Which of the following tests should be administered to see if an experimental medicine lowers blood pressure among hypertensive patients? A. two-tailed test OB. right-tailed test OC. alternative test OD. left-tailed test

Which Of The Following Tests Should Be Administered To See If An Experimental Medicine Lowers Blood Pressure

Answers

Answer 1

We have to select the appropiate test to see if an experimental medicine lowers blood pressure among hypertensive patients.

In this case, we want to test if the mean for the blood pressure after the treatment is significantly lower than the blood pressure mean without treatment.

Then, for the blood pressure to be significantly different it has to be to the left of a critical value.

Then, it is a left-tailed test.

Answer:


Related Questions

In ABC, B = 51°, b = 35, and a = 36. What are the two possible values for angle A to the nearest tenth of a degree?Select both correct answers.

Answers

Using the law of sines:

[tex]\frac{a}{\sin(A)}=\frac{b}{\sin (B)}[/tex]

Solve for A using the data provided:

[tex]\begin{gathered} \sin (A)=\frac{\sin (B)\cdot a}{b} \\ A=\sin ^{-1}(\frac{\sin (51)36}{35}) \\ A\approx53.1 \\ or \\ A\approx126.9 \end{gathered}[/tex]

A student is trying to solve the set of two equations given below:Equation A: x + z = 6Equation B: 3x + 2z = 1Which of the following is a possible step used in eliminating the z-term

Answers

[tex]\begin{gathered} Let\colon \\ x+z=6_{\text{ }}(A) \\ 3x+2z=1_{\text{ }}(B) \end{gathered}[/tex][tex]\begin{gathered} Multiply_{\text{ }}A_{\text{ }}by_{\text{ }}-2\colon \\ -2(x+z)=-2(6) \\ -2x-2z=-12 \\ Add_{\text{ }}A_{\text{ }}and_{\text{ }}B\colon \\ -2x+3x-2z+2z=-12+1 \\ x=-11 \end{gathered}[/tex]

Answer:

multiply equation A by -2

In an office building, 54 office are currently being rented, this represent 30% of the total units. how many offices are in the building

Answers

given that,

54 offices are currently rented

and it represent 30% of the total unit

to get the total offices in the building

let the total offices be x

30% of x = 54

30/100 X x = 54

cross multiply

30x = 5400

dividing both sides by 30

30x/30 = 5400/30

x = 5400/30

x = 180

therefore the total offices in the building is 180

Given f <-2, 3> and g <1, -5> find f + 2g

Answers

Here are the steps in adding vector f and vector 2g.

1. First, multiply vector G by 2. To do this, simply multiply each component of g by 2.

[tex]<2(1),2(-5)>\Rightarrow<2,-10>[/tex]

2. Add the result in step 1 to vector f.

To add, simply add each component of vector f to its corresponding component of vector g.

[tex]\begin{gathered} <-2,3>+<2,-10> \\ <-2+2,3+(-10)> \\ <0,-7> \end{gathered}[/tex]

The result is <0, -7>.

Hence, f + 2g = <0, -7>. (Option 3)

Hence, f + 2g = <0, -7>. (Option 3)

Which equation could be represented by the number line? A. 3 OB.-4 5=1 OC. 1+ -5)= OD. -3+4 -1

Answers

According to the given number line, we have to go back from the second point to the first point 4 spots. In other words, the equation has to include a sum with -4.

Therefore, the answer is A since it's expressing an initial number 3, then the sum with -4.

In December, 64 teams qualify for a basketball tournament. After each round, half of the teams are eliminated.
Which exponential function can be used to find the number of teams left after a rounds, where is a whole number?
O f(x) = (64)
O f(x) =
(x)64
O f(x) = 64 (¹)
○ f(x) = x(¹)

Answers

The exponential function is f(x) = 64·(1/2)ˣ which can be used to find the number of teams left after a round.

What is an exponential function?

An exponential function is defined as a function whose value is a constant raised to the power of an argument is called an exponential function.

Given that 64 teams qualify for a basketball tournament. After each round, half of the teams are eliminated.

Because it is an exponential function, f(x) will reach 0 as x increases, allowing us to construct the following table of values:

x    f(x)

0    64

1     32

2    16

3     8

4     4

5     2

6     1

At that point, 64 teams are in the tournament, and the total number of teams (from this point forward)

Therefore, half of the teams are eliminated after each round and the exponential function is:

f(x) = 64·(1/2)ˣ

Learn more about exponential function here:

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Find the distance between the pair of points. (16,0) and (1, -7) The distance is. (Round to the nearest thousandth as needed.)

