A solar system has the five planets shown below. The mass of each planet is proportional to its size. Planet X is at equal distance from Planet A, Planet B, Planet C and Planet D Planet A Planet B Planet X Planet D Planet C O Which planet exerts the greatest gravitational force on Planet X? Planet A Planet B Planet C Planet D
Please help me i will mark Brainlast
Answer:
Explanation:
The gravitational force is equal to the equation [tex]\frac{Gm_{x} m_{p} }{r^{2} }[/tex]
r: distance between the planet and planet xm[tex]_{x}[/tex] : mass of planet x[tex]m_{p}[/tex]: mass of any planetSince we know that the distance between the planets to planet x is equal, thus the value 'r' is of no use to use to increase the gravitational force.
The only way to increase gravitational force is by increasing the mass of the planet. Thus planet C which has the greatest mass has the greatest gravitational force
Hope that helps!
A raised object has energy in its __________ __________ energy stores. What two words complete the sentence?
The complete statement is -
"A raised object has energy in its gravitational potential energy".
What is gravitational potential energy? Gravitational energy or gravitational potential energy is the potential energy a massive object has in relation to another massive object due to gravity. It is the potential energy associated with the gravitational field, which is released (converted into kinetic energy) when the objects fall towards each other. Gravitational potential energy increases when two objects are brought further apart.For two pairwise interacting point particles, the gravitational potential energy {U} is given by -[tex]${\displaystyle U=-{\frac {GMm}{R}}}[/tex]
Close to the Earth's surface, the gravitational field is approximately constant, and the gravitational potential energy of an object reduces to -U = mgh
The force between a point mass {M} and another point mass {m} is given by Newton's law of gravitation -[tex]${\displaystyle F={\frac {GMm}{r^{2}}}}[/tex]
To get the total work done by an external force to bring point mass
{m} from infinity to the final distance {R} (for example the radius of
Earth) of the two mass points, the force is integrated with respect to
displacement -
[tex]${\displaystyle W=\int _{\infty }^{R}{\frac {GMm}{r^{2}}}dr=-\left.{\frac {GMm}{r}}\right|_{\infty }^{R}}[/tex]
[tex]${\displaystyle U=-{\frac {GMm}{R}}}[/tex]
Given is the statement as -
"A raised object has energy in its __________ __________ energy"
An object that is raised above the surface of earth {near to earth surface} than it has gravitational potential energy.
Therefore, the complete statement is -
"A raised object has energy in its gravitational potential energy".
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You are working in the field to assess the stability of various slopes in the area of a new housing development. You conclude that the ratio of resisting forces to driving forces is 0.73 in an area where many houses are slated to be built. What do you recommend to the builder
The stability of the slope to vehicles moving on it is high, thus the builder can use materials that improves or maintains the given stability of the slope so that vehicles won't skid on the slope.
Stability of the slopeThe stability of the slopes comes with the availability of the static frictional forces.
Ff/F = 0.73
where;
Ff is the frictional forceF is the driving forceThe stability of the slope to vehicles moving on it is high, thus the builder can use materials that improves or maintains the given stability of the slope so that vehicles won't skid on the slope.
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The slope's stability to vehicles traveling on it is high, thus the builder can employ materials that strengthen or preserve the slope's provided stability so that cars do not slide on the slope.
What is the friction force?It is a type of opposition force acting on the surface of the body that tries to oppose the motion of the body. its unit is Newton (N). Mathematically it is defined as the product of the coefficient of friction and normal reaction.
On resolving the given force and acceleration in the different components and balancing the equation gets.Components in the x-direction.
The given data in the problem is
the ratio of resisting forces to driving forces is 0.73
f is the resisting force
F is the driving force
[tex]\rm \frac{f}{F} = 0.73[/tex]
The slope's stability to vehicles traveling on it is high.
Hence the builder can employ materials that strengthen or preserve the slope's provided stability so that cars do not slide on the slope.
