Which has a bigger surface area, powder or marble chips

Answers

Answer 1

Answer:

powder

Explanation:

Between the powder and marble chips, the powder will have a larger surface area.

For the same masses of a solid substance in different forms such as lump, granules or powder, the smaller particle size of each form the larger the surface area.

Surface area increases from lumps to granules and them powder

A powder has the largest surface area and hence undergoes a more faster chemical reaction.

Related Questions

Determine the molar mass of Cao​

Answers

Answer:

Molar mass of CaO

(40 + 16)g

= 56g

hope it helps you

What makes this inauguration different from the past?

Answers

Answer:

there's just a lot of drama around grumpy trumpy's StOlEN eLecTiOn which are all just fake claims. all his hardcore followers are brainwashed into believing anything he says, so people (especially people who are inside the capitol) fear that trump's followers might incite violence AGAIN even after they broke into the Capitol on the 6th.

That's why they have the National Guard and thousands of people to keep the building secure during Biden's Inauguration.

hope this helps!

Do earthquakes occur at convergent plate boundaries?
Yes or no?

Answers

Answer:yes

Explanation:

Which animal is a primary consumer in the Ethiopian Highlands?

Answers

Answer:

I believe it is the Ethiopian ibex

Explanation:

Answer:

I think it the Ethiopian ibex

Explanation:

im srry if it wrong.

hope this helps tho

grams can be converted to moles and vice versa which conversion factors is/are used for this

Answers

Answer:

Converting Grams to Moles of an Element and Vice Versa.

We can convert back and forth between grams of an element and moles.

The conversion factor for this is the molar mass of the substance. The molar mass is the ratio giving the number of grams for each one mole of the substance

molar mass is the factor

Grams can be converted to moles and vice versa so the conversion factor which is used for this is molar mass.

How do we convert mass into moles?

Mass of any substance will be converted into moles by using the below equation:

n = W/M, where

n = moles

W = given mass

M = molar mass

By using the above formula we can convert the mass of any object to moles and moles to mass.

Hence conversion factor which is used for this is molar mass(M).

To know more about mass & moles, visit the below link:

https://brainly.com/question/24639749

#SPJ2

The subatomic particle that is different in isotopes

Answers

Answer:

Neutrons

Explanation:

Subatomic particles are components atoms, and they include protons, electrons and neutrons. In different isotopes of an atom, the number of neutrons that the atom contains is what changes.

I hope this helps!

Consider the reaction of solid aluminum iodide and potassium metal to form solid potassium iodide and aluminum metal.The balanced chemical equation is AlI₃(s) + 3 K(s) → 3 KI(s) + Al(s).Given the reaction has a percent yield of 67.8%, what is the mass in grams of aluminum iodide that would be required to yield an actual amount of 30.25 grams of aluminum?

Answers

Answer:

674.26 g of AlI₃

Explanation:

We'll begin by calculating the theoretical yield of aluminum (Al). This can be obtained as follow:

Percentage yield of Al = 67.8%

Actual yield of Al = 30.25 g

Theoretical yield of Al =?

Percentage yield = Actual yield /Theoretical yield × 100/

67.8% = 30.25 / Theoretical yield

67.8 / 100 = 30.25 / Theoretical yield

0.678 = 30.25 / Theoretical yield

Cross multiply

0.678 × Theoretical yield = 30.25

Divide both side by 0.678

Theoretical yield = 30.25 / 0.678

Theoretical yield of Al = 44.62 g

Next, we shall determine the mass of AlI₃ that reacted and the mass of Al produced from the balanced equation. This can be obtained as follow:

AlI₃(s) + 3K(s) → 3KI(s) + Al(s)

Molar mass of AlI₃ = 27 + (3×127)

= 27 + 381 = 408 g/mol

Mass of AlI₃ from the balanced equation = 1 × 408 = 408 g

Molar mass of Al = 27 g/mol

Mass of Al from the balanced equation = 1 × 27 = 27 g

Summary:

From the balanced equation above,

408 g of AlI₃ reacted to produce 27 g of Al.

Finally, we shall determine the mass of

AlI₃ required to produce 44.62 g of Al. This can be obtained as follow:

From the balanced equation above,

408 g of AlI₃ reacted to produce 27 g of Al.

Therefore, Xg of AlI₃ will react to produce 44.62 g of Al i.e

Xg of AlI₃ = (408 × 44.62)/27

Xg of AlI₃ = 674.26 g

Thus, 674.26 g of AlI₃ is needed for the reaction.

A sample of gas has a density of 0.53 g/L at 225 K and under a pressure of 108.8 kPa. Find the density of the gas at 345 K under a pressure of 68.3 kPa. Assuming the mass is equal to 1 gram.

