Answer:
GO over the work that the teacher gave you and use Quizlet to help study the work. It works for me
Step-by-step explanation:
Step-by-step explanation:
Study and play, or u can say hav fun while studying.
Eat healthy food and light food.
Play some music at the background for concentration.
Take 10 min break.
These are the things which i do
Hope they are helpful to you if yes then please let me
Stay safe, stay healthy and blessed.
Have a great day !
Thank you
A student answers
92
%
of questions on a test before the end of class bell rings. If the student answers
46
questions before the end of class, how many questions are on the whole test?
Answer:
50 questions
Step-by-step explanation:
Given the following question:
92% of 50
To find the answer we have to use the formula to calculate percentage.
[tex]\frac{p\times n}{100}[/tex]
[tex]\frac{92\times50}{100} =92\times50=4600\div100=46[/tex]
[tex]=46[/tex]
Which means in total there was "50 questions" on the test.
Hope this helps.
Convert polar equation to the standard form of each rectangular equation: θ=-135
x - y = 0 is the standard form of the polar equation θ = -135
[tex]\sf \theta \ =-135[/tex]
we should know tan(-135) is 1[tex]\rightarrow \sf tan(\theta) \ =tan(-135)[/tex]
[tex]\rightarrow \sf tan(\theta) \ =1[/tex]
[tex]\rightarrow \sf \dfrac{y}{x} \ = 1[/tex]
[tex]\rightarrow \sf y =x[/tex]
[tex]\rightarrow \sf x -y = 0[/tex]
[tex]\\ \rm\Rrightarrow \theta=-135[/tex]
[tex]\\ \rm\Rrightarrow tan\theta=tan(-135)[/tex]
[tex]\\ \rm\Rrightarrow \dfrac{Perpendicular}{Base}=tan(-\dfrac{3\pi}{4})[/tex]
Perpendicular is y and base is x[tex]\\ \rm\Rrightarrow \dfrac{y}{x}=1[/tex]
[tex]\\ \rm\Rrightarrow y=x[/tex]
Convert to standard form Ax+By+C=0[tex]\\ \rm\Rrightarrow x-y=0[/tex]
Factor completely 36x2 − 25. (6x − 5)(x 5) (6x 5)(6x 5) (6x − 5)(6x − 5) (6x 5)(6x − 5).
The complete factor of the polynomial 36x² - 25 is (6x + 5)(6x − 5). Then the correct option is D.
What is polynomial?Polynomial is an algebraic expression that consists of variables and coefficients. Variable are called unknown. We can apply arithmetic operations such as addition, subtraction, etc. But not divisible by variable.
Factor completely 36x² - 25.
We know that
[tex]\rm a^2 - b^2 = (a+b)(a-b)[/tex]
(6x)² − 5²
(6x + 5)(6x − 5)
The complete factor of the polynomial 36x² - 25 is (6x + 5)(6x − 5). Then the correct option is D.
More about the polynomial link is given below.
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A shop sells 2 brands of sunflower seeds. Brand A’s package is in the shape of a cone with radius 2.5 centimeters and height 10 centimeters. Brand B’s package is in the shape of a square prism. The prism’s height is 2.5 centimeters, and each side of the base measures 5 centimeters.
HELPPPPPP
Which package contains more seeds? Explain or show your reasoning.
The package that contains more seed is brand b's package.
Which seed contains more seed?In order to determine which package contains more seeds, the volume of each package has to be determined.
The volume of brand A's package = 1/3(nr^2h)
n = 22/7r = radius h = height1/3 x 2.5^2 x 10 x 22/7 = 65.48
The volume of brand b's package = 2.5 x 5 x 5 = 62.5
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The probability of spinning a 3 and flipping heads is
bro I thought I had the right answer but I didn't so I'm now contemplating my life's decisions
(GIVING 30 POINTS!!) Find the discriminant for the following equation: 3x^2 + 4x = 2 Question 3 options: 8 -8 40 -40
Answer:
are you sure?
Step-by-step explanation:
hind ko alm yan eh HAHAHAHA
HELP I NEED THIS ASAP ILL GIVE BRAINLIST
Answer:
um there's nothing there I don't see it?
Answer:
What help
Step-by-step explanation:
_______________________
5. I am a number that tells how many times the base is used as a factor.
What is the exact value of cotangent (StartFraction 3 pi Over 4 EndFraction)? –1 Negative StartRoot 2 EndRoot 1 StartRoot 2 EndRoot.
