The time needed to travel a certain distance varies inversely with the rate of speed, so:
[tex]\begin{gathered} let\colon \\ t=\text{time} \\ v=\text{rate of speed} \\ t\propto\frac{1}{v} \end{gathered}[/tex]8hours----------------------------->36mi/h
xhours----------------------------->60mi/h
[tex]\begin{gathered} \frac{8}{x}=\frac{36}{60} \\ \text{ Since the it varies inversely:} \\ \frac{8}{x}=(\frac{36}{60})^{-1} \\ \frac{8}{x}=\frac{5}{3} \\ \text{solve for x:} \\ x=\frac{3\cdot8}{5} \\ x=4.8h \end{gathered}[/tex]4.8 hours or 4 hours and 48 minutes
Identify the algebraic expression for the given word phrase.
6 times the sum of r and 9
A. 6 + r + 9
B. 6 (r + 9)
C. r (6 + 9)
D. 6r + 9
b because 6 times the sum of r and 9 means 6(r+9)
The annual rainfall in a town has a mean of 54.11 inches and a standard deviation of 12.59 inches. Last year there was rainfall of 48 inches. How many standard deviations away from the mean is that? Round your answer to two decimal places.
SOLUTION
Mean=54.11, standard deviation = 12.59
X=48
Using the z formula
[tex]z=\frac{x-\mu}{\sigma}[/tex]Substituting values gives
[tex]z=\frac{48-54.11}{12.59}[/tex]Solve for z
[tex]z=-0.4853[/tex]This shows that the result shows that the value x=48 is 0.4853 standard deviation to the left of the mean.
how do i use a graphing calculator to solve the system.
Given:
[tex]\begin{gathered} 0.4x\text{ + }\sqrt{2}y\text{ = 1} \\ \sqrt{5}\text{ x + 0.8y = 1} \end{gathered}[/tex]Using a graphing calculator, we have the graph shown below:
The point of intersection of the equations represents the solution to the system.
Hence, the solution to the system is:
x = 0.216
y = 0.646
A ball is dropped from a state of rest at time T = 0.The distance traveled after t seconds is s(t) = 16t^2 ft.
ANSWERS
(a) 68 ft
(b) 136 ft/s
(c) 128 ft/s
EXPLANATION
(a) The time interval is from 4s to 4.5s, so the distance the ball travels from 4s to 4.5s is,
[tex]\Delta s=16\cdot(4.5)^2-16(4)^2=68ft[/tex](b) As stated, the average velocity is the quotient between the distance traveled and the time,
[tex]\frac{\Delta s}{\Delta t}=\frac{68ft}{0.5s}=136ft/s[/tex](c) Here we have to find the distance as we did in part b and then divide by the time interval,
[tex]\begin{cases}\lbrack4,4.01\rbrack\to\Delta s=1.28016\to V=1.28016/0.01=128.16ft/s \\ \lbrack4,4.001\rbrack\to\Delta s=0.128016\to V=0.128016/0.001=128.016ft/s \\ \lbrack4,4.0001\rbrack\to\Delta s=0.01280016\to V=0.01280016/0.0001=128.0016ft/s \\ \lbrack3.9999,4\rbrack\to\Delta s=0.01279984\to V=0.01279984/0.0001=127.9984ft/s \\ \lbrack3.999,4\rbrack\to\Delta s=0.127984\to V=0.127984/0.001=127.984ft/s \\ \lbrack3.99,4\rbrack\to\Delta s=1.2784\to V=1.2784/0.01=127.84ft/s\end{cases}[/tex]As we can see in the middle values, as the time interval is shorter - the difference approaches 0, the value of the velocity is closer to 128ft/s.
Hence, the estimated instantaneous velocity at t = 4 is 128 ft/s
See the attached for the math problem
1. If the cake rises by ¹/₃ as it bakes, the number of cups of cake batter needed for the four cakes is 140.
2. If ¹/₄ in. is used between layers and ¹/₂ in. is used on the top and sides, the number of cups of icing needed for the four cakes is 47.
