which statement is true?
Answers
This is the graph of the function
The answer is (8,0)
Related Questions
in a public opinion poll 624 people from a sample of 1100 indicated they would vote for specific candidate how many votes can the candidate expect to receive from a population of 40000
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Hello!
In a sample of 1100 people, the specific candidate got 624 votes. So, we can write it as 624/1100.
And if the total of voters is 40,000, how many votes this specific candidate will receive? We can write it as x/40,000.
Now, let's equal both fractions look:
[tex]\begin{gathered} \frac{624}{1100}=\frac{x}{40000} \\ \\ 1100x=624\times40000 \\ 1100x=24960000 \\ x=\frac{24960000}{1100} \\ \\ x\cong22691 \end{gathered}[/tex]Answer:Approximately 22691 votes.
1. Write a linear equation of the form y1 = mx + b for your first set of data.2. Write a linear equation of the form y2 = mx + b for the other equation in your system. 3. Graph and explain the solution.
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Given:
Company A: transport 56 people in one hour for $40 per person in 30 minutes
Company B:
The table shows a function. Is the function linear or nonlinear?x y0 1918 1200
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By plotting the points, we get a non-linear function
1. A train moves at a constant speed and travels 6 miles in 4 minutes. What is its speed in miles per minute? d/t = r time distance t d 4 mins. 6 miles
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Answer: 1.5 miles / minute
Given that:
Distance travelled = 6
Time = 4 minutes
Speed = Distance / time
Speed = 6 / 4
1.5 mile / minute
if A/B and C/D are rational expressions,then which of the following is true?*PHOTO*
Answers
In general,
[tex]\begin{gathered} \frac{w}{x}*\frac{y}{z}=\frac{w*y}{x*z} \\ x,z\ne0 \end{gathered}[/tex]Therefore, in our case, (Notice that since A/B and C/D are rational expressions, B and D cannot be equal to zero)
[tex]\frac{A}{B}*\frac{C}{D}=\frac{A*C}{B*D}[/tex]Notice that the left side of each option includes the term
[tex]\frac{A}{B}*\frac{D}{C}[/tex]However, we cannot assure that C is different than zero because it is only stated that C/D is rational.
Furthermore,
[tex]\frac{A}{B}*\frac{D}{C}=\frac{A*D}{B*C}[/tex]And (A*D)/(B*C) is not included among the options.
Therefore, the answer has to be option D as it is the only one that correctly expresses the multiplication of two fractions.Remember that there is a mistake in each option, the left side has to be A/B*D/CGiven the graph of f (x), determine the domain of f –1(x).
Radical function f of x that increases from the point negative 3 comma negative 2 and passes through the points 1 comma 0 and 6 comma 1
Answers
The domain of the function f(x) that has a range of [-2, ∞) is [-2, ∞)
What is the inverse of a function?The inverse of a function that maps x into y, maps y into x.
The given coordinates of the points on the radical function, f(x) are; (-3, -2), (1, 0), (6, 1)
To determine the domain of
[tex] {f}^{ - 1}( x)[/tex]
The graph of the inverse of a function is given by the reflection of the graph of the function across the line y = x
The reflection of the point (x, y) across the line y = x, gives the point (y, x)
The points on the graph of the inverse of the function, f(x), [tex] {f}^{ - 1} (x)[/tex] are therefore;
[tex]( - 3, \: - 2) \: \underrightarrow{R_{(y=x)}} \: ( - 2, \: - 3)[/tex]
[tex]( 1, \: 0) \: \underrightarrow{R_{(y=x)}} \: ( 0, \: 1)[/tex]
( 6, \: 1) \: \underrightarrow{R_{(y=x)}} \: ( 1, \: 6)
The coordinates of the points on the graph of the inverse of the function, f(x) are; (-2, -3), (1, 0), (1, 6)
Given that the coordinate of point (x, y) on the image of the inverse function is (y, x), and that the graph of the function, f(x) starts at the point (-3, -2) and is increasing to infinity, (∞, ∞), such that the range of y–values is [-2, ∞) the inverse function, [tex] {f}^{ - 1}( x)[/tex], which starts at the point (-2, -3) continues to infinity, has a domain that is the same as the range of f(x), which gives;
The domain of the inverse of the function, [tex] {f}^{ - 1}( x)[/tex], using interval notation is; [-2, ∞)
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I wondered if you could teach me how to do this so I can do these problems independently.
Answers
Answer
a)
A' (-2, 6)
B' (7, 3)
C' (4, 0)
b)
D' (3, 3)
E' (-5, 0)
F' (2, 2)
c)
G' (3, 1)
H' (0, 4)
P' (-2, -3)
Explanation
For the coordinate (x, y)
A transformation to the right adds that number of units to the x-coordinate.
A transformation to the left subtracts that number of units from the x-coordinate.
A transformation up adds that number of units to the y-coordinate.
A transformation down subtracts that number of units from the y-coordinate.
For this question,
a) The coordinates are translated to the right by 4 units and upwards by 1 unit
That is,
(x, y) = (x + 4, y + 1)
A (-6, 5) = A' (-6 + 4, 5 + 1) = A' (-2, 6)
B (3, 2) = B' (3 + 4, 2 + 1) = B' (7, 3)
C (0, -1) = C' (0 + 4, -1 + 1) = C' (4, 0)
When a given point with coordinates P (x, y) is reflected over the y-axis, the y-coordinate remains the same and the x-coordinate takes up a negative in front of it. That is, P (x, y) changes after being reflected across the y-axis in this way
P (x, y) = P' (-x, y)
For this question,
b) The coordinates are reflected over the y-axis
D (-3, 3) = D' (3, 3)
E (5, 0) = E' (-5, 0)
F (-2, 2) = F' (2, 2)
In transforming a point (x, y) by rotating it 90 degrees clockwise, the new coordinates are given as (y, -x). That is, we change the coordinates and then add minus to the x, which is now the y-coordinate.
P (x, y) = P' (y, -x)
For this question,
c) The coordinates are rotated about (0, 0) 90 degrees clockwise.
G (-1, 3) = G' (3, 1)
H (-4, 0) = H' (0, 4)
I (3, -2) = P' (-2, -3)
Hope this Helps!!!
What is the sign of when x > 0 and y < 0 ?
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The number line always goes from negative to positive :
It increases from left to right
SInce negative is always on the left side of the zero
Snumber greater than zero are always positive
i.e. x > o
the vertices of ABC and the endpoints of DE have coordinates that are integers. Determine the coordinates of point F so That ABC≈DEFOPTIONS:(-7, 1)(-5, 3)(-7, -8)(-2, -8)
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We want figure EDF≈ABC.
We can see that if we rotate figure ABC we will obtain the following:
If we rotate it we can see that the segment AB is exactly as the segment ED.
We can now find the answer if we look how far is the point C, we see it is three unities up from B and 5 unities to its left. Then F must be 3 unities up from E and 5 unities to its left.
Since E is located :
at y = -2 if we go up 3 unities
-2 + 3 = 1
at x = -2 if we go at its left 5 unities then
-2 - 5 = -7
Then, F must be at x = -7 and y = 1.
Answer: (-7, 1)Caitlyn is 160 centimeters tall. How tall is she in feet and inches, rounded to the nearest inch?
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Answer:
5 ft 3 in.
Explanation:
First, recall the standard conversion rates below.
• 1 foot = 30.48 cm
,• 1 foot = 12 inches
First, convert 160 cm to feet.
[tex]\begin{gathered} \frac{1ft}{30.48\operatorname{cm}}=\frac{x\text{ ft}}{160\text{ cm}} \\ 30.48x=160 \\ x=\frac{160}{30.48} \\ x=5.2493\text{ ft} \\ x=(5+0.2493)\text{ ft} \end{gathered}[/tex]Next, we convert the decimal part (0.2493 ft) of the result above to inches.
[tex]\begin{gathered} 1ft=12\text{ inches} \\ \frac{1\text{ ft}}{12\text{ inches}}=\frac{0.2493\text{ ft}}{y\text{ inches}} \\ y=0.2493\times12 \\ y=2.9916 \\ y\approx3\text{ inches (to the nearest inch)} \end{gathered}[/tex]Therefore, 160 centimeters in feet and inches is:
[tex]5\text{ feet 3 inches}[/tex]A student entering a doctoral program in educational psychology is required to select two courses from the list provided as part of his or her program (a)List all possible two-course selections (b)Comment on the likelihood that you EPR 625 and EPR 686 will be selected The course list EPR 613, EPR 664, EPR 625, EPR 685, EPR 686(a)select all the possible two-course selections belowA. 613, 686B. 625,686C. 613,613,664D. 664,685E. 625,685F. 625,672G. 613,625H. 685,686I. 664,625J 686,686K. 613,613L. 613,685M. 664, 686N. 613,664
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List of courses that the student entering a doctoral program in educational psychology can take:
EPR 613, EPR 664, EPR 625, EPR 685, EPR 686
Therefore, the possible two-course selections for the student are:
A. Both courses are on the list given: 613, 686
B. Both courses are on the list given: 625, 686
C. It's not possible. This option contains three courses.
D. Both courses are on the list given: 664, 685
E. Both courses are on the list given: 625, 685
F. It's not possible, Course 672 isn't available.
G. Both courses are on the list given: 613, 625
H. Both courses are on the list given: 685, 686
I. Both courses are on the list given: 664, 625
J. It's not possible. Just one course is given.
K. Same case than J. Just one course.
L. Both courses are on the list given: 613, 685
M. Both courses are on the list given: 664, 686
N. Both courses are on the list given: 613, 664
Transformations that preserve shape and size are called rigid motions. Find a definition of just the word rigid using the internet and write it below.
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Simply put,
Rigid means not moving.
In transformations, rigid motions are transformations that preserve distance.
Find the missing quantity with the information given. Round rates to the nearest whole percent and dollar amounts to the nearest cent% markdown = 40Reduced price = $144$ markdown = ?
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The given information:
% mark up = 40
Reduced = $144
Markdown = ?
The formula for percentage markup is given as
[tex]\text{ \%markup }=\frac{markup}{actual\text{ price}}\times100[/tex]Let the actual price be x
Hence,
Reduced price = 60% of actual price
[tex]60\text{\% of x = 144}[/tex]Solving for x
[tex]\begin{gathered} \frac{60x}{100}=144 \\ x=\frac{144\times100}{60} \\ x=240 \end{gathered}[/tex]Therefore, actual price = $240
Inserting these values into the %markup formula gives
[tex]40=\frac{\text{markup}}{240}\times100[/tex]Solve for markup
[tex]\begin{gathered} 40=\frac{100\times\text{markup}}{240} \\ 40\times240=100\times\text{markup} \\ \text{markup}=\frac{40\times240}{100} \\ \text{markup}=96 \end{gathered}[/tex]Threefore, markup = $96
If TRAP is an isosceles trapezoid, what is the value of x?A. 1B. 22C. 12D. 23E. 11F. Cannot be determined
Answers
In an Isosceles trapezoid, it is known that the base angles have equal measures, and non-congruent angles are supplementary.
The non-congruent angles ∠RAP and ∠APTfrom the figure have measures 6x° and (2x+4)°, respectively.
Since they must be supplementary, it follows that their sum is 180°:
[tex]\begin{gathered} 6x+2x+4=180 \\ \Rightarrow8x+4=180\Rightarrow8x=180-4 \\ \Rightarrow8x=176\Rightarrow\frac{8x}{8}=\frac{176}{8} \\ \Rightarrow x=22 \end{gathered}[/tex]Hence, the value of x is 22. The correct option is B.
Answer:B
Step-by-step explanation:just took the test
Find the mean: 16,12,15,10,7,916
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You can calculate the mean by using the formula:
Mean=sum of values/number of values
Then,
[tex]undefined[/tex]Find the sum of the first 39 terms of the following series, to the nearest integer.2,7, 12,...
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The sequence 2,7,12,... given is an arithmetic progression. This is because it has a common difference.
Given:
first term, a = 2
common difference, d = second term - first term = 7 - 2 = 5
d = 5
n = 38
The sum of an arithmetic progression is given by;
[tex]\begin{gathered} S_n=\frac{n}{2}\lbrack2a+(n-1)d\rbrack \\ S_{38}=\frac{38}{2}\lbrack2(2)+(38-1)5\rbrack \\ S_{38}=19\lbrack4+37(5)\rbrack \\ S_{38}=19\lbrack4+185\rbrack \\ S_{38}=19(189) \\ S_{38}=3591 \end{gathered}[/tex]Therefore, the sum of the first 39 terms of the series is 3,591
Gary is saving money to buy a ticket to a New York Jets game that costs $225. Healready has saved $18. What is the least amount of money Gary must save each week, sothat at the end of 9 weeks he has enough money to buy the ticket? (Only an algebraic- solution will be accepted.)
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lillyvong13, this is the solution:
Cost of the ticket to a New York Jets game = $ 225
Savings up to now = $ 18
Difference = 225-18 = 207
Number of weeks = 9
Let x to represent the amount of money Gary must save each week for buying the ticket, as follows:
x = 207/9
x = 23
Gary must save $ 23 at the end of 9 weeks to have enough money to buy the ticket
how much must be deposited at the beginning of every six months in account that pays 6% compounded semi-annually so that account will contain 21,000 at the end of three years
Answers
The formula for Final Amount, A after compounding for n period of times is given by
[tex]A=p(1+\frac{r}{100})^n[/tex]Where A = amount
p= principal
r = rate (in %)
n = number of compounding periods
From the question.
A=21,000, p = ?, r=6, n = 3 x 2 = 6
[tex]\begin{gathered} 21000=p(1+\frac{6}{100})6 \\ \\ 21000=p(1+0.06)^6 \\ 21000=p(1.06)6 \\ 21000=p(1.41852) \\ 21000=1.41852p \\ p=\frac{21000}{1.41852} \\ p=14,804.17 \end{gathered}[/tex]The amount that must be deposited at the beginning is 14,804.17
0.75 greater than 1/2
Answers
True
0.75 is greater than 0.5
Explanation
Step 1
remember
[tex]\frac{a}{b}=\text{ a divided by b}[/tex]then
[tex]\frac{1}{2}=\text{ 1 divided by 2 = 0.5}[/tex]Step 2
compare
0.75 and 0.5
[tex]0.75\text{ is greater than 0.5}[/tex]I hope this helps you
FOR GREATER THAN WE ADD THE TERMS.
MATHEMATICALLY THIS MEANS
[tex] = 0.75 + \frac{1}{2} \\ = 0.75 + 0.5 \\ = 1.25[/tex]
1.25 is the answer.
How many different committees can be formed from 12 teachers and 32 students if the committee consists of 3 teachers and 2 students?
Answers
Answer: 4 committees
Step-by-step explanation:
12 divided by 3 = 4 (this equation represents the teachers)
2 x 4 = 8 (this equation represents the students)
There can only be 4 committees because there are only 12 teachers. There are some students that will not be in a committee. 24 students will be committee-less to be exact.
kenny has red marbles, 3 blue marbles,and 4 black marbes. Which ration compares a part to the whole? Please help me
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A ratio comparing a part to the whole must then have 9 as the second number.
In this question, we have been given Kenny has red marbles, 3 blue marbles, and 4 black marbles.
We need to find the ratio that compares a part to the whole.
Here, the total number of marbles are:
2 red + 3 blue + 4 black = 9 marbles.
Let x be either number of marbles (either red marbles or blue marbles or black marbles)
Then the ratio that compares a part to the whole would be,
x : 9
Therefore, a ratio comparing a part to the whole must then have 9 as the second number.
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You choose a marble from the bag. What is the probability you will NOT choose blue?1/25/72/72
Answers
Given a sample and required to get the probability of a particular outcome, we make a couple of considerations including:
- Sample Space: The universal set
- Required Outcome
We can identify these variables as:
Sample space: total number of marbles = 7
Required outcome: Not blue = 7 - 2 = 5
Probability is given as:
[tex]\begin{gathered} P=\text{ }\frac{\text{number of required outcome}}{Sample\text{ space}}=\frac{5}{7} \\ P=\frac{5}{7} \end{gathered}[/tex]Z A I + 5 4x - 3 3r-1 2x + 1 What value of x makes ASTW - AXYZ? s 3 + 1 T 4r-5 x = 2 X = 3 X=4 X=1
Answers
Here, we have two congruent triangles.
Given:
ST = 3x - 1 XY = 4x - 5
SW = 3x + 1 XZ = 4x - 3
TW = 2x + 1 YZ = x + 5
Since triangle STW and triangle XYZ are congruent, they have exactly the same corresponding sides.
To find the value of x, equate the corresponding sides and evaluate.
ST = XY
SW = XZ
TW = YZ
Take one of the corresponding sides.
We have:
ST = XY
3x - 1 = 4x - 5
Subtract 4x from both sides:
3x - 4x - 1 = 4x - 4x - 5
-x - 1 = -5
Add 1 to both sides:
-x - 1 + 1 = -5 + 1
-x = -4
Divide both sides by -1:
[tex]\begin{gathered} \frac{-x}{-1}=\frac{-4}{-1} \\ \\ x=4 \end{gathered}[/tex]Therefore, the value of x that makes ΔSTW ≅ ΔXYZ is 4
ANSWER:
x = 4
the inside diameter (I.D.) and outside diameter (O.D.) of a pope are shown in the figure. The wall thickness of the pope is the dimension labeled t. Calculate the wall thickness of the pipe if its I.D. is 0.599 in. and its O.D. is 1.315 in.
Answers
Given:
The inside diameter of the pope, I.D.=0.599 in.
The outside diameter of the pope, O.D.=1.315 in.
The inside radius of the pope is,
[tex]IR=\frac{ID}{2}=\frac{0.599}{2}=0.2995\text{ in}[/tex]The outside radius of the pope is,
[tex]OR=\frac{OD}{2}=\frac{1.315}{2}=0.6575\text{ in}[/tex]The wall thickness of the pope can be calculated as,
[tex]t=OR-IR=0.6575-0.2995=0.358\text{ in}[/tex]Therefore, the wall thickness of the pope is t=0.358 in.
determine the point and slope that were used to write each linear equation in point slope form
Answers
The slope-point form is:
[tex]y-y_0=m(x-x_0)[/tex]where (x0,y0) is a point in the line and m is the slope.
A) If the equation is written in slope-point form, we have:
[tex]y-0=2(x-5)[/tex]Then, the point is (5,0) and the slope is m=2.
Answer: Point = (5,0)
Slope = 2
B)
[tex]\begin{gathered} y+3=5x \\ y-(-3)=5(x-0) \end{gathered}[/tex]Answer: Point (0,-3)
Slope = 5
sjsvsjsowbdjdbsosbwybwiw
Answers
Given 4 h + 6 = 30
4 h = 30 - 6
4 h = 24
Divide both sides by 4, we have:
h = 24 /4
h = 6
5|x +1| + 7 = 38
Solve for x
Answers
Answer: No solutions
Step-by-step explanation:
[tex]5|x+1|+7=-38\\\\5|x+1|=-45\\\\|x+1|=-9[/tex]
However, as absolute value is non-negative, there are no solutions.
Solve radical∛x²-8=4
Answers
Let's determine the value of x on the given radical expression:
[tex]\text{ }\sqrt[3]{x^2-8}\text{ = 4}[/tex]Over which interval(s) is the function decreasing?A) -4 < x < 3B) -0.5 < x < ∞C) -∞ < x < -0.5D) -∞ < x < -4
Answers
In the interval where the function is decreasingcreasing, the input or x values increase as the output or y values decrease. Looking at the graph, moving from the left to the right, the values of x are increasing whie the values of y are decreasing. This trend continued till we got to x = 0.5. Thus, in the interval from negative infinity to x = - 0.5, the function was decreasing.
The correct option is C
Segment AC has a midpoint B. If AB = 2x - x - 42 andBCI_x+11x +21, find the length of Ac.
Answers
The equation for the segment AB is;
[tex]2x^2-x-42[/tex]The equation for the segment BC is ;
[tex]x^2+11x+21[/tex]If segment AC has midpoint at B , this means ;
AC = AB + BC
To get AC we add the equation for AB and BC
Performing addition as;
[tex]2x^2-x-42+x^2+11x+21[/tex]Collect like terms as;
[tex]2x^2+x^2+11x-x-42+21=AC[/tex][tex]3x^2+10x-21=AC[/tex]Answer
[tex]AC=3x^2+10x-21[/tex]
