Answers
Given the following function:
[tex]tan\text{ }\theta=\frac{10}{y}[/tex]Both θ and y are functions of the time (t)
We will find the derivatives of θ and y with respect of the time (t) as follows:
[tex]sec^2θ*\frac{dθ}{dt}=-\frac{10}{y^2}*\frac{dy}{dt}[/tex]Now, we will find dy/dt when θ = π/6 and dθ/dt = π/12
First, we need to find the value of y when θ = π/6
[tex]\begin{gathered} tan(\frac{\pi}{6})=\frac{10}{y} \\ \frac{1}{\sqrt{3}}=\frac{10}{y} \\ \\ y=10\sqrt{3} \end{gathered}[/tex]so, we will substitute the values to find dy/dt as follows:
[tex]\begin{gathered} sec^2(\frac{\pi}{6})*\frac{\pi}{12}=-\frac{10}{(10\sqrt{3})^2}*\frac{dy}{dt} \\ \\ so,\frac{dy}{dt}=-\frac{(10\sqrt{3})^2}{10}*sec^2(\frac{\pi}{6})*\frac{\pi}{12}=-10.4719755 \end{gathered}[/tex]Rounding to 2 decimal places
So, the answer will be:
[tex]\frac{dy}{dt}=-10.47\text{ feet/hour}[/tex]Related Questions
if the probability of drawing an A or B is 9/25, what is the probability of the complementary event?
Answers
If an event has a probability of "A", then the complementary event will have a probability of "1 - A".
Given, the probability of an event is 9/25, we can easily find the probability of the complementary event. Shown below:
[tex]\begin{gathered} 1-\frac{9}{25} \\ =\frac{25}{25}-\frac{9}{25} \\ =\frac{16}{25} \end{gathered}[/tex]The correct answer is:
[tex]\frac{16}{25}[/tex]the perimeter of a rectangle is a rational number. the length of a rectangle is 6 units. the width of a rectangle must be a/an rational/irrational (circle one) number.
Answers
A rational number
Explanations:The perimeter of a rectangle is given by the formula:
Perimeter = 2(Length + Width)
The Length = 6 units
Perimeter = 2 (6 + Width)
Perimeter = 12 - 2 Width
2 Width = 12 - Perimeter
Width = (12 - Perimeter)/2
Note that a rational number is a number that can be written as a fraction of two integers.
Since the perimeter is said to be a rational number, any rational number substituted into the formula equation for the width above will give a rational number.
The width of the rectangle is therefore a rational number
Select three equations that could represent a step in solving this system using the substitution method. 4x+y = 6 x = 8 0.00 0:52 9 1x 2 4(8)+y=6 o y = 18
Answers
the first step is replacing x=8 on the first equation, so
[tex]4(8)+y=6[/tex]the second step is do the multiplication
[tex]\begin{gathered} 32+y=6 \\ y+32=6 \end{gathered}[/tex]and the last step is place the 32 on the other side substracting
[tex]\begin{gathered} y=6-32 \\ y=-26 \end{gathered}[/tex]dog brought a new jet ski for $299 down in 14 monthly payments are $57 how much did Doug pay for the jet ski total
Answers
If he paid $57 monthly for 14 months, the total amount paid is:
[tex]57\times14=798[/tex]He paid $798 in total
If the time to climb the mountain took an hour more than the time to hike down how long was entire hike?
