What is the term for when the
body loses too many fluids? *
A) bulimia
B) frostbite
C) dehydration
D) all of the above

Answer:

Explanation:

Satellite A and satellite B are approaching the earth from opposite directions , that means they are approaching each other . The velocity of satellite A and B are .648c and .795c respectively . Their velocities are comparable to velocity of light so they will follow relativistic laws .

Their relative velocity will be given by the following relation .

[tex]V_r=\frac{u+v}{1+\frac{uv}{c^2} } }[/tex]

where u and v are velocities of vehicles coming from opposite direction and c is velocity of light .

[tex]V_r=\frac{.795c+.648c}{1+\frac{.648c\times .795c}{c^2} } }[/tex]

[tex]V_r=\frac{1.443c}{1+.515 } }[/tex]

= .952c

Answer: The mean value = 9.85m/s².

Explanation:

Mean = [tex]\dfrac{\text{Sum of n observations}}{n}[/tex]

The given measurements the acceleration of gravity (units of m/s²): 10.1, 9.87, 9.76, 9.91, 9.75, 9.88, 9.69, 9.83, and 9.90.

Number of measurements =9

Sum of measurements =  88.69

Mean = [tex]\dfrac{88.69}{9}=9.85444444\approx9.85[/tex]

Hence, the mean value = 9.85m/s².

Answer:

- 9m/s²

Explanation:

Given parameters:

Initial velocity  = 40m/s

Time taken  = 3s

Final velocity  = 13m/s

Unknown:

Acceleration of the car  = ?

Solution:

Acceleration is the rate of change of velocity with time taken.

   Acceleration  = [tex]\frac{Final velocity - Initial velocity }{Time taken}[/tex]  

  Acceleration  = [tex]\frac{13 - 40 }{3}[/tex]   = - 9m/s²

Complete Question

Consider a system consisting of an ideal gas confined within a container, one wall of which is a movable piston. Energy can be added to the gas in the form of heat by applying a flame to the outside of the container. Conversely, energy can also be removed from the gas in the form of heat by immersing the container in ice water. Energy can be added to the system in the form of work by pushing the piston in, thereby compressing the gas. Conversely, if the gas pushes the piston out, thereby pushing some atmosphere aside, the internal energy of the gas is reduced by the amount of work done.

          [tex]pV=nRT[/tex]

so the absolute temperature T is directly proportional to the product of the absolute pressure p and the volume V,Here n denotes the amount of gas moles,which is a constant because the gas is confined and R is the universal constant

What is the [tex]\triangle U[/tex] as the system of ideal gas goes from point A to point B on the graph recall u is proportional to T

Answer:

[tex]\triangle T=0[/tex]

[tex]\triangle V=0[/tex]

The gas A and B have same internal energy

Explanation:

From the question we are told that

[tex]Pa=u atm\\Va=1m^3\\Pb=1 atm\\Vb=4m^3[/tex]

Generally the equation of temperature is mathematically given as

[tex]Ta=\frac{Pv}{nR}[/tex]

[tex]Ta=\frac{u*1}{nR}[/tex]

And

[tex]Tb=\frac{PbVb}{nR}[/tex]

[tex]Tb=\frac{u*1}{nR}[/tex]

Generally the change in temperature [tex]\triangle T[/tex] is mathematically given as

[tex]\triangle T=Tb-Ta=Tb=\frac{u*1}{nR}-\frac{u*1}{nR}[/tex]

[tex]\triangle T=0[/tex]

Generally the change in internal energy [tex]\triangle V[/tex]

[tex]\triangle V=nC_v \triangle T\\[/tex]

[tex]\triangle V=0[/tex]

Therefore with

[tex]\triangle T=0[/tex]

[tex]\triangle v=0[/tex]

The gas A and B have same internal energy

Answer:

The strength of the electric field is [tex]E=15.66\: N/C[/tex]

Explanation:

Here the electric force is equal to Newton's second law.

