Who PLAYS Apex Legend?

Answer:

Wireless technology.

Explanation:

In earlier years, the broadcasting of information or any video or audio type was done "over-the-air". This means that sharing or the distribution of any content was done "wireless", through the use of transmitters that are wireless or requires no physical connecting wires.

Wireless technological form of broadcasting became the original form of distributing media, be it entertainment, news or information, etc. This 'over-the-air' broadcasting was then replaced by the cabled-wires transmission later on.

The technology through which Television broadcasts were originally delivered was through:

According to the given question, we are asked to state the technology through which Television broadcasts were originally delivered

As a result of this, we can see that in the earlier years, there was the use of wireless technology to relay the transmissions of information through radio waves or short waves and did not require any physical connection of wires.

'Read more about Wireless technology here:

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Answer:

Here is the program:

#include <iostream>  //to use input output functions

#include <string>  // to use functions to manipulate strings

using namespace std;  //to identify objects cin cout

void function(string prefix, unsigned int levels){  // function that takes two parameters, a string, using the string class and levels an unsigned integer

   if (levels == 0) {  //if number of levels is equal to 0

       cout << prefix << endl;  //displays the value of prefix

       return;    }  

  for (int i = 1; i <=9 ; i++){  //iterates 1 through 9 times

       string sections = (levels == 1 ? "" : ".");  //if the number of levels is equal to 1 then empty space in sections variable otherwise stores a dot

       string output = prefix +  std::to_string(i) + sections;   // displays the string prefix followed by the section numbers. Here to_string is used to convert integer to string

       function(output, levels - 1);   } }   //calls function by passing the resultant string and levels-1  recursively to print the string prefix followed by section numbers

int main() {  // start of main function

   int level = 2;  //determines the number of levels

   function("BOX", level);  } //calls function by passing the string prefix and level value

Explanation:

The program has a function named function() that takes two parameters, prefix (a string, using the string class from ) and levels (an unsigned integer). The function prints the string prefix followed by "section numbers" of the form 1.1., 1.2., 1.3., and so on. The levels argument determines how many levels the section numbers have. If the value of levels is 0 means there is 0 level then the value of prefix is printed. The for loop iterates '1' through '9' times for number of digits in each level. If the number of levels is 1 then space is printed otherwise a dot is printed. The function() calls itself recursively to print the prefix string followed by section numbers.

Let us suppose that prefix = "BOX" and level = 1

If level = 1 then the loop for (int i = 1; i <=9 ; i++) works as follows:

At first iteration:

i = 1

i <=9 is true because value of i is 1

string sections = (levels == 1 ? "" : "."); this statement checks if the levels is equal to 1. It is true so empty space is stored in sections variable so,

sections = ""

Next, string output = prefix +  std::to_string(i) + sections; statement has prefix i.e BOX plus value of i which is 1 and this int value is converted to string by to_string() method plus sections has an empty space. So this statement becomes

string output = BOX + 1  

So this concatenates BOX with 1 hence output becomes:

output = BOX1

At second iteration:

i = 2

i <=9 is true because value of i is 2

string sections = (levels == 1 ? "" : "."); is true so

sections = ""

Next, string output = prefix +  std::to_string(i) + sections; statement becomes

string output = BOX + 2  

So this concatenates BOX with 1 hence output becomes:

output = BOX2

At third iteration:

i = 3

i <=9 is true because value of i is 3

string sections = (levels == 1 ? "" : "."); is true so

sections = ""

Next, string output = prefix +  std::to_string(i) + sections; statement becomes

string output = BOX + 3  

So this concatenates BOX with 1 hence output becomes:

output = BOX3

Now at each iteration the prefix string BOX is concatenated and printed along with the value of i. So at last iteration:

At last iteration:

i = 9

i ==9 is true because value of i is 9

string sections = (levels == 1 ? "" : "."); is true so

sections = ""

Next, string output = prefix +  std::to_string(i) + sections; statement becomes

string output = BOX + 9  

So this concatenates BOX with 1 hence output becomes:

output = BOX9

After this the loop breaks at i = 10 because the condition i<=9 becomes false. So the output of the entire program is:

BOX1                                                                                                                                          BOX2                                                                                                                                          BOX3                                                                                                                                          BOX4                                                                                                                                          BOX5                                                                                                                                          BOX6                                                                                                                                          BOX7                                                                                                                                          BOX8                                                                                                                                          BOX9  

The program along with the output is attached.

Answer:

network adapter

Explanation:

took the test

Answer:

If this is a Mac, it's a common problem and there isn't anything to fix it because it's just like that. I reccomend unplugging the computer and NOT signing off. Because of that, that may be why it is the problem for you. I do not know about Windows Computers, but this is some info that applies with all computers.

Explanation:

Answer:

this is what the battery on your motherboard is for. Also as long as you are connected to wifi, then it will sync your computer time with the current timezone you are in.

Explanation:

Which element is located on the top left of the Word screen? Quick Access toolbar

Which key combination will move the user to the beginning of the document? Ctrl+Home

A user can easily move to the end of a document by pressing the _____ key combination. Ctrl+End

Answer:

The answer is A-a computer that provides special service to client computers on demand.

Explanation:

Edge 2020

A computer that provides special services to client computers on demand is best describes a server. Hence, option A is correct.

A computer program or appliance that serves a remote server and its user, also known as the client, is referenced to as a server. The actual computer that a server program runs on in a data centre is also frequently referred to as a server.

Any server, network computer, software, or device that handles client requests, see client-server architecture. For instance, a Web server on the World Wide Web is a computer that utilizes the HTTP protocol to transfer Web pages to a client's computer in response to a client request.

Data is sent, received, and stored by a server. It basically serves another purpose and is there to offer services. One or more services may be offered via a server, which can be a computer, software application, or even a storage device.

Thus, option A is correct.

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Answer:

Vertical justifying

Explanation:

Answer:

Written in Python

word = input("Word: ")

if(word[0]=='a' or word[0]=='e' or word[0]=='i' or word[0] =='o' or word[0]=='u'):

     print(word+"ay")

else:

     a = word[1:]

     print(a+word[0]+"ay")

Explanation:

The program was written in Python and I've added the explanation as an attachment; where I used comments as explanations

Answer:

A procedure for solving a problem in terms of the actions to be executed and the order in which to execute those actions is known as a(n).

They can be used in multiple places.

They save a programmer time since they are reusable.

They can contribute to excessive use of a computer’s resources.

:)

Students can perform several tasks in a digital environment. For example, they can watch instructional videos, take notes, and participate in peer discussions.

A digital classroom is a study space that has been electronically improved and allows students to use the internet and web-based applications to improve their learning.

A digital classroom is one that improves student learning by utilizing computers, tablets, the internet, and instructional software.

The digital classroom can be a supplement to the physical classroom, offering more chances for study and cooperation.

A digital classroom is a learning environment that has been enhanced electronically so that students can access the internet and web-based tools to enhance their learning.

The following tasks could be carried out in such a setting:

Thus, a digital classroom's capabilities give students the resources they need for easier, more seamless learning.

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#SPJ6

Answer:

A. declines in labor productivity

Explanation:

Answer:

B. Format

Explanation:

You must have selected a picture in order the tab Format to be available. You should click the picture that you want to change the brightness for and u under Picture Tools, on the Format tab, in the Adjust group, click Corrections. And the correct option is the Format tab.

Answer the adjustment layers can not be used a lot?

Explanation: i think that was it

Answer:

Initial settings can not be modified, only layer opacity.

Explanation:

Answer:

The explaination of this question is given below in the explanation section

Explanation:

The following steps are used to create a workbook.

1- Go to start menu and search about EXCEL (application software) and then click on it to open.

If you already opened a EXCEL's workbook, and you want to create a new workbook, then you follow the following steps:

A new workbook will be created.

Answer:

The people of the thriving community has a more encouraging life than becoming a town or community of laziness and the fact that people will not help each other. When a community of people know one another they know the at that moment that everyone can get along, but when health comes as a problem, people's attitude toward each other change rapidly in a bad way, then the neighboring families become rivals, and people will not help others when it is most needed, and at that point, life in that area is a internal civil war.

Answer:

actual_value = float(input("Enter the actual value of a piece of property: "))

tax_rate = float(input("Enter the current tax rate for each $100.00 of assessed value: "))

assessed_value = actual_value * 0.6

tax = (assessed_value * tax_rate) / 100

print("The annual property tax is $" + str(tax))

Explanation:

*The code is in Python.

Ask the user to enter the actual value and the tax rate

Calculate the assessed value, multiply the actual value by 0.6

Calculate the tax, multiply the assessed value by the tax rate and divide result by 100

Print the tax

Answer:

Word art

Explanation:

its copy and paste

Answer:

Graph

Explanation:

I took the quiz it is the right answer.

Answer:

-Select one of the headings.

-Open the Styles dialog box.

Explanation:

edge 2020

Answer:

Man above me is right listen to him

Explanation:

CTRL+SHIFT+W

Have a nice day :}

Answer:

The marco command is available on the VIEW tab.  

Your welcome!!!

Answer:

Science. Science is where you learn about the worlds enviroment.

Book. A Book is a object that has words in it that you can read. It has sometimes thick pages or thin pages.

Answer:

automatically moves the text to the next line if necessary

Answer:

automatically moves text to the next line when necessary

Answer:

Written using C++

/*Enter Your Details Here*/

#include<iostream>

#include<cmath>

using namespace std;

int main()

{

//1

float side;

cout<<"Enter the side of a square: ";

//2

cin>>side;

//3

float perimeter = 4 * side;

cout<<"The perimeter is "<<perimeter<<endl;

//4

float area = side *side;

cout<<"The area is "<<area<<endl;

//5

float diagonal = sqrt(2 * side * side);

cout<<"The length of the diagonal is "<<diagonal;

return 0;

}

Explanation:

I've added the full source code as an attachment where I used more comments to explain difficult line

Answer:

typing on a keyboard (input) makes letter appear on a screen (output)is removing that

In this exercise we have to be able to explain the difference between output and input used in computers, like this:

So the output allows some information to appear on the screen while the input is a string.

In this way we will define some characteristics of each one as:

Input, means: Contribute, Input, Insert and etc. In the case of Output, its meaning is: Output, Production, Power, Send.

See more about input or output at brainly.com/question/408477

Answer:

First off, I'm not writing your essay. I will give you a guide and you can take it from there. Also, I don't know any context about the question.

Answer:

import java.util.Scanner;

public class TestAveGrade

{

public static void main(String[] args) {

 Scanner scanner = new Scanner( System.in );

       double userScore1, userScore2, userScore3, userScore4, userScore5;

       System.out.print ("Enter test grade for student1:");

       userScore1 = scanner.nextDouble();

       System.out.print ("Enter test grade for student2:");

       userScore2 = scanner.nextDouble();

       System.out.print ("Enter test grade for student3:");

       userScore3 = scanner.nextDouble();

       System.out.print ("Enter test grade for student4:");

       userScore4 = scanner.nextDouble();

       System.out.print ("Enter test grade for student5:");

       userScore5 = scanner.nextDouble();

       System.out.println("The letter grades are as follows:");

       System.out.println("Student-1: " + determineGrade(userScore1));

       System.out.println("Student-2: " + determineGrade(userScore2));

       System.out.println("Student-3: " + determineGrade(userScore3));

       System.out.println("Student-4: " + determineGrade(userScore4));

       System.out.println("Student-5: " + determineGrade(userScore5));

       System.out.printf("The average grade was: %.2f", calcAverage (userScore1, userScore2, userScore3, userScore4, userScore5));

}

public static double calcAverage(double userScore1, double userScore2, double userScore3, double userScore4, double userScore5){

       double average;

       average = (userScore1 +userScore2 +userScore3 +userScore4 +userScore5) /5;

       return average;

   }

   public static String determineGrade(double testScore){

       String letterGrade = " ";

       if (testScore < 60){

           letterGrade = "F";

       }

       else if (testScore <70) {

           letterGrade = "D";

       }

       else if (testScore <80) {

           letterGrade = "C";

       }

       else if (testScore <90) {

           letterGrade = "B";

       }

       else if (testScore <100) {

           letterGrade = "A";

       }

       return letterGrade;

   }

}

Explanation:

Hi, I modified your code. Your methods work but you need to update the main.

Ask the user to enter five grades and store the values in different variables

Call the determineGrade method passing each grade as a parameter

Call the calcAverage method passing all the grades as parameter

Answer:

Here is the program:

#include <stdio.h>  //to use input output functions

#include <unistd.h> //provides access to the POSIX OS API

int main() { //start of main function

   int x;  //declare an int type variable x

   x = 100;  // sets the value of x to 100

   int r = fork();  //calls fork() method to create a new process. r is used to store the value returned by fork()

   if(r<0){  //if fork() returns -1 this means no child process is created

           fprintf(stderr, "Error");}     //prints the error message using standard error stream

  else if (r == 0)     {  //if fork returns 0 this means child process is created

       printf("This is child process\n");  //prints this message

       x = 150;  //changes value of x to 150

       printf("Value of x in child process: %d\n", x);     }  //prints the new value of x in child process

   else      {

       printf("This is parent process\n");  //if r>0

       x = 200;  //changes value of x to 200

       printf("Value of x in parent process: %d\n", x);     }  } //prints the new value of x in parent process

Explanation:

The program is well explained in the comments added to each line of the code. The answers to the rest of the questions are as follows:

What value is the variable in the child process?

The variable x is set to 150 in child process. So the printf() statement displays 150 on the screen.

What happens to the variable when both the child and parent change the value of x?

fork() creates a copy of parent process. The child and parent processes have their own private address space. Therefore none of the both processes cannot interfere in each other's memory. The both maintain their own copy of variables. So, when parent process prints the value 200 and child process prints the value 150.

In order to see which is the final value of x, lets write a statement outside all of the if else statements:

  printf("Final value of x: %d\n", x);

This line is displayed after the value of parent class i.e. 200 is printed on the screen and it shows:

Final value of x: 200

Note this is the value of x in parent process

However the same line displayed after the value of child class i.e. 150 is printed on the screen and it shows:

Final value of x: 150

The screenshot of the program along with the output is attached.

In this exercise we have to use the knowledge of computational language in C code to describe a code, like this:

The code can be found in the attached image.

To make it easier the code can be found below as:

#include <stdio.h>

#include <unistd.h>

int main() {

  int x;

  x = 100;

  int r = fork();

  if(r<0){  

          fprintf(stderr, "Error");}  

 else if (r == 0)     {

      printf("This is child process\n");

      x = 150;

      printf("Value of x in child process: %d\n", x);     }

  else      {

      printf("This is parent process\n");

      x = 200;  

      printf("Value of x in parent process: %d\n", x);     }  }

See more about C code at brainly.com/question/25870717

Answer:

Follows are the solution to this question:  

Explanation:

In the previous algorithm has also been fine yet un optimal and also gives O(n^2) computation time, that is is very powerful. It is a proposed algorithm, that has been arriving because its method has also been defined, its sorting provides the O( nlogn), which is much better than the last time complexity.  

When did I consider repeat figures, it is another aspect to note at the same figures arise as figures are ordered, for instance, the number is 1, 2, 1, 3, 2, 1, 3.  It becomes such as these number once sorted  1 , 1 , 1, 2 , 2 , 3 , 3.  

The smaller number 1, that's also 3 times combined in the second-largest amount, which is 2 times, but instead number 3, that's 2 times together consequently, with one pass in series, they can conveniently check the amount of duplicate.

It is a particular characteristic that appears 2 or more times, so it gets the same increases and amount for multiple copies when it sorted, and search for a specific transaction if it is equal with the original weeks.  If there is indeed a problem we have an amount more than 2 times for the same amount we need additional iterations.  

Therefore, the second 1 method fits it's very first 1 and its increase in multiple copies, however, the third 1 is the same for the second 1, so the amount of double for step 1 was already increased again so the same number also has an element following.  To remove this problem, a hashmap keeps track as a number, which crossed 1 time must be initialized the algorithm and doesn't search for amount again.

The algorithm functions as follows:  

1.initialize a hashmap which defaults to 0.  

2.Now sorted array with the second position element.  

3.Check if the element hashmap value is 0 as well as the previous variable has the same value.  

4. Increase the number of multiple copies and fill out hazmap element to 1 if both conditions and AND conditions become valid.  

5. if  the element and move to the next item if the state of AND is wrong.  

6. go to 3 and take the same steps to the end of the array.

Answer:

The answer to this question is given below in the explanation section. However, the correct answer is: student should practice netiquette in an online course when they are participating in online discussion board.

Explanation:

It is important for you as a student to recognize that the online classroom is in fact a classroom, and certain behaviors are expected when you communicate with both your peers and your instructors. These guidelines for online behavior and interaction are known as “netiquette”.

So, the correct option of this question is: students should practice netiquette in an online course when they are participating in an online discussion board. Because the discussion board is opened by the instructor/tutor, he constantly looking for student behavior throughout the discussion. so, students should use netiquette practice during the discussion in the online class.

However, other options are not correct because, in these options, there is not the presence of teacher/instructor. And, also noted that netiquette is practiced in online class by the student.  

Answer:

B, D, E

Explanation:

ed2020