Answers
4.8 mi
Explanation
[tex]\text{time}=\text{ }\frac{\text{distance}}{\text{rate}}[/tex]
Step 1
Set the equations
a) uphill
let
rate1= 1.5 miles per hour
time= unknow= t1
distance = x
b) down hille
rate=4 miles per hour
time=time2=one hour less than the time to climb = t1-1
distance = x
so
replacing
[tex]\begin{gathered} t_1=\frac{x}{1.5\frac{mi}{\text{hour}}}\rightarrow t_1=\frac{x}{1.5}\rightarrow equation(1) \\ t_2=\frac{x}{4\frac{mi}{\text{hour}}} \\ \text{replace t}_2=t_1-1 \\ t_1-1=\frac{x}{4} \\ \text{add 1 in both sides} \\ t_1-1+1=\frac{x}{4}+1 \\ t_1=\frac{x}{4}+1\rightarrow equation(2) \end{gathered}[/tex]Step 2
solve the equations
[tex]\begin{gathered} t_1=\frac{x}{1.5}\rightarrow equation(1) \\ t_1=\frac{x}{4}+1\rightarrow equation(2) \end{gathered}[/tex]set t1= t1
[tex]\begin{gathered} t_1=t_1 \\ \frac{x}{1.5}=\frac{x}{4}+1 \\ \frac{x}{1.5}=\frac{x+4}{4} \\ 4x=(x+4)1.5 \\ 4x=1.5x+6 \\ subtract\text{ 1.5 x in both sides} \\ 4x-1.5x=1.5x+6-1.5x \\ 2.5x=6 \\ \text{divide both sides by 2.5} \\ \frac{2.5x}{2.5}=\frac{6}{2.5} \\ x=2.4 \end{gathered}[/tex]it means the distance to the top of the mountain is 2.4 miles, so the entire hike is twice that amount
total distance=2.4 mi*2
total distance=4.8 miles
Step 3
now, the times
[tex]\begin{gathered} t_1=\frac{x}{1.5} \\ t_1=\frac{2.4}{1.5} \\ t_1=1.6\text{ hours} \\ t_2=t_1-1 \\ t_2=1.6-1=\text{ 0.6 hours} \end{gathered}[/tex]table
I hope this helps you
Can you help me with #7? X^3-2x^2+3x-6 = 0Please follow prompt b
Answers
Given:
The polynomial is given as,
[tex]x^3-2x^2+3x-6=0[/tex]The objective is to factor the polynomial completely.
Explanation:
Consider x = 2 in the given equation.
[tex]\begin{gathered} f(2)=2^3-2(2)^2+3(2)-6 \\ =8-8+6-6 \\ =0 \end{gathered}[/tex]Thus, (x -2) is a factor of the polynomial.
Now, using synthetic division,
Thus, the polynomial equation will be,
[tex]x^2+3=0\text{ . . . . .(1)}[/tex]On factorizing the equation (1),
[tex]\begin{gathered} x^2=-3 \\ x=\pm\sqrt[]{-3} \\ x=\pm i\sqrt[]{3} \\ x=i\sqrt[]{3},-i\sqrt[]{3} \end{gathered}[/tex]Hence, the factors of the polynomial are (x-2), (x+i√3), (x-i√3).
1 What is the volume of a triangular pyramid with thesame base and height dimensions of the prism below?5.5 in.13 in.7 in.
Answers
volume of a triangular pyramid = 1/3 * base area (triangle) *height
triange area= 1/2 base * height
triegle area= 1/7 in * 5.5 in = 38.5 in^2
Volume = 1/3 * 38.5 in^2 * 3 in
Volume = 38.5 in^3
___________________
Answer
choice b)
Find The measure of the indicated to the nearest angle
Answers
The given figure is a right triangle, then we can apply the sine function to find the missing angle, so:
[tex]\sin\theta=\frac{opposite}{hypotenuse}[/tex]The opposite side to the angle measures 17, and the hypotenuse measures 19.
By replacing these values, we can find the angle:
[tex]\begin{gathered} \sin\theta=\frac{17}{19} \\ \\ \theta=\sin^{-1}(\frac{17}{19}) \\ \\ \theta=63.47 \\ \theta\approx64\degree \end{gathered}[/tex]The answer is 64°.
In the diagram below of rhombus ABCD,angle C is 100,what is angle DBC
Answers
Okay, here we have this:
Considering the provided information, that in a rhombus opposite angles are equal, and that the sum of the angles of a triangle is 360 °, we obtain:
360°=100°+100°+4(m∠DBC)
Now, let's clear "m∠DBC":
360°=200°+4(m∠DBC)
4(m∠DBC)=360°-200°
4(m∠DBC)=160°
m∠DBC=160°/4
m∠DBC=40°
Finally we obtain that the correct answer is the option A.
Given that angle A lies in Quadrant IV and cos(A)= 7/10, evaluate sin(A).
Answers
The value of the trigonometric function is; sin(A) =√51/10.
What are trigonometric identities?Trigonometric identities are the functions that include trigonometric functions such as sine, cosine, tangents, secant, and, cot.
We have been given that angle A lies in Quadrant IV and cos(A)= 7/10 then;
cos(A)= 7/10
Hence, base = 7
hypotenuse = 10
Therefore, perpendicular
h² = b² + p²
10² = 7² + p²
100 = 49 + p²
p = √51
Then sin(A = perpedicular/ hypotenuse
sin(A) = √51/10
Hence, the value of the trigonometric function is; sin(A) =√51/10.
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1
Pratap Puri rowed 26 miles down a river in 2 hours, but the return trip took him 6; hours. Find the rate Pratap can row
in still water and find the rate of the current. Let x=rate Pratap can row in still water and y = rate of the current.
What is the rate that Pratap rows in still water?
Pratap can row at a rate of
(Type an integer or a decimal.)
in still water.
Answers
The speed of current will be "4.5 mph" and the rate Pratap can row in still water will be "8.5 mph".
What does "speed" mean in mathematics?
Speed is what it means. the speed of a change in an object's location in any direction. Speed is defined as the ratio of distance to the amount of time it took to cover that distance. Speed is a scalar quantity because it just has a direction and no magnitude.Given:
Distance "26 miles" in time "2 hours".
Let,
Speed of water = y
Pratap speed when rowing in still water = x
As we know,
Speed = distance/time
then,
x + y = 26/2
x + y = 13
x = 13 - y
In return trip took him time "6.5 hours",
x - y = 26/6.5
x - y = 4
By substituting the value of "x", we get
13 - y - y = 4
13 - 2y = 4
2y = 13 - 4
2y = 9
y = 9/4 = 4.5 mph (Rate of the current)
By substituting the value of "y", we get
x = 13 - a
x = 13 - 4. 5 = 8.5 mph (Pratap can row in still water)
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find x..in a right triangle ️ with a height of 10 and hypotenuse of 19
Answers
Since it is a right triangle we can apply the Pythagorean theorem:
c^2 = a^2 + b^2
Where:
c= hypotenuse (the longest side) = 19
a & b = the other 2 legs of the triangle
Replacing:
19^2 = 10^2 + x^2
Solve for x
361 = 100 + x^2
361 - 100 = x^2
261 = x^2
√261 =x
x= 16.16
f (x+2) - 3o vertical shiftvertical stretchhorizontal reflectionhorizontal shiftvertical compressionhorizontal stretchhorizontal compressionvertical reflection
Answers
ANSWER:
[tex]\begin{gathered} (5x+3)\cdot(x+4) \\ x=-\frac{3}{5}\text{ and }x=-4 \end{gathered}[/tex]STEP-BY-STEP EXPLANATION:
We have the following function:
[tex]5x^2+23x+12[/tex]we factor and calculate the roots like this:
[tex]\begin{gathered} (5x+3)\cdot(x+4) \\ (5x+3)=0\rightarrow x=-\frac{3}{5} \\ (x+4)=0\rightarrow x=-4 \end{gathered}[/tex]Therefore the factored form would be
[tex](5x+3)\cdot(x+4)[/tex]And the roots of the functions are - 3/5 and -4
| 5-6x | -12 = 0Solve the absolute. equation for 2 values of x
Answers
Given
[tex]|5-6x|-12=0[/tex]To solve this equation for both possible values of x, you have to separate it into two calculations.
1) One will be for the case that the values inside the absolute term are multiplied by "+1":
[tex]\begin{gathered} 1\cdot(5-6x)-12=0 \\ 5-6x-12=0 \\ -6x+5-12=0 \\ -6x-7=0 \\ -6x=7 \\ -\frac{6x}{-6}=\frac{7}{-6} \\ x=-\frac{7}{6} \end{gathered}[/tex]The first value of x is -7/6
2) The second will be the case that the absolute values are negative, that is as if they are multiplied by -1
[tex]\begin{gathered} (-1)(5-6x)-12=0 \\ -5+6x-12=0 \\ 6x-5-12=0 \\ 6x-17=0 \\ 6x=17 \\ \frac{6x}{6}=\frac{17}{6} \\ x=\frac{17}{6} \end{gathered}[/tex]The second value of x is 17/6
So for this absolute equation, the possible values of x are -7/6 and 17/6
without dividing, how can you tell which quotient is smaller, 30:5 or 30:6 ? eXPLAIN
Answers
Without dividing, we can tell that 30:6 has smaller quotient between 30:5 and 30:6.
According to the question,
We have the following two expressions:
30:5 and 30:6
Now, we can easily find which expression has a smaller quotient when the dividend is the same. We need to look at the divisor. If the dividend is the same then the quotient will be smaller for the one with the greater divisor.
In this case, 30:6 has a greater divisor than 30:5 (6 is larger than 5). So, it will have smaller quotient.
Now, we can prove this by dividing both the expressions.
30/6 = 5
(So, it has smaller quotient.)
30/5 = 6
Hence, 30:6 has smaller quotient than 30:5.
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Use any strategy to determine a combination of apples
and pineapples that will balance the scale.
Explain how you know it will balance.
Answers
1 Pine- apple equal to 9 Apples.
What is Ratio proportion?The divisional comparison of two quantities yields a ratio, and the equality of two ratios yields a proportion.
A ratio is commonly written as "x: y," though it can also be read as "x is to y" or "x/y."
In terms of comparison, a proportional equation says that two ratios are equal.
When x: y: z: w is used to represent a ratio, it is understood to mean that x is to y as z is to w.
In this case, w and Y are not equal to 0, therefore x/y Equals z/w.
6 Apples = 4 Pomegranates
6 Pomegranates = 1 Pine- apple
1 Pine- apple = 9 Apples.
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Which function rule would help you find the values in the table?J K2 -124 -246 -368 -48A k=-12jB k=-6jC k=j - 12D k=j - 6
Answers
Solution
As seen from the table
For each values of the table
We define the variation from K to J
[tex]\begin{gathered} K\propto J \\ K=cJ\text{ (where c is constant of proportionality)} \end{gathered}[/tex]When J = 2, K = -12
[tex]\begin{gathered} K=cJ \\ -12=c(2) \\ 2c=-12 \\ c=-\frac{12}{2} \\ c=-6 \end{gathered}[/tex]Therefore, the formula connecting them will be
[tex]k=-6j[/tex]Option B
Amtrak's annual passenger revenue for the years 1985 - 1995 is modeled approximately by the formulaR = -60|x- 11| +962where R is the annual revenue in millions of dollars and x is the number of years after 1980. In what year was the passenger revenue $722 million?In the years ____ and ___, the passenger revenue was $722 million.
Answers
ANSWER
1987 and 1995
EXPLANATION
The revenue is modeled by:
[tex]R=-60|x-11|+962[/tex]To find the years that the revenue was $722 million, we have to solve for x when R is 722.
That is:
[tex]\begin{gathered} 722=-60|x-11|+962 \\ \Rightarrow722-962=-60|x-11| \\ -240=-60|x-11| \\ \Rightarrow|x-11|=\frac{-240}{-60} \\ |x-11|=4 \end{gathered}[/tex]We can split the absolute value equation into two different equations because the term in the absolute value is equal to both the positive and the negative of the term on the other side of the equality.
That is:
[tex]\begin{gathered} x-11=4 \\ x-11=-4 \end{gathered}[/tex]Solve for x in both:
[tex]\begin{gathered} x=11+4 \\ \Rightarrow x=15 \\ x=11-4 \\ \Rightarrow x=7 \end{gathered}[/tex]That is to say 7 and 15 years after 1980.
Therefore, in the years 1987 and 1995, the revenue was $722 million.
I need help on thisChange the equation into a equivalent equation written in the Slope-intercept form. x -7y + 5 =0
Answers
The slope-intercept form is an equation as follows:
[tex]y=mx+b[/tex]Then, we need to change the original equation in this equivalent:
[tex]-7y=-5-x\Rightarrow-7y=-x-5\Rightarrow7y=x+5[/tex]Dividing the total equation by 7, we have:
[tex]\frac{7}{7}y=\frac{x}{7}+\frac{5}{7}\Rightarrow y=\frac{1}{7}x+\frac{5}{7}[/tex]Therefore, the slope-intercept form is:
[tex]y=\frac{1}{7}x+\frac{5}{7}[/tex]Solve for "x":3x - 5 < -14 or 2x - 1 > 7
Answers
We are given the following inequalities:
[tex]\begin{gathered} 3x-5<-14,(1)\text{ or} \\ 2x-1>7,(2) \end{gathered}[/tex]First, we will solve for inequality 1. To do that we will add 5 to both sides:
[tex]3x-5+5<-14+5[/tex]Solving the operations:
[tex]3x<-9[/tex]Now we divide both sides by 3:
[tex]\frac{3x}{3}<-\frac{9}{3}[/tex]Solving the operations:
[tex]x<-3[/tex]Now we solve for "x" in inequality (2). To do this we will add 1 to both sides:
[tex]2x-1+1>7+1[/tex]Solving the operations:
[tex]2x>8[/tex]Now we divide both sides by 2:
[tex]\frac{2x}{2}>\frac{8}{2}[/tex]Solving the operations:
[tex]x>4[/tex]Therefore, the solution to the system is:
[tex]x<-3\text{ or x > 4}[/tex]Nicholas and Jack volunteer to fill gift boxes for soldiers serving overseas. Both work at a constant rate. They work together for 6 hours and fill 126 boxes. Nicholas fills 9 boxes every hour. How many boxes does Jack fill every hour?
Answers
Firstly, we need to know the number of boxes they both filled per hour.
From the question, we are told that 126 boxes were filled in six hours; thus in an hour, the number of boxes filled will be 126/26 = 21 boxes
Now in an hour, Nicholas filled 9 boxes; the number of boxes that will be filled is clearly the remainder of the 21 boxes.
The number of boxes filled by Jack is thus; 21 - 9 = 12 boxes
Jack fills 12 boxes in an hour
The mean amount of time it takes a kidney stone to pass is 16 days and the standard deviation is 5 days. Suppose that one individual is randomly chosen. Let X = time to pass the kidney stone. Round all answers to 4 decimal places where possible.a. What is the distribution of X? X ~ N(16Correct,5Correct) b. Find the probability that a randomly selected person with a kidney stone will take longer than 17 days to pass it. 0.2Incorrectc. Find the minimum number for the upper quarter of the time to pass a kidney stone. 0.8Incorrect days.
Answers
Answer:
• (a)X ~ N(16, 5)
,• (b)0.4207
,• (c)19.37 days
Explanation:
(a)
• The mean amount of time = 16 days
,• The standard deviation = 5 days.
