What is the percent mass of 42.5 g KCl dissolved in 122.5 g water?

Answer:

Linear (180 degrees)

Explanation:

Whenever you have a triple bond between two atoms, their shape is linear. This is because the density of the triple bond between them is heavy, causing the other things attached to the atom to be as far away as possible, creating a linear structure.

A. r: distance

B. q: charge

C. Fe: electric force

D. E: Electric field

So the answer is option C.

How many molecules of carbon dioxide, CO₂, comprise 1.22 moles?

According to Avogadro's Number we have 6.02 * 10^23 molecules in one mol of molecules. So:

1 mol of CO₂ = 6.02 * 10^23 molecules of CO₂

Then:

1.22 moles of CO₂ * 6.02 * 10^23 molecules of CO₂ / 1 mol of CO₂ = 7.34 * 10^23 molecules of CO₂

There are 7.34 * 10^23 molecules of CO₂ in 1.22 moles of it

The relative atomic mass of the given element is 40.372 amu.

The relative atomic mass of an element is considered as the sum of the isotopes masses each multiplied by the percentage which is found in nature.

The formula which is used to calculate the relative atomic mass is

Relative atomic mass = sum of all atomic masses of isotopes × fractional abundance

Given,

Mass of isotopes 1 = 19.19 amu

Mass of isotopes 2 = 20.99 amu

Mass of isotopes 3 = 21.99 amu

Fractional abundance of isotope 1 = 0.9092

Fractional abundance of isotope 2 = 0.0025

Fractional abundance of isotope 3 = 0.0883

By substituting all the values, we get

[( 19.19 × 0.9092) + (20.99 × 0.0025) + (21.99 × 0.883)]

= 17.447 + 0.052 + 22.873

= 40.372 amu.

Thus, we concluded that the relative atomic mass of the given element is 40.372 amu.

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Combination (also called synthesis): Where two elements or one compound and one element will bond and form a new compound as a product, the representation for this reaction is:

A + B -> AB

Decomposition: The opposite from Combination, now one compound will decompose and form 2 new elements or compounds as the product:

AB -> A + B

Single Replacement: One element will take the place of another element in already existing compound:

A + BC -> AB + C

Double Replacement: Now we have two compounds switching elements and forming two new compounds:

AB + CD -> AC + BD

Combustion: Reactions that involve oxygen as reactant and we have CO2 and H2O as products:

X + O2 -> CO2 + H2O

According to the explanation, what we have in this reaction is a Single Displacement reaction, letter A

M = mol/L

To solve for the number of atoms in a certain amount of moles, we must multiply the number of moles by Avogadro's number ([tex]N_A[/tex]): [tex]6.02*10^{23}[/tex], and multiply the product by the number of atoms in the compound.

We're given:

First, we must find the number of moles. We can do this by first converting 800.0 mL to L and multiplying it by 0.10 M.

800.0 mL ÷ 1000 = 0.8 L

⇒ Now, multiply 0.8 L by 0.10 M:

0.8 L × 0.10 M = 0.08 mol

Now, we must find the number of molecules in this sample. Multiply 0.08 mol by Avogadro's number:

[tex]0.08*6.02*10^{23}\\=0.4816*10^{23}\\=4.816*10^{22}[/tex]

Finally, to find the number of atoms in the sample, multiply the number of molecules by the number of atoms in the compound.

We can begin by finding the number of atoms in sucrose:

[tex]C_{12}H_{22}O_{11}[/tex]

12 + 22 + 11 = 45 atoms

⇒ Multiply 45 atoms by [tex]4.816*10^{22}[/tex] mol:

[tex]45*4.816*10^{22}\\=216.72*10^{22}\\=2.1672*10^{24}[/tex]

Convert to the correct number of significant figures (2):

[tex]=2.17*10^{24}[/tex]

[tex]2.17*10^{24}[/tex] atoms

Answer:

1.33 moles

Explanation:

[tex]n = \frac{mass}{molar \: mass} [/tex]

note Molar Mass according to websearch is 64 066

you could calculate this using the individual elements on a periodic table (sulfur and oxygen) and their masses

[tex]n = \frac{85}{64.066} [/tex]

[tex]n = 1.33[/tex]

STP or Standard Pressure and Temperature is widely used when the subject is gases. The used standard temperature is 273 K or 0°C and the standard temperature used is 1 atm. At these conditions 1 mol will be equal to 22.4 L of volume, therefore if we have 11.2 L of Argon:

22.4 L = 1 mol

11.2 L = x moles of Argon

22.4x = 11.2 L

x = 0.500 moles of Ar will be present in 11.2 L of volume

Ions can travel directly from the cytoplasm of one animal cell to the cytoplasm of an adjacent cell through  gap junctions.