By using a trigonometric table, we will see that:
cotangent(3pi/4) = -1
How to find the value of the cotangent?We want to find:
cotangent(3pi/4)
This is equal to:
[tex]\frac{cos(3pi/4)}{sin(3pi/4)}[/tex]
We can use a table to evaluate these two, we know that:
cos(3pi/4) = -√2/2
sin(3pi/4) = √2/2
Then:
[tex]\frac{cos(3pi/4)}{sin(3pi/4)} = \frac{-\sqrt{2}*2 }{\sqrt{2}*2 } = -1[/tex]
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A person 2 m tall casts a shadow 10 m long. At the same time, a building casts a shadow 80 m long. How tall is the building ?
Answer:
The building is 16 m tall.
Step-by-step explanation:
x/2 = 80/10
10x=160
10x/10 = 160/10
x=16
Answer:
this is a ratio question. The answer is 16 m
Step-by-step explanation:
The persons height to shadow length ratio is 2 : 10
We want to know what the height of the building is when the shadows length is 80.
Let H represent height:
Persons ratio:
2 : 10
Buildings ratio:
H : 80
In other words for every 2 meters height a 10 m shadow is casted so we want to know how many of this ratio can fit into the building:
Let’s find the equivalent ratio:
80/10=8
That means 8 of the persons ratio makes up the building. Let’s find the height of building by 2*8=16.
therefore the building is 16m tall.
If A=1/2bxh, find A when b=4.5 and h=5.2
Answer:
A = 11.7
Step-by-step explanation:
Just substitute the known values into the equation:
[tex]A=\frac{1}{2}(4.5)(5.2)\\A=11.7[/tex]
A player chooses one card from Deck A and one card from Deck B. What is the probability that the player will choose a C2 card from the first deck or a C6 card from the second deck?
The probability of choosing a C3 card from Deck A or choosing a C5 card from Deck B is
(Use a simplified fraction to represent the probability).
Probabilities are used to determine the chances of events
The probability that the player will choose a C2 card from the first deck or a C6 card from the second deck is 17/42The probability that the player will choose a C3 card from the first deck or a C5 card from the second deck is 9/14How to calculate the probabilityThere are 4 C2 cards in the first deck out of a total of 12 cards, and there are 3 C6 cards in the second deck out of a total of 14 cards.
So, the probability that the player will choose a C2 card from the first deck or a C6 card from the second deck is:
[tex]P = \frac{4}{12} + \frac{3}{14}[/tex]
Simplify
[tex]P = \frac{1}{3} + \frac{3}{14}[/tex]
Take the LCM
[tex]P = \frac{14 + 3}{42}[/tex]
[tex]P = \frac{17}{42}[/tex]
Also;
There are 3 C3 cards in the first deck out of a total of 12 cards, and there are 4 C5 cards in the second deck out of a total of 14 cards.
So, the probability that the player will choose a C3 card from the first deck or a C5 card from the second deck is:
[tex]P = \frac{3}{12} + \frac{4}{14}[/tex]
Simplify
[tex]P = \frac{1}{4} + \frac{2}{7}[/tex]
Take the LCM
[tex]P = \frac{4 + 14}{28}[/tex]
[tex]P = \frac{18}{28}[/tex]
[tex]P = \frac{9}{14}[/tex]
Hence, the probability that the player will choose a C3 card from the first deck or a C5 card from the second deck is 9/14
Read more about probabilities at:
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]Aisha has 5 candies. If Ken has 8 times as many candies as Aisha, which number sentence shows how many candies Ken has?
A.
5 × 5 = 25
B.
8 × 5 = 40
C.
8 + 5 = 13
Answer:
[B]8 × 5 = 40
Step-by-step explanation:
Aisha has 5 candies. If Ken has 8 times as many candies as Aisha.
8 Times = Multiply.
Therefore, we can get rid of Answer choice [C]
Now, We know that Aisha have 5 candies and ken has 8 times as many therefore, equation =
5 * 8 = 40
which given us.
[B] 8 * 5 = 40 is the correct Answer.
[RevyBreeze]
Which expression is equivalent to x² + 10x+ 24?
Answer:
(x+4) (x+6)
Step-by-step explanation:
use backwards foil
two numbers that add up to 10 and multiply to 24 are 6 and 4
both signs are positive so you will be adding
Answer:
(x+4) (x+6)
Step-by-step explanation:
Find 2 numbers that added = 10 and multiplied =24
(6 &4) 6+4 = 10 6x4 = 24
=x²+10x+24
=(x²+6x)+(4x+24)
=x(x+6)+4(x+6)
=(x+4)(x+6)
i need the anser to this question
Answer:
x = 4
Step-by-step explanation:
4/4 = 1 1 + 8 = 9 9x2 = 18 give me brainliest pls
Answer:
its my alt ima give u
Step-by-step explanation:
if two objects have the same weight dors the gravitational feild strength effect the mass
(x^2 times x^3)^3
Some body please help me
[tex] = (x^2 \times x^3)^3 \\ = x {}^{6} \times {x}^{9} \\ = (x) {}^{6 + 9} \\ = {x}^{15} [/tex]
4x+5t = 22
5x - t = 13
what is x and t
Answer:
5(5x-t)
=13×5
25x - 5t
=65
25x -5t + 4x +5t
=65 + 22
29x
= 87
x
= 87÷29
x =3
substituting x=3 in 5x-t=13
15- t
=13
15 - 13
= t
t = 2
Step-by-step explanation:
[tex] \frac{7}{8} \times \frac{2}{4} = [/tex]
what is the answer
Answer:
7/16
Step-by-step explanation:
[tex]\dfrac78 \times \dfrac24=\dfrac{7 \times 2}{8 \times 4}=\dfrac{14}{32}=\dfrac{7}{16}[/tex]
Please help I don’t get it!!!
3(-x+2)
Answer:
-3x + 6
Step-by-step explanation:
Distribute the 3 across the parentheses, like you are multiplying. 3 x (-x) = -3x and 3 x 2 = 6. Then write as an expression.
Write an addition equation or a subtraction equation (your choice!) to describe the diagram.
Which is a factor of x2 8x – 48? (x – 6) (x 4) (x – 16) (x 12).
The factors of the equation are [tex]\rm (x+12)(x-4)[/tex]
What are the factors?
Factorization of an algebraic expression means writing the given expression as a product of its factors.
These factors can be numbers, variables, or an algebraic expression.
Given
The equation is
[tex]\rm x^2+8x-48[/tex]
The factors of the equation are given by;
[tex]\rm x^2+8x-48\\\\x^2+12x-4x-48\\\\x(x+12)-4(x+12)\\\\(x+12)(x-4)[/tex]
Hence, the factors of the equation are [tex]\rm (x+12)(x-4)[/tex]/
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Ted has $55. 00 in his pocket. Which purchase will he be able to pay for with cash? two books for $29. 95 each headphones for $29. 99 and a portable speaker set for $30. 95 an MP3 player for $35. 99 and a $20. 00 gift card for downloading music three books for $16. 99 each.
If Ted has $55. 00 in his pocket then out of two books for $29. 95 each headphones for $29. 99 and a portable speaker set for $30. 95 an MP3 player for $35. 99 and a $20. 00 gift card for downloading music three books for $16. 99 each he can purchase three books for $16. 99 each.
How to calculate total money spent ?To calculate total money spent we have to add all the money we spent on all things.
Given that Ted has $55. 00 in his pocket.
(i)
two books for $29. 95 each
Money needed for 2 books = [tex]2\times 29.95=59.9[/tex]
So Ted is not able to purchase 2 books
(ii) headphones for $29. 99 and a portable speaker set for $30. 95
Money needed for headphones and portable speaker = 29.99+30.95=60.94
So Ted is not able to purchase headphones and portable speaker
(iii) an MP3 player for $35. 99 and a $20. 00 gift card for downloading music
Money needed for MP3 player and gift card= 35.99+20.00=55.99
So Ted is not able to purchase MP3 player and gift card
(iv) three books for $16. 99 each.
Money needed for 3 books =[tex]3\times16.99[/tex]=50.97
So ted is able to purchase these three books .
If Ted has $55. 00 in his pocket then out of two books for $29. 95 each headphones for $29. 99 and a portable speaker set for $30. 95 an MP3 player for $35. 99 and a $20. 00 gift card for downloading music three books for $16. 99 each he can purchase three books for $16. 99 each.
To learn more about money spent visit : https://brainly.com/question/21625005
Answer:
d)three books for $16. 99 each.
