With what minimum speed must athlete leave the ground in order to lift his center of mass 2.00 m and cross the bar with a speed of 0.95 m/s

Answer:

1J

Explanation:

Work done = force × distance

1 × 1 = 1

Work done = 1J

J = Joules

Thermal equilibrium is attained and the both rods are now at the same temperature.

Two bodies are said to have attained thermal equilibrium when the two bodies at the same temperature. It should be known that when two rods are firmly attached to each other heat flows from one rod to another.

As such, after some time, thermal equilibrium is attained and the both rods are now at the same temperature.

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Answer:

A

Explanation:

Because A looks like it's in the 10,700 degree area and also in the 23 luminosity area.

Answer:

it contains Einsteins opinion

Answer:

Answer is D

Explanation:

<3

A magnetic force is the answer

The number of revolutions the wheel will make in 14 s is 97.5 revolutions.

The angular speed of the wheel is the rate of change of angular displacement with time.

ω = v/r

where

ω = 14/0.32

ω = 43.75 rad/s

Ф = ωt

Ф = 43.75 rad/s  x 14s

Ф = 612.5 rad

N = (612.5 rad) / (2π)

N = 97.5 revolutions

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Awesome to see a chainsaw man fan! Here's your answer!

Answer:
Follow:

Explanation:

Facts  - Key Details Given:

P.E = mgh

P.E = (2)(9.8)(20)

P.E= 392 J

K.E = ¹/₂mv²

where;

v is velocity of the rock at the top of the cliff = 0

K.E = ¹/₂(2)(0)²

K.E = 0

P.E = mg(¹/₂h)

P.E = (2)(9.8)(¹/₂ x 20)

P.E = 196 J

K.E = ¹/₂mv²

where;

v is velocity of the rock at the halfway point = 14 m/s

K.E = ¹/₂(2)(14)²

K.E = 196 J.

Answer:

600 J

Explanation:

The formula to find the kinetic energy of an object is [tex]\frac{1}{2}mV^2[/tex]

Now, let's plug in the variables we're given and simplify.

Thus, the answer is 600 Joules.

[tex] \qquad \huge \underline{ \boxed{\sf Answer}}[/tex]

Here's the correct choices for the blank questions~

# 1 : position - time graph

#2 : Displacement - time graph

#3 : Motion graphs

#4 : Ticker tape diagram

#5 : Wave

#6 : Amplitude

#7 : Frequency

The answers to the questions are as follows :

Position time graphs are motion graphs that show the change in an object position in relation to time traveled, while a displacement time graph shows if an object is going backwards or forward and unlike distance, she does not consider the direction of movement of an object.

Motion graphs are used for the presentation of the motion of objects visually.

Hence we can conclude that the answers to your questions are as listed above.

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#SPJ5

Answer:

It is in a line parallel with the wire.

Explanation:

trust me

Answer:

b on edge

Explanation:

yes

Answer: Yes it is possible.

Explanation: The reason is being because, people tend to like to see different stuff. Like in the movie Pocahontas she was a totally different person. And John Smith was a different person too. SO it is possible.

Answer:

∠ABD = 100°

∠CBD = x

we have to find the value of x .

Since ∠ABD & ∠CBD formed on straight line.

Then Sum of ∠ABD & ∠CBD is 180° ( by linear pair)

[tex] \dashrightarrow\sf \: 100 {}^{ \circ} + x \: = 180 {}^{ \circ} \\ \\ \dashrightarrow\sf \:x \: = 180 {}^{ \circ} - 100 {}^{ \circ} \\ \\ \dashrightarrow\sf \:x \: = 80 {}^{ \circ} [/tex]

So, the value of x is 80° .

♧ Supplementary angles add up to 180 degrees

x + 100 = 180

x = 180 - 100

Hope it helps ~

Answer:

Yes

Explanation:

You included all the stages of matter and described each of them. You're outlining their properties and you've created a clear diagram (and by diagram I mean chart) of solids, liquids, and gas.

