What is the number of protons neutrons and electrons in a family Osito that is used in medical diagnosis atomic number 43 mass number 99 charge of 7+

Answers

Answer 1

Answer:

43 protons

36 electrons

56 neutron

Explanation:

neutron is mass number minus proton number.

in a non neutral atom the electron is determined after minusing the charges or electron lost.

the number of proton obviously is 43


Related Questions

A sample of pure acetic acid, CH3COOH, contains 1.40x10^23 carbon atoms. How many moles of acetic acid are in the sample. Explain

Answers

Taking into account the definition of Avogadro's number, 0.116 moles of acetic acid are in the sample.

Avogadro's Number

Avogadro's Number or Avogadro's Constant is called the number of particles that make up a substance (usually atoms or molecules) and that can be found in the amount of one mole of said substance. Its value is 6.023×10²³ particles per mole. Avogadro's number applies to any substance.

Amount of moles of acetic acid that contains 1.40×10²³ carbon atoms

Then you can apply the following rule of three: if 6.023×10²³ atoms are contained in 1 mole of carbon, then 1.40×10²³ atoms are contained in how many moles of carbon?

amount of moles of carbon= (1.40×10²³ atoms × 1 mole)÷ 6.023×10²³ atoms

amount of moles of carbon= 0.232 moles

So, the amount of moles of carbon in acetic acid that contains 1.40×10²³ carbon atoms is 0.232 moles.

On the other side, the small subscripts placed to the right of some symbol indicate the number of moles of the element that are found in the compound.

So, in pure acetic acid, CH₃COOH, are present 2 moles of carbon in 1 mole of acetic acid.

Then you can apply the following rule of three: if 2 moles of carbon are present in 1 mole of acetic acid, then 0.232 moles of carbon are contained in how many moles of acetic acid?

[tex]amount of moles of acetic acid=\frac{0.232 moles of carbonx1 mole of acetic acid}{2 moles of carbon}[/tex]

amount of moles of acetic acid= 0.116 moles

In summary, 0.116 moles of acetic acid are in the sample.

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Which term describes this reaction?
R1
R2
0.
R2
+
| 121
|
H3N+ -C-C
|
H
H
| |
H-N+-C-C
| |
H H
R10
| |
H3N+ -C-C-N-C-C
| | |
H H H
0-
o
H20
addition
condensation
elimination
O substitution

Answers

Answer:Biopolymer: the monomeric amino acids are linked through an

amide bond (the carboxylic acids of one AA with the α-amino

group of a second)

Explanation:

In this reaction, elimination of water molecule takes place, therefore this reaction is elimination reaction. So, option C is correct.

What is elimination reaction ?

In a one- or two-step method, two substituents are removed from a molecule in an organic reaction known as an elimination reaction. The E2 reaction is the name given to the one-step mechanism, and the E1 reaction to the two-step mechanism.

Dehydration and oxidation are the two basic techniques used in this kind of process. Dehydrohalogenation. Because it allows us to remove one of the variables and answer a more straightforward equation.

The halogenoalkane and either sodium or potassium hydroxide solution are the same chemicals you use for replacement or elimination.

Thus, option C is correct.

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PLEASE HELP!!!!!!!!!!!
Molar mass is the molecular (formula) mass of any substance expressed in which unit?

kilograms
liters
moles
grams

Answers

Answer:

I believe your answer would be grams.

Which is the correct set of products for the acid-base neutralization reaction between hydrochloric acid and sodium hydroxide?

Answers

Answer: I think the answer is C. NaCl and H2O

Explanation: I’m not sure tho

Answer:

C) - Water and a Salt

Explanation:

Because Water and a Salt are the products of a neutralization reaction between an acid and a hydroxide base.

Petrified fossils are really
They are made of minerals that have replaced the original matter.
wood
Orock
O plants
dead bodies

Answers

i think it would be either dead bodies or rocks? i dont really understand too well but sorry if this doesn’t help!! :((

Petrified fossils are made of minerals that have replaced the original matter from wood. Petrified fossils are really rock.

What are Petrified fossils?

These are the fossils that are obtained when there is porous wooden material present and wood from that material is replaced by organic material from minerals.

It is very much similar to creating a mold or statue of what was once there. Very common example is of trees or wood that become petrified fossils, the trees or wood generally turn to stone.

Petrified Wood gets its name from the Greek word “petro” that says the phrase “wood turned to stone” because Petrified Wood is nothing but a stone. When organic material is overrun with minerals such as quartz or silicate, the preservation of the fossil is made possible.

Therefore, Petrified fossils are made of minerals that have replaced the original matter from wood. Petrified fossils are really rock.

