level:
|0 - (-2)| = | 0 + 2| = |2| = 2 ft
distance between hook and the end of the fishing pole:
| 5 - (-2)| = | 5 + 2| = |7| = 7 ft
To find out the distance we must consider the entire interval.
That is the full solution.
Answer:
Given a fishing line acting as number line, find the asked distances
Explanation:
given a fishing line having its one end of the fishing pole above the water. Let this distance be denoted by 'a'.
given that the hook of this fishing line is in the water hence, below the sea level. Let this depth be denoted by 'b'.
let the height of pole from sea-level be denoted by , height of the hook from sea level be denoted by and the length between pole end and hook be
since, this fishing line is acting as a number line with sea level as . The depth of fishing hook is negative and the elevation of the pole end is positive .
hence we get expressions,
for given values the evaluation of the expressions is,
Step-by-step explanation:
Let the graph of f(x) be given below. Find the formula of f(x), a polynomial function, of least degree.
To detrmine the formula of the polynomial, we check for the roots on the graph:
when y = 0, x = -2
when y = 0, x = 4
We have two roots.
x = -2
x + 2 = 0
x = 4
x - 4 = 0
3rd factor is x = 0
Hence, we have two factors: x(x + 2) and (x - 4)
The polynomial function using the factors:
[tex]f(x)\text{ = ax(x + 2)(x - 4)}[/tex]Next, we find the value of a:
To get a , we pick a point on the graph. let the point be (0, -4)
substitute the point in the function above:
[tex]\begin{gathered} f(x)\text{ = y = -4, x = 0} \\ -4\text{ = a(0 + 2) (0 - 4)} \\ -4\text{ = a(2)(-4)} \\ -4\text{ = -8a} \\ a\text{ = -4/-8} \\ a\text{ = 1/2} \end{gathered}[/tex]The formula of the polynomial becomes:
[tex]f(x)\text{ = }\frac{1}{2}x(x\text{ }+2)(x-4)[/tex]1 1 10 1 b. What fraction of the whole square is shaded? Explain how you know.
1/100
Explanation:To get the fraction of the square shaded we would use the rows and columns
For the row:
The total on the 1st row = 1
The first row is divided into 10. This means each box in the first row: 1/10
One of the box is shaded. This implies the fraction shaded in the first row is 1/10
For the column:
The total on the 1st column = 1
The column is also divided into 10 box which means each box represent 1/10
Since one of the box in the column is shaded, it represent 1/10
Fraction of the whole square shaded = fraction shaded in the row × fraction shaded in the column
Fraction of the whole square shaded = 1/10 × 1/10
Fraction of the whole square shaded = 1/100
identifies the kind of symmetry the figure has below if any.
We are asked to identify the types of symmetries found in the given geometrical figure. Let's remember that asymmetry is a transformation that maps the figure onto itself. In this case the object has symmetry under reflections, also has symmetry under rotations around its center
Use the law of detachment to determine what you can conclude from the given information
In mathematical logic, the Law of Detachment says that if the following two statements are true:
( 1 ) If p, then q.
( 2 ) p
Then we can derive a third true statement:
( 3 ) q.
In our question, we have
( 1 ) If 0º< A <90º, then A is an acute angle.
( 2 ) The measure of A is 58º.
Then, from the first statement, we can affirm
( 3 ) A is an acute angle.
Shawn needs to reach a windowsill that is 10 feet above the ground. He placed his ladder 4 feet from the base of the wall. It reached the base of the window.
a. Draw a diagram of the right triangle formed by Shawn's ladder, the ground and the wall.
b. Find the length of Shawn's ladder to the nearest tenth of a foot.
If shown needs to reach a windowsill that is 10 feet above the ground and he placed his ladder 4 feet from the base of the wall.
Part a
The diagram of the right triangle formed by Shawn's ladder, the ground and wall has been plotted
Part b
The length of the Shawn's ladder is 10 foot
The distance between ladder base to the base of the wall = 4 feet
The distance between the wall base to the base of the window = 10 feet
Draw the right triangle using the given details
Part b
Using the Pythagorean theorem
[tex]AC^2= AB^2+BC^2[/tex]
Where AC is the length of the ladder
Substitute the values in the equation
AC = [tex]\sqrt{10^2+4^2}[/tex]
= [tex]\sqrt{100+16}[/tex]
= [tex]\sqrt{116}[/tex]
= 10.77
≈ 10 Foot
Hence, if shown needs to reach a windowsill that is 10 feet above the ground and he placed his ladder 4 feet from the base of the wall.