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Two point charges, 3.4 μC and -2.0 μC , are placed 5.0 cm apart on the x axis. Assume that the negative charge is at the origin, and the positive x-axis is directed from the negative charge to the positive. At what points along the x axis is the potential zero? Let V=0 at r=∞ .
The electric field is zero at x = -16.45cm
Data;
q1 = 3.4 μC q2 = -2.0 μC distance = 5cmThe Electric Field at point 0As the 3μC is larger than -2.0μC and the charges are opposite sign. The electric field will be zero at the negative axis.
Let the point be at x.
For an electric field to be equal to zero;
[tex]k(\frac{q_1}{d_1})^2 + k(\frac{q_2}{d_2})^2 = 0\\\frac{3.4}{(5-x)^2} - \frac{2}{x^2} = 0\\[/tex]
Let's solve for x using mathematical methods.
[tex]\frac{3.4x^2 - 2(5-x)^2}{(5-x)^2x^2}= 0\\ 3.4x^2 - 2(5-x^2) = 0\\3.4x^2 - 50 - 2x^2 + 20x = 0\\1.4x^2 +20x - 50 = 0[/tex]
Solving the above quadratic equation;
[tex]x = -16.45cm[/tex]
The electric field is zero at x = -16.45cm
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What is the kinetic energy of a moving toy car if the car has a mass of 15.0 kg and the velocity is 7.2 m/s ? ______ J
Answer:
389 J
Explanation:
m = 15.0 kg, v = 7.2 m/s
Kinetic energy = mv²/2 = 15.0 * 7.2²/2 = 389 J
If the voltage in a circuit is 12V and is connected to a single 3Ohm resistor, what is the current flowing through the circuit?
Answer:
12/30
Explanation:
v=ir
i=v/r
12/30=i
Two charged particles with opposite signs but the same magnitude of charge enter a magnetic field that is perpendicular to their direction of motion. How will the motion of the two particles differ when they enter the magnetic field?
Answer:
the two particles will go opposite directions, along clockwise circle and counter-clockwise circle, respectively.
Explanation:
charge = ±q, velocity = v, magnetic field = B
force F = q v x B
opposite q will give opposite force, so the two particles will go opposite directions, along clockwise circle and counter-clockwise circle, respectively.
A box of weight 100 N is at rest on a floor where μs = 0.4. A rope is attached to the box and pulled horizontally with tension T = 30 N. Which way does the box move?
∑F = F-fs
∑F = F - μs.N
∑F = 30 - 0.4 x 100
ΣF = 30 - 40 = -10
the box doesn't move
Due to the fact that the tension of 30 N that is given to the rope is less than the maximum static friction force of 40 N, the box remains in its current position.
We need to make a comparison between the force of static friction and the force that was applied in order to figure out which way the box is going to move. The static friction force (F[tex]_friction[/tex]) works in the opposite direction to the applied force, and it keeps the box from moving so long as the applied force does not exceed the maximum static friction force. This is true provided that the applied force does not exceed the maximum static friction force.
The following equation can be used to derive the greatest static friction force (F[tex]_friction_max[/tex]) that exists between the box and the floor:
F[tex]_friction_max[/tex] = s multiplied by N
where s is the coefficient of static friction and N is the normal force. Because the box is sitting still on the floor, the normal force is equal to the weight of the box, which is 100 N in this example.
F[tex]_friction_max[/tex] equals 0.4 times 100 N, which equals 40 N.
The tension in the rope, measured in newtons (N), is thirty. Due to the fact that T (30 N) is less than the maximum force of static friction (40 N), the box will not be able to overcome the static friction, and it will not move in the direction where the applied force is exerting its force.
Therefore, there is no movement of the box when a strain of 30 N is applied to the rope and it is pulled.
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which issue was not a problem that had to be overcome for humans to travel into space
A.High levels of radiation
B.Extreme hot and cold temperatures
C.Lack of government support
D.Lack of oxygen
Lack of government support is not a problem faced by humans to travel to space.