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What kind of weather is associated with high air pressure?

Answers


High pressure occur where air sinks.

Creates dry and hot conditions
A high pressure system is a whirling mass of cool, dry air that generally brings fair weather and light winds. High pressure weather tend to be free of clouds. Without clouds, there is no rain and hence the weather tends to be clear and fair.

If you have a 350 gram sample of an isotope with a four-year half-life, how much of the sample would remain after three half-lives? Explain your reasoning.

Answers

After one half life initial amounts gets half so :-

First half life :- 350÷2 = 175 grams second half life :- 175 ÷2 = 87.5 grams third half life :- 87.5 ÷2 = 43.75 grams

so at last of third half life amount left = 43.75 grams

each time amount get half

ask ure doubt freely in comments

Which of the following would be a stable compound?

A.
BeO2

B.
NaS2

C.
KF3

Answers

Answer:

NaS2 it is the most stable

Balance the equation: ___Li3N + ___NH4NO3 -> ___LiNO3 + ___ (NH4)3N

Answers

Answer:

1. Label Each Compound With a Variable

  aLi3N + bNH4NO3 = cLiNO3 + d(NH4)3N

2. Create a System of Equations, One Per Element

  Li: 3a + 0b = 1c + 0d

  N: 1a + 2b = 1c + 4d

  H: 0a + 4b = 0c + 12d

  O: 0a + 3b = 3c + 0d

3. Solve For All Variables (using substitution, gauss elimination, or a calculator)

  a = 1

  b = 3

  c = 3

  d = 1

Explanation:


Kalia spent a quarter of her weekly allowance on a movie. The movie was $4.75. What is her weekly allowance?

Answers

Answer:

$17

Explanation:

$4.75 is equal to 0.75 * x value, where x is the weekly allowance

$4.75=0.75x

$17=x

How could the spread of CCD affect the growth of bee larvae?

Answers

It can effect on leaving a colony basically to die

In counting the electron pairs around the central atom in VSEPR theory, __________ are not included.

Answers

Answer:

See Explanation

Explanation:

Electron pairs about the central element in simple binary compounds can be determined as follows:

Total e⁻ pairs = Bonded e⁻ pairs + Non-bonded e⁻ pairs

Example:

Given XeF₄ determine the total e⁻ pairs about the central element Xe.

Bonded e⁻ pairs = #substrates bonded to central element

                           = 4 Fluoride atoms

                           => 4 Bonded e⁻ pairs

Non-bonded e⁻ pairs = [Valence# - Substrate#] / 2

Valence# = Xe + 4F = 1(8) + 4(7) = 36 valence e⁻s

Substrate# = 4F = 4(8) = 32 bonded e⁻s (about central element)

Non-bonded e⁻ pairs = V# - S# / 2 = 36 - 32 / 2 = 4/2 = 2 non-bonded pr.

Total e⁻ prs around central element = Bonded Pr e⁻ + Non-bonded e⁻

                                                           = 4 + 2 = 6 e⁻ pairs

This implies a Trigonal Bipyramidal parent geometry with a Square Planer molecular geometry.

if you needed a buffer that was 2 ph units away from the pka of your assigned buffer, how would you go about making this buffer

Answers

In order to make a buffer that was 2 pH away from the pka, what you have to do is to dilute the buffer.

How to dilute the buffer.

If the buffer was made using a base and an acid, then there can be an adjustment through the use of hydrochloric acid.

It can also be adjusted to the value that you want through the use of base such as sodium hydroxide

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advantages of fossil fuels

Answers

Answer:

advantages of fossil fuels are:

1. they can generate a large amount of electricity at a single location.

2. they can be found very easily.

3. they are cost-effective.

hope this helps you:)

Answer:

Fossil fuels widely used by we human beings although they cause air pollution when they are burntbfor their use. Due to the following properties found in them, they are being used throughout the world.

They are cheap sources of energy.They can be transported easily so that they are available anywhere.There are very large deposits of fossil fuels inside the earth.They have multipurpose usage.As they are very old sources of energy, a number of machineries have been invented in which fossil fuels are used.

The energy used to power one of the Apollo lunar missions was supplied by
the following overall reaction:
2N2H4 + (CH3)2N2H2 + 3N204 → 6N2 + 2CO2 + 8H20.
For that phase of the mission when the lunar module ascended from the
surface of the moon, a total of 1200.kg of N H4 were available to react with
1000. kg of (CH3)2N2H2 and 4500. Kg of N204.
(a) For this portion of the flight, which of the allocated components
was used up first?
(b) How much water, in kilograms, was left in the lunar
atmosphere through this reaction?
102

Answers

Answer: 2N2H4 + (CH3)2N2H2 + 3N204 → 6N2 + 2CO2 + 8H20.

Explanation:

As per the balanced reaction,  3 moles of N₂O₄ is needed one mole of dimethyl hydrazine and  2 moles of hydrazine. Thus, it is the limiting reactant. The amount of water produced by this reaction will be 2021.73 Kg.

What is limiting reactant?

The reactant which is has fewer number of moles in a reaction and thus, it determines the yields of products is called the limiting reactant. In the given reaction, 2 moles of hydrazine requires 3 moles of nitrogen oxide.

Molar mass of hydrazine = 32 g/mol.

2 moles = 64 g.

Molar mass of N₂O₄ = 60 g/mol

3 moles = 276 g.

64 g needs 276 g. Thus mass of N₂O₄ needed for 1200 Kg is

= (1200000 g × 276 g)/ 64 g

= 5175 Kg

But we have only 4500 Kg N₂O₄ . Thus it is the limiting reactant.  276 g of N₂O₄  produces 8 moles or 124 g of water. Thus mass  of water produced by 4500 kg of N₂O₄  is  calculated as follows:

mass of water =  (4500000 g × 124 g) / 276

                        = 2021.73 Kg.

Therefore, there will be 2021.7 g of water left in the lunar atmosphere through this reaction.

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1. What is the mass of 2.23 x 1023 atoms of sulfur?

Answers

Answer:

La masa de 2,23×10²³ átomos de azufre es 11,85 g

A partir de una comprensión detallada de la hipótesis de Avogadro, entendimos que 1 mol de cualquier sustancia contiene 6,02 × 10²³ átomos.

La afirmación anterior implica que:

6,02×10²³ átomos = 1 mol de azufre

Recordar :

1 mol de azufre = 32 g

Así, podemos decir que:

6,02×10²³ átomos = 32 g de azufre

Con la información anterior , podemos obtener la masa de 2,23×10²³ átomos de azufre. Esto se puede obtener de la siguiente manera:

6,02×10²³ átomos = 32 g de azufre

Por lo tanto,

2,23×10²³ átomos = *la imagen*

2,23×10²³ átomos = 11,85 g de azufre

Así, la masa de 2,23×10²³ átomos de azufre es 11,85 g

Explanation:

The mass of 2.23×10²³ sulfur atoms is 11.85 g

From a detailed understanding of Avogadro's hypothesis, we understood that 1 mole of any substance contains 6.02 × 10²³ atoms.

The above statement implies that:

6.02×10²³ atoms = 1 mole of sulfur

Remember :

1 mole of sulfur = 32 g

Thus, we can say that:

6.02×10²³ atoms = 32 g of sulfur

With the above information, we can obtain the mass of 2.23×10²³ sulfur atoms. This can be obtained as follows:

6.02×10²³ atoms = 32 g of sulfur

Therefore,

2.23×10²³ atoms =*the picture*

2.23×10²³ atoms = 11.85 g of sulfur

Thus, the mass of 2.23×10²³ sulfur atoms is 11.85 g

​can guys help me to answer it​​​​

Answers

12. All of the above
13. False

How do some deep-sea animals use their bioluminescence, or ability to give off light? (

Answers

Certain fish species use bioluminescence as a form of "night light". Some use it for communication. Certain species of crustaceans send out coded signals to others of their own kind during mating season. Other creatures use bioluminescence as a trap.

To avoid being spotted, some deep-sea animals use bioluminescence as a cloaking device. Hatchet fish have light-producing organs in rows along their bellies that allow them to avoid detection — a strategy called counter illumination. These organs shine a pale blue light that matches daylight filtering down from above.

What is Bioluminescence?

Bioluminescence is light produced by a chemical reaction within a living organism.

Bioluminescence is therefore a certain type of chemiluminescence, which is the term used for a chemical reaction where light is produced, but we use bioluminescence because this reaction is taking place inside a living organism.

Most bioluminescent organisms are found in the ocean. These bioluminescent marine species include fish, bacteria, and jellies.

Therefore, To avoid being spotted, some deep-sea animals use bioluminescence as a cloaking device. Hatchet fish have light-producing organs in rows along their bellies that allow them to avoid detection — a strategy called counter illumination. These organs shine a pale blue light that matches daylight filtering down from above.

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A pump with an 80% efficiency drives water up between two reservoirs through a piping system of total length L = 15 and circular cross -section diameter d = 7 cm. The reservoirs are open to the atmosphere at an ambient temperature of 20 C. The difference in elevation between the free surface can be accounted for by the local loss coefficients Kentrance  Kexit 1.0, Kelbow 0.4. If the volumetric flow rate in the system Q = 10 Liter/s, and the surface roughness of the pipe is  = 0.15 mm, calculate:
(a) The average water flow velocity in the pipe.
(b) The Reynolds number.
(c) The friction factor.
(d) The ratio between the friction head loss and other (local) head losses.
(e) The power required to drive the pump.

Answers

The losses in the pipe increases the power requirement of the pipe to

maintain a given flowrate.

Responses (approximate value);

(a) 2.598 m/s

(b) 181,058.58

(c) 0.025

(d) 227:1000

(e) 1,216.67 W

Which methods can be used to calculate the pressure head in the pipe?

The given parameters are;

Pump efficiency, η = 80%

Length of the pipe, L = 15 m

Cross-sectional diameter, d = 7 cm

Reservoir temperature, T = 20°C = 293.15 K

[tex]\mathbf{K_{entrance}}[/tex] ≈ [tex]\mathbf{K_{exit}}[/tex] ≈ 1.0, [tex]\mathbf{K_{elbow}}[/tex] ≈ 0.4

Volumetric flow rate, Q = 10 Liters/s = 0.01 m³/s

Surface roughness, ∈ = 0.15 mm

(a) The cross sectional area of the pipe, A = π·r²

Where;

[tex]r = \mathbf{\dfrac{d}{2}}[/tex]

Which gives;

[tex]r = \dfrac{0.07 \, cm}{2} = \mathbf{0.035 \, cm}[/tex]

[tex]Average \ water \ velocity, \ v =\mathbf{ \dfrac{Q}{A}}[/tex]

Therefore;

[tex]v = \dfrac{0.01}{ \pi \times 0.035^2} \approx 2.598[/tex]

The average velocity of the water, v ≈ 2.598 m/s

(b) The viscosity of water at 20°C is 0.001003 kg/(m·s) given as follows;

Density of water at 20°C, ρ = 998.23 kg/m³

Reynolds' number, Re, is found as follows;

[tex]Re = \mathbf{\dfrac{\rho \cdot V \cdot D}{\mu}}[/tex]

Which gives;

[tex]Re = \dfrac{998.58 \times 2.598 \times 0.07 }{0.001003} \approx \underline{181,058.58}[/tex]

(c) The friction factor is given by the following formula;

[tex]\dfrac{1}{\sqrt{f} } = \mathbf{-2.0 \cdot log \left(\dfrac{\epsilon/D}{3.7} + \dfrac{5.74}{Re^{0.9}} } \right)}[/tex]

Which gives;

f ≈ 0.025

(d) Friction head loss is given as follows;

[tex]h_f = \mathbf{f \times \dfrac{L}{D} \times \dfrac{V^2}{2 \cdot g}}[/tex]

Which gives;

[tex]h_f = 0.025 \times \dfrac{15}{0.07} \times \dfrac{2.598^2}{2 \times 9.81} \approx \mathbf{1.84}[/tex]

[tex]Other \ head \ losses, \ h_l= \sum K \cdot \dfrac{V^2}{2}[/tex]

Which gives;

[tex]h_l=(1 + 1+0.4) \times \dfrac{ 2.598^2}{2} \approx \mathbf{8.0995}[/tex]

Ratio between friction head loss and other head loss is therefore;

[tex]\dfrac{h_f}{h_l} \approx \dfrac{1.84}{8.0995} \approx \underline{0.227}[/tex]

The ratio between friction head loss and other head loss is approximately 227:1000

(e) The power required P is found as follows;

[tex]P= \mathbf{ \dfrac{\rho \cdot g \cdot Q \cdot H}{\eta}}[/tex]

Which gives;

[tex]P= \dfrac{998.23 \times 9.81 \times 0.01 \times (1.84 + 8.0995)}{0.8} \approx \mathbf{ 1216.67}[/tex]

The power required to drive the pump, P ≈ 1,216.67 W

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2) The pH of 1x10-1M (HNO3) solution is:

A)1
B) 1.3
C)5
D)2

Answers

Concentration of H+ ions in HNO3 solution is 10¹ which is equal to 0.1 M

[tex] \bf \: pH \: = - log[{h}^{ + }][/tex]

putting the value we get

[tex] \sf \dashrightarrow \: pH \: = - log \: [ \frac{1}{10}] \\ \\ \sf \dashrightarrow \: pH \: = - log \: {10}^{ - 1} \\ \\ \sf \dashrightarrow \: pH \: = 1[/tex]

So, the required option is A) 1

How does the amount of carbon dioxide affect the rate of photosynthesis?