Answer:-2.86*10⁻⁴

Explanation: Use the equation change in volume = (change in pressure * original volume) / Bulks Modulus. ΔV = (-Δp*V₀) / B

Plugging in your numbers, you should get ΔV = (-2.29*10⁷*1) / (8*10¹⁰) = -2.86*10⁻⁴

ΔP = P₂-P₁  ----> ΔP = 2.30*10⁷ - 1.00*10⁵ = 2.29*10⁷

Answer: because when you remove the battery, the the magnet no longer has electricity flowing through it, therefore the magnetic field disappears. Thats why its called a temporary magnet

Explanation:

Explanation:

Answer:

could you tell me what the question is pls, that way I can help you

Explanation:

Based on the mass and luminosity of the Sun, the time required to convert of its original hydrogen into helium is 7.505 × 10^10 years.

Nuclear fusion is the process whereby nucleus of lighter atoms are fused together to produce heavier atoms with the release of large amounts of energy.

Nuclear fusion occurs at the core of the sun where four hydrogen atoms are fused to form one helium atom with the release considerable energy, and this is known as hydrogen fusion.

The mass of the Sun = 2.0 × 10^30 kg

The Sun’s hydrogen mass is 0.71 × 2.0 × 10^30 kg = 1.42 × 10^30 kg.

The Sun converts 6 × 10^11 kg of hydrogen into helium per second.

Time required to convert all of the Sun's hydrogen to helium = 1.42 × 10^30 kg/6 × 10^11 kg/s

Time required = 2.367 × 10^18 seconds

Converting to years:

3.154 × 10^7 seconds = 1 year

2.367 × 10^18 seconds = 2.367 × 10^18 seconds * 1 year/3.154 × 10^7 seconds

Time required = 7.505 × 10^8 years

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Answer:

the answer is C. rocket 4.

Explanation:

[tex]a = \frac{f}{m} \\ \\ c) a = \frac{120}{3.25} = 36.923...[/tex]

it's the biggest amongst the four.

rocket one has an acceleration of 34.782...

rocket two has an acceleration of 22.429...

rocket three has an acceleration of 26.666...

rocket four has an acceleration of 36.923

Answer:

the gravitational potential energy is converted to kinetic energy

Explanation:

Because the conversation of the energy as a tool permits the calculation of the velocity just before it hits the surface

Answer:

We are given the trajectory of a projectile:

y=H+xtan(θ)−g2u2x2(1+tan2(θ)),

where H is the initial height, g is the (positive) gravitational constant and u is the initial speed. Since we are looking for the maximum range we set y=0 (i.e. the projectile is on the ground). If we let L=u2/g, then

H+xtan(θ)−12Lx2(1+tan2(θ))=0

Differentiate both sides with respect to θ.

dxdθtan(θ)+xsec2(θ)−[1Lxdxdθ(1+tan2(θ))+12Lx2(2tan(θ)sec2(θ))]=0

Solving for dxdθ yields

dxdθ=xsec2(θ)[xLtan(θ)−1]tan(θ)−xL(1+tan2(θ))

This derivative is 0 when tan(θ)=Lx and hence this corresponds to a critical number θ for the range of the projectile. We should now show that the x value it corresponds to is a maximum, but I'll just assume that's the case. It pretty obvious in the setting of the problem. Finally, we replace tan(θ) with Lx in the second equation from the top and solve for x.

H+L−12Lx2−L2=0.

This leads immediately to x=L2+2LH−−−−−−−−√. The angle θ can now be found easily.

The cross-sectional area of the lead bar is [tex]9.188 \times 10^{-4} \ m^2[/tex].

The Young's modulus (E)of lead bar is given as 1.6 x 10¹⁰ Pa.

The cross-sectional area of the bar is calculated as follows;

[tex]E = \frac{stress}{strain} = \frac{F/A}{e/l} = \frac{Fl}{Ae} \\\\A = \frac{Fl}{Ee}[/tex]

where;

[tex]A = \frac{(mg) l}{Ee} \\\\A = \frac{(10^3 \times 9.8) \times 3}{1.6 \times 10^{10} \times 2 \times 10^{-3}} \\\\A = 9.188 \times 10^{-4} \ m^2[/tex]

Thus, the cross-sectional area of the lead bar is [tex]9.188 \times 10^{-4} \ m^2[/tex].

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Vector multiplied by constant (scalar number),the new vector

becomes k |a|. If k> 0, the same direction, k <0, the opposite direction

If we multiply vector A by 2 then the length becomes 2 times vector A and in the same direction

first point (-1,1)

end point after multiplied: 2(-1,1) ⇒(-2,2)

I think that mechanism is called a "lens turret".

We can see from the calculations that the acceleration of the proton is 1.43 * 10^7 ms-2.

Acceleration is the rate of change of velocity with time. We know that the magnetic force is obtained by;

F = qvB

q= 1.6 * 10^-19 C

v = 365 m/s

B =  4.10*10^-5 T

F = 1.6 * 10^-19 C * 365 m/s *  4.10*10^-5 T

F = 2.39 * 10^-20 N

Recall that the mass of the proton is 1.67 × 10−27 kg hence

a = F/m = 2.39 * 10^-20 N/1.67 × 10−27 kg  = 1.43 * 10^7 ms-2

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Explanation:

Explanation:

If an object having initial velocity

uExplanation:

If an object having initial velocity

u

is applied an acceleration of

a

for

t

time, its final velocity

v

is given by

v

=

u

+

a

t

and distance covered

S

is given by

S

=

u

t

+

1

2

a

t

2

.

We have

u

=

o

(as the object starts from rest),

t

=

5

sec., and acceleration

a

=

−

1.5

m

sec

2

.

Hence final velocity

v

=

−

1.5

×

5

=

−

7.5

m

sec

.

Distance covered

S

=

1

2

×

(

−

1.5

)

×

5

2

=

−

18.75

m

.

Minus sign indicates that acceleration is in reverse direction.

is applied an acceleration of

a

for

t

time, its final velocity

v

is given by

v

=

u

+

a

t

and distance covered

S

is given by

S

=

u

t

+

1

2

a

t

2

.

We have

u

=

o

(as the object starts from rest),

t

=

5

sec., and acceleration

a

=

−

1.5

m

sec

2

.

Hence final velocity

v

=

−

1.5

×

5

=

−

7.5

m

sec

.

Distance covered

S

=

1

2

×

(

−

1.5

)

×

If an object having initial velocity

u

is applied an acceleration of

a

for

t

time, its final velocity

v

is given by

v

=

u

+

a

t

and distance covered

S

is given by

S

=

u

t

+

1

2

a

t

2

.

We have

u

=

o

(as the object starts from rest),

t

=

5

sec., and acceleration

a

=

−

1.5

m

sec

2

.

Hence final velocity

v

=

−

1.5

×

5

=

−

7.5

m

sec

.

Distance covered

S

=

1

2

×

(

−

1.5

)

×

5

2

=

−

18.75

m

.

Minus sign indicates that acceleration is in reverse direction

5

2

=

−

18.75

m

.

Minus sign indicates that acceleration is in reverse direction.

Answer:

density of liquid x = 2000kg/m3

Explanation:

mass of water = mass of bottle with water - mass of bottle

mass of water = 4g - 2g

mass of water = 2g

mass of liquid x = mass of bottle with liquid x - mass of bottle

mass of liquid x = 6g - 2g

mass of liquid x = 4g

since the mass of liquid x is double the mass of the water and the volume of the bottle is the same, the density is doubled

density of liquid x = 1000kg/m3 • 2

density of liquid x = 2000kg/m3