[tex]F_{e}=ma[/tex]

Let's recall that electric force is the electric field times the charge, so we have:

[tex]qE=ma[/tex]

[tex]E=\frac{ma}{q}[/tex] (1)

Where:

m is the proton mass

q is the proton charge

a is the acceleration        

Using the equation (1) we have:

[tex]E=\frac{1.67*10^{-27}1.5x10^{9}}{1.6*10^{-19}}[/tex]

Therefore, the strength of the electric field is [tex]E=15.66\: N/C[/tex]

I hope it helps you!

Answer:

(A) J = -10.57 kg-m/s   (B) 17.61 N

Explanation:

Given that,

Mass of a volleyball, m = 0.263 kg

Initial speed of volleyball, u = 17.4 m/s

Final speed of volleyball, v = -22.8 (in opposite direction)

(a) We need to find the impulse delivered to the ball by the player.

Impulse = change in momentum

J = m(v-u)

Put all the values,

J = 0.263(-22.8-17.4) kg-m/s

= -10.57 kg-m/s

(b) The time of contact with the ball, t = 0.6 s

We need to find the magnitude of the average force exerted on the players first.

Impulse, J = Ft

[tex]F=\dfrac{J}{t}\\\\F=\dfrac{10.57 }{0.6}\\\\F=17.61\ N[/tex]

So, the magnitude of the average force exerted on the player is 17.61 N.

Answer:

20.41 s

3534.80 m

Explanation:

In how many seconds will it reach the ground?

We are given the initial velocity of the body, which is 200 m/s at a 30° angle.

We know the acceleration in the vertical direction is -9.8 m/s², assuming that the upwards/right direction is positive and the downwards/left direction is negative.

Since we are using acceleration in the y-direction, let's use the vertical component of the initial velocity.

Let's use the fact that at the top of its trajectory, the body will have a final velocity of 0 m/s.

Now we have one missing variable that we are trying to solve for: time t.

Find the constant acceleration equation that contains v₀, v, a, and t.

Substitute known values into the equation.

Recall that this is only half of the body's trajectory, so we need to double the time value we found to find the total time the body is in the air.

The body will reach the ground in 20.41 seconds.

How far from the point of projection would it strike?

We want to find the displacement in the x-direction for the body.

Let's find the constant acceleration equation that contains time t, that we just found, and displacement (Δx).

Substitute known values into the equation. Remember that we want to use the horizontal component of the initial velocity and that the acceleration in the x-direction is 0 m/s².

The body will strike 3534.80 m from the point of projection.

Answer:

20 C to F

Ans: 68F

-40 C to F

Ans:-40F

40C to F

Ans:104F

Explanation:

In physics, a force is any interaction that, when unopposed, will change the motion of an object. A force can cause an object with mass to change its velocity, i.e., to accelerate. Force can also be described intuitively as a push or a pull. A force has both magnitude and direction, making it a vector quantity.

Formula

Newton's Second Law

F = m * a

F = force

m = mass of an object

a = acceleration

The total displacement of the dispatch rider is calculated as 43km.

Data;

To calculate the total displacement of the dispatch rider, we can simply add up the total distance covered by the rider.

This becomes;

[tex]10+11+22 = 43km[/tex]

The total displacement of the dispatch rider is calculated as 43km.

Learn more on displacement here;

https://brainly.com/question/13416288

https://brainly.com/question/1397750

Answer:

markers are 29.76 m far apart in the laboratory

Explanation:

Given the data in the question;

speed of particle = 0.624c

lifetime = 159 ns = 1.59 × 10⁻⁷ s

we know that; c is speed of light which is equal to 3 × 10⁸ m/s

we know that

distance = vt

or s = ut

so we substitute

distance = 0.624c × 1.59 × 10⁻⁷ s

distance = 0.624(3 × 10⁸ m/s) × 1.59 × 10⁻⁷ s

distance = 1.872 × 10⁸ m/s × 1.59 × 10⁻⁷ s

distance =  29.76 m

Therefore, markers are 29.76 m far apart in the laboratory

Answer:

1200N/m

Explanation:

Given parameters:

Force on the motorcycle spring = 240N

Extension  = 2cm or 0.02m

Unknown:

Spring constant  = ?

