What is the mass of 3.15 moles of calcium sulfate, CaSO4?

Answer:

C

Explanation:

O2 is a gas and gas has spread out molecules compared to the other states of matter. As such, liquid and solids have stronger intermolecular forces. Since dioxygen is the only gas in the possible answers, O2 has the weakest intermolecular force.

The substance with the weakest intermolecular forces among the options provided is [tex]O_2[/tex](g), which refers to gaseous oxygen molecules. The correct answer is option C.

Intermolecular forces are the attractive forces that exist between molecules and affect the physical properties of substances. The strength of intermolecular forces depends on factors such as the types of molecules involved and their molecular structures.

Among these options, the substance [tex]O_2[/tex](g) has the weakest intermolecular forces. Gaseous oxygen ([tex]O_2[/tex]) molecules are non-polar and are held together by relatively weak London dispersion forces, which are a type of van der Waals forces. These forces arise from temporary fluctuations in electron density within the molecules.

Therefore, compared to the other options, [tex]O_2[/tex](g) has the weakest intermolecular forces because the dispersion forces are generally weaker than the dipole-dipole forces present in the other substances.

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Answer:

The answer is

Explanation:

The pH of a solution can be found by using the formula

[tex]pH = - log( {H }^{ + } ) [/tex]

From the question

[tex]{H }^{ + } = 8.4 × {10}^{-6} M[/tex]

The pH of the solution is

[tex]pH = - log(8.4 \times {10}^{ - 6} ) \\ = 5.0757207...[/tex]

We have the final answer as

Hope this helps you

Answer:

In Parts I and II of the lab, what happened to the electrons of each element to produce the different colors of light? ... When heat was added to the elements, the electrons absorbs the energy and moves to its excited state. Once the electron starts to fall back to a lower orbit, it emits energy in the form of light.

Happy to help ☀️Keep on shining☀️

Explanation:

Answer:

2

Explanation:

16 ÷ 8 = 2

Answer:

Sp3

Explanation:

According to the question, atom 1 is an N atom bonded to 2 C atoms and 1 H atom through single bonds.

Whenever nitrogen is bonded to three atoms via single bonds (in this case two carbon atoms and one hydrogen atom) the nitrogen atom is sp3 hybridized and in tetrahedral geometry. The lone pair on nitrogen atom occupies one of the hybrid sp3 orbitals.

Cyanazine is used as an herbicide to control the growth of weeds and annual grasses. The herbicide has been phased out due to increased toxicity to the environment and humans.

The hybridization of the molecule is sp³.

The given information in the question suggests that Nitrogen (atom 1) to two Carbon atoms and single bonded to 1 hydrogen atom.

The nitrogen is bonded with three single bonds, two with carbon and one with a hydrogen bond.

Based on the given data, the hybridization of the molecule will be sp³ and will have tetrahedral geometry. The lone pair present on the nitrogen atom will occupy one of the hybrid sp³ orbitals.

Therefore, the sp3 hybridization of the cyanazine molecule will exist.

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Answer:

Enthalpy of formation of KF = -555 kJ/mol

Enthalpy of formation of CsF = -539kJ/mol

Explanation:

Explanations are provided in the attachment below

Answer:to regulate the transfer on material into and out of the cell

Answer:

[tex]\rm C_2H_8N_2O_3[/tex].

Explanation:

Look up the relative atomic mass of these four elements on a modern periodic table:

The relative atomic mass of an element is numerically equal to the mass (in grams, [tex]\rm g[/tex],) of one mole of atoms of this element.

For example, the relative atomic mass of [tex]\rm C[/tex] is approximately [tex]12[/tex]. Therefore, each mole of [tex]\rm C\![/tex] atoms would have a mass of [tex]12\; \rm g[/tex].

This sample contains [tex]24\; \rm g[/tex] of carbon. That would correspond to approximately [tex]\displaystyle \left(\frac{24}{12}\right)\; \rm mol = 2\; \rm mol[/tex] of [tex]\rm C[/tex] atoms.

Similarly, for the other three elements:

[tex]\displaystyle n(\mathrm{H}) \approx \frac{8\; \rm g}{1\; \rm g \cdot mol^{-1}} = 8\; \rm mol[/tex].

