write an equation illustrating the condensation of p-diaminobenzene with the acid chloride of oxalic acid (cocl)2

Answer:

2. sea level rises sorry if it's wrong

Answer:

erosion.

Explanation:

Answer:

11.2g of the 45% pure silver and 2.8g of the 50% pure silver.

Explanation:

14g of 46% pure silver contains:

14g*46% = 6.44g of silver are required. Thus, we can write:

6.44 = X*50% + Y*45% (1)

Where X is the mass of 50% pure silver and Y the mass of 45% pure silver.

As the mass of the sample must be 14g:

14g = X + Y (2)

Replacing (2) in (1):

6.44 = (14-Y)*50% + Y*45%

6.44 = 7 - 0.5Y + 0.45Y

-0.56 = -0.05Y

Y = 11.2g of the 45% pure silver

And:

14g-11.2g = X

X =

2.8g of the 50% pure silver

The required amount to obtain 14g of 46% pure silver is 2.8g of 50% silver and 11.2g of 45% silver.

To solve this question, we can assume it's a mathematical problem more than a chemistry problem.

let x represent the amount of 45% of pure Ag

let y represent the amount of 50% of pure Ag

But from the question, we only need 14g from both x and y

We can write an equation to represent this

[tex]x+y=14...equation(i)[/tex]

likewise, we can say that

[tex]0.45x+0.50y=14*0.46\\0.45x+0.50y=6.44...equation(ii)[/tex]

Solving both equations simultaneously,

[tex]x+y=14...equation(i)\\0.45x+0.5y=6.44...equation(ii)[/tex]

from equation (i)

[tex]x+y=14\\x=14-y...equation(iii)[/tex]

substitute equation (iii) into equation (ii)

[tex]0.45x+0.5y=6.44\\x=14-y\\0.45(14-y)+0.5y=6.44\\6.3-0.45y+0.5y=6.44\\[/tex]

collect like terms

[tex]-0.45y+0.50y=6.44-6.3\\0.05y=0.14\\y=\frac{0.14}{0.05}\\y=2.8[/tex]

Now we know the value of the 50% Ag which is 2.8g. Let's substitute it's value into equation (i) and solve for x

[tex]x+y=14\\x+2.8=14\\x=14-2.8\\x=11.2g[/tex]

Learn more about definite proportions here

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Answer: Food webs are made of many food chains is the answer.

Explanation:

Food web consists many food chains.

Answer:

[tex]C_3H_6[/tex]

Explanation:

Hello!

In this case, since the empirical formula is the smallest representation of the molecular formula, it is known that the times in which the empirical formula is into the molecular formula is a whole number and is computed by dividing the molar mass of the molecular formula by that of the empirical formula as shown below:

[tex]\frac{42.08g/mol}{12.01+1.01x2}= \frac{42.08g/mol}{14.03g/mol}=3[/tex]

Thus, the molecular formula times the empirical formula by 3 to obtain:

[tex]C_3H_6[/tex]

Regards!

Answer:

Because the compound has a formula of M2O, the number of valence electrons of M should be 1. Therefore, (1) Group 1 is the correct answer because elements in group 1 have 1 valence electron.

Explanation:

Pounds of gold ore :  11,02311

Given

5 g of gold

0.1% gold by mass

Required

Pounds of gold ore

Solution

[tex]\tt \%mass~gold=\dfrac{mass~gold}{mass~ore}\times 100\%[/tex]

For percent mass = 0.1%, than mass of gold ore :

[tex]\tt 0.1\%=\dfrac{5~g}{mass~ore}\times 100\%\\\\mass~ore=\dfrac{5\times 100}{0.1}\\\\mass~ore=5000~g[/tex]

Conversion factor :

1 g = 0,00220462 pound, than for 5000 g = 11,02311 pounds

Answer:

520 mg Al(OH)₃

Explanation:

The reaction that takes place is:

Now we calculate how many moles of each reagent were added, using their concentrations and volumes:

10 mmol of Al(NO₃)₂ would react completely with (10*3) 30 mmol of KOH, there are not as many KOH mmol, so KOH is the limiting reactant.

We calculate how many moles of Al(OH)₃ are produced, using the limiting reactant:

Finally we convert mmol of Al(OH)₃ to mg, using its molar mass:

Answer:

50%

Explanation:

Let assume that there are:

"a" moles of CH4 & "b" moles of C2H2

Then by applying the ideal gas equation:

PV = nRT

[tex]16.8 \times 10^3 \times V = (a+b)RT[/tex]

Make (a+b) the subject of the formula:

[tex](a+b) = \dfrac{16800 \ V }{RT} mol[/tex] --- (1)

Since 1 mole of CH₄ yields 1 mol of CO₂ & 1 mol of C₂H₂ yields 2 moles of CO₂

Then;

the total moles of CO₂ = (a +2b)

Now:

[tex]25.3 \times 10^3 \times V = (a+ 2b)RT[/tex]

[tex](a + 2b) = \dfrac{25200 \ V}{RT \ mol}[/tex]    ---- (2)

∴

By solving the above equations

[tex]a = \dfrac{8400 \ V}{RT} \\ \\ b = \dfrac{8400 \ V}{RT}[/tex]

Hence, the estimate of the percentage of methane in the original mixture is:

[tex]= 100 \times \dfrac{a}{(a+b)}[/tex]

[tex]= 100 \times \dfrac{8400\dfrac{ \ V}{RT} }{8400\dfrac{ \ V}{RT} + 8400\dfrac{ \ V}{RT}}[/tex]

= 50%

When Silicone is altered with Phosphorus, 4 of its electrons form covalent bonding and the 5th electron becomes delocalized and thus it increases electrical conduction

Answer:

blue blah blue blah

Explanation:

Answer:

10.80 g of H2

Explanation:

As per the equation, let us calculate the mole ratio. N2+3H2→2NH3. As per the equation one mole of nitrogen

Answer:

I believe it is the Ethiopian ibex

Explanation:

Answer:

I think it the Ethiopian ibex

Explanation:

im srry if it wrong.

hope this helps tho

Answer:

837.02 ohms

Explanation:

Step one:

Given data

Frequency= 60Hz

L1= 0.75H

L2= 1.47H

When inductors are connected in series, the total inductance is the sum of the individual inductance

Step two:

Inductor 1

[tex]Xl1= 2\pi fL\\\\Xl1= 2*3.142*60*0.75\\\\Xl1= 282.78 ohms[/tex]

Inductor 2

[tex]Xl2= 2\pi fL\\\\Xl2= 2*3.142*60*1.47\\\\Xl2= 554.24 ohms[/tex]

The total inductance is

=282.78+554.24

=837.02 ohms

Answer:

Ok:

Explanation:

a) 2-fluoropropane

b) 2,3 dichlorobutane

c) pent-2-ene or 2 pentene (I assume the semicolon was a typo)

d) Same as c (I assume Z is a typo too)

e) non-1-ene or 1-nonene (I assume the B is a 2)

Answer:

Molar mass of CaO

(40 + 16)g

= 56g

hope it helps you

Answer:

Security

Explanation:

A wireless network consists of good connection with fast speed, convenience, and reliability. Security is a major problem with wireless connection as someone can get your information by joining the same connection as you.

Answer:

21. Al (Aluminium)

+3 (most common), -1, -2, +1, +2

22. Bi (Bismuth)

+3 (most common), -3, -2, -1, +1, +2, +4, +5

23. Ni (Nickel)

+2 (most common), -2, -1, 0,+1, +3, +4

24. Xe (Xenon)

0 (most common), +1, +2, +4, +6, +8

25. Pb (Lead)

+2 (most common), +4 (most common), -4, -2, -1, +1, +3

Explanation:

Now we proceed to present the answers for each element:

21. Al (Aluminium)

+3 (most common), -1, -2, +1, +2

22. Bi (Bismuth)

+3 (most common), -3, -2, -1, +1, +2, +4, +5

23. Ni (Nickel)

+2 (most common), -2, -1, 0,+1, +3, +4

24. Xe (Xenon)

0 (most common), +1, +2, +4, +6, +8

25. Pb (Lead)

+2 (most common), +4 (most common), -4, -2, -1, +1, +3

Answer: The average kinetic energy is proportional to the absolute temperature of the gas. Gas particles are in random motion. Gas particles have no volume. And the collisions between gas particles are elastic.

Explanation: I heard this question before, I think. Hope this helps!

Answer:

Fluorine

Explanation:

These particles stick in the atoms and make them radioactive.

Answer:

[tex]\rho _2=0.22g/L[/tex]

Explanation:

Hello!

In this case, since we are considering an gas, which can be considered as idea, we can write the ideal gas equation in order to write it in terms of density rather than moles and volume:

[tex]PV=nRT\\\\PV=\frac{m}{MM} RT\\\\P*MM=\frac{m}{V} RT\\\\P*MM=\rho RT[/tex]

Whereas MM is the molar mass of the gas. Now, since we can identify the initial and final states, we can cancel out R and MM since they remain the same:

[tex]\frac{P_1*MM}{P_2*MM} =\frac{\rho _1RT_1}{\rho _2RT_2} \\\\\frac{P_1}{P_2} =\frac{\rho _1T_1}{\rho _2T_2}[/tex]

It means we can compute the final density as shown below:

[tex]\rho _2=\frac{\rho _1T_1P_2}{P_1T_2}[/tex]

Now, we plug in to obtain:

[tex]\rho _2=\frac{0.53g/L*225K*68.3kPa}{345K*108.8kPa}\\\\\rho _2=0.22g/L[/tex]

Regards!