Answers

Answer:

An increase in the carbon dioxide concentration increases the rate at which carbon is incorporated into carbohydrate in the light-independent reaction, and so the rate of photosynthesis generally increases until limited by another factor.

Explanation:

At the _______ point of a substance, the particles have enough kinetic energy to break free from their fixed positions.

Answers

Answer:

At the nucleus point of a substance, the particles have enough kinetic energy to break free from their fixed positions.

Answer : nucleus

When the seed is fertilized, the sprout turns into an adult before a seedling?

Answers

Yes because it’s growing to become a flower

Identify What part of
Thomson's model are
represented by the
"chocolate chips” in the
ball of cookie dough?

Answers

The part of Thomson's model are represented by the "chocolate chips” are the electrons.

Thomson's model

Thomson's model was the first atomic model to address the electricity of the atom and its divisibility.

In this model, Thomson made an analogy to a cookie dough with chocolate chips, indicating that the atom would be a large positive mass with small negative particles (electrons).

So, the "chocolate chips" in the ball of cookie dough are electrons.

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The empirical formula for cyclohexane is CH2 and its molar mass is 84.18 g/mole. What is its molecular formula?

Answers

Answer:

The empirical formula is C3H4O which would have a formula mass of 56 g/mol (numerically the same as 56 amu/molecule). With a molar mass of 112.

How many moles of oxygen are needed for the complete combustion of 12.6 moles of acetylene?

2C2H2 + 5O2 → 4CO2 + 2H2O

Answers

The moles of oxygen required to completely react with 1-mole acetylene is 2.5 mol.

The moles of reactant and product in a chemical reaction to the whole number ratio is given by the stoichiometric coefficient of the balanced chemical equation.

What is germination?

A. It is the beginning of growth of a plant embryo.

B. It is the transition from a sprout to a seedling.

C. It is the seed being planted into the soil.

D. It is the process of going from a seedling to a tree

Answers

Answer:

it is the seed being planted into the soil

Explanation:

Answer:

C. It is the seed being planted into the soil.

Explanation:

Exactly 25.0 mL of an aqueous solution of barium hydroxide required 32.0 mL of 0.200 M nitric acid to neutralize it. What is the concentration of the barium hydroxide solution?


Give only your numerical answer and do not include the M. For example, 0.262 or 1.25.​

Answers

Answer:

[tex] \frac{0.200 \times 320}{57} = .112[/tex]

Hope this helps

The concentration of 25 ml barium hydroxide required to neutralize 32 ml of 0.200 M nitric acid is 0.256 M.

What is neutralization?

Neutralization is the reaction of acid with base to form a salt of neutrality. The salt formed is not acidic or basic.

In the given reaction, barium hydroxide is a base and nitric acid is the acid and they forms barium nitrate and water.

If the volume and molarity of a solution is given and the molarity or volume either one of the second solution is given, then the unknown quantity of the second solution can be calculated as follows:

M₁V₁ = M₂V₂

Where, M₁ and V₁ is the molarity and volume respectively of first solution and   M₂ and V₂ be that of second solution.

The molarity and volume of nitric acid is 0.200 M and 32.0 ml. Volume of nitric acid is given 25 ml. Thus the molarity of nitric acid is calculated as follows:

Volume of nitric acid = (32 ml × 0.200 M) /25 ml

                                   = 0.256 M

Therefore, the concentration of barium hydroxide required to neutralize 0.200 M nitric acid 0.256 M.

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Name the following compound:
A. Propyl dihydrogen amine
B. ethyl amine
C. Ethyl dihydrogen amine
D. Propyl amine

Answers

Answer:

C. Ethyl dihydrogen amine

Explanation:

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The reaction A + 2B + C → Products has a rate law of Rate = k[A]²[B]. By what factor would the reaction rate change if [C] is tripled?

Answers

The rate of reaction would change by a factor of 1  if [C] is tripled.

What is the rate law?

We know that the rate law is a relationship that shows the connection that exists between the reactants and the products in a given reaction. Now we know that species that appear in the rate law are the species who actually participate in the reaction. If there is any specie that does not participate in the rate determining step of the reaction then it does not in any way appear in the rate determining step of the reaction.

We have the reaction equation as;  A + 2B + C → Products

The we have the rate law for the reaction as;  Rate = k[A]²[B]

We can see that C dos not appear in the rate law thus the formation of the product is independent of the concentration of C.

Thus, the rate of reaction would change by a factor of 1  if [C] is tripled.

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