Answers
Answer:
a. The relation is a function because every input has an output.
Step-by-step explanation:
a relation in which for every input there is exactly one output (for every x there is just one y)
quizlet
Answer:
A. The relation is a function because every input has an input
Step-by-step explanation:
A relation is a function as long as there are not multiple outputs for one input. It's okay if there are multiple inputs for one output, like we can see here with points (-6, 1) and (2, 1).
Another way to test if a graphed relation is a function is the vertical line test. Draw vertical lines at multiple spots on the graph and if any of the vertical lines touches 2 points, the graphed relation is not a function.
:)
Related Questions
I need help with his practice problems from my ACT prep guidePlease show your work in steps
Answers
Answer:
[tex]-\sqrt[]{6}+1[/tex]Explanation:
Given the below expression;
[tex]\frac{\tan(-\frac{2\pi}{3})}{\sin(\frac{7\pi}{4})}-\sec (-\pi)[/tex]Recall that;
[tex]\begin{gathered} \sec x=\frac{1}{\cos x} \\ \sin x=\cos (\frac{\pi}{2}-x) \end{gathered}[/tex]So we can rewrite the expression as;
[tex]\begin{gathered} \frac{\tan(-\frac{2\pi}{3})}{\cos(\pi-\frac{7\pi}{4})}-\frac{1}{\cos(-\pi)} \\ \frac{\tan(-\frac{2\pi}{3})}{\cos(-\frac{5\pi}{4})}-\frac{1}{\cos(-\pi)} \end{gathered}[/tex]Also, recall that;
[tex]\begin{gathered} \cos (-x)=\cos x \\ \tan (-x)=-\tan x \end{gathered}[/tex]So we'll have;
[tex]\frac{-\tan (\frac{2\pi}{3})}{\cos (\frac{5\pi}{4})}-\frac{1}{\cos (\pi)}[/tex]From the Unit circle, we have that;
[tex]\begin{gathered} \cos \pi=-1 \\ \cos (\frac{5\pi}{4})=\frac{-\sqrt[]{2}}{2} \\ \tan (\frac{2\pi}{3})=-\sqrt[]{3} \end{gathered}[/tex]Substituting the above values into the expression and simplifying, we'll have;
[tex]\begin{gathered} \frac{-(-\sqrt[]{3})}{\frac{-\sqrt[]{2}}{2}}-\frac{1}{-1}=\frac{\sqrt[]{3}}{\frac{-\sqrt[]{2}}{2}}+1=-\frac{2\sqrt[]{3}\sqrt[]{2}}{\sqrt[]{2}\cdot\sqrt[]{2}}+1 \\ =-\sqrt[]{6}+1 \end{gathered}[/tex]the sum of three consecutive integers is 219. find The largest of the three integers.
Answers
Let n be the lesser number of the three. Therefore,
[tex]n+(n+1)+(n+2)=219[/tex]Solving for n,
[tex]\begin{gathered} \Rightarrow3n+3=219 \\ \Rightarrow3n=216 \\ \Rightarrow n=72 \end{gathered}[/tex]Then, the three numbers are 72, 73, and 74. The answer is 74
10. If you invest $2000 at 6% compounded monthly, how long will it take the account to double in
value?
Answers
If I invest $2000 at 6% interest compounded monthly, it will take 11.58 years by the account to double in value.
What is compound interest?
The practice of adding interest to the principal amount of a loan or deposit is known as compound interest, sometimes known as interest on principal and interest. It happens when interest is reinvested, added to the lent capital rather than paid out, or required to be paid by the borrower, resulting in interest being created the next period on the principal amount plus any accrued interest. Compound interest is a prominent concept in finance and economics.
The initial investment of $2000 at 6% compounded monthly.
Since, the interest rate of 6% is compounding monthly, then the effective annual interest rate will be
= (1+)−1i = (1+rm)m−1
Here, r = interest rate in decimals
= (1+0.0612)12−1i = (1+0.0612)12−1
= 0.061678i = 0.061678
= ×100 = 6.1678%
Now, we are using Rule 72 to calculate the doubling time
Time to double the initial amount = 72 /effective annual interest rate
Time to double the initial amount = 11.58 years
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Why is it important to
line up the digits in each place-value position when subtracting?