How are the numbers determined?The number of cups of cake batter and icing can be determined using the mathematical operations of multiplication, addition, division, and subtraction.
First, the volumes of each cake and its batter are calculated using the given dimensions and the rise.
Using the division operation, the number of cups of cake batter for each cake is determined and multiplied by four.
We understand that the normal volume of the cake will increase with the icing, helping us to calculate the increased volume after the icing.
The difference between the two volumes becomes the volume of the icing required, which is divided by 14.4 in³ to get the number of cups of icing required.
a) Cups of Cake Butter:The volume of each cake = Length x Width x Height
Length = 14 inches
Width = 12 inches
Height = 4 inches (2 x 2)
= 12 x 14 x 4
= 672 in³.
Rise of the cake as it bakes = ¹/₃
The normal volume before rising = 1
Risen volume = 1¹/₃
1¹/₃ = 672 in³
The normal volume of cake batter before the ¹/₃ rise = 504 in³ (672/1¹/₃).
1 cup = 14.4 in³, the total cups for each cake = 35 cups (504 in³/14.4 in³).
The total cups of cake batter for the 4 cakes = 140 cups (35 x 4).
b) Cups of Icing:The total quantity of icing = 1¹/₄ (¹/₄ + ¹/₂ + ¹/₂).
The new volume after the icing = 840 in³ (672 x 1¹/₄)
The difference in volume after the icing = 168 in³ in (840 in³ - 672 in³)
If 1 cup = 14.4 in³, the cups of icing for each cake = 11.67 cups (168 in³/14.4 in³).
The total cups of icing for the 4 cakes = 47 cups (11.67 x 4).
Learn more about mathematical operations at https://brainly.com/question/20628271
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Question Completion:Four double-layered cakes, each 12.0 in. x 14.0 in., have been ordered for a special event. Each layer is 2.0 in. high.
a) If the cake rises by ¹/₃ as it bakes, how many cups of cake batter are needed? (1 cup = 14.4 in³. Hint: The ¹/₃ rise should be treated as a constant.)
b) How many cups of icing are needed if ¹/₄ in. is used between layers and ¹/₂ in. is used on the top and sides? (Assume icing is not layered on top of the icing. 1 cup = 14.4 in³.)
A tennis racket cost 12$ more than a hockey stick , if the price of the two is 31$ find the cost of a tennis racket
A 33-inch piece of steel is cut into three pieces so that the second piece is twiceas long as the first piece, and the third piece is one inch more than five times thelength of the first piece. What is the length of the first piece?
Let;
x = the length of the first piece
y=the length of the second piece
z=the length of the third piece
From the question;
"the second piece is twice as long as the first piece" can be written in equation as:
y = 2x
"the third piece is one inch more than five times the length of the first piece"
can be written as :
z= 5x+ 1
Total length of the 3 pieces = 33
This implies:
x + y + z =33
substitute y=2x and z=5x+1 into the above
x + 2x + 5x+1 = 33
8x + 1 = 33
subtract 1 from both-side of the equation
8x = 33 -1
8x = 32
divide both-side of the equation by 8
x= 32/8
x= 4
The length of the first piece is 4-inches
Y = X - 8. y = -x +6* Parallel Perpendicular Neither
The equation of a line given in slope-intercept form is written as
[tex]\begin{gathered} y=mx+b \\ \text{Where m is the slope. This means the coeeficient of x is the slope} \end{gathered}[/tex]For two lines to be parallel, their slopes must equal to each other. Also for the two lines to be perpendicular, their slopes must be a negative inverse of each other. An example of negative inverse is given as;
[tex]\begin{gathered} -\frac{1}{4}\text{ is a negative inverse of 4} \\ \text{Likewise, -4 is a negative inverse of }\frac{1}{4}\text{ } \end{gathered}[/tex]The slope of the first line is 1, since the line is given as,
y = x - 8
(The coefficient of x is 1)
The slope of the second line is -1, since the line is given as,
y = -x + 8
(The coefficient of x is -1)
Therefore, since both slopes are not equal and not negative inverses of each other, then the correct answer is NEITHER.
