PLEASE HELPPPP!!!!
in the diagram, the direction of a current and the magnetic field around it are shown. describe what would happen to the magnetic field if you increased the number of turns in the coil and reversed the direction of the current
Answer:
more turns in a coil will make stronger magnet field and reversed direction of the current will change the pole of the magnet
Explanation:
by winding a coil , it concentrates magnetic field of the current in smaller space so more turns of coil mean stonger magnetic field.
explanation for change of direction of current is in pic.
i hope it helps.
More turns in a coil will make stronger magnet field and reversed direction of the current will change the pole of the magnet.
What is Current?By winding a coil , it concentrates magnetic field of the current in smaller space so more turns of coil mean stonger magnetic field.
In a full electrical circuit, current is the rate at which electrons move past a certain point. Current = flow, at its most fundamental level.
The international unit for measuring current is an ampere (AM-pir), sometimes known as an amp. It describes how many electrons.
In a circuit, a current of 1 ampere corresponds to the movement of 1 coulomb of electrons, or 6.24 billion billion (6.24 x 1018) electrons, through a single location in a second.
Therefore, More turns in a coil will make stronger magnet field and reversed direction of the current will change the pole of the magnet.
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In a rocket-propulsion problem the mass is variable. Another such problem is a raindrop falling through a cloud of small water droplets. Some of these small droplets adhere to the raindrop, thereby increasing its mass as it falls. The force on the raindrop is
Fext=dpdt=mdvdt+vdmdt
Suppose the mass of the raindrop depends on the distance x that it has fallen. Then m=kx, wherek is a constant, and dm/dt=kv. This gives, since Fext=mg,
mg=mdvdt+v(kv)
Or, dividing by k,
xg=xdvdt+v2
This is a differential equation that has a solution of the form v=at, where a is the acceleration and is constant. Take the initial velocity of the raindrop to be zero.
A) Using the proposed solution for v, find the acceleration a.
B) Find the distance the raindrop has fallen in t = 2.00s.
C) Given that k = 2.00g/m, find the mass of the raindrop at t = 2.00s.
Answer:
a) a = g / 3
b) x (3.0) = 14.7 m
c) m (3.0) = 29.4 g
Explanation:
Given:-
- The following differential equation for (x) the distance a rain drop has fallen has the form:
- Where, v = Speed of the raindrop
- Proposed solution to given ODE:
v = a*t
Where, a = acceleration of raindrop
Find:-
(a) Using the proposed solution for v find the acceleration a.
(b) Find the distance the raindrop has fallen in t = 3.00 s.
(c) Given that k = 2.00 g/m, find the mass of the raindrop at t = 3.00 s.
Solution:-
- We know that acceleration (a) is the first derivative of velocity (v):
a = dv / dt ... Eq 1
- Similarly, we know that velocity (v) is the first derivative of displacement (x):
v = dx / dt , v = a*t ... proposed solution (Eq 2)
v .dt = dx = a*t . dt
- integrate both sides:
∫a*t . dt = ∫dt
x = 0.5*a*t^2 ... Eq 3
- Substitute Eq1 , 2 , 3 into the given ODE:
0.5*a*t^2*g = 0.5*a^2 t^2 + a^2 t^2
= 1.5 a^2 t^2
a = g / 3
- Using the acceleration of raindrop (a) and t = 3.00 second and plug into Eq 3:
x (t) = 0.5*a*t^2
x (t = 3.0) = 0.5*9.81*3^2 / 3
x (3.0) = 14.7 m
- Using the relation of mass given, and k = 2.00 g/m, determine the mass of raindrop at time t = 3.0 s:
m (t) = k*x (t)
m (3.0) = 2.00*x(3.0)
m (3.0) = 2.00*14.7
m (3.0) = 29.4 g
Which statement about local and global winds is true?.
Answer:
Global winds occur in belts around the globe.
Explanation:
This is because they blow over a limited area. They are influenced by local geography, such as nearness to an ocean.
Two satellites are in circular orbits around Earth. Satellite A has speed vA. Satellite B has an orbital radius nine times that of satellite A. What is the speed of satellite B
Answer:
option B
Explanation:
given,
Satellite B has an orbital radius nine times that of satellite A.
R' = 9 R
now, orbital velocity of the satellite A
........(1)
now, orbital velocity of satellite B
from equation 1
hence, the correct answer is option B
A 0.50-kg red cart is moving rightward with a speed of 40 cm/s when it collides
with a 1.50-kg blue cart that is initially at rest. The two carts stick together and
move to the right with a speed of 10 cm/s after the collision,
Enter the momentum values of each individual cart and of the system of two
carts before and after the collision. Also indicate the change in momentum of the
carts and of the system,
The momentum of the red cart before the collision is 0.2 kgm/s and the blue cart is 0.
The momentum of the red cart after the collision is 0.05 kgm/s and the blue cart is 0.15 kgm/s.
The change in momentum of the system of the carts is 0.
Initial momentum of the carts before collisionThe momentum of the carts before the collision is calculated as follows;
P(red) = 0.5 kg x 0.4 m/s = 0.2 kgm/s
P(blue) = 1.5 x 0 = 0
Momentum of the carts after collisionThe momentum of the carts after the collision is calculated as follows;
P(red) = 0.5 x 0.1 = 0.05 kgm/s
P(blue) = 1.5 0.1 = 0.15 kgm/s
Change in momentum of the carts[tex]\Delta P = P_f - P_i[/tex]
ΔP = (0.05 + 0.15) - (0.2)
ΔP = 0
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A 70.0 kg astronaut is training for accelerations that he will experience upon reentry. He is placed in a centrifuge (r = 10.0 m) and spun at a constant angular velocity of 16.3 rpm. Answer the following:
What is the angular velocity of the centrifuge in ?
What is the linear velocity of the astronaut at the outer edge of the centrifuge?
What is the centripetal acceleration of the astronaut at the end of the centrifuge?
How many g’s does the astronaut experience?
What is the centripetal force and net torque experienced by the astronaut? Give magnitudes and directions.
Answer:
1.3823 rad/s
20.7345 m/s
28.66129935 m/s²
2006.29095 N radially outward
Explanation:
r = Radius = 15 m
m = Mass of person = 70 kg
g = Acceleration due to gravity = 9.81 m/s²
Angular velocity is given by
Angular velocity is 1.3823 rad/s
Linear velocity is given by
The linear velocity is 20.7345 m/s
Centripetal acceleration is given by
The centripetal acceleration is 28.66129935 m/s²
Acceleration in terms of g
Centripetal force is given by
The centripetal force is 2006.29095 N radially outward
The torque will be experienced when the centrifuge is speeding up of slowing down i.e., when it is accelerating and decelerating.
a stone is thrown at 45 degree with velocity 10m/sec.calculate the range of projectile
Answer:
As per Given Information
Angle on which the stone thrown ,theta = 45°
Velocity ,u = 10m/s
Acceleration due to gravity ,g is 10m/s²
We have to find the "Range of Projectile "
Range of projectile is denoted by R .
Using Formulae
[tex]\\ \bigstar{\boxed{\pink{\bf{R = \frac{ {u}^{2}sin2 \theta }{g} }}}} \\ \\ [/tex]
On putting the value we get
[tex] \sf\dashrightarrow \: R\: = \frac{ {10}^{2} \times sin(2 \times 45) }{10} \\ \\ \sf\dashrightarrow \: R = \frac{100 \times sin90 {}^{ \circ} } {10} \\ \\ \sf\dashrightarrow \: R \: = \frac{100 \times 1}{10} \\ \\ \sf\dashrightarrow \: R \: = \frac{100}{10} \\ \\ \sf\dashrightarrow \: R = \cancel \frac{100}{10} \\ \\ \sf\dashrightarrow \: R = 10m[/tex]
So, the range of projectile is 10m.
6 The amount of strawberries Maria uses is 383/8 times the amount of the other fruits
combined
How many cups of strawberries does Maria use?
CA. 3/8x(3 2/3+2 1/4+2 3/4)=3/8x868=3932 cups
B. 3 2/3+2 1/4+2 3/4=8 2/3 cups
C. 3/8 3 2/3 +2 74 + 24 = 3 8 (3 8/12+2 31 2+2 9/12)=3/8x8
8/12=3/8x8 2/3=3 2/8=3 1/4 cups
• D. 3/8x3 2/3=3/8x11/3=11/8=1 3/8 cups
.
help me please┐(‘～`;)┌
Answer:
(3) Potent energy per unit volume
Explanation:
The kinetic energy, pressure and flow speed all change with cross-section area so they are not constant over time. Because the flow is in a horizontal pipe, the height never changes so (3) Potent energy per unit volume is constant.
Answer:
Option C
Explanation:
Mark the line horizontal pipe.
Means the height is constantPotential energy depends upon height.So potential energy also remains unchangedShondra takes notes in class. I. Electromagnetic Waves II. The ability to work - Has many forms - Mechanical III. Potential energy - Chemical - Elastic - Gravitational Kinetic energy - Energy of movement - Electrical IV. Nuclear - Radiant - Thermal One line of Shondra’s notes is irrelevant to the rest of her notes. Which line is about a different topic than the rest of Shondra’s notes? I II III IV.
The waves that are related to both electricity and magnetism are known as (EM) waves .electromagnetic Waves' this line is about a different topic than the rest of Shondra’s notes.
What is an electromagnetic wave?The waves that are related to both electricity and magnetism are known as electromagnetic (EM) waves. These waves are made up of time-varying electric and magnetic fields that travel over space.
These waves, which are related to electricity and magnetism, would undoubtedly spread in space. The waves that are related to both electricity and magnetism are known as electromagnetic (EM) waves.
These waves are made up of time-varying electric and magnetic fields that travel over space. These waves, which are related to electricity and magnetism, would undoubtedly spread in space.
Hence option 1 is right because the 'Electromagnetic Waves' these line is about a different topic than the rest of Shondra’s notes.
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How are velocity and acceleration related
Answer:
Acceleration is the rate of change of velocity. If an object is changing its velocity, its speed, or changing its direction, then it is said to be accelerating.
Explanation:
when you change directions or speed up you are accelerating (or decelerating) and when you change directions or speed its called velocity.
Trains A and B travel at the same constant rate in opposite directions along the same route between Town G and Town H. If Train A travels for exactly two hours before passing Train B, how long does it take Train B to travel the entire distance between Town G and Town H?
(1) Train B started traveling between Town G and Town H 1 hour after Train A started traveling between Town H and Town G.
(2) Train B travels at the rate of 150 miles per hour.
Which statement describes the relationship between bonding and surface
tension?
O A. The more hydrogen bonds a molecule can make, the higher the
surface tension,
O B. The more ionic bonds a molecule can make, the higher the surface
tension
C. The more hydrogen bonds a molecule can make, the lower the
surface tension,
O D. The more ionic bonds a molecule can make, the lower the surface
tension,
Answer:
The more hydrogen bonds a molecule can make, the higher the surface tension.
Explanation:
Hydrogen bonds provide higher surface tension to a liquid
More hydrogen molecules - stronger cohesive forces
Answer:
The statement describes the relationship between bonding and surface
Explanation:
C. The more hydrogen bonds a molecule can make, the higher the surface tension.
Hope this helps
i need helpp pls!!!!??????
Answer:
too hard bro others will answer it
Explanation:
sry
Determine the horizontal displacement of a projectile if it has a flight time of 8 seconds and a horizontal velocity of 14 m/s
[tex]\\ \rm\bull\rightarrowtail Displacement=Velocity\times Time[/tex]
[tex]\\ \rm\bull\rightarrowtail Displacement=8(14)[/tex]
[tex]\\ \rm\bull\rightarrowtail Displacement =112m[/tex]
What law explains why a collapsing cloud usually forms a protostellar disk around a protostar?.
Answer:
conservation of angular momentum
Explanation:
Quizlet
If a spinning skater pulls her arms in so as to reduce her rotational inertia by half, by how much will her rate of spin increase
A person uses a force of 7 N to drag a garbage can a distance of 15 m. How much work is done on the garbage can?
Walt ran 5 kilometers in 25 minutes, going eastward. What was his average velocity? 0. 17 km/min east 0. 2 km/min east 5 km/min east 25 km/min east.
Answer:
0.2 km/min east
Explanation:
Walt ran 5 kilometers in 25 min, going eastward. What was his average velocity?
m a t h
What change slowly occurs during the main-sequence lifetime of a star?.
What will be the extension of a spring with a spring constant of 3N/m if a 15N force is applied?
What is the meaning of the reference point in electric potential?.
Answer:
ELECTRIC POTENTIAL• the amount of work needed to move a unit charge from a reference point to a specific point against an electric field.
Object 1 has a mass of 3m and is moving to the right at a velocity of
4v. Object 2 has a mass of m is moving to the left at v. After the objects collide inelastically, object A is moving to the left at a velocity of v (one third of its original velocity). Derive an expression for the final velocity V of object B.
I am confused because I thought the when it is an inelastic equation, then that means that the objects stick together. So how can you find the final velocity of object B (also it shows that after the collision, the two objects to in fact split apart)?
