Answers
We know that two lines are parallel if they have the same slope. So we first find the slope of the given line. One way to do this is to rewrite the equation in its slope-intercept form, solving for y:
[tex]\begin{gathered} y=mx+b \\ \text{ Where} \\ m\text{ is the slope and} \\ b\text{ is the y-intercept} \end{gathered}[/tex]Then, we have:
[tex]\begin{gathered} 4x-5y=5 \\ \text{ Subtract 4x from both sides of the equation} \\ 4x-5y-4x=5-4x \\ -5y=5-4x \\ \text{ Divide by -5 from both sides} \\ \frac{-5y}{-5}=\frac{5-4x}{-5} \\ y=\frac{5}{-5}-\frac{4x}{-5} \\ y=-1+\frac{4x}{5} \\ y=\frac{4x}{5}-1 \\ y=\frac{4}{5}x-1 \end{gathered}[/tex]Now, we have the slope and a point through which the line passes:
[tex]\begin{gathered} m=\frac{4}{5} \\ (x_1,y_1)=(-5,2) \end{gathered}[/tex]Then, we can use the point-slope formula:
[tex]\begin{gathered} y-y_1=m(x-x_1) \\ y-2=\frac{4}{5}(x-(-5)_{}) \\ y-2=\frac{4}{5}(x+5_{}) \end{gathered}[/tex]The above equation is the equation of the line in its point-slope form. However, we can also rewrite the equation of the line in its standard form by solving for the constant:
[tex]ax+by=c\Rightarrow\text{ Standard form}[/tex][tex]\begin{gathered} y-2=\frac{4}{5}(x+5_{}) \\ \text{ Multiply by 5 from both sides of the equation} \\ 5(y-2)=5\cdot\frac{4}{5}(x+5_{}) \\ 5(y-2)=4(x+5_{}) \\ \text{ Apply the distributive property} \\ 5\cdot y-5\cdot2=4\cdot x+4\cdot5 \\ 5y-10=4x+20 \\ \text{ Subtract 5y from both sides} \\ 5y-10-5y=4x+20-5y \\ -10=4x+20-5y \\ \text{Subtract 20 from both sides } \\ -10-20=4x+20-5y-20 \\ -30=4x-5y \end{gathered}[/tex]Therefore, an equation of the line that passes through the point (-5,2) and is parallel to the line 4x - 5y = 5 is
[tex]\boldsymbol{4x-5y=-30}[/tex]Related Questions
Need help with a math word problem for homework. Thank you in advance
Answers
Given:
A client is making a 10-lb bag of trail mix
The chocolates cost $4 per pound and mixed nuts cost $7 per pound
the client has a budget of $6.1 per pound
We will use the variables c and n to represent the number of pounds for chocolates and nuts
So, we have the following system of equations:
[tex]\begin{gathered} c+n=10\rightarrow(1) \\ 4c+7n=6.1\cdot10\rightarrow(2) \end{gathered}[/tex]Solving the system by substitution method
From equation (1)
[tex]c=10-n\rightarrow(3)[/tex]substitute with (c) from equation (3) into equation (2)
[tex]\begin{gathered} 4(10-n)+7n=6.1\cdot10 \\ \end{gathered}[/tex]solve the equation to find (n)
[tex]\begin{gathered} 4\cdot10-4n+7n=6.1\cdot10 \\ -4n+7n=6.1\cdot10-4\cdot10 \\ 3n=21 \\ n=\frac{21}{3}=7 \end{gathered}[/tex]Substitute with (n) into equation (3) to find (c)
[tex]c=10-7=3[/tex]so, the answer will be:
The number of pounds of chocolates = c = 3 pounds
The number of pounds of nuts = n = 7 pounds
Which of the following is equal to - 7/4w expressed as a linear combination of vectors, if W= -1/2i- 3/2j?