Identify the property of equality that justifies the missing step to solve the given equation.Equation3x + (1 - 8) = 124r-I8 = 12StepsOriginal equationAssociative property of addition4r= 20r=5Division property of equalitya. subtraction property of equalityb. addition property of equalityc. division property of equalityd. multiplication property of equality
From the attached image;
[tex]4x-8=12[/tex]The next step is to add 8 to both sides of the equation to remove -8.
[tex]\begin{gathered} 4x-8+8=12+8 \\ 4x=20 \end{gathered}[/tex]Since we added to the equation.
The step is an addition property of equality
Is 4b-2c leqslant 12 inequalities or not inequalities[tex] ax+by \leqslant c[/tex]
First, let's write the expression below:
[tex]4b-2c\leqslant12[/tex]Since the expression contains the symbol "<=" (that is, "lesser than or equal to") between two terms, the complete expression is an inequality.
In order to solve this inequality for a given variable, we need to rewrite the inequality such as one side of the inequality has only the wanted variable.
For example, solving the inequality for b, we have:
[tex]\begin{gathered} 4b-2c\leqslant12\\ \\ 4b\leq12+2c\\ \\ b\leq\frac{12+2c}{4}\\ \\ b\leq3+0.5c \end{gathered}[/tex]Suppose that $6000 is placed in an account that pays 19% interest compounded each year. Assume that no withdrawals are made from the account.
We are going to use the formula for the compound interest, which is
[tex]A=P\cdot(1+\frac{r}{n})^{nt}[/tex]A = the future value of the investment
P = the principal investment amount (the initial deposit or loan amount)
r = the annual interest rate (decimal)
n = the number of times that interest is compounded per unit t
t = the time the money is invested or borrowed for
Replacing the values in the first question we have:
[tex]\begin{gathered} A=P\cdot(1+\frac{r}{n})^{nt} \\ A=6000,r=0.19,n=1,t=1 \\ A=6000\cdot(1+\frac{0.19}{1})^1=7140 \end{gathered}[/tex]Answer for the first question is : $7140
Then, replacing the values in the second question we have:
[tex]\begin{gathered} A=P\cdot(1+\frac{r}{n})^{nt} \\ A=6000,r=0.19,n=1,t=2 \\ A=6000\cdot(1+\frac{0.19}{1})^2=8497 \end{gathered}[/tex]Answer for the second question is : $8497
What is the x values that satisfies the linear equations on the graph?
In the linear equations shown on the coordinate grid, the values of x that satisfies both equations is 2 (option b).
The graph of both equations intersect at the point where x equals 2.
divide fraction2*1/3 / 7*3/8 =
Step-by-step explanation:
3.999 is the correct answer
A park in a subdivision is triangular shaped. Two adjacent sides of the park are 533 feet and 525 feet. The angle between the sides is 53 degrees. To the nearest unit, what is the area of the park in square yards?A. 27,935B. 24,831C. 37,246D. 12,415thank you ! :)
Given:
Length of the two adjacent sides = 533 feet and 525 feet
Angle between the two sides = 53 degrees
Let's find the area of park.
Let's make a sketch representing this situation:
Let's first find the length of the third side.
Apply the cosine rule.
We have:
[tex]\begin{gathered} a=\sqrt{533^2+525^2-2(533)(525)cos53} \\ \\ a=\sqrt{284089+275625-336805.7777} \\ \\ a=\sqrt{222908.2223} \\ \\ a=472.13\text{ ft} \end{gathered}[/tex]Now, apply the Heron's formula to find the area:
[tex]A=\sqrt{s(s-a)(s-b)(s-c)}[/tex]Where:
a = 472.13
b = 533
c = 525
Let's solve for s:
[tex]\begin{gathered} s=\frac{472.13+533+525}{2} \\ \\ s=\frac{1530.13}{2} \\ \\ s=765.1\text{ } \end{gathered}[/tex]• Therefore, the area will be:
[tex]\begin{gathered} A=\sqrt{765.1(765.1-472.13)(765.2-533)(765.1-525)} \\ \\ A=\sqrt{765.1(292.97)(232.1)(240.1)} \\ \\ A=111738.81\text{ ft}^2 \end{gathered}[/tex]The area in square feet is 111,738.81 square feet.
Now, let's find the area in square yards.
Apply the metrics of measurement.
Where:
1 square yard = 9 square feet
Thus, we have:
111,738.81 square feet =
[tex]\frac{111738.81}{9}=12415.4\approx12415\text{ square yards}[/tex]Therefore, the area of the park in square yards is 12,415 square yards.
ANSWER:
12,415 square yards.
(a)If Diane makes 75 minutes of long distance calls for the month, which plan costs more?
Answer:
Step-by-step explanation:
huh the proper question
Select the correct answer. Which equation, when solved, gives 8 for the value of x? OA. +3 = =+14 OB. 5-9=31-12 OC. 21-2=r-4 OD. 5.-7=*=+14
Let's solve for each and see which gives 8
For A
5/2 x + 7/2 = 3/4 x + 14
collect like term aand solve for x
5/2 x - 3/4 x = 14 - 7/2
[tex]\frac{10x-3x}{4}=\frac{28-7}{2}[/tex][tex]\frac{7x}{4}=\frac{21}{2}[/tex][tex]x=\frac{21}{2}\times\frac{4}{7}=6[/tex]For B
5/4 x - 9 = 3/2 x -12
collect like term and solve for x
[tex]\frac{5}{4}x-\frac{3}{2}x=-12+9[/tex][tex]=\frac{5x-6x}{4}=-3[/tex][tex]-\frac{x}{4}=-3[/tex][tex]x=12[/tex]For C
5/4 x - 2 = 3/2 x - 4
collect like term and then solve for x
[tex]\frac{5}{4}x-\frac{3}{2}x=-4+2[/tex][tex]\frac{5x-6x}{4}=-2[/tex][tex]-\frac{x}{4}=-2[/tex][tex]x=8[/tex]For D
5/4 x - 7 = 3/4 x + 14
collect like term and solve for x
[tex]\frac{5}{4}x-\frac{3}{4}x=14+7[/tex][tex]\frac{2x}{4}=21[/tex][tex]x=42[/tex]Therefore, the correct option is C
wich time of line are shown in the figure
Solution
Step 1
Two distinct lines intersecting each other at 90° or at right angles are perpendicular to each other.
Hence apply this to question 8 the type of lines shown in the figure is perpendicular lines. Option C
Step 2
To explain this as stated above line A and line B intersect each other at a right angle hence line A and B are perpendicular lines. The line segments are seen below.
The probability of a certain brand of battery going dead within 15 hours is 1/3. Noah has a toy that requires 4 of these batteries. He wants to simulate the situation to estimate the probability that at least one battery will die before 15 hours are up. 1. Noah will simulate the situation by putting marbles in a bag. Drawing one marble from the bag will represent the outcome of one of the batteries in the toy after 15 hours. Red marbles represent a battery that dies before 15 hours are up, and green marbles represent a battery that lasts longer. How many marbles of each color should he put in the bag? Explain your reasoning. *
a.
Noah put marbles on a bag, each color marble represents that the battery of the toy died before 15 hours (red marbles) or that the battery lasted after 15 hours (green marbles)
There are 4 batteries on the toy, for each battery there are two possible outcomes, each one represented by a red and green marble.
So, for each battery, he has to put two marbles. There will be 4 red marbles and 4 green marbles in the bag.
b.