Solution:

To a spring the force applied is given as :

       F  = K e

F is the applied force

K is the spring constant

e is the extension

              240  = k x 0.02

                 k  = 1200N/m

Answer:

4m/s^2

Explanation:

Answer:

In general, if the dimensions are same, the quantities do represent the same physical content. Like work and energy have the same dimensions and represent inter-convertible quantity. ... These two quantities represent the same quantity - same meaning and content.

Explanation: i hope this helped.

Answer:

a. d₁/d₂ = 1.09 b. 0.054 mW

Explanation:

a. What is the ratio of the diameter of the first student's eardrum to that of the second student?

We know since the power is the same for both students, intensity I ∝ I/A where A = surface area of ear drum. If we assume it to be circular, A = πd²/4 where r = radius. So, A ∝ d²

So, I ∝ I/d²

I₁/I₂ = d₂²/d₁² where I₁ = intensity at eardrum of first student, d₁ = diameter of first student's eardrum, I₂ = intensity at eardrum of second student, d₂ = diameter of second student's eardrum.

Given that I₂ = 1.18I₁

I₂/I₁ = 1.18

Since I₁/I₂ = d₂²/d₁²

√(I₁/I₂) = d₂/d₁

d₁/d₂ = √(I₂/I₁)

d₁/d₂ = √1.18

d₁/d₂ = 1.09

So, the ratio of the diameter of the first student's eardrum to that of the second student is 1.09

b. If the diameter of the second student's eardrum is 1.01 cm. how much acoustic power, in microwatts, is striking each of his (and the other student's) eardrums?

We know intensity, I = P/A where P = acoustic power and A = area = πd²/4

Now, P = IA

= I₂A₂

= I₂πd₂²/4

= 1.18I₁πd₂²/4

Given that I₁ = 0.58 W/m² and d₂ = 1.01 cm = 1.01 × 10⁻² m

So, P = 1.18I₁πd₂²/4

= 1.18 × 0.58 W/m² × π × (1.01 × 10⁻² m)²/4

= 0.691244π × 10⁻⁴ W/4 =

2.172 × 10⁻⁴ W/4

= 0.543 × 10⁻⁴ W

= 0.0543 × 10⁻³ W

= 0.0543 mW

≅ 0.054 mW

(a) The ratio of the diameter of the first student's eardrum to that of the second student is 1.09.

(b) The acoustic power, in microwatts, striking each of his (and the other student's) eardrums is of 0.054 mW.

Given data:

The sound intensity of first student is, [tex]I_{1}= 0.58 \;\rm W/m^{2}[/tex].

And sound intensity of second student is, [tex]I_{2} = 1.18 \times I_{1}[/tex].

The diameter of second eardrum is, [tex]d_{2} = 1.01 \;\rm cm=1.01 \times 10^{-2} \;\rm m[/tex]

(a)

The power is the same for both students, intensity I ∝ I/A where A = surface area of ear drum. If we assume it to be circular, A = πd²/4 where r = radius. So, A ∝ d²

So,

I ∝ I/d²

I₁/I₂ = d₂²/d₁²

Here

I₁  is the intensity at eardrum of first student.

d₁ is the diameter of first student's eardrum.

I₂ is the  intensity at eardrum of second student.

d₂ is the diameter of second student's eardrum.

Since,  I₂ = 1.18I₁

I₂/I₁ = 1.18

Also,  I₁/I₂ = d₂²/d₁²

=√(I₁/I₂) = d₂/d₁

=d₁/d₂ = √(I₂/I₁)

=d₁/d₂ = √1.18

d₁/d₂ = 1.09

Thus, we can conclude that  the ratio of the diameter of the first student's eardrum to that of the second student is 1.09.