Answer:
In a collision, the velocity change is always computed by subtracting the initial velocity value from the final velocity value. If an object is moving in one direction before a collision and rebounds or somehow changes direction, then its velocity after the collision has the opposite direction as before.
How many electrons does one atom of carbon share to complete its valence shell?.
Answer:
2 electrons
Explanation:
carbon has 6 and only needs 2 to get to 8
What are the uses of a magnet?
Answer:
A magnet is used in a compass to show the direction.
Magnets are used in medical equipment.
Powerful magnets are used to lift objects
they are used in refrigerator, televisions, earphones etc
Answer:
1. they are used in medical equipment
2. they are used in dynamos
3. they are used in generators and motors
4. powerful magnets are used to lift heavy objects
5. they are used to prevent corrosion in a water heater
A 300 kg snowmobile is traveling at 30 m/s. How fast would a 200 kg snowmobile need to travel to have
the same momentum?
A 200 kg snowmobile having the same momentum will travel at 45 m/s.
What is momentum?Momentum of an object is the product of mass and speed of an object.
P = mv
where;
m is mass of the objectv is speed of the objectm₁v₁ = m₂v₂
v₂ = m₁v₁/m₂
v₂ = (300 x 30)/200
v₂ = 45 m/s
Thus, a 200 kg snowmobile having the same momentum will travel at 45 m/s.
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Is the story of isaac newton and the apple tree true??.
Answer:
si
Explanation:
A yellow train of mass 100 kg is moving at 8 m/s toward an orange train of mass 200 kg traveling in the opposite direction on the same track at a speed of 1 m/s. They collide and stick together! What is the final momentum of the new combined train?
A. 100 kgm/s
B. 600 kgm/s
C. 800 kgm/s
D. 80 kgm/s
Answer:
Let the momentum of the orange train be positive
P = 100 * 8 - 200 * 1 = 600 kg-m/s
P(final) = 600 kg-m/s
P / M = 600 kg-m/sec / 300 kg = 2 m/s
Answer-B final momentum = 600 kg-m/s
what is the magnetic force value due to 3.5nanocoloumb charge moves to the
east with velocity of 250m/s making angle of 30 degree with the magnetic
filed (25m.T)?
The force on the charge is 1.1×10⁻⁸ N.
What is force?Force can be defined as the product of the mass of a body and its acceleration
To calculate the force on the charge, we use the formula below.
Formula:
F = qvBsin∅............. Equation 1Where:
q = chargev = velocityB = magnetic field∅ = Angle.From the question,
Given:
B = 25 mT = 0.025 Tv = 250 m/sq = 3.5 nC = 3.5×10⁻⁹ C∅ = 30°Substitute the given values into equation 1
F = (0.025)(250)(3.5×10⁻⁹)(sin30°)F = 1.093×10⁻⁸ NF ≈ 1.1×10⁻⁸ NHence, the force on the charge is 1.1×10⁻⁸ N.
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Light with a wavelength of about 490 nm is made to pass through a diffraction grating. The angle formed between the path of the incident light and the diffracted light is 9. 2° and forms a first-order bright band. What is the number of lines per mm in the diffraction grating? Round your answer to the nearest whole number. Lines per mm.
A diffraction grating is a type of optical instrument obtained with a continuous pattern. The number of lines per mm in the diffraction grating is 326.
What is diffraction grating?A diffraction grating is a type of optical instrument obtained with a continuous pattern. The pattern of the diffracted light by a grating depends on the structure and number of elements present.
The given data in the problem is
[tex]\theta[/tex] is the angle formed between the path of the incident light and the diffracted light = 9. 2°
λ is the wavelength of the light=490nm=4.9
N is the number of lines per mm in the diffraction grating=?
n is ordered = 1
The formula for diffraction grating will be
[tex]\rm n\lambda=dsin\theta\\\\ \rm d=\frac {n \lambda}{sin\theta} \\\\ \rm d=\frac {1\times4.90\times10^{-7}}{sin9.2^0} \\\\\rm d=3.06\times10^{-6}m=3.06\times10^{-3}mm[/tex]
The number of lines per mm is the inverse of the distance between grating in mm.
[tex]\rm N=\frac{1}{d}[/tex]
[tex]\rm N=\frac{1}{3.06\times10^-3}\\\\\rm N=326.8/mm[/tex]
Hence the number of lines per mm in the diffraction grating is 326.
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Answer:
326
Explanation:
