What is the acceleration at the apex of a vertical up and down problem?

Answer:

A)  d = 7.9267 km,  θ = 157.19

D) d = 35.17 km

Explanation:

For this exercise the easiest way is to decompose the vectors

Ship

X axis  (North)

The angle measured from the positive side of the x axis (unit vector i^ ) counterclockwise

           θ = 136- 136 = 224

           cos θ = x₁ / 13.9  

           x₁ = 13.9  cosc 224

           x₁ = - 9.9988 103 m

z axis

           sin 224 = z₁ / 13.9

           z₁ = 13.9 sin224

           z₁ = -9.6558 m

Axis y

            y₁ = 0

Helicopter

x-axis (North)

         θ = 360 - 152

         θ = 208

          cos θ = x₂ / 19.6

          x₂ = 19.6 cos 208

          x₂ = -17.3058 km

z axis

           sin 204 = z₂ / 19.6

           z₂ = 19.6 sin 204

           z₂ = -7.9720 km

Axis y

           y₂ = 2.57 km

It's a bit strange the way the axes give, but having the decomposition of the vectors we can answer the questions

A) They ask the displacement vector, let's start looking for the distance

            d = √ [(x₂-x₁)² + (y₂-y₁)² + (z₂-z₁)²]

we substitute

            d =√[(17.3058 - 9.9988)² + (2.57 - 0)² + (7.9720 -9.6558)²]

            d = √ [7.307² + 2.57² + 1.6838²]

            d = 7.9267 km

the angle of this vector is with respect to North (x-axis)

            cos θ = -7.307 / 7.9267  

            θ = cos⁻¹ (-0.9218)

            θ = 157.19

Y-axis elevation angle

           cos θ'= 2.57 / 7.9267

           θ’= cos⁻¹ (0.3242)

           θ’= 71.09

b) d = 7.9267 km

c) at this time the ship is sinking at constant speed, the sinking direction is the same vertical direction of the helicopter (y-axis)

          the distance is

               y₁ = v₁ t

let's reduce speed to km /h

              v₁ = 5.4 m / s (1km/1000m ) (3600s/1h)= 19.44 km /h

              y₁ = 19.44 t

the vector positions is

             d = √ [(x₂-x₁)² + (y₂-y₁)² + (z₂-z₁)²]

            d = √ [7.307² + (2.57 -19.44 t)² + 1.6838²]

in vertical angle is

          cos θ'= (2.57 -19.44t) / d

At an angle to the x axis is

         cos θ = -7.307 / d

d) let's evaluate the position for t = 1.90 h    

distance

       d = √ [7.307² + (2.57- 19.44 1.9)² + 1.6838²]

       d = √ [7.307² + (-34.366)² + 1.6838²]

       d = 35.17 km

Answer:

C i think

Explanation:

One consequence of Newton's third law of motion is that all actions have equal and opposite reactions. that means  net force on body is zero.

A force in physics is an effect that has the power to alter an object's motion. An object with mass can change its velocity, or accelerate, as a result of a force. An obvious way to describe force is as a push or a pull. A force is a vector quantity since it has both magnitude and direction.

Newton's third law states that when two bodies interact, they apply forces to one another that are equal in magnitude and opposite in direction.

If an object A exerts a force on object B, then object B must exert a force of equal magnitude and opposite direction back on object.

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Answer:

Be: Beryllium

C: Carbon

H: Hydrogen

He: Helium

Given parameters;

Time taken to complete a lap  = 8.667s

Radius of flower = 13.9cm

    convert to SI unit of m,  100cm = 1m

            13.9cm gives [tex]\frac{13.9}{100}[/tex]   = 0.139m

Unknown  = speed

To solve this problem, we need to first find the circumference of the flower.

 Circumference of the circular flower  = 2 π r

    where r is the radius of the flower;

           Circumference  = 2 x 3.142 x 0.139 = 0.87m

Now to find the how fast the bug is travelling,

   Speed  = [tex]\frac{distance}{time}[/tex]

Since the bug covered 1 lap, the distance is 0.87m

Now input the parameters and solve for speed;

    Speed  = [tex]\frac{0.87}{8.667}[/tex]  = 0.1m/s

The bug is travelling at a speed of  0.1m/s

Answer:

Series circuit:

The voltage that is measured across the circuit is different.

The current measured in a series circuit remains the same at all points in the circuit.

Parallel circuit:

The current measured across each resistor varies

The voltage measured across a parallel circuit will remain the same

Explanation:

Series and parallel circuits behave differently when it comes to the circulation of current and the interaction with a potential difference.

In a series circuit, the resistances are connected end to end. As a result, the voltage that is measured across the circuit is different once resistance is encountered. However, the current measured in a series circuit remains the same at all points in the circuit.

A parallel circuit behaves in an exactly opposite manner to the series circuit. In a parallel circuit, the resistances are connected side by side. As a result of this, the current measured across each resistor varies as there are circuit branches through which electric current can flow into. On the other hand, the voltage measured across a parallel circuit will remain the same

Answer:

t

Explanation:

Answer: true

Explanation:

Answer:

Explanation:

Frictional force acting on the box = mg cos 25 x μ where μ is coefficient of friction

= 2.4 x 9.8 x cos 25 x .51 = 10.87 N

Weight of the box acting along the incline = mg sin 25 = 9.94 N

Net force = 10.87 - 9.94 = .93 N . It will create a deceleration of .93 / 2.4

= .3875 m /s² in the box.

v² = u² - 2 a s

v = 0 , a = .3875 , s = 5.4 m

= = u² - 2 x .3875 x 5.4

u = 2.045 m /s

Answer:

We know that the resistance of a material is its length divided by its cross-sectional area and all that multiplied by its resistivity

Hence, resistance = ρ * length(in m) / Cross-sectional area  

(ρ = constant of resistivity)

If you do not understand cross-sectional area, comment on this answer

since both the wires are made of the same substance, both their resistivity will be the same

since we are told that both the wires have the same resistance,

(ρ * length 1) / cross-sectional area 1 = (ρ * length 2) / cross-sectional area 2

since they both have the same resistivity, both the ρ will cancel out

length 1 / cross-sectional area 1  = length 2 / cross-sectional area 2------(1)

Calculating the cross-sectional area

To simplify it , the cross-sectional area is the area of the circle you can currently see on either of the wire

let the radius of wire 1 = 2r

then, the radius of wire 2 = r

Cross-sectional area 1 = π (2r)^2 = 4πr^2

Cross-sectional area 2 = π (r)^2

Now, using these values in (1)

l / 4πr^2 = l' / πr^2

l / l' = 4πr^2/πr^2

l / l'  = 4 / 1

the length of rod 'P' is l

from the equation, we can simplify:

l (length of rod 'P') = 4 l'(length of rod 'Q')

Therefore, we can say that the length of rod 'P' is 4 times the length of rod 'Q'

Answer:

the magnitude of the linear acceleration is  [tex]=1.995 \,\,cm/s^2\\[/tex]

Explanation:

Recall that the linear acceleration (a) is associated with the angular acceleration vi the formula:  

[tex]a=R\,\alpha[/tex]

where R stands for the radius of the rotational motion (in our case 2.1 cm/2 = 1.05 cm, and [tex]\alpha[/tex] stands for the angular acceleration in radians per units of time squared.

Then the linear acceleration in our case is:

[tex]a=R\,\alpha\\a=1.05 cm * (1.9\,\,\,rad/s^2)\\=1.995 \,\,cm/s^2[/tex]

Explanation:

Environmental science is the pursuit of knowledge about the workings of the environment and our interactions with it. Environmentalism is a social movement dedicated to protecting the natural world. Nature makes resources at similar speeds

Answer:

Explanation:

2.1 km = 2100 m

1.68 km = 1680 m

a ) Time taken by wild beast to travel 1680 m

= 1680 / 19 = 88.42 s

Time taken by wild beast to travel 2100 m

2100 / 19 = 110.52 s

distance travelled by chicken in 88.42 s

= 88.42 x 3.3 = 291.78 s

Its distance from the end point

= 2100 - 291.78 = 1808.22m

b ) Time taken by chicken to travel 2100 m

= 2100 / 3.3 = 636.36 s

Both reach simultaneously so , time of resting by wild beast

= 636.36 - 110.52 = 525.84 s .

Answer:

A force is any interaction that, when unopposed, will change the motion of an object

Explanation:

Answer:

a. 17.34 s. b. 104.51 m c. -7.16 m/s²

Explanation:

a. The distance, d moved by the car at constant speed v = 6.00 m/s in time t which they collide is d = vt. The distance d' moved by the bus from its initial position 70 m away from the car with a constant velocity u = 28.0 m/s and deceleration a = -3.00 m/s² is d' = 70 + ut + 1/2at².

At collision, s = d

vt = 70 + ut + 1/2at²

substituting the values of the variables, we have

6t = 70 + 28t + 1/2(-3)t²

6t = 70 + 28t - 1.5t²

collecting like terms, we have

1.5t² + 6t - 28t - 70 = 0

1.5t² - 22t - 70 = 0

using the quadratic formula to find t, we have

[tex]t = \frac{-(-22) +/- \sqrt{(-22)^{2} - 4 X -70 X 1.5} }{2 X 1.5} \\t = \frac{22 +/- \sqrt{484 + 420} }{3} \\\\t = \frac{22 +/- \sqrt{904} }{3} \\\\t = \frac{22 +/- 30.01 }{3} \\\\t = \frac{22 - 30.01 }{3} or \frac{22 + 30.01 }{3} \\t = \frac{-8.01 }{3} or \frac{52.01 }{3} \\\\t = -2.67 s or 17.34 s[/tex]

We take the positive value.

So t = 17.34 s.

So, 17.34 s elapses before the bus and car collide.

b. Since the distance covered by the bus is d' = 70 + ut + 1/2at², this is how far down the road the collision occurs.

Substituting the values of the variables, we have

d' = 70 + 28 m/s × 17.34 s + 1/2(-3 m/s²)(17.34)²

d' = 70 + 485.52 - 451.01

d'= 104.51 m

c. To just avoid the collision, the bus must decelerate in the distance of 104.51 m from the car to the speed of the car. So using

v² = u² + 2ad' where v = 6.00 m/s, u = 28.0 m/s and d' = 104.51 m

the acceleration is thus

a = (v² - u²)/d'

a = ((6 m/s)² - (28 m/s)²)/104.51 m

a = (36 m²/s² - 784 m²/s²)/104.51 m

a = -748 m²/s² ÷ 104.51 m

a = -7.16 m/s²

Answer:

all are social influences

Answer: 100

Explanation:

Answer:

The physical properties is hardness shape and color, I choose hardness because I have grabbed bowling balls before and they are very hard well there could be different types of bowling balls made of different things but I have never seen one or toughed a bowling ball that is not hard. Another physical property  I chose for the bowling ball was shape, The reason I chose shape was because the bowling ball is circle, the actual name for a 3-D circle is sphere. The last physical property for a bowling ball is color because mostly all bowling balls have color for example the one in the picture it is red with a little bit of pink, there is many different bowling balls that have different color different hardness but NOT different  shape. That is the physical properties of a bowling ball.

Explanation:

Answer: The bowling ball is round in shape and red in color. The bowling ball is smooth and hard.

Explanation:

did it on edge

Answer:

Lightning

Explanation

Answer:

Its northeast. Just took the exam.

Explanation:

Answer:

See image

Explanation:

Plato

Answer:

Explanation:

Given that:

p = 6.17 × 10⁻³⁰ Cm

Electric field E = 94.7 × 10⁻⁶ N/C

Then:

[tex]U= -p^{\to} *E^{\to}[/tex]

[tex]U_i = -pE \ cos180^0 =pE \\ \\ U_f = -pE \ cos 0^0 = -pE[/tex]

∴

[tex]\Delta U = U_i - U_f = 2pE \ \ per \ dilute/per \ switch[/tex]

This implies that one switch of dipole produces 2pE energy to be deposited in the water.

mass of water = 13.1 g

The number of water molecule = [tex]\dfrac{mass}{molar \ mass}\times N_A[/tex]

=[tex]\dfrac{13.1}{18.015}\times6.023 \times 10^{23}[/tex]

= 4.38 × 10²³ molecules of water.

∴ Number of dipoles = 4.38 × 10²³

The total number of switches in 2.39  sec = switch frequency × 2.73

Number of switches = 2.39 × 3.42 × 10⁸

Number of switches = 817380000

Number of switches = 8.174  × 10⁸

The total energy Q deposited = Energy deposited per dipole × Number of dipole × no of switches

Q = (2pE) × 4.38 × 10²³ × 8.174  × 10⁸

Q = (2 × 6.17 × 10⁻³⁰ × 94.7 × 10⁻⁶  × 4.38 × 10²³ × 8.174  × 10⁸ )

Q = 0.41838 J

Answer:

Compaction and cementation

Explanation:

Cementation: As ions are deposited by fluids to form a compound that hardens loose sedimentary rocks.

Compaction: As the density of sedimentary rocks on edge of them are forced together through sediments.

Answer:

number 2 is correct

Explanation:

cementation as icons are deposited by fluids to form a compound that hardens looses sedimentary rocks .

compaction is the density of sedimentary rocks on edge of them, are forced together though sediments mark me brainest add and follow me

Answer:

We use electrolysis to prevent a material from rusting,

The metal forms a coating around the material and hence prevents any contact between the material and the environment

This process also gives us the physical strength of the material and the aesthetic properties of the coated metal

the metal commonly used to coat the object is Zinc and the process is called galvanisation

If the ball is dropped with no initial velocity, then its velocity v at time t before it hits the ground is

v = -g t

where g = 9.80 m/s² is the magnitude of acceleration due to gravity.

Its height y is

y = 40 m - 1/2 g t²

The ball is dropped from a 40 m height, so that it takes

0 = 40 m - 1/2 g t²

==>  t = √(80/g) s ≈ 2.86 s

for it to reach the ground, after which time it attains a velocity of

v = -g (√(80/g) s)

==>  v = -√(80g) m/s ≈ -28.0 m/s

During the next bounce, the ball's speed is halved, so its height is given by

y = (14 m/s) t - 1/2 g t²

Solve y = 0 for t to see how long it's airborne during this bounce:

0 = (14 m/s) t - 1/2 g t²

0 = t (14 m/s - 1/2 g t)

==>  t = 28/g s ≈ 2.86 s

So the ball completes 2 bounces within approximately 5.72 s, which means that after 5 s the ball has a height of

y = (14 m/s) (5 s - 2.86 s) - 1/2 g (5 s - 2.86 s)²

==>  (i) y ≈ 7.5 m

(ii) The ball will technically keep bouncing forever, since the speed of the ball is only getting halved each time it bounces. But y will converge to 0 as t gets arbitrarily larger. We can't realistically answer this question without being given some threshold for deciding when the ball is perfectly still.

During the first bounce, the ball starts with velocity 14 m/s, so the second bounce begins with 7 m/s, and the third with 3.5 m/s. The ball's height during this bounce is

y = (3.5 m/s) t - 1/2 g t²

Solve y = 0 for t :

0 = (3.5 m/s) t - 1/2 g t²

0 = t (3.5 m/s - 1/2 g t)

==>  (iii) t = 7/g m/s ≈ 0.714 s

As we showed earlier, the ball is in the air for 2.86 s before hitting the ground for the first time, then in the air for another 2.86 s (total 5.72 s) before bouncing a second time. At the point, the ball starts with an initial velocity of 7 m/s, so its velocity at time t after 5.72 s (but before reaching the ground again) would be

v = 7 m/s - g t

At 6 s, the ball has velocity

(iv) v = 7 m/s - g (6 s - 5.72 s) ≈ 4.26 m/s

When you draw all 4 of those moves, you see that he winds up 9m North and 11m West of where he started.

So the magnitude of his displacement is

D = √(9² + 11²)  m²

D = √(81 + 121)  m²

D = √(202)  m²

D = 14.2 m

The direction is arctan(-11/9) = 50.7° west of North

Answer:

No energy

Explanation:

Answer:

Mass is the quantitative measure of inertia of any object.

Explanation:

The object that have largest mass will   have largest inertia as well as largest momentum.

The amount of water affects the mass and the height of the plants.

The correct conclusion is the conclusion which the data obtained supports.

Plants need both water and sunlight to grow.

The variation the amount of water or sunlight that a plant receives will affect the growth rate of the plant.

Based on the data obtained from the experiment where Pots A and B both have plain soil, bean seeds, and the same amount of light, while Pot B receives more water, the amount of water affects the mass and the height of the plants.

In conclusion, plants need both water and sunlight for growth.

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Answer: 12,000 Newton’s

Explanation: multiply by the number of cars the 200 kg.

The force exerted on the roller coaster to bring it to stop is 12000 N.

Given data:

The magnitude of acceleration of car is, [tex]a = 15 \;\rm m/s^{2}[/tex].

The mass of each car is, m = 200 kg.

As per the Newton's second law, the force is given as the product of acceleration and the mass of object. Then the force exerted on each car is,

F = ma

And the force exerted on the roller coaster is,

F' = 4F

F' = 4ma

Solving as,

[tex]F' = 4 \times 200 \times 15\\\\F' = 12000\;\rm N[/tex]

Thus, we can conclude that the force exerted on the roller coaster to bring it to stop is 12000 N.

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