What is the slope of the line below? If necessary, enter your answer as afraction in lowest terms, using the slash (/) as the fraction bar. Do not enteryour answer as a decimal number or an equation.
Answers
To find the slope of a line use two points (x,y) in the next formula:
[tex]m=\frac{y_2-y_1}{x_2-x_1}[/tex]In the given line you have the points: (-4, -9) and (-2, -3)
[tex]m=\frac{-3-(-9)}{-2-(-4)}=\frac{-3+9}{-2+4}=\frac{6}{2}=3[/tex]Then, the slope of the given line is 3Related Questions
What is the slope of a line that is perpendicular to the line whose equation is 3x+2y=6?A. −3/2B. −2/3C. 3/2D. 2/3
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We would begin by determining the slope of the line given;
[tex]3x+2y=6[/tex]To determine the slope, we would have to express the equation of the line in slope-intercept form as follows;
[tex]y=mx+b[/tex]Therefore, we need to make y the subject of the equation as shown below;
[tex]\begin{gathered} 3x+2y=6 \\ \text{Subtract 3x from both sides of the equation} \\ 2y=6-3x \\ \text{Divide both sides by 2 } \\ \frac{2y}{2}=\frac{6-3x}{2} \\ y=\frac{6}{2}-\frac{3x}{2} \\ y=3-\frac{3}{2}x \end{gathered}[/tex]The equation in slope-intercept form appears as shown above. Note that the slope is given as the coefficient of x.
Note alo that the slope of a line perpendicular to this one would be a "negative inverse" of the one given.
If the slope of this line is
[tex]-\frac{3}{2}[/tex]Then, the inverse would be
[tex]-\frac{2}{3}[/tex]The negative of the inverse therefore is;
[tex]\begin{gathered} (-1)\times-\frac{2}{3} \\ =\frac{2}{3} \end{gathered}[/tex]The answer therefore is option D
Please someone can help me please #1
Answers
Complete the following Division
Quotient of 96, 55, 84 and 63 is 12, 11, 14 and 21 respectively
What is Division?
One of the four fundamental arithmetic operations, or how numbers are combined to create new numbers, is division. The other operations are multiplication, addition, and subtraction.
1) 96
Divisor = 8
96 / 8
= 12
Quotient = 12
2) 55
Divisor = 5
55 / 5
= 11
Quotient = 11
3) 84
Divisor = 6
84 / 6
= 14
Quotient = 14
4) 63
Divisor = 3
63 / 3
= 21
Quotient = 21
Hence , Quotient of 96, 55, 84 and 63 is 12, 11, 14 and 21 respectively
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i inserted a picture of the question please state whether the answer is a b c or d please don’t ask questions, yes i’m following.
Answers
Solution
- We are asked to find the complement of rolling a 5 or 6 given a cube numbered 1 - 6.
- The complement of an event is defined as every other event asides the event in context.
- Other than rolling a 5 or 6, we can also roll a 1, 2, 3, or 4. This constitutes the complement of rolling 5 or 6.
Final Answer
The complement of rolling a 5 or 6 is:
{Rolling a 1, 2, 3, or 4} (OPTION B)
identify point in region of inequalities
Answers
We want to picture the inequalities
[tex]y<\text{ - x -3}[/tex]and
[tex]y>\frac{4}{5}x\text{ +5}[/tex]First, we consider the lines y= -x -3 and and y=(4/5) x +5 . Since the first line has a negative slope, this means that its graph should go downwards as x increases and since the other line has a positive slope, this means that its graph should go upwards as x increases. This leads to the following picture
Now, the expression
[tex]y<\text{ -x -3}[/tex]means that the y coordinate of the line should be below the red line. Also, the expression
[tex]y>\frac{4}{5}x+5[/tex]means tha the y coordinate should be above the blue line. If we combine both conditions, we find the following region
so we should look for a point that lies in this region
We are given the points (-1,9), (-6,2), (9,-9) and (-8,-5).
We see that the yellow region is located where the x coordinate is always negative. So, this means that we discard (9,-9).
so we should test the other points. Since -8 is the furthest to the left, let us calculate the value of each line at x=-8.
[tex]\text{ -(-8) -3 = 8 -3 = 5}[/tex]so, in this case the first expression is accomplished since -5 < 5. And
[tex]\frac{4}{5}\cdot(\text{ -8)+5= =}\frac{\text{ -7}}{5}=\text{ -1.4}[/tex]However note that -5 < 1.4, and it should be greater than -1.4 to be in the yellow region. So we discard the point (-8,-5) .
We can check , iusing the graph, that the lines cross at the point (-40/9, 13/9) which is about (-4.44, 1.44). This means that for the point to be on the yellow region, it should be on the left of -4.44. Since the only point that we are given that fulfills this condition is (-6, 2), this should be our answer. We check that
[tex]\text{ -(-6)-3=3>2}[/tex]and
[tex]\frac{4}{5}\cdot(\text{ -6)+5 = }\frac{1}{5}=0.2<2[/tex]so, the point (-6,2) is in the yellow region
Finding Angles with JustificationIn the diagram below BC = EC and m
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Answer:
Angle Reason
m∠ECD = 140 Given
m∠ECB = 40 Supplementary angles
m∠EBC = 70 Isosceles triangle
m∠ABE = 110 Supplementary angles
Explanation:
Angle ECB and CED are supplementary because they form a straight line and their sum is 180 degrees. So, we can calculate the measure of ∠ECB as
m∠ECB = 180 - 140
m∠ECB = 40
Then, the interior sum of the angles of a triangle is equal to 180 degrees, so
m∠ECB + m∠EBC + m∠BEC = 180
40 + m∠EBC + m∠BEC = 180
However, m∠EBC = m∠BEC because triangle ABC is an isosceles triangle where 2 sides have the same length BC and EC. So, we can find m∠EBC as follows
40 + m∠EBC + m∠EBC = 180
40 + 2m∠EBC = 180
40 + 2m∠EBC - 40 = 180 - 40
2m∠EBC = 140
m∠EBC = 140/2
m∠EBC = 70
Then, the measure of ∠ABE is equal to
∠ABE = 180 - m∠EBC
∠ABE = 180 - 70
∠ABE = 110
Therefore, we can answer it as follows
Angle Reason
m∠ECD = 140 Given
m∠ECB = 40 Supplementary angles
m∠EBC = 70 Isosceles triangle
m∠ABE = 110 Supplementary angles
Curt and melanie are mixing blue and yellow paint to make seafoam green paint. Use the percent equation to find how much yellowp they should use.
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To solve the exercise you can use the rule of three, like this
[tex]\begin{gathered} 1.5\text{ quarts}\rightarrow100\text{ \% }\Rightarrow\text{ Green paint} \\ x\text{ quarts}\rightarrow30\text{ \%}\Rightarrow\text{ Yellow paint} \end{gathered}[/tex][tex]\begin{gathered} x=\frac{30\text{ \% }\ast\text{ 1.5 quarts}}{100\text{ \%}} \\ x=0.45\text{ quarts} \end{gathered}[/tex]Therefore, Curt and Melanie should use 0.45 quarts of yellow paint to make seafoam green paint.
write a quadratic fuction f whose zeros are -3 and -13
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The zeros of a quadratic function are the points where the graph cuts the x axis.
If one zero is - 3, it means that
x = - 3
x + 3 = 0
Thus, one of the factors is (x + 3)
If another zero is - 13, it means that
x = - 13
x + 13 = 0
Thus, one of the factors is (x + 13)
Thus, the quadratic function would be
(x + 3)(x + 13)
We would open the brackets by multiplyingeach term inside one bracket by each term inside the other. Thus, we have
x * x + x * 13 + 3 * x + 3 * 13
x^2 + 13x + 3x + 39
x^2 + 16x + 39
Thus, the quadratic function is
f(x) = x^2 + 16x + 39
Suppose you have $14,000 to invest Which of the two rates would yield the larger amount in 2 years 6% compounded monthly or 5.88% compounded continuously?
Answers
We were given a principal to invest ($14,000) in a timespan of 2 years, and we need to choose between applying it on an account that is compounded montlhy at a rate of 6%, and one that is compounded continuously at a rate of 5.88%. To solve this problem, we need to calculate the final amount on both situations, and compare them.
The expression used to calculate the amount compounded monthly is shown below:
[tex]A=P(1+\frac{r}{12})^{12\cdot t}[/tex]Where A is the final amount, P is the invested principal, r is the interest rate and t is the elapsed time.
The expression used to calculate the amount compounded continuously is shown below:
[tex]A=P\cdot e^{t\cdot r}[/tex]Where A is the final amount, P is the invested principal, r is the interest rate, t is the elapsed time, and "e" is the euler's number.
With the two expressions we can calculated the final amount on both situations, this is done below:
[tex]\begin{gathered} A_1=14000\cdot(1+\frac{0.06}{12})^{12\cdot2} \\ A_1=14000\cdot(1+0.005)^{24} \\ A_1=14000\cdot(1.005)^{24} \\ A_1=14000\cdot1.127159 \\ A_1=15780.237 \end{gathered}[/tex][tex]\begin{gathered} A_2=14000\cdot e^{0.0588\cdot2} \\ A_2=14000\cdot e^{0.1176} \\ A_2=14000\cdot1.124794 \\ A_2=15747.12 \end{gathered}[/tex]The first account, that is compounded monthly yields a return of $15780.24, while the second one that is compounded continuously yields a return of $15747.12, therefore the first account is the one that yield the larger amount in 2 years.
Cynthia wants to buy a rug for a room that is 18ft wide and 28ft long. She wants to leave a uniform strip of floor around the rug. She can afford to buy 264 square feet of carpeting. What dimensions should the rug have ?
Answers
SOLUTION
Let us use a diagram to illustrate the information, we have
Now, from the diagram, let the length of the uniform strip of floor around the rug be x, So, this means the length and width of the rug is
[tex]\begin{gathered} \text{length = 2}8-x-x=28-2x \\ \text{width = }18-x-x=18-2x \end{gathered}[/tex]Now, since she can afford to buy a rug of 264 square feet for carpeting, this means that the area of the rug is 264, hence we have that
[tex]\begin{gathered} \text{area of rug = (2}8-2x)\times(18-2x) \\ 264=\text{(2}8-2x)(18-2x) \\ \text{(2}8-2x)(18-2x)=264 \end{gathered}[/tex]Solving for x, we have
[tex]\begin{gathered} \text{(2}8-2x)(18-2x)=264 \\ 504-56x-36x+4x^2=264 \\ 504-92x+4x^2=264 \\ 4x^2-92x+504-264=0 \\ 4x^2-92x+240=0 \end{gathered}[/tex]Dividing through by 4 we have
[tex]\begin{gathered} x^2-23x+60=0 \\ x^2-20x-3x+60=0 \\ x(x-20)-3(x-20)=0 \\ (x-3)(x-20)=0 \\ x=3\text{ or 20} \end{gathered}[/tex]So from our calculation, we go for x = 3, because 20 is large look at this
[tex]\begin{gathered} \text{From the length which is (2}8-2x) \\ 28-2(20) \\ =28-40=-12 \end{gathered}[/tex]length cannot be negative, so we go for x = 3.