Step-by-step explanation:
A car filled with x kg of gasoline consumes [tex]\displaystyle \large{\frac{100+x}{100}e^{kv}}[/tex] kg/hr of gasoline when driving at v km/hr. (k is a positive constant.) Given that this car drives to a destination 100 km away at a constant speed, find the initial amount of gasoline and the driving speed such that gasoline consumption is minimized. Assume that the car stops immediately after running out of gasoline.
Answer:
The vehicle should start with [tex](100\, e^{ke} - 100)\; {\rm kg}[/tex] of fuel and drive at a speed of [tex](1/k)\; {\rm km \cdot hr^{-1}}[/tex].
Step-by-step explanation:
Let [tex]t\; {\rm hr}[/tex] denote the number of hours after the vehicle started. As in the question, let the amount of fuel currently on this vehicle be [tex]x\; {\rm kg}[/tex]. The question states that the vehicle consumes fuel at a rate ([tex]dx/dt[/tex]) of [tex]((100 + x) / 100)\, e^{kv}[/tex]. In other words:
[tex]\displaystyle \frac{dx}{dt} = -\frac{100 + x}{100}\, e^{k\, v}[/tex].
Note the minus sign in front of the right-hand side. The amount of fuel on this vehicle decreases over time. Hence, the rate of change in [tex]x[/tex] should be negative.
This equation is a separable ordinary differential equation. The variables are [tex]x[/tex] and [tex]t[/tex]. Solve this ODE to find an expression of [tex]x\![/tex] (fuel in the vehicle) in terms of [tex]t\![/tex] (time.) Follow these steps:
Rearrange this equation such that all [tex]x[/tex] and [tex]dx[/tex] are are on the same side of the equation, while [tex]t[/tex] and [tex]dt[/tex] on all on the other side.
[tex]\displaystyle \frac{dx}{100 + x} = -\frac{e^{k\, v}\, dt}{100}[/tex].
Integrate both sides, and the equality should still hold. Note that [tex]k[/tex] and [tex]v[/tex] are considered as constants. Be sure to include the constant of integration [tex]C[/tex] on one side of the equation.
[tex]\displaystyle \int \frac{dx}{100 + x} = -\frac{e^{k\, v}}{100}\int dt[/tex].
[tex]\displaystyle \ln | 100 + x | = -\frac{(e^{k\, v})\, t}{100} + C[/tex].
Let [tex]x_{0}[/tex] denote the initial amount of fuel on this vehicle (i.e., the value of [tex]x[/tex] when [tex]t = 0[/tex]). The constant of integration [tex]C[/tex] should ensure that [tex]x = x_{0}[/tex] when [tex]t = 0[/tex]. Thus:
[tex]\displaystyle \ln | 100 + x_{0} | = C[/tex].
Hence, the value of the constant of integration should be [tex]\ln | 100 + x_{0} |[/tex]. Therefore:
[tex]\displaystyle \ln | 100 + x | = -\frac{(e^{k\, v})\, t}{100} + \ln | 100 + x_{0}|[/tex].
Since the speed of the vehicle is constant at [tex]v\; {\rm km\cdot hr^{-1}}[/tex], the time required to travel [tex]100\; {\rm km}[/tex] would be [tex](100 / v)\; {\rm hr}[/tex].
For optimal use of the fuel, the vehicle should have exactly [tex]x = 0[/tex] fuel when the destination is reached. Therefore, [tex]x = 0[/tex] at [tex]t = 100 / v[/tex]. Hence:
[tex]\displaystyle \ln | 100 | = -\frac{(e^{k\, v})\, (100 / v)}{100} + \ln | 100 + x_{0}|[/tex].
[tex]\displaystyle \ln | 100 | = -\frac{e^{k\, v}}{v} + \ln | 100 + x_{0}|[/tex].
Notice that [tex]\ln|100 + x_{0}|[/tex] is monotone increasing with respect to [tex]x_{0}[/tex] as long as [tex]100 + x_{0} > 0[/tex]. Thus, given that [tex]x_{0} > 0[/tex], [tex]x_{0}\![/tex] would be minimized if and only if the surrogate [tex]\ln|100 + x_{0}|\![/tex] is minimized.
While the goal is to find the [tex]v[/tex] that minimize [tex]x_{0}\![/tex], finding the [tex]v\![/tex] that minimizes [tex]\ln|100 + x_{0}|[/tex] would achieve the same purpose.
[tex]\displaystyle \ln | 100 + x_{0}| = \ln | 100 | + \frac{e^{k\, v}}{v}}[/tex].
The [tex]\texttt{RHS}[/tex] of this equation is indeed convex with respect to [tex]v[/tex] ([tex]v > 0[/tex].) Thus, the [tex]\texttt{RHS}\![/tex] could be minimized by setting the first derivative with respect to [tex]v[/tex] to [tex]0[/tex].
Differentiate the right hand side with respect to [tex]v[/tex]:
[tex]\begin{aligned} & \frac{d}{dv}\left[\frac{e^{k\, v}}{v}\right] \\ =\; & \frac{k\, e^{k\, v}}{v} - \frac{e^{k\, v}}{v^{2}}\\ =\; & \frac{(k\, v - 1)\, e^{k\, v}}{v^{2}}\end{aligned}[/tex].
Setting this first derivative to [tex]0[/tex] and solving for [tex]v[/tex] gives:
[tex]k\,v - 1 = 0[/tex].
[tex]v = (1/k)[/tex].
Therefore, the amount of fuel required for this trip is minimized when [tex]v = (1/k)\; {\rm km \cdot hr^{-1}}[/tex].
Substitute [tex]v[/tex] back and solve for [tex]x_{0}[/tex] (initial amount of fuel on the vehicle.)
[tex]\displaystyle \ln | 100 + x_{0}| = \ln | 100 | + \frac{e^{k\, (1/k)}}{(1/k)}}[/tex].
[tex]\displaystyle \ln | 100 + x_{0}| = \ln | 100 | + k\, e[/tex].
[tex]e^{\ln| 100 + x_{0}|} = e^{\ln|100| + k\, e}[/tex].
[tex]e^{\ln| 100 + x_{0}|} = e^{\ln|100|}\, e^{k\, e}[/tex].
[tex]100 + x_{0} = 100\, e^{k\, e}[/tex].
[tex]x_{0} = 100\, e^{k\, e} - 100[/tex].
In other words, the initial amount of fuel on the vehicle should be [tex](100\, e^{k\, e} - 100)\; {\rm kg}[/tex].
Sarah scored 82 points on her first test of the year. On the second test,
she scored 77 points. What is the percent of change?
Sarah scored 82 points on her first test of the year. On the second test,
82%
On the Second Test, She scored 77 points
77%
82
-77
=5
The Percent of Change is 5%
or -5% Because The second test Is lower than her first test
Answer:
5%
Step-by-step explanation:
82% - 77%=5%
82%
77%
so there fore the answer is 5%
Find the perimeter of a building that measures 23 √149
Answer:
This question is incomplete
where is the length width and breath
Step-by-step explanation:
meanwhile
[tex]23 √149 \\ 23 \times 12.20655561573370 \\ 280.7507791618751 \\ approx \\ 280.8[/tex]
What would the height need to be for this curve to be a
density curve?
O 1/5
O 1/4
O 1/2
O 1
Answer: A
Step-by-step explanation:
The total area would have to be 1, so (1/2)(5)(height)=1
2.5height = 1
height = 1/2.5 = 2/10 = 1/5
The height for the density curve will be 1/5. The correct option is A.
What is a density curve?The area under the curve represents 100% of all probabilities. Because we normally use decimals in probabilities, we can also say that the area is equal to 1 (because 100% is a decimal). The density curve shown above depicts how body weights are distributed.
The image of the triangle is showing the base 5 units. For the density curve, the area under the curve must be 1. The height of the curve will be calculated as,
Area = 1
1/2 x B x H = 1
1/2 x 5 x H = 1
2.5 x H = 1
H = 1 / 2.5
H = 1 / 5
Therefore, the height will be 1 / 5.
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There are 10 girls in the class. This is 4 more than 2 times the number of boys. How many boys are in the class?
Answer:
let us suppose the number of boys be x
now,
10=4+2x
or, 10-4/2=x
or,x=3
therefore, 3 boys are there
plese help thank yous
The sum of 2 numbers is 32. Their difference is 30. What are the 2 numbers? Show all work
Answer:
31 and 1
Step-by-step explanation:
let the first number be x
let the second number be y
x + y = 32 ---------- eq 1
x - y = 30 ---------- eq 2
eq 1 - eq 2
(x - x) + (y -(-y)) = 32 - 30
y + y = 2
2y = 2
y = 1
Substitute the value of y in eq 1
x + y = 32
x + 1 = 32
x = 32 - 1
x = 31
Therefore the first number is 31 and the second number is 1