Answers
Therefore, the scalar multiplication of vector -7/4 w is given by
[tex]-\frac{7}{4}w=-\frac{7}{4}(-\frac{1}{2}i-\frac{3}{2}j)[/tex][tex]=\frac{7}{8}i+\frac{21}{8}j[/tex]Hence, the linear combination is 7/8 i + 21/8 j
The following are all 5 quiz scores of a student in a statistics course. Each quiz was graded on a 10-point scale.6, 8, 9, 6, 5,Assuming that these scores constitute an entire population, find the standard deviation of the population. Round your answer to two decimal places.
Answers
For this type of problem we use the following formula:
[tex]\begin{gathered} \sigma=\sqrt[]{\frac{\sum^{}_{}(x_i-\mu)^2}{N},} \\ \\ \end{gathered}[/tex]where μ is the population mean, xi is each value from the population, and N is the size of the population.
First, we compute the population mean in order to do that we use the following formula:
[tex]\mu=\frac{\Sigma x_i}{N}\text{.}[/tex]Substituting each value of x_i in the above formula we get:
[tex]\mu=\frac{6+8+9+6+5}{5}=\frac{34}{5}=6.8.[/tex]Now, we compute the difference of each x_i with the mean:
[tex]\begin{gathered} 6-6.8=-0.8, \\ 8-6.8=1.2, \\ 9-6.8=2.2, \\ 6-6.8=-0.8, \\ 5-6.8=-1.8. \end{gathered}[/tex]Squaring each result we get:
[tex]\begin{gathered} (-0.8)^2=0.64, \\ (1.2)^2=1.44, \\ (2.2)^2=4.84, \\ (-0.8)^2=0.64, \\ (-1.8)^2=3.24. \end{gathered}[/tex]Now, we add the above results:
[tex]0.64+1.44+4.84+0.64+3.24=10.8.[/tex]Dividing by N=5 we get:
[tex]\frac{10.8}{5}=2.16.[/tex]Finally, taking the square root of 2.16 we obtain the standard deviation,
[tex]\sigma=\sqrt[]{2.16}\approx1.47.[/tex]Answer:
[tex]\sigma=1.47.[/tex]Basically, the question is asking to solve a problem about rectangular prisms. It says the the shape of one box, with (h) height in feet, has a volume defined by the function:V(h) = h (h-5)(h-6)It says to graph the function. What is the maximum volume for the domain 0
Answers
The function representing the volume of the rectangular prism is given to be:
[tex]V(h)=h(h-5)(h-6)[/tex]Since we are expected to find the volume using the graph, we can prepare a table of values for the function using values of h as integers from 1 - 5, such that:
[tex]\begin{gathered} At\text{ }h=1 \\ V(1)=1(1-5)(1-6)=-4\times-5=20 \end{gathered}[/tex]The completed table is shown below:
Hence, we can plot these points on a graph using a graphing calculator for ease of work. This is shown below:
The maximum volume of the prism is represented by the highest point on the graph. The graph's highest point is at:
[tex]h=1.811[/tex]The corresponding value for the volume as can be seen on the graph is:
[tex]V=24.193[/tex]This is the maximum volume of the prism.
To the nearest cubic foot, the maximum volume of the rectangular prism is 24 cubic feet.
How do I simplify 5 8/48
Answers
Given:
[tex]5\frac{8}{48}[/tex][tex]5\frac{8}{48}=\frac{248}{48}[/tex][tex]5\frac{8}{48}=\frac{31}{6}[/tex][tex]5\frac{8}{48}=5.1667[/tex]what can divide into 8 and 48
if you need to you can do small numbers like 2
but you can divide 4 and 8
you don’t have to worry about 5 because that a whole number so pretend that’s not that there until you break down the fraction till you can’t anymore
once you can’t break down the fraction anymore and the 5 back
hope this helped
The rotation of the smaller wheel in the figure causes the larger wheel to rotate. Find the radius of the largerwheel in the figure if the smaller wheel rotates 70.0° when the larger wheel rotates 40.0°The radius of the large wheel is approximately ____ cm.