[tex]\displaystyle n(\mathrm{N}) \approx \frac{28\; \rm g}{14\; \rm g \cdot mol^{-1}} = 2\; \rm mol[/tex].

[tex]\displaystyle n(\mathrm{O}) \approx \frac{48\; \rm g}{16\; \rm g \cdot mol^{-1}} = 3\; \rm mol[/tex].

Hence, the ratio between these elements in this compound would be:

[tex]n(\mathrm{C}): n(\mathrm{H}): n(\mathrm{N}):n(\mathrm{O}) = 2: 8 : 2 : 3[/tex].

In the empirical formula of a compound, the coefficients should represent the smallest possible integer ratio between the number of atoms of these elements.

[tex]n(\mathrm{C}): n(\mathrm{H}): n(\mathrm{N}):n(\mathrm{O}) = 2: 8 : 2 : 3[/tex] is indeed the smallest possible integer ratio between the number of atoms of these elements.

Apply the Hill System to arrange these four elements in the empirical formula. In the Hill System:

If carbon, [tex]\rm C[/tex], is present in this compound, then:

If there is no carbon [tex]\rm C[/tex] in this compound, then list all the elements in this compound in alphabetical order.

Both [tex]\rm C[/tex] (carbon) and [tex]\rm H[/tex] (hydrogen) are found in this compound. Therefore, the first element in the list would be [tex]\rm C\![/tex]. The second would be [tex]\rm H\![/tex], followed by [tex]\rm N\![/tex] and then [tex]\rm O\![/tex].

Hence, the empirical formula of this compound would be [tex]\rm C_2H_8N_2O_3[/tex].

The empirical formula of the compound is C₂H₈N₂O₃  

From the question given above, the following data were:

Carbon (C) = 24 g

Hydrogen (H) = 8 g

Nitrogen (N) = 28 g

Oxygen (O) = 48 g

The empirical formula of the compound can be obtained as follow:

C = 24 g

H = 8 g

N = 28 g

O = 48 g

C = 24 /12 = 2

H = 8 /1 = 8

N = 28 /14 = 2

O = 48 / 16 = 3

We can see from the above calculations that the elements are in simple whole number ratio.

Thus, the empirical formula of the compound is C₂H₈N₂O₃

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Answer:

They would both have a pull.

Explanation:

Every object in space and time has a pull, more specific, a gravitational pull. The objects will have a very slight pul, but still have a gravitational pull.

Answer:

They would both have a pull.

Explanation:

also how do u do that obj thing???



Answer:

There are 3.011 × 10^23 oxygen atoms

Answer:

900 J/kg°C.

Explanation:

Answer:

Option A is correct = combustion

Explanation:

When substance react with oxygen combustion is occur. The substance which burned is called fuel and in this process large amount of heat is released to the surrounding. It is exothermic process.

For example:

4Li + O₂    →      2Li₂O

2Mg + O₂    →    2MgO

 S +  O₂      →      SO₂  

The product which is formed as a result of combustion reaction are called oxides.  

In given examples we can see that lithium, magnesium and sulfur react with oxygen and product formed is oxides of respective elements such as lithium oxide ( Li₂O), magnesium oxide (MgO) and sulfur oxide ( SO₂ ).

Other options are incorrect because:

Single replacement:

It is the reaction in which one elements replace the other element in compound.

AB + C → AC + B

Double replacement:

It is the reaction in which two compound exchange their ions and form new compounds.

AB + CD → AC +BD

Decomposition reaction:

It is the reaction in which one reactant is break down into two or more product.

AB → A + B

Answer:

a

Explanation:

Answer:

Explanation:

From the information given:

Feed F = 150.0 kmol/hr

The saturated liquid mixture of the distillation column is [tex]X_F[/tex] = 30%

Reflux ration  = 2.0%

methanol distillate mole fraction [tex]X_D[/tex] = 0.990

recovery of methanol in the distillate = 97.0%

The distillate flow rate D can be determined by using the formula;

[tex]D = 0.97 (F* X_F)[/tex]

D = 0.97 × 150 × 0.3

D = 43.65 kmol/h

The bottom flow rate Balance B  on the column is:

F = D + B

150 = 43.65 + B

B = ( 150 - 43.65 )kmol/h

B = 106.35 kmol/h

The methanol mole fraction in the bottom [tex]x_M[/tex] can be computed by using the formula:

[tex]F*X_F = DX_D + BX_B[/tex]

150(0.3) = 43.65(0.999) + 106.3([tex]X_B[/tex])

45 = 43.60635 + 106.3([tex]X_B[/tex])

45 -  43.60635 = 106.3([tex]X_B[/tex])

1.39365 = 106.3([tex]X_B[/tex])

[tex]X_B[/tex] = 1.39365 /  106.3

[tex]X_B[/tex] =  0.013

the fractional recovery of water in the bottoms f is calculated as:

[tex]f = \dfrac{B(1-X_B)}{F_X_F}[/tex]

[tex]f = \dfrac{106.35(1-0.013)}{150\times 0.7}[/tex]

[tex]f = \dfrac{106.35(0.987)}{150\times 0.7}[/tex]

f = 0.99969

Answer:

the formula is 164.088 g/mol

Explanation:

Answer:

Moles of KOH in 1000 mL solution = 0.255 moles

Moles of KOH in 1 mL solution = 0.255/1000 = 0.000255 moles

Moles in 95 mL solution = (95 * 255)/1000000 = 24225/1000000

Moles of KOH in 95 mL 0.255M solution = 0.024225 moles

The number of moles of KOH present in 95.0 ml of 0.255 M solution is 0.024mol

HOW TO CALCULATE NUMBER OF MOLES:

no. of moles = molarity (M) × volume (L)

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Answer:

What are the characteristics of science? Objectivity: Scientific knowledge is objective. Verifiability: Science rests upon sense data, i.e., data gathered through our senses—eye, ear, nose, tongue and touch. Ethical Neutrality: Science is ethically neutral. Systematic Exploration.

Explanation:

there are no options but I search and this is what I got.

can I have brainliest

Answer:

half life of carbon=5730 yrs

half life passed=1.5

how old is the pot=??

Explanation:

about 8595 yrs old bcuz its half life is 5730yrs and after 1.5half lives 8595yrs have passed

Answer:

The protein has 4 subunits: 2 subunits of 90 kDa, 1 subunit of 160 kDa and 1 subunit of 60 kDa

Explanation:

In gel electrophoresis, the SDS agent produces denaturation of the protein and confers negative charge, so the protein subunits can migrate according to their masses. It produces dissociation of the protein in its subunits but it cannot disrupt disulphyde bridges (S-S) that can bond subunits together.

From the data, with SDS we observe 3 bands ⇒ 180 kDa + 160 kDa + 60 kDa

The addition of dithiotreitol (DTT), a reducing agent, produces the disruption of disulphyde bridges. From the data:

With DTT ⇒ 160 kDa + 90 kDa + 60 kDa

We observe that 160 kDa and 60 kDa subunits are conserved (they are the same as with SDS only), but 180 kDa subunit is missing and in its place appears a band of 90 kDa - a half 180 kDa.

So, the band at 180 kDa is composed by two subunits bonded by a disulphyde bridge.

Therefore, the composition of the protein is: 1 subunit of 160 kDa, 2 subunits of 90 kDa and 1 subunit of 60 kDa.

Answer:

B: Olfactory Bulb

Explanation:

edg2020

The olfactory bulb is located at the base of the brain and receives neural signals about the smell from the sensory receptors. Hence, option B is correct.

Sensory receptors are dendrites of sensory neurons specialized for receiving specific kinds of stimuli.

There are two olfactory bulbs on the bottom side of the brain, one above each nasal cavity.

The olfactory bulbs receive information about smells from the nose and send it to the brain by way of the olfactory tracts.

Hence, option B is correct.

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Answer:

The mass is 63.1 grams.

Explanation:

ck-12 said it was correct.

Answer:

Sixth transition element: [X] 3d8 4s0

Seventh transition element: [X] 3d8 4s0

Explanation:

In the universe, we have 5 number of "d" orbitals.

Now, Aufbau's rule states that in the ground state of an atom/ion, the electrons will usually fill atomic orbitals of the lowest available energy levels before they occupy higher levels. Meanwhile Hund's rule states that all orbitals in a subshell will be singly occupied with one electron before any single orbital is doubly occupied, and also all electrons in singly occupied orbitals will have the same spin.

From the periodic table, we know that the 6th & 7th transition elements in the universe are Iron & cobalt respectively. Their respective electronic configuration are;

Iron - [Ar] 3d6 4s2

Cobalt - [Ar] 3d7 4s2

Now, in the new universe(L) where there are 8 d - orbitals: from a combination of aufbau's rule and hund's rule; since there are six numbers of d orbitals as earlier said, in iron, which is the sixth transition metal, due to the fact that half filled orbitals will be more stable than partially filled orbitals, it means the 4s orbital will be empty and then two electrons will be removed from the 4s and used to fill the 3d orbital to half way.

Thus, ground state configurations of

Iron = [X] 3d8 4s0

Similarly, for the 7th transition element which is cobalt, the new extra electron will just fill the lower energy orbital which is 4s,thereby leaving the eight numbers of 3d orbitals to be half filled.

Thus, ground state configurations of

Cobalt = [X] 3d8 4s1

Therefore their ground state configurations are;

- Sixth transition element: [X] 3d8 4s0

Seventh transition element: [X] 3d8 4s1

Carbon, C, P Block, 2, 6, 12.0107u. 6 protons, 6 electrons, 6 neutrons

Helium, He, S Block, 1, 2, 4.0026u, 2 protons, 2 electrons, 2 neutrons

Germanium, Ge, P Block, 4, 32, 72.64u, 32 protons, 32 electrons, 41 neutrons

Oxygen, O, P Block, 2, 8, 16u, 8 protons, 8 electrons, 8 neutrons

Scandium, Sc, D Block, 4, 21, 44.9559u, 21 protons, 21 electrons, 24 neutrons

Tellurium, Te, P Block, 5, 52, 127.60u, 52 protons, 52 electrons, 76 neutrons

Hydrogen, H, S Block, 1, 1, 1.008u, 1 proton, 1 electron, 0 neutrons

Iron, Fe, D Block, 4, 26, 55.845u, 26 protons, 26 electrons, 30 neutrons

Beryllium, Be, S Block, 2, 4, 9.012u, 4 protons, 4 electrons, 5 neutrons

Vanadium, V, D Block, 4, 23, 50.942u, 23 protons, 23 electrons, 28 neutrons

Silver, Ag, D Block, 5, 47, 108u, 47 protons, 47 electrons, 61 neutrons

Gallium, Ga, P Block, 4, 31, 69.723u, 31 protons, 31 electrons, 39 neutrons

Bromine, Br, P Block, 4, 35, 79.904u, 35 protons, 35 electrons, 45 neutrons

Fluorine, F, P Block, 2, 9, 18.998u, 9 protons, 9 electrons, 10 neutrons

Manganese, Mn, D Block, 4, 25, 54.938u, 25 protons, 25 electrons, 30 neutrons

Strontium, Sr, S Block, 5, 38, 87.62u, 38 protons, 38 electrons, 50 neutrons

Francium, Fr, S Block, 7, 87, 223u, 87 protons, 87 electrons, 136 neutrons

Answer:

