Solution:
What is the domain and range of arccosine?
The function is
[tex]f(x)=\cos^{-1}(x)[/tex]The graph of the function is shown below
From the graph above;
The domain of the function is
[tex]-1\leq x\leq1[/tex]The range of the function is
[tex]0\leq y\leq\pi[/tex]Find the area of the triangle below.9 cm6 cm2 cm
We recall that the area of a triangle is defined by the product of the triangle's base times its height divided by 2.
So we notice that in our image, we know the height (6 cm), and we also know the base of the triangle (2 cm)
Therefore the triangles are is easily estimated via the formula:
[tex]\text{Area}=\frac{base\cdot height}{2}=\frac{2\cdot6}{2}=6\, \, cm^2[/tex]Then the area is 6 square cm.
The table shows the amount of water used daily to water the fairways at Fairlawn Golf Course. To the nearest tenth,determine the mean absolute deviation of the data. A. 2.3 B. 7.7 C. 10 D. 12.3
Answer:
2.3
Explanation:
The formula for calulating mean deviation is expressed as:
[tex]\frac{1}{n}\sum ^n_{i\mathop=1}|x_i-m|[/tex]where;
m is the mean of the data set
Xi are individual values
n is the total sample space
Get the mean;
n = 7
mean = (10+12+11+15+9+8+5)/7
mean = 70/7
mean = 10
Get the mean deviation:
Mean deviation = (10-10)+(12-10)+(11-10)+(15-10)+(9-10)+(8-10)+(5-10)/7
Since the values is in modulus |xi - m| will give a positive value, hence;
Mean deviation = (0+2+1+5+1+2+5)/7
Mean deviation = 16/7
Mean deviation = 2.28
Mean deviation = 2.3 (to the nearest tenth)
740In the table on the right there are grades that were earned by students on a midtermbusiness math exam What percent of the students earned a grade below 80?83977084986685687783958879648890859396The percent of students with grade below 80 is(Round to the nearest whole number as needed)
Notice that the number of students that got a grade below 80 is:
[tex]7,[/tex]and the total number of students is:
[tex]20.[/tex]Therefore, we have to determine what percentage 7 represents from 20. To determine the percentage that x represents from y, we can use the following expression:
[tex]\frac{x}{y}*100.[/tex]Finally, we get that 7 represents the
[tex]\frac{7}{20}*100=35\%,[/tex]of 20.
Answer:
[tex]35\%.[/tex]The volume of a right circular cylinder with a radius of 4 in. and a height of 12 in. is ___ π in^3.
For the given right cylinder:
Radius = r = 4 in
Height = h = 12 in
The volume of the cylinder =
[tex]\pi\cdot r^2\cdot h=\pi\cdot4^2\cdot12=192\pi[/tex]So, the answer will be the volume is 192π in^3
help me please if you can A.(0, 3)B. (-1, 5)C.(1, 1.5)
Answer:
A. (0, 3)
C. (1, 1.5)
Explanation:
A point is a solution to the system if it satisfies both inequalities.
So for each option, we get:
Replacing (x, y) = (0, 3)
y ≥ -2x + 3
3 ≥ -2(0) + 3
3 ≥ 3
y ≤ -x² - x + 4
3 ≤ -0² - 0 + 4
3 ≤ 4
Since both inequalities are satisfied, (0, 3) is a solution.
For (x, y) = (-1, 5)
y ≥ -2x + 3
5 ≥ -2(-1) + 3
5 ≥ 2 + 3
5 ≥ 5
y ≤ -x² - x + 4
5 ≤ -(-1)² - (-1) + 4
5 ≤ -1 + 1 + 4
5 ≤ 4
Since 5 is not lower than 4, (-1, 5) is not a solution
For (x, y) = (1, 1.5)
y ≥ -2x + 3
1.5 ≥ -2(1) + 3
1.5 ≥ -2 + 3
1.5 ≥ 1
y ≤ -x² - x + 4
1.5 ≤ -(1)² - (1) + 4
1.5 ≤ -1 - 1 + 4
1.5 ≤ 2
Since both inequalities are satisfied, (1, 1.5) is a solution.
Therefore, the answers are
A. (0, 3)
C. (1, 1.5)
A local band was interested in the average song time for rock bands in the 1990s. They sampled eight different rock bands and found that the average time was 3.19 minutes with a standard deviation of 0.77 minutes.
Calculate the 95% confidence interval (in minutes) for the population mean.
The 95% confidence interval (in minutes) for the population mean is of:
(2.55, 3.83).
What is a t-distribution confidence interval?The bounds of the confidence interval are given according to the following rule:
[tex]\overline{x} \pm t\frac{s}{\sqrt{n}}[/tex]
In which the parameters are described as follows:
[tex]\overline{x}[/tex] is the sample mean.t is the critical value.n is the sample size.s is the standard deviation for the sample.The distribution is used when the standard deviation of the population is not known, only for the sample.
In the context of this problem, the values of the parameters are given as follows:
[tex]\overline{x} = 3.19, s = 0.77, n = 8[/tex]
The critical value, using a t-distribution calculator, for a two-tailed 95% confidence interval, with 8 - 1 = 63 df, is t = 2.3646.
Then the lower bound of the confidence interval is calculated as follows:
[tex]\overline{x} - t\frac{s}{\sqrt{n}} = 3.19 - 2.3646\frac{0.77}{\sqrt{8}} = 2.55[/tex]
The upper bound is calculated as follows:
[tex]\overline{x} + t\frac{s}{\sqrt{n}} = 3.19 + 2.3646\frac{0.77}{\sqrt{8}} = 3.83[/tex]
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My answer is correct or no please check
Answer:
D) 5 minus a number M
hope this helps!
Answer:
Yep. You got it right. Good job!
Step-by-step explanation:
in a triangle one angle is three times the smallest angle and the third angle is 45 more than twice the smallest angle. find the measure of all 3 angles. Hint: the angles of a triangle add up to 180.
Please show me full steps. I need help.
The angles are 22.5°, 67.5° and 90°.
How to calculate the angle?Let the smallest angle = x
Total angles in a triangle = 180°
One angle is three times the smallest angle. This will be 3x.
The third angle is 45 more than twice the smallest angle. This will be:
= (2 × x) + 45
= 2x + 45
The angles will be:
x + 2x + 45 + 3x = 180
6x + 45 = 180
Collect like terms
6x = 180 - 45
6x = 135
Divide
x = 135 / 6
x = 22.5°
Smallest angle = 22.5°
The other angles will be calculated by substitutibg 22.5° for x. This will be:
3x = 3 × 22.5 = 67.5°
Also, 2x + 45 = 2(22.5) + 45 = 90°
This illustrates the concept for angles in a triangle.
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2/(x - 1) - 1/(x + 1) - 3/(x ^ 2 - 1)
The first step to solve this problem is to solve the substraction between the first two fractions:
[tex]undefined[/tex]TASK 2: Awards DinnerTran is in charge of the school's Awards Dinner. She set up the multi-purpose room with a stage in front and round tables for parents, students, and family membersto sit around for dinner. Below is the floor plan that she drew for the event.StageCLUE Illuminate EducationIncSign out11US 01:09hp
According to the image each table has an amount of 8 seats, and there are
in a recent year the annual salary of the governor of New York was 1790000 during the same year the annual salary of the governor of Tennessee was 940000 less write and solve an equation to find the annual salary of the government of Tennessee in that year
Step 1 : Let's review the information given to us to answer the problem correctly:
• Annual salary of the governor of New York = $ 1,790,000
,• Annual salary of the governor of Tennessee = $ 940,000
Step 2: Let x to represent the annual salary of the governor of New York
and let's find the ratio of the salary of the governor of Tennessee, as follows:
940,000/1,790,000 = 0.525
Step 3: Now, let's write the equation for calculating the salary of the governor of Tennessee for any given year, this way:
• 0.525x = Annual salary of the governor of Tennessee
,•
Step 4: If the salary of the governor of New York for the next year is 2,000,000, then we can calculate the salary of the governor of Tennessee, this way:
0.525x = 0.525 * 2,000,000 = 1,050,000
The annual salary of the governor of Tennessee woudl be 1,050,000
simplify x⁹ divided by x^5
Answer:
[tex]x^{4}[/tex]
Step-by-step explanation:
Whenever it comes to the division of the same variable, we subtract their powers in order to get the correct answer:
[tex]x^{9}/x^{5}[/tex]
[tex]x^{9-5}[/tex]
[tex]x^{4}[/tex]
Solve the following system of equations graphically on the set of axes below. Plot two or more dotes on the graphy = 2x - 8 y = -x + 4
Given:-
[tex]y=2x-8,y=-x+4[/tex]To find the graphical representation.
So the graph of y=2x-8 is,
Also the graph of y=-x+4 is,
Combining we get the graph
So the point is (4,0).
The state of California charges homeowners approximately $1,200 per year in property taxes for every $100,000 a person's home is worth. If Mr. Cohen's home in Studio City, CA is worth $1,600,000, how much does he have to pay in property taxes per year? Set up a pair of equivalent ratios and then use your knowledge of cross products to solve. You may use calculator.
We have the next information
1,200 ----- 100,000
x ----- 1,600,000
x is the missing quantity
x can be calculated in this way
[tex]x=\frac{1,600,000\cdot1200}{100,000}=19200[/tex]Mr. Cohen has to pay per year $19,200 taxes per year
what is 9/36 simplified?
Answer:
1/4
Step-by-step explanation:
it can be simplified by dividing both the numerator and denominator with 9.
[tex] \displaystyle \large{ \sf{ \frac{9}{36}}} [/tex]
[tex]\displaystyle \large{ \sf{ \frac{9}{36} = \frac{ \cancel9}{ \cancel3 \cancel6} }}[/tex]
[tex]\displaystyle \large{ \bf{ = \frac{1}{4} }}[/tex]
simplest form is 1/4
For these problems, please show your algebraic work using logarithms. 1. Determine the doubling time for each situation listed below. a. A population is growing according to P = P_0e^0.2t b. A bank account is growing by 2.7% each year compounded annually.
Answer: We need to find the doubling time for population growth:
Population growth is given by
[tex]P=P_oe^{(0.2)t}[/tex]Where:
[tex]\begin{gathered} P\rightarrow\text{final} \\ P_o\rightarrow I\text{nitial} \end{gathered}[/tex]For the population to double, it implies that:
[tex]P=2P_o[/tex]Therefore:
[tex]\frac{P}{P_o}=\frac{2P_o}{P_o}=2=e^{(0.2)t}[/tex]Solving for time "t" gives:
[tex]2=e^{(0.2)t}\rightarrow\ln (2)=(0.2)t\rightarrow t=\frac{\ln (2)}{(0.2)}=3.46u[/tex]Can I get help w this pleaseThe dimensions of a rectangular prism are quadrupled.if the original surface area was 225ft^2 was is the new surface area?
Answer:
Concept:
Doubling the dimensions of a prism will increase the new area by 4 times the original area
Tripling the the dimensions of the prism will increase the new area by 9 times the original area
Quadrupling will increase the new area by 16 times the original area
Given that the original area given is
[tex]=225ft^2[/tex]The new area therefore will be
[tex]\begin{gathered} 16\times225 \\ =3600ft^2 \end{gathered}[/tex]Hence,
The final answer will be
[tex]\rightarrow3600ft^2[/tex]Use the fact that 521•73=38, 033.Enter the exact product of 5.21•7.3
Answer: 38.033
5.21 x 7.3
= 38.033
Newton's Second Law, F=m.a, describes the relationship between an object's mass, a force acting on it, and the resulting acceleration, where: F is force, in Newtons m is mass, in kilograms a is acceleration, in meters per second squared A young boy and his tricycle have a combined mass of 30 kilograms. If the boy's sister gives him a push with a force of 60 Newtons, what is his acceleration? 1 2 meter per second squared 2 meters per second squared 30 meters per second squared 90 meters per second squared
Newton's Second Law, F=m.a, describes the relationship between an object's mass, a force acting on it, and the resulting acceleration, where: F is force, in Newtons m is mass, in kilograms a is acceleration, in meters per second squared A young boy and his tricycle have a combined mass of 30 kilograms. If the boy's sister gives him a push with a force of 60 Newtons, what is his acceleration? 1 2 meter per second squared 2 meters per second squared 30 meters per second squared 90 meters per second squared
we have that
F=m*a
we have
m=30 kg
F=60 N
substitute in the formula
60=30*a
solve for a
a=60/30
a=2 m/s^2
therefore
the answer is 2 meters per second squaredFind the coordinates of the vertex of the graph of y=4-x^2 indentify the vertex as a maximum or minimum point A.(2,9);maximumB.(0,4);minimumC.(0,4);maximum D.(2,0);minimum
Let's begin by identifying key information given to us:
[tex]\begin{gathered} y=4-x^2 \\ y=-x^2+4 \\ a=-1,b=0,c=4 \\ x_v=-\frac{b}{2a}=-\frac{0}{2(-1)}=0 \\ y_v=-\frac{b^2-4ac}{4a}=-\frac{0^2-4(-1)(4)}{4(-1)} \\ y_v=-\frac{0+16}{-4}=\frac{-16}{-4}=4 \\ y_v=4 \\ \\ \therefore The\text{ vertex of the equation is }(0,4) \end{gathered}[/tex]To know if the vertex is the maximum or minimum point, we will follow this below:
[tex]\begin{gathered} y_v=4 \\ \Rightarrow This\text{ is a minimum point} \end{gathered}[/tex]Hence, the answer is B.(0,4); minimum
How many solutions does the following equation have? - 6(x + 7) = - 4x – 2 А. No solutions B.Exactly one solution C.Infinitely many solutions
ANSWER
Exactly one solution.
EXPLANATION
We are given the equation:
-6(x + 7) = -4x - 2
To find the number of solutions, we have to solve for x:
-6x - 42 = -4x - 2
Collect like terms:
-6x + 4x = 42 - 2
-2x = 40
x = 40 / -2
x = -20
Therefore, the equation has exactly one solution.
rectangle rstw has diagonals RT and SW that intersect at Z. If RZ= 5x+8 and SW= 11x-3 find the value of x.
Answer:
19
Explanation:
We know that the diagonals of a rectangle are always equal, therefore RT = SW.
So if RZ = 5x + 8 and SW = 11x - 3, lets's go ahead and find x as shown below;
[tex]\begin{gathered} 2(5x+8)=11x-3 \\ 10x+16=11x-3 \\ 16+3=11x-10x \\ 19=x \\ \therefore x=19 \end{gathered}[/tex]Mike is shopping for new clothes. He has a coupon for 20% off of his total purchase. His purchase price before the discount is $68. Let T represent the total cost after the discount. Which equation can be written to model this scenario? Select all that apply.68-0.2(68) = T68 - .20 =T68-20 = T0.8(68) = T0.2(68) =T
ANSWER
68 - 0.2(68) = T
0.8(68) = T
EXPLANATION
The coupon allows for 20% off of his total purchase.
His purchase price before the discount is $68.
To find the price after the discount, we can use two methods:
=> Find 20% of $68 and then subtract from $68 to get T.
That is:
[tex]\begin{gathered} 68\text{ - (}\frac{20}{100}\cdot\text{ 68) = T} \\ \Rightarrow\text{ 68 - 0.2(68) = T} \end{gathered}[/tex]=> Subract 20% from a total of 100% and then multiply by $68 to get T.
That is:
[tex]\begin{gathered} (100\text{ - 20)\% }\cdot\text{ 68 = T} \\ \Rightarrow\text{ 80\% }\cdot\text{ 68 = T} \\ \Rightarrow\text{ 0.8(68) = T} \end{gathered}[/tex]Those are the two answers.
A population forms a normal distribution with a meanof μ = 85 and a standard deviation of o = 24. Foreach of the following samples, compute the z-score forthe sample mean.a. M=91 for n = 4 scoresb. M=91 for n = 9 scoresc. M=91 for n = 16 scoresd. M-91 for n = 36 scores
In this problem, we have a population with a normal distribution with:
• mean μ = 85,
,• standard deviation σ = 24.
We must compute the z-score for different samples.