Therefore, the distribution of X is:
[tex]X\sim N(16,5)[/tex](b)P(X>17)
To find the required probabability, recall the z-score formula:
[tex]z=\frac{X-\mu}{\sigma}[/tex]When X=17
[tex]z=\frac{17-16}{5}=\frac{1}{5}=0.2[/tex]Next, find the probability, P(x>0.2) from the z-score table:
[tex]P(x>0.2)=0.4207[/tex]The probability that a randomly selected person with a kidney stone will take longer than 17 days to pass it is 0.4207.
(c)The upper quarter is the value under which 75% of data points are found.
The z-score associated with the 75th percentile = 0.674.
We want to find the value of X when z=0.674.
[tex]\begin{gathered} z=\frac{X-\mu}{\sigma} \\ 0.674=\frac{X-16}{5} \\ \text{ Cross multiply} \\ X-16=5\times0.674 \\ X=16+(5\times0.674) \\ X=19.37 \end{gathered}[/tex]The minimum number for the upper quarter of the time to pass a kidney stone is 19.37 days.
A plane flies from Oahu and back. Flying to Oahu the plane is flying against the wind and the trip takes 6 hours. On the way back the plane flies with the wind and it takes 5 hours. If the distance one way is 900 miles, what is the speed of the plane in still air and the speed of the wind?
Answers
Answer:
Plane: 165 miles per hour
Wind: 15 miles per hour
Explanation:
Let's call x the speed of the plane in still air and y the speed of the wind.
Additionally, the velocity is equal to distances over time. So, when the plane is flying against the wind, we can write the following equation:
[tex]\begin{gathered} x-y=\frac{\text{distance}}{\text{time}} \\ x-y=\frac{900\text{ miles}}{6\text{ hours}} \\ x-y=150 \end{gathered}[/tex]Because x - y is the total velocity of the plane when it is flying against the wind.
On the other hand, when the plane flies with the wind, we get:
[tex]\begin{gathered} x+y=\frac{900\text{ miles}}{5\text{ hours}} \\ x+y=180 \end{gathered}[/tex]So, we have the following system of equations:
x - y = 150
x + y = 180
Adding both equations, we get:
x - y = 150
x + y = 180
2x + 0 = 330
Solving for x:
2x = 330
2x/2 = 330/2
x = 165
Finally, Replace x by 165 on the second equation and solve for y as:
x + y = 180
165 + y = 180
165 + y - 165 = 180 - 165
y = 15
Therefore, the speed of the plane in still air is 165 miles per hour and the speed of the air is 15 miles per hour.
A game fair requires that you draw a queen from a deck of 52 ards to win. The cards are put back into the deck after each draw, and the deck is shuffled. That is the probability that it takes you less than four turns to win?
Answers
The probability (P) is winning in less than four turns can be decomposed as the following sum:
The probability of winning in one turn is
[tex]P(\text{Winning in turn 1})=\frac{\#Queens}{\#Cards}=\frac{4}{52}.[/tex]The probability of winning in the second turn is
[tex]\begin{gathered} P(\text{ Winning in the second turn})=P(\text{ Lossing (in turn 1)})\cdot P(\text{ Winning (in turn 2)}), \\ \\ P(\text{ Winning in the second turn})=\frac{\#NoQueens}{\#Cards}\cdot\frac{\#Queens}{\#Cards}, \\ \\ P(\text{ Winning in the second turn})=\frac{48}{52}\cdot\frac{4}{52}\text{.} \end{gathered}[/tex]The probability of winning in the third turn is
[tex]\begin{gathered} P(\text{ Winning in the third turn})=P(\text{ Lossing (in turn 1)})\cdot P(\text{ Lossing (in turn 2)})\cdot P(\text{ winning (in turn 3)}), \\ \\ P(\text{ Winning in the third turn})=\frac{\#NoQueens}{\#Cards}\cdot\frac{\#NoQueens}{\#Cards}\cdot\frac{\#Queens}{\#Cards}, \\ \\ P(\text{ Winning in the third turn})=\frac{48}{52}\cdot\frac{48}{52}\cdot\frac{4}{52}\text{.} \end{gathered}[/tex]Adding all together, we get
[tex]\begin{gathered} P(\text{ Winning in less than four turns})=\frac{4}{52}+\frac{48}{52}\cdot\frac{4}{52}+\frac{48}{52}\cdot\frac{48}{52}\cdot\frac{4}{52}, \\ \\ P(\text{ Winning in less than four turns})=\frac{469}{2197}, \\ \\ P(\text{ Winning in less than four turns})\approx0.2135, \\ \\ P(\text{ Winning in less than four turns})\approx21.35\% \end{gathered}[/tex]AnswerThe probability of winning in less than four turns is (approximately) 21.35%.
Unit 6 lesson3 plsss help
Answers
From the triangles ∠ABC ≅ ∠MNP.
Given we have two triangles ABC and PNM
Both triangles have same shape but different angles.
we need to find ∠ABC ≅ ?
we can notice that :
∠A ≅ ∠M
∠B ≅ ∠N
∠C ≅ ∠P
hence these angles are similar to each other.
So, ∠ABC ≅ ∠MNP.
Hence we get the answer as ∠ABC ≅ ∠MNP.
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All lines that cross the x-axis are vertical lines.A. TrueB. False
Answers
Given:
All lines that cross the x-axis are vertical line.
Required:
To find whether the given statement is true or false.
Explanation:
A vertical line is one the goes straight up and down, parallel to the y-axis of the coordinate plane.
The x-intercept is the point at which the graph crosses the x-axis.
Here all lines are not vertical lines.
Therefore the given statement is false.
Final answer:
False.
Find the perimeter and area for each figure.
10.
6 in.
P =
A =
3 in.
6 in.
2 in.
5 in.
11.
7 in.
P =
A =
6 in.
(each side is 6 in.)
Answers
The perimeter and the area of a rectangle of dimensions 15 cm and 8 cm is given as follows:
Perimeter: 46 cm.Area: 120 cm².What are the area and the perimeter of a rectangle?Considering a rectangle of length l and width w, we have that the area and the perimeter are given, respectively, by these following equations:
Area: A = lw.Perimeter: = 2(l + w).In the context of this problem, the dimensions are given/supposed as follows:
l = 15 cm, w = 8 cm.
Applying the rule, the area, in cm², as the variables are multiplied, is given as follows:
A = 15 x 8 = 120 cm².
The perimeter, in cm, as the measures are added, is given as follows:
P = 2 x (15 + 8) = 2 x 23 = 46 cm.
Missing informationThis problem is incomplete and could not be found on any search engine, hence we suppose that it is a rectangle of dimensions 15 cm and 8 cm.
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Angles A and B are supplementary angles. The measure of angle A is
73∘
What is the measure of angle B?
Answers
Answer:
17
Step-by-step explanation:
73+b=90
b=90-73
b=17
the length of a rectangle is 2 inches more than the width. The area is 24 square inches. Find the dimensions
Answers
Given:
length(l) = width(w) + 2
[tex]\text{Area}=24[/tex][tex]l\times w=24[/tex][tex](w+2)w=24[/tex][tex]w^2+2w-24=0[/tex][tex](w+6)(w-4)=0[/tex][tex]w=4\text{ or -6}[/tex]Negative not possible.
[tex]\text{width(w)}=4\text{ inches}[/tex][tex]\text{length(l)}=w+2[/tex][tex]\text{length of the rectangle=4+2}[/tex][tex]\text{length of the rectangle=}6\operatorname{cm}[/tex]The bank requires that customers select a PIN (personal identification number) so ATM’s can be accessed. The PIN must be 3 digits followed by one letter. How many different PIN numbers can be selected if the first digit cannot be zero?
Answers
Answer:
A lot
Step-by-step explanation:
use random numbers from 1 to 9 and or 0, after the first natural number. And different letters, so there is no specific amount to say that can be used.