(b)

We know that the expression for the intensity of sound is,

I = P/A

P = IA

Here,

P is the  acoustic power and A is the area. (A = πd²/4)

P = I₂A₂

P= I₂πd₂²/4

P= 1.18I₁πd₂²/4

Since,

I₁ = 0.58 W/m² and d₂ = 1.01 cm = 1.01 × 10⁻² m

Substituting the values as,

P = (1.18I₁πd₂²) /4

P = 1.18 × 0.58 W/m² × π × (1.01 × 10⁻² m)²/4

P = (0.691244π × 10⁻⁴ W) /4  

P = (2.172 × 10⁻⁴ W) /4

P = 0.543 × 10⁻⁴ W

P  ≅ 0.054 mW

Thus, we can conclude that the acoustic power, in microwatts, striking each of his (and the other student's) eardrums is of 0.054 mW.

Learn more about the acoustic power here:

https://brainly.com/question/14932158

Answer:

Final Answer

T1=736 NT1=736 N

T2=194 

Answer:they seperate from eachother but they don't touch eachother at all

Explanation:

Answer:

a. 2.25 × 10^10 yrs

b. 9 × 10^9 yrs

c. 59.5g

d. 8.78g

Explanation:

(a) Original sample(N) = 238g

Half-life = 4.5 × 10^9 yrs

5 half-life 5T½ = 5 × 4.5 × 10^9 yrs

= 2.25 × 10^10 yrs

(b) If N = 240g

N/2 = 120g

N/4 = 60g

Meaning 2T½

= 2 × 4.5 × 10^9 yrs

= 9 × 10^9 yrs

(c) 1.8 × 10^10 ÷ 4.5 × 10^9 = 4

at 4T½ we have N/16 = 238/4 = 59.5

=> the sample left = 59.5g

(d) from the question N = 562g

at 6T½

the amount left will be N/64

= 562÷64 = 8.78g

NB: For questions please you can read more on radioactivity

Answer:

C would make the most sense.

Explanation:

ok so basically the reason why i chose C is because i've always been told that whatever i type, send, or receive on my phone is stored into the phone's memory and can be brought back up with keystrokes. so yeah, i'd go with C but it's DEFINATELY not A or D.

Answer:

Explanation:

Most environments have many niches. If a niche is "empty" (no organisms are occupying it), new species are likely to evolve to occupy it. This happens by the process of natural selection. By natural selection, the nature of the species gradually changes to become adapted to the niche.

Answer:

fr = μ[tex]\miu _{k}[/tex] m g cos θ

the correct answer is less than fr = μ[tex]\miu _{k}[/tex] 2m g cos θ

Explanation:

Let's propose the solution of the problem to be able to answer the question, let's fix a reference system with one axis parallel to the plane (x-axis) and the other perpendicular, let's write Newton's second law

Y Axis  

     N - W cos θ = 0

     N = mg cos θ

X axis.

     fr - w sin θ = 0

     fr = mg sin θ

the friction force is described by the expression

     fr = μ N

      fr = μ[tex]\miu _{k}[/tex] m g cos θ

When we analyze this expression we see that the friction force is equal to (μ_k m g cos θ)

If everything is well written in your problem, the correct answer is less, even though I think you have an error when writing the number

Answer:

9 seconds

Explanation:

450 divided by 50 equals 9.

Answer:

9s

Explanation:

Given parameters:

Displacement  = 450m

Velocity  = 50m/s

Unknown:

Time taken for the train to make the trip  = ?

Solution:

Since velocity is displacement divided by the time taken,

   Time  = [tex]\frac{Displacement}{Velocity}[/tex]  

   Time  = [tex]\frac{450}{50}[/tex]   = 9s

Answer:

The egg drop experiment is about building a structure around an egg with different materials so that when it is dropped from a high place it doesn't break.

Explanation:

I have done this experiment before so I know. Have a cool awesome great splendid Supercalifragilisticexpialidocious day ok bye.

Answer:

 t = 23.255 s,   x = 2298.98 m,    v_y = - 227.90 m / s

Explanation:

After reading your extensive writing, we are going to solve the approach.

The initial speed of the plane is 250 miles / h and it is at an altitude of 2650 m; In general, planes fly horizontally for launch, therefore this is the initial horizontal speed.

As there is a mixture of units in different systems we are going to reduce everything to the SI system.

         v₀ₓ = 250 miles h (1609.34 m / 1 mile) (1 h / 3600 s) = 111.76 m / s

         y₀ = 2650 m

Let's set a reference system with the x-axis parallel to the ground, the y-axis is vertical. As time is a scalar it is the same for vertical and horizontal movement

Y axis  

       y = y₀ + v₀ t - ½ g t²

the initial vertical velocity when the cargo is dropped is zero and when it reaches the floor the height is zero

       0 = y₀ + 0 - ½ g t²

       t = [tex]\sqrt{ \frac{2 y_o}{g} }[/tex]

       t = √(2 2650/ 9.8)

       t = 23.255 s

Therefore, for the cargo to reach the desired point, it must be launched from a distance of

       x = v₀ₓ t

       x = 111.76 23.255

       x = 2298.98 m

at the point and arrival the speed is

        vₓ = v₀ₓ = 111.76

vertical speed is

         v_y = v_{oy} - gt

          v_y = 0 - gt

          v_y = - 9.8 23.25 555

         v_y = - 227.90 m / s

the negative sign indicates that the speed is down

in the attachment we have a diagram of the movement

Answer:

a)  perfectly inelastic,  b)  collision is inelastic,  c)   elastic  

Explanation:

In this exercise, it is asked to identify what type of shock occurs between the skater and the frisbee, for this we must define a system formed by the skater and the fribee, so that the forces during the crash have been internal and the amount of movement is preserved

Initial instant. Before the skater touches the frisbee

    p₀ = M v₁ + m v₂

where M and m are the masses of the skater and frisbee, respectively

for the final moment they give us several possibilities, in all case the moment is conserved

       p₀ = [tex]p_{f}[/tex]

case a)

Final instant. grabs the frisbee and holds it

    p_{f} = (M + m) v '

     p₀ = p_{f}

We can see that this shock is perfectly inelastic, it holds the fressbee

case b)

final instant.

This case is similar to the previous one, but the final speed of fresbee is zero, therefore this collision is inelastic and the kinetic energy is not conserved.

case c)

final instant. Grab the fressbee and resend it

      [tex]p_{f} = M v_{1f} + m v_{2f}[/tex]

this is an elastic Shock since the equivalent of a rebound of the fressbee, the kinetic energy is conserved.

Explanation:

Memory loss in retrograde amnesia has long been held to be larger for recent periods than for remote periods, a pattern usually referred to as the Ribot gradient. One explanation for this gradient is consolidation of long-term memories. Several computational models of such a process have shown how consolidation can explain characteristics of amnesia, but they have not elucidated how consolidation must be envisaged. Here findings are reviewed that shed light on how consolidation may be implemented in the brain. Moreover, consolidation is contrasted with alternative theories of the Ribot gradient. Consolidation theory, multiple trace theory, and semantization can all handle some findings well but not others.

Answer:

1.19m

Explanation:

Given parameters:

Speed of the trumpet sound  = 351m/s

Frequency of the note = 294Hz

Unknown:

Wavelength of the sound  = ?

Solution:

To solve this problem, we use the wave - velocity equation.

    V  = F x ∧  

V is the velocity of the body

F is the frequency

∧ is the wavelength

 So;

          351   = 294 x ∧  

       ∧   = [tex]\frac{351}{294}[/tex]   = 1.19m

Answer:

The impulse is 90Ns.

Explanation:

Given that the formula for impulse is F×t, where F represents force and t is time (in seconds) :

Impulse = F × t

Impulse = 30 × 3 = 90Ns

Answer:

A.The positive z-direction

Explanation:

We are given that

Linear charge density of long line which is  located on the x-axis=[tex]\lambda_1[/tex]

Linear charge density of another long line which is  located on the y-axis=[tex]\lambda_2[/tex]

We have to find the direction of electric field at z=a on the positive z-axis if [tex]\lambda_1[/tex] and [tex]\lambda_2[/tex] are positive.

The direction of electric field  at z=a on the positive z-axis  is positive z-direction .

Because [tex]\lambda_1[/tex] and [tex]\lambda_2[/tex] are positive and the electric field is  applied away from the positive charge.

Hence, option A is true.

A.The positive z-direction