To estimate the probability that at least one battery will die within 15 hours, you have to calculate the expected value.
can you please help me solve this practice problem I really need help
Question:
Solution:
Step 1: Find the equation of a line:
Notice that the line passes through the point (x2,y2)= (4,-2) and (x1,y1)=(0,3). Then, the slope of this line would be:
[tex]m\text{ = }\frac{Y2-Y1}{X2-X1}=\text{ }\frac{-2-3}{4-0}\text{ = }\frac{-5}{4}\text{ =-}\frac{5}{4}[/tex]now, notice that the y-intercept of this line is b=3. Then, the equation for this line is:
[tex]y\text{ = -}\frac{5}{4}x+3[/tex]Step 2:
note that the shaded region is all points on the line and those above it. So, the shaded region can be represented by the following inequality:
[tex]y\text{ }\ge\text{ -}\frac{5}{4}x+3[/tex]and it is shown graphically like this:
So that, we can conclude that the correct answer is:
[tex]y\text{ }\ge\text{ -}\frac{5}{4}x+3[/tex]Mr. Baker wants to divide his class into smaller, equal-sized groups of students.
However, he finds that his class cannot be divided evenly into any size group except for individual groups of 1.
Complete the statements below about the number of students in Mr. Baker's class.
The completion of the statements about the number of students in Mr. Baker's class is as follows:
The number of students in his class must be a prime number.The quotient from the division of the students into equal-sized groups is not even because there must be a remainder.What is a prime number?A prime number is a number divisible by itself and 1 only.
When a prime number is divided by another number except by itself and 1, there is always a remainder in the quotient.
Some examples of the prime numbers in Mr. Baker's class include 19, 23, 29, 31, or 37 students.
Thus, these numbers of students cannot be divided by another number without a remainder because they are prime numbers.
Learn more about prime numbers at brainly.com/question/145452
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Question Completion:1. The number of students in his class must be a --- number.
2. The quotient from the division of the students into equal-sized groups is .... because there must be a .....
If you have a 40% decrease, what percentage of the original amount do you have?
A 40% decrease represents subtraction.
[tex]100-40=60[/tex]So, the initial percentage is 100%, if it decreases by 40%, we get 60% as result.
Hence, we would have 60% of the original amount.a triangular pyramid has four faces h = b = 1. What is the pryimands surface area?(There's no image)(
Let's find the area of one face
[tex]A=\frac{bh}{2}[/tex]Where h = b = 1.
[tex]A=\frac{1\cdot1}{2}=\frac{1}{2}[/tex]Given that there are four faces, we have to multiply the area above by 4
[tex]S=4\cdot\frac{1}{2}=2[/tex]Hence, the answer is 2 square units.Using the information provided in the given table, determine how much monthly income would be necessary to budget in order to cover the expenses of attending a local college for the 9-month academic year. Round your answer to the nearest cent, if necessary.