What is Space travel?Space exploration or travel refers to employing the use of astronomy and space technology by humans to travel outer space. This is carried out by astronomers using uncrewed robotic space probes and human spaceflight.
Therefore,lack of government support is not a problem faced by humans while traveling to space because it does not require government support and outer space have harsh weather's which are not conducive to humans living on Earth, there is also high level of radiations,emissions of dangerous rays because of it's closeness to sun and also lack of oxygen which can be as a result of non existence of plants that release oxygen during photosynthesis.
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A container of an ideal gas at 1 atm is compressed to 1/3 its volume, with the temperature held constant, what is its final pressure?
Answer:
0.013atm
Explanation:
every gas contains 22.4 GameCube at atmospheric pressure
A container of an ideal gas at 1 atm is compressed to 1/3 its volume, with the temperature held constant, then its final pressure would be 3 atm
What is an ideal gas?It is an imaginary gas for which the volume occupies by it is negligible, this gas does not exist in a practical situation and the concept of an ideal gas is only the theoretical one, the real gases approach the behaviors of an ideal gas at a very high temperature and very low pressure.
As given in the problem A container of an ideal gas at 1 atm is compressed to 1/3 its volume, with the temperature held constant
By using the Boyle's law equation for the given problem
P₁V₁=P₂V₂
By substituting the values in the above equation
P₁ = 1 atmospheric pressure
V₁= V
P₂ =?
V₂= V/3
1×V=P₂×V/3
P₂ = 3V/V
P₂ = 3 atm
Thus, then its final pressure would be 3 atm
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You are driving on a rural road and see a person on the shoulder ahead, riding or leading an
animal. You should
A: Use reasonable care, and don't make any loud noises when approaching them, to avoid
frightening the animal.
B: Speed up, to get past them quickly.
C: Honk your horn to wam them that you are approaching.
Answer:
A
Explanation:
Any sort of honk can frighten the animal, drive slow enough that the person would know you're coming/you're there and make sure you are taking a lot of care.
The thing that should be done when driving is A. Use reasonable care, and don't make any loud noises when approaching them, to avoid frightening the animal.
How to illustrate the information?It should be noted that the person is driving on a rural road and see a person on the shoulder ahead, riding or leading an animal.
In this case, the person should reasonable care, and don't make any loud noises when approaching them, to avoid frightening the animal.
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Brainliest if correct
Answer:
B is the correct answer of the question
Potential energy is the energy an object has because of its position; it is energy waiting to be released. What conclusion is BEST supported by the selection above? A All still objects have potential energy. B Some objects have more energy than others. C Most still objects do not have potential energy. D Potential energy makes objects move.
Answer:
Explanation:
An object can store energy as the result of its position. For example, the heavy ball of a demolition machine is storing energy when it is held at an elevated position. This stored energy of position is referred to as potential energy. Similarly, a drawn bow is able to store energy as the result of its position. When assuming its usual position (i.e., when not drawn), there is no energy stored in the bow. Yet when its position is altered from its usual equilibrium position, the bow is able to store energy by virtue of its position. This stored energy of position is referred to as potential energy. Potential energy is the stored energy of position possessed by an object.
A 100 kg block slides down a frictionless ramp which is at an angle of 26.6 ∘ with the horizontal. Find the magnitude of the velocity of the block when it gets to the bottom of the ramp if the length of the incline is 50 meters. V=_____m/s
The block accelerates down the ramp due to the component of its weight that acts parallel to the ramp; this force has magnitude
(100 kg) g sin(26.6°) ≈ 438 N
(Note that the positive sign here means we take "down the ramp" to be the positive direction.)
Since the ramp is frictionless, this is the only force acting on the block in this direction. By Newton's second law, the block's acceleration is a such that
438 N ≈ (100 kg) a ⇒ a ≈ 4.38 m/s²
The block accelerates uniformly, so that it attains a speed v as it moves 50 m such that
v² = 2a (50 m)
Solve for v :
v = √(2a (50 m)) ≈ 20.9 m/s
Calculate: the charge flow in 60 seconds in a wire when the current in the wire is 3.0 A.
Answer:
180 C
Explanation:
t = 60 sec, I = 3.0 A
Q = I*t = 3.0 * 60 = 180 C
A wire loop having area 0.606 m2 is placed in a uniform magnetic field with the normal vector of the loop at a 75.1 degree angle to the field. The field has an initial magnitude of 2.91 Tesla and then is increased at a constant rate to 7.97 Tesla in 0.856 seconds. If a current of 0.0980 Amps is measured to flow through the wire during this time, what must the resistance of the wire be in Ohms
The resistance of the wire is is 36.55 ohms.
Induced emf of the coilThe induced emf in the loop is calculated by Faraday's law as follows;
emf = A(B₂- B₁)/t
emf = 0.606 (7.97 - 2.91)/0.856
emf = 3.58 V
Resistance of the wireThe resistance of the wire is calculated by using Ohms law as follows;
emf = IR
R = emf/I
R = 3.58/0.098
R = 36.55 ohms
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In the simulation, there are three balls on the floor. Drag each of them up off the floor, and then let go. See what happens to the balls. In what way do the balls behave the same? In what way do they behave differently?
Answer:
I hope this helps and I'm not to late
A way the balls behave the same way is by bouncing about 1 time after throwing the balls up. A way the balls act differently is the blue ball is bouncier than all the balls, the red ball bounces about 2 times before stopping, and the green ball doesn’t really bounce except for one time.
Explanation:
you also can use paraphrase to help you reword bye bye!!
My Answer:
Starting with how they acted the same. All three balls fell at the same rate since they are of the same mass; gravity has equal force on all three. Next to the differences, all three balls bounce differently. The blue ball had an average of four bounces before it stopped. The red ball bounced twice before stopping, and lastly, the green ball didn't bounce.
My Explanation:
This is how I answered the question, and I'm on edmentem aswell.
relation between linear and cubical expansion?
cubic expansion is 3 times the linear expansion. expressed mathematically as
[tex] \gamma = 3 \alpha [/tex]
An object has a mass of 785g and a volume of 15cm cubed. What is its density
Answer:
52.33 repeating
Explanation:
Density is equal to the Mass of an object divided by its Volume. or p = m/V
the ball is accelerating at a rate of 10 m/s squared. the balls mass if 5 kg. what is the net force on the ball? help me men plez
Answer:
50N
Explanation:
[tex]F=ma\\F=(5kg)*(10m/s^{2})\\F=50N[/tex]
How much force is needed to stretch a spring 1.2m if the spring constant is 8.5 N/m?
Explanation:
spring constant k::8.5
and displacement x::1.2
f:? f: k×x
8.5×1.2:10.2N
How does the law of conservation apply to Earth's Energy Budget?
Answer:
The balance between incoming energy from the sun and outgoing energy from Earth ultimately drives our climate. This energy balance is governed by the first law of thermodynamics, also known as the law of conservation of energy.
A person pushes a box across a horizontal surface at a constant speed of 0.5 meter per second The box has
a mass of 40 kilograms, and the coefficient of sliding friction is 0.25. The power supplied to the box by the
person is
a. 0.2 W
c. 50 W
b. 5W
d. 100 W
Answer:
The correct option
(C) 50W
-
Hope it help's u :))!
How fast does light travels the earth?
Answer:
Light travels at a constant, finite speed of 186,000 mi/sec.
Explanation:
Light travels at a constant, finite speed of 186,000 mi/sec.
When light traveling in straight lines passes through an object that is curved like a lens, the light is ________ at different angles.