Hence the dimensions of the rug becomes
[tex]\begin{gathered} \text{(2}8-2x) \\ =28-2(3) \\ =28-6=22 \\ \text{and } \\ 18-2x \\ 18-2(3) \\ 18-6=12 \end{gathered}[/tex]So the dimension of the rug should be 22 x 12 feet
for each triangle identify a base and corresponding height use them to find the are
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A)
For this tringle we can turn the figure like this:
now we have two right triangles and we can calulate the base of the first triangle with the sin law
[tex]\begin{gathered} \frac{\sin (90)}{3}=\frac{sin(a)}{2.5} \\ \sin (a)=\frac{2.5\sin (90)}{3} \\ \sin (a)=0.8 \\ a=\sin ^{-1}(0.8)=53º \end{gathered}[/tex]the angle b is going to be:
[tex]\begin{gathered} 180=90+53+b \\ b=180-90-53 \\ b=37 \end{gathered}[/tex]Now the base is going to be:
[tex]\begin{gathered} \frac{\sin(90)}{3}=\frac{\sin(37)}{\text{base}} \\ \text{base}=\frac{3\sin (37)}{\sin (90)}=1.8 \end{gathered}[/tex]and the base of the secon triangle is going to be:
[tex]\text{base}2=7.2-1.8=5.4[/tex]And the area of the triangles is going to be:
[tex]A1=\frac{base\times2.5}{2}=\frac{1.8\times2.5}{2}=2.25[/tex][tex]A2=\frac{base2\times2.5}{2}=\frac{5.4\times2.5}{2}=6.75[/tex]so in total the area is going to be:
[tex]A1+A2=2.25+6.75=9[/tex]B)
the procedure is similar, first we turn the tiangle like this:
the angle a is going to be:
[tex]\begin{gathered} \frac{\text{sin(a)}}{4.8\text{ }}=\frac{\sin (90)}{6} \\ \sin (a)=\frac{4.8\sin (90)}{6}=0.8 \\ a=\sin ^{-1}(0.8) \\ a=53º \end{gathered}[/tex]the angle b is going to be:
[tex]\begin{gathered} 180=90+53+b \\ b=180-90-53 \\ b=37º \end{gathered}[/tex]now the base is going to be:
[tex]\begin{gathered} \frac{\sin (37)}{base}=\frac{sen(90)}{4.8} \\ \text{base}=\frac{4.8\sin (37)}{\sin (90)} \\ \text{base}=2.8 \end{gathered}[/tex]and the base of the other triangle will be:
[tex]\text{base}2=5-2.8=2.2[/tex]And the area of the triangles will be:
[tex]\begin{gathered} A1=\frac{base\times4.8}{2}=\frac{2.8\times4.8}{2}=6.72 \\ A2=\frac{base2\times4.8}{2}=\frac{2.2\times4.8}{2}=5.28 \end{gathered}[/tex]And the total area will be:
[tex]A1+A2=6.72+5.28=12[/tex]Find the maximum and minimum values of the function g(theta) = 2theta - 4sin(theta) on the interval Big[0, pi 2 Bigg\
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Hello there. To solve this question, we have to remember some properties about polar curves and determining maximum and minimum values.
In this case, we have the function in terms of the angle θ:
[tex]g(\theta)=2\theta-4\sin(\theta)[/tex]We want to determine its minimum and maximum values on the closed interval:
[tex]\left[0,\,\dfrac{\pi}{2}\right][/tex]We graph the function as follows:
Notice on the interval, it has a maximum value of 0.
We can determine its minimum value using derivatives, as follows:
[tex]g^{\prime}(\theta)=2-4\cos(\theta)[/tex]Setting it equal to zero, we obtain
[tex]\begin{gathered} 2-4\cos(\theta)=0 \\ \Rightarrow\cos(\theta)=\dfrac{1}{2} \\ \\ \Rightarrow\theta=\dfrac{\pi}{3} \end{gathered}[/tex]Taking its second derivative, we obtain
[tex]g^{\prime}^{\prime}(\theta)=4\sin(\theta)[/tex]And notice that when calculating it on this point, we get
[tex]g^{\prime}^{\prime}\left(\dfrac{\pi}{3}\right)=4\sin\left(\dfrac{\pi}{3}\right)=2\sqrt{3}[/tex]A positive value, hence it is a minimum point of the function.
Its minimum value is then given by
[tex]g\left(\dfrac{\pi}{3}\right)=2\cdot\dfrac{\pi}{3}-4\sin\left(\dfrac{\pi}{3}\right)=\dfrac{2\pi}{3}-2\sqrt{3}[/tex]Of course we cannot determine that 0 is a maximum value of this function using derivatives because it is a local maxima on a certain interval, and derivatives can only gives us this value when the slope of the tangent line is equal to zero.
a man pushes a car with a force of 127.5n along a straight horizontal road.he manages to increase the speed of the car from 1 m/s to 2.8 m/s in 12 seconds. find the mass of the car. figure out acceleration first.