Carbon, C, P Block, 2, 6, 12.0107u. 6 protons, 6 electrons, 6 neutrons

Helium, He, S Block, 1, 2, 4.0026u, 2 protons, 2 electrons, 2 neutrons

Germanium, Ge, P Block, 4, 32, 72.64u, 32 protons, 32 electrons, 41 neutrons

Oxygen, O, P Block, 2, 8, 16u, 8 protons, 8 electrons, 8 neutrons

Scandium, Sc, D Block, 4, 21, 44.9559u, 21 protons, 21 electrons, 24 neutrons

Tellurium, Te, P Block, 5, 52, 127.60u, 52 protons, 52 electrons, 76 neutrons

Hydrogen, H, S Block, 1, 1, 1.008u, 1 proton, 1 electron, 0 neutrons

Iron, Fe, D Block, 4, 26, 55.845u, 26 protons, 26 electrons, 30 neutrons

Beryllium, Be, S Block, 2, 4, 9.012u, 4 protons, 4 electrons, 5 neutrons

Vanadium, V, D Block, 4, 23, 50.942u, 23 protons, 23 electrons, 28 neutrons

Silver, Ag, D Block, 5, 47, 108u, 47 protons, 47 electrons, 61 neutrons

Gallium, Ga, P Block, 4, 31, 69.723u, 31 protons, 31 electrons, 39 neutrons

Bromine, Br, P Block, 4, 35, 79.904u, 35 protons, 35 electrons, 45 neutrons

Fluorine, F, P Block, 2, 9, 18.998u, 9 protons, 9 electrons, 10 neutrons

Manganese, Mn, D Block, 4, 25, 54.938u, 25 protons, 25 electrons, 30 neutrons

Strontium, Sr, S Block, 5, 38, 87.62u, 38 protons, 38 electrons, 50 neutrons

Francium, Fr, S Block, 7, 87, 223u, 87 protons, 87 electrons, 136 neutrons

Explanation:

Answer: Bones.

Explanation:

Answer:

Bone

Explanation:

The chemical formula of carbonic acid is H₂CO₃ and in the structure form it will be represented according to the first structure.

Acids are those substances which are having carboxylic group (-COOH) as a funtional group in it.

Given molecular formula of carbonic acids is H₂CO₃, in which one carbon atom is present in carboxylic group. In the molecule two hydrogen atoms are present and one of them is present in -COOH group and all three oxygen atoms are attached with carbon atom.

Hence the first image shows the structure of carbonic acid.

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Answer:

Explanation:

a ) 2FeCl₃ + 3Li₂S  = Fe₂S₃ ( s )  + 6 LiCl

2Fe⁺³ + 6Li ⁻ + 6Cl⁻ + 3S⁻² = 6Li + 6Cl⁻ + Fe₂S₃ ( s )

b  )

3CH₃COONa +( NH₄)₃PO₄ = 3CH₃COONH₄ + Na₃PO₄

3CH₃COO + 3Na⁺ +  3NH₄⁻  +  PO₄⁺³  = 3CH₃COO⁻ +3NH₄⁺ + Na₃PO₄

c )

HClO₄  + KOH = kClO₄ + H₂O

H ⁺ + ClO₄⁻ +  K⁺ + OH⁻  =  k⁺  ClO₄⁻  + H₂O

d )

NH₄OH + HNO₃ = NH₄NO₃  + H₂O

NH₄⁺ + OH⁻ + H⁺ + NO₃⁻ = NH₄⁺ + NO₃⁻ +  H₂O

e )

HNO₂ + KOH = KNO₂ + H₂O

H⁺ + NO₂⁻ + K⁺ + OH⁻ = K⁺ + NO₂⁻ + H₂O

f ) HIO₃ + CaCO₃ ( s ) = Ca( IO₃ )₂ + H₂CO₃

H⁺ + IO₃⁻ + CaCO₃ ( s ) = Ca( IO₃ )₂ + H₂CO₃

g )

c ) is strong acid and strong base

d ) is weak base and strong acid

e ) weak acid and strong base

f ) Strong acid and basic salt

Answer:

D. Photosynthesis uses carbon dioxide while cellular produces carbon dioxide

Answer:

use the percent as the abundance and multiply it by the atomic mass and add the values together

Explanation: idk but i got it from quizlet

We have that the % values  shown in the sim into a number you could use for your calculation of average  masses is given as

[tex]Avg M=\frac{\sum(atomic masses of every existing element)}{100 atoms}[/tex]

From the question we are told

If you assumed 100 total atoms in a sample, how could you relate the % values  shown in the sim into a number you could use for your calculation of average  masses?

Generally

We will consider  that the 100 total atoms  as the the atoms at  a 100 percent

The substance at a 100 atoms is to be calculated and is to be given as

Generally the equation for the  average atomic mass  is mathematically given as

[tex]Avg M=\frac{\sum(atomic masses of every existing element)}{100 atoms}[/tex]

Therefore

Now, the % values  shown in the sim into a number you could use for your calculation of average  masses is given as

[tex]Avg M=\frac{\sum(atomic masses of every existing element)}{100 atoms}[/tex]

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Answer:

2.3 Work with the numerator first: 165 mg is 0.165 g. ... 2.9 (a) 1 mg Mo 1 10 3 g

Explanation:

im pretty sure this is the answer

Answer:

changes like leaves turning color in the fall are chemical changes. They involve chemical reactions. Bonds break in chemicals and new bonds form. Substances change into new chemical compounds.

Explanation: