What is the acceleration of gravity on Earth?

Answer:

200N ;)

Explanation:

Answer:

200N

Explanation:

Answer:

conduction

Explanation:

Answer:

Velocity Has vector Quantity

Answer:

b. The force exerted by the piston on the object is less than F because the piston is accelerating downward.

Explanation:

Given that object exerts a downward force F on the piston that accelerates the piston downward.

An object can accelerate if the net force acting on it is non-zero.

Here, the piston is acceleration in the downward direction, so the net for on the piston is in the downward direction.

Force due to object, F, is in the downward direction while the force exerted by the piston on the object is in the upward direction.

As the acceleration of the piston is in the downward direction, so the downward force is more.

Therefore, the force exerted by the piston on the object is less than F because the piston is accelerating downward.

Hence, option (b) is correct.

Answer:

kdfjnfkasd

Explanation:

Answer:

A. Force of friction

Explanation:

Find the diagram attached

From the diagram we can see that the force B is acting up on the body along the plane. This force is the force that prevents the body from sliding down the plane. Originally, the body on the line will tend to slide down the incline even without application of a force hence the reason of an opposing force that must act in the opposite direction is counter this motion to make the body be in a state of equilibrium. Hence the required force is force of friction since it is am opposing force acting in the direction opposite to the moving force acting on the body.

The box is accelerated from rest to 4 m/s in a matter of 2.5 s, so its acceleration a is such that

4 m/s = a (2.5 s)   →   a = (4 m/s) / (2.5 s) = 1.6 m/s²

Then the force applied to the box has a magnitude F such that

F = (10 kg) (1.6 m/s²) = 16 N

Answer:

Explanation:

To convert Celsius to Fahrenheit, use the following formula;

= (°C * 9/5) + 32

= (453 * 9/5) + 32

= 847.4 °F

To convert Celsius to Kelvin, use the following;

= °C + 273.15

= 453 + 273.15

= 726.15K

Answer:

The processes of photosynthesis and respiration are interrelated because the products of such processes are used as reactants for one process. One product of photosynthesis is oxygen. This oxygen is used in the process of respiration as a reactant producing carbon dioxide which is used as a reactant for photosynthesis.

Answer:

-15J

Explanation:

Step one:

given data

m1= 1.2kg

v1= 5 m/s

m2= 4.8kg

v2= 0 m/s

Required

The kinetic energy lost

Step two:

The kinetic energy before impact is KE1

[tex]KE1= 1/2mv^2\\\\KE1= 1/2*1.2*5^2\\\\KE1= 15J[/tex]

KE after impact is KE2

[tex]KE2= 1/2*(m1+m2)v2\\\\KE2= 1/2*(6)0\\\\KE2= 0 J[/tex]

The loss in Kinetic energy is

Loss in KE= KE2-KE1

Loss in KE= 0-15

Loss in KE= -15J

Answer: it’s actually C, electrical to magnetic

Explanation:

Answer:

 v = 1.078 10⁴ m / s

Explanation:

To solve this exercise we can use conservation of mechanical energy

Starting point. Just clearing

          Em₀ = K + U = ½ m v² - G m M / [tex]R_{e}[/tex]

Final point. At r = 14R_{e}

        Em_{f} = U = -G m M / 14R_{e}

how energy is conserved

         Em₀ = [tex]Em_{f}[/tex]

         ½ m v² - G m M /R_{e} = -G m M / 14R_{e}

        ½ v² = G M / R_{e} (-1/14 + 1)

        v² = 2 G M / R_{e} 13/14

we calculate

       v² = 2 6.67 10⁻¹¹ 5.98 10²⁴ / 6.37 10⁶ 13/14

       v = √ (1,16 10⁸)

       v = 1.078 10⁴ m / s

The launch speed of a projectile that rises above the earth will be

v = 1.078 10⁴ m / s

Speed is defned as the movement of any object with respect to the time the formula of speed is given as the ratio of the distance with time.

To solve this exercise we can use conservation of mechanical energy

Starting point. Just clearing

[tex]E_{mo} = K + U = \dfrac{1}{2}m v^2 - \dfrac{G m M} { r}[/tex]

Final point. At[tex]r = 14R_{e}[/tex]

 [tex]Em_{f} = U = \dfrac{-G m M }{14R_{e}}[/tex]

how energy is conserved

 [tex]E_{mo }= \dfrac{1}{2} m v^2 -\dfrac{-G m M }{R_{e}} = \dfrac{-G m M }{ 14R_{e}}[/tex]

  [tex]\dfrac{1}{2} v^2 = \dfrac{G M }{ R_{e} (\dfrac{-1}{14} + 1)}[/tex]

    [tex]v^2 = \dfrac{2 G M} { R_{e} \dfrac{13}{14}}[/tex]

we calculate

[tex]v^2 = \dfrac{2 6.67 \times10^{-11}\times 5.98 \times 10^{24}} { 6.37 \times 10^{6} \times \dfrac{13}{14}}[/tex]

  [tex]v = \sqrt{ (1,16\times 10^8)}[/tex]

  v = 1.078 10⁴ m / s

Hence the launch speed of a projectile that rises above the earth will be

v = 1.078 10⁴ m / s

To know more about speed follow

https://brainly.com/question/4931057

Answer:

The value is  [tex]u = 3.23 *10^{7} \ m/s[/tex]

Explanation:

From the question we are told that

   The diameter of the nucleus is [tex]d = 5.50 \ fm = 5.50 *10^{-15} \ c[/tex]

   The charge of the proton that makes up the nucleus is  [tex]Q_2 = \frac{12}{2} * 1.60 *10^{-19} =9.6*10^{-19} \ C[/tex]

    The energy to be impacted is  [tex]KE_f = 2.30 \ MeV = 2.30 *10^{6} \ eV = 2.30 *10^{6} * 1.60 *10^{-19} = 3.68*10^{-13} \ J[/tex]

Generally the radius of the nucleus is mathematically represented as

         [tex]r = \frac{d}{2}[/tex]

=>      [tex]r = \frac{5.50 *10^{-15}}{2}[/tex]

=>      [tex]r = 2.75 *10^{-15} \ m[/tex]

Generally from the law energy conservation we have that

     [tex]Initial \ total \ energy \ of the \ proton = final \ total \ energy \ of the \ proton[/tex]

i.e

    [tex]T_i = T_f[/tex]

Here

   [tex]T_i = KE_i + PE_i[/tex]

Here [tex]KE_i[/tex] is the initial kinetic energy which is mathematically represented as

       [tex]KE_I = \frac{1}{2} * m * u ^2[/tex]

Here  [tex]PE_i[/tex] is the initial potential energy of the proton and the value is  0 J given that the proton is moving

Also  [tex]T_f[/tex] is mathematically represented as

         [tex]T_f = KE_f + PE_f[/tex]

Here  

        [tex]PE_f[/tex]  is the final potential energy which is mathematically represented as

         [tex]PE_f = \frac{k * Q_1 * Q_2}{r}[/tex]

Here [tex]Q_1[/tex] is the charge on the proton with a value of [tex]Q_1 = 1.60 *10^{-19} \ C[/tex]

So

        [tex]PE_f = \frac{9*10^{9} *(1.60 *10^{-19} ) * ( 9.6 *10^{-19})}{ 2.75 *10^{-15}}[/tex]

=>     [tex]PE_f = 5.027 *10^{-13 } \ J[/tex]

So  

         [tex]KE_i + PE_i = KE_f + PE_f[/tex]

=>       [tex]\frac{1}{2} * m * u ^2 +0 = 3.68*10^{-13} + 5.027 *10^{-13 }[/tex]

Here m is the mass of the moving proton with value [tex]m = 1.67*10^{-27} \ kg[/tex]

So

       [tex]\frac{1}{2} * 1.67*10^{-27} * u ^2 +0 = 3.68*10^{-13} + 5.027 *10^{-13 }[/tex]

=>      [tex]u = \sqrt{\frac{3.68*10^{-13} + 5.027 *10^{-13 }}{0.5 * 1.67*10^{-27}} }[/tex]

=>       [tex]u = 3.23 *10^{7} \ m/s[/tex]

Answer:

Traveling 381m in 5 seconds means the average velocity is: 381m/5s = 76.2 m/s.

Explanation:

Letting x be the initial velocity and v the final velocity, we have:

12(x+v)=76.2m/s

and (since v=x+50),

12(2x+50)=76.2m/s

x+25=76.2m/s

x=51.2m/s

Answer:

-49 m/s

Explanation:

You would use the formula vf = vi + at, where vf stands for final velocity, vi stands for initial velocity, a stands for acceleration, and t stands for time. Assuming you're dropping the marble on Earth, the acceleration would be -9.8m/s², and the final velocity would be 0 m/s, as it stops after hitting the ground. (0 = vi + (9.8)(5))

Answer:

the answer is A!! 2560 J

Answer:

[tex]\frac{dV}{dt}= \frac{\pi d^2}{4}v[/tex]

Explanation:

The rate of volume flow out of tank can be expressed as:

[tex]\frac{dV}{dt} = A\frac{dL}{dt}[/tex]

where,

dV/dt = Volume flow rate

A = Cross-sectional area of outlet = πd²/4

d = diameter of circular outlet

dL = Displacement covered by water

dt = time taken

but we know that:

Velocity = υ = displacement/time = dL/dt

Substituting the values of "dL/dt" and "A" in the equation, we get:

[tex]\frac{dV}{dt} = \frac{\pi d^2}{4}v[/tex]

This is the expression for volume flow rate dV/dt, on terms pf v, d.

Answer:

You can determine if the ship is moving by lying down and measuring your height.

Explanation:

Answer:

your answer is some

Explanation:

just so you know i took the test and i got an 80% on edge

Answer:

Pulley = Flag Pole

Screw = Side latch

Wedge = Scissors

Wheel and axle = Car

Answer:

double replacement

Explanation:

sorry if im wrong

Answer:

The ball needs approximately [tex]0.41\; \rm s[/tex] to reach that height for the first time.

Explanation:

The initial speed of the ball [tex]17.7\; \rm m \cdot s^{-1}[/tex]. However, what would be the initial vertical speed of this ball?

The angle of elevation is [tex]\theta = 49.8^\circ[/tex]. Consider the initial speed of this ball as the length of the hypotenuse of a right triangle. If the angle of elevation is one of the two acute angles of this triangle, the initial vertical speed of this ball would be the leg opposite to that angle.

[tex]\displaystyle \sin \theta = \frac{\text{opposite}}{\text{hypotenuse}}[/tex].

[tex]\displaystyle \sin \theta = \frac{v(\text{vertical, initial})}{v(\text{initial})}[/tex].

Therefore:

[tex]\begin{aligned}&v(\text{vertical, initial})\\ &= v(\text{initial}) \cdot \sin\theta \\ &= 17.7\; \rm m \cdot s^{-1} \times \sin \left(49.8^\circ\right) \approx 13.5\; \rm m \cdot s^{-1}\end{aligned}[/tex].

Let [tex]t[/tex] denote the time (in seconds) required for the ball to reach a height of [tex]4.7\; \rm m[/tex].

Let [tex]g[/tex] denote the acceleration because of gravity (typically [tex]g \approx 9.81\; \rm m \cdot s^{-2}[/tex] near the surface of the earth.) The height of the ball [tex]t[/tex] seconds after it was thrown would be: [tex]\displaystyle \frac{1}{2}\, g \cdot t^{2} + v(\text{vertical, initial}) \cdot t[/tex].

Assume that [tex]g \approx 9.81\; \rm m \cdot s^{-2}[/tex]. Set the value of this expression for height to [tex]4.7\; \rm m[/tex] and solve for [tex]t[/tex]:

[tex]\displaystyle \frac{1}{2} \times 9.81 \, t^{2} + 13.5 \, t = 4.7[/tex].

Either [tex]t \approx 0.41[/tex] or [tex]t \approx 2.3[/tex] will satisfy this equation. Both of these two values are reasonable. The first value for [tex]t[/tex] ([tex]0.41\; \rm s[/tex]) is the time required for the ball to reach a height of [tex]4.7\; \rm m[/tex] for the first time. The second value ([tex]2.3\; \rm s[/tex]) is the time required for the ball to come under that height on its way back to the ground. The question seems to be asking only for the first (the smaller one) of these two times.

The acceleration of the object if the net force is decreased = 0.13 m/s²

Given

A net force of 0.8 N acting on a 1.5-kg mass.

The net force is decreased to 0.2 N

Required

The acceleration of the object if the net force is decreased

Solution

Newton's 2nd law :

[tex]\tt \sum F=m.a[/tex]

The mass used in state 1 and 2 remains the same, at 1.5 kg

ΣF=0.8 N

m=1.5 kg

The acceleration, a:

[tex]\tt a=\dfrac{\sum F}{m}\\\\a=\dfrac{0.8}{1.5}\\\\a=0.53`m/s^2[/tex]

ΣF=0.2 N

m=1.5 kg

The acceleration, a:

[tex]\tt a=\dfrac{\sum F}{m}\\\\a=\dfrac{0.2}{1.5}\\\\a=0.13~m/s^2[/tex]

Answer:

A spring scale shows a net force of 0.8 N acting on a 1.5-kg mass. What happens to the acceleration of the object if the net force is decreased to 0.2 N? A, The acceleration decreases to a quarter of its original value, or about 0.13 m/s².

Answer:

v = [tex]\sqrt{2gh}[/tex]

the speed in the two planes will be the same since it does not depend on the angle of the same

Explanation:

In this exercise we are told that the two inclined planes have no friction force, so we can apply the conservation of energy for each one, we will assume that the initial height in the two planes is the same

starting point. Highest part of each plane

         Em₀ = U = m g h

final point. Lowest part of each plane

        [tex]Em_{f}[/tex] = K = ½ m v²

as there is no friction, the mechanical energy is preserved

          Em₀ = Em_{f}

          mg h = ½ m v²

          v = [tex]\sqrt{2gh}[/tex]

As we can see, the speed in the two planes will be the same since it does not depend on the angle of the same

Answer:

They can figure out when the person died, possibly the nature of crime, it can also detect if the body was moved in certain area.

Explanation:

Answer:the nucleus controls and regulates the activities of the cell

Explanation:trust me bro

Answer:

The nucleus controls and regulates the activities of the cell and carries the genes, structures that contain the hereditary information.

Answer:

Q = 4.52 10¹⁷ J

Explanation:

Thermal energy can be calculated with  

      Q = m c_{e} ΔT

in this case it indicates that we approximate seawater to pure water with  

    c_{e} = 4186 J/ kg K  

with the density

    ρ = m / V  

    m = ρ V  

    V = L³  

we substitute  

   m = ρ L³  

   Q = ρ L3 c_{e} ΔT

calculate  

   Q = 1000 (3 103) 3 4186 4  

   Q = 4.52 10¹⁷ J

Answer:

The frequency of the second harmonic ([tex]2f_o[/tex]) is 11.97 Hz.

Explanation:

Given;

mass of the string, m = 25 g = 0.025kg

tension on the string, T = 43 N

length of the string, L = 12 m

The speed of wave on the string is given as;

[tex]v = \sqrt{\frac{T}{\mu} }[/tex]

where;

μ is mass per unit length = 0.025 / 12 = 0.002083 kg/m

[tex]v = \sqrt{\frac{43}{0.002083} }\\\\v = 143.678 \ m/s[/tex]

The wavelength of the first harmonic wave is given as;

[tex]L = \frac{1}{2} \lambda _o\\\\\lambda _o = 2L \\\\\lambda _o = 2 \ \times \ 12\\\\\lambda _o = 24 \ m[/tex]

The frequency of the first harmonic is given as;

[tex]f_o = \frac{v}{\lambda _o} = \frac{v}{2L} = \frac{143.678}{24} = 5.99 \ Hz\\\\[/tex]

The wavelength of the second harmonic wave is given as;

[tex]L = \lambda_1 \\\\\lambda_1 = 12 \ m[/tex]

The frequency of the second harmonic is given as;

[tex]f_1 = \frac{v}{\lambda _1} = \frac{143.678}{12} = 11.97 \ Hz = 2(\frac{v}{\lambda _0}) = 2f_o[/tex]

Therefore, the frequency of the second harmonic ([tex]2f_o[/tex]) is 11.97 Hz.

Answer: no other source

Explanation:

The Earth gets energy from the sun which includes both heat and light and these are necessary for chemical reaction.

When the energy from the Sun gets to the Earth, they come as solar radiation and included in such solar radiation are infrared, invisible light, X-rays, ultraviolet light, radio waves, and gamma rays.

We should note that no other source is required for the Earth to get energy. The sun supplies it its energy.

Answer:

True

Explanation:

When it's turn off, chemical energy is stored (the battery) in the flashlight, when it's turn on the chemical energy transfers into light and thermal energy.