Answer:
x = 10.53 m
Explanation:
Let's analyze this problem a bit, the time that the cowboy must take to fall must be the time that the horse takes to arrive
Let's start by looking for the cowboy's time, which starts from rest and the point where the chair is is y = 0
y =y₀ + v₀ t - ½ g t²
0 = y₀ - ½ g t²
t = [tex]\sqrt{ \frac{2 y_o}{g} }[/tex]
we calculate
t = √(2 3.22 / 9.8)
t = 0.81 s
the horse goes at a constant speed
x = [tex]v_{c}[/tex] t
x = 13 0.81
x = 10.53 m
this is the distance where the horse should be when in cowboy it is left Cartesian
The position of the horse from the cowboy must be 10.53 m apart.
The time taken by the cowboy to fall must be equal to the time that the horse takes to arrive at the point where the cowboy falls.
We can calculate the time taken by the cowboy to reach the saddle by applying the second equation of motion
h = ut + (1/2)gt²
here h =3.22m , u = 0m/s as he starts from rest
[tex]t=\sqrt[]{\frac{2h}{g} }\\ t=\sqrt{\frac{2*3.22}{9.8} } [/tex]
t = 0.81 s
the horse goes at a constant speed
x = vt , given that v = 13 m/s
x = 13 × 0.81
x = 10.53 m is the distance where the horse should be when the cowboy jumps.
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A long rope with a knot tied in the middle lies straight along a smooth floor. A student picks up one end of the rope. This sends waves along the rope. a State whether the waves on the rope are transverse or longitudinal waves. b 1 the direction of energy transfer along the rope 2 the movement of the knot.!? Does Enyone know the answer
Answer:
1. Transverse
2. Along the rope from one end to the other.
3. Oscillates in a direction perpendicular to energy transfer.
Explanation:
I majored in Physics
A 1000 kg car moving a 10 m/s collides with a stationary 2000 kg truck. The two vehicles interlock as a result of the collision. What is the final velocity of the two combined vehicles?
Answer:
3.33m/s
Explanation:
Given parameters:
M1 = 1000kg
V 1 = 10m/s
M2 = 2000kg
V2 = 0m/s
Unknown:
Final velocity of the two combined vehicles = ?
Solution:
This is a typical example of an inelastic collision.
Here, it is pertinent that momentum must be conserved;
So;
M1 V1 + M2 V2 = V (M1 + M2)
1000 x 10 + 2000 x 0 = V (1000 + 2000)
10000 = 3000V
V = 3.33m/s
A person weighing 600 N gets on an elevator. The elevator lifts the person 6 m in 10 seconds. How much power was used?
Answer: 3600 J
Explanation:
W = (F)(d)(cosФ)
W = (600 N)(6 m)(cos 1)
W = 3600 J
what is physical quantity
Answer:
a physical quantity is any physical property that can be quantified, that is, be measured using numbers.
Answer: A physical quantity is a property of a material or system that can be quantified by measurement. A physical quantity can be expressed as the combination of a numerical value and a unit. For example, the physical quantity mass can be quantified as n kg, where n is the numerical value and kg is the unit.
What happens when air from the balloon has exited the balloon?
How will motion change?
Answer:
When you release the opening of the balloon, gas quickly escapes to equalize the pressure inside with the air pressure outside of the balloon. The escaping air exerts a force on the balloon itself. ... That opposing force—called thrust, in this case—propels the rocket forward.
If you want to store 160 J of energy in this spring, should you compress it or stretch it?
Answer:
x = 21.7 cm
Explanation:
The energy stored in the spring is given by :
[tex]U=\dfrac{1}{2}kx^2[/tex]
Where
k is spring constant
x is compression or elongation in the spring
Let us assume that the spring constant of the spring is 6740 N/m.
We can find x by using above formula.
[tex]x=\sqrt{\dfrac{2U}{k}} \\\\x=\sqrt{\dfrac{2\times 160}{6740}} \\\\x=0.217\ m[/tex]
or
x = 21.7 cm
Hence, to store 160 J of energy, it must compress 21.7 cm.
How much work can an engine do in 15 minutes if it generates 22 MW of power and has a mass of 330 kg? *
Answer: 1/gk
Explanation: 15(22/330kg) (330/330gk) = 1/gk
The left hemisphere of the brain has which of the following functions?
O A. Processes language
B. Processes positive emotions
C. Focuses on small details
D. All of the above
Answer:
I thing it will option D thanks
(PLEASE HELP ITS DUE SOON ILL MARK BRAINLIEST AND 5 STARS & PLEASE SHOW WORK!!)
(And the answer is not 44 I already tried that and it doesn’t start with 4 either)
What is the term for when the
body loses too many fluids? *
A) bulimia
B) frostbite
C) dehydration
D) all of the above
Answer:
C. Dehydration is the word describing too little body fluids
The total amount of water on Earth
Answer:
The total volume of water on Earth is estimated at 1.386 billion km³ (333 million cubic miles), with 97.5% being salt water and 2.5% being fresh water. Of the fresh water, only 0.3% is in liquid form on the surface.
energy flow diagram of petrol driven lawnmower
I forgot the answer but I read it early
Please help I will mark brainlest .
Answer:
lithium atom
Explanation:
If you search up lithium atom the same atom will come out.
Sorry if it's wrong.
What phenomenon allows the sidewalk to heat up and
cook an egg?
O absorption
O diffraction
O reflection
O transmission
By the processes of heat transfer, the sidewalk absorbs heat by radiation and cooks the egg.
What is heat energy?Heat energy is a form of energy that is due to difference in temperature between two bodies.
Heat energy always flow from hotter to colder bodies
The processes of heat transfer include;
conduction convection radiationThe sidewalk absorbs heat by radiation and cooks the egg.
