what statements are always true about limiting reactants? select one or more: the limiting reactant is completely used up in the reaction. there will be an excess of other reactants at the end of the reaction. the limiting reactant is always the same for a given reaction. the limiting reactant dictates the amount of product. the limiting reactant has a lower mass than other reactants.

Answers

Answer 1

The correct statements are:

The limiting reactant is completely used up in the reaction.

There will be an excess of other reactants at the end of the reaction.

The limiting reactant dictates the amount of product.

Which reactant will be the limiting reactant depends on the molar ratios of all the reactants in the experiment (and the coefficients in the balanced reaction equation), so it will absolutely vary depending on the reaction setup and conditions, which is why it cannot always be the same for a given reaction.

Because the molar ratios of the reactants dictate which of them will be the limiting one, it is not true that the one with the lowest mass will always be the limiting reactant.

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Related Questions

you know that the boiling point of a given liquid is dependent on several different variables. what would happen to the boiling point of a liquid if the volume of the liquid was halved?

Answers

Because boiling point is independent of liquid volume, the boiling point would not vary.

What is boiling point  ?

A liquid's boiling point changes depending on the pressure being applied; the normal boiling point is the temperature at which the vapor pressure is equal to the average atmospheric pressure at sea level (760 mm [29.92 inches] of mercury). Water boils at sea level at 100° C.

The temperature at which a liquid's vapor pressure equals the pressure around it and the liquid turns into a vapor is known as the boiling point of a substance

A liquid's boiling point varies depending on the atmospheric pressure in the area. The boiling point of a liquid is lower in a partial vacuum than it is at atmospheric pressure. A liquid's boiling point is lower under low pressure than it is under air pressure. As a result, water boils at 99.97 °C (211.95 °F) at sea level but at 93.4 °C (200.1 °F) at 1,905 m (6,250 ft) altitude under standard pressure. Various liquids will boil at different temperatures at a given pressure.

Because boiling point is independent of liquid volume, the boiling point would not vary.

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Put the following elements in order, with the element having the most valence electrons at the top of your list and the element with the fewest valence electrons at the bottom.swap_vertAstatine (At)swap_vertArsenic (As)swap_vertCalcium (Ca)swap_vertSodium (Na)swap_vertOxygen (O)swap_vertSilicon (Si)swap_vertAluminum (Al)

Answers

answer

1. Neon

2. Astatine

3. oxygen

4. Arsenic

5. Silicone

6. Aluminium

7. Calcium

8. Sodium

which of the following will be the strongest oxidizing agent (weakest reducing agent)? a) chromium (0) b) chromium (ii) c) chromium (iii) d) chromium (iv) e) chromium (vi)

Answers

The strongest oxidizing agent is chromium (vi); option E.

What are oxidizing agents?

Oxidizing agents are compounds that readily accept electrons and are reduced.

Oxidizing agents will oxidize other substances, resulting in an increase in the oxidation state of the compounds. However, they are themselves reduced as their oxidation states are reduced when they accept electrons.

Strong oxidizing agents are weak reducing agents.

Reducing agents readily give up electrons to other compounds, and hence are oxidized.

Transition elements are known for their variable oxidation states due to their ability to lose different numbers of electrons.

The higher the oxidation state of a transition element in a compound, the more oxidizing the compound will be.

Hence, a compound of a transition element in the highest oxidation state will be the most oxidizing.

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I am doing an assignment for science but i messed up my char on the elements can someone fix it for me please ( WILL ALSO GIVE BRAINLIEST )
VVVVVVVVVVVVVVVVVVVVVVVVVVVVVVVVVVVVVVVV

Answers

Answer: The part I think you messed up on is the atoms not all of them have 0 and 1. Sodium Chloride has 2 atoms. Other than that it looks amazing! Hope this helps!

The pH of a 1.00 M solution of urea, a weak organic base, is 7.050.
Calculate the Ka of protonated urea.

Answers

The Ka value of a protonated base is the acid ionization constant. Which can be calculated from the concentration of H+ ion and the conjugate base. The ka value of protonated urea of the given pH is 7.92 ×10⁻¹⁵.

What is pH ?

pH of a solution is the measure of its H+ ion concentration. It is says how much acidic or basic the solution is. If the pH value is 7, then the solution is neutral and if it is less than 7 the solution is acidic. pH value greater than 7 indicates that the solution is basic.

pH of a solution mathematically is the negative logarithm of H+ ion concentration. Given that the pH of urea solution is 7.050. Thus its H+ ion concentration is calculated as follows;

-7.050 = log [H+]

[H+] = antilog (-7.050)

       = 8.9 × 10⁻⁸

Now when the protonated urea say it as HA is dissociated into its ions H+ and A-, then the ka value is written as;

[tex]Ka = \frac{[H+][A-]}{[HA]}[/tex]

Here, the [H+] and A- ion concentrations are equal and concentration of the solution HA is given 1 M.

Thus, Ka value of protonated urea can be calculated as follows:

Ka =  (8.9 × 10⁻⁸)² / (1-[ 8.9 × 10⁻⁸])

    = 7.92 ×10⁻¹⁵

Therefore, the acid ionization constant Ka of 1 M protonated urea with a pH of 7.050 is 7.92 ×10⁻¹⁵.

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Please help How many moles of a gas sample are in 5.0 L container at 215 K and 342 kPa(The gas constant is 8.31 L kPa/mol K) Round your answer to one decimal place and enter the number only with no units.

Answers

Answer

1.0 mol

Explanation

Given:

Volume, V = 5.0 L

Temperature, T = 215 K

Pressure, P = 342 kPa

The gas constant, R = 8.31 L kPa/mol K

What to find:

The number of moles of the gas sample.

Step-step-solution:

The number of moles of the gas can be determine using the ideal gas equation formula:

[tex]PV=nRT[/tex]

Put the given values into the formula and calculate for n:

[tex]\begin{gathered} 342\times5.0=n\times8.31\times215 \\ 1710=1786.65n \\ \text{Divide both sides by 1786.65} \\ \frac{1710}{1786.65}=\frac{1786.65n}{1786.65} \\ n=0.9571\text{ mol} \\ To\text{ one decimal place,} \\ n=1.0\text{ mol} \end{gathered}[/tex]

The number of moles of the gas sample is 1.0 mol.

How many molecules are there in 4.00 moles of glucose, C6H1206?​

Answers

Molecules in 4 moles of glucose are 24.088x10²³.

We need to find the number of molecules by applying the concept of moles

number of moles(n)= Number of Molecules(N)/Avogadro's Number(Nₐ)

n=N/Nₐ

4=N/6.022x10²³

N=24.088x10²³

Therefore, the number of molecules in 4 moles of Glucose is 24.088x10²³.

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A compound conducts electricity in the solid state and does not dissolve in water. It isshiny and malleable. What type of bonding does it likely have?b. Ionicc. metallica.Covalent

Answers

Metallic solids,

the atoms within such a metallic solid are held together by a unique force known as metallic bonding that gives rise to many useful and varied bulk properties. All exhibit high thermal and electrical conductivity, metallic luster, and malleability.

Answer: c. metallic

Which solution of the following has the lowest freezing point?
A. 40g of KBr dissolved in 200g of water
B. 30g of KBr dissolved in 100g of water
C. 20g of KBr dissolved in 250g of water
D. 10g of KBr dissolved in 100g of water

Pls do reply this answer with proper explanation.

Answers

Based on freezing point depression, the solution that has the lowest freezing point is 30g of KBr dissolved in 100g of water; option B.

What is freezing point depression?

Freezing point depression is a phenomenon that occurs when a solute is dissolved in a pure solvent such as water.

When a solute is dissolved in a solvent, the freezing point depression is calculated using the formula below:

∆T = i * K * m

Where;

i = number of moles of ions produced

K = mola freezing point depression constant

m = molality

From the data given, i (same salt, KBr) and k are both constants.

Hence, the freezing point depression depends on the molality of the solution.

molality = moles / mass of solvent in Kg

Assuming moles = mass (since salt is the same)

Molality of A = 40 / 0.2 = 200 molal

Molality of B = 30 / 0.1 = 300 molal

Molality of A = 20 / 0.25 = 80 molal

Molality of A = 10 / 0.1 = 100 molal

Hence, solution B will have the highest freezing point depression.

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what do sanding a piece of wood and rain forming into a cloud have in common

Answers

As a result, it is a natural bodily alteration. The chemical shape of the material is affected by physical changes, but not its makeup.

What kind of change is cloud formation?

Since natural water undergoes a phase transformation cycle from liquid to gas and back to liquid, the production of clouds is a physical shift.

The physical conversion of water from vapour to liquid during cloud formation is known as condensation. When water evaporates during the evaporation process and condenses in the air to form clouds, there is a physical shift that takes place.

Condensation is the process by which water transforms from a gas to a liquid, whereas deposition is the process by which a gas transforms straight into a solid. Clouds are created by these two processes.

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Based on its electron configuration, which element will most likely gain electrons from another element when forming an ionic compound?.

Answers

The element that is able to gain electrons and form an ionic bond is Iodine.

What is an ionic bond?

The term ionic bond has to do with the kind of bond that is formed between a metal and a non metal. In this type of bond, there is a transfer of electrons from the metal to the non metal. s such the metal would become positively charged while the non metal would become negatively charged as we can see in the crystal of the ionic compound.

We just have to look at the string of elements that we have been given because, this is how we can be able to make a decision about which of the elements would be able to gain an electron. While doing this, we must keep in kind that it is only the non metal that are able to gain electron within the context of forming an ionic bond.

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Missing parts;

Based on its electron configuration which element will most likely gain electrons from another element when forming an ionic compound? Potassium , Vanadium, Iodine, Xenon

coal-based power plants have a carbon dioxide emission of around 1,000 gco2eq/kwh. large scale hydropower plants have a carbon dioxide emission of around 30 gco2eq/kwh. rutgers university average power requirements is 20mw. what is the monthly (30 days) carbon dioxide emission reduction if the source of electricity is hydropower plant instead of coal-based generation?

Answers

In Niger State, Nigeria, there is a deposit of clay similar to kaolin that has a lot of promise for use in pollution control processes including wastewater treatment.

This study looks into the ideal settings for Kpautagi clay modification for use in treating the effluent from refineries. The clay was modified using sulphuric acid, and the modification factors taken into account were acid concentration, activation time, and temperature.

The sulphuric acid-modified Kpautagi clay was used in the treatment of refinery wastewater in column mode at a fixed flow rate and mass of adsorbent to establish the best conditions for the modification variables.

The results show that 4M acid concentration, 120min of activation time, and 100°C activation temperature are the best conditions for modifying Kpautagi clay for use in the treatment of petroleum refinery wastewater.

As a result, the best conditions discovered in this work for Kpautagi clay modification could be used to treat wastewater from petroleum refineries more effectively.

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Which two elements do not have a second energy level at all?

Answers

The two elements that do not have a second energy levels are Hydrogen (H) and Helium (He)

Energy levels are nothing but the 3-D spaces around the nucleus of an atom. The electrons revolve around the nucleus in their respective energy levels. Each energy levels can accommodate only a particular number of electrons.

For example, first energy level can accommodate only a maximum of 2 electrons whereas second energy level can accommodate 8 electrons.

Hydrogen has 1 electron and helium has 2 electrons around their respective nucleus. In both hydrogen and helium, electrons are accommodated in the first energy level.

Hence, the two elements that do not have a second energy levels are Hydrogen (H) and Helium (He)

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Name the following covalent bond Ch4

Answers

Answer:

sp³-s sigma bond.

Hope that was the answer

a student prepared an agno3 (aq) stock solution by dissolving an unknown mass of agno3 in a 250.00 ml volumetric flask and filling to the line with water. the student added 25.059 ml of the stock solution to a 500 ml volumetric flask and filled to the line with water to make 500 ml of a 9.443x10-3 m agno3 solution? what mass (in g) of agno3(s) did the student add to the 250 ml volumetric flask to make the stock solution?

Answers

Using the molarity of the final solution and the molar mass of silver nitrate, we can calculate that the student used 8.0015 g of silver nitrate to make the stock solution.

First, we calculate the number of moles in the 500.00 mL flask using the molarity (c) of the final solution and its volume (V = 500.00 mL = 0.50000 L).

c = n/V ⇒ n = c*V

n = 9.443 * 10⁻³ M * 0.50000 L

n = 4.7215 * 10⁻³ mol

This same number of moles was in the 25.059 mL solution that was subsequently diluted to 500.00 mL. Knowing this, we can make a simple proportion to calculate the number of moles present in the original 250.00 mL:

4.7215 * 10⁻³ mol : 25.059 mL = X : 250.00 mL

X = 4.7215 * 10⁻³ mol * 250.00 mL / 25.059 mL

X = 0.047104 mol

That's the amount (n) of silver nitrate used to make the stock solution. Now we can convert it to mass (m) by using the molar mass of silver nitrate (M = 169.87 g/mol):

n = m/M ⇒ m = n*M

m = 0.047104 mol * 169.87 g/mol

m = 8.0015 g

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boron has two naturally occurring isotopes: boron-10 (abundance 19.8%, mass 10.013 amu), boron-11 (abundance 80.2%, mass 11.009 amu). calculate the atomic mass of boron.

Answers

Answer:

Atomic mass of Boron: 10.8 amu

Explanation:

Boron-10: (0.198)(10.013) = 1.98 amu

Boron-11: (0.802)(11.009) =  8.83 amu

Add them up: 1.98+8.83= 10.8 amu

the distribution coefficient between methylene chloride and water for solute y is 11. an amount of 50.0 g of y is dissolved in 250 ml of water. a) what weight of y would be removed from water with a single extraction with 250-ml of methylene chloride? show calculations and report to 1 decimal place. copyright 2021. govindarajoo, g. rutgers, the state university of new jersey. all rights reserved. b) what weight of y would be removed from water (the original solution) with two successive extractions with 125-ml portions each of methylene chloride? show calculations and report to 1 decimal place.

Answers

Using the distribution coefficient, we can calculate the masses removed from water: a) 45.8 g; b) 48.8 g.

If the distribution coefficient between DCM (methylene chloride) and water is 11, that means that the concentration in DCM is 11 times greater than the concentration in water.

a) When equal volumes of the solvents are used, the amount of the solute in DCM (A) will be 11 times greater than the amount of solute remaining in water (B).

A + B = 50.0 g

A = 11 B

11 B + B = 50.0 g

12 B = 50.0 g

B = 50.0 g / 12

B = 4.17 g

A = 11 * 4.2 g

A = 45.8 g

b) Because the solvent volumes are not the same, we have to use concentrations. We can still label the mass of Y in DCM as A, and the mass of Y in water as B. After a single extraction with 125 mL of DCM we get:

A₁ + B₁ = 50.0 g

(A₁ / 125 mL) / (B₁ / 250 mL) = 11

2 A₁ / B₁ = 11

A₁ = 11 B₁ / 2

A₁ = 5.5 B₁

5.5 B₁ + B₁ = 50.0 g

6.5 B₁ = 50.0 g

B₁ = 50.0 g / 6.5

B₁ = 7.7 g

So, after the first extraction, 7.7 g of Y has remained in water. That means that for the second extraction:

A₂ + B₂ = 7.7 g

A₂= 5.5 B₂

5.5 B₂ + B₂ = 7.7 g

6.5 B₂ = 7.7 g

B₁ = 7.7 g / 6.5

B₁ = 1.2 g

After the second extraction, only 1.2 g of Y has remained in water, while 50.0 g - 1.2 g = 48.8 g of Y was removed from water.

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the reaction of tert-butyl bromide, (ch3)3cbr, with ethanol affords the substitution product tert-butyl ethyl ether, (ch3)3coch2ch3, in acidic conditions. what would happen to the rate of the reaction if the concentration of ethanol was doubled?

Answers

The rate of the reaction if the concentration of ethanol was doubled will remain the same.

The rate of the reaction tert-butyl ethyl ether, (ch3)3coch2ch3, in acidic conditions, will undergo the SN1 mechanism so the rate of reaction will remain the same.

The rate of reaction is the rate at which a chemical reaction takes region, defined as proportional to the increase inside the concentration of a product in step with unit time and to the lower within the awareness of a reactant in line with unit time. response prices can vary dramatically.

The speed with which a reaction takes area is called the fee of a response. as instance, timber combustion has a high response rate since the manner is fast, and rusting of iron has a low response rate as the technique is slow. Rate is most customarily calculated by the usage of the equation The devices of rate calculated in this manner are s -1.

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in part 2 of the experiment, you will be analyzing a sample of household bleach. a 0.0854 g sample of household bleach is completely reacted with ki(s). the resulting solution is then titrated with 0.150 m nas2o3 solution. 0.890 ml of the solution is required to reach the colorless endpoint. what is the mass percent of naocl (mm

Answers

There is  5.8 %  of NaOCl in the sample.

The oxidation of hypochlorite is the first process, which goes as follows:

OCl^- + 2I^- + 2H^+ -----> I2 + Cl2 + H2O

Iodine and sodium thiosulfate react in the second stage as follows:

I2 + 2NaS2O3 -----> Na2S4O6 + 2NaI

Thiosulfate moles = 0.150 M * 0.890/1000 L = 1.335 * 10-4 moles.

Since 2 molecules of thiosulfate react with 1 mole of I2,

1.335 * 10-4 moles of thiosulfate and x moles of I2 react.

x = 1.335 * 10-4 moles/2 moles times one mole.

Iodine equivalent to 6.675 x 10-5 moles

6.675 * 10-5 moles of hypochlorite were reacted because 1 mole of hypochlorite yields 1 mole of iodine.

Therefore, the mass of NaOCl is equal to 4.97 * 10-3 g (6.675 * 10-5 moles * 74.44 g/mole).

5.8% of NaOCl is equal to 4.97 * 10-3 g/0.0854 g * 100/1.

NaOCl makes up 5.8% of the sample.

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a 9.791 gram sample of an organic compound containing , and is analyzed by combustion analysis and 14.35 grams of and 5.876 grams of are produced. in a separate experiment, the molar mass is found to be 60.05 g/mol. determine the empirical formula and the molecular formula of the organic compound.

Answers

The empirical formula of the compound is CH₂O, and the molecular formula of the compound is C₂H₄O₂.

All of the carbon in the compound is converted into carbon dioxide (14.35 g) and all the hydrogen in the compound is converted to water (5.876 g). This means that we can use these masses to find the masses of carbon, hydrogen, and oxygen in the original compound.

First, we calculate the mass of carbon in carbon dioxide and the mass of hydrogen in water, using their respective molar masses (M(CO₂) = 44 g/mol; M(H₂O) = 18 g/mol):

12 g of carbon : 44 g of carbon dioxide = X : 14.35 g of carbon dioxide

X = 12 g of carbon * 14.35 g of carbon dioxide / 44 g of carbon dioxide

X = 3.914 g of carbon

2 g of hydrogen : 18 g of water = X : 5.876 g of water

X = 2 g of hydrogen : 5.876 g of water / 18 g of water

X = 0.6529 g of hydrogen

Because the compound contains carbon, hydrogen and oxygen, we can now calculate the mass of oxygen in the compound:

m(O) = m(sample) - m(C) - m(H)

m(O) = 9.791 g - 3.914 g - 0.6529 g

m(O) = 5.224 g

Now we use these masses to calculate the number of moles (n) for each of the elements, using their respective molar masses (M(C) = 12 g/mol, M(H) = 1 g/mol, M(O) = 16 g/mol):

n = m/M

n(C) = m(C) / M(C)

n(C) = 3.914 g / 12 g/mol

n(C) = 0.3284 mol

n(H) = m(H) / M(H)

n(H) = 0.6529 g / 1 g/mol

n(H) = 0.6529 mol

n(O) = m(O) / M(O)

n(O) = 5.224 g / 16 g/mol

n(O) = 0.3265 mol

We divide each of these amounts by the smallest of them (0.3265 mol) to obtain the molar ratio of the elements:

carbon: 0.3284 mol / 0.3265 mol = 1.006

hydrogen: 0.6529 mol / 0.3265 mol = 2.000

oxygen: 0.3265 mol / 0.3265 mol = 1.000

These integers are indexes in the empirical formula of the compound - CH₂O

The molar mass of this empirical formula is:

12 g/mol + 2 * 1 g/mol + 16 g/mol = 30 g/mol

We divide the molar mass of the compound by the molar mass of the empirical formula:

60.05 g/mol / 30 g/mol = 2.002

So, we multiply the indexes by 2 to obtain the molecular formula - C₂H₄O₂

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If a molecule has strong intermolecular forces, would you expect for it to have a high or low vapor pressure?.

Answers

A molecule with strong intermolecular forces will have a weak or low vapor pressure.

Molecules generally with a high intermolecular force of attraction will have a low vapor pressure. This is because since the force of attraction between molecules is high as they are tightly packed, only fewer molecules will get a chance to move with kinetic energy at a given temperature.

Whereas, molecules with weak intermolecular force can travel easily and escape and so will have a greater vapor pressure. But it is not the case with strong intermolecular forces. Molecules with high vapor pressure are called volatile. Therefore, the molecules with strong intermolecular forces will have a low vapor pressure, and only that is expected to happen in such cases.

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Why are low pressure systems associated with high temperatures?

Answers

Low pressure systems associated with high temperatures because warm air rises :)

Determine the energy of a photon whose frequency is 5.94x10^17Hz. Answer in units of J

Answers

Answer:

[tex] \huge{ 3.935 \times {10}^{ - 16} J}[/tex]

Explanation:

The energy of the photon can be found by using the formula

E = hf

where

E is the energy

f is the frequency

h is the Planck's constant which is

6.626 × 10-³⁴ Js

From the question the frequency is

5.94x10^17Hz

We have

[tex]E = 6.626 \times {10}^{ - 34} \times 5.94 \times {10}^{17} \\ = 3.935 \times {10}^{ - 16} J[/tex]

Hope this helps you

Is "Honey with water" a homogeneous or heterogeneous mixture? explain why?​

Answers

Answer: Homogenous mixture

Mixing honey with water will give you a homogenous mixture. It is uniform and even, as the honey particles are distributed equally throughout the water.

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The heating curve shows the energy gain of a substance as it changes from solid to gas. Which section of the graph shows the liquid phase of the
substance gaining kinetic energy?
A. A
B. B
C. C
D. D
E. E

Answers

The heating curve is a graphical representation of how various phases of substances change as temperature or heat increases. The graph's C section depicts the liquid phase of the substance gaining kinetic energy.

What is kinetic energy?

Kinetic energy is the energy that an object has as a result of its movement. If we want to accelerate an object, we must apply force to it. Using force requires us to put in effort. When the work is finished, energy is transferred to the object, and it moves at a new constant speed.

Therefore,

Section A represents the solid phase

Section B the solid-liquid phase

Section C the liquid phase

Section D the liquid-gas phase

Section E the gas phase

Section C of the graph depicts the substance's liquid phase gaining kinetic energy. Heat energy is absorbed during Phase C, and liquid particles gain kinetic energy to change into gas form in Section E.

As a result, C.C. is the correct answer.

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5. few spiders are
dangerous because they
are

Answers

The answer is Poisonous

a reaction involving acetic acid has an enthalpy change of 55.7 kj/mol. what is the concentration of 27.90-ml of this acetic acid solution if the reaction it is involved in evolves 716.12-j of heat?

Answers

not gon find it here cuh

Explanation:

The concentration of the acetic acid solution is approximately 0.0128 mol/L, given the information provided.

To determine the concentration of the acetic acid solution, we need to use the given enthalpy change and the heat evolved in the reaction.

The enthalpy change (ΔH) is given as 55.7 kJ/mol, which represents the heat released or absorbed per mole of acetic acid involved in the reaction.

The heat evolved in the reaction is given as 716.12 J. However, we need to convert it to kilojoules to match the unit of the enthalpy change. There are 1000 J in 1 kJ, so 716.12 J is equal to 0.71612 kJ.

Now, we can set up a proportion to find the concentration of the acetic acid solution. The heat evolved is directly proportional to the moles of acetic acid involved in the reaction, which is in turn proportional to the concentration of the solution.

Let's assume the concentration of the acetic acid solution is c mol/L.

The proportion can be set up as:

ΔH (kJ/mol) / Heat evolved (kJ) = 1 mol / c L

Substituting the values we have:

55.7 kJ/mol / 0.71612 kJ = 1 mol / c L

Simplifying:

c = 1 mol / (55.7 kJ/0.71612 kJ)

c ≈ 0.0128 mol/L

Therefore, the concentration of the acetic acid solution is approximately 0.0128 mol/L, given the information provided.

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aldol condensation is an easy way of making: group of answer choices carbon-carbon bond carbon-oxygen bond carbon-nitrogen bond carbon-hydrogen bond all of these bond types

Answers

Aldol condensation is an easy way of making carbon-carbon bond.

In the field of chemistry, we can describe aldol condensation as a type of bond that occurs due to electrophilic substitution at the alpha carbons of the enol.

Aldol condensation is known to be the easiest way for one carbon to form bonds with another carbon.

Such an aldol reaction that takes place between carbonyl compunds instead of aldehydes or enols is referred to as crossed aldol condensation.

Aldol reactions are known to be an important part of synthesizing organic compounds as carbon-carbon bonds are formed due to it.

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Five liters of hydrogen gas are stored at a pressure of 400
torr. If the temperature does not change, what will be the
volume of the gas when the pressure is decreased to 250
torr?

Answers

Five liters of hydrogen gas are stored at a pressure of 400 torrs. If the temperature does not change, then the volume of the gas would be 8 liters when the pressure is decreased to 250 torrs.

What is an ideal gas?

It is an imaginary gas for which the volume occupies by it is negligible, this gas does not exist in a practical situation and the concept of an ideal gas is only the theoretical one,

Using the Boyle's law for the given problem,

P₁V₁=P₂V₂

400 × 5 = 250 × V₂

V₂ = 400 × 5 / 250

    = 8 Litres

Thus, if the temperature does not change the volume of the gas would be  8 Litres.

Learn more about ideal gas from here, refer to the link ;

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Can someone help me pls, i have like another 3 questions like this .-.

Answers

Answer:

1st box: Potential

2nd box: Electrical

3rd box: Kinetic

Explanation:

(1st box) Potential because the energy is stored and ready to act, which is definitely something desired for a battery.

(2nd box) Chemical, as discussed in the comments

(3rd box) Kinetic because the stored, potential energy is now 'acting' or 'in motion', causing it to be kinetic energy.

Answer:

Batteries store potential chemical energy

That the swith releases it into kinetic energy to light the room.

Explanation:

Energy comes in two main forms:

Kinetic energy which is energy of moving object or motion.

2. Potential energy which is energy stored in object to be realesed to make effect. It can be stored in form of

Chemical energy. This can be in fuels or food taken by human body or the battery. Gravitational energy. This is due to the gravity and the force pulling the object from a height. Elastic energy. It is energy stored in rubber bands and spring balances.

And there is much more....

Principle of conservation of energy says energy is not created nor destroyed but transferred from and object to another in different forms.

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