Answer:
You are right. It is reflected
Explanation:
if it is concave then the light is reflected at one direction.
if it is convex the light is reflected outwards and they will travel away from the focal point and the light scatters or will be reflected to different directions
When light traveling in straight lines passes through an object that is curved like a lens, the light is refracted at different angles. Thus, the correct option is B.
What is refraction of light?Refraction is the phenomena of bending of light, it also happens with sound, water and other waves as it passes from one transparent substance into another substance. This bending of light by refraction makes it possible for us to have lenses, such as magnifying glasses, prisms, and rainbows.
When a ray of light travels in straight line, it passes through an object that is curved like a lens, the light is refracted at various different angles, depending upon the angle of incidence of light on the lens.
Therefore, the correct option is B.
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How many atoms of oxygen in the chemical formula 2 Ca(CIO2)2?
O 2
O 4
O 6
O 8
Answer:
I believe it's 8
Explanation:
A point charge q1=+5.00nC is at the fixed position x=0, y=0, z=0. You find that you must do 8.10×10−6J of work to bring a second point charge from infinity to the position x=+4.00cm, y=0, z=0. What is the value of the second charge?
The value of the second charge is 1.2 nC.
Electric potential
The work done in moving the charge from infinity to the given position is calculated as follows;
W = Eq₂
E = W/q₂
Magnitude of second chargeThe magnitude of the second charge is determined by applying Coulomb's law.
[tex]E = \frac{kq_2}{r^2} \\\\\frac{kq_2}{r^2} = \frac{W}{q_2} \\\\kq_2^2 = Wr^2\\\\q_2^2 = \frac{Wr^2}{k} \\\\q_2 = \sqrt{\frac{Wr^2}{k} } \\\\q_2 = \sqrt{\frac{(8.1 \times 10^{-6}) \times (0.04)^2}{9\times 10^9} } \\\\q_2 = 1.2 \times 10^{-9} \ C\\\\q_2 = 1.2 \ nC[/tex]
Thus, the value of the second charge is 1.2 nC.
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A wheel is turning at 55 rad/s, and is slowing due to friction at a rate of -1.7 rad/s?. How long will the
wheel turn before coming to rest?(in seconds) How far will the wheel turn before coming to rest?( in
radians)
Answer:
32.4 s, 890 rad
Explanation:
ω₀ = 55 rad/s, α = -1.7 rad/s², ω = 0
α = (ω - ω₀)/t, so
t = -ω₀/α = -55/(-1.7) = 32.4 s
Δθ = ω₀t + αt²/2 = 55*32.4 + (-1.7)*32.4²/2 = 890 rad
Which property describes the rate at which waves pass by?
O A. Wavelength
B. Speed
O c. Period
C.
O D. Frequency
Option D is correct. Frequency is the property describes the rate at which waves pass by.
What is wave frequency?Wave frequency is the number of waves that travel through a specified location in a given amount of time.
The distance between two successive troughs or crests is known as the wavelength. The peak of the wave is the highest point, while the trough is the lowest.
Frequency is the property describes the rate at which waves pass by.
Hence,frequency is the right answer.
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You push a box out of a carpeted room and along a hallway with a waxed linoleum floor. While pushing the crate 3 m out of the room you exert a force of 28 N; while pushing it 4 m along the hallway you exert a force of 14 N. To bring it to a stop you exert a force of 5 N through a distance of 1.2 m, opposite to the motion. How much work do you do in all
The total work done is equal to 134 J.
Work
The work formula is characterized as the multiplication of the force performed and the distance in which the movement was performed, so that:
[tex]W = F \times d[/tex]
Thus, it is enough to calculate the value of the work in each movement and add to find the total work, so that:
[tex]W_1 = 3 \times 28 = 84J\\W_2= 4 \times 14 = 56J\\W_3 = (-1.2) \times 5 = 6J[/tex]
[tex]84 + 56 + (-6) = 134J[/tex]
So, the total work done is equal to 134 J.
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