Answers
Let's begin by listing out the information given to us:
r (1) = 11.4 cm, θ (1) = 70°, θ (2) = 40°, r(2) = ?
The arc length is the same for the 2 circles
r (1) * θ (1) = r (2) * θ (2)
11.4 * 70° = r (2) * 40°
r (2) = 11.4 * 70 ÷ 40
r (2) = 19.95 cm
Hence, the radius of the larger circle is 19.95 cm
#Classify each number as a natural number, a whole number, or an integer.
If a number belongs to more than one set, list all possible sets it belongs to.
a) 1
b) -20
c) -3
Answers
(a) Whole number and integer
(b) Negative integer
(c) Negative integer
What are whole numbers an integers?Positive, negative, and zero numbers all fall under the category of integers. The word "integer" is a Latin word that signifies "whole" or "intact." Therefore, fractions and decimals are not considered to be integers. A number line is a graphic representation of positive and negative integers. The use of integers on a number line facilitates mathematical procedures. The right-side number is always greater than the left-side number. Due to the fact that they are greater than 0, positive numbers are positioned to the right of zero. All natural numbers and 0 are included in a group of numbers known as whole numbers. They belong to the category of real numbers, which excludes fractions, decimals, and negative numbers. Numbers used for counting are also regarded as whole numbers.
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Draw the graph of the line that is parallel to Y -3 = 1/3(x+2) and goes through the point (1, 7)
Answers
Explanation:
We are required to draw the graph of the line that is parallel to y-3=1/3(x+2) and goes through the point (1, 7).
Given the equation of the line:
[tex]y-3=\frac{1}{3}(x+2)[/tex]Compare the equation with the slope-point form of a line:
[tex]$$y-y_1=m(x-x_1)$$[/tex]• The slope of the line, m=1/3
,• In addition, the line goes through the point (1,7)
Substitute these values into the point-slope form given above:
[tex]y-7=\frac{1}{3}(x-1)[/tex]Finally, graph the line by looking for another point in addition to point (1,7):
When x=-2
[tex]\begin{gathered} y-7=\frac{1}{3}(x-1) \\ y-7=\frac{1}{3}(-2-1) \\ y-7=\frac{1}{3}(-3) \\ y-7=-1 \\ y=-1+7 \\ y=6 \\ \implies(-2,6) \end{gathered}[/tex]Join the points (1, 7) and (-2, 6) to plot the line.
Answer:
The graph showing the two points is attached below:
Note:
For comparison purposes and to show that the two lines are parallel, the other graph is added below:
3 ftFind the outer perimeter ofthis figure. Round youranswer to the nearesthundredth. Use 3.14 toapproximate .4 ft5 ft5 ftP = [ ? ] ftNotice that only half of the circle is included in the figure!Enter
Answers
Perimeter = sum of outer lengths
Lenght of the triangle sides = 5ft
perimeter of a semicircle = π d; half = π d / 2
5 ft + 5ft + π r
5 + 5 + (3.14*3) = 19.42 ft
Estimate. Then find the quotient. Round to the nearest thousandth.24.752:6Estimate=Quotient =
Answers
Estimate = 4.13
Quotient = 4.12533333
To the nearest thousand 4.12533
Use the number line to video to find two other solutions to the inequality 7 + m < 20.
Answers
Answer:
m = 2 and m = 3
Explanation:
To find the solutions to the inequality, we need to isolate m. So, we can subtract 7 from both sides as:
7 + m < 20
7 + m - 7 < 20 - 7
m < 13
Therefore, any number that is less than 13, is a solution of the inequality.
For example: 2 and 3 are solutions of the inequality.
I got stuck and I need help on this I would appreciate the help:0
Answers
1) In this problem, we can see that this is an isosceles right triangle.
2) So, one way of solving it is to make use of the Pythagorean theorem. Note that an isosceles triangle has two congruent sides, so we can write out:
[tex]\begin{gathered} a^2=b^2+c^2 \\ b=c \\ 9^2=x^2+x^2 \\ 81=2x^2 \\ 2x^2=81 \\ \frac{2x^2}{2}=\frac{81}{2} \\ x^2=\frac{81}{2} \\ \sqrt[]{x^2}=\sqrt[]{\frac{81}{2}} \\ x=\frac{9}{\sqrt[]{2}} \end{gathered}[/tex]Usually, we rationalize it. But since the question requests the denominator to be a rational one, so this is the answer.
Consider the function f (x) = x2 – 3x + 10. Find f (6).
Answers
The given function is f(x) = x^2 - 3x + 10
this means that the expression is a function of x
f(6) means replace x with 6
f(6) = (6)^2 - 3(6) + 10
f(6) = 36 - 18 + 10
f(6) = 18 + 10
f(6) = 28
The answer is 28
what would be an equation for a decrease of 75% using the y=kx format?
Answers
Input data
75% = 0.75
format
y = kx
Procedure
The k factor would be equal to 0.25
The answer would be
[tex]y=0.25x[/tex]7. An antique dealer has a fund of $1,160 for investments. She spends 50%of the fund on a 1911 rocking chair. She then sells the chair for $710, all ofwhich she returns to the fund.a) What was the percent gain on the investment?b) What percent of the original value of the fund is the new value of the fund?
Answers
Given:
Total amount dealer has is $1160.
Spend 50% of the fund to buy a 1911 rocking chair and sells it for $710.
[tex]Fund\text{ she spends on chair=}1160\times\frac{50}{100}[/tex][tex]Fund\text{ she spends on chair= \$580}[/tex]a)
[tex]\text{Fund gain on selling the chair= 710-580}[/tex][tex]\text{Fund gain on selling the chair= \$}130[/tex][tex]\text{Percent gain on the investment=}\frac{130}{580}\times100[/tex][tex]\text{Percent gain on the investment=}22.41\text{ \%}[/tex]b)
[tex]\text{New value of the fund=1160+130}[/tex][tex]\text{New value of the fund= \$}1290[/tex][tex]\text{Percentage of original to the new value = }\frac{1290}{1160}\times100[/tex][tex]\text{Percentage of original to the new value =111.21 \%}[/tex]111.21% of the original value of the fund is the new value of the fund.
Hi! I was absent today and did not understand this lesson please I will be really grateful if you help me ! I appreciate it this is classwork assignment does not count as a test
Answers
Answer:
Given:
[tex]\begin{gathered} \sin \alpha=\frac{40}{41}first\text{ quadrant} \\ \sin \beta=\frac{4}{5},\sec ondquadrant \end{gathered}[/tex]Step 1:
Figure out the value of cos alpha
We will use the Pythagoras theorem below
[tex]\begin{gathered} \text{hyp}^2=\text{opp}^2+\text{adj}^2 \\ \text{hyp}=41,\text{opp}=40,\text{adj}=x \\ 41^2=40^2+x^2 \\ 1681=1600+x^2 \\ x^2=1681-1600 \\ x^2=81 \\ x=\sqrt[]{81} \\ x=9 \end{gathered}[/tex]Hence,
[tex]\begin{gathered} \cos \alpha=\frac{\text{adjacent}}{\text{hypotenus}} \\ \cos \alpha=\frac{9}{41} \end{gathered}[/tex]Step 2:
Figure out the value of cos beta
To figure this out, we will use the Pythagoras theorem below
[tex]\begin{gathered} \text{hyp}^2=\text{opp}^2+\text{adj}^2 \\ \text{hyp}=5,\text{opp}=4,\text{adj}=y \\ 5^2=4^2+y^2 \\ 25=16+y^2 \\ y^2=25-16 \\ y^2=9 \\ y=\sqrt[]{9} \\ y=3 \end{gathered}[/tex]Hence,
[tex]\begin{gathered} \cos \beta=\frac{\text{adjacent}}{\text{hypotenus}} \\ \cos \beta=-\frac{3}{5}(\cos \text{ is negative on the second quadrant)} \end{gathered}[/tex]Step 3:
[tex]\cos (\alpha+\beta)=\cos \alpha\cos \beta-\sin \alpha\sin \beta[/tex]By substituting the values, we will have
[tex]\begin{gathered} \cos (\alpha+\beta)=\cos \alpha\cos \beta-\sin \alpha\sin \beta \\ \cos (\alpha+\beta)=\frac{9}{41}\times-\frac{3}{5}-\frac{40}{41}\times\frac{4}{5} \\ \cos (\alpha+\beta)=-\frac{27}{205}-\frac{160}{205} \\ \cos (\alpha+\beta)=-\frac{187}{205} \end{gathered}[/tex]Hence,
The final answer = -187/205
7. f(x) = x² + 4 (a) f(-2) (b) f(3) f) f (c) f(2) (d) f(x + bx)
Answers
Find the minimum or maximum value of the function f(x)=8x2+x−5. Give your answer as a fraction.
Answers
Answer
Minimum value of the function = (-41/8)
Explanation
The minimum or maximum of a function occurs at the turning point of the graph of the function.
At this turning point, the first derivative of the function is 0.
The second derivative of the function is positive when the function is at minimum and it is negative when the function is at maximum.
f(x) = 8x² + 2x - 5
(df/dx) = 16x + 2
At minimum or maximum point,
16x + 2 = 0
16x = -2
Divide both sides by 16
(16x/16) = (-2/16)
x = (-1/8)
Second derivative
f(x) = 8x² + 2x - 5
(df/dx) = 16x + 2
(df²/d²x) = 16 > 0, that is, positive.
So, this point is a minimum point.
f(x) = 8x² + 2x - 5
f(-1/8) = 8(-1/8)² + 2(-1/8) - 5
= 8 (1/64) - (1/4) - 5
= (1/8) - (1/4) - 5
= (1/8) - (2/8) - (40/8)
= (1 - 2 - 40)/8
= (-41/8)
Hope this Helps!!!
Consider the following graph. Determine the domain and range of the graph? Is the domain and range all real numbers?
Answers
ANSWER
Domain = [-10, 10]
Range = [4]
EXPLANATION
Domain of a graph is the set of all input values on x-axis; while
Range is the set of all possible output values on y-axis.
Determining the Domain from the given graph,
The set of all INPUT values on x-axis are -10, -9, -8,....0......5,6,7,8,9,10.
So the Domain = [-10, 10].
Determining the Range from the given graph,
For the set of all possible OUTPUT values on y-axis, we only have 4,
So the Range = [4]
Hence, Domain = [-10, 10] and Range = [4]
Created by Cortin Lyons riables on Both Sides #3 2.12r – 14 = 8x + 16 12x – 14 = 6x + 16 as with Distributive Property
Answers
Problem N 2
we have
12x-14=8x+16
solve for x
subtract 8x both sides
12x-14-8x=8x+16-8x
4x-14=16
Adds 14 both sides
4x-14+14=16+14
4x=30
divide by 4 both sides
x=30/4
x=7.5
Problem N 4
we have
12x-14=6x+16
solve for x
subtract 6x both sides
12x-14-6x=6x+16-6x
6x-14=16
adds 14 both sides
6x=16+14
6x=30
divide by 6 both sides
x=30/6
x=5
what is the line that passes through points(-6,-10)(-2,-10)
Answers
The line passes through the points, (-6,-10) and (-2,-10)
We know equation of the line passing through points (x',y') and (x'',y'') is given by:
[tex]y-y^{\prime}=\frac{y^{\prime}^{\prime^{}}-y^{\prime}}{x^{\prime}^{\prime}-x^{\prime}}(x-x^{\prime})[/tex]So the equation of the line is:
[tex]\begin{gathered} y-(-10)=\frac{-10-(-10)}{-2-(-6)_{}}(x-(-6)) \\ \Rightarrow y+10=0 \\ \Rightarrow y=-10 \end{gathered}[/tex]The equation of the line is y=-10
24. How many gallons of ethanol are in a 100 gal mixture that is 10%
ethanol?
Answers
By working with percentages, we will see that there are 10 gallons of ethanol in the mixture.
How many gallons of ethanol are in the mixture?We know that we have a mixture with a volume of 100 gallons, and 10% of that mixture is ethanol, so we just need to find the 10% of 100 gallons.
To work with percentages, we will use the equation:
Volume of ethanol = total volume*ratio of ethanol.
V = 100gal*(10%/100%)
V = 100gal*0.10 = 10 gal
There are 10 gallons in the mixture.
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Help please I’ll give 10 points
Answers
The writing of the symbols, <, =, or > in each of the comparison (equality or inequality) statements is as follows:
1. 0.02 > 0.002
2. 0.05 < 0.5
3. 0.74 < 0.84
4. 0.74 > 0.084
5. 1.2 < 1.25
6. 5.130 = 5.13
7. 3.201 > 3.099
8. 0.159 < 1.590
9. 8.269 > 8.268
10. 4.60 > 4.060
11. 302.026 > 300.226
12. 0.237 > 0.223
13. 3.033 < 3.303
14. 9.074 < 9.47
15. 6.129 < 6.19
16. 567.45 > 564.75
17. 78.967 > 7.957
18. 5.346 < 5.4
19. 12.112 < 12.121
20. 26.2 = 26.200
21. 100.32 > 100.232
22) The strategy for solving comparison mathematical statements is to check the place values.
What is a place value?A place value is a numerical value that a digit possesses because of its position in a number.
To find a digit's place value, discover how many places the digit is to the right or left of the decimal point in a number.
Some of the place values before the decimal place include Millions, Hundred Thousands, Ten Thousands, Thousands, Hundreds, Tens, and Units.
After the decimal place, the place values are tenths, hundredths, thousandths, ten thousandths, hundred thousandth, and millionths.
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the cone has a height of 19 mm and the radius of 15 mm what is its volume use pie and round your answer to the nearest hundredth
Answers
Answer
Volume = 4,478.57 mm³
Explanation
The volume of a cone is given as
Volume = ⅓ (πr²h)
where
π = pi = 3.142
r = radius of the cone = 15 mm
h = height of the cone = 19 mm
Volume = ?
Volume = ⅓ (πr²h)
Volume = ⅓ (3.142 × 15² × 19) = 4,478.57 mm³
Hope this Helps!!!
the sum of interior angle measures of a polygon with n sides is 2340 degrees. find n15
Answers
the measure of each angle will be 2340/n then if n=15 the measure of each one of the angles will be 2340/15=156 degrees
A football team is losing by 14 points near the end of a game. The team scores two touchdowns (worth 6 points each) before the end of the game. After each touchdown, the coach must decide whether to go for 1 point with a kick (which is successful 99% of the time) or 2 points with a run or pass (which is successful 45% of the time). If the team goes for 1 point after each touchdown, what is the probability that the coach’s team wins? loses? ties? If the team goes for 2 points after each touchdown, what is the probability that the coach’s team wins? loses? ties? Can you develop a strategy so that the coach’s team has a probability of winning the game that is greater than the probability of losing
Answers
His football team is losing 14 points near the end of the game. The team scores two touchdowns with each worth 6 points (total = 12 points).
After each touchdown, the coach must decide whether to go for 1 point with each kick(99% successful) or 2 points with a run or pass(45% successful).
Note
Two touchdown = 12 points
So, it remaining 2 point to level up and more than 2 points to win the game
a.
If the team goes for 1 point after each touchdown, the probability that the coach's team loses? wins? ties? can be computed below
[tex]undefined[/tex]A hairdresser is considering ordering a certain shampoo. Company A charges $5 per 8 ounce bottle plus a $5 handling fee per order. Company B charges $2 per 8 ounce bottle plus a $23 handling fee per order. How many bottles must the hairdresser buy to justify using Company B?
Answers
For the shampoo:
Company A charges $5 per ounce bottle + $5 handling fee.
Company B charges $2 per ounce bottle + $23 handling fee.
Let C represent the total cost for the shampoo and x represent the number of bottles of shampoo then you can express the total cost for both companies as equations:
[tex]\begin{gathered} C_A=5x+5 \\ C_B=8x+23 \end{gathered}[/tex]For the hairdresser to justify using the shampoo of company C, the cost must be less than for company A, so that:
[tex]\begin{gathered} C_BNowShow the steps needed to Evaluate (2)^-2
Answers
Answer:
[tex]\dfrac{1}{4}[/tex]
Step-by-step explanation:
Given expression:
[tex]2^{-2}[/tex]
[tex]\boxed{\textsf{Exponent rule}: \quad a^{-n}=\dfrac{1}{a^n}}[/tex]
Apply the exponent rule to the given expression:
[tex]\implies 2^{-2}=\dfrac{1}{2^2}[/tex]
Two squared is the same as multiplying 2 by itself, therefore:
[tex]\begin{aligned}\implies 2^{-2}&=\dfrac{1}{2^2}\\\\&=\dfrac{1}{2 \times 2}\\\\&=\dfrac{1}{4}\end{aligned}[/tex]
Solution
[tex]2^{-2}=\dfrac{1}{4}[/tex]
Answer:
1/4
Step-by-step explanation:
Now we have to,
→ find the required value of (2)^-2.
Let's solve the problem,
→ (2)^-2
→ (1/2)² = 1/4
Therefore, the value is 1/4.
Determine the solution to the given equation.4 + 3y = 6y – 5
Answers
Answer:
[tex]y=3[/tex]Explanation:
Step 1. The expression we have is:
[tex]4+3y=6y-5[/tex]And we are required to find the solution; the value of y.
Step 2. To find the value of y, we need to have all of the terms that contain the variable on the same side of the equation. For this, we subtract 6y to both sides:
[tex]4+3y-6y=-5[/tex]Step 3. Also, we need all of the numbers on the opposite side that the variables are, so we subtract 4 to both sides:
[tex]3y-6y=-5-4[/tex]Step 4. Combine the like terms.
We combine the terms that contain y on the left side of the equation, and the numbers on the right side of the equation:
[tex]-3y=-9[/tex]Step 5. The last step will be to divide both sides of the equation by -3 in order to have only ''y'' on the left side:
[tex]\begin{gathered} \frac{-3y}{-3}=\frac{-9}{-3} \\ \downarrow\downarrow \\ y=3 \end{gathered}[/tex]The value of y is 3.
Answer:
[tex]y=3[/tex]FIRST OPTIONS ARE THE NUMBER OF CONVERTIBLES SOLD BY PLATO CARSTHE REVENUE FROM SALES OF CONVERTIBLE CARS BY PLATO CARSTHE REVENUE FROM SALES OF SEDANS BY PLATO CARSTHE TOTAL SALES REVENUE OF PLATO CARS SECOND OPTIONS 0.1070.2250.290.33
Answers
Given:
The number in the highlighted cell is 18.
The total sales revenue of pluto cars is 80.
To find the relative frequency from the sales of sedans by Plato cars to the total sales revenue of Plato cars:
The formula for relative frequency is,
[tex]\begin{gathered} RF=\frac{subgroup\text{ fr}equency}{\text{Total frequency}} \\ =\frac{18}{80} \\ =0.225 \end{gathered}[/tex]So, the relative frequency is 0.225.
Hence, the answer is,
The number in the highlighted cell is 18. The relative frequency from the sales of sedans by Plato cars to the total sales revenue of Plato cars is 0.225