Part a
The diagram of the right triangle formed by Shawn's ladder, the ground and wall has been plotted
Part b
The length of the Shawn's ladder is 10 foot
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how to write the rule for the rotation on #11?
#11
If the point (x, y) is rotated 180 degrees around the origin clockwise or anti-clockwise, then its image will be (-x, -y)
We just change the sign of the coordinates
From the attached picture we can see
The parallelogram MNOP where
M = (1, -2)
N = (3, -2)
O = (4, -4)
P = (2, -4)
The parallelogram M'N'O'P' where
M' = (-1, 2)
N' = (-3, 2)
O' = (-4, 4)
P' = (-2, 4)
Since all the signs of the coordinates are changed, then
M'N'O'P' is the image of MNOP by rotation 180 degrees around the orign
The rule of transformation is
[tex]R\rightarrow(O,180^{\circ})[/tex]this is a Statistics question. Please help
Using the normal distribution, it is found that the measures are given as follows:
a) Proportion with less than 125 mg/dl: 0.16.
b) Percentage between 200 and 225 mg/dl: 2.35%.
Normal Probability DistributionThe z-score of a measure X of a variable that has mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex] is given by the rule presented as follows:
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
The z-score measures how many standard deviations the measure X is above or below the mean of the distribution, depending if the z-score is positive or negative.From the z-score table, the p-value associated with the z-score is found, and it represents the percentile of the measure X in the distribution.The mean and the standard deviation of the cholesterol levels are given as follows:
[tex]\mu = 150, \sigma = 25[/tex]
The proportion below 125 mg/dl is the p-value of Z when X = 125, hence:
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
Z = (125 - 150)/25
Z = -1
Z = -1 has a p-value of 0.16, rounded with the Empirical Rule, which is the proportion.
The proportion with cholesterol levels between 200 and 225 mg/dl is the p-value of Z when X = 225 subtracted by the p-value of Z when X = 200, hence:
X = 225
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
Z = (225 - 150)/25
Z = 3
Z = 3 has a p-value of 0.9985.
X = 200
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
Z = (200 - 150)/25
Z = 2
Z = 2 has a p-value of 0.975.
0.9985 - 0.975 = 0.0235 = 2.35%, which is the percentage.
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The director of a film festival received 9 submissions, 7 of which were sci-fi films. If the director randomly chose to play 6 of the submissions on the first day of the festival, what is the probability that all of them are sci-fi films? Write your answer as a decimal rounded to four decimal places .
Given data:
9 submissions out of which 7 were sci-fi
If the director randomly chose to play 6 of the submissions on the first day of the festival
Then, the probability that all of them are sci-fi films will be obtained as follows
At the first selection, it will be: 7/9
At the second selection, it will be: 6/8
At the third selection, it will be: 5/7
At the fourth selection, it will be: 4/6
At the fifth selection, it will be: 3/5
At the sixth selection, it will be: 2/4
Thus, the probability will be
[tex]\frac{7}{9}\times\frac{6}{8}\times\frac{5}{7}\times\frac{4}{6}\times\frac{3}{5}\times\frac{2}{4}=\frac{5040}{60480}[/tex]=>
[tex]\frac{5040}{60480}=\frac{1}{12}[/tex]=>
[tex]\frac{1}{12}=0.0833[/tex]Answer = 0.0833
what is the slope of a line parallel to the line whose equation is 18 x - 3 y equals -45
The equation of the line in Slope-Intercept form is:
[tex]y=mx+b[/tex]Where "m" is the slope and "b" is the y-intercept.
Let's solve for "y" from the equation of the line given in the exercise, in order to express it in Slope-Intercept form:
[tex]\begin{gathered} 18x-3y=-45 \\ -3y=-18x-45 \\ y=\frac{-18x-45}{-3} \\ y=6x+15 \end{gathered}[/tex]You can identify that:
[tex]\begin{gathered} m=6 \\ b=15 \end{gathered}[/tex]By definition, the slopes of parallel lines are equal. Therefore, the slope of the line parallel to line given in the exercise, is:
[tex]m=6[/tex]Factor by grouping:y^3-5y^2+3y-15
we have the expression
y^3-5y^2+3y-15
Grouping terms
(y^3-5y^2)+(3y-15)
factor y^2
y^2(y-5)+(3y-15)
factor 3
y^2(y-5)+3(y-5)
factor (y-5)
(y-5)[y^2+3]jen has to put 180 cards into boxes of 6 cards each. she put 150 cards into boxes. write an equation that could use to figure out how many boxes jen need. let b stand for the unknown number of boxes.
Let b be the number of boxes.
Since each box has 6 cards, we will have the term 6b to get the remaining boxes.
Since Jen already put 150 cards into boxes, we have the following:
[tex]150+6b=180[/tex]for 150 cards, Jen used 25 boxes. We can check that the remaining 5 boxes can be found using the previous equation:
[tex]\begin{gathered} 150+6b=180 \\ \Rightarrow6b=180-150=30 \\ \Rightarrow b=\frac{30}{6}=5 \\ b=5 \end{gathered}[/tex]therefore, the equation is 150+6b=180
given which of the following describes the boundary line and shading for the second inequality in the system
Answer:
Solid Line, Shade Above
Explanation:
Given:
[tex]\left\{\begin{array}{l} y<-2 x+3 \\ y \geq x-4 \end{array}\right.[/tex]The second inequality in the system is:
[tex]y\geq x-4[/tex]The intercepts of the boundary line (y=x-4) are (0, -4) and (4,0).
Since the inequality has an equal to sign attached, we use a solid line.
At (0,0)
[tex]\begin{gathered} y\geq x-4 \\ 0\geq-4 \end{gathered}[/tex]Since the inequality 0≥-4 is true, shade the side that contains (0, 0) as shown in the graph below:
So, we use a solid line and shade above the boundary line.
solving systems by graphing and tables : equations and inequalities
Given,
The system of inequalitites are,
[tex]\begin{gathered} 2x+3y>0 \\ x-y\leq5 \end{gathered}[/tex]The graph of the inequalities is,
The are three possible solution for the inequality.
For (0, 0),
[tex]\begin{gathered} 2x+3y>0 \\ 2(0)+3(0)>0 \\ 0>0 \\ \text{Similarly,} \\ x-y\leq5 \\ 0-0\leq5 \\ 0\leq5 \end{gathered}[/tex]For (3, -2),
[tex]\begin{gathered} 2x+3y>0 \\ 2(3)+3(-2)>0 \\ 0>0 \\ \text{Similarly,} \\ x-y\leq5 \\ 3-(-2)\leq5 \\ 5=5 \end{gathered}[/tex]For (5, 0),
[tex]\begin{gathered} 2x+3y>0 \\ 2(5)+3(0)>0 \\ 5>0 \\ \text{Similarly,} \\ x-y\leq5 \\ 5-(0)\leq5 \\ 5=5 \end{gathered}[/tex]Hence, the solution of the inequalities is (5, 0).
MP and MN are tangents to the circle.What is the value of x?133M90940NxºР17286
To get x, we will use the equation below:
[tex]\frac{1}{2}\lbrack(360-x)-x\rbrack=94[/tex]open the inner paremthesis
[tex]\frac{1}{2}\lbrack360-2x\rbrack=94[/tex]
open the parenthesis
180 - x = 94
collect like term
180 - 94 = x
86 = x
I have the area of the circle but having trouble find the area of the triangle
To calculate the area of the triangle we need the length of the base and the height, being the height perpendicular to the base.
The base of the triangle has a length that is equal to the diameter of the circle. It can also be expressed as 2 times the radius r. So the base is:
[tex]b=2\cdot r=2\cdot4=8\operatorname{cm}[/tex]The height is the segment perpendicular to the base that goes up to the vertex at the top. as it goes from the center of the circle to the border of the circle, it has a length that is equal to the radius r:
[tex]h=r=4\operatorname{cm}[/tex]Then, we can calculate the area of the triangle as:
[tex]A=\frac{b\cdot h}{2}=\frac{8\cdot4}{2}=\frac{32}{2}=16\operatorname{cm}^2[/tex]We can calculate the area of the circle as:
[tex]A_c=\pi r^2\approx3.14\cdot4^2=3.14\cdot16=50.24[/tex]The probability that a randomly selected point within the circle falls in the white area is equal to the ratio of white area to the area of the circle.
The white area is equal to the area of the circle minus the area of the triangle.
Then, we can calculate the probability as:
[tex]p=\frac{A_w}{A_c}=\frac{A_c-A_t}{A_c}=\frac{50.24-16}{50.24}=\frac{34.24}{50.24}\approx0.68=68\%[/tex]Answer: The probability is p=0.68.