Answers
Answer: it’s important because when you do that it makes it easier to remember what’s not a whole number and what is
Step-by-step explanation: the answer is basically the explanation
Use the quadratic formula to solve for X 5x^2 +2x=2
Answers
Given:
[tex]5x^2+2x=2[/tex]To solve for x using the quadratic formula, we simplify the given equation first:
[tex]\begin{gathered} 5x^2+2x=2 \\ 5x^2+2x-2=0 \end{gathered}[/tex]Next, we use the quadratic formula of the form ax^2+bx+c=0:
[tex]x_{1,2}=\frac{-b\pm\sqrt[]{b^2-4ac}}{2a}[/tex]where:
a=5
b=2
c=-2
We plug in what we know:
[tex]\begin{gathered} x_{1,2}=\frac{-2\pm\sqrt[]{2^2^{}-4(5)(-2)}}{2(5)} \\ \text{Simplify} \\ x_{1,2}=\frac{-2\pm\sqrt[]{44}}{10} \\ x_{1,2}=\frac{-2\pm2\sqrt[]{11}}{10} \end{gathered}[/tex]We separate the solutions:
[tex]x_1=\frac{-2+2\sqrt[]{11}}{10}=\frac{-1+\sqrt[]{11}}{5}=0.46[/tex][tex]x_2=\frac{-2-2\sqrt[]{11}}{10}=-\frac{1+\sqrt[]{11}}{5}=-0.86[/tex]Therefore,
[tex]x=0.46,-0.86[/tex]Use the tangent to find the length of side PR. Express your answer to the nearest tenth. P 559 The length of side PR is approximately units.
Answers
tan (Q) = opposite/ adjacent
tan (55º) = PR/ 4.9
________________________
1.43 = PR/ 4.9
PR= 1.4* 4.9 = 6.9
Answer
6.9
______________________________________
Can you see the updates?
Do you have any questions regarding the solution?
____________________
PR= tan (55)* 4.9 = 6.997925 ≅ 7
_________________________________
Liz is collecting aluminum cans for a school fundraiser. So far, she has collected 16 cans, which is 20% of her goal. How many cans must she collect to reach her goal?Parts A & B
Answers
Given the word problem, we can deduce the following information:
1. Liz collected 16 cans, which is 20% of her goal.
To determine the number of cans that Liz needs to collect to reach her goal, we use below equation:
[tex]0.20x=16[/tex]where:
x= total number of cans that Liz needs to collect
So,
[tex]\begin{gathered} 0.20x=16 \\ \text{Simplify} \\ x=\frac{16}{0.20} \\ x=80 \end{gathered}[/tex]Hence, the total number of cans is 80.
A.
To complete the double number line, we must determine first the other percent values. It the goal is 100%, we must subtract 20% from 100% and divide it by 4 to get the remaining percent values. So,
[tex]\frac{100-20}{4}=20[/tex]So the other percent values are:
0%
20%
20%+20%=40%
40%+20%=60%
60%+20%=80%
80%+20%=100%
To determine the amount of cans for each percent value,the process is shown below:
[tex]80(\frac{40}{100})=32[/tex][tex]\begin{gathered} 80(.6)=48 \\ \end{gathered}[/tex][tex]80(.8)=64[/tex][tex]80(\frac{100}{100})=80[/tex]Therefore, the answer for double number line is:
Cans : 0 16 32 48 64 80
Percent : 0% 20% 40% 60% 80% 100%
B.
Based on the information gathered from A, for every 16 cans Liz collects, she adds 20% toward her goal. She will have 32 cans if she reaches 40% of her goal. Liz must collect 80 cans to reach her goal.
ABC with coordinates (1.3), B.4.5), and C15,2), what are the coordinates of ABC after the glide reflection described by t (-1,1) R y-axis?
Answers
Answer:
A'(0,4)
B'(-3,6)
C(-4,3)
Step-by-step explanation:
A glide reflection is the combination of a translation with a rotation.
In this question:
T(-1,1): This means that the translation is given by:
(x,y) -> (x-1,y+1)
Rotation: Around the y-axis. This means that:
(x,y) -> (-x,y)
The triangle has the following coordinates:
A(1,3), B(4,5), C(5,2)
Applying the translation:
(x,y) -> (x-1,y+1)
A(1,3) -> (1-1,3+1) = (0,4)
B(4,5) -> (4-1,5+1) = (3,6)
C(5,2) -> (5-1, 2+1) = (4,3)
Rotation over the y-axis:
(x,y)->(-x,y)
A'(0,4)
B'(-3,6)
C(-4,3)
Marco states that 7.696696669...... is a rational numberbecause it is a repeating decimal. Is he correct? Justifyyour answer.Yes he is correct because it keeps going and going and it will go on forever and ever so that is my guess
Answers
The answer is NO, Marco is wrong.