Learn more about absorption of heat at: https://brainly.com/question/26253561
A 540,000 kg plane is coming in to land at 210 m/s. If it hits a 24,000 kg firetruck that's on the runway, inelastically, what will the final velocity be after the collision?
Answer:
201.06m/s
Explanation:
The solve this problem, we must understand that momentum must be conserved.
This implies that the starting momentum must be the same as the ending momentum. Since we are dealing with an inelastic collision:
Momentum of Plane + Momentum of truck = Momentum of plane + truck
Mp x Vp + Mt x Vt = V(Mp + Mt)
M is the mass
V is the velocity
t is truck
p is the plane
(540000 x 210) + (24000 x 0) = V (540000+24000)
113400000 = 564000V
V = 201.06m/s
If you are givin force and time, you can determine power if you can know.
A. Watts
B. Energy
C. Joules
D. Distance
Answer:
D. Distance
Explanation:
Power is work divided by time. Work is force times distance, therefore you need distance in order to find power.
What is the range of a ball thrown horizontally at 12 m/s if its time of flight is 3.0 s?
Answer:
6
Explanation:
because I did this assignment, :) your welcome
Next time do it by yourself, but here's the answer kid
When many atoms are split in a chain reaction, a large explosion occurs. This is an example of what type of energy conservation.
Nuclear to chemical or Nuclear to mecanical? Why?
Explanation:
Nuclear to chemical is the type of energy conversion that occurs when atoms are split in a chain reaction and a large explosion occurs.
Apilot of mass 70 kg rides a fighter jet The fighter jet moves in a vertical circle of radius 100 m at a constant
‘speed of 120 mis. Determine the force exerted by the seat on the pilot at the top of the circle (note that the pilot is fastened
to the seat)
Answer:
the force exerted by the seat on the pilot is 10766.7 N
Explanation:
The computation of the force exerted by the seat on the pilot is as follows:
[tex]F = Mg + \frac{MV^2}{R}\\\\= 70 \times 9.81 + \frac{70 \times 120^2}{100}\\\\= 10766.7 N[/tex]
Hence, the force exerted by the seat on the pilot is 10766.7 N
A nonconducting spherical shell, with an inner radius of 4.0 cm and an outer radius of 6.0 cm, has charge spread nonuniformly through its volume between its inner and outer surfaces. The volume charge density rho is the charge per unit volume, with the unit coulomb per cubic meter. For this shell rho = b/r, where r is the distance in meters from the center of the shell and b=3.0μC/m². What is the net charge in the shell?
Answer:
the net charge in the shell is 3.7699 × 10⁻⁸ C or 3.7699 × 10⁻² μC
Explanation:
Given that;
Inner radius r = 4.0 cm = 0.04 m
Outer radius R = 6.0 cm = 0.06 m
b = 3.0μC/m² = 3.0 × 10⁻⁶ C/m²
we know that volume density = b/r
Now consider spherical shell inside the given shell with radius r and with of dr
the volume of the spherical shell will be;
dv = 4πr².dr
Now total change in this shell will be;
dQ = P.dv
so
dQ = b/r . 4πr².dr
dQ = b × 4πr.dr
Q = 4πb [tex]\int\limits^R_r {r} \,dx[/tex]
Q = 4πb[ r²/2 ][tex]^R_r[/tex]
Q = 4πb[ R²/2 - r²/2 ]
Q = 2πb[ R² - r² ]
so we substitute our values
Q = 2π×3.0 × 10⁻⁶[ 0.06² - 0.04² ]
Q = 2π×3.0 × 10⁻⁶ × 0.002
Q = 3.7699 × 10⁻⁸ C or 3.7699 × 10⁻² μC
Therefore, the net charge in the shell is 3.7699 × 10⁻⁸ C or 3.7699 × 10⁻² μC
A uniform soda can of mass 0.140 kg is 12.0 cm tall and filled with 0.354 kg of soda (Fig. 9-41). Then small holes are drilled in the top and bottom (with negligi- ble loss of metal) to drain the soda. What is the height h of the com of the can and contents
a. initially
b. after the can loses all the soda?
c. What happens to h as the soda drains out?
d. If x is the height of the remaining soda at any given instant, find x when the com reaches its lowest point .
Answer:
Explanation:
a ) The centre of mass of a can filled completely with any liquid of any mass lies at the center of the can or at height h /2 where h is height of the can . So centre of mass of can of mass .140 kg of height 12 cm will lie at height 6 cm . Similarly center of mass of its content will also lie at height 6 cm that is center point of the content .
Hence overall center of mass of can along with its content will lie at height 6 cm initially .
b )
After the can loses all the soda , can becomes empty . Hence its center of mass will lie at its center again .
c ) Its center of mass remains unchanged as the soda drains out completely .
d ) When soda starts draining out of the can , its lower part becomes heavier than the upper part . Hence its center of mass moves downwards . Its height is lowered . As height of soda is lowered in the can , center of mass also is lowered . It reaches its lowest point when soda in the can reaches half the height or when the can is half filled .
After that center of mass again starts rising upwards until the can is completely empty .
Each of the following statements is related to conductors in electrostatic equilibrium. Choose the words that make each statement correct. HINT (a) The net charge is always zero ---Select--- the surface of an isolated conductor. (b) The electric field is always zero ---Select--- a perfect conductor. (c) The charge density on the surface of an isolated, charged conductor is highest where the surface is ---Select---
Answer:
a) interior, b) inside, c) minor
Explanation:
In this exercise you are asked to select the correct words so that the statements have been correct
Electric charges always repel each other when they are of the same sign, in conductors this has the consequence that charges accumulate on the surface and the interior remains without electric charges. with this we analyze the statements
a) interior
b) inside
c) minor
therefore the phrase would be:
(a) The net charge is always zