A tone is a sound with definite and steady vibrations.
What is tone?
The author's attitude toward the topic they are writing about is the definition of tone in literature. The Latin word tonus, which means a sound or accent, and the French word tonne, which denotes a musical sound, are the origins of the word tone. Whether the author intends it or not, the reader always picks up on the tone of a work of literature. The words an author chooses as well as how they are used make up their diction. The way an author speaks affects the reader's mood. The syntax, point of view (a particular attitude as well as way of describing a subject), diction, and degree of formality used in writing all convey the tone of the piece. Writing can take on a formal or informal tone.
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what is the name of the theory that describes the history and fate of the universe?? what is the name of the theory that describes the history and fate of the universe?? the nebular theory. the big bang theory. the theory of everything. the general theory of relativity.
The name of the theory that describes the history and fate of the universe is the big bang theory.
The most influential theory of the origin of the universe at present is the so-called Big Bang theory. According to this theory, the universe was formed when a very hot dense fireball exploded, blowing matter outward. The consensus among scientists, astronomers, and cosmologists is the universe as we know it.
It was created in a massive explosion that determined not only most of the matter but also the physical laws that govern our ever-expanding universe about it. This is known as the Big Bang Theory. The most widely held theory of the origin of the universe is called the Big Bang theory. This argues that the universe began as a near-single point with near-infinite temperature and density. Since then the universe has continued to expand.
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A cosmic-ray electron moves at 7. 5 × 10^6 m/s perpendicular to earth’s magnetic field at an altitude where the field strength is 1. 0 × 10^-5t. What is the radius of the circular path the electron follows?.
4.266 m is the radius of the circular path the electron follows
Electron's speed = 7.50 × 10⁶ m/s
Magnetic field, B = 1 × 10⁻⁵ T
Electron's mass. m = 9.11 × 10⁻³¹
Charge of electron, q = 1.6 × 10⁻¹⁹
We know the relation of radius of curvature, = 4.266 m
What is a circle's radius of curvature?Every point on a circle has a curvature that is equal to the reciprocal of the radius; for other curves (and straight lines, which can be thought of as circles of infinite radius), the curvature is equal to the reciprocal of the radius of the circle that at that point most closely approximates the curve.
The curvature's reciprocal, R, is the radius of curvature in differential geometry. It is equal to the radius of the circular arc that, at that moment, most closely resembles the curve for a curve. The radius of curvature for surfaces is the diameter of a circle that, individually or in combination, best fits a normal section.
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You are driving at the speed of 29.5 m/s
(66.0037 mph) when suddenly the car in
front of you (previously traveling at the same
speed) brakes and begins to slow down with
the largest deceleration possible without skidding. Considering an average human reaction,
you press your brakes 0.558 s later. You also
brake and decelerate as rapidly as possible
without skidding. Assume that the coefficient
of static friction is 0.708 between both cars’
wheels and the road.
The acceleration of gravity is 9.8 m/s
2
.
Calculate the acceleration of the car in front
of you when it brakes.
Answer in units of m/s
2
.
The acceleration of the car in front before stopping is 6.94 m/s².
What is the acceleration of the car?The acceleration of the car is the rate of change of velocity of the car with time.
The acceleration of the car in front is determined by applying the Newton's second law of motion assuming the car decelerated at a constant rate before stopping.
Ff = F
μmg = ma
μg = a
where;
Ff is the frictional force on the car when it stopsF is the force of the carm is the mass of the cara is the acceleration of the carg is acceleration due to gravityμ is coefficient of static frictionSubstitute the given parameters and solve for the acceleration of the car.
a = (0.708) x (9.8 m/s²)
a = 6.94 m/s²
Thus, the acceleration of the car in front before stopping is 6.94 m/s².
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supppose object a has double the specific heat and triple the mass of object b. if the same amount of heat is applied to both objects, how will the temperature changes of a be related to the temperature change of b?
