Work out the area of ABCD.
А,
B
38%
10 cm
55°
D
44°
Give your answer to 1 decimal place.
Answers
Answer: 45.1
Step-by-step explanation:
The area of the figure is about 45 square cm.
What is a triangle?A triangle is a polygon with 3 sides.
Given the quadrilateral ABCD.
The sum of the interior angles of a triangle is 180°, therefore,
44° + 38° + m∠C = 180°
m∠C = 180° - 44° - 38°
m∠C = 98°
Now, using the sine law in triangle BDC, it follows:
sin44°/ BC = sin98°/10
BC = (10·sin44°)/ sin98°
BC ≈ 7
The area of a triangle is half the product of its two sides and the sine of the included angle, therefore, the area of triangle BDC is:
A₁ = (1/2)× 10×7× sin38°
A₁ = 21.5
Now, in triangle ABD,
cos55° = AD/10
AD = 10 cos55°
Similarly,
sin55° = AB/10
AB = 10sin 55°
Hence, the area of the triangle ABD is:
A₂ = (1/2) × (10 cos55°) ×(10sin 55°)
A₂ = 23.5
Therefore, the total area of the figure is:
A = A₁ + A₂
A = 21.5 + 23.5
A = 45.0
Hence, the area of the figure is about 45 square cm.
Learn more about triangles here:
https://brainly.com/question/2773823
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Answers:
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======================================
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---------------------------------------
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Answers
[tex] 99.12[/tex] is the answer.
Step-by-step Explanation:
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Steps-
0.5 lies to the lie of the mean value.
→ 0.93 - 0.5 = 0.43 lies to the right of the mean.
Now find the corresponding "z" value for 0.43
It is 1.48.
Use this value to determine the requix value.
You have to use the formula -
[tex]z = x - μσ[/tex]
Solve it for [tex]x[/tex]:-
[tex]x = z \times σ + μ[/tex]
Where;
[tex]x = ? \\ z = 1.48 \\ σ = 0.62 \\ μ = 98.20[/tex]
Now put these values in the
formula;
[tex]x = (1.48 \times 0.62) + 98.20[/tex]
[tex] = > 0.9176+98.20[/tex]
[tex] = > 99.1176[/tex]
[tex] = > 99.12[/tex]
Hence, the temperature that separates
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Answer:
The temperature that separates the top 7% with the bottom 93% is 99.12 degrees.
Step-by-step explanation:
The z-score that corresponds to 93% is about 1.48(x - 98.2) / 0.62 = 1.48
x - 98.2 = 0.9176
x = 99.12 degrees
