Answer:
5.4 × 10^-11
Step-by-step explanation:
Find the volume of a cone. Round your answer to the nearest wholenumber.7 ft4 ft
Answer:
117 cubic feet
Explanation:
From the diagram:
• The radius of the cone, r = 4 ft
,• The perpendicular height, h = 7 ft
[tex]\text{Volume of a cone=}\frac{1}{3}\pi r^2h[/tex]Substitute the given values:
[tex]\begin{gathered} V=\frac{1}{3}\times\pi\times4^2\times7 \\ =117.2ft^3 \\ \approx117\; ft^3 \end{gathered}[/tex]The volume of a cone is 117 cubic feet (to the nearest whole number).
Find the absolute maximum and minimum values of the following function on the given interval. f(x)=3x−6cos(x), [−π,π]
Answer:
Absolute minimum: x = -π / 6
Absolute maximum: x = π
Explanation:
The candidates for the absolute maximum and minimum are the endpoints and the critical points of the function.
First, we evaluate the function at the endpoints.
At x = -π, we have
[tex]f(-\pi)=3(-\pi)-6\cos (-\pi)[/tex][tex]\Rightarrow\boxed{f(-\pi)\approx-3.425}[/tex]At x = π, we have
[tex]f(\pi)=3(\pi)-6\cos (\pi)[/tex][tex]\Rightarrow\boxed{f(\pi)\approx15.425.}[/tex]Next, we find the critical points and evaluate the function at them.
The critical points = are points where the first derivative of the function are zero.
Taking the first derivative of the function gives
[tex]\frac{df(x)}{dx}=\frac{d}{dx}\lbrack3x-6\cos (x)\rbrack[/tex][tex]\Rightarrow\frac{df(x)}{dx}=3+6\sin (x)[/tex]Now the critical points are where df(x)/dx =0; therefore, we solve
[tex]3+6\sin (x)=0[/tex]solving for x gives
[tex]\begin{gathered} \sin (x)=-\frac{1}{2} \\ x=\sin ^{-1}(-\frac{1}{2}) \end{gathered}[/tex][tex]x=-\frac{\pi}{6},\; x=-\frac{5\pi}{6}[/tex]
on the interval [−π,π].
Now, we evaluate the function at the critical points.
At x = -π/ 6, we have
[tex]f(-\frac{\pi}{6})=3(-\frac{\pi}{6})-6\cos (-\frac{\pi}{6})[/tex][tex]\boxed{f(-\frac{\pi}{6})\approx-6.77.}[/tex]At x = -5π/6, we have
[tex]f(\frac{-5\pi}{6})=3(-\frac{5\pi}{6})-6\cos (-\frac{5\pi}{6})[/tex][tex]\Rightarrow\boxed{f(-\frac{5\pi}{6})\approx-2.66}[/tex]Hence, our candidates for absolute extrema are
[tex]\begin{gathered} f(-\pi)\approx-3.425 \\ f(\pi)\approx15.425 \\ f(-\frac{\pi}{6})\approx-6.77 \\ f(-\frac{5\pi}{6})\approx-2.66 \end{gathered}[/tex]Looking at the above we see that the absolute maximum occurs at x = π and the absolute minimum x = -π/6.
Hence,
Absolute maximum: x = π
Absolute minimum: x = -π / 6
Use the trapezoidal approximation to estimate he distance the turtle traveled from 0 to 10 seconds.
we have that
The trapezoidal approximation is equal to
[tex]A=\frac{1}{2}\cdot\lbrack f(a)+f(b)\lbrack\cdot(b-a)[/tex]where
a=0
b=10
f(a)=f(0)=0.05
f(b)=f(10)=0.043
substitute given values
[tex]\begin{gathered} A=\frac{1}{2}\cdot\lbrack0.05+0.043\lbrack\cdot(10-0) \\ A=0.465\text{ m} \end{gathered}[/tex]therefore
the answer is 0.465 meters15. The new county park is one mile square. What would be the length of a road around its boundaries?
In this case, we'll have to carry out several steps to find the solution.