Cytoplasm is the gelatinous liquid that fills the inside of a cell.

The cytoplasm is composed of water, salts, and various organic molecules. Some intracellular organelles, such the nucleus and mitochondria, are enclosed by membranes that separate them from the cytoplasm.

The cytoplasm has the following functions :

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Answer:

Ammonium hydroxide. Ammonium hydroxide is an inorganic herbicide, fungicide and microbiocide.It is non-volatile and highly soluble in water.

Explanation:

According to the concept of solubility, ammonium hydroxide is insoluble in water.

Solubility is defined as the ability of a substance which is basically solute to form a solution with another substance. There is an extent to which a substance is soluble in a particular solvent. This is generally measured as the concentration of a solute present in a saturated solution.

The solubility mainly depends on the composition of solute and solvent ,its pH and presence of other dissolved substance. It is also dependent on temperature and pressure which is maintained.Concept of solubility is not valid for chemical reactions which are irreversible. The dependency of solubility on various factors is due to interactions between the particles, molecule or ions.

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According to the stoichiometry, 4.85 g of propane is required to produce 14.7 g carbon dioxide.

It is the determination of proportions of elements or compounds in a chemical reaction. The related relations are based on law of conservation of mass and law of combining weights and volumes.

Stoichiometry is used in quantitative analysis for measuring concentrations of substances present in the sample.

In the given problem as per balanced equation of combustion of propane 2 molecules of propane produce  8 molecules of carbon dioxide.That is, 116.24 g of propane produces 352.08 g of carbon dioxide.

∴14.7 g of carbon dioxide is produced by, 14.7×116.24/352.08=4.85 g of propane.

Thus, 4.85 g of propane is required to produce 14.7 g of carbon dioxide.

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Answer:

Explanations:

Answer:

Explanations:

Answer:

NaOH

Explanation:

Sodium hydroxide is a proton acceptor. Metal hydroxides are almost always bases. H₂O is water and is neutral. Sodium is a positively charged metallic ion. Hydroxide is a negatively charged ion.

To solve this question we will use the integrated rate late law for first order reaction:

By substituting the values we have to determine the unknown we get:

Answer: Rate constant k is 6.392x10^-4 per min.

The PV work formula is:

w = -Pexternal * ΔV

w = -44.0 atm * (89.0 - 90.0)

w = -44.0 atm * -1 L

w = 44.0 L atm

For each L atm, we will have 101.325 Joules, therefore

44.0 L atm * 101.325 J

w = 4458.3 J or 4.4 kJ

Answer:

Explanation:

Here, we want to select the correct option

We evaluate each of the options as follows:

a) Boiling

It is a state that occurs when the vapor pressure equals atmospheric pressure for liquid substances

b) Evaporation

Evaporation occurs when liquid substances change directly into the gaseous state

c) Melting is the change from the solid state to the liquid state

d) Sublimation is the direct change of a substance from the solid to the vapor state. We can see this in iodine and naphthalene

Step 1

The reaction involved:

2 KClO3 => 2 KCl + 3 O2 (completed and balanced)

------------

Step 2

Data provided:

Mass of KClO3 = 163.27 g

---

Data needed:

The molar mass of:

KClO3) 122.6 g/mol

O2) 32.00 g/mol

-------------

Step 3

Procedure:

By stoichiometry,

2 KClO3 => 2 KCl + 3 O2

2 x 122.6 g KClO3 ------ 3 x 32.00 g O2

163.27 g KClO3 ------ X

X = 163.27 g KClO3 x 3 x 32.00 g O2/2 x 122.6 g KClO3

X = 63.92 g

Answer: 63.95 g (the nearest value)

0.167L

In order to know how much L of the 3M NaOH solution would you need, we will simply set up an equal proportion solution expressed as;

C1 and C2 are the concentration of the solutions

V1 and V2 are the volumes of the solutions

Given the following parameters;

C1 = 1M

V1 = 500mL

C2 = 3M

V2 = ?

Substitute the given parameters into the formula above to get the required litre of solution needed.

Divide both sides by 3:

Converting to litres

Since 1mL = 0.001L

166.67mL = x

Cross multiply

Hence the amount of L of the 3M NaOH solution would you need is 0.167L

2 brome butane

it has 4 C atoms therefor we know it is a butan-- and the brome is placed in the second carbone so that gives the answer 2 brome butane

Answer

B - They increase the H+ concentration in solution.

Explanation

All acids contain H+ for example, HCl contributes H+ ions into the solution, which decreases the pH of the solution. for example, a base, NaOH increases the concentration of OH⁻ ions and decreases the concentration of H⁺ ions. Therefore all acids increase the H+ concentration in solution.

827.76 m/60.65 s = 13.65 m/s

685.5 mol/0.50 L = 1371 mol/L

20.9476 cm x 26 cm = 545 cm^2

When adding/subtracting

Use the least number of significant figures past the decimal point when adding or subtracting numbers.

When multiplying/dividing

Use the least number of significant figures present in any number in the problem when multiplying or dividing numbers.

The mass of quinine in the original tonic water sample is 37.8 mg.

The concentration of the diluted sample with a fluorescence intensity of 73.7 is calculated using the formula of Lambert-Beer's law as follows:

C₁/C₂ = A₁/A₂

where:

C₁ = 25 ppm or 25 mg/L

C₂ = ?

A₁ = 195

A₂ = 73.7

C₂ = 73.7 * 25 / 195

C₂ = 9.45 mg/L

To concentration of the original sample will be determined from the dilution formula:

C₁V₁ = C₂V₂

where;

C₁ = ?

V₁ = 25. 0 mL

C₂ = 9.45 mg/L

V₂ = 200 mL

C₁ = 9.45 * 200 / 25

C₁ = 75.6 mg/L

The volume of the stock sample was 500 mL or 0.5 L

The mass of quinine = 75.6 mg/L * 0.5 L

mass of quinine = 37.8 mg

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Answer:

0.124 M.

Explanation:

What is given?

Volume 1 (V1) = 239 mL,

Concentration 1 (C1) = 0.274 M,

Volume 2 (V2) = 239 mL + 288 mL = 527 mL.

What do we need? Concentration 2 (C2).

Step-by-step solution:

To solve this problem, we have to use the following formula:

Where the initial concentration (C) and volume (V) are represented with subindex 1, and the final concentration and volume are represented with subindex 2.

The problem is telling us that we are adding 288 mL of water to 239 mL, so the final volume is the sum of these two volumes, i.e., 527 mL.

As we want to find the final concentration, C2, we just have to solve for this unknown value and replace the values that we have, like this:

The answer would be that the final concentration of the solution is 0.124 M.

After one of the reactants has been totally consumed, the moles of HCl that have been produced is 20 moles.

The mole ratio of the reactants in the reaction is given below:

Equation of the reaction:

C₃H₈ + 4 Cl₂ --> C₃H₄Cl₄ + 4 HCl

The mole ratio of C₃H₈ and Cl₂  is 1 : 4

The mole ratio of the reactants, C₃H₈ and Cl₂  present is 6 : 20

mole ratio of the reactants, C₃H₈ and Cl₂  present is 3 : 10

Hence the limiting reactant is  Cl₂

Moles of HCl to  Cl₂  is 1  : 1.

Hence, the moles of HCl produced will be 20 moles

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Answer:

All atoms of a specific element are identical in mass, size, and other properties. However, atoms of different element exhibit different properties and vary in mass and size. Atoms can neither be created nor destroyed. Furthermore, atoms cannot be divided into smaller particles.

Answer:

the more hotter the star, the more brightly it burns

Explanation:

someone just deleted my answer ugh sorry....ill write it again

so, te main sequence is a sequence in mass (and not a sequence in time).

The most massive stars are located at the the top left (since they are the brightest and hottest/bluest). The lowest mass stars are are located at the bottom left ( since they dimmer and cooler/redder).

Following the main sequence from the top left to the bottom right is thus a sequence from high to low mass.

The amount of heat, in kilojoules, that is required to melt 15 g of ice at 0 degrees Celsius and raise the temperature of the liquid to 85 degrees Celsius is 10.3178 kJ.

The process involves melting of ice at 0 degrees Celsius and then heating the resulting water to a temperature of 85 degrees Celsius.

Now, let's calculate the heat change of the process:

Heat change (ΔH) = n x heat of fusion) + mcΔt

Where n = number of moles

           m = mass = 15 g

           c = specific heat capacity of water = 4.81 J/g[tex]^oC[/tex]

           heat of fusion = 6010 J/mole

In this case, n = mass/molar mass

                       = 15/18

                       = 0.83 moles

ΔH = (0.83 x 6010) + 15 x 4.81 x (85 - 0)

      = 10317.8 Joules

But 1000 Joules = 1 kilojoules

Thus, 10317.8 joules = 10.3178 kJ

The kilojoule of heat required to melt the ice and raise the temperature of the resulting water to 85 degrees Celsius is 10.3178 kJ.

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