Answer:
Sulphur
Explanation
Rhombic and monoclinic sulphur are its allotropic forms
Draw both the chair and boat conformation of 1,4-dimethylcyclohexane with the methyl groups as cis and trans for both conformations. Label your molecules for cis and trans. Tell which is the highest in energy.
Answer:
Boat conformation cis 1,4-dimethyl cyclohexane has the highest energy.
Explanation:
From the conformations, the boat conformation cis 1,4-dimethyl cyclohexane is least stable due to the fact that two methyl groups are located in opposite direction to each other, this leads to the production of a higher strain. Similarly, Chair conformations appear more stable than boat conformation. Hence, energy is inversely proportional to stability. As a result of the aforementioned, boat conformation cis 1,4-dimethyl cyclohexane has the highest energy.
What is the molecular formula for a compound with a molar mass of 42.08g/mol and an empirical formula of ch2
Answer:
[tex]C_3H_6[/tex]
Explanation:
Hello!
In this case, since the empirical formula is the smallest representation of the molecular formula, it is known that the times in which the empirical formula is into the molecular formula is a whole number and is computed by dividing the molar mass of the molecular formula by that of the empirical formula as shown below:
[tex]\frac{42.08g/mol}{12.01+1.01x2}= \frac{42.08g/mol}{14.03g/mol}=3[/tex]
Thus, the molecular formula times the empirical formula by 3 to obtain:
[tex]C_3H_6[/tex]
Regards!
3) Tears are produced by the lacrimal glands located:
A) above the lateral canthus of each eye
B) below the medial canthus of each eye
C) below the lateral canthus of each eye
D) above the medial canthus of each eye
E) behind the nasal bones
List all possible oxidation numbers for the elements. 21. Al
22. Bi
23. Ni
24. Xe
25. Pb
Answer:
21. Al (Aluminium)
+3 (most common), -1, -2, +1, +2
22. Bi (Bismuth)
+3 (most common), -3, -2, -1, +1, +2, +4, +5
23. Ni (Nickel)
+2 (most common), -2, -1, 0,+1, +3, +4
24. Xe (Xenon)
0 (most common), +1, +2, +4, +6, +8
25. Pb (Lead)
+2 (most common), +4 (most common), -4, -2, -1, +1, +3
Explanation:
Now we proceed to present the answers for each element:
21. Al (Aluminium)
+3 (most common), -1, -2, +1, +2
22. Bi (Bismuth)
+3 (most common), -3, -2, -1, +1, +2, +4, +5
23. Ni (Nickel)
+2 (most common), -2, -1, 0,+1, +3, +4
24. Xe (Xenon)
0 (most common), +1, +2, +4, +6, +8
25. Pb (Lead)
+2 (most common), +4 (most common), -4, -2, -1, +1, +3
What are the outcomes of the ice cap melting? Choose all that apply.
1. Light cannot be reflected back to the atmosphere
2. Sea level rises
3. Absorption of solar radiation leads to increase in ocean temperature
4. Ocean remains unaffected
Answer:
2. sea level rises sorry if it's wrong
which is a characteristics of all ions
Answer:
All ions must a overall charge
Explanation:
Answer:
i belive its B
Explanation:
Which of the following is a radioactive element?Sodium, Fluorine,Oxygen
francium
Answer:
Fluorine
Explanation:
These particles stick in the atoms and make them radioactive.
(1) Phosphorus silicon is a semi-conductor
When Silicone is altered with Phosphorus, 4 of its electrons form covalent bonding and the 5th electron becomes delocalized and thus it increases electrical conduction
Answer:
blue blah blue blah
Explanation:
Which animal is a primary consumer in the Ethiopian Highlands?
Answer:
I believe it is the Ethiopian ibex
Explanation:
Answer:
I think it the Ethiopian ibex
Explanation:
im srry if it wrong.
hope this helps tho
Do earthquakes occur at convergent plate boundaries?
Yes or no?
Answer:yes
Explanation:
Determine the molar mass of Cao
Answer:
Molar mass of CaO
(40 + 16)g
= 56g
hope it helps you
g What amounts of 45% pure silver and 50% pure silver should be mixed to obtain 14 grams of 46% pure silver
Answer:
11.2g of the 45% pure silver and 2.8g of the 50% pure silver.
Explanation:
14g of 46% pure silver contains:
14g*46% = 6.44g of silver are required. Thus, we can write:
6.44 = X*50% + Y*45% (1)
Where X is the mass of 50% pure silver and Y the mass of 45% pure silver.
As the mass of the sample must be 14g:
14g = X + Y (2)
Replacing (2) in (1):
6.44 = (14-Y)*50% + Y*45%
6.44 = 7 - 0.5Y + 0.45Y
-0.56 = -0.05Y
Y = 11.2g of the 45% pure silver
And:
14g-11.2g = X
X =
2.8g of the 50% pure silver
The required amount to obtain 14g of 46% pure silver is 2.8g of 50% silver and 11.2g of 45% silver.
To solve this question, we can assume it's a mathematical problem more than a chemistry problem.
let x represent the amount of 45% of pure Ag
let y represent the amount of 50% of pure Ag
But from the question, we only need 14g from both x and y
We can write an equation to represent this
[tex]x+y=14...equation(i)[/tex]
likewise, we can say that
[tex]0.45x+0.50y=14*0.46\\0.45x+0.50y=6.44...equation(ii)[/tex]
Solving both equations simultaneously,
[tex]x+y=14...equation(i)\\0.45x+0.5y=6.44...equation(ii)[/tex]
from equation (i)
[tex]x+y=14\\x=14-y...equation(iii)[/tex]
substitute equation (iii) into equation (ii)
[tex]0.45x+0.5y=6.44\\x=14-y\\0.45(14-y)+0.5y=6.44\\6.3-0.45y+0.5y=6.44\\[/tex]
collect like terms
[tex]-0.45y+0.50y=6.44-6.3\\0.05y=0.14\\y=\frac{0.14}{0.05}\\y=2.8[/tex]
Now we know the value of the 50% Ag which is 2.8g. Let's substitute it's value into equation (i) and solve for x
[tex]x+y=14\\x+2.8=14\\x=14-2.8\\x=11.2g[/tex]
Learn more about definite proportions here
https://brainly.com/question/1496091
which element can form an oxide with the general formula m2o or mo where m is a metal
Answer:
Because the compound has a formula of M2O, the number of valence electrons of M should be 1. Therefore, (1) Group 1 is the correct answer because elements in group 1 have 1 valence electron.
Explanation:
How many pounds of gold ore would need to be processed to obtain 5 grams of gold (Au) if the ore is 0.1% gold by mass?
Pounds of gold ore : 11,02311
Further explanationGiven
5 g of gold
0.1% gold by mass
Required
Pounds of gold ore
Solution
[tex]\tt \%mass~gold=\dfrac{mass~gold}{mass~ore}\times 100\%[/tex]
For percent mass = 0.1%, than mass of gold ore :
[tex]\tt 0.1\%=\dfrac{5~g}{mass~ore}\times 100\%\\\\mass~ore=\dfrac{5\times 100}{0.1}\\\\mass~ore=5000~g[/tex]
Conversion factor :
1 g = 0,00220462 pound, than for 5000 g = 11,02311 pounds
grams can be converted to moles and vice versa which conversion factors is/are used for this
Answer:
Converting Grams to Moles of an Element and Vice Versa.
We can convert back and forth between grams of an element and moles.
The conversion factor for this is the molar mass of the substance. The molar mass is the ratio giving the number of grams for each one mole of the substance
molar mass is the factor
Grams can be converted to moles and vice versa so the conversion factor which is used for this is molar mass.
How do we convert mass into moles?Mass of any substance will be converted into moles by using the below equation:
n = W/M, where
n = moles
W = given mass
M = molar mass
By using the above formula we can convert the mass of any object to moles and moles to mass.
Hence conversion factor which is used for this is molar mass(M).
To know more about mass & moles, visit the below link:
https://brainly.com/question/24639749
#SPJ2
What mass of hydrogen is required to react with 24.7 g of nitrogen?
Answer:
10.80 g of H2
Explanation:
As per the equation, let us calculate the mole ratio. N2+3H2→2NH3. As per the equation one mole of nitrogen
What mass of solid aluminum hydroxide can be produced when 50.0mL of 0.200M aluminum nitrate is added to 200.0mL of 0.100M potassium hydroxide
Answer:
520 mg Al(OH)₃
Explanation:
The reaction that takes place is:
Al(NO₃)₂ + 3KOH → Al(OH)₃ + 3KNO₃Now we calculate how many moles of each reagent were added, using their concentrations and volumes:
Al(NO₃)₂ ⇒ 50.0 mL * 0.200 M = 10 mmol Al(NO₃)₂ KOH ⇒ 200.0 mL * 0.100 M = 20 mmol KOH10 mmol of Al(NO₃)₂ would react completely with (10*3) 30 mmol of KOH, there are not as many KOH mmol, so KOH is the limiting reactant.
We calculate how many moles of Al(OH)₃ are produced, using the limiting reactant:
20 mmol KOH * [tex]\frac{1mmolAl(OH)_3}{3mmolKOH}[/tex] = 6.67 mmol Al(OH)₃Finally we convert mmol of Al(OH)₃ to mg, using its molar mass:
6.67 mmol Al(OH)₃ * 78 mg/mmol = 520 mg Al(OH)₃How are food webs and food chains related? HELP IF YOU WANT BRAINLEIST!!
Food webs only contain consumers.
Food webs consist of only one food chain.
Food webs are made of many food chains.
Food webs only contain producers.
Answer: Food webs are made of many food chains is the answer.
Explanation:
Food web consists many food chains.
10 points!!!!!!!!!!!!!!!!!!!!!!!!!!
Answer:
B
Explanation:
i think the filtering would make it possible to separate the liquids....
Answer:
My friend is guessing so she says it's letter C
Explanation:
Sorry if she is wrong.
Which of the following conditions does not affect equilibrium?
A. Particle Size
B. None of these
C. Concentration
D. Pressure
Answer:
B. None of these
Explanation:
Consider the reaction of solid aluminum iodide and potassium metal to form solid potassium iodide and aluminum metal.The balanced chemical equation is AlI₃(s) + 3 K(s) → 3 KI(s) + Al(s).Given the reaction has a percent yield of 67.8%, what is the mass in grams of aluminum iodide that would be required to yield an actual amount of 30.25 grams of aluminum?
Answer:
674.26 g of AlI₃
Explanation:
We'll begin by calculating the theoretical yield of aluminum (Al). This can be obtained as follow:
Percentage yield of Al = 67.8%
Actual yield of Al = 30.25 g
Theoretical yield of Al =?
Percentage yield = Actual yield /Theoretical yield × 100/
67.8% = 30.25 / Theoretical yield
67.8 / 100 = 30.25 / Theoretical yield
0.678 = 30.25 / Theoretical yield
Cross multiply
0.678 × Theoretical yield = 30.25
Divide both side by 0.678
Theoretical yield = 30.25 / 0.678
Theoretical yield of Al = 44.62 g
Next, we shall determine the mass of AlI₃ that reacted and the mass of Al produced from the balanced equation. This can be obtained as follow:
AlI₃(s) + 3K(s) → 3KI(s) + Al(s)
Molar mass of AlI₃ = 27 + (3×127)
= 27 + 381 = 408 g/mol
Mass of AlI₃ from the balanced equation = 1 × 408 = 408 g
Molar mass of Al = 27 g/mol
Mass of Al from the balanced equation = 1 × 27 = 27 g
Summary:
From the balanced equation above,
408 g of AlI₃ reacted to produce 27 g of Al.
Finally, we shall determine the mass of
AlI₃ required to produce 44.62 g of Al. This can be obtained as follow:
From the balanced equation above,
408 g of AlI₃ reacted to produce 27 g of Al.
Therefore, Xg of AlI₃ will react to produce 44.62 g of Al i.e
Xg of AlI₃ = (408 × 44.62)/27
Xg of AlI₃ = 674.26 g
Thus, 674.26 g of AlI₃ is needed for the reaction.
As ice cream freezes do the chemical properties of the substance change? Explain why or why not?
which of the following statements are part of the kinetic molecular theory ?
Answer: The average kinetic energy is proportional to the absolute temperature of the gas. Gas particles are in random motion. Gas particles have no volume. And the collisions between gas particles are elastic.
Explanation: I heard this question before, I think. Hope this helps!
A mixture of ethyne gas (C2H2) and methane gas (CH4) occupied a certain volume at a total pressure of 16.8 kPa. When the sample burned, the products were CO2 gas and H2O vapor. The CO2 was collected and its pressure found to be 25.2 kPa in the same volume and at the same temperature as the original mixture. What percentage of the original mixture was methane
Answer:
50%
Explanation:
Let assume that there are:
"a" moles of CH4 & "b" moles of C2H2
Then by applying the ideal gas equation:
PV = nRT
[tex]16.8 \times 10^3 \times V = (a+b)RT[/tex]
Make (a+b) the subject of the formula:
[tex](a+b) = \dfrac{16800 \ V }{RT} mol[/tex] --- (1)
Since 1 mole of CH₄ yields 1 mol of CO₂ & 1 mol of C₂H₂ yields 2 moles of CO₂
Then;
the total moles of CO₂ = (a +2b)
Now:
[tex]25.3 \times 10^3 \times V = (a+ 2b)RT[/tex]
[tex](a + 2b) = \dfrac{25200 \ V}{RT \ mol}[/tex] ---- (2)
∴
By solving the above equations
[tex]a = \dfrac{8400 \ V}{RT} \\ \\ b = \dfrac{8400 \ V}{RT}[/tex]
Hence, the estimate of the percentage of methane in the original mixture is:
[tex]= 100 \times \dfrac{a}{(a+b)}[/tex]
[tex]= 100 \times \dfrac{8400\dfrac{ \ V}{RT} }{8400\dfrac{ \ V}{RT} + 8400\dfrac{ \ V}{RT}}[/tex]
= 50%
(1132 CHCH2CH = CH2
12. Give the complete IUPAC name for each of the following compounds:
(a) (CH3)2CHF
(b) CH3CHCICHCICH3
(C)
CH3CHCH;
CH2CH3
(d) CH3 CH2 CH = CHCHZ
(e)
CH3CH2CH2CHBCH2CH3
CH2CH=CH2
Answer:
Ok:
Explanation:
a) 2-fluoropropane
b) 2,3 dichlorobutane
c) pent-2-ene or 2 pentene (I assume the semicolon was a typo)
d) Same as c (I assume Z is a typo too)
e) non-1-ene or 1-nonene (I assume the B is a 2)
Which of the following is NOT an advantage of a wireless network? convenience reliability security speed
Answer:
Security
Explanation:
A wireless network consists of good connection with fast speed, convenience, and reliability. Security is a major problem with wireless connection as someone can get your information by joining the same connection as you.
Two inductors are connected in series to a 120 volt, 60 Hz line. The values are .75 H and 1.47 H. The total inductive reactance is
Answer:
837.02 ohms
Explanation:
Step one:
Given data
Frequency= 60Hz
L1= 0.75H
L2= 1.47H
When inductors are connected in series, the total inductance is the sum of the individual inductance
Step two:
Inductor 1
[tex]Xl1= 2\pi fL\\\\Xl1= 2*3.142*60*0.75\\\\Xl1= 282.78 ohms[/tex]
Inductor 2
[tex]Xl2= 2\pi fL\\\\Xl2= 2*3.142*60*1.47\\\\Xl2= 554.24 ohms[/tex]
The total inductance is
=282.78+554.24
=837.02 ohms
what is the answer to this question?
Answer:
Vertebrae
Explanation:
Vertebrae are the 33 individual bones that interlock with each other to form the spinal column. The vertebrae are numbered and divided into regions: cervical, thoracic, lumbar, sacrum, and coccyx (Fig. 2). Only the top 24 bones are moveable; the vertebrae of the sacrum and coccyx are fused.
I believe the answer is vertebrae. There are 24 bones stacked up on each other that make up your backbone.
Weather, erosion and deposition will change the environment over time. When water runs over rocks it can smooth out jagged edges and even leave streak on the surface of the rock. This is an example of _____________.
Answer:
erosion.
Explanation:
A sample of gas has a density of 0.53 g/L at 225 K and under a pressure of 108.8 kPa. Find the density of the gas at 345 K under a pressure of 68.3 kPa. Assuming the mass is equal to 1 gram.
Answer:
[tex]\rho _2=0.22g/L[/tex]
Explanation:
Hello!
In this case, since we are considering an gas, which can be considered as idea, we can write the ideal gas equation in order to write it in terms of density rather than moles and volume:
[tex]PV=nRT\\\\PV=\frac{m}{MM} RT\\\\P*MM=\frac{m}{V} RT\\\\P*MM=\rho RT[/tex]
Whereas MM is the molar mass of the gas. Now, since we can identify the initial and final states, we can cancel out R and MM since they remain the same:
[tex]\frac{P_1*MM}{P_2*MM} =\frac{\rho _1RT_1}{\rho _2RT_2} \\\\\frac{P_1}{P_2} =\frac{\rho _1T_1}{\rho _2T_2}[/tex]
It means we can compute the final density as shown below:
[tex]\rho _2=\frac{\rho _1T_1P_2}{P_1T_2}[/tex]
Now, we plug in to obtain:
[tex]\rho _2=\frac{0.53g/L*225K*68.3kPa}{345K*108.8kPa}\\\\\rho _2=0.22g/L[/tex]
Regards!