Answers

Solution

For this case we can use the formula for the distance between two points:

[tex]d=\sqrt[]{(y_2-y_1)^2+(x_2-x_1)^2}[/tex]

and replacing we got:

[tex]d=\sqrt[]{(-7-0)^2+(1-16)^2}=\sqrt[]{274}[/tex]

And the correct answer after round would be:

16.553

This question is from a MATH extra credit assignment, so unless I accidentally clicked on a subject other than maths... This question is also not from a test. Please help me if you can. Thank you if you do :)

Answers

Answer

$6,314

Step-by-step explanation

Compound interest formula

[tex]A=P(1+\frac{r}{n})^{nt}[/tex]

where

• A: final amount, in dollars

,

• P: principal, in dollars

,

• r: interest rate, as a decimal

,

• n: number of times interest is applied per year

,

• t: time in years

In this case, the investment is compounded annually, that is, once per year (n = 1). Substituting P = $4,625, r = 0.0352 (=3.52/100), n = 1, and t = 9 years, we get:

[tex]\begin{gathered} A=4,625(1+\frac{0.0352}{1})^{1\cdot9} \\ A=4,625(1.0352)^9 \\ A=\text{ \$}6,314 \end{gathered}[/tex]

Paulina bought a used car as she was entering college and planned to trade it in when she graduated four years later. She had learned in her high school financial algebra class that the average used car depreciated at an annual rate of 15%. If she had paid $13,900 for her car, how much can she expect to get when it is time for her to trade it in for a new car?

Answers

1st year

depreciable value: $13900

annual depreciation: $13900*15% = $2085

2nd year

depreciable value: $13900 - $2085 = $11815

annual depreciation: $11815*15% = $1772.25

3rd year

depreciable value: $11815 - $1772.25 = $10042.75

annual depreciation: $10042.75*15% = $1506.41

4th year

depreciable value: $10042.75 - $1506.41 = $8536.34

annual depreciation: $8536.34*15% = $1280.45

Final value: $8536.34 - $1280.45 = $7255.89

In the figure, ∆ABD ≅ ∆CBD by Angle-Side-Angle (ASA). Which segments are congruent by CPCTC? BC ≅ AD CB ≅ AB AB ≅ CD DB ≅ DC

Answers

By CPCTC this is the only valid answer:

CB ≅ AB

Another statement should be AD≅ CD

Use a trig equation to solve for x. Round to the nearest tenth.

Answers

Given a right angle triangle

We need to find the measure of the angle x

The opposite side to the angle x = 19

the adjacent side to the angle x = 15

We will find x using the tan function as follows:

[tex]\begin{gathered} \tan x=\frac{opposite}{adjacent} \\ \\ \tan x=\frac{19}{15} \\ \\ x=\tan ^{-1}\frac{19}{15}\approx51.7098^{} \end{gathered}[/tex]

Round the answer to the nearest tenth

so, the answer will be x = 51.7

A local real estate company has 5 real estate agents. The number of houses that each agent sold last year is shown in the bar graph below. Use this bar graph to answer the questions.

Answers

Given:

Rachel sold 4 houses.

Heather sold 4 houses.

Kaitlin sold 12 houses.

Lena sold 11 houses.

Deshaun sold 3 houses.

Required:

a) We need to find which agent sold the most houses.

b) We need to find the number of houses Lna soldemore than Heather.

c) We need to find the number of agents who sold fewer than 4 houses.

Explanation:

a)

The greatest number of houses sold =12 houses.

Kaitlin sold 12 houses.

Answer:

The agent Kaitlin sold the most houses.

The agent sold 12 houses.

b)

Lena sold 11 houses.

Heather sold 4 houses.

The difference between 11 and 4 is 11-4 =7.

Answer:

Lena sold 7 housmore than Heather

Please step-by-step help me how much of a circle is shaded

Answers

The given data is ratio from the the total are of circle is 1 .

let the shaded area is x then:

All area is equal to one.

[tex]\begin{gathered} \frac{1}{2}+\frac{2}{9}+x=1 \\ \frac{9+4}{18}+x=1 \\ \frac{13}{18}+x=1 \\ x=1-\frac{13}{18} \\ x=\frac{18-13}{18} \\ x=\frac{5}{18} \end{gathered}[/tex]

So area of shaded region is

[tex]\frac{5}{18}[/tex]

Santa worked 3.5 hours, 6.9 hours, & 4.3 hours in the last three days. If he earns $7.1 an hour, how much did he earn in the last three days?

