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I need answers help please
Answer: Can't see clearly.
Explanation:
Enumerate some things you can do to make work easier and faster when working with simple machines. (2 answer)
Answer:
by increasing the distance through which force is applied, by multiplying force of speed to the energy applied
The first user who answer is correct :)
i know it’s 30 but how ??? what equations did you use and how do you get there ?
The change in momentum of the object between 0 and 4s is 40 Ns.
What is momentum?The momentum of an object is determined from the product of mass and velocity of the object.
The change in momentum of an object is equal to the impulse received by the object.
ΔP = J = Ft
where;
ΔP is change in momentumJ is impulseF is forcet is timeThe change in momentum of the object between 0 and 4s is calculated as follows;
ΔP = Ft
ΔP = 10 x 4
ΔP = 40 Ns
Learn more about change in momentum here: https://brainly.com/question/7538238
Who is juan pablo duarte?
Answer:
Juan Pablo Duarte was a Dominican military leader, writer, activist, and nationalist politician who was the foremost of the founding fathers of the Dominican Republic.
Can someone please answer this? I am really lost.
Answer:
8.0 rad/s
Explanation:
I₁ = 1.0 kgm², ω₁ = -20.0 rad/s (clockwise is positive direction)
I₂ = 4.0 kgm², ω₂ = 15.0 rad/s
Angular momentum conservation:
I₁ω₁ + I₂ω₂ = (I₁ + I₂)ω
1.0 x (-20.0) + 4.0 * 15.0 = (1.0 + 4.0)ω
40.0 = 5.0ω
so ω = 8.0 rad/s
5) Two cables support a mass of 100kg. One cable is perfectly horizontal, while the other
makes an angle of 40 degrees above the horizontal. Find the tension in the horizontal
cable.
T sin θ = M g = W cable supporting weight
T = 100 * 9.8 / sin 40 = 1525 N
T cos θ = Th horizontal force due to cable
Th = 1525 cos 40 = 1168 N
Brainliest if correct
Answer:
It's is c coz the weight is equal to the normal force
TRUE or FALSE: Sound travels faster through dense materials.
True
False
Answer:
True
Explanation:
The denser the materals the fast sound travels
Answer:
True
Explanation:
I believe tue answer is true
What is the magnitude of the electric field at a point that is 0.5m to the right of a small sphere with a net charge of -6.0x10-6 C?
Answer:
lil durk a goat
Explanation:
As observed from Earth, the Sun has an angular size of about 0.53o. From the observation, estimate the diameter of the Sun. How large in volume is the Sun when compared to Earth?
A 4-lb collar can slide without friction along a horizontal rod and is in equilibrium at A when it is pushed 1 in. to the right and released from rest. The springs are undeformed when the collar is at A and the constant of each spring is 2800 lb/in. Determine the maximum velocity of the collar.
The maximum velocity of the collar is 0.335 m/s.
Maximum velocity of simple harmonic motion
The maximum velocity of a simple harmonic motion occurs when the object is in equilibrium position.
K.E = U
¹/₂mv² = ¹/₂kx²
mv² = kx²
where;
k is spring constant = 2800 lb/in = 316.36 N/mx is extension = 1 in = 0.0254 mm is mass = 4 lb = 1.81 kg[tex]v = \sqrt{\frac{kx^2}{m} } \\\\v = \sqrt{\frac{316.36 \times 0.0254^2}{1.81} }\\\\v = 0.335 \ m/s[/tex]
Thus, the maximum velocity of the collar is 0.335 m/s.
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How do you think this Eskimo nebula could affect Earth and
the organisms that live on our planet?
Answer:
It does not affect. The closest nebula is the Orion Nebula at more than 1300 light years from Earth. It is so remote that nothing that happens there can influence the Earth. The only influence is to have beautiful colors and shapes and to let us dream one day to go there and explore them.
Explanation:
How much work is needed to lift a 50kg weight 3.0m ?
A bridge that was 5m long has been washed out by a heavy rain. The road on the
far side of the stream is 2m lower that the road the car starts on. How fast must
the car be going to successfully jump the stream?
Suppose that Salim hits a 100 g fastball moving towards him at a speed of 42 m/s with his bat as shown in the image.the impulse of the fastball is 8 kg.m/s in the antiparallel direction of the initial velocity. Then the final momentum of the fastball is --------------( Suppose that the direction of the fastball toward the bat is negative and away from the bat is positive)
1.8 kg m/s
0.6 kg m/s
3.8 kg m/s
2.4 kg m/s
The final momentum of the ball is 3.8 kgm/s.