Step 01:
Data:
County park:
area = 1 mile²
Step 02:
length of a road around:
area = side²
1 mile ² = s²
[tex]\begin{gathered} s^2=1 \\ s=\sqrt[]{1}=\text{ 1 } \end{gathered}[/tex]s = 1 mile
perimeter = 4 s = 4 * 1 mile = 4 miles
The answer is:
the length of a road around its boundaries is 4 miles
A bag contains 8 red marbles, 2 blue marbles, 5 white marbles, and 7 black marbles. What is the probability of randomly selecting:A white marble:A red marble:A red marble, white or blue marble: A black marble: A green marble:
How to solve 11 3/7 × 7/10 =
Given:
The objective is to solve the given equation.
The given equation can be solved by,
[tex]\begin{gathered} =11(\frac{3}{7})\cdot\frac{7}{10} \\ =\frac{11\cdot3}{10} \\ =\frac{33}{10} \\ =3.3 \end{gathered}[/tex]Hence, the value of the equation is 3.3
solve for y. 2x-y=12
Answer:
2x - 12 = y
Step-by-step explanation:
→ Add y to both sides
2x = 12 + y
→ Minus 12 from both sides
2x - 12 = y
Can you please help me out with a question
S = 2(a*b + a*c + b*c)
= 2 (12*15 + 12*6 + 15*6)
= 2 (342)
= 684 ft^2
Use the point-slope formula to write an equation of the line that passes through (- 1, 4) and (1, 5 ) .Write the answer in slope-intercept form (if possible).The equation of the line is Hi everyone, this is very hard for me I have tried 18 times by myself before I found you folks .I need this in the simplest terms as i don't get it if it is too involved .
To solve this problem, we will compute the slope of the line and then we will use it to find the equation of the line.
To determine the slope of a line that passes through points (x₁,y₁), and (x₂,y₂), we can use the following formula:
[tex]m=\frac{y_2-y_1}{x_2-x_1}.[/tex]Substituting
[tex]\begin{gathered} (x_2,y_2)=(-1,4), \\ (x_1,y_1)=(1,5), \end{gathered}[/tex]in the above formula, we get:
[tex]s=\frac{4-5}{-1-1}=\frac{-1}{-2}=\frac{1}{2}.[/tex]Now, with the above slope, we use the following formula for the equation of a line with slope m:
[tex]y-y_1=m(x-x_1).[/tex]Finally, we substitute one of the points:
[tex]y-5=\frac{1}{2}(x-1)[/tex]and take the equation to its slope-intercept form:
[tex]\begin{gathered} y-5=\frac{1}{2}(x-1), \\ y-5=\frac{1}{2}x-\frac{1}{2}, \\ y=\frac{1}{2}x+\frac{9}{2}. \end{gathered}[/tex]Answer: [tex]y=\frac{1}{2}x+\frac{9}{2}=0.5x+4.5.[/tex]What is the value of the expression below when w = 3?5W^2 – 5W – 8
According to the given data we have the following expression:
5W^2 – 5W – 8
In order to calculate the value of the expression above when w=3 we would need to substitute the w with 3 and then calculate the expression.
So, if w=3 then:
5(3)^2 -5(3) -8
=45 - 15 -8
=22
The value of 5W^2 – 5W – 8 when w = 3 would be 22
NO LINKS!! Show all work where necessary to get full credit Part 2
21. Circle R
A circle is named using its center.22. RV
A radius connects the center to a point on the circle.23. ZV
A chord connects two points on the circle.24. TX
A diameter passes through the center of the circle and connects two points on the circle.25. RV
See 22 and 24.26. 4 feet
The diameter is twice the radius, 2(2)=4.Answer:
21. R
22. RU
23. VZ
24. BE
25. RU
26. 4 feet
Step-by-step explanation:
Question 21
A circle is named by its center.
Therefore the name of the given circle is R.
Question 22
The radius of a circle is a straight line segment from the center to the circumference.
Therefore, the radii of the given circle are:
RZ, RT, RU, RV, RW and RX.Question 23
A chord is a straight line segment joining two points on the circumference of the circle.
Therefore, the chords of the given circle are:
WZ, TX and VZ.Question 24
The diameter of a circle is the width of the circle at its widest part. It is a straight line segment that passes through the center of the circle and whose endpoints lie on the circumference.
Therefore, the diameters of the given circle are:
TX and WZ.Question 25
As the diameters are TX and WZ, they contain the radii RZ, RT, RW and RX.
Therefore, the radii that are not contained in the diameter is:
RU and RV.Question 26
The diameter is twice the length of the radius.
Therefore, if the radius of the circle is 2 feet:
⇒ Diameter = 2 × 2 = 4 feet.
help meeeeeeeeee pleaseee !!!!!
For the two given functions, the compositions are:
(f o g)(x) = √(2x + 3)(g o f)(x) = 2*√x + 3How to find the two compositions?
Here we have two functions:
f(x) = √x
g(x) = 2x + 3
Now we want to get the compositions:
(f o g)(x) = f( g(x))
So here we just need to evaluate f(x) in g(x), we will get:
(f o g)(x) = √g(x) = √(2x + 3)
The other composition is:
(g o f)(x) = g(f(x)) = 2*f(x) + 3 = 2*√x + 3
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hello can you help me with this question and this a homework assignment
Problem
Solution
For this case we can use the Cosine law and we have:
[tex]\cos (c)=\frac{a^2+b^2-c^2}{2ab}=\frac{35^2+56^2-33^2}{2\cdot35\cdot56}=0.8346938776[/tex][tex]\cos (b)=\frac{a^2+c^2-b^2}{2ac}=\frac{35^2+33^2-56^2}{2\cdot35\cdot33}=-0.356[/tex][tex]\cos (a)=\frac{c^2+b^2-a^2}{2cb}=\frac{33^2+56^2-35^2}{2\cdot33\cdot56}=0.8116883117[/tex]And then we can find the angles with the arcos like this:
[tex]<\gamma=ar\cos (0.8346938776)=33.42[/tex][tex]<\beta=ar\cos (-0.356)=110.85[/tex][tex]<\alpha=ar\cos (0.8116883117)=35.74[/tex]Can you see the new values for gamma and alfa
Convert decimal to 0.147 to fraction ( the last digit 7 repeating)
Answer:
133/900
Explanation:
To convert the decimal 0.147777 to a fraction, we first identify the decimal part, so we have 147 as a decimal part.
Then, we subtract 14 because that part is not repeating. So:
147 - 14 = 133
Now, we need to divide by 9 to get the repeating part, but the repeating part starts at the third decimal place, so we will divide by 900 instead of 9.
Therefore, 0.147777... as a decimal is:
[tex]0.14777\ldots=\frac{133}{900}[/tex]So, the answer is 133/900
Find the slope of the line that passes through (8, 7) and (6, 2).
[tex]m = \frac{y2 - y1}{x2 - x1} \\ m = \frac{2 - 7}{6 - 8} \\ m = \frac{ - 5}{ - 2} \\ m = \frac{5}{2} [/tex]
ATTACHED IS THE SOLUTION WITH THE FORMULA TO CALCULATE THE SLOPE BETWEEN POINTS.
Find the equation for the horizontal line passing through the point (-6,-6).
SOLUTION
We are trying to get the equation for the horizontal line passing through the point (-6,-6).
( x1 , y 1 ) = ( 0, 0 )
( x2 , y2 ) = ( -6 , -6 )
Gradient, m = ( y2 - y1 ) / ( x2 - x1 )
m = ( -6 -0 ) / ( -6 - 0 )
m = -6 / - 6
m = 1
Then, using the equation of a line;
y - y 1 = m ( x - x 1 )
y - 0 = 1 ( x - 0 )
y = x
Vincent turned his head 30° to the side. Which of the following shows the angle that he turned his head?
Given data:
Vincent turned his head 30° to the side.
The figure in the option b is the angle that he turned his head.
PLEASE HELP I JUST NEED TO KNOW THE POINTS AND HOW THE GRAPH LOOKS LIKE
You have the following function:
[tex]g(x)=2x^2-4x-16[/tex]the x coordinate of the vertex is given by:
[tex]x=-\frac{b}{2a}[/tex]in this case, a = 2 and b = -4. Replace these values into the previous expression and simplify:
[tex]x=-\frac{-4}{2(2)}=1[/tex]next, replace the previous values of x into the function g(x):
[tex]\begin{gathered} g(1)=2(1)^2-4(1)-16 \\ g(1)=-18 \end{gathered}[/tex]then, the vertex is (1,-18)
In order to graph, calculate another point for any value of x, for instance, for x = 0:
g(0) = 2(0)^2 - 4(0) - 16
which methods correctly solve for the variable x in the equation 2/5m = 8?