The given problem is related to the calorimetry. The definition of calorimetry states that, "Calorimetry is the science of determining the change in energy of a system by measuring the heat exchange of the system with the surroundings". According to this, the temperature change of A will be one sixth of the temperature change of B. Calorimetry is the measurement and calculation of the amounts of heat exchanged by a body or a system.
Sensible heat is defined as the amount of heat that a body absorbs or releases without any changes in its physical state (phase change).
So, the equation that allows to calculate heat exchanges is:
Q = c× m× ΔT
where Q is the heat exchanged by a body of mass m, made up of a specific heat substance c and where ΔT is the temperature variation.
Temperature change of A related to the temperature change of B
In this case, for object A:
QA = cA× mA× (ΔT)A
and for object B:
QB = cB× mB× (ΔT)B
You know:
Object A has double the specific heat of object B. ⇒ cA= 2× cB
Object A has triple the mass of object B. ⇒ mA= 3× mB
If the same amount of heat is applied to both objects ⇒ QA= QB
Then:
cA× mA× (ΔT)A= QB = cB× mB× (ΔT)B
2× cB × 3× mB× (ΔT)A= cB× mB× (ΔT)B
Solving:
6× cB × mB× (ΔT)A= cB× mB× (ΔT)B
(ΔT)A= (cB× mB× (ΔT)B) ÷ (6× cB × mB)
(ΔT)A= (ΔT)B
Finally, the temperature change of A will be one sixth of the temperature change of B.
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in the video, forces acting on the car that are parallel to the direction of motion are analyzed. how are these forces related?in the video, forces acting on the car that are parallel to the direction of motion are analyzed. how are these forces related?
The forces have a same magnitude, act in opposing directions, and result in a net force of zero. The forces produce a net force in the direction of motion that is in the same direction, but they are not equal in size.
All forces operating on an automobile travelling uniformly at a steady speed are balanced. In this instance, the two opposing forces air resistance and friction perfectly balance the force that the wheels are exerting on the ground. However, the instant your foot leaves the gas pedal, there is no longer an applied force, and the forces are out of balance: Now when the car is out of balance, the forces pushing backward on it cause it to slow down; this is known as negative acceleration.
Because there wasn't enough upward force (i.e., regular force from the chair) to balance the extra mass, you would speed downward as a result of the unbalanced force, possibly breaking your tailbone as you plunged through the chair to the floor.
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A ball is shot 58m/s at 40 degrees to the ground. What is the magnitude of the vertical component of the velocity of the plane?
The magnitude of vertical component of the velocity of the plane when a ball is shot 58 m/s at 40 degree to the ground is 37.28 m/s.
What is velocity?
Velocity can be defined as the rate of change of displacement, The S.I unit of velocity is m/s.
To calculate the magnitude of the vertical component of the velocity, we use the formula below.
Formula:
Vy = Vsin∅.............. Equation 1Where:
Vy = Vertical component of the velocityV = Velocity of the ball∅ = Angle the ball makes with the groundFrom the question,
Given:
V = 58 m/s∅ = 40°Substitute these values into equation 1
Vy = 58(sin40°)Vy = 58×0.6428Vy = 37.28 m/sHence, The magnitude of the vertical component of the velocity is 37.28 m/s.
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a 7.50-nc point charge is located 1.80 m from a 4.20-nc point charge. (a) find the magnitude of the electric force that one particle exerts on the other. (b) is the force attractive or repulsive?
The electric force is 8.370 x 10^9N.
We need to know about the electric force to solve this problem. The electric force produced by charges interacting each other, whose strength is given by the equation
F = k.Q1 . Q2/r²
where F is the electric force, Q1 and Q2 is the charge and r is the radius.
From the question above, we know that
k = 9 x 10⁹ Nm²/C²
Q1 =e = 7.50 x 10^-9 C
Q2 = e = 4.02 x 10^-9 C
r = 1.80 m
The electric force will attract each other when the charges are different and will repel each other when the charges are same.
F = k.Q1 . Q2/r²
F = 9 x 10⁹ . 7.50 x 10^-9 . 4.02 x 10^-9/(1.80)²
F = 8.37 x 10^9 N
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PLEASE HELP 50 POINTS AND MARKED AS BRAINLIEST
A spring scale is a device that uses a spring with a known spring constant to measure the weight of objects. You have a spring scale with a spring constant of 13 Nm. How much will the spring stretch when a 12-N weight is hung from one end?
Answer:
It would stretch about 6 inches, but it depends on the metal.
Explanation:
pls mark brainliest with the crown
If the same elevator accelerates downwards
with an acceleration of 1.2 m/s
2
, what is the
upward force exerted by the elevator floor on
the passenger?
The upward force exerted by the elevator floor on the passenger is 7.6 times mass of the passenger.
What is force?A force in physics is an effect that has the power to alter an object's motion. An object with mass can change its velocity, or accelerate, as a result of a force. An obvious way to describe force is as a push or a pull. A force is a vector quantity since it has both magnitude and direction.
Given in question elevator accelerates downwards with an acceleration of 1.2 m/s². There is acceleration due to gravity working downward which is 9.8 m/s².
So, net acceleration due to gravity is given as 9.8 - 1.2 = 7.6 m/s²
The upward force exerted by the elevator floor on the passenger is mass times acceleration, 7.6 times mass of passenger.
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Physics Trajectory question.
I need help finding the answers on Vy.
The vertical component of the velocity after the given interval of time will be:
B: -9.8 m/s
D: -19.6 m/s
F: -29.4 m/s
H: -39.2 m/s
What is a projectile?A projectile can be described as any object upon which the only force is gravity. The projectile travels with a parabolic trajectory because of the influence of gravity. No horizontal forces are acting upon projectiles so there is no horizontal acceleration.
The horizontal velocity of a projectile is constant and the vertical acceleration is caused by gravity. The vertical component of the velocity of a projectile changes by 9.8 m/s each second while the horizontal motion of a projectile is independent of its vertical motion.
Given, the initial horizontal velocity, vₓ = 18 m/s
The initial vertical velocity, Vy = 0 m/s
The time interval = 1 sec
The vertical component of the velocity is calculated as;
[tex]V_y = V_{0y} -gt[/tex]
[tex]V_y = 0- (9.8) (1)\\V_y = -9.8 m/s[/tex]
The vertical component when t = 2 sec and horizontal velocity, Vx = 18 m/s
[tex]V_y = 0- (9.8) (2)\\V_y = -19.6 m/s[/tex]
The vertical component of velocity when t = 3sec:
[tex]V_y = 0- (9.8) (3)\\V_y = -29.4 m/s[/tex]
The vertical component of velocity when t = 4sec:
[tex]V_y = 0- (9.8) (4)\\V_y = -39.2 m/s[/tex]
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Free-body diagrams for four situations are shown below. For each situation, determine the net force acting upon the object. Your answer must include both the magnitude and the direction of the net force vector. You should have four (4) total responses to this question (labeled A, B, C, and D).
The magnitude and direction of the net force are:
A: the net force is 3N in the downward direction,
B: the net force is zero,
C: The net force is 5N in the downward direction,
D: The net force is 4N in the right direction.
What is the net force?The net force of an object can be described as the vector sum of all the forces acting on an object. The net force is a single force that shows the same effect as the original forces on the particle's motion.
The net force becomes the resultant force. The net force has the same effect on the rotational motion as all original forces together by the object.
The mathematical expression can be written for the net force as:
[tex]\vec F_{net} = \vec F_{x} + \vec F_{y}[/tex]
For figure (A), the net force is equal to :
F = (2N - 2N) + (2N - 5N) = - 3N
So the magnitude of the force is 3N in the downward direction.
For figure (B), the net force is equal to :
F = (2N - 2N) + (5N - 5N) = 0
So the magnitude of the net force is equal to zero.
For figure (C), the net force is equal to :
F = (5N - 5N) + (5 N) = 5 N
So the magnitude of the net force is 5N in the downward direction.
For figure (D), the net force is equal to :
F = (2N - 2N) + (7N - 3N) = 4N
So the magnitude of the net force is 4N towards the right direction.
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two boys hang by their hands from the same tree branch. the branch is straight, and grows out from the tree trunk at an angle of 30 degree above the horizontal. one boy, with a mass of 50.00 kg, is hanging 1.40 m along the branch from the tree trunk. the other boy, with a mass of 33.00 kg, is hanging 2.10 m from the tree trunk. what is the magnitude of the net torque exerted on the branch by the children? assume that the axis is located where the branch joins the tree trunk and is perpendicular to the plane formed by the branch and the trunk.
Magnitude offers products that automate and provide insights throughout the whole supply chain. Determine and emphasize any bottlenecks, potential delays, and urgent.
Calculation Magnitude?Magnitude offers products that automate and provide insights throughout the whole supply chain. Determine and emphasize any bottlenecks, potential delays, and urgent.
The size of the undertaking would have discouraged a regular man due to its importance.
Magnitude is a way to gauge a star's brightness.
inclination of tree from horizontal =30°
mass of first child m[tex]1[/tex]=50kg
distance of first child r[tex]1[/tex]=1.4
mass of first child m[tex]2[/tex]=33kg
distance of first child r[tex]2[/tex]=2.10
Torque exerted by first child
T[tex]1[/tex]=m[tex]1[/tex] cos 0*r1
T1=50*9.8 cos27*2*1.4
=489.7513N-M
Torque exerted by second child
T2=m2 cos0*r2
T2=33 *9.8cos27*2
=292.7374
Both torques are in same sense therefore
T[tex]net[/tex]=T1+T2
T[tex]net[/tex]=489.75+292.73
T[tex]net[/tex]=782.48N-m
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HELP ASAP!!
What has more momentum in a collision, a fly or a Corvette?
According to Newton’s third law, the force of a fly on the windshield of a Corvette is equal to the force of the Corvette’s windshield on the fly, only in the opposite direction. Why then does the fly get crushed and the Corvette doesn't even feel the collision? This is where momentum comes into play. Momentum of an object is its mass in kilograms times its velocity in m/s. The mass of the fly is 0.2 kilograms and it’s flying at a velocity of 11 meters per second. The Corvette has a mass of 1,518 kilograms and is driving with a velocity of 27 m/s in the opposite direction. During the collision, the Corvette’s mass times velocity will equal a greater momentum because it has significantly more mass and a much greater velocity than the fly.
ANSWER BELOW USING THE RACES STRATEGY
Answer:
convert not telling why but it was the answer I gave it says it was right
Momentum of an object is directly proportional to the mass of the object. The corvette has greater mass and thus more momentum it gains than the little fly.
What is momentum:Momentum of an object is the product of mass and velocity. Thus momentum is directly proportional to the mass and velocity of the object. This relation of momentum with mass and velocity is defined by Newton's law of motion.
According to Newton's third law of motion every reaction has an equal and opposite reaction. Thus if apply a force on object it may return a force but that will depend on the mass and direction.
When the fly hit the moving corvette, the greater impulse will be for the fly since it is very less in mass compared to that of the corvette. The momentum of corvette is higher because velocity and mass of the corvette is significantly higher than that of fly.
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a pellet gun fires ten 3.0 g pellets per second with a speed of 400 m/s. the pellets are stopped by a rigid wall. what is the magnitude of the average force on the wall from the stream of pellets?
a boy and a girl are at rest on separate skis 12 m apart on a horizontal icy surface. the boy and his skis have twice the inertia of the girl and her skis. determine the location of the center of mass in meters measured from the position of the girl.
With the position of the girl as a reference point, the center of mass is 8 m from the girl position.
If there are two objects as shown on the attached picture, the center of mass is:
xc = m₁ / (m₁ + m₂) . x₁ + m₂ / (m₁ + m₂) . x₂
From the problem, we know that the boy and his skis have twice the inertia of the girl and her skis. We can replace the mass in the equation with inertia, hence:
xc = I₁ / (I₁ + I₂) . x₁ + I₂ / (I₁ + I₂) . x₂
Let:
I₁ = the girl's inertia
I₂ = the boy's inertia
Hence,
I₂ = 2 I₁
Let make the position of the girl as a reference point, then,
x₁ = 0
x₂ = 12
Plug these parameters into the formula:
xc = I₁ / (I₁ + I₂) . 0 + 2 I₁ / (I₁ + 2 I₁) . 12
xc = 2/3 . 12 = 8 m
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It took 89.5 degrees to stop the wheel from 47.8 rpm. What is the angular acceleration?
Given:
The angular displacement, θ=89.5°
Initial angular velocity, ω₀=47.8 rpm
Final angular velocity, ω=0 rad/s
To find:
The angular acceleration of the wheel.
Explanation:
The angular velocity can be converted to rad/s as,
[tex]\begin{gathered} \omega_0=\frac{47.8\times2\pi}{60} \\ =5\text{ rad/s} \end{gathered}[/tex]The angle is converted into the radians as,
[tex]\begin{gathered} \theta=\frac{89.5\times\pi}{180} \\ =1.56\text{ rad} \end{gathered}[/tex]From the equation of motion,
[tex]\omega^2-\omega^2=2\alpha\theta[/tex]Where α is the angular acceleration of the wheel.
On substituting the known values,
[tex]\begin{gathered} 0^2-5^2=2\times\alpha\times1.56 \\ \implies\alpha=\frac{-5^2}{2\times1.56} \\ =-8.01\text{ rad/s}^2 \end{gathered}[/tex]Final answer:
Thus the angular acceleration of the wheel is -8.01 rad/s²
Help show how you got answers
The speed at which a wave of frequency of 14 Hz and a wavelength of 3 m will travel is 42 m / s
v = λ / T
f = 1 / T
v = f λ
v = Wave speed
λ = Wavelength
T = Time period
f = Frequency
f = 14 Hz
λ = 3 m
v = 14 * 3
v = 42 m / s
Frequency is the number of time an event occurs repeatedly in an unit amount of time. Its unit is hertz which in terms of SI unit is [tex]s^{-1}[/tex].
Therefore, the speed at which the wave will travel is 42 m / s
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A bus traveling at a speed of 50 km/h has a momentum of 180,345
kg.m/s. What is the mass of the bus?
The mass of the truck is 12,974.4kg .
Describe bulk in plain terms.As a measure of inertia, which is a fundamental characteristic of all matter, mass is used in physics. Effectively, it is the resistance a body of matter offers to a change in its speed or position as a result of the application of a force.
An object's mass is what?Measures a substance's resistance to acceleration in physics. A measure of an object's mass is roughly equivalent to counting the atoms that make up the object. The kilogram serves as the fundamental mass unit. Mass multiplied by the gravitational acceleration equals weight.
50km/h =50×5/18 m/s= 13.88 = 13.9
momentum (p)=180,345 kg.m/s
P=mv
180,345= m X 13.9
m = 180345/13.9
m = 12,974.46
m = 12,974.4
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solve for x: |2x + 6| − 4 = 20 Group of answer choicesx = 9 and x = 11x = −9 and x = 15x = 9 and x = −15No solution
Given,
[tex]|2x+6|-4=20[/tex]On simplifying,
[tex]\begin{gathered} |2x+6|=20+4 \\ \Rightarrow|2x+6|=24 \\ 2x+6=\pm24 \end{gathered}[/tex]Thus,
[tex]\begin{gathered} 2x=+24-6 \\ \Rightarrow x=\frac{18}{2} \\ =9 \end{gathered}[/tex]Or
[tex]\begin{gathered} 2x=-24-6 \\ x=\frac{-30}{2} \\ =-15 \end{gathered}[/tex]Thus, x=9 and x=-15
Therefore the correct answer is the third option
If air resistance can be neglected, what happens to the horizontal velocity
of a basketball as it is thrown to the basket from the free-throw line?
O decreases
O stays constant
O increases
increases while the ball is going up, and then decreases while the ball is coming
down
O decreases while the ball is going up, and then increases while the ball is coming
down
If air resistance can be neglected, what happens to the horizontal velocity of a basketball as it is thrown to the basket from the free-throw line increases while the ball is going up, and then decreases while the ball is coming down.
Does the horizontal velocity change if air resistance is neglected?- When anything is hurled horizontally, gravity accelerates the object downward. – The only direction in which gravitational acceleration occurs is vertical. If we exclude the effects of air resistance, the object's horizontal velocity remains constant.
We know that the horizontal component of the force acting on the projectile at any given time will be zero if the air resistance is ignored in the projectile motion, which results in Fx=0.
The only force operating on the body in a horizontal direction if we neglect air resistance is gravity, which is acting in a vertical direction. As a result, the horizontal motion moves at a constant speed.
Therefore, option C is correct.
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Select the correct answer from each drop-down menu. earth's rotation causes the cycle of . if earth began to spin a little bit faster .
Your community is considering building a dam on a nearby river to reduce flooding. Would you support this proposal? Explain
Yes I would support the proposal of building a dam on a nearby river to reduce flooding.
What is flooding?Flooding is defined as the over spreading of water beyond the banks of a water body or the covering of a large area of land with uncontrolled flow of water.
A dam is a structure that is usually constructed over a flowing water body such as a river, to withhold water which can be diverted for the generation of electricity.
The construction of dam over a water body that usually overflows and floods an area can help control water spread as it's diverts the excess water for other purposes.
Therefore, I would support the proposal that a dam on the nearby river should be constructed.
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When a red light with a wavelength of 670 nm shines on a piece of metal, an electron is ejected. What is the energy of the photon absorbed by the electron to overcome the attractive forces?.
The energy of the photon of light as we can see here is 2.9 * 10-19 J.
What is the energy of the light?We know that light has to do with any of the components of the electromagnetic spectrum. These are the kinds of radiation that are able to pass through vacuum because they do not need a medium for the propagation of the wave. We are now asked to obtain the energy of the photon based in the wavelength that we have been supplied in the question here.
We have that the wavelength of the photon from what we can see in the question have been given as 670 nm. Then;
E = hc/λ
E = energy of the light
h = Plank's constant
c = speed of light
λ = wavelength of the light
It then follows that;
E = 6.6 * 10^-34 * 3 * 10^8/670 * 10^-9
E = 2.9 * 10-19 J
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a satellite moves in a circular earth orbit that has a radius of 8.75 x 106 m. a model airplane is flying on a 20.3-m guideline in a horizontal circle. the guideline is nearly parallel to the ground. find the speed of the plane such that the plane and the satellite have the same centripetal acceleration.
The speed of the plane is 32.519 m/s
Given radius of satellite orbit is [tex]r_{1} = 8.75[/tex] × [tex]10^{6} m[/tex]
Also, Orbital velocity is given by
[tex]v = \sqrt{\frac{GM}{r} }[/tex]
where M is the mass of the earth which is equal to [tex]5.98[/tex] × [tex]10^{24}[/tex] kg
G = [tex]6.67[/tex] × [tex]10^{-11}[/tex]
[tex]v = \sqrt{\frac{(6.67 * 10^{-11} )(5.98*10^{24}) }{8.75 * 10^{6} } }[/tex]
[tex]v=21.35[/tex] × [tex]10^{3}[/tex] m/s
Centripetal acceleration is given as
[tex]a_{c} = \frac{v^{2} }{r}[/tex]
[tex]a_{c} = \frac{(21.35 * 10^{3} )^{2} }{8.75 * 10^{6} }[/tex]
[tex]a_{c} = 52.094 m/s^{2}[/tex]
For model airplane
[tex]a_{c} = \frac{v^{2} }{r}[/tex]
[tex]52.094 = \frac{v^{2} }{20.3}[/tex]
v = 32.519 m/s
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an old chrysler with mass 2050 kg is moving along a straight stretch of road at 75 km/h. it is followed by a ford with mass 1300 kg moving at 40 km/h. how fast is the center of mass of the two cars moving?
the center of mass of the two cars moving is with a speed of 61.41m/s
What is center of mass ?
A position established in relation to an object or set of objects is the center of mass. It represents the system's average location as weighted by each component's mass. The centre of mass for straightforward stiff objects with homogeneous density is found at the centroid.
The center of mass also functions as a location at which inertial forces, such as centrifugal force, and gravitational force are applied. There are a number of direct and indirect techniques for locating the center of mass.
Let mc be the mass of the Chrysler and νc be its velocity .
Let mf be the mass of the Ford and νf be its velocity . Then the velocity of the center of mass is
ν com = (mc v c + mf v f) /m c+ m f = [tex](2050*75 + 1300*40)/(2050+1300)[/tex]
= 61.41 km/h
We note that the two velocities are in the same direction, so the two terms in the numerator have the same sign.
the center of mass of the two cars moving is with a speed of 61.41m/s
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If Earth's circumference at the
equator is 40,070 km, what is the
speed of the stationary satellite
GOES above the equator in km/
hour? (Use the formula: Speed =
Distance/Time)
The stationary satellite crosses the equator at a speed of 1180 kilometres per hour.
How does speed at the equator get calculated?At the equator, where the Earth's circumference is 40,070 kilometres and the day lasts for 24 hours, the speed is 1670 kilometres per hour (1037 miles per hour). This slows down by the latitude's cosine, so at a latitude of 45 degrees, cos(45) =. 707, and the speed is. 707 x 1670 = 1180 kilometres per hour.
How fast would a student travelling at the equator while seated on Earth's surface?
The daily motion felt on our earth is brought on by this spinning. You would move at almost 1,000 miles per hour (1,600 km/hr) if you were standing on the equator of the Earth, but your pace would slow down if you started moving in the direction of the North or South Poles.
A latitude of 45 degrees, cos(45) =. 707, and the speed is. 707 x 1670 = 1180 kilometres per hour.
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How are an electromagnetic wave’s wavelength and frequency related to the wave’s period of oscillation?.
Cocoa is made from _______. a. cacao beans b. cacao leaves c. the meat of the cacao fruit d. milk, butter, sugar and cacao fruit please select the best answer from the choices provided a b c d
The correct option is (a) Cocoa beans are used to make cocoa.
Cocoa bean shapes during manufacture The dried and fully fermented seed of Theobroma cacao, usually known as the cocoa bean or simply cocoa, is where cocoa solids and cocoa butter are extracted.
The dried, fully fermented cacao grain known as Theobroma is what is commonly referred to as a cacao bean or a cocoa bean. Solids, a mixture of nonfat substances, and cocoa butter, or lard, can be extracted from Theobroma cacao. The chocolate and meals from Mesoamerica were made from these cacao beans. As a result, cacao beans are used to create chocolate.
Hence, cocoa is made from cocoa beans.
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what is the momentum of an 7.2- kg bowling ball rolling at 3.0 m/sm/s ? express your answer to two significant figures and include the appropriate units.
The momentum of an 7.2 kg bowling ball rolling at 3 m/s is 21.6 kgm/s.
What is momentum and how the momentum of bowling ball calculated out to be 21.6 kgms?Momentum is defined simply as the quantity of motion of the body , but it is the product of mass and velocity.There are several kind of momentum like linear momentum, translational momentum.Here is given the mass of the object 7.2 kg and the velocity is 3 m/s of the ball.Now to calculate the momentum we will simply apply the formula momentum = mass x velocity.7.2 x 3 = 21.6 kg-m/s is the momentum of the bowling ball rolling at 3 m/s .To know more about momentum visit:
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The velocity of a wagon increases from 3 m/s to 9 m/s as it
accelerates uniformly down a hill. The average velocity of the
wagon is
m/s.
Answer:
6 m/s
Explanation:
The equation that relates time, distance, and acceleration is:
a = (vf - vi)/t
where a is acceleration (m/s^2), time is time (seconds) and vf and vi are the initial (vi) and final (vf) velocities (m/s).
Average velocity is (vf + vi)/2
We are given that:
vi = 3 m/s
vf = 9 m/s
Average velocity for the wagon is thus:
is (9 + 3)/2 = 6 m/s