Answers

ANSWER:

$104.37

STEP-BY-STEP EXPLANATION:

To calculate the total profit, we must add the amount he earned each day, multiplying the salary by the number of hours, like this:

[tex]\begin{gathered} e=3.5\cdot7.1+6.9\cdot7.1+4.3\cdot7.1 \\ e=24.85+48.99+30.53 \\ e=104.37 \end{gathered}[/tex]

Therefore, he earned in the last three days a total of $104.37

Solve the equation for y.1/3 x + y = 4

Answers

In order to solve the equation for y, we just need to isolate the variable y in one side of the equation. So we have:

[tex]\begin{gathered} \frac{1}{3}x+y=4 \\ y=4-\frac{1}{3}x \end{gathered}[/tex]

So the answer is y = 4 - 1/3 x

The variables x and y vary directly. Use values to write an equation that relates x and y. y=25;x=5And y=20;x=12

Answers

A lineal equation has the next form:

[tex]y=mx+b[/tex]

where m is the slope and is calculated as follow:

[tex]m=\frac{y_2-y_1}{x_2-x_1}[/tex]

For this case

y1=20

y2= 25

x1=12

x2= 5

so:

[tex]m=\frac{25-20}{5-12_{}}=\frac{5}{-7}=-\frac{5}{7}[/tex]

then the equation will be:

[tex]y=(-\frac{1}{7})x+b[/tex]

Using one of the points we calculate the b

we are going to use y=25 x=5

[tex]25=(-\frac{5}{7})5+b[/tex]

Clearing the b we get:

[tex]25-\frac{25}{7}=b\Rightarrow\frac{200}{7}=b[/tex]

b=200/7 or b=28.57

So the final equation is:[tex]y=-\frac{1}{7}x+\frac{200}{7}[/tex]

A lineal equation has the next form:

[tex]y=mx+b[/tex]

where m is the slope and is calculated as follow:

[tex]m=\frac{y_2-y_1}{x_2-x_1}[/tex]

For this case

y1=20

y2= 25

x1=12

x2= 5

so:

[tex]m=\frac{25-20}{5-12_{}}=\frac{5}{-7}=-\frac{5}{7}[/tex]

then the equation will be:

[tex]y=(-\frac{1}{7})x+b[/tex]

Using one of the points we calculate the b

we are going to use y=25 x=5

[tex]25=(-\frac{5}{7})5+b[/tex]

Clearing the b we get:

[tex]25-\frac{25}{7}=b\Rightarrow\frac{200}{7}=b[/tex]

b=200/7 or b=28.57

So the final equation is:[tex]y=-\frac{1}{7}x+\frac{200}{7}[/tex]

Please help.
A circle has a diameter of 18 inches. A central angle of 75° intercepts an arc of the circle. What is the intercepted arc length to the nearest tenth of an inch?

A.) 2.08 inches

B.) 3.8 inches

C.) 11.8 inches

D.) 23.6 inches

Answers

Answer:

C.) 11.8 inches

===========================

Given

A circle with diameter d = 18 in,Central angle θ = 75°.

To find

The length of the given arc

Solution

Use arc length formula:

s = πdθ/360

Substitute the values and calculate:

s = 3.14 * 18 in * 75°/360° = 11.8 in (rounded)

The matching answer choice is C.

Which is the image of vertex K after the parallelogram is rotated 180degrees about the origin?

Answers

Answer:

The image of vertex K is (3,-2)

Step-by-step explanation:

Rotated 180 degrees about the origin means that the value of x will not change, while y will have the same distance from the origin, but in a different direction.

Vertex K:

Value of x: x = 3

Value of y: y = 2

Distance from the origin: 2 - 0 = 2

Rotated, new coordinate: 0 - 2 = -2

The image of vertex K is (3,-2)

Dr. Hughes instructs her students to solve the equation, 2x - 5y = -20, for y. What is the correct first step?Add +5y to both sides of the equation.O Add -2x to both sides of the equation.Add +2x to both sides of the equation.Divide each term in the equation by -5.

Answers

We have the following expression given:

2x -5y = -20

For this case the correct set in order to begin is add 5y in both sides

Add +5y to both sides of the equation.

9) solve using substitution method and check your answer:4x - 3y + 2z = 16- 4y - Z = 7= 146x - y

Answers

Given the system of equations, solve the third equation for y, as shown below

[tex]\begin{gathered} 6x-y=14 \\ \Rightarrow y=6x-14 \end{gathered}[/tex]

And, solve for z in the second equation,

[tex]\begin{gathered} -4y-z=7 \\ \Rightarrow z=-4y-7 \\ \Rightarrow z=-4(6x-14)-7=-24x+49 \end{gathered}[/tex]

Thus, substitute the values of y and z in terms of x into the first equation, as shown below

[tex]\begin{gathered} \Rightarrow4x-3y+2z=4x-3(6x-14)+2(-24x+49)=4x-18x+42-48x+98 \\ \Rightarrow-62x+140=16 \\ \Rightarrow-62x=-124 \\ \Rightarrow x=2 \end{gathered}[/tex]

Then, solving for y and z given x=2,

[tex]\begin{gathered} x=2 \\ \Rightarrow y=6*2-14=-2 \\ and \\ z=-24*2+49=-48+49=1 \end{gathered}[/tex]Therefore, the solution to the system of equations is x=2, y=-2, z=1

To verify the solutions, substitute the values we found into the three equations of the system, as shown below

[tex]\begin{gathered} x=2,y=-2,z=1 \\ \Rightarrow4x-3y+2z=4*2-3*(-2)+2*1=8+6+2=16\rightarrow correct \\ \Rightarrow-4y-z=-4*(-2)-1(1)=8-1=7\rightarrow correct \\ \Rightarrow6x-y=6*2-1(-2)=12+2=14\rightarrow correct \end{gathered}[/tex]

helppppppppppppppppppppppppppppppppppp

Answers

For (fog)(x) all you do is substitute the value of x for the value of (g)(x) because (fog)(x)=(f(g(x))), and vice versa for (gof)(x)!!

Instructions: Find the value of that completes the square and creates a perfect square trinomial.

Answers

Solution:

Given the expression;

[tex]x^2+18x+c[/tex]

c is the half of square of coefficient of x. That is;

[tex]\begin{gathered} x^2+18x+c=x^2+18x+(\frac{1}{2}(18))^2 \\ \\ x^2+18x+c=x^2+18x+9^2 \\ \\ x^2+18x+c=x^2+18x+81 \\ \\ x^2+18x+81=(x+9)(x+9) \end{gathered}[/tex]

Hence, the value of c is;

[tex]c=81[/tex]

A triangle has vertices on a coordinate grid at D(-10, -1), E(-10,6), and F(2,6). What is the length, in units, of DE?

Answers

A triangle has vertices on a coordinate grid at D(-10, -1), E(-10,6), and F(2,6). What is the length, in units, of DE?​

we know that

The formula to calculate the distance between two points is equal to

[tex]d=\sqrt[]{(y2-y1)^2+(x2-x1)^2}[/tex]

we have

D(-10, -1), E(-10,6)

substitute the given values in the formula

[tex]\begin{gathered} d=\sqrt[]{(6+1)^2+(-10+10)^2} \\ d=\sqrt[]{(7)^2+(0)^2} \\ d=\sqrt[]{49} \\ d=7\text{ units} \end{gathered}[/tex]

therefore

the distance DE is 7 units

if a certain number is added to both the numerator and denominator of the fraction 8/9, the result is 6/7. Find the numer.

Answers

[tex]\begin{gathered} \text{The given fraction is}\Rightarrow\frac{8}{9} \\ \text{Add x in both numerator and denominator as,} \\ \Rightarrow\frac{8+x}{9+x}=\frac{6}{7} \\ 7(8+x)=6(9+x) \\ 56+7x=54+6x \\ x=54-56 \\ x=-2 \end{gathered}[/tex]

I need to find the radius and the diameter but I don't understand.

Answers

ANSWER

Radius = 3 yd

Diameter = 6 yd

EXPLANATION

We are given the circle in the figure.

The radius of a circle is defined as the distance between the centre of a circle and its circumference.

Therefore, from the circle given, the radius is 3 yards

The diameter of a circle is defined as the total distance (through the centre) from one end of a circle to another.

It is twice the radius. Therefore, the diameter of the given circle is:

D = 3 * 2

D = 6 yards

The diameter is 6 yards.

Which of the following ordered pairs is a solution to the equation 2x+y=2? Select all that apply.(11,0)(−4,10)(−13,4)(−11,−1)(0,2)

Answers

You have the following equation:

2x + y = 2

In order to determine which of the given pairs is a solution, replace the values of x and y of such pairs and verify the equation, as follow:

(11,0)

2(11) + 0 = 22 ≠ 2 it's not a solution

(-4,10)

2(-4) + 10 = -8 + 10 = 2 it's a solution

(-13,4)

2(-13) + 4 = -26 + 4 ≠ 2 it's not a solution

(-11,-1)

2(-11) + (-1) = -22 - 1 ≠ 2 it's not a solution

(0,2)

2(0) + 2 = 2 it's a solution

I need help to find the indicated operation:g(x)= -x^2 +4xh(x)= -4x-1Find (3g-h)(-3)

Answers

We have the following functions:

[tex]\begin{gathered} g\mleft(x\mright)=-x^2+4x \\ h\mleft(x\mright)=-4x-1 \end{gathered}[/tex]

And we need to find:

[tex](3g-h)(-3)[/tex]

Step 1. Find 3g by multiplying g(x) by 3:

[tex]\begin{gathered} g(x)=-x^2+4x \\ 3g=3(-x^2+4x) \end{gathered}[/tex]

Use the distributive property to multiply 3 by the two terms inside the parentheses:

[tex]3g=-3x^2+12x[/tex]

Step 2. Once we have 3g, we subtract h(x) to it:

[tex]3g-h=-3x^2+12x-(-4x-1)[/tex]

Here we have 3g and to that, we are subtracting h which in parentheses.

Simplifying the expression by again using the distributive property and multiply the - sign by the two terms inside the parentheses:

[tex]3g-h=-3x^2+12x+4x+1[/tex]

Step 4. Combine like terms:

[tex]3g-h=-3x^2+16x+1[/tex]

What we just found is (3g-h)(x):

[tex](3g-h)(x)=-3x^2+16x+1[/tex]

Step 5. To find what we are asked for

[tex]\mleft(3g-h\mright)\mleft(-3\mright)​[/tex]

We need to evaluate the result from step 4, when x is equal to -3:

[tex](3g-h)(-3)=-3(-3)^2+16(-3)+1[/tex]

Solving the operations:

[tex](3g-h)(-3)=-3(9)^{}-48+1[/tex][tex](3g-h)(-3)=-27^{}-48+1[/tex][tex](3g-h)(-3)=-74[/tex]

Answer:

[tex](3g-h)(-3)=-74[/tex]

A newsletter publisher believes that more than 31% of their readers own a Rolls Royce. Is there sufficient evidence at the 0.01 level to substantiate the publisher's claim? State the null and alternative hypotheses for the above scenario. Answer

Answers

The null hypothesis is H0: P = 0.31 and the alternative hypothesis is Ha: P > 0.31.

What is a null hypothesis?

The null hypothesis is simply to predict that there is no effect of relationship between the variables.

The alternative hypothesis is to state the research prediction of a relationship or effect. In this case, the newsletter publisher believes that more than 31% of their readers own a Rolls Royce.

The null hypothesis is P = 0.31. while the alternative hypothesis will be that it's greater than 0.31.

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Graph the inequality and give interval notation for the solution. Use two o's (as in octopus) forinifinity and a U for union as needed.-- 5x + 4 >I 19 OR – 22 - 15 – 3-8 -7 -6 -5-4-3-2-] 022345678Clear All Draw:Interval notation for the above inequality and graph is

Answers

- 5x + 4 > 19

1st step let us move 4 to the other side by subtracting both sides by 4

- 5x + 4 - 4 > 19 - 4

- 5x > 15

2nd step is move - 5 to the other side by dividing both sides by -5, BUT when we divide the sides of an inequality by a negative number we must reverse the sign of inequality

[tex]\frac{-5x}{-5}<\frac{15}{-5}[/tex]

x < -3

The solution is all values smaller than -3

On the number, line draw an empty circle at -3 then draw from it an arrow pointing to the left ( - ve infinity)

The solution is {x : x < -3} or (-00, -3)

If 6 is subtracted from the third of three consecutive odd integers and the result is multiplied by 2, the answer is 23 less then the sun if the first and twice the second of the integers

Answers

[tex]\begin{gathered} \text{Let }x\text{ be the first odd integer, then it goes that} \\ x+2\rightarrow\text{second odd integer} \\ x+4\rightarrow\text{third odd integer} \\ \text{If 6 is subtracted from the third of three consecutive odd integer, translates to} \\ (x+4)-6\Rightarrow x+4-6\Rightarrow x-2 \\ \text{and the result is multiplied by 2, which translates to} \\ (x-2)\cdot2\Rightarrow2x-4 \\ \text{the answer is 23 less than the sum of the first and twice of the second integers} \\ (x)+2(x+2)\rightarrow x+2x+4\rightarrow3x+4 \\ (3x+4)-23 \\ 3x-19 \\ \text{equate them both sides and we have} \\ 2x-4=3x-19,\text{ left hand is the first part, right hand is the second part} \\ \text{solve for }x \\ 2x-4=3x-19 \\ -4+19=3x-2x \\ 15=x \\ x=15 \\ \text{so the three odd integers are, } \\ x=15 \\ x+2=17 \\ x+4=19 \\ 15,17,19 \end{gathered}[/tex]

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