what is the result if you divide -12x^8y^8 by 3x^4y^2

Answer: 11 to the power of three

Answer

3 to the power of 11

Step-by-step explanation:

Answer:

im not sure i got stuck here ;; but i started sort of

Step-by-step explanation:

The first step is to get the inner angles. I'll start with the one at 60 degrees and call it A and go counter clockwise

A flat angle is 180 and -60 makes it 120 = Angle A

180-100=80=B
180-20=160=C

Then when you're trying to calculate a figure with more than 4 corners, you're supposed to divide them into triangles. Now we have a hexagon and the total degrees is 720. And we know that we have 2 6x and they're the angles

Answer:

-1

Step-by-step explanation:

[tex](-4 +6)( -5 +2 )\\ - 4 + 6 = 2 \\ - 5 +2 = - 3 \\ 2 - 3 = - 1[/tex]

Answer:

-1

Step-by-step explanation:

Necesitas agregar 6 a 4 negativo, luego obtienes 2, luego restas eso a 5 y obtienes -3 y luego sumas 2 para dejarte con -1.

I put Spanish and English just in case.

You need to add 6 to negative 4 then you get 2 then subtract that to 5 and you get -3 then add 2 to leave you with -1.

Answer:

Step-by-step explanation:

Answer:

y=3x+6

Step-by-step explanation:

50.26 in.

12 + 5 + 5 + (3.14 x 9)

Let p(x) be any polynomial of degree greater than or equal to one and let 'a' be any real number. If a polynomial p(x) is divided by x - a then the remainder is p(a). Hence by the remainder theorem, 0 is the remainder when x3 + 3x2 + 3x + 1 is divided by x + 1.

Answer:

20% of $68 is $13.60

Step-by-step explanation:

 (20/100)x68

(20x68)/100 

1360/100 = 13.6

Answer:

If the current population is 850,000. Next year it will be 935,000, and the year following that it will be 1,028,500. This is a linear growth (its growth has a common ratio).

Answer:

1,028,500 people

Step-by-step explanation:

When finding the percentage of a number you moved the decimal place over twice and then multiply.

850,000 x 0.10 = 85,000

10% of 850,000 is 85,000

I then found the population of the 1st year

85,000 + 850,000 = 935,000

then I found 10% of that 1st year

935,000 x 0.10 = 93,500

then added 85,000 and 93,500 to find the population growth in the 2 years

85,000 + 93,500 = 178,500

Then added the population growth to the original population

178,500 + 850,000 = 1,028,500 people

(I'm sorry, my last answer was wrong)

Hope this helps! :)

Answer:

it's by "Say, can you see

By"

Answer: 200% increase

Step-by-step explanation:

Being an increase from 12inches to 36inches, we will calculate the percentage increase.

%increase = final length -initial length/initial length × 100%

Initial length = 12inches

Final length = 36inches

%increase = 36-12/12 × 100%

%increase = 24/12 × 100%

%increase = 200%

Answer:

200% increase

Step-by-step explanation:

percent change = [(difference between initial and final value) ÷ initial value] x 100

⇒ percent change = [(36 - 12) ÷ 12] x 100 = 200% increase

Answer:

Step-by-step explanation:

Simplified expression:

[tex]3x^3 -x^3 +5x^3-9x^3[/tex]

[tex]2x^3 +5x^3-9x^3[/tex]

[tex]7x^3 -9x^3[/tex]

[tex]-2x^3[/tex]

If x = -1, the value of the expression is:

[tex]-2x^3[/tex]

[tex]-2(-1^3)[/tex]

[tex]-2(-1)[/tex]

[tex]2[/tex]

Hope this helps!

Answer:

1)6.000

2)8.935.600

5)70.000

4)2.509.200

7)6.000

8)9.000

10)5.800

11)6.900.000

13)5.000

14)2.000

16)5.000

17)6.400

Step-by-step explanation:

if you a line on the  numbers you will see it easy

Answer:

I think it's 15 students

Step-by-step explanation:

i think since 150 is half of 300 so in each class there should also be half of the people wearing red

Answer:

150 of 300, 150 is 50 % of 300 so 300/30 = 1 , so I think 15 of the students should be wearing red

Step-by-step explanation:

Answer:

Well

If we choose plan B then it would be better. 15 cents a messages would be 3 messages in total if we choose plan b.

Step-by-step explanation:

Answer:

Step-by-step explanation:

You can use synthetic division method.

P(x) =x² + x  - 2

(x + 2) is a factor.

Image attached.

[tex]\textit{Logarithm Change of Base Rule} \\\\ \log_a b\implies \cfrac{\log_c b}{\log_c a}\qquad \qquad c= \begin{array}{llll} \textit{common base for }\\ \textit{numerator and}\\ denominator \end{array} \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ \log_5(18)\implies \cfrac{\log(18)}{\log(5)}\implies \cfrac{\log(2\cdot 3\cdot 3)}{\log(5)}\implies \cfrac{\log(2)+\log(3)+\log(3)}{\log(5)}[/tex]

[tex]\begin{cases} \log(3)=a\\ \log(2)=b\\ \log(5)=c \end{cases}\implies \cfrac{b+a+a}{c}\implies \cfrac{b+2a}{c} \\\\[-0.35em] ~\dotfill\\\\ \log_5^2(18)\implies [\log_5(18)]^2\implies \left( \cfrac{b+2a}{c} \right)^2\implies \cfrac{(b+2a)^2}{c^2} \\\\[-0.35em] ~\dotfill\\\\ ~\hfill \cfrac{b^2+4ab+4a^2}{c^2}~\hfill[/tex]

Solution:

Note that:

Substituting the values into the equation:

This means that Jack has 99 + b buttons.

Answer/Step-by-step explanation:

72/12=6

6x5=30

30 points.

Answer:

40 degrees

Step-by-step explanation:

This is a 40 degree angle

Hope this helps!

Answer:

I did this. But there's only 5 points . But it's ok

Answer:

3.374

Step-by-step explanation:

[tex]\mathrm{Write\:the\:numbers\:one\:under\:the\:other,\:line\:up\:the\:decimal\:points.}[/tex]

[tex]\mathrm{Add\:trailing\:zeroes\:so\:the\:numbers\:have\:the\:same\:length.}[/tex]

[tex]\begin{matrix}\:\:&5&.&3&1&6\\ -&1&.&9&4&2\end{matrix}[/tex]

[tex]\mathrm{Subtract\:each\:column\:of\:digits,\:starting\:from\:the\:right\:and\:working\:left}[/tex]

[tex]\mathrm{In\:the\:bolded\:column,\:subtract\:the\:second\:digit\:from\:the\:first}:\quad \:6-2=4[/tex]

[tex]\frac{\begin{matrix}\:\:&5&.&3&1&\textbf{6}\\ -&1&.&9&4&\textbf{2}\end{matrix}}{\begin{matrix}\:\:&\:\:&\:\:&\:\:&\:\:&\textbf{4}\end{matrix}}[/tex]

[tex]\mathrm{In\:the\:bolded\:column,\:subtract\:the\:second\:digit\:from\:the\:first}[/tex]

[tex]\frac{\begin{matrix}\:\:&5&.&3&\textbf{1}&6\\ -&1&.&9&\textbf{4}&2\end{matrix}}{\begin{matrix}\:\:&\:\:&\:\:&\:\:&\textbf{\:\:}&4\end{matrix}}[/tex]

[tex]\mathrm{The\:bottom\:number\:is\:larger\:than\:the\:upper\:number.\:\:Try\:to\:'borrow'\:a\:digit\:from\:the\:left.}[/tex]

[tex]\mathrm{The\:top\:digit\:is\:not\:bigger\:than\:the\:bottom\:one.\:\:Try\:to\:'borrow'\:a\:digit\:from\:the\:left.}[/tex]

[tex]\frac{\begin{matrix}\:\:&5&.&\textbf{3}&1&6\\ -&1&.&\textbf{9}&4&2\end{matrix}}{\begin{matrix}\:\:&\:\:&\:\:&\textbf{\:\:}&\:\:&4\end{matrix}}[/tex]

[tex]\mathrm{Borrow\:}1\mathrm{\:from\:}5\mathrm{.\:\:The\:remainder\:is\:}4[/tex]

[tex]\frac{\begin{matrix}\:\:&\textbf{4}&\:\:&10&\:\:&\:\:\\ \:\:&\textbf{\linethrough{5}}&.&3&1&6\\ -&\textbf{1}&.&9&4&2\end{matrix}}{\begin{matrix}\:\:&\textbf{\:\:}&\:\:&\:\:&\:\:&4\end{matrix}}[/tex]

[tex]\mathrm{Add\:}1\mathrm{\:ten\:to\:}3:\quad \:10+3=13[/tex]

[tex]\frac{\begin{matrix}\:\:&4&\:\:&\textbf{13}&\:\:&\:\:\\ \:\:&\linethrough{5}&.&\textbf{\linethrough{3}}&1&6\\ -&1&.&\textbf{9}&4&2\end{matrix}}{\begin{matrix}\:\:&\:\:&\:\:&\textbf{\:\:}&\:\:&4\end{matrix}}[/tex]

[tex]\mathrm{Borrow\:}1\mathrm{\:from\:}13\mathrm{.\:\:The\:remainder\:is\:}12[/tex]

[tex]\frac{\begin{matrix}\:\:&4&\:\:&\textbf{12}&10&\:\:\\ \:\:&\linethrough{5}&.&\textbf{\linethrough{13}}&1&6\\ -&1&.&\textbf{9}&4&2\end{matrix}}{\begin{matrix}\:\:&\:\:&\:\:&\textbf{\:\:}&\:\:&4\end{matrix}}[/tex]

[tex]\mathrm{Add\:}1\mathrm{\:ten\:to\:}1:\quad \:10+1=11[/tex]

[tex]\frac{\begin{matrix}\:\:&4&\:\:&12&\textbf{11}&\:\:\\ \:\:&\linethrough{5}&.&\linethrough{13}&\textbf{\linethrough{1}}&6\\ -&1&.&9&\textbf{4}&2\end{matrix}}{\begin{matrix}\:\:&\:\:&\:\:&\:\:&\textbf{\:\:}&4\end{matrix}}[/tex]

[tex]\mathrm{In\:the\:bolded\:column,\:subtract\:the\:second\:digit\:from\:the\:first}:\quad \:11-4=7[/tex]

[tex]\frac{\begin{matrix}\:\:&4&\:\:&12&\textbf{11}&\:\:\\ \:\:&\linethrough{5}&.&\linethrough{13}&\textbf{\linethrough{1}}&6\\ -&1&.&9&\textbf{4}&2\end{matrix}}{\begin{matrix}\:\:&\:\:&\:\:&\:\:&\textbf{7}&4\end{matrix}}[/tex]

[tex]\mathrm{Place\:the\:decimal\:point\:in\:the\:answer\:directly\:below\:the\:decimal\:points\:in\:the\:terms}[/tex]

[tex]\frac{\begin{matrix}\:\:&4&\textbf{\:\:}&12&11&\:\:\\ \:\:&\linethrough{5}&\textbf{.}&\linethrough{13}&\linethrough{1}&6\\ -&1&\textbf{.}&9&4&2\end{matrix}}{\begin{matrix}\:\:&\:\:&\textbf{.}&3&7&4\end{matrix}}[/tex]

[tex]\mathrm{In\:the\:bolded\:column,\:subtract\:the\:second\:digit\:from\:the\:first}:\quad \:4-1=3[/tex]

[tex]\frac{\begin{matrix}\:\:&\textbf{4}&\:\:&12&11&\:\:\\ \:\:&\textbf{\linethrough{5}}&.&\linethrough{13}&\linethrough{1}&6\\ -&\textbf{1}&.&9&4&2\end{matrix}}{\begin{matrix}\:\:&\textbf{3}&.&3&7&4\end{matrix}}[/tex]

[tex]=3.374[/tex]

Hence the correct answer is 3.374

Slope of line passing through two points (x1,y1 ) and (x2 ,y2 ) is given by

m= y2-y1/x2 −x1

Since the line passes through (−2,5) and (6,4)

We have

Slope(m)= 4-5/6−(−2) =− 1/8

To find the area of the shape which is the shaded area I assume: we must find the sum of the area of the rectangle AECD and triangle BEC

   Total Area =area of rectangle AECD + triangle BEC

                     = 9 * 15 +  (1/2) * 6 * 15 = 136 + 45 = 181 square milimeters

Hope that helped!

Answer:

Frank is correct, because (see explanation below)

Step-by-step explanation:

Let's separate into two cases:

Case 1: Blue marble

[tex]\frac{6}{7}[/tex] (There are 6 blues in the bag and 7 marbles in total in the bag, we put the 6 in the numerator because we want a blue marble first.)

Case 2: Green marble

[tex]\frac{1}{6}[/tex] (There is only 1 green in the bag and 6 marbles remaining in the bag, because we already took 1 blue out in Case 1. We put 1 in the numerator because we want the green marbloe only.)

Multiply Case 1 with Case 2 because they are a combination:

[tex]\frac{6}{7} * \frac{1}{6} = \frac{1}{7}[/tex]

Therefore Frank is correct.

Answer:

y = 11

Step-by-step explanation:

being equilateral triangle

Answer:

a translation moves a thing up and down or left and right.

Step-by-step explanation:

so true?

Answer:

True

Step-by-step explanation:

A translation means you are moving a figure in some direction(s). This can mean both vertically and horizontally.

Answer:

option a please mark me as brainlist please

Answer:

6 4/11

Step-by-step explanation:

Answer: Yes, because with each round table, the amount of chair goes up by 5.