The number 7.696696669.... has not a repeating decimal there is no a number that is repeating, like 0.6969696969... in the last number the 69 is repeating, in the Marco's number the decimal number change every time.
What is the y intercept of this equation10x+5y=30Write answer in (x,y)
Answers
The y intercept of a straight line is the point on the y axis where the line cuts the y axis.
Given equation of lineis
[tex]10x+5y=30[/tex]Putting x=0 in the above equation, we have,
[tex]\begin{gathered} 5y=30 \\ y=6 \end{gathered}[/tex]So, the y intercept is
[tex](0,6)[/tex]A ball is thrown from an initial height of 4 feet with an initial upward velocity of 23 ft/s. The ball's height h (in feet) after 1 seconds is given by the following.h=4+231-167Find all values of 1 for which the ball's height is 12 feet.Round your answer(s) to the nearest hundredth.(If there is more than one answer, use the "or" button.)Please just provide the answer my last tutor lost connection abruptly.
Answers
Answer
t = 0.59 seconds or t = 0.85 seconds
Step-by-step explanation:
[tex]\begin{gathered} Given\text{ the following equation} \\ h=4+23t-16t^2\text{ } \\ h\text{ = 12 f}eet \\ 12=4+23t-16t^2 \\ \text{Collect the like terms} \\ 12-4=23t-16t^2 \\ 8=23t-16t^2 \\ 23t-16t^2\text{ = 8} \\ -16t^2\text{ + 23t - 8 = 0} \\ \text{ Using the general formula} \\ t\text{ }=\text{ }\frac{-b\pm\sqrt[]{b^2\text{ - 4ac}}}{2a} \\ \text{let a = -16, b = 23, c = -8} \\ t\text{ = }\frac{-23\pm\sqrt[]{(23)^2\text{ - 4}\cdot\text{ }}(-16)\text{ x (-8)}}{2(-16)} \\ t\text{ = }\frac{-23\pm\sqrt[]{529\text{ - 512}}}{-32} \\ t\text{ = }\frac{-23\pm\sqrt[]{17}}{-32} \\ \text{t = -23+}\frac{\sqrt[]{17}}{-32}\text{ or -23-}\frac{\sqrt[]{17}}{-32} \\ t\text{ = -23 }+\text{ 4.12/-32 or t = }\frac{-23\text{ - 4.12}}{-32} \\ t\text{ = }0.59\text{ seconds or t =0.85 seconds} \end{gathered}[/tex]Therefore, t = 0.59 seconds or t = 0.85 seconds
35* 35. Which of the following values for r suggests that one variable causes another? A. -0.7 B. O C. 0.9 D. None of the above
Answers
The correlation coefficient r indicates if two variables are or not dependent. If r is close to 1, then one variable causes the other one. From the options, a value of 0.9 suggests that one variable causes another
Find the length of arc CD. Use 3.14for tt. Round to the nearest tenth.h 7.9 cm66.40D[? ]cm
Answers
For this problem we know that the radius is 7.9cm and the angle between C and D is 66.4ª. We also want to find the arclenght so we can use the following formula:
[tex]AL=\frac{x}{360}\cdot2\pi r[/tex]Where x is the angle and r the radius r=7.9cm. So then replacing into the function we got:
[tex]AL=\frac{66.4}{360}\cdot2\pi(7.9cm)=9.16\operatorname{cm}[/tex]And if we round to the nearest tenth we got 9.2 cm
Find the radius of a circle in which a 24 cm chord is 4 cm closer to the center than a 16 cm chord. Round your answer to the nearest tenth.
Answers
The diagram representing the scenario is shown below
A represents the center of the circle. It divided each chord equally. Thus, we have CB = 16/2 = 8 for the shorter chord and DE = 24/2 = 12 for the longer chord
Assuming the distance between the
A
please help 40 points!!
Answers
Answer:
The midpoint is (-1,1)
Equation: y = -x -2
Step-by-step explanation:
Midpoint:
([tex]\frac{-5+3}{2}[/tex], [tex]\frac{-5 + 3 }{2}[/tex]) You are taking the averages of the x values and the y values.
([tex]\frac{-2}{2}[/tex],[tex]\frac{-2}{2}[/tex])
(-1,-1)
Equation:
The slope of the 2 points given is
[tex]\frac{3 - -5}{3- - 5}[/tex] = [tex]\frac{8}{8}[/tex] = 1 The slope is the change of y over the change in x. Points are given in the form (x,y) So, I subtracted the y values on top and the x values on the bottom of the fraction.
The equation that is created is perpendicular to the original line, so it slope is the negative reciprocal.
1 as a fraction is [tex]\frac{1}{1}[/tex]. negative reciprocal means turn the fraction upside down and take the opposite value. If I flip [tex]\frac{1}{1}[/tex] upside down, I get the same fraction which is equal to 1. Now I will take the opposite sign. Since it is positive, the new slope will be negative
slope -1
x = -1
y = -1
I am using the point that will be on the new line. This is the midpoint that we just found (-1,-1) I am going to plug in the number that I know and solve for b or the y=intercept.
y = mx + b
- 1 = -1(-1) + b
-1 = 1 + b Subtract 1 from both sides of the equation
-2 = b
y = mx + b
y = -1x -2
or
y = -x -2
find the product of 1/1728.
Answers
The answer is 12
Because 12x12x12 = 1728
What is the y-intercept of the line that passes through the point (4,-9) with a slope of -1/2
Answers
Answer:
The y-intercept b for the derived equation is;
[tex]b=-7[/tex]Explanation:
Given that the line passes through the point (4,-9) and has a slope of -1/2;
[tex]\begin{gathered} \text{slope m=-}\frac{1}{2} \\ \text{ point (4,-9)} \end{gathered}[/tex]Applying the point-slope form of linear equation;
[tex]y-y_1=m(x-x_1)[/tex]substituting the slope and the given point;
[tex]\begin{gathered} y-(-9)=-\frac{1}{2}(x-4) \\ y+9=-\frac{1}{2}x+\frac{4}{2} \\ y+9=-\frac{x}{2}+2 \\ y=-\frac{x}{2}+2-9 \\ y=-\frac{x}{2}-7 \end{gathered}[/tex]Comparing it to the slope intercept form of linear equation;
[tex]y=mx+b[/tex]where;
m = slope
and b = y-intercept
Therefore, the y-intercept b for the derived equation is;
[tex]b=-7[/tex]The two-way table shows the number of students that do or do not do chores at home and whether they receive an allowance or not. I Allowance No Allowance 13 3 Do Chores Do Not Do Chores 5 a. How many total students do chores? b. What is the relative frequency of students that do chores and get an allowance to the number of students that do chores? Round to the nearest hundredth if necessary. chores nor get an allowance to the total number of What is the relative frequency of students that do not students? Round to the nearest hundredth if necessary, d. Of those that do not do chores what percentage still receive an allowance?
Answers
a) do chores 13 + 3 = 16
answer: 16 students
b) this is
[tex]\frac{chores\text{ and allowance}}{\text{chores}}=\frac{13}{16}=0.8125[/tex]answer: 0.81
c) this is
[tex]\frac{\text{no chores and no allowance}}{total}=\frac{4}{25}=0.16[/tex]answer: 0.16
d) this is
[tex]\frac{no\text{ chores and allowance}}{no\text{ chores}}\times100=\frac{5}{9}\times100=\frac{500}{9}=55.55[/tex]answer: 55.55%
a bottle of juice is 2/3 full the bottle contains 4/5 cup of juice write division problem that represents the capacity of the bottle
Answers
Answer:
x = ( 6 / 5 )y
Step-by-step explanation:
Identify the equaiton.
let x = bottle;
let y = cups;
( 2 / 3 )x = ( 4 / 5 )y;
Multiply both sides by ( 3 / 2 ).
( 3 / 2 )( 2 / 3 )x = ( 3 / 2 )( 4 / 5 )y;
x = ( 12 / 10 )y;
Write the fraction in its simplest form.
x = ( 6 / 5 )y;
It takes 1 + ( 1 / 5 ) of a cup to fill the bottle.
Type the correct answer in each box. Use numerals instead of words.Consider the quadratic equation x2 + 10x + 27 = 0.Completing the square leads to the equivalent equation (x +__ )^2 = __
Answers
Given:
[tex]x^2+10x+27=0[/tex]Required:
To complete the square that leads to the equivalent equation (x +__ )^2 = __.