The standard deviation of a sample with mean M and size n is:
[tex]σ_M=\frac{σ}{\sqrt{n}}.[/tex]The z-score of the sample is given by:
[tex]z(M,n)=\frac{M-\mu}{\sigma_M}=\sqrt{n}\cdot(\frac{M-\mu}{\sigma})[/tex]Using these formulas, we compute the z-score of each sample:
(a) M = 91, n = 4
[tex]z(91,4)=\sqrt{4}\cdot(\frac{91-85}{24})=0.5.[/tex](b) M = 91, n = 9
[tex]z(91,9)=\sqrt{9}\cdot(\frac{91-85}{24})=0.75.[/tex](c) M = 91, n = 16
[tex]z(91,16)=\sqrt{16}\cdot(\frac{91-85}{24})=1.[/tex](d) M = 91, n = 36
[tex]z(91,9)=\sqrt{36}\cdot(\frac{91-85}{24})=1.5.[/tex]Answera. z = 0.5
b. z = 0.75
c. z = 1
d. z = 1.5
After a translation, the image of P(-3, 5) is P'(-4, 3). Identify the image of the point (1, 6) after this same translation.
The image of the point (1, 6) after the translation is (0, 4).
What is named as translation?In geometry, translation refers to a function that shifts an object a specified distance. The object is not elsewhere altered. It has not been rotated, mirrored, or resized.Every location of the object should be relocated in the same manner and at the same distance during a translation.When performing a translation, this same initial object is referred to as the pre-image, as well as the object that after translation is referred to as the image.For the given question,
The image of point P(-3, 5) after a translation is P'(-4, 3).
In this, there is a shift of 1 units to the left of x axis and shift of 2 units up on the y axis.
Thus, do the same translation for the point (1, 6).
After translation image will be (0, 4)
Thus, image of the point (1, 6) after the translation is (0, 4).
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Given AFGH ~ ALMN, which must be true? Select all that apply.A.FGLMFHLNB. FH ~ LNC.mZFmZLmZGmZMD. GHMNE. mZH ^mZN
Find decimal notation for 100%
The decimal notation of percentage is the quotient of the percentage divided by 100.
So it follows that :
[tex]\frac{100\%}{100}=1[/tex]The answer is 1
At one time, it was reported that 27.9% of physicians are women. In a survey of physicians employed by a large health system, 45 of 120 randomly selected physicians were women. Is there sufficient evidence at the 0.05 level of significance to conclude that the proportion of women physicians in the system exceeds 27.9%?Solve this hypothesis testing problem by finishing the five steps below.
SOLUTION
STEP 1
The hull hypothesis can written as
[tex]H_0\colon p=0.279[/tex]The alternative hypothesis is written as
[tex]H_1\colon p>0.279[/tex]STEP 2
The value of p will be
[tex]\begin{gathered} \hat{p}=\frac{X}{n} \\ \hat{p}=\frac{45}{120}=0.375 \\ \text{where n=120, x=}45 \end{gathered}[/tex]STEP3
From the calculations, we have
[tex]\begin{gathered} Z_{\text{cal}}=2.34 \\ \text{Z}_{\text{los}}=0.05 \end{gathered}[/tex]We obtained the p-value has
[tex]\begin{gathered} p-\text{value}=0.0095 \\ \text{level of significance =0.05} \end{gathered}[/tex]STEP4
Since the p-value is less than the level of significance, we Reject the null hypothesis
STEP 5
Conclusion: There is no enought evidence to support the claim
Use the definition of the derivative to find the derivative of the function with respect to x. Show steps
The derivative of the function f(x) = -5x²+3x-2 is -10x+3.
Given the function is f(x) = -5x²+3x-2
Differentiate with respect to x.
d/dx -5x²+3x-2 = d/dx (-5x²) + d/dx(3x) - d/dx(2)
using the power rule d/dx [xⁿ] = nxⁿ⁻¹
⇒ d/dx -5x²+3x-2 = -5(2)x²⁻¹ + 3(1) - 0
⇒ d/dx -5x²+3x-2 = -10x+3
The power rule states that the derivative of xn is nx(n-1) for every x if n is a positive integer, regardless of whether you are thinking of derivatives at a point (numbers) or derivatives on an interval (functions).
Hence we get the derivative as -10x+3.
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identify the slope: 6x - 2y = -6
The slope = 3
Explanations:Note that:
The slope - Intercept form of the equation of a line takes the form y = mx + c
where m is the slope and
c is the intercept
The given equation is:
6x - 2y = -6
The equation can be re-written as:
2y = 6x + 6
2y / 2 = 6x/2 + 6/2
y = 3x + 3
The slope, m = 3
The intercept, c = 3