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Answer:

mass NH₃ produced = 72.9g (3 sig. figs.)

Explanation:

                 3H₂      +      N₂                =>       2NH₃

given      excess           60.1g                    (?)grams

moles =>                      (60.1g/28g/mol)

                                     = 2.15mole    =>     2(2.15mole)

                                                                     = 4.29mole NH₃

mass NH₃ = 4.29moles x 17 g/mole = 72.9grams NH₃

Always convert given data into moles, solve in terms of moles and convert to needed dimension from mole yields. :-)

Answer:

73.07 grams of ammonia is produced.

Explanation:

In order to find the grams of ammonia produced, we need to find the amount of the reactants so that we know how much product (ammonia) the reactants (Hydrogen and Nitrogen) can and will produce.

First, we need to use the balanced equation to find the amount of moles equivalent to the 60.1 grams of Nitrogen that reacts.

To convert from Grams to Moles, we will divide by the molar mass (amu)..

60.1 grams of N2 /  2(14.01) grams  N2 = 2.144896502 moles of N2.

So, we know that 60.1 grams of N2 equals 2.144896502 moles.

       Now, we will look at the balanced equation and convert from moles of N2 to moles of NH3 in order to later find the grams of NH3 (ammonia) produced..

2.144896502 moles N2 *  2 moles NH3/1 mol N2 = 4.289793004 moles NH3.

     Now that we know the amount of moles produced of ammonia, we will convert to grams. We can do this by multiplying by the molar mass of ammonia which is 17.034 (N = 14.01, H = 1.008, ---> 14.01 +3(1.008) = 17.034)

4.289793004 moles NH3 * 17.034/1 mol = 73.07233403 grams NH3

This can be estimated to 73.07 grams of NH3 (ammonia) produced.

If you are still confused on how to convert between moles and grams, please see the uploaded image.

Answer:

which one you didnt explain or added attachment?

Answer: the answer is c i looked it up please give me brainliest pleaseeee

Explanation:

Answer:

Feed rate F = 625 kg/h

Explanation:

Given that:

percentage mass of the solids = 7% = 0.07

rate of removal of water W = 500 kg/h

Concetration  C = 35% = 0.35

To fine the feed rate = ???

Using the Overall balance equation,

Suppose: F = W + C

F = 500 + C  ---- (1)

Then, the Solids balance can be computed as:

(0.07)F = (0)500 + (0.35)C

0.07F = 0.35C

C = 0.07F/0.35

C = 0.2F

Now

F = 500 + 0.2F

Collect like terms

F – 0.2F = 500

0.8F = 500

F = 500/0.8

F = 625 kg/h

Therefore, the feed rate F = 625 kg/h

Answer:

See image attached and explanation

Explanation:

The reaction of phenol with SO3/H2SO4 is an electrophilic reaction. The electrophile attacks portions of high electron density in the substrate phenol.

The -OH group activates phenol towards electrophilic substitution at the ortho and para positions, hence the product(s) formed in this reaction(only one product is shown here as required by the question).

The sulphonation of phenol using concentrated sulfuric acid at lower temperature yields majorly the ortho product whereas at higher temperature the para product predominates.

Answer:

poggers

Explanation:

Answer:

B. they release most of the oxygen to the atmosphere

They release most of the oxygen into the atmosphere. Therefore, the correct option is option B among all the given options.

Photosynthesis is a method that organisms like plants utilize to transform chemical energy into light that may then be released to power the organism's activities via cellular respiration. A portion of this chemical energy is held in carbohydrate molecules, including such sugar and starches, which are formed by the reaction of carbon dioxide and water.

Photosynthesis is performed by the majority of plants, algae, and cyanobacteria; these organisms are known as photoautotrophs. Photosynthesis is accountable for creating and maintaining the oxygen concentration of the Earth's atmosphere, as well as supplying the majority of the energy required for life on Earth.  They release most of the oxygen into the atmosphere.

Therefore, the correct option is option B.

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Answer:

pretty sure its B

Explanation:

Answer:

b :)

Explanation:

right on edge 2020

the answer to your question is 2g of magnesium plus 1g of oxygen equals magnesium oxide

Answer:

202 L

Explanation:

Step 1: Write the balanced equation

C₆H₁₂O₆ + 6 O₂(g) ⇒ 6 CO₂(g) + 6 H₂O(l)

Step 2: Calculate the moles corresponding to 270 g of C₆H₁₂O₆

The molar mass of C₆H₁₂O₆ is 180.16 g/mol.

270 g × 1 mol/180.16 g = 1.50 mol

Step 3: Calculate the moles of CO₂ generated from 1.50 moles of glucose

The molar ratio of C₆H₁₂O₆ to CO₂ is 1:6. The moles of CO₂ formed are 6/1 × 1.50 mol = 9.00 mol

Step 4: Calculate the volume of 9.00 moles of CO₂ at STP

The volume of 1 mole of an ideal gas at STP is 22.4 L.

9.00 mol × 22.4 L/mol = 202 L

Answer:

Being a weak acid and a strong base, where it is diluted in a neutral medium such as water, the basic medium predominates, almost alkaline pH.

Explanation:

The acidity of the solution, being weak, means that its pH is not so low, therefore it will be easier to reach the values of 7 or 7 where alkalinity or basity is indicated.

Answer:

If an equal number of moles of the weak acid HF and the strong base KO are added to water,

HF           +          KOH        ---->     KF       +      [tex]H_2O[/tex]

weak                  strong                salt

acid                     base

The salt formed is KF which is a basic salt since it is formed by reaction of weak acid and strong base

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Answer: A

Explanation:

Answer: I think the answer is A or D I'm not sure

Explanation:

Mass of Hydrogen atoms : 18 g

Given

73 gram of HCl

144gram of H₂O

Required

Mass (gram) atom of Hydrogen

Solution

H atoms are in 2 compounds, H₂O and HCl, so we calculate their mass in each compound

[tex]\tt \dfrac{1}{36.5}\times 73=2~g[/tex]

mass H in HCl :

[tex]\tt \dfrac{2}{18}\times 144=16~g[/tex]

total mass = 2 g+ 16 g = 18 g

Answer:

In Chemistry the coefficient is the number in front of the formula. The coefficient tells us how many molecules of a given formula are present.

Explanation:

Answer:

You didnt put the graph

Answer:

increases, the ratio of drink mix to water particles increases.

Explanation:

also took the test

Answer:

A

Explanation:

complete question with the graphs are attached to this answer.

Let us consider the question closely. When the student was walking home, his/her speed was uniform. However, after 5 minutes, the student increased his/her pace due to the light rain. This is seen as a slight increase in speed after 5 minutes on the graph A. two minutes after (at the 7th minute) the rain comes hard and the student had to increase his/her speed by a much higher magnitude by running and maintaining this uniform speed all the way untill the end of the journey at the 10th minute.

Answer:

What’s the answer ‍♀️

Explanation:

Answer:

Qsp > Ksp, BaCO3 will precipitate

Explanation:

The equation of the reaction is;

Na2CO3 + BaBr2 -------> 2NaBr + BaCO3

Since BaCO3 may form a precipitate we can determine the Qsp of the system.

Number of moles of Na2CO3 = 0.96g/106 g/mol = 9.1 * 10^-3 moles

concentration of NaCO3 = number of moles/volume of solution = 9.1 * 10^-3 moles/10 L = 9.1 * 10^-4 M

Number of moles of BaBr2 = 0.20g/297 g/mol = 6.7 * 10^-4 moles

concentration of BaBr2 = 6.7 * 10^-4 moles/10 L = 6.7 * 10^-5 M

Hence;

[Ba^2+] = 6.7 * 10^-5 M

[CO3^2-] = 9.1 * 10^-4 M

Qsp = [6.7 * 10^-5] [9.1 * 10^-4]

Qsp = 6.1 * 10^-8

But, Ksp for BaCO3 is 5.1*10^-9.

Since Qsp > Ksp, BaCO3 will precipitate

Precipitate of BaCO₃ will form when 0.96g of Na₂CO₃ is combined with 0.20g BaBr₂ in a 10 L solution.

Precipitate will form in the reaction if for the given reaction value of Qsp i.e. solubility product quotient is more than Ksp i.e. solubility product constant.

Given chemical reaction is:
Na₂CO₃ + BaBr₂ → 2NaBr + BaCO₃

We can calculate the concentration of reactants in terms of molarity, as no. of moles of solute present in per liter of solution.

And moles will be calculate as n = W/M, where

W = given mass

M = molar mass

Given mass of Na₂CO₃ = 0.96g

Moles of Na₂CO₃ = 0.96g / 106 g/mol = 9.1×10⁻³ moles

Volume of solution = 10L

Concentration of Na₂CO₃ = 9.1×10⁻³ moles/10L = 9.1×10⁻⁴ M

Given mass of BaBr₂ = 0.20g

Moles of BaBr₂ = 0.20g / 297g/mol = 6.7×10⁻⁴ moles

Concentration of BaBr₂ = 6.7×10⁻⁴ moles/10L = 6.7×10⁻⁵ M

Qsp will be calculated as the product of their concentration:

Qsp = (9.1×10⁻⁴)(6.7×10⁻⁵) = 6.1×10⁻⁸

And value of Ksp for BaCO₃ = 5.1×10⁻⁹

From this we conclude that BaCO₃ will form precipitate.

Hence, precipitation of BaCO₃ takes place.

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Answer:

none of the above

Explanation:

Answer:

Sedimentary rock

Explanation:

Rocks found at the beach and near land surface are usually sedimentary rocks such as shale, sandstone, limestone, breccia e.t.c.

Now,these rocks are formed from the porosity destruction through compaction & cementation process of unconsolidated sediments by calcium carbonate cements in the tidal zone occurring primarily in the tropical and subtropical beaches. Various crystalline forms of Aragonite and calcite, are the primary agents of hardening and bonding of clastic sediments by the precipitation of mineral matter formed in the pore spaces.

The rock Kelly found on the beach has been sedimentary rock. The rocks have been formed by the series of events including melting, erosion, weathering, and compacting.

The rocks are the hard piece of matter that has compact structure. Rock has been of there types, namely igneous, metamorphic and sedimentary rocks.

The rocks that has been found near the seashore has been sedimentary rock as they have been formed with the erosion and the compacting of erode with the weather conditions resulting in the rock.

The rocks have been formed with the process of melting, eroding, compacting, and deformation. The rocks form has been interchangeable.

Melting and cooling of the metamorphic rock results in the formation of the igneous rock. The igneous rock has been weathered and sediment to form the sedimentation rock. The effect of heat and pressure over sedimentation rock turns it into metamorphic rock.

The rock Kelly found on the beach has been sedimentary rock. The rocks have been formed by the series of events including melting, erosion, weathering, and compacting.

For more information about the rocks, refer to the link:

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Answer:

K2SO4, NH3, HOCI, HCI, CH3NH2,  SiCl4, CO2, CH20

Explanation:

Substances are soluble in water when they are ionic or polar covalent substances.

If we look at the substances listed, K2SO4 is ionic while  NH3, HOCI, HCI, CH3NH2,  SiCl4, CO2, CH20 all contain polar covalent bonds which accounts for their water solubility.

Hence ionic and polar covalent substances are soluble in a polar solvent such as water.

Answer:

1 : motion as observed from or referred to some material system constituting a frame of reference (as two adjacent walls and floor of a room) — see relativity sense 3. 2 : the motion of one body with respect to another regarded as fixed — compare relative velocity

Answer: True

Explanation: They are formed by the cooling and hardening of molten magma

Answer:

Birds have adapted to feed on different food sources.

Explanation:

Answer:

D

Explanation:

Answer:

4.963x 10²

7.8761x 10³

8.9 x 10⁻²

Explanation:

Scientific notation is the way to express the large value in short form.

The number in scientific notation have two parts.

. The digits (decimal point will place after first digit)

× 10 ( the power which put the decimal point where it should be)

for example the number 6324.4 in scientific notation will be written as = 6.3244 × 10³

a) 496.3 x 10²

4.963x 10²

b) 7876.1 x 10⁻⁷

7.8761x 10³

c) 0.089 x 10⁻⁹

8.9 x 10⁻²

Answer:

See explanation

Explanation:

The word equation for the formation of copper acetate is as follows;

copper + vinegar →  copper II oxide → copper acetate

Copper and vinegar  are reactants while the copper acetate is the product

Note that vinegar is a weak solution of acetic acid. Pure copper does not react with acetic acid (copper is less than hydrogen in the electrochemical series); however, a reactive oxide layer is formed upon exposure to air. This layer interacts with non-oxidizing acids to give green copper(II) compounds (DeMeo, 1997; Tétreault et al., 2003), a typical example of such compounds is the copper(II) acetate formed in the word equation above.

Acid rain forms new substances because it is capable of interacting chemically with surfaces. When substances are exposed to acid rain, they dissolve in water if they are soluble in acids to form new substances.