What is one watt ? Write the relation of watt with kilowatt , megawatt , and horsepower .​

Answer:

Difference is given below.

Explanation:

The main difference between beneficial and harmful friction is that beneficial friction is necessary for performing different activities while on the other hand, harmful effect of friction is destroy different parts of products and machines. examples of beneficial friction are walking, holding things, rubbing hands to produce heat, running etc whereas examples of harmful friction are destruction of sole, slipping, tearing of machine's part, Wet roads and Mudslides etc.

Answer:

Not all the pictures are popping up. So I can't answer them all. :(

Explanation:

The fist one is B. And the second is D. That's all I can see. I hope this helps a little bit :(

Answer:The answer is A

Explanation:

Answer:

A. Electromagnetism

Explanation:

Whenever current travels through a conductor (the wire) a magnetic field is generated. Due to being a wire, the current formed is electric, so this making it an electromagnetic field.

Answer:

Steps include:

Assumption: both planet earth and this hypothetical planet are spheres of uniform density.

Explanation:

Let [tex]M_0[/tex], [tex]r_0[/tex], and [tex]\rho_0[/tex] denote the mass, radius, and density of planet earth.

The radius and density of this hypothetical planet would be [tex](1/2)\, r_0[/tex] and [tex]2\, \rho_0[/tex], respectively.

The volume of a sphere is [tex]\displaystyle V = \frac{4}{3}\, \pi\, r^3[/tex].

Therefore:

The mass of an object is the product of its volume and density. Hence, the mass of the earth could also be represented as:

[tex]\displaystyle M_0 = \rho_0\, V_0 = \frac{4}{3}\, \pi\, {r_0}^{3}\, \rho_0[/tex].

In comparison, the mass of this hypothetical planet would be:

[tex]\begin{aligned}M &= \rho\, V\\ &= (2\, \rho_0) \cdot \left(\frac{1}{6}\, \pi\, {r_0}^3\right) \\ &= \frac{1}{3}\, \pi\, {r_0}^{3}\, \rho_0 \end{aligned}[/tex].

Compare these two expressions. Notice that [tex]\displaystyle M = \frac{1}{4}\, M_0[/tex]. In other words, the mass of the hypothetical planet is one-fourth the mass of planet earth.

The acceleration of free fall near the surface of a planet is equal to the gravitational field strength at that very position.

Consider a sphere of uniform density. Let the mass and radius of that sphere be [tex]M[/tex] and [tex]r[/tex], respectively. Let [tex]G[/tex] denote the constant of universal gravitation. Right next to the surface of that sphere, the strength of the gravitational field of that sphere would be:

[tex]\displaystyle g = \frac{G \cdot M}{r^2}[/tex].

(That's the same as if all the mass of that sphere were concentrated at a point at the center of that sphere.)

Assume that both planet earth and this hypothetical planet are spheres of uniform density.

Using this equation, the gravitational field strength near the surface the earth would be:

[tex]\displaystyle g_0 &= \frac{G \cdot M_0}{{r_0}^2}[/tex].

.

On the other hand, the gravitational field strength near the surface of that hypothetical planet would be:

[tex]\begin{aligned}g &= \frac{G \cdot (M_0/4)}{{(r_0/2)}^2} = \frac{G \cdot M_0}{{r_0}^2}\end{aligned}[/tex].

Notice that these two expressions are equal. Therefore, the gravitational field strength (and hence the acceleration of free fall) would be the same near the surface of the earth and near the surface of that hypothetical planet.

As a side note, both [tex]g[/tex] and [tex]g_0[/tex] could be expressed in terms of [tex]\rho_0[/tex] and [tex]r_0[/tex] alongside the constants [tex]\pi[/tex] and [tex]G[/tex]:

[tex]\begin{aligned}g &= \frac{G \cdot M}{r^2}\\ &= \frac{G \cdot (1/3)\, \pi\, {r_0}^3 \, \rho_0}{(r_0/2)^2} = \frac{4}{3}\,\pi\, G\, r_0\, \rho_0\end{aligned}[/tex].

[tex]\begin{aligned}g_0 &= \frac{G \cdot M_0}{{r_0}^2}\\ &= \frac{G \cdot (4/3)\, \pi\, {r_0}^3 \, \rho_0}{{r_0}^2} = \frac{4}{3}\,\pi\, G\, r_0\, \rho_0\end{aligned}[/tex].

Answer:

a is the correct choice

Explanation:

The wave has the highest frequency in option A.

The frequency of a wave is the number of cycles completed by the wave in a given period of time. Frequency is measured in Hertz (Hz).

The frequency of a wave is calculated as follows;

[tex]v = f \lambda\\\\f = \frac{v}{\lambda}[/tex]

where;

From the given chart, in option A the wave completed more cycles in the given period of time.

Thus, the wave has the highest frequency in option A.

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Answer:

The answer is temperature

Answer:

What is the question?

Explanation:

If you tell me the question I can help.

Answer:

graph 1

Explanation:

When it comes to a graph showing "constant acceleration," the line should be straight and upward (positive acceleration) or straight and downward (negative acceleration). The variables for acceleration are time and velocity. The independent variable (time) should be placed on the x-axis while the dependent variable (velocity) should be placed on the y-axis. As time increases, the velocity increases the same way. It doesn't slow down or changes. This makes it constant. They are also directly proportional to each other. This is evident on the first graph.

Answer:

the motion of the sled decrease

Explanation:

the mass increase

The acceleration of the sled will is inversely proportional to the mass on it. Therefore, the motion of the sled would slow if Joslyn's friend Lisa also wanted to ride.

Acceleration in mechanics can be described as the rate of change of velocity of an object with respect to time. The acceleration of an object is a vector quantities with magnitude and direction.

The S.I. unit for acceleration can be represented as m/s² the net balance of all external forces acting is equal to the magnitude of the net resulting force.

The force (F) acting on an object is equal to the product of the mass (m) of the object and acceleration (a) of an object.

F = ma

And, a = F/m

As shown in the above equation, the mass of the object is inversely proportional to the acceleration of the object, therefore, the acceleration of the sled decrease as the mass on it increases.

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Answer:

a) The centripetal acceleration of the car is 0.68 m/s²

b) The force that maintains circular motion is 940.03 N.

c) The minimum coefficient of static friction between the tires and the road is 0.069.

Explanation:

a) The centripetal acceleration of the car can be found using the following equation:

[tex] a_{c} = \frac{v^{2}}{r} [/tex]

Where:

v: is the velocity of the car = 51.1 km/h

r: is the radius = 2.95x10² m

[tex] a_{c} = \frac{(51.1 \frac{km}{h}*\frac{1000 m}{1 km}*\frac{1 h}{3600 s})^{2}}{2.95 \cdot 10^{2} m} = 0.68 m/s^{2} [/tex]

Hence, the centripetal acceleration of the car is 0.68 m/s².

b) The force that maintains circular motion is the centripetal force:

[tex] F_{c} = ma_{c} [/tex]

Where:

m: is the mass of the car

The mass is given by:

[tex] P = m*g [/tex]

Where P is the weight of the car = 13561 N

[tex] m = \frac{P}{g} = \frac{13561 N}{9.81 m/s^{2}} = 1382.4 kg [/tex]

Now, the centripetal force is:

[tex] F_{c} = ma_{c} = 1382.4 kg*0.68 m/s^{2} = 940.03 N [/tex]

Then, the force that maintains circular motion is 940.03 N.

c) Since the centripetal force is equal to the coefficient of static friction, this can be calculated as follows:

[tex] F_{c} = F_{\mu} [/tex]

[tex] F_{c} = \mu N = \mu P [/tex]

[tex] \mu = \frac{F_{c}}{P} = \frac{940.03 N}{13561 N} = 0.069 [/tex]

Therefore, the minimum coefficient of static friction between the tires and the road is 0.069.

I hope it helps you!                

Answer:

push up agaisnt you with equal force.

Answer:

c

Explanation:

Answer:

2.5m

Explanation:

Speed/velocity = 0.5m/s

Time = 5s

speed = Distance/Time

Distance = Speed x Time

Distance = 0.5 x 5

Distance = 2.5m

A plant growing towards a light source is an example of an organism of Phototropism

Answer:

W = 1526.43 J

Explanation:

Given that,

Force acting on a heavy crate, F = 325 N

The rope will make 29.0° angle with the horizontal

The distance covered by the crate, d = 5.37 m

We need to find the work done by the crate. The work done by an object is given by :

[tex]W=Fd\cos\theta\\\\=325 \times 5.37\times \cos29\\\\=1526.43\ J[/tex]

So, the required work done is 1526.43 J.