We have to add all the annual expenses:
[tex]9122+10612+1109+732+1092+1197+132[/tex][tex]=23,996[/tex]However, this quantity we obtained are the annual expenses, then, we have to divide them by the months of the academic year:
[tex]\frac{23996}{9}[/tex][tex]=2666.22[/tex]Answer: $2,666.22
Find the surface area and the volume of the figure below round your answer to the nearest whole number
The shape in the questionis a sphere having
Radius = 10ft
Finding the Surface area
The surface area of a square is given as
[tex]\text{Surface Area of sphere = 4}\pi r^2[/tex]putting the value for radius
[tex]\begin{gathered} \text{Surface Area of sphere = 4 }\times\frac{22}{7}\times\text{ 10}\times10 \\ \text{Surface Area of sphere = }\frac{4\text{ }\times22\times10ft\times10ft}{7} \\ \text{Surface Area of sphere = }\frac{8800ft^2}{7} \\ \text{Surface Area of sphere = 1257.14ft}^2 \\ \text{Surface Area of sphere }\cong1257ft^2\text{ ( to the nearest whole number)} \end{gathered}[/tex]The surface area of the sphere = 1257 square feet
Finding the volume
The volume of a sphere is given as
[tex]\text{volume of sphere = }\frac{4}{3}\pi r^3[/tex]putting the value of radius
[tex]\begin{gathered} \text{Volume of sphere = }\frac{4}{3}\times\frac{22}{7}\text{ }\times10ft\text{ }\times10ft\text{ }\times10ft \\ \text{Volume of sphere = }\frac{88000ft^3}{21} \\ \text{Volume of sphere = 4190.47ft}^3 \\ \text{Volume of sphere}\cong4190ft^3\text{ (to the nearest whole number)} \end{gathered}[/tex]Therefore, the volume of the sphere = 4190 cubic feet
Xavier wants to compare two websites based on customer ratings in order to decide on which website to make a big purchase. He creates a boxplot for each website with the same number of ratings. (look at the graph)What can Xavier NOT include?A. Website A has a higher median rating B. Website A has a larger interquartile range C. Website A has larger rangeD. Website A has a lower median rating E. Website A has a lower first quartile value
D.
Since the median of the blue box is upper from the orange one we conclude that the median is higher in website A.
Therefore, the wrong statement is D.
I have tried multiple times but still could not get the correct answer or at least accurate answers
Given:
R is the midpoint of QS.
[tex]RS=5\text{,RT}=13[/tex]The midpoint is the point on a line segment equally distant from the two endpoints.
It gives,
[tex]\begin{gathered} QR=RS\ldots\ldots\text{. R is midpoint of QS} \\ \Rightarrow QR=5 \end{gathered}[/tex]Also,
[tex]\begin{gathered} RS+ST=RT \\ 5+ST=13 \\ ST=13-5 \\ ST=8 \end{gathered}[/tex]So, QT is calculated as,
[tex]\begin{gathered} QT=QR+RE+ST \\ QT=5+5+8=18 \end{gathered}[/tex]Answer: QT = 18
Question 8 of 20If f(x) = 2x²+2 and g(x)=x2-1, find (f- g)(x).O A.3x²+3O B.x2²+1 O C.3x2² +1O D.x² +3
Solution
Step 1
Write the two functions:
[tex]f\mleft(x\mright)=2x²+2\text{ }and\text{ }g\left(x\right)=x2-1[/tex]Step 2
(f- g)(x) = f(g) - g(x)
[tex]\begin{gathered} \left(f-g\right)\left(x\right)=2x²+2\text{ - \lparen}x^2-1) \\ \\ (f-g)(x)=2x^2+\text{ 2 - x}^2\text{ + 1} \\ \\ (f-g)(x)=x^2+3 \end{gathered}[/tex]Final answer
D. x² +3
I had $70 and my mother gave me $10 and my father gave me $30 and aunt and uncle gave me $150 and I had another $7 how much do I have
Initial money = 70
then add
10 + 30 + 150 + 7 = 197
Now add both results
70 + 197 = 267
Answer is
You have $267
calculated the slope (5,-14),(-14,0) help
the slope can be calculated using the next formula
[tex]m=\frac{y_2-y_1}{x_2-x_1}[/tex]where
(5,-14)=(x1,y1)
(-14,0)=(x2,y2)
then we substitute the values
[tex]m=\frac{0+14}{-14-5}=\frac{14}{-19}=-\frac{14}{19}[/tex]the answer is -14/19
Karen has 5 more quarters than dimes. She has $3.70. How many quarters and dimes she have?
A dime is 10% of a dollar = 10/100 x 100 cent = 10 cents
A quater is 25% of a dollar = 25/100 x 100 cent = 25 cents
Since Karen has 5 more quaters than dimes
let quaters = q
let dimes = d
Then Karen has 5q : d = $ 3.70
$ 3.70 = 3.70 x 100 cents = 370 cents