Explanation:
Consider
[tex]\begin{gathered} x^2+10x+27=0 \\ \\ x^2+10x+25+2=0 \\ \\ x^2+10x+25=-2 \\ \\ x^2+5x+5x+25=-2 \\ \\ x(x+5)+5(x+5)=-2 \\ \\ (x+5)(x+5)=-2 \\ \\ (x+5)^2=-2 \end{gathered}[/tex]Final Answer:
[tex](x+5)^{2}=-2[/tex]You roll a six-sided die twice. What is the probability of rolling an even number and then an odd number?A)1B)1/3 큼C)nilaD)
Answers
Let's begin by listing out the given information:
A fair dice has 6 sides
The dice has its sides numbered from 1-6
The number of sides with even numbers (2, 4 & 6) equals 3
The number of sides with odd numbers (1, 3 & 5) equals 3
The probability of rolling an even number is given as shown below:
[tex]\begin{gathered} P=\frac{Number\text{ of Possible Outcome}}{Total\text{ Number of Outcome}} \\ P\mleft(even\mright)=\frac{3}{6}=\frac{1}{2} \\ P(even)=\frac{1}{2} \end{gathered}[/tex]The probability of rolling an odd number is given as shown below:
[tex]\begin{gathered} P=\frac{Number\text{ of Possible Outcome}}{Total\text{ Number of Outcome}} \\ P(odd)=\frac{3}{6}=\frac{1}{2} \\ P(odd)=\frac{1}{2} \end{gathered}[/tex]The probability of rolling an even number followed by an odd number is obtained by the product of the probabilities above. We have:
[tex]\begin{gathered} P(even,odd)=P(even)\times P(odd) \\ P(even,odd)=\frac{1}{2}\times\frac{1}{2}=\frac{1}{4} \\ P(even,odd)=\frac{1}{4} \end{gathered}[/tex]Therefore, the probability of rolling an even number and then an odd number is 1/4
while eating your yummy pizza, you observe that the number of customers arriving to the pizza station follows a poisson distribution with a rate of 18 customers per hour. on average, how many customers arrive in each 10 minutes interval?
Answers
In every 10 minutes an average of 3 customers will arrive to the pizza station
Given,
The number of customers arriving to the pizza station follows a poisson distribution with a rate of 18 customers per hour.
We have to find the average number of customers arrives in each 10 minutes.
Here,
The chance that X represents the number of successes of a random variable in a Poisson distribution is provided by the following formula:
P (X = x) = (e^-μ × μ^x) / x!
Where,
The number of successes is x.
The Euler number is e = 2.71828.
μ is the average over the specified range.
Now,
Rate of 18 customers per hour;
μ = 18 n
n is the number of hours.
Number of customers arrive in each 10 minutes
10 minutes = 10/60 = 1/6
Then,
μ = 18 x 1/6 = 3
That is,
In every 10 minutes an average of 3 customers will arrive to the pizza station.
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To beA train started from City A to City B at 13:30. The train travelledat an average speed of 180 miles per hour. If the distancebetween City A and City B is 756 miles, at what time did thetrain arrive at City B? Give your answer in a 24-hour clockformat, such as 19:00. DEnter the answer
Answers
Remember that
the speed is equal to divide the distance by the time
speed=d/t
solve for t
t=d/speed
we have
d=756 miles
speed=180 miles per hour
substitute
t=756/180
t=4.2 hours
4.2 hours=4 hours +0.20 hours
Convert 0.20 hours to minutes
Multiply by 60
0.20 h=0.20*60=12 minutes
so
4.2 hours=4 h 12 min
therefore
A train started from City A to City B at 13:30.
13:30+ 4h 12 min=17:42 hrs
find the are and perimeter
Answers
L: Length
W: Width
The perimeter of a rectangle is:
[tex]P=2W+2L[/tex][tex]\begin{gathered} P=2(3ft)+2(5ft) \\ P=6ft+10ft \\ P=16ft \end{gathered}[/tex]The area of a rectangle is:
[tex]A=W\cdot L[/tex][tex]\begin{gathered} A=3ft\cdot5ft \\ A=15ft^2 \end{gathered}[/tex]an alloy contains copper and zinc in the ratio 3:7. find the mass of the metal in 750g of alloy
Answers
Given:
An alloy contains copper and zinc in a ratio of 3:7. The total mass of the alloy is 750g.
Required:
Find the mass of the metal in 750g of alloy.
Explanation:
Let the mass of the metal is x gm.
The weight of copper = 3x
The weight of zinc= 7x
Total weight
[tex]\begin{gathered} 3x+7x=750 \\ 10x=750 \\ x=\frac{750}{10} \\ x=75\text{ gm} \end{gathered}[/tex]
help meeeeeeeeee pleaseee !!!!!
Answers
The values for the composition of the functions are:
(f o g)(x) = 9x² + 5
(g o f)(x) = 3x² + 15
How to Evaluate the Composition of Functions?To evaluate the composition of a function, the first thing to do is to evaluate the inner function, then use the output as an input to evaluate the outer function of the composition.
Given the following functions:
f(x) = x² + 5
g(x) = 3x
We are required to find (f o g)(x) and (g o f)(x).
To find (f o g)(x), replace g(x) for x in the outer function f(x):
(f o g)(x) = (3x)² + 5
(f o g)(x) = 9x² + 5
To find (g o f)(x), replace f(x) for x in the outer function g(x):
(g o f)(x) = 3(x² + 5)
(g o f)(x) = 3x² + 15
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1. 9c-3c=48A) c=9B) c=3C) c=4D) C=8
Answers
To solve this equation, we need to subtract both, 9c - 3c:
[tex]9c\text{ - 3c = 6c = 48}[/tex]Dividing by 6 at both sides of the equation
[tex]\frac{6c}{c}\text{ = }\frac{48}{6}[/tex]Then
[tex]c\text{ = 8}[/tex]Then the answer C = 8. (Option D)
create a system of equations to represent this situation. be sure to explain the meaning of each variable. graph the system of equations. determine the break even point for Chuck E Cheese and Bright Child, Adventure Plex and Bright Child, Adventure Plex and Chuck E Cheese.
Answers
For them, let x = number of children of the party and
A=Adventure Plext cost
B= Bright Child cost
C= Chuck E Cheese cost
So,
[tex]\begin{gathered} A=300+12x \\ B=180+15x \\ C=18x \end{gathered}[/tex]Then, graphing each equation of the system of equations
Now, for determine the break even point for Chuck E Cheese and Bright Child you have
[tex]\begin{gathered} 180+15x=18x \\ 180=18x-15x \\ 180=3x \\ \frac{180}{3}=x \\ 60=x \end{gathered}[/tex]That is, the break even point for Chuck E Cheese and Bright Child occurs when x = 60 children.
For determine the break even point for Adventure Plex and Bright Child you have
[tex]\begin{gathered} 300+12x=180+15x \\ 300+12x-180=180+15x-180 \\ 120+12x=15x \\ 120+12x-12x=15x-12x \\ 120=3x \\ \frac{120}{3}=\frac{3x}{3} \\ 40=x \end{gathered}[/tex]That is, the break even point for Adventure Plex and Bright Child occurs when x = 40 children.
Finally, For determine the break even point for Adventure Plex y Chuck E Cheese you have
[tex]\begin{gathered} 300+12x=18x \\ 300+12x-12x=18x-12x \\ 300=6x \\ \frac{300}{6}=\frac{6x}{6} \\ 50=x \end{gathered}[/tex]That is, the break even point for Adventure Plex and Chuck E Cheese occurs when x = 50 children.
In the given figure ABC is a triangle inscribed in a circle with center O. E is the midpoint of arc BC . The diameter ED is drawn . Prove that
Answers
Answer:
we can use two ways to write 180° along with the inscribed angle theorem to obtain the desired relation
Step-by-step explanation:
Given ∆ABC inscribed in a circle O where E is the midpoint of arc BC and ED is a diameter, you want to prove ∠DEA = 1/2(∠B -∠C).
SetupWe can add add arcs to make 180° in two different ways, then equate the sums.
arc EB +arc BA +arc AD = 180°
arc EC +arc CA -arc AD = 180°
Equating these expressions for 180°, we have ...
arc EB +arc BA +arc AD = arc EC +arc CA -arc AD
SolutionRecognizing that arc EB = arc EC, we can subtract (arc EB +arc BA -arc AD) from both sides to get ...
2·arc AD = arc CA -arc BA
The inscribed angle theorem tells us ...
arc AD = 2∠DEAarc CA = 2∠Barc BA = 2∠CMaking these substitutions into the above equation, we have ...
4∠DEA = 2∠B -2∠C
Dividing by 4 gives the relation we're trying to prove:
∠DEA = 1/2(∠B -∠C)
An arts academy requires there to be 6 teachers for every 96 students and 3 tutors for every 30 students. How many students does the academy have per teacher? Per tutor? How many tutors does the academy need if it has 100 students?
Answers
If the school requieres 6 teachers for every 96 students then
1 teacher will be required for every
= 96/6
= 16 students
If 3 tutors for every 30 students then 1 tutor is required for
= 30/3
= 10 students
If the academy has 100 students, the number of tutors required would be
= 100/10
= 10 tutors
Hence
The academy requires;