Answers

Answer:

[tex]\rho _2=0.22g/L[/tex]

Explanation:

Hello!

In this case, since we are considering an gas, which can be considered as idea, we can write the ideal gas equation in order to write it in terms of density rather than moles and volume:

[tex]PV=nRT\\\\PV=\frac{m}{MM} RT\\\\P*MM=\frac{m}{V} RT\\\\P*MM=\rho RT[/tex]

Whereas MM is the molar mass of the gas. Now, since we can identify the initial and final states, we can cancel out R and MM since they remain the same:

[tex]\frac{P_1*MM}{P_2*MM} =\frac{\rho _1RT_1}{\rho _2RT_2} \\\\\frac{P_1}{P_2} =\frac{\rho _1T_1}{\rho _2T_2}[/tex]

It means we can compute the final density as shown below:

[tex]\rho _2=\frac{\rho _1T_1P_2}{P_1T_2}[/tex]

Now, we plug in to obtain:

[tex]\rho _2=\frac{0.53g/L*225K*68.3kPa}{345K*108.8kPa}\\\\\rho _2=0.22g/L[/tex]

Regards!

which element can form an oxide with the general formula m2o or mo where m is a metal

Answers

Answer:

Because the compound has a formula of M2O, the number of valence electrons of M should be 1. Therefore, (1) Group 1 is the correct answer because elements in group 1 have 1 valence electron.

Explanation:

As ice cream freezes do the chemical properties of the substance change? Explain why or why not?

Answers

Yes. When ice cream is melted is a liquid and therefore jot a solid. When it freezes it becomes a solid

What mass of solid aluminum hydroxide can be produced when 50.0mL of 0.200M aluminum nitrate is added to 200.0mL of 0.100M potassium hydroxide

Answers

Answer:

520 mg Al(OH)₃

Explanation:

The reaction that takes place is:

Al(NO₃)₂ + 3KOH → Al(OH)₃ + 3KNO₃

Now we calculate how many moles of each reagent were added, using their concentrations and volumes:

Al(NO₃)₂ ⇒ 50.0 mL * 0.200 M = 10 mmol Al(NO₃)₂ KOH ⇒ 200.0 mL * 0.100 M = 20 mmol KOH

10 mmol of Al(NO₃)₂ would react completely with (10*3) 30 mmol of KOH, there are not as many KOH mmol, so KOH is the limiting reactant.

We calculate how many moles of Al(OH)₃ are produced, using the limiting reactant:

20 mmol KOH * [tex]\frac{1mmolAl(OH)_3}{3mmolKOH}[/tex] = 6.67 mmol Al(OH)₃

Finally we convert mmol of Al(OH)₃ to mg, using its molar mass:

6.67 mmol Al(OH)₃ * 78 mg/mmol = 520 mg Al(OH)₃

Two inductors are connected in series to a 120 volt, 60 Hz line. The values are .75 H and 1.47 H. The total inductive reactance is

Answers

Answer:

837.02 ohms

Explanation:

Step one:

Given data

Frequency= 60Hz

L1= 0.75H

L2= 1.47H

When inductors are connected in series, the total inductance is the sum of the individual inductance

Step two:

Inductor 1

[tex]Xl1= 2\pi fL\\\\Xl1= 2*3.142*60*0.75\\\\Xl1= 282.78 ohms[/tex]

Inductor 2

[tex]Xl2= 2\pi fL\\\\Xl2= 2*3.142*60*1.47\\\\Xl2= 554.24 ohms[/tex]

The total inductance is

=282.78+554.24

=837.02 ohms

PlEasE help ASAP
Snskskssmskssm

Answers

Answer:

message me on messenger johnpatrick so I can help you

Which of the following conditions does not affect equilibrium?

A. Particle Size
B. None of these
C. Concentration
D. Pressure

Answers

Answer:

B. None of these

Explanation:

Which of the following is a radioactive element?Sodium, Fluorine,Oxygen
francium

Answers

Answer:

Fluorine

Explanation:

These particles stick in the atoms and make them radioactive.

(1) Phosphorus silicon is a semi-conductor

Answers

When Silicone is altered with Phosphorus, 4 of its electrons form covalent bonding and the 5th electron becomes delocalized and thus it increases electrical conduction

Answer:

blue blah blue blah

Explanation:

List all possible oxidation numbers for the elements. 21. Al
22. Bi
23. Ni
24. Xe
25. Pb

Answers

Answer:

21. Al (Aluminium)

+3 (most common), -1, -2, +1, +2

22. Bi (Bismuth)

+3 (most common), -3, -2, -1, +1, +2, +4, +5

23. Ni (Nickel)

+2 (most common), -2, -1, 0,+1, +3, +4

24. Xe (Xenon)

0 (most common), +1, +2, +4, +6, +8

25. Pb (Lead)

+2 (most common), +4 (most common), -4, -2, -1, +1, +3

Explanation:

Now we proceed to present the answers for each element:

21. Al (Aluminium)

+3 (most common), -1, -2, +1, +2

22. Bi (Bismuth)

+3 (most common), -3, -2, -1, +1, +2, +4, +5

23. Ni (Nickel)

+2 (most common), -2, -1, 0,+1, +3, +4

24. Xe (Xenon)

0 (most common), +1, +2, +4, +6, +8

25. Pb (Lead)

+2 (most common), +4 (most common), -4, -2, -1, +1, +3

Balance the chemical equation below using the smallest possible whole number stoichiometric coefficients. FE2O3(s) Fe(s) O2(g)

Answers

Answer:

2Fe₂O₃(s) → 4Fe(s) + 3O₂(g)

Explanation:

The unbalanced reaction is:

Fe₂O₃(s) → Fe(s) + O₂(g)

To balance the oxygen atoms, we put a 2 before Fe₂O₃ and a 3 before O₂(g) - so as to make the total of O atoms in both sides 6 -:

2Fe₂O₃(s) → Fe(s) + 3O₂(g)

There are four Fe atoms on the left side and only one on the right side, so we put a 4 before Fe(s):

2Fe₂O₃(s) → 4Fe(s) + 3O₂(g)

Now the equation is balanced: there is an equal number of both Fe and O atoms in both sides of the equation.

please help..............

Answers

rgrgtff

ghhbbbhhghghgghgggferer

What mass of hydrogen is required to react with 24.7 g of nitrogen?

Answers

Answer:

10.80 g of H2

Explanation:

As per the equation, let us calculate the mole ratio. N2+3H2→2NH3. As per the equation one mole of nitrogen

Which of the following is NOT an advantage of a wireless network? convenience reliability security speed

Answers

Answer:

Security

Explanation:

A wireless network consists of good connection with fast speed, convenience, and reliability. Security is a major problem with wireless connection as someone can get your information by joining the same connection as you.

A mixture of ethyne gas (C2H2) and methane gas (CH4) occupied a certain volume at a total pressure of 16.8 kPa. When the sample burned, the products were CO2 gas and H2O vapor. The CO2 was collected and its pressure found to be 25.2 kPa in the same volume and at the same temperature as the original mixture. What percentage of the original mixture was methane

Answers

Answer:

50%

Explanation:

Let assume that there are:

"a" moles of CH4 & "b" moles of C2H2

Then by applying the ideal gas equation:

PV = nRT

[tex]16.8 \times 10^3 \times V = (a+b)RT[/tex]

Make (a+b) the subject of the formula:

[tex](a+b) = \dfrac{16800 \ V }{RT} mol[/tex] --- (1)

Since 1 mole of CH₄ yields 1 mol of CO₂ & 1 mol of C₂H₂ yields 2 moles of CO₂

Then;

the total moles of CO₂ = (a +2b)

Now:

[tex]25.3 \times 10^3 \times V = (a+ 2b)RT[/tex]

[tex](a + 2b) = \dfrac{25200 \ V}{RT \ mol}[/tex]    ---- (2)

By solving the above equations

[tex]a = \dfrac{8400 \ V}{RT} \\ \\ b = \dfrac{8400 \ V}{RT}[/tex]

Hence, the estimate of the percentage of methane in the original mixture is:

[tex]= 100 \times \dfrac{a}{(a+b)}[/tex]

[tex]= 100 \times \dfrac{8400\dfrac{ \ V}{RT} }{8400\dfrac{ \ V}{RT} + 8400\dfrac{ \ V}{RT}}[/tex]

= 50%

(1132 CHCH2CH = CH2
12. Give the complete IUPAC name for each of the following compounds:
(a) (CH3)2CHF
(b) CH3CHCICHCICH3
(C)
CH3CHCH;
CH2CH3
(d) CH3 CH2 CH = CHCHZ
(e)
CH3CH2CH2CHBCH2CH3
CH2CH=CH2​

Answers

Answer:

Ok:

Explanation:

a) 2-fluoropropane

b) 2,3 dichlorobutane

c) pent-2-ene or 2 pentene (I assume the semicolon was a typo)

d) Same as c (I assume Z is a typo too)

e) non-1-ene or 1-nonene (I assume the B is a 2)

Weather, erosion and deposition will change the environment over time. When water runs over rocks it can smooth out jagged edges and even leave streak on the surface of the rock. This is an example of _____________.

Answers

Answer:

erosion.

Explanation:

A solution is made by mixing 49.g of chloroform CHCl3 and 73.g of acetyl bromide CH3COBr. Calculate the mole fraction of chloroform in this solution. Round your answer to 2 significant digits.

Answers

Answer: The mole fraction of chloroform in this solution is 0.41

Explanation:

To calculate the moles, we use the equation:

[tex]\text{Number of moles}=\frac{\text{Given mass}}{\text {Molar mass}}[/tex]

a) moles of [tex]CHCl_3[/tex]

[tex]\text{Number of moles}=\frac{49g}{119g/mol}=0.41moles[/tex]

b) moles of [tex]CH_3COBr[/tex]

[tex]\text{Number of moles}=\frac{73g}{123g/mol}=0.59moles[/tex]

To calculate the mole fraction, we use the formula:

[tex]\text{Mole fraction of a component}=\frac{\text{Moles of the component}}{\text{total moles}}[/tex]

[tex]\text{Mole fraction of chloroform}=\frac{\text{Moles of chloroform}}{\text{total moles}}=\frac{0.41}{0.41+0.59}=0.41[/tex]

The mole fraction of chloroform in this solution is 0.41

How are food webs and food chains related? HELP IF YOU WANT BRAINLEIST!!

Food webs only contain consumers.

Food webs consist of only one food chain.

Food webs are made of many food chains.

Food webs only contain producers.

Answers

Answer: Food webs are made of many food chains is the answer.

Explanation:

Food web consists many food chains.

What is the molecular formula for a compound with a molar mass of 42.08g/mol and an empirical formula of ch2

Answers

Answer:

[tex]C_3H_6[/tex]

Explanation:

Hello!

In this case, since the empirical formula is the smallest representation of the molecular formula, it is known that the times in which the empirical formula is into the molecular formula is a whole number and is computed by dividing the molar mass of the molecular formula by that of the empirical formula as shown below:

[tex]\frac{42.08g/mol}{12.01+1.01x2}= \frac{42.08g/mol}{14.03g/mol}=3[/tex]

Thus, the molecular formula times the empirical formula by 3 to obtain:

[tex]C_3H_6[/tex]

Regards!

which of the following statements are part of the kinetic molecular theory ?

Answers

Answer: The average kinetic energy is proportional to the absolute temperature of the gas. Gas particles are in random motion. Gas particles have no volume. And the collisions between gas particles are elastic.

Explanation: I heard this question before, I think. Hope this helps!

g What amounts of 45% pure silver and 50% pure silver should be mixed to obtain 14 grams of 46% pure silver

Answers

Answer:

11.2g of the 45% pure silver and 2.8g of the 50% pure silver.

Explanation:

14g of 46% pure silver contains:

14g*46% = 6.44g of silver are required. Thus, we can write:

6.44 = X*50% + Y*45% (1)

Where X is the mass of 50% pure silver and Y the mass of 45% pure silver.

As the mass of the sample must be 14g:

14g = X + Y (2)

Replacing (2) in (1):

6.44 = (14-Y)*50% + Y*45%

6.44 = 7 - 0.5Y + 0.45Y

-0.56 = -0.05Y

Y = 11.2g of the 45% pure silver

And:

14g-11.2g = X

X =

2.8g of the 50% pure silver

The required amount to obtain 14g of 46% pure silver is 2.8g of 50% silver and 11.2g of 45% silver.

To solve this question, we can assume it's a mathematical problem more than a chemistry problem.

let x represent the amount of 45% of pure Ag

let y represent the amount of 50% of pure Ag

But from the question, we only need 14g from both x and y

We can write an equation to represent this

[tex]x+y=14...equation(i)[/tex]

likewise, we can say that

[tex]0.45x+0.50y=14*0.46\\0.45x+0.50y=6.44...equation(ii)[/tex]

Solving both equations simultaneously,

[tex]x+y=14...equation(i)\\0.45x+0.5y=6.44...equation(ii)[/tex]

from equation (i)

[tex]x+y=14\\x=14-y...equation(iii)[/tex]

substitute equation (iii) into equation (ii)

[tex]0.45x+0.5y=6.44\\x=14-y\\0.45(14-y)+0.5y=6.44\\6.3-0.45y+0.5y=6.44\\[/tex]

collect like terms

[tex]-0.45y+0.50y=6.44-6.3\\0.05y=0.14\\y=\frac{0.14}{0.05}\\y=2.8[/tex]

Now we know the value of the 50% Ag which is 2.8g. Let's substitute it's value into equation (i) and solve for x

[tex]x+y=14\\x+2.8=14\\x=14-2.8\\x=11.2g[/tex]

Learn more about definite proportions here

https://brainly.com/question/1496091

What are the outcomes of the ice cap melting? Choose all that apply.


1. Light cannot be reflected back to the atmosphere


2. Sea level rises


3. Absorption of solar radiation leads to increase in ocean temperature


4. Ocean remains unaffected

Answers

Answer:

2. sea level rises sorry if it's wrong

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