Which of the following is a correct description of an atom?
A. A very small particle that holds a positive or negative charge depending upon the element
B. A mixture of protons and electrons surrounded by neutrons in very tight orbits
C.A very small particle that's the same for every element
D. The smallest particle of an element that still keeps the properties of that element

Answer:

She fell out of a tree

Explanation:

Answer:

Wavelength in water, [tex]\lambda=1.12\times 10^6\ m[/tex]

Explanation:

Given that,

A submarine uses sub-radio communication at 200 Hz.

The index of refraction, n = 1.333

The refractive index of a medium is given by :

[tex]\mu=\dfrac{c}{v}\\\\\mu=\dfrac{c}{\lambda_m f}\\\\\lambda_m=\dfrac{c}{\mu f}\\\\\lambda_m=\dfrac{3\times 10^8}{1.333\times 200}\\\\=1.12\times 10^6\ m[/tex]

So, the wavelength of the electromagnetic waves in water is [tex]1.12\times 10^6\ m[/tex].

First of all, weight is a force typically measured in Newtons. So right away, you can eliminate 35 kg and 343 kg from the given choices.

The object's weight F on Venus as given by the universal law of gravitation is

F = G (35 kg) (4.87 x 10²⁴ kg) / (6.05 x 10⁶ m)²

where G = 6.67 x 10⁻¹¹ N•m²/kg² is the gravitational constant. You would find the weight of the object to be

F ≈ 310.8 N

so the closest answer is 311 N.

Answer:

Storing it at a temperature greater than its Curie temperature will demagnetize it. The Curie temperature--named after the French scientist Pierre Curie--is the temperature at which magnets lose their permanent magnetism. ... Samarium cobalt, neodymium, and ceramic/ferrite magnets are brittle.

Answer:

Granite

Explanation:

The best choice would be granite.

This is because granite has the highest specific heat capacity of 0.79 J/(g.K) and would thus store more heat in it for the same mass and same temperature change as the other materials.

Since it contains more heat, it would be able to heat up the room to a higher temperature than the other materials.

Answer:

69

Explanation:

Perform addition first as;

(0.210 + 0.41) = 0.62 -------{2 significant figures}

Perform product

(1.10 x 102) = 112 -------------- {3 significant figures}

The combined product

0.62 x 112 =69.44

                 = 69 ----------2 significant figures

Rule

The least number of significant figures in the numbers performing the operation determines the number of significant figures in the answer.

Answer:

b. 40 ms

Explanation:

A wave travels at a speed of 20 m/s

the wavelength is 0.800 m

Required

the period

The expression for the velocity of a wave is given as

[tex]v=f \lambda\\\\f= v/ \lambda\\[/tex]

substituting our data

[tex]f= 20/0.8\\\\f=25Hz[/tex]

But T=1/f

T=1/25

T=0.04s

T=40ms

Explanation:

Fnet = ma = (20kg)(2.5m/s²) = 50N to the left.

Hence Ff = 30N to the right. (Ff is frictional force)

Coefficient of kinetic friction

= Ff / Normal force

= 30N / (mg)

= 30N / [(20kg)(9.81N/kg)]

= 0.15.

Answer:

an acceleration on the y-axis, on the x-axis she has no acceleration.

y-axis the speed increases linearly,  speed of the ball is constant on the x-axis

Explanation:

When the girl throws the ball, she is subjected to an acceleration on the y-axis called a relationship of gravity that is constant, on the x-axis she has no acceleration.

The speed of the ball is constant on the x-axis since there are no acceleration relationships and on the y-axis the speed increases linearly, daring the relationship constant.

Answer:

the potential energy stored in two bands is 15J

Explanation:

The computation of the potential energy stored in two bands is as follows:

Given that

F = 15N

x = -1.00 m = -0.01m

F = -kx

k = -F ÷ x

= 15N ÷ 0.01m

= 1,500 N/m

Now the potential energy would be

= 1,500N/m × (-0.10m)^2

= 15J

hence, the potential energy stored in two bands is 15J

The same is to be considered

Answer:

a) 6.9*10^14 Hz

b) 9*10^-12 T

Explanation:

From the question, we know that

435 nm is given as the wavelength of the wave, at the same time, we also know that the amplitude of the electric field, E(max) has been given to be 2.7*10^-3 V/m

a)

To find the frequency of the wave, we would be applying this formula

c = fλ, where c = speed of light

f = c/λ

f = 3*10^8 / 435*10^-9

f = 6.90*10^14 Hz

b) again, to find the amplitude of the magnetic field, we would use this relation

E(max) = B(max) * c, magnetic field amplitude, B(max) =

B(max) = E(max)/c

B(max) = 2.7*10^-3 / 3*10^8

B(max) = 9*10^-12 T

c) and lastly,

1T = 1 (V.s/m^2)

Answer:

Energy

A medium

Explanation:

A wave is a disturbance that travels through a medium, transferring energy from one point to another in the medium.

Mechanical waves are waves that require a medium for their propagation.

Answer:

THE ANSWER FOR THE FIRST SENTENCE IS ENERGY WHILE THE ANSWER FOR THE SECOND SENTENCE IS MATTER.

Explanation:

HOPE THIS HELPS

the answer is B

i jus took the assement

Answer:

B

Explanation:

Answer:

bbx

Explanation:

xbb

Answer:

Happy now?

Explanation:

Correct answer:

Sound waves are longitudinal waves, meaning that the waves propagate by compression and rarefaction of their medium. They are termed longitudinal waves because the particles in the medium through which the wave travels (air molecules in our case) oscillate parallel to the direction of motion.

Answer:

d. (1/8πε0)Q/a

Explanation:

The potential difference [tex]v = \dfrac{1}{4 \pi \epsilon _0} \dfrac{Q}{r}[/tex]

[tex]= (\dfrac{1}{4 \pi \epsilon _0}Q) \dfrac{1}{r}[/tex]

Suppose we separate the quantity [tex](\dfrac{1}{4 \pi \epsilon _0}Q)[/tex] which is dimensionally and equally the same as [tex](\dfrac{1}{8 \pi \epsilon _0}Q)[/tex]. Then, we will have [tex]\dfrac{1}{r}[/tex] and [tex]\dfrac{1}{a}[/tex] as the same dimension.

Therefore, the correct option is:

d. (1/8πε0)Q/a

Answer:

To investigate into how the height of a ramp affects the speed of a toy car rolled down a hill or slope because the higher the ramp the more Gravitational potential Energy (GPE), the more kinetic energy converted and the car will go faster. So the ramp increases, the velocity will also increase.

Explanation:

Answer:

The distance the car traveled during the given time is 94.44 m.

Explanation:

Given;

time of motion t = 8 seconds

initial velocity, u = 15 km/hr = 4.167 m/s

final velocity, v = 70 km/hr = 19.444 m/s

The distance traveled by the car during this time is given by;

[tex]s = (\frac{u+v}{2} )t\\\\s = (\frac{4.167+19.444}{2} )*8\\\\s = 94.44 \ m[/tex]

Therefore, the distance the car traveled during the given time is 94.44 m.

Answer:

The angle from vertical of the axis of the second polarizing filter is 50.57⁰.

Explanation:

Given;

intensity of the unpolarized light, I₀ = 300 W/m²

intensity of emergent polarized light, I = 121 W/m²

let the angle from vertical of the axis of the second polarizing filter = θ

Apply Malus's law, intensity of emergent polarized light is given as;

I = I₀Cos²θ

[tex]Cos^2 \theta = \frac{I}{I_o} \\\\Cos^2 \theta =\frac{121}{300} \\\\Cos^2 \theta =0.4033\\\\Cos \theta = \sqrt{0.4033} \\\\Cos \theta = 0.6351\\\\\theta = Cos^{-1} (0.6351)\\\\\theta = 50.57 ^0[/tex]

Therefore, the angle from vertical of the axis of the second polarizing filter is 50.57⁰.

Answer:

D. the same as force. the applied force per cross-sectional area.

Explanation:

Tensile stress of a material is defined as the ratio of the applied force on the material to its cross sectional area. this is expressed mathematically as;

Tensile stress = Force/cross sectional area

Tensile stress = F/A

Force is measured in newton while cross sectional area is measured in m

Hence the unit of Tensile stress is N/m²

The tensile stress is the same as force. the applied force per cross-sectional area. Hence, option (D) is correct .

The given problem is based on the concept of stress and strain. The force applied on a material per unit area is known as Stress. It is denoted by the symbol [tex]\sigma[/tex] .

And due to the applied force, the ratio of change in length to the original length is known as Strain. It is denoted by the symbol [tex]\epsilon[/tex].

And the ratio of Stress and Strain is known as Elastic modulus. That is,

[tex]E = \dfrac{stress}{strain}\\\\E = \dfrac{\sigma }{\epsilon}[/tex]

So, the tensile stress is obtained as,

[tex]E = \dfrac{\sigma}{\epsilon}\\\\\sigma = E \times \epsilon[/tex]

So, clearly stress is nothing but the force applied per unit cross sectional area. That is,

[tex]\sigma = \dfrac{F}{A}[/tex]

Thus, we can conclude that the tensile stress is the same as force. the applied force per cross-sectional area. Hence, option (D) is correct .

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Answer:

A. the same speed as the first trip

Explanation:

there's no friction

pls mark as brainliest

D. A beam balance does not measure mass; it measures weight. The gravitational force of attraction between the earth and an object depend on the mass of the object. ... The beam balance measures the force F exerted by the mass on the beam balance

Answer:

to turn red litmus blue and react with acid to form salt

Answer:

a)  F_total = -648 10⁻⁴ N

,  b)   F_total = - 312 N,  c)   F_total = (38.6 i ^ + 883.4 j ^) 10⁻⁴ N

Explanation:

To solve this exercise we will use Coulomb's law

         F = k q₁ q₂ / r²

and that forces are vectors

They indicate that the charge q₁ = 3 10⁻⁴ C and the charge q₂ = 12 10⁻⁴ C being separated d = 1 m

Let's place the reference system on the charge q₁

a) we place a third charge q₃ = 2 10⁻⁹ C at the midpoint

        r = d / 2

        r = ½ m

Since all charges have the same sign, the forces are repulsive, so the total force is

        F_total = F₁₃ - F₂₃

let's develop this expression

        F_total = k q₁ q₃ / r² - k q₂ q₃ / r²

        F_total = [tex]k \frac{q_{3} }{r^{2} } ( q_{1} - q_{2} )[/tex]

let's calculate

         F_total = 9 10⁹  (3- 12) 10⁻⁴

         F_total = -648 10⁻⁴ N

b)  place the charge q₃ at a distance r = -0.5 m to the left of the charge q₁  

        F_total = -F₁₃ -F₂₃  

       F_total = -k q₁ q₃/ r₁₃² - k q₂ q₃ / r₂₃²  

      F_total = - [tex]k q_{3} ( \frac{q_{1} }{r_{13}^{2}} + \frac{q_{2} }{r_{23}^{2} } )[/tex] 

the distances  

      r₁₃ = 0.5 m  

     r₂₃ = 0.5 +1 = 1.5 m  

calculate  

    F_total = - 9 10⁹ 2 10⁻⁹ (3 /0.5² + 12 /1.5²) 10⁻⁴  

    F_total = - 18 (12 + 5.33) 10⁻⁴  

    F_total = - 312 N

c) the charged q₃ is placed on the charge q₂ on the y axis.  

In this case the charge q₂ exerts a force on the y-axis on the charge q₃  

F₂₃ = k q₂ q₃ / r² j ^

where r = 0.5 m  

let's calculate  

F₂₃ = 9 10⁹ 12 10⁻⁴ 2 10⁻⁹ / 0.5²  

F₂₃ = 864 10⁻⁴ j ^  

Charge q1 exerts a repulsive force on the axis that joins them  

F₁₃ = k q₁ q₃ / r₁₃²

let's look for the distance  

r₁₃ =  

r₁₃ = 1,118 m  

Let's use trigonometry to find the direction of this distance  

tan θ = y / x  

θ = tan⁻¹ (y / x)  

θ = tan⁻¹ (0.5 / 1)  

θ = 26.6º

let's write this force in its components  

F₁₃ = k q₁  

(cos 26.6 i ^ + sin 26.6 j ^)  

let's calculate  

F₁₃ = 9 10⁹ 3 10⁻⁴  

(cos 26.6 i ^ + sin 26.6 j ^)  

F₁₃ = 43.2 (0.894 i ^ + 0.448 j ^) 10⁻⁴  

F₁₃ = (38.6 i ^ + 19.4 j⁾ 10⁻⁴ N  

Let's write the total force  

F_total = F₁₃ i ^ +  

j ^ + F₂₃ j ^  

let's substitute  

F_total = 38.6 10⁻⁴ i ^ + (19.4 + 864) 10⁻⁴ j ^  

F_total = (38.6 i ^ + 883.4 j ^) 10⁻⁴ N

Answer: 600 feet

Explanation:

A circuit is complete when there is a continuous path for electricity to travel from one end of the energy source to the other end.

Electric circuit: a way for current to travel. A battery or generator, a device that provides energy to the charged particles that make up the current, a device that uses current, such as a lamp, an electric motor, or a computer, and the connecting wires or transmission lines make up an electric circuit. Ohm's law and Kirchhoff's rules are two fundamental laws that quantitatively define how electric circuits function.

Several categories are used to categorise electric circuits. One-way current only flows through a direct-current circuit. As in most residential circuits, an alternating-current circuit transports current that pulses back and forth repeatedly every second.

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Answer:

The answer is A) River delta

Explanation:

River deltas are formed by the deposition of sediment carried by rivers.

Answer:

Explanation:

The distance covered can be found by using the formula

[tex]d = \frac{w}{f} \\ [/tex]

f is the force

w is the workdone

From the question we have

[tex]a = \frac{12000}{800} = \frac{120}{8} \\ [/tex]

We have the final answer as

Hope this helps you

Answer:

λ = 7.333 x 10⁻⁷ m = 733.3 nm

Explanation:

We can use the formula of fringe spacing from Young's Double Slit Experiment, to find the wavelength of light:

Δx = λL/d

where,

Δx = fringe spacing = 1.6 cm = 0.016 m

λ = wavelength of laser light = ?

L = Distance between slits and screen = 4.8 m

d = slit separation = 0.22 mm = 0.00022 m

Therefore, using these values in the given equation, we get:

0.016 m = (λ)(4.8 m)/(0.00022 m)

λ = (0.016 m)(0.00022 m)/(4.8 m)

λ = 7.333 x 10⁻⁷ m = 733.3 nm