Ok, so the equation is (2/5)m=8
1st option: Divide by 2 on both sides, then multiply by 5 on both sides:
[tex]\begin{gathered} \frac{2}{10}m=4 \\ \frac{10}{10}m=20 \\ m=20 \end{gathered}[/tex]2nd option: Multiply both sides by 5/2
[tex]\begin{gathered} \frac{2}{5}\cdot\frac{5}{2}m=8\cdot\frac{5}{2} \\ m=20 \end{gathered}[/tex]3rd option: First dristibute 2/5 to (m=8), the multiply by 5/2 in both sides
[tex]\begin{gathered} \frac{2}{5}m=8 \\ \frac{5}{2}\cdot\frac{2}{5}m=8\cdot\frac{5}{2} \\ m=20 \end{gathered}[/tex]4th option: Divide both sides by 2/5:
[tex]\begin{gathered} \frac{\frac{2}{5}}{\frac{2}{5}}m=8\cdot\frac{5}{2} \\ m=20 \end{gathered}[/tex]5th option: First, multiply by 5. Then, divide by 2.
[tex]\begin{gathered} 5\cdot\frac{2}{5}m=40 \\ 2m/2=40/2 \\ m=20 \\ \end{gathered}[/tex]All the methods are correct
DATA ANALYSIS AND STATISTICS Outcomes and event probability A number cube is rolled three times. An outcome is represented by a string of the sort OEE (meaning an odd number on the first roll, an even number on the second roll, and an even number on the third roll). The 8 outcomes are listed in the table below. Note that each outcome has the same probability. For each of the three events in the table, check the outcome(s) that are contained in the event. Then, in the last column, enter the probability of the event. Event A: An odd number on each of the last two rolls Event B: An even number on the last roll Event C: An even number on the last roll or the second roll (or both) Explanation Check 000 0 0 OOE EEE O Outcomes OEO 0 0 EOO EEO EOE OEE 0 0 Probability 0 0 0 00 음 0/5 X Nikida V Españe
Event A:
The event A occurs when an odd number is rolled in the second roll and in the third roll. We can see in the table that the outcomes that correspond with this event are:
OOO
EOO
Now to calculate the probability, we need to divide the number of favorable outcomes by the number of total outcomes. There are 8 possible outcomes, and the favorable outcomes for event A are 2. Thus:
[tex]P(A)=\frac{2}{8}=\frac{1}{4}[/tex]Event B:
In event B we want the last roll to be even. Then, the outcomes corresponding to this event are:
OOE
EEE
EOE
OEE
The number of favorable outcomes is 4, the total outcome is 4:
[tex]P(B)=\frac{4}{8}=\frac{1}{2}[/tex]Event C:
Here, we are looking for outcomes with an even number in the second or last roll (or both). Thus the outcomes that satisfy this are:
OOE
EEE
OEO
EEO
EOE
OEE
The number of favorable outcomes is 6, and the number of total outcomes is 8:
[tex]P(C)=\frac{6}{8}=\frac{3}{4}[/tex]Write the following number in standard decimal form.five and seventy-nine hundredths
five and seventy-nine hundredths = 5.79
Set up the system of equations:The cost of 4 bananas and 6 pears is $1.68. Nine bananas and 2 pears cost $1.48. Set up thesystem of equations to find the cost of each banana and pear.4B + 6P = 1.689B - 2P = 1.484B + 6P + 1.689B + 2P + 1.484B + 6P = 1.689B + 2P = 1484B = 6P + 1.689B = 2P + 148
Solution:
Let b represent the cost of 1 banana
Let p represent the cost of 1 pear
From the first statement, The cost of 4 bananas and 6 pears is $1.68
4b + 6p = 1.68 ----------------------------equation (1)
From the second statement, Nine bananas and 2 pears cost $1.48
9b + 2p = 1.48 -----------------------------equation (2)
Solve both equations simultaneously
4b + 6p = 1.68 ----------------------------equation (1)
9b + 2p = 1.48 -----------------------------equation (2)
Multiply equation (2) by 3 to eliminate p
27b + 6p = 4.44
4b + 6p = 1.68
Subtract both equatuions above
23b = 2.76
b = 2.76/23
b= 0.12
Substitute b = 0.12 into equation (1)
9b + 2p = 1.48
9(0.12) + 2p = 1.48
1.08 + 2p = 1.48
2p = 1.48 - 1.08
2p = 0.4
p = 0.4/2
p = 0.2
Hence, the cost of each banana is $0.12 while the cost of each pear is $0.2
Translate to an algebraic expression Twice "a"The translation is ...
Okay, here we have this:
Considering that twice an amount generally indicates taking two of the things in question; generally this indicates multiplying by 2.
This mean that if we have "twice a" when transferring it to an algebraic expression we obtain: 2a.
the table below shows the attendance and revenue at theme parks in the us
Let
y ------> the year
x ----> revenue
so
Plot the given ordered pairs
see the attached figure
(please wait a minute to plot the points)
In the graph the x-coordinate 0 represent year 1990
Find out the equation of the line
take two points
(1990, 5.7) and (2006, 11.5)
Find the slope m
m=(11.5-5.7)/(2006-1990)
m=5.8/16
m=0.3625
Find the equation of the line in slope intercept form
y=mx+b
we have
m=0.3625
point (1990, 5.7)
substitute and solve for b
5.7=(0.3625)(1990)+b
b=-715.675
therefore
y=0.3625x-715.675Look at the first Model It. In the first place-value chart, why is the thousandths column for the decimal 5.67 empty?
The thousandths column for the decimal 5.67 is empty because there's no thousandth value in the decimal.
What is a place value?Place value is the value provided by a digit in a number based on its place in the number. For example, 7 hundreds or 700 is the place value of 7 in 3,743. Place value is the value provided by a digit in a number based on its place in the number.
In this case, the decimal that's given is illustrated as 5.67. It should be noted that 6 is the tenths value and 7 is the hundredth value. Therefore, there is no thousandth value. This is why it's empty.
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The function c = 100+.30m represents the cost c (in dollars) of renting a car afterdriving m miles.How many miles would a customer have to drive for the cost to be $149.50?
149.5 = 100 + .30m
149.5 - 100 = .30m
49.5 = .30m
Divide both sides by 0.30
m = 49.5/0.3
m =165
Option D
If an item is discounted 30% then what percent of the original price is the sale price? if the organal price of the item is $500 what is the dollar amount of the discount?how much is the sale price ?
a.) Discount = 30%
Percent of the original price on sale = 100% - 30% = 70%
b.) Original price = $500
Discount = 30%
Dollar amount of the discount = $500 x (30% / 100%) = $500 x 0.30 = $150
c.) The sale price = $500 - (Discount Amount) = $500 - $150 = $350
How to solve problem 31? Solve for x y and z using ratios
The Solution:
Given:
Required:
Find the values for x, y, and z.
By the Similarity Theorem:
[tex]\Delta BAD\cong\Delta CBD[/tex]So,
[tex]\begin{gathered} \frac{x}{36}=\frac{36}{6x} \\ \\ \frac{x}{36}=\frac{6}{x} \end{gathered}[/tex]Cross multiply:
[tex]\begin{gathered} x^2=36\times6 \\ \\ x=\sqrt{36\times6}=6\sqrt{6} \end{gathered}[/tex]Find y by applying the Pythagorean Theorem on the right triangle CBD:
[tex]\begin{gathered} y^2=36^2+(6\sqrt{6)}^2 \\ \\ y=6\sqrt{42} \end{gathered}[/tex]Find z:
By the Pythagorean Theorem:
[tex]\begin{gathered} z^2=(42\sqrt{6})^2-(6\sqrt{42})^2 \\ \\ z=36\sqrt{7} \end{gathered}[/tex]Answer:
[tex]\begin{gathered} x=6\sqrt{6} \\ \\ y=6\sqrt{42} \\ \\ z=36\sqrt{7} \end{gathered}[/tex]Type a counter example that would have to exist in order for the conclusion to be false.5>0,6> 0.12 > 0,16 > 0,20 > 0,100 > 0.Conclusion: All numbers are greater than 0.Counterexample: ?
Here, we want to give a counter example which would exist to make the conclusion wrong.
To do this, we have to get the values which are in actual terms lesser in value to zero. These values include the negative integers i.e negative whole numbers. On the number line, these values exist before zero, to the left handside of the number line.
Examples of these values include -5, -4 , -3 , -2 etc
So the counter example can be in the form;
-3 < 0 , -5 < 0 , -2 < 0
With these set of examples, we have made the conclusion false.
8.Find the range,A. (-0,00)B. (-0,0)C. (- 0, 1)D. Cannot be determined4/5
From the graph, the range of the graph, the y values range from zero down; so the range is given by;
[tex](-\infty,0\rbrack[/tex]Option