Answer:

Explanation:

The speed of an object can be found by using the formula

[tex]v = \frac{d}{t} \\ [/tex]

d is the distance

t is the time taken

From the question

600 km = 600,000 m

8hrs = 28,800 s

We have

[tex]v = \frac{600000}{28800} = \frac{6000}{288} = \frac{125}{6} \\ = 20.83333...[/tex]

We have the final answer as

Hope this helps you

Answer:

20.833333... m/s  or   20 & 5/6 m/s

Explanation:

You want to convert km to meters, and hours to seconds. You do "dimensional analysis," which is just multiplying fractions so that units cancel.[tex]\frac{600 km}{8hr} * \frac{1hr}{60mins} * \frac{1min}{60sec} = \frac{600km}{28,800sec} = \frac{6km}{288sec}[/tex]

so now we have km/sec, but we need m/s, so...

[tex]\frac{6km}{288sec} * \frac{1000m}{1km} = \frac{6000m}{288sec} = \frac{125m}{6sec} = 20\frac{5}{6} m/s = 20.83333... m/s[/tex]

Answer:

Full moon

Explanation:

Answer:

B

Explanation:

The question does not specify any outside forces that could slow down the ball horizontally. There fore the ball does not accelerate or decelerate horizontally. Therefore,  a = 0m/s2

Answer:

rick, also known by his fans as they benevolently call him as "Uncle Rick"

Explanation:

he is the one and only author of his trademark mythology

known best for his PJO, HBO and TOA series, uncle rick is one of the best things to ever happen to this planet

Answer:

Constructive interference

Explanation:

Answer:

C. Constructive interference

Explanation:

Answer:

9 times

Explanation:

Mass of a body remains constant.

Let the mass of a body be 'm'

Let the speed of the body be 'v'

Initial Kinetic Energy (K.E.) = [tex] \frac{1}{2} m {v}^{2} [/tex]

When speed is tripled , new speed = 3v

Mass of body = m (Mass is always constant)

Final Kinetic Energy (K.E.") =

[tex] \frac{1}{2} \times m \times {(3v)}^{2} [/tex]

[tex] = > \frac{1}{2} \times m \times 9v[/tex]

[tex] = > 9( \frac{1}{2} m {v}^{2} )[/tex]

But we already know that [tex]k.e. = \frac{1}{2} m {v}^{2} [/tex]

Hence

[tex] = > final \: k.e. = 9(initial \: k.e.)[/tex]

I = V/Rt = 1.5/(100+100) = 1.5/200 = 0.0075 A ....or 0.0075*1000 = 7.50 mA

I = V/Rt

= 1.5/(100+100) = 1.5/200

= 0.0075 A ....or 0.0075*1000 = 7.50 mA

In a full electrical circuit, current is the rate at which electrons move past a certain point. Current = flow, at its most fundamental level.

The international unit for measuring current is an ampere (AM-pir), sometimes known as an amp. It describes how many electrons (sometimes referred to as "electrical charge") travel past a certain point in a circuit over a specified period of time.

In a circuit, a current of 1 ampere corresponds to the movement of 1 coulomb of electrons, or 6.24 billion (6.24 x 1018) electrons, through a single location in a second.

Therefore, I = 0.0075 A ....or 0.0075*1000 = 7.50 mA

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Answer:

1 m/s so number 2 is the right one

Explanation:

so when it is at rest it still has some of the left over energy so it would be at 1 m/s

Answer:

Increase Water Consumption

Try a New Diet

Help Your Cat Maintain a Healthy Weight

Increase Exercise and Enrichment

Minimize Stress and Anxiety

Add More Litter Boxes

Try Fiber or Probiotics

Ask Your Vet About Over-the-Counter Laxatives

Explanation:

Answer:

Picture?

Explanation:

The roller coaster will have equal kinetic and potential energy at any point starting from rest and reaching the minimum height.

The given problem is based on the concepts and fundamentals of kinetic energy and potential energy. The energy of an object by virtue of its position is known as kinetic energy. And the energy of object by virtue of its position is called potential energy.

Thus, we can conclude that the roller coaster will have equal kinetic and potential energy at any point starting from rest and reaching the minimum height.

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Answer:

735

Explanation:

w=mg

w=75*9.8=735N

Answer:

4s

Explanation:

Using the formula of motion as follows:

V = u + at

Where;

V = final velocity (m/s)

U = initial velocity (m/s)

a = acceleration (m/s)

t = time (s)

Based on the provided information, v = 160m/s, u = 100m/s, a = 15m/s², t = ?

V = u + at

160 = 100 + 15t

160 - 100 = 15t

60 = 15t

t = 60/15

t = 4seconds.

Therefore, the time it takes for the plane to complete this increase in speed is 4s.