Answer:

Neutrons

Explanation:

Subatomic particles are components atoms, and they include protons, electrons and neutrons. In different isotopes of an atom, the number of neutrons that the atom contains is what changes.

I hope this helps!

Answer:

2Fe₂O₃(s) → 4Fe(s) + 3O₂(g)

Explanation:

The unbalanced reaction is:

To balance the oxygen atoms, we put a 2 before Fe₂O₃ and a 3 before O₂(g) - so as to make the total of O atoms in both sides 6 -:

There are four Fe atoms on the left side and only one on the right side, so we put a 4 before Fe(s):

Now the equation is balanced: there is an equal number of both Fe and O atoms in both sides of the equation.

Answer:

there's just a lot of drama around grumpy trumpy's StOlEN eLecTiOn which are all just fake claims. all his hardcore followers are brainwashed into believing anything he says, so people (especially people who are inside the capitol) fear that trump's followers might incite violence AGAIN even after they broke into the Capitol on the 6th.

That's why they have the National Guard and thousands of people to keep the building secure during Biden's Inauguration.

hope this helps!

Answer:

674.26 g of AlI₃

Explanation:

We'll begin by calculating the theoretical yield of aluminum (Al). This can be obtained as follow:

Percentage yield of Al = 67.8%

Actual yield of Al = 30.25 g

Theoretical yield of Al =?

Percentage yield = Actual yield /Theoretical yield × 100/

67.8% = 30.25 / Theoretical yield

67.8 / 100 = 30.25 / Theoretical yield

0.678 = 30.25 / Theoretical yield

Cross multiply

0.678 × Theoretical yield = 30.25

Divide both side by 0.678

Theoretical yield = 30.25 / 0.678

Theoretical yield of Al = 44.62 g

Next, we shall determine the mass of AlI₃ that reacted and the mass of Al produced from the balanced equation. This can be obtained as follow:

AlI₃(s) + 3K(s) → 3KI(s) + Al(s)

Molar mass of AlI₃ = 27 + (3×127)

= 27 + 381 = 408 g/mol

Mass of AlI₃ from the balanced equation = 1 × 408 = 408 g

Molar mass of Al = 27 g/mol

Mass of Al from the balanced equation = 1 × 27 = 27 g

Summary:

From the balanced equation above,

408 g of AlI₃ reacted to produce 27 g of Al.

Finally, we shall determine the mass of

AlI₃ required to produce 44.62 g of Al. This can be obtained as follow:

From the balanced equation above,

408 g of AlI₃ reacted to produce 27 g of Al.

Therefore, Xg of AlI₃ will react to produce 44.62 g of Al i.e

Xg of AlI₃ = (408 × 44.62)/27

Xg of AlI₃ = 674.26 g

Thus, 674.26 g of AlI₃ is needed for the reaction.

rgrgtff

ghhbbbhhghghgghgggferer

Answer:

B. None of these

Explanation:

Answer:

Converting Grams to Moles of an Element and Vice Versa.

We can convert back and forth between grams of an element and moles.

The conversion factor for this is the molar mass of the substance. The molar mass is the ratio giving the number of grams for each one mole of the substance

molar mass is the factor

Grams can be converted to moles and vice versa so the conversion factor which is used for this is molar mass.

Mass of any substance will be converted into moles by using the below equation:

n = W/M, where

n = moles

W = given mass

M = molar mass

By using the above formula we can convert the mass of any object to moles and moles to mass.

Hence conversion factor which is used for this is molar mass(M).

To know more about mass & moles, visit the below link:

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Answer: The mole fraction of chloroform in this solution is 0.41

Explanation:

To calculate the moles, we use the equation:

[tex]\text{Number of moles}=\frac{\text{Given mass}}{\text {Molar mass}}[/tex]

a) moles of [tex]CHCl_3[/tex]

[tex]\text{Number of moles}=\frac{49g}{119g/mol}=0.41moles[/tex]

b) moles of [tex]CH_3COBr[/tex]

[tex]\text{Number of moles}=\frac{73g}{123g/mol}=0.59moles[/tex]

To calculate the mole fraction, we use the formula:

[tex]\text{Mole fraction of a component}=\frac{\text{Moles of the component}}{\text{total moles}}[/tex]

[tex]\text{Mole fraction of chloroform}=\frac{\text{Moles of chloroform}}{\text{total moles}}=\frac{0.41}{0.41+0.59}=0.41[/tex]

The mole fraction of chloroform in this solution is 0.41

Answer:yes

Explanation: