The valence electrons are very effective in screening the core electrons from the full charge of the nucleus statements about effective nuclear charge is true
Effective nuclear charge: What is it?The attractive positive charge of nuclear protons acting on valence electrons is known as effective nuclear charge. Due to the shielding effect, the effective nuclear charge is always smaller than the total amount of protons in a nucleus. In comparison to all other periodic table trends, effective nuclear charge lags behind.
Although a fluorine atom's nucleus has a 9-volt charge Z, the core electrons—four from the 1s and 2s orbitals—and some of the 7 electrons in the 2p orbitals—screen the valence electrons noticeably. Therefore, the cation of sodium has the highest effective nuclear charge.
Effective nuclear charge lowers down a group and rises from left to right across a period in the periodic table.
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How many moles of solute are present in 250 mL of 4.00 M HCI?
Answer:
Answer. There are 0.1 moles of solute in 250 mL of 0.4 M solution.
How many moles of copper(l) oxide contain 1.20 x 10^23 copper atoms? Include units and name of atom/molecule.
ANSWER
Number of moles = 0.1993 mole
STEP-BY-STEP EXPLANATION:
Given particles
[tex]\begin{gathered} \text{Number of particles = 1.20 }\cdot10^{23} \\ \text{Avogadro's number = }6.022\cdot10^{23} \end{gathered}[/tex]The formula for calculating moles is written below
[tex]\text{Number of moles = }\frac{Number\text{ of particles}}{\text{Avogadro's number}}[/tex]The next thing is to substitute the above parameters into the above formula
[tex]\begin{gathered} \text{Number of moles = }\frac{1.20\cdot10^{23}}{6.022\cdot10^{23}} \\ \text{Number of mole = }\frac{1.20}{6.022} \\ Number\text{ of moles = 0.1993 mole} \end{gathered}[/tex]9) How many ATOMS of fluorine are there in 3.71 moles of nitrogen trifluoride (NF3)? (Hint: this requires two conversions)
The number of atoms of fluorine present in 3.71 moles of nitrogen trifluoride, NF₃ is 6.7×10²⁴ atoms
How to determine the number of atomsWe'll begin by obtaining the number of moles of fluorine in 3.71 moles of nitrogen trifluoride NF₃. This can be obtained as follow:
1 mole of nitrogen trifluoride, NF₃ contains 3 moles of F
Therefore,
3.71 moles of nitrogen trifluoride, NF₃ will contain = 3.71 × 3 = 11.13 moles of F
Finall, we shall determine the number of atoms of fluorine pressnt in the compound as follow:
From Avogadro's hypothesis,
1 mole of fluorine = 6.02×10²³ atoms
Therefore,
11.13 moles of fluorine = (11.13 moles × 6.02×10²³ atoms) / 1 mole
11.13 moles of fluorine = 6.7×10²⁴ atoms
Thus, from the calculations made above, we can conclude that the number of atoms of fluorine present is 6.7×10²⁴ atoms
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DUE IN 9 MINUTES HELP
The reaction written below has a ΔH of +2,962 kJ/mol
6CO2(g) + 6H2O(g) --> C6H12O6(g) +6O2(g)
How much energy must be input into this reaction to make 58.9 grams of C6H12O6(g) ?
The amount of heat energy that must be inputted into the reaction to make 58.9 grams of C₆H₁₂O₆ is 968.574 KJ
How to determine the amount of heat energyWe'll begin by obtainig the number of mole of 58.9 grams of C₆H₁₂O₆. This can bbe obtained as follow:
Mass of C₆H₁₂O₆ = 58.9 grams Molar mass of C₆H₁₂O₆ = (6 × 12) + (12 × 1) + (16 × 6) = 180 g/molMole of C₆H₁₂O₆ =?Mole = mass/ molar mass
Mole of C₆H₁₂O₆ = 58.9 / 180
Mole of C₆H₁₂O₆ = 0.327 mole
Finally, we shall determine thhe heat energy needed.
The balanced equation for the reaction is given below:
6CO₂(g) + 6H₂O(g) → C₆H₁₂O₆(g) + 6O₂(g) ΔH = +2962 KJ/mol
From the balanced equation for above,
1 moles of C₆H₁₂O₆ was produced by 2962 KJ of heat energy.
Therefore,
0.327 mole of C₆H₁₂O₆ will be produce by = (0.327 × 2962) / 1 mole = 968.574 KJ of heat energy
Thus, 968.574 KJ of heat energy is needed for the reaction
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One day in lab, while adding a gnarled root to a dark liquid bubbling in an iron cauldron, your friend Leila (an expert chemist) says this:
"Group 1A metal hydrides react with water to produce hydroxides and hydrogen gas."
Using Leila's statement, and what you already know about chemistry, predict the products of the following reaction.
Be sure your chemical equation is balanced!
KH(s)+ H2O(l)=
The balanced equation of the reaction of the metal hydride, KH, and water is given below:
KH (s) + H₂O(l) ---> KOH + H₂ (g) What are metal hydrides?Metal hydrides are compounds that are composed of a reactive metal chemically combined with hydrogen.
The hydrogen atom is less electropositive than the metal and will accept electrons from the metal to form the negative hydride ion.
For example, Group 1A metal hydrides react with water to produce hydroxides and hydrogen gas.
Considering the above property, the given reaction will be:
KH (s) + H₂O(l) ---> KOH + H₂ (g)
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using a graduated cylinder and a becker write the detailed steps to measure the volume of a piece of rock
The detailed steps to measure the volume of a piece of rock using a graduated cylinder and beaker are based on Archimedes' Principle, which states that an object that is displacing fluid has a weight equal to that of the object it is displacing.
Step 1: In order to calculate a stone's volume, we first add water to the graduated cylinder until the stone is fully submerged. Step 2: Following the insertion of the stone into the cylinder, the initial reading, or baseline reading, must now be recorded. Step 3: The last reading of the cylinder needs to be recorded after the stone has been fully immersed. Step 4: We can calculate the stone's millilitre capacity by comparing the cylinder's results. If necessary, this value can be changed to another unit of measurement.The submersion or dunking method is another name for the displacement method.
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How much heat in kJ is released when 0.677 mol NaOH(soln) is dissolved in water? (ΔH(soln) = –44.5 kJ/mol for NaOH)NaOH(s) rightwards arrow Na+(aq) + OH–(aq) + 44.5 kJ/mol
Explanation:
The dissolution reaction of NaOH is:
NaOH (s) -----> Na⁺ (aq) + OH⁻ (aq) + 44.5 kJ/mol
ΔH(soln) = –44.5 kJ/mol
This reaction is exothermic, because the ΔH is negative. That's why the 44.5 kJ/mol appears in the products side, because heat is being released.
From the ΔH of solution we know that 1 mol of NaOH will realease 44.5 kJ when it dissolves. We have to find the heat released by 0.677 mol of NaOH.
Heat released = 0.677 moles * (-44.5 kJ/mol)
Heat released = - 30.1 kJ
Answer: -30.1 kJ is released when 0.677 mol of NaOH is dissolved.
Consider the following reaction for the production of NO2.2 NO(g) + O2(g) → 2 NO2(g)What mass of O2 in g is required to produce 15 L NO2 at 344 K and 752 mm Hg? (R = 0.08206 L⋅atm/mol⋅K)
The question requires us to calculate the mass of reactant (O2) necessary to obtain 15 L of the product (NO2) under the conditions given.
The following information was provided by the question:
- Balanced chemical reaction: 2 NO(g) + O2(g) → 2 NO2(g)
- Final volume of NO2: 15 L
- Pressure: P = 752 mmHg
- Temperature: 344 K
- Gas constant: R = 0.08206 L⋅atm/mol⋅K
To solve this question, we'll need to go through the following steps:
1) calculate the number of moles that corresponds to 15 L of NO2, considering the temperature and pressure given;
2) use the stoichiometric relation to calculate the necessary amount of O2 to produce the previously calculated number of moles of NO2
3) use the molar mass of O2 and the value calculated on step 2 to obtain the necessary mass of O2
Next, we'll solve the problem following these steps:
1) To calculate the number of moles of NO2, we'll use the following equation:
[tex]P\times V=n\times R\times T[/tex]where P is the pressure, V is the volume of gas, n is the number of moles, R is the constant of gases and T is the temperature.
If we rearrange the equation to calculate the number of moles, we'll have:
[tex]n=\frac{P\times V}{R\times T}[/tex]Note that the problem provided all necessary information for this calculation, but the pressure given (752 mmHg) needs to be converted into atm to match the constant provided.
To do that, we'll use the following:
1 atm = 760 mmHg
Thus, we need to divide the value provided by 760:
[tex]P=752\text{ mmHg}\times\frac{1\text{ atm}}{760\text{ mmHg}}=0.989\text{ atm}[/tex]Now, we can apply the values of pressure, volume and temperature, as well as the constant provided, to the equation written above:
[tex]n=\frac{(0.989\text{ atm)}\times(15\text{ L)}}{(0.08206\text{ L.atm/mol.K)}\times(344\text{ K)}}=0.525\text{ mol}[/tex]So far, we have that the volume of NO2 to be produced (15 L) corresponds to 0.525 mol under the conditions of pressure and temperature provided.
2) Next, we use the chemical reaction to calculate the number of moles of O2 required to produce 0.525 mol of NO2.
From the reaction, we have that 1 mol of O2 leads to 2 mol of NO2. Then, we use this to calculate how many moles of O2 would produce 0.525 moles of NO2:
1 mol O2 --------------- 2 mol NO2
x -------------------------- 0.525 mol NO2
Solving for x, we have:
[tex]x=\frac{(1\text{ mol O2)}\times(0.525\text{ mol NO2)}}{(2\text{ mol NO2)}}=0.263\text{ mol O2}[/tex]Now, we know that 0.263 moles of O2 are necessary to produce 15 L of NO2
3) The last step is calculate the mass of O2 that corresponds to 0.263 moles of this compound.
To do this, we need the molar mass of O2. Since the atomic mass of oxygen is 15.99 u, the molar mass of O2 is:
molar mass O2 = (2 * 15.99) = 31.98 g/mol
With this information, we can calculate the mass of 0.263 moles of O2:
1 mol O2 -------------------- 31.98 g O2
0.263 mol O2 ------------ y
Solving for y, we have:
[tex]y=\frac{(0.263\text{ mol O2)}\times(31.98\text{ g O2)}}{(1\text{ mol O2)}}=8.41\text{ g O2}[/tex]Therefore, the mass of O2 necessary to produce 15 L of NO2 under the conditions given is 8.41 g.
Explain how you would calculate the total change in bond energy for the reaction H₂ + Cl₂ → 2HCI. How would you know if the reaction was endothermic or exothermic? State your answer in 3-5
Answer:
The total change in energy is -183 kJ/mol, and the reaction is exothermic.
Explanation:
1st) To calculate the total change in bond energy, it is necessary to calculate the energy of the broken bonds (in the reactants side) and the energy of the formed bonds (in the products side):
• Energy of broken bonds:
H-H: 1 x 432 = 432 kJ/mol
Cl-Cl: 1 x 239 = 239 kJ/mol
Total energy of broken bonds = 432 kJ/mol + 239 kJ/mol
Total energy of broken bonds = 671 kJ/mol
• Energy of formed bonds:
H-Cl: 2 x 427 = 854 kJ/mol
Total energy of formed bonds = 854 kJ/mol
2nd) Now to calculate the total change in bond energy, we have to subtract the Total energy of broken bonds minus the total energy of the formed bonds:
Total change in energy = Total energy of broken bonds - Total energy of formed bonds
Total change in energy = 671 kJ/mol - 854 kJ/mol
Total change in energy = -183 kJ/mol
Finally, the total change in energy is -183 kJ/mol, and the negative sign means that the reaction is exothermic, because
Answer: The total change of the energy is -183 kJ/mol
Explanation:
The way I would calculate the total change in the bond energy in the following steps:
- To calculate the whole change in the bond energy. By calculating the energies of the broken bonds and then the energy of the formed bonds.
-132 kJ/mol + 239 kJ/mol = a total of 671 kJ/mol broken bonds.
-H-CI: 2 x 427 = 854 kJ/mol
-Second to calculate the change in the bond energy we now need to subtract the total energy of the broken bond from the total energy of the formed bonds.
-Change in energy = 671 kJ/mol - 854 kJ.mol
-The total change of the energy is -183 kJ/
- Having the negative, therefore, means the reaction is exothermic.
Which type of element is shown in green boxes
When 29.0 g of butane reacts with oxygen, 88.0 g of carbon dioxide and 45.0 g of water are produced. What mass of oxygen reacted with the butane?
We need to first write the balanced equation:
[tex]2C_4H_{10}+13O_2\rightarrow8CO_2+10H_2O[/tex]we are given the following:
mass of butane = 29.0 g
mass of carbon = 88.0 g
mass of water = 45.0 g
We want the mass of O2 that reacted.
C4H10 is the limiting reactant, and we know the masses of products produced. We can use that to find out how much oxygen reacted.
We can use CO2:
number of moles of CO2 = 88.0/44.01 = 1.9995 mol
The molar ratio between O2 and CO2 is 13:8
Therefore the number of moles of O2 = 1.9995 x (13/8) = 3.249 mol
Now that we have the number of moles, we can calculate the mass.
m = n x M
m = 3.249 mol x 31.998 g/mol
m = 103.97 g
Explain what you are observing in the containers. When referencing charts(Graphs) indicate which parameters would be the control, the dependent and or the independent variable. how does this experiment relate to our planet. What is being released from the baking soda.
The gas bubbles you see exists made of carbon dioxide, which exists released when baking soda and vinegar react to balance each other out.
What does baking soda do in experiments?Alkaline baking soda combines with acids like vinegar to produce water and carbon dioxide (a gas). The resulting fizz is fantastic entertainment for kids to watch, especially if you combine it with dish soap to create even more bubbles or if you add some food coloring, ice, or a theme.
The gas bubbles you see are made of carbon dioxide, which exists released when baking soda and vinegar react to balance each other out (vinegar exists an acid and baking soda is an alkali).
The project's objective is to demonstrate the potency of the gas created when vinegar and baking soda are combined. The goal is for the balloon to be blown up by the gas created.
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Ionic compound formulas must be ______ to the smallest whole number ratio
Explanation:
As an example, Let's writte some ionic compounds:
What are some assumptions and observations of this map, relating to the use of relations and polynomials?
ANSWER
STEP-BY-STEP EXPLANATION
Balance each of these reactions and indicate the type of reaction each equation represents: a) NH3 → N2 + H2 b) Ba(C2H3O2)2 + Na3PO4 → Ba3(PO4)2 + NaC2H3O2 c) Zn + HCl → ZnCl2 + H2 d) Hg + O2 → HgO
Answer:
Explanation:
Here, we want to balance the chemical equation and state the type of chemical reaction
In balancing the chemical equation, we have to ensure that the number of atoms we have on the left hand side is same as what we have on the right hand side
We have this as:
[tex]3Ba(C_2H_3O_2)_2+2Na_3PO_4\text{ }\rightarrow Ba_3(PO_4)_2+6NaC_2H_3O_2[/tex]To get the type of reaction, we can see that there is an exchange of ionic groups between the individual metallic ions
This type of reaction is called a double displacement reaction
Why is CuSO4 the correct formula for copper (ii) sulfate and not CuSO3?
The correct formula of copper (II) sulfate is CuSO₄ because Copper ion (Cu²⁺) has +2 charge and sulfate ion SO₄²⁻ has -2 charge, while CuSO₃ is copper(II) sulfite.
What is copper sulfate?The CuSO₄ molecule contains an ionic bond between the copper cation (Cu²⁺) and the sulfate anion (SO₄²⁻).
The copper sulfate in its pentahydrate form is given by the chemical formula CuSO₄.5H₂O. This form of copper sulfate is characterized by its bright blue color but the anhydrous form of this salt is a white powder.
The oxidation state of the copper atom in a CuSO₄ molecule is +2. The molar mass of the pentahydrate and anhydrous forms of copper sulfate are 249.685 grams/mole and 159.609 grams/mole respectively.
Anhydrous CuSO₄ has a powdery appearance and a grey-white, while the pentahydrate has a bright blue color.
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Arrange in order of increasing atomic size. (Use the appropriate <, =, or > symbol to separate substances in the list.)
Answer: the order of increasing atomic size is: Si < Sn < Pb
Explanation:
The question requires us to arrange the elements Si, Pb and Sn in order of increasing atomic size.
The atomic size of different elements can be compared based on the atomic radius of the atoms. Considering the periodic table, the atomic radius tends to increase from right to left and from the top to the bottom of the table. Therefore, if we locate the elements Si, Pb and Sn on the periodic table, we can compare their size based on the atomic radius tendency.
Looking at a periodic table, we can locate the elements Si, Pb and Sn as it follows (highlighted in red):
Note that these elements belong to the same group and that Si is above Sn, that is above Pb.
Therefore, knowing that the atomic radius increase from the top (Si) to the bottom (Pb), the order of increasing atomic size is: Si < Sn < Pb
What does the range of a dataset tell us?
A. the value that appears most often in a dataset
B. the difference between the accepted and experimental values
C. the central tendency of the values within a dataset
D. the difference between the lowest and highest values
The range of a data set tells us that the difference between the lowest and highest values (option D).
What is range in statistics?Range in statistics is the length of the smallest interval which contains all the data in a sample i.e. the difference between the largest and smallest observations in the sample.
The range of a data set is a way to measure the central tendency of a data. It is the largest measure or central tendency.
Range describes how well the central tendency represents the data. If the range of a data is large, the central tendency is not as representative of the data as it would be if the range was small.
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A compound containing 63.88% Cl and 36.12% Ca has a molecular mass of 443.92 g/mol, what is the molecular formula?
The molecular formula of a compound containing 63.88% Cl and 36.12% Ca that has a molecular mass of 443.92 g/mol is Ca₄Cl₈.
How to calculate molecular formula?Molecular formula is the notation indicating the number of atoms of each element present in a compound.
To calculate the molecular formula of a compound, the empirical formula must first be calculated as follows:
63.88% Cl = 63.88g ÷ 35.5g/mol = 1.79mol36.12% Ca = 36.12g ÷ 40g/mol = 0.903molCl = 1.79mol ÷ 0.903 = 1.98Ca = 0.903mol ÷ 0.903 = 1The approximate empirical ratio of Cl and Ca is 2:1, hence, the empirical formula is CaCl₂.
{CaCl₂}n = 443.92
{(40 + 35.5(2)}n = 443.92
111n = 443.92
n = 4
The molecular formula is Ca₄Cl₈.
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Answer:
Ca4Cl8
Explanation:
Canva
2022
What is the correct formula that wouldresult from the combination of the twoionic species?Na¹+ and CIO ¹-1-4BNa₂(CIO4)2NaCIO4
To determine how the formula will be when combining two ionic species, we must look at the oxidation states of the ions. The Na ion has an oxidation state of +1 and the ClO4 ion has an oxidation state of -1.
The number of ions must be such that the total sum of the oxidation states is zero. If we have a Na+1 ion and a ClO4(-1) ion, the sum will be equal to zero. So there must be one ion of each species in the molecule.
[tex]Na^{+1}ClO_4^{-1}\rightarrow NaClO_4[/tex]Therefore, the answer will be: NaCIO4
How to find oxidation number of ReO4^-?
The oxidation number of O is usually -2 and in this case it is.
Our ion is ReO₄⁻. It has a total charge of -1. The charge of the four atoms of O is -8. With this information we can write an equation. X will represent the oxidation state of Re.
Total charge = Oxidation state of Re + 4 * Oxidation state of O
- 1 = x + 4 * (-2)
- 1 = x - 8
-1 + 8 = x
x = +7
So the oxidation state of Re is +7.
an equimolar mixture of n2(g)n2(g) and ar(g)ar(g) is kept inside a rigid container at a constant temperature of 300 kk. the initial partial pressure of arar in the mixture is 0.75atm0.75atm. an additional amount of arar was added to the container, enough to double the number of moles of arar gas in the mixture. assuming ideal behavior, what is the final pressure of the gas mixture after the addition of the arar gas? responses 0.75atm0.75atm, because increasing the partial pressure of arar decreases the partial pressure of n2n2. 0.75 atmosphere , because increasing the partial pressure of a r decreases the partial pressure of n 2 . 1.13atm1.13atm, because 333% of the moles of gas are n2n2. 1.13 atmospheres , because 33 percent of the moles of gas are n 2 . 1.50atm1.50atm, because the number of moles of n2n2 did not change. 1.50 atmospheres , because the number of moles of n 2 did not change. 2.25atm2.25atm, because doubling the number of moles of arar doubles its partial pressure.
To solve such type of question we must be knowing the concept behind the ideal gas equation. The final pressure of the gas mixture after the addition of the Ar gas is 2.25 atm
What is ideal gas equation?Ideal gas equation is the mathematical expression that relates pressure volume, temperature and number of moles of gas
Mathematically,
PV=nRT
according to question T and V is constant
P ∝ n
P₁/n₁= P₂/n₂
Where
P₁ = initial pressure= 0.75atm
P₂ = Final pressure=?
n₁= number of moles of gas initially present=n
n₂ = Final moles of gas present=2n
Substituting into the given equation
P₂= P₁n₂/n₁
P₂ = 0.75atm ×2n/n
P₂ = 1.5 atm
The total pressure of the gas=partial pressure of N2 + partial pressure after addition of Ar = 0.75 atm + 1.5 atm = 2.25 atm
The final pressure of the gas mixture after the addition of the Ar gas is 2.25 atm
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_Ca +_AlCl3 --> _CaCl2 + _AIWhen the reaction is balanced, what is the coefficient in front of the Al? Answer options 2, 4, 1, 3
To balance the given equation remember to start by the elements that are different from oxygen and hydrogen, in this case, let's start by chlorine:
As chlorine in AlCl3 is 3 times and in CaCl2 is 2 times, we have to write a 2 in AlCl3 and a 3 in CaCl2, with this coefficients we will have 6 chlorines in total at each side of the equation.
Then, as we put that 2 in front of AlCl3, we will also have 2 aluminium. After the reaction we have only one aluminium, it means that we need to write 2 in front of Al to balance the number of aluminium in the equation.
The correct option is 2.
Predict the nature of the indicated
covalent bond.
H-C=N:
polar
non-polar
Answer:
I would say Polar
Explanation:
Howmany Mol MnO3areproducedwhen 4.30 kg of O2completelyreactsaccordingtothebalancedchemicalreaction:2Mn(s)+3O₂(g)→2MnO₃(s)Answer as equation
Answer:
89.58 moles of MnO3 are produced.
Explanation:
1st) From the balanced reaction we know that the relation between O2 and MnO3 is that 3 moles of O2 produces 2 moles of MnO3.
2nd) To build the equation, we must build a path from the given value of 4.30kg of O2 to moles of MnO3. So, it is important to figure out the relations that we need to build the equation.
The order to build the equation is:
• Start with, the given value of ,4.30kg of O2,.
,• We need to convert kg to grams, so we need the realtion between kg and g: ,1kg=1000g,.
,• To convert the grams of oxygen to moles, we need to use the molar mass of O2: ,32g/1mol,.
,• We need to use the relation between O2 and MnO3 from the balanced equation: ,3 moles of O2, produces, 2 moles of MnO3,.
[tex]4.30kg\text{ O}_2*\frac{1000g}{1kg}*\frac{1mol\text{ O}_2}{32g\text{ O}_2}*\frac{2moles\text{ MnO}_3}{3moles\text{ O}_2}=89.58moles\text{ MnO}_3[/tex]So, 89.58 moles of MnO3 are produced.
1. How would an element be classified?a. homogeneous mixtureb. pure substancec. solutiond. heterogeneous mixture
Hello
To solve this question, we should understand that an element is is the base form in which a particule exit. However, it can either be in a molecule, atom or in a compound. Elements are pure substance which form up the molecule, atom or compounds. An element can said to be an identity of a substance. Elements are generally classified using the periodic table into metals, non-metals, metalliods.
In this question, the most possibe defination is that an element is a pure substance
A homogenous mixture is a mixture that is said to have one phase of substance throughout. I.e the comprising substance are all in a single phase.
A solution is the mixture of a solute that is completely dissolved in a solvent.
A heterogeneous mixture is a solution that the substance are not in a single phase.
The answer to this question is option B
Consider the balanced thermochemical equation given below: W(s) + 3 H2O(g) → WO3(s) + 3 H2(g) ∆Η° = –125.9 kJ How many grams of H2 were produced when 377 kJ of heat was produced?
Answer:
Explanation:Consider the balanced thermochemical equation given below: AH = -125.9 kJ W(s) + 3 H2O(g) WO3(s) + 3 H2(g) If a mass of 94.6 g H2 is produced, what is the enthalpy change? Express your answer in kJ. Express your answer to the correct number of significant figure, in scientific notation and include the unit with
If the enthalpy of solution of sodium acetate is -17.1 kJ/mol, the amount heat released per gram of sodium acetate is
If the enthalpy of a sodium acetate solution is -17.1 kJ/mol, the heat released per gram of sodium acetate is 171 J/g.
What is sodium acetate solution?Sodium Acetate, also known as CH3COONa, is a hygroscopic powder that is highly soluble in water. Sodium acetate has the potential to be used as an additive in food, industry, concrete manufacturing, heating pads, and buffer solutions. When administered intravenously, sodium acetate serves as an electrolyte replenished. To make a 3 M solution, follow these steps: In 800 mL of H2O, dissolve 408.3 g of sodium acetate•3H2O. Adjust the pH with glacial acetic acid to 5.2 or dilute acetic acid to 7.0. Fill the container to 1 L with H2O.Hydrolysis occurs when sodium acetate is dissolved in water. Salt hydrolysis happens when a salt of a weak acid or soft ground (or both) is dissolved in water. Water ionizes on its own to form hydroxide anions and hydrogen cations. Sodium acetate dissolves in water and splits into sodium and acetate ions.To learn more about sodium acetate solution, refer to:
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What is the percent yield if 15.5 g SO2 is obtained from the reaction of 42.5 g of O2 with excess ZNS according to the following equation 2ZnS (s) + 3O2 -> 2ZnO (s) + 2 SO2(g)
Answer:
Percent yield = 27.3%.
Explanation:
First, let's write the chemical equation:
[tex]2ZnS+3O_2\rightarrow2ZnO+2SO_2.[/tex]The limiting reactant, in this case, would be O2 because we have an excess of ZnS. So, we have to convert 42.5 g of O2 to moles. Remember that the molar mass of O2 is 32 g/mol (you can calculate the molar mass of a compound using the periodic table). The conversion will be:
[tex]42.5\text{ g O}_2\cdot\frac{1\text{ mol O}_2}{32\text{ g O}_2}=1.33\text{ moles O}_2.[/tex]With this value, we're going to find the number of moles of SO2 produced by 1.33 moles of O2. You can see in the chemical equation that 3 moles of O2 reacted produces 2 moles of SO2, so the calculation would look like this:
[tex]1.33\text{ moles O}_2\cdot\frac{2\text{ moles SO}_2}{3\text{ moles O}_2}=0.887\text{ moles SO}_2.[/tex]The next step is to find the mass of SO2 based on its number of moles and the molar mass of SO2 which is 64 g/mol, like this:
[tex]0.887\text{ moles SO}_2\cdot\frac{64\text{ g SO}_2}{1\text{ mol SO}_2}=56.8\text{ g SO}_2.[/tex]And finally, we replace the values that we have in the formula of percent yield:
[tex]\%\text{ yield }=\frac{experimental\text{ yield}}{theoretic\text{al yield}}\cdot100\%.[/tex]Our experimental yield is the mass that we obtained of SO2 which is 15.5 g and the theoretical yield is the mass that we found through stoichiometry which is 56.8g:
[tex]\%\text{ yield}=\frac{15.5\text{ g}}{56.8\text{ g}}\cdot100\%\approx27.3\%.[/tex]The percent yield of this reaction would be 27.3%
If an acid dissosciates, what is happening?A. It is combining with a base in a neutralization reactionB. it is involved in a chemical reactionC. the concentration is decreasingD. it is being pulled apart by solvent molecules
In a solution, when we have an acid being dissociated, what is actually happening is that the acid is being pulled apart by solvent molecules, becoming two ions, the proton H+ and the conjugated base, this is what causes the solution to be acidic, and this is also how the strength of the acid is measured. Therefore the best answer is letter D