Change in momentum of the ballThe impulse received by the ball is equal to change in momentum of the ball.
J = ΔP
where;
J is the impulseΔP is change in momentumΔP = P₂ - P₁
P₂ = ΔP + P₁
Final momentum of the ballThe final momentum of the ball is calculated as follows;
P₂ = 8 + (- 0.1 x 42)
P₂ = 8 - 4.2
P₂ = 3.8 kgm/s
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Siobhan wants to measure the mass of a bag of flour. What should she use?
This depends on how big the bag is. Most commonly, the bag weighs 2 kg to 10 kg or more. With this range of weight, Siobhan should use a balance to measure the mass of the flour and record the mass in kilograms. Thus, the answer is the first choice
Answer:
A weighing scale
Explanation:
A weighing scale graduated in grams or kilograms can be used.
True or false: charge can be created or destroyed
Answer:
False
Explanation:
Charges only be transferred from one system to another. Materials that permit electrons to move freely through them, such as most metals
khanacademy
With what minimum speed must athlete leave the ground in order to lift his center of mass 2.00 m and cross the bar with a speed of 0.95 m/s
The athlete must leave the ground with a speed of 6.33m/s.
Kinect and potential energyTo calculate the initial speed, with the information of height and final speed, we can use the following expression that uses the kinetic energy and potential energy:
[tex]mgh_1 + \frac{1}{2}mv_1^{2}= mgh_2 + \frac{1}{2}mv_2^{2}[/tex]
Applying the values given by the statement we have:
[tex]9.81\times 0 + \frac{1}{2}v_1^{2} = 9.81 \times 2 + \frac{1}{2}(0.95)^{2}[/tex]
[tex]v_1 = 6.33m/s[/tex]
So, the athlete must leave the ground with a speed of 6.33m/s.
Learn more about kinect and potential energy in: brainly.com/question/14509624
state some important uses of magnet
The rear wheel of a 150 kg tricycle accidentally ran over a nail. The circular tip of the nail has a diameter of 0.001 m. How much pressure did the wheel of the tricycle experience assuming that the entire weight of the tricycle is concentrated on the rear wheel that ran over the nail.
The pressure experienced by the wheel of the tricycle is 1.85×10¹⁰ N/m²
Pressure can be defined as the force acting perpendicular per unit area on the surface of a body. The S.I unit of pressure is N/m²
To calculate the pressure of the wheel of the tricycle, we use the formula below
Formula:
P = 4mg/πd².............. Equation 1Where:
P = Pressure of the tricycle wheelm = mass of the wheeld = diameter of the wheelg = acceleration due to gravityπ = pie.From the question,
Given:
m = 150 kgd = 0.001 mg = 9.8 m/s²π = 3.14Substitute these values into equation 1
P = 4(150)(9.8)/(0.001²×3.14)P = 5880/0.00000314P = 1.85×10¹⁰ N/m²Hence, The pressure experienced by the wheel of the tricycle is 1.85×10¹⁰ N/m².
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As shown below, if M = 6.0 kg, what is the tension in the
connecting string? The pulley and all surfaces are frictionless.
30°
The tension in the connecting string is 14.7 N.
Net force of the masses
The net force of the masses is calculated as follows;
[tex]F_{net} = Mgsin(\theta)+ Mg[/tex]
Acceleration of the massesThe acceleration of the masses is calculated as follows;
[tex]a = \frac{F_{net}}{M+ M} = \frac{M(gsin\theta + g)}{2M} = \frac{gsin\theta + g}{2} \\\\a = \frac{9.8sin(30) \ + \ 9.8}{2} = 7.35 \ m/s^2[/tex]
Tension in the connecting stringThe tension in the connecting string is calculated as follows;
[tex]mg - T = ma\\\\T = mg - ma\\\\T = m(g - a)\\\\T = 6(9.8 - 7.35)\\\\T = 14.7 \ N[/tex]
Thus, the tension in the connecting string is 14.7 N.
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A rotating turntable (rt=4.50 m) is rotating at a constant rate. At the edge of the turntable is a mass (m = 3.00 kg) on the end of a 5.00 m - long string (L). If theta = 40.0o,determine:
The magnitude of the tension in the string is 9.31 N.