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In order to determine the mass of the car, you first calculate the acceleration of the car, by using the following formula:
[tex]a=\frac{v_2-v_1}{\Delta t}[/tex]where:
v2: final speed of the car = 2.8 m/s
v1: initial speed of the car = 1 m/s
Δt: time interval = 12 s
You replace the previoues values into th formula for the acceleration:
[tex]a=\frac{2.8m/s-1.0m/s}{12s}=0.15\frac{m}{s^2}[/tex]Next, you the Newton's second law to find the mass of the car. You proceed as follow;
[tex]F=ma[/tex]where:
m: mass of the car = ?
a: acceleration of the car = 0.15m/s²
F: force exerted on the car by the man = 127.5N
You solve for m in the formula for F, and you replace the values of the other parameters to obtain m, just as follow:
[tex]m=\frac{F}{a}=\frac{127.5N}{0.15m/s^2}=850\operatorname{kg}[/tex]Hence, the mass of the car is 850kg
Suppose that at age 25, you decide to save for retirement by depositing $95 at the end of every month in an IRA that pays 6.25% compounded monthly. How much will you have from the IRA when you retire at age 65? Find the interest.
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1. At age 65 when you retire, you have (future value) $202,531.69 from the IRA.
2. The total interest earned on the monthly investment of $95 at 6.25% for 40 years is $156,931.69.
How is the future value determined?The future value, which represents the compounded value of the monthly investments, can be computed using the FV formula or an online finance calculator as follows:
Number of years = 40 (65 - 25)
N (# of periods) = 480 months (40 x 12)
I/Y (Interest per year) = 6.25%
PV (Present Value) = $0
PMT (Periodic Payment) = $95
Results:
Future Value (FV) = $202,531.69
Sum of all periodic payments = $45,600 ($95 x 480 months)
Total Interest = $156,931.69
Thus, the future value of the monthly investment is $202,531.69 with an interest of $156,931.69.
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Identify the constant of variation. 8y-7x=0
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A direct variation between two variables "x" and "y" is given by the following formula:
y = kx
We can rewrite the given expression 8y-7x=0 to get an equation of the form y = kx like this:
8y - 7x = 0
8y - 7x + 7x = 0 + 7x
8y = 7x
8y/8 = 7x/8
y = 7/8x
The number that is being multiplied by x should be the constant of variation k, then in this case, the constant of variation equals 7/8
A rectangle is graphed on a coordinate plane and then reflected across the y-axis. If a vertex of the rectangle was at (x, y), which ordered pair represents the corresponding vertex of the new rectangle after the transformation? F (y, x) G (-x, -y) H (-x, y) J (x, y)
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Let's say that the vertex is the following red point:
Then, its reflection across y-axis would be the blue point:
If we observe the coordinates, we will have that:
(5, 3) is transformed into (-5, 3). This is going to happen no matter the coordinate:
Decide whether the change is an increase or decrease and find the percent change. Original number = 45 New number = 18 Answer: 60% decrease 60% increase 150% increase 150% decrease
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The percentage change can be found below
[tex]\begin{gathered} \text{percentage change = }\frac{\text{ new number}-\text{original number}}{\text{original number}}\times100 \\ \text{percentage change=}\frac{18-45}{45}\times100 \\ \text{percentage change}=-60 \\ \end{gathered}[/tex]Since the percentage is negative, this means there is a 60% decrease.
timmy stated that the product of 3/3 and 12 is greater than the product of 3/2 and 12. is timmy correct?
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Hence the product of 3/3 and 12 is not greater than the product of 3/2 and 12.
So timmy is not correct
Find the quotient32 divided by 517 what is quotient and what is remainder
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Calculate the division as shown below
Therefore, the quotient is 16 and the remainder is 5
The answer is 16R5Find 8 3/4 ÷ 1 2/7. Write the answer in simplest form.
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Problem: Find 8 3/4 ÷ 1 2/7. Write the answer in the simplest form.
Solution:
[tex](8+\frac{3}{4}\text{ )}\div(1\text{ + }\frac{2}{3})[/tex]this is equivalent to:
[tex](\frac{32+3}{4}\text{ )}\div(\text{ }\frac{3+2}{3})\text{ = }(\frac{35}{4}\text{ )}\div(\text{ }\frac{5}{3})\text{ }[/tex]Now, we do cross multiplication:
[tex]=(\frac{35}{4}\text{ )}\div(\text{ }\frac{5}{3})=\frac{35\text{ x 3}}{5\text{ x 4}}\text{ =}\frac{105}{20}[/tex]then, the correct answer would be:
[tex]=\frac{105}{20}[/tex]Determine the z-intercepts of the parabola whose graph is given below.
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The x-intercepts are the points where a curve intercepts the x-axis.
From the picture of the problem, we see that the curve intercepts the x-axis in two points:
Answer
The x-intercepts are at:
• x = -6 at (-6,0)
,• x = -2 at (-2,0)
why are whole numbers rational numbers?
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Answer:
Step-by-step explanation:
A whole number can be written as a fraction that has a denominator of 1. So, the whole numbers 18, 3, and 234 can be written as the rational numbers 18/1, 3/1, and 234/1.
So, all whole numbers are rational numbers, but not all rational numbers are whole numbers.
Find the distance between the parallel lines. If necessary, round your answer to the nearest tenths.
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The distance between the parallel lines is [tex]\frac{3}{5}}[/tex].
The given parallel lines are
[tex]y= $-$3x+4\\y= $-$3x+1[/tex]
We have to find the distance between the given parallel lines.
The formula is used to solve the distance between two parallel lines [tex]ax+by+c_{1}=0[/tex] and [tex]ax+by+c_{2}=0[/tex] is
[tex]d=|c_{2} $-$c_{1}|\frac{1}{\sqrt{a^{2}+b^{2}}}[/tex]
The first given line is [tex]y= $-$3x+4[/tex]
We can write that line as [tex]3x$-$y $-$4=0[/tex]
The second given line is [tex]y= $-$3x+1[/tex]
We can write that line as [tex]3x$-$y $-$1=0[/tex]
Comparing the both given parallel lines with the standard equation of line.
After comparing we get
[tex]a=3, b= $-$1, c_{1}= $-$4, c_{2}= $-$1[/tex]
Putting the value in the formula
[tex]d=|(-1) -(-4)|\frac{1}{\sqrt{(3)^{2}+(-4)^{2}}}\\d=|-1+4|\frac{1}{\sqrt{9+16}}\\d=|3|\frac{1}{\sqrt{25}}\\d=\frac{3}{5}}[/tex]
Hence, the distance between the parallel lines is [tex]\frac{3}{5}}[/tex].
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A system of equations is shown below:Equation A: 3c = d − 8Equation B: c = 4d + 8Which of the following steps should be performed to eliminate variable d first?Multiply equation A by −4.Multiply equation B by 3.Multiply equation A by 3.Multiply equation B by 4.
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We have the following: system of equations:
A: 3c=d-8
B: c=4d+8
To eliminate variable d first, if we want to use elimination method, we need to have variable d in both equations with the same coefficient but with different signs.
As in equation B, the coefficient of d is 4, then we need to have in equation A a coefficient of -4 for variable d.
Then the answer is we need to multiply equation A by -4.
I was wondering if you could help me with this problem. I am not sure where to start solving it. Thank you.
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As shown at the graph, we need to find x and y
The angles (x+1) and (2y+1) are vertical
so, x + 1 = 2y + 1
so,
x = 2y eq.(1)
And the sum of the angles (x+1) , (3x + 4y) and (71 - 3y) are 180
So,
(x+1) + (3x + 4y) + (71-3y) = 180
x + 1 + 3x + 4y + 71 - 3y = 180
4x + y = 180 - 1 - 71
4x + y = 108
Substitute with x from eq (1) with 2y
4 * 2y + y = 108
8y + y = 108
9y = 108
y = 108/9 = 12
x = 2y = 2 * 12 = 24
So, x = 24 and y = 12
I need help with this problem it says to find the area of each shaded sector and round to the hundredth place
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Answer:
1330.81 square feet
Explanation:
In the circle, there are two unshaded sectors with central angles 26° and 90°.
The sum of the central angles = 360°.
Therefore, the sum of the central angle of the shaded sectors will be:
[tex]360\degree-(26\degree+90\degree)=244\degree[/tex]The area of a sector is calculated using the formula:
[tex]A=\frac{\theta}{360\degree}\times\pi r^2\text{ where }\begin{cases}Central\; Angle,\theta=244\degree \\ Radius,r,HK=25ft\end{cases}[/tex]Substitute the values into the formula:
[tex]\begin{gathered} A=\frac{244}{360}\times\pi\times25^2 \\ =1330.8136 \\ \approx1330.81\; ft^2 \end{gathered}[/tex]The area of the shaded sector is 1330.81 square feet (rounded to the hundredth place).
x - 5 = 2(4x-3) - 5 = 7x - 6 1/7= xx - 5 = 8x - 6-5 + 6 = 7x-6+6 1 = 7x x-x-5 = 8x - x - 6 1/7 = 7x/7Original equationCombine like terms. Solution Distributive PropertyAddition Property of EqualityCombine like terms.Subtraction Property of EqualityDivision Property of Equality What is the order to do this equation.
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We have to solve the equation:
[tex]\begin{gathered} x-5=2(4x-3) \\ x-5=8x-6 \\ x-x-5=8x-x-6 \\ -5+6=7x-6+6 \\ 1=7x \\ \frac{1}{7}=\frac{7}{7}x \\ \frac{1}{7}=x \end{gathered}[/tex]The steps are:
1. Original equation
2. Distributive property
3. Substraction property of equality
4. Addition property of equality
5. Combine all terms
6. Division property of equality
7. Solution
You begin at the origin and travel 5 units to the right and then vertically 3 units. You will be at what ordered pair?
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In a x-y coordinate plane of you moves to the right it increase the value of x and if you moves vertically it increases the value of y.
The ordered pair is (x,y)
For the given moves: (5,3)Solve the problem. Use 3.14 as the approximate value of pie
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The volume of a cylinder is calculated using the formula:
[tex]V=\pi r^2h[/tex]where r is the radius of the cylinder and h is the height.
From the question, we have the following parameters:
[tex]\begin{gathered} diameter=4.8 \\ \therefore \\ r=\frac{4.8}{2}=2.4 \\ and \\ h=6.66 \end{gathered}[/tex]Therefore, we c n calculae tehe volume of a cylinder to be:
[tex]\begin{gathered} V=3.14\times2.4^2\times6.66 \\ V=120.455424 \end{gathered}[/tex]For four cylinders, the combined volume will be:
[tex]\begin{gathered} V=120.455424\times4 \\ V=481.821696 \end{gathered}[/tex]The volume i 481 .82 cubic inches.
Move the sliders h and k so that the graph of y = r2 gets shifted up 3 units and to the right 2 units. Then type the new function, f(t) in the answer box 3 2 1 4. بنا -2 0 1 2 3 f(x) -1 h = 0.00 -2 K = 0.00 о Don't forget to shift the graph. Using function notation, i.e. f(x) = , enter the function that results from the transformation.
Answers
Given the graph of the function:
[tex]y=x^2[/tex]The graph will be shifted 3 units and to the right 2 units
So, the new vertex will be the point ( 2, 3 )
The new function will be:
[tex]f(x)=(x-2)^2+3[/tex]So, we will adjust the slider on the following values:
[tex]\begin{gathered} h=2 \\ k=3 \end{gathered}[/tex]help meeeeeeeeee pleaseee !!!!!
Answers
The composition of the function, (g o h)(0) = 0.
How to Find the Composition of a Function?To find the composition of a function, first, find the value of the inner function by plugging in the given value of x. The output of the inner function would now be used as the input to evaluate the outer function.
We are given the following:
g(x) = 5x
h(x) = √x
To find the composition of the function, (g o h)(0), first, find h(0). To find h(0), substitute x = 0 into the inner function, h(x) = √x:
h(0) = √0
h(0) = 0
Find (g o h)(0) by substituting x = 0 into g(x) = 5x:
(g o h)(0) = 5(0)
(g o h)(0) = 0
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