Tension in the stringThe magnitude of the tension in the string in the horizontal circle formed by the turn table is calculated as follows;
T = Fcos(θ)
where;
F is centripetal forceθ is inclination of the string[tex]T = \frac{mv^2}{r} \times cos(\theta)\\\\T = \frac{3 \times 4.5^2}{5} \times cos(40)\\\\T = 9.31 \ N[/tex]
Thus, the magnitude of the tension in the string is 9.31 N.
The complete question is below:
A rotating turntable (rt=4.50 m) is rotating at a constant rate. At the edge of the turntable is a mass (m = 3.00 kg) on the end of a 5.00 m - long string (L). If theta = 40.0o,determine the magnitude of the tension in the string.
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Perform an experiment in which you flip a switch 2,300,000 times. Write this
number in scientific notation.
O A. 23 x 10-6
O B. 2.3 x 106
O C. 0.23 x 105
O D. 0.23 x 106
Answer:
B. 2.3 x 10⁶
Explanation:
To calculate scientific notation for the number 2,300,000, we have to follow this notation
a × 10^bStep 1 :
To find a we have to write the non-zero digits placing a decimal after the first non-zero digit.
2,300,000 to 2.300000Step 2 :
Now, to find b count how many numbers of digits are there to the right of the decimal.
2.300000Hence, there are 6 digits to the right of the decimal.
Step 3 :
Since, we had found the value of a and b, we can now reconstruct the number into scientific notation.
a = 2.3
b = 6
2.3 × 10⁶Therefore, option b is correct.
Select the correct answer.
While Jordan was playing with her favorite doll, one of its legs fell off. Now she wants to take the doll to visit the doctor. What does Jordan's
thought process demonstrate?
O A. logic
OB. animism
O C. classification
OD. conservation
A sphere of mass M 5 1.00 kg is supported by a string that passes over a pulley at the end of a horizontal rod of length L 5 0.300 m (Fig. P17.15). The string makes an angle u 5 35.08 with the rod. The fundamental frequency of standing waves in the portion of the string above the rod is f 5 60.0 Hz. Find the mass of the portion of the string above the rod.
A fundamental frequency of 60 Hz, attached mass of 1 kg., rod length of
0.3 m gives the mass of the part of the string as 3.245 × 10⁻³ kg.
Response:
The mass of the string, m ≈ 3.245 × 10⁻³ kgHow can the mass of the part of the string be calculated?The given parameters are;
Mass of the sphere, M = 1.00 kg
Length of the rod, L = 0.300 m
Angle the string makes with the rod, θ = 35°
The fundamental frequency of the standing wave in the portion of the
string above the rod, f₁ = 60.0 Hz
Required;
The mass of the portion of the string above the rod
Solution:
The fundamental frequency in a string is given as follows;
[tex]f_1 = \mathbf{\dfrac{\sqrt{\dfrac{T}{m/l} } }{2 \cdot l}}[/tex]Where;
T = The tension in the string
m = The mass of the string
l = The length of the string
[tex]The \ tension \ in \ the \ string, \ T= \mathbf{\dfrac{M \cdot g}{sin(\theta)}}[/tex]Which gives;
[tex]T= \mathbf{\dfrac{1 \times 9.81}{sin(35)}} \approx 17.1[/tex]
The tension in the string, T ≈ 17.1 N
[tex]The \ length \ of \ the \ string, \ l=\mathbf{\dfrac{L}{cos(\theta)}}[/tex]
Therefore;
[tex]l=\dfrac{0.300}{cos \left(35^{\circ} \right)} \approx 0.366[/tex]
Therefore;
[tex]60.0 = \mathbf{\dfrac{\sqrt{\dfrac{17.1}{m/0.366} } }{2 \times 0.366}}[/tex]
Which gives;
[tex]m = \dfrac{17.1}{(60.0 \times 2 \times 0.366)^2} \times 0.366 \approx 3.245 \times 10^{-3}[/tex]
The mass of the string, m ≈ 3.245 × 10⁻³ kgLearn more about the fundamental frequency of an material here:
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Directions: Read the following excerpts carefully, then identify whether they employ informative, persuasive, or argumentative writing technique.
ENGLISH Subject:
I am really confused, might anyone know?
Hi there!
Informative writing has the intent to inform or educate us on a particular topic or event. It gives us more information and insight onto something.
Persuasive writing has the intent of convincing us to believe in a certain idea or to perform a certain action. For instance, advertisements have a persuasive intent; they are persuading us to buy a product or service.
Argumentative writing is similar to persuasive writing in the sense that they are persuading us to believe a certain idea. However, they are often based on logic and fact rather than opinions.
Let's look at the first excerpt.
This morning at 9 a.m., a school bus collided with a car at the intersection of Osmena and Cabrera streets. The passengers were not injured, but the medical personnel checked each student as well as the driver before they were transported to their school.
This text doesn't try to convince us in believing something. It doesn't argue anything and it only tries to give us more insight onto the event, which is a car accident. No opinions are stated and only events are given.
Therefore, this excerpt uses an informative writing technique.
Answer:
1. Informative
2. Persuasive
3. Informative
4. Persuasive
5. Argumentative
Explanation:
Informative is a way to inform the audience on a particular topic throughout the reading. Common examples of an informative paragraph would be to inform people on different situations around the world or a news outlet some would say.
Persuasive is a way to convince one to change/commit an act of sorts. Through persuasion you can convince your audience to look at a situation from a different perspective and perhaps convince the person to be more willing to do change the way they do something else. Common example of a persuasive paragraph would be trying to persuade someone to use less water through telling them the importance of water conservation and how water is a nonrenewable source.
Argumentative somewhat similar to persuasive but is more assertive you are trying to convince the audience why the side you're apart of is more better then the opposite side through a means of ethos, pathos, and logos. Common example of a argumentative paragraph would be something like why pizza is better then hamburgers.
Now that we know this information it's time to answer:
Excerpt one:
Excerpt one is known "informative excerpt" because we are informing the readers about how a school bus collided with a car nearby, and how thankfully none of the passengers were injured.
Excerpt two:
Excerpt two would be known as a "persuasive writing." We aren't trying to convince the audience on our side of donating blood so this won't be an argumentative writing, we are trying to persuade them by saying the benefits of how donating blood can save a person's life.
Excerpt three:
Excerpt three would be known as an "informative writing." We aren't trying to persuade or convince we are trying to inform the audience of the dangers of drinking while in high school by listing all the negative effects drinking has on a highschooler like unsafe encounters.
Excerpt four:
Excerpt four would be known as an "persuasive writing." This writing is trying to convince the reader about how the death penalty is a good punishment for criminals because the bible says an eye for an eye and how we should keep it on the books.
Excerpt five:
The final excerpt will be known as an "argumentative writing." This writing is again assertive, and it lists both sides of the spectrum how parents won't let their children study abroad because of how expensive it costs for things like tuition, food, shelter along with other necessities. It even goes as far as stating it's own position by saying how it's expensive to study abroad.
Hope this helps.
A car of mass 1ton is brought to rest from a speed of 40m/s in a
distance of 80m. Find the braking force of the car assuming that it is
constant and that there is a constant resistance to motion of 100N.
Answer:
10,100 N
Explanation:
m - 1 ton = 1,000 kg
v₀ = 40 m/s, v = 0
d = 80 m
f = 100 N
Net force = F + f = ma
v² - v₀² = 2ad, so a = (v² - v₀²)/(2d) = (0 - 40²)/(2*80) = -10 m/s²
F = ma - f = 1,000*(-10) - 100 = -10,100 N
negative sign means opposite to the driving direction
If the frequency increased, how would the change impact the wave speed and wavelength?
Answer:
The frequency and wavelength of a wave are related. When frequency increases more wave crests pass a fixed point each second. That means the wavelength shortens. So, as frequency increases, wavelength decreases.
Explanation:
Answer: The waves travel at the same speed, but the observed frequency depends on any relative motion between the observer and source. When the observed frequency changes, so does the wavelength. If the observer and source are moving toward each other, then the frequency increases and the wavelength decreases.
Explanation: I hope this helped you understand
A concave cosmetic mirror has a focal length of 40 cm . A 4.0-cm-long mascara brush is held upright 20 cm from the mirror.
a) Use ray tracing to determine the location of its image
b) What is the height of the image? Use ray tracing to determine.
The location of image and the height of the image is mathematically given as
di = -40 cm
h=8 cm
The location of image and the height of the image
upright and enlarged
Question Parameters:
Generally the equation for the is mathematically given as
using mirror equation
1/f = (1/do) + (1/di)
Therefore
1/40 = (1/20) + (1/di)
di = -40 cm
Therefore, Magnification
m = -di/do = hi/h\
m = 40/20 = hi/4
m = 2 = hi/4
image height is
hi = 4*2
h=8 cm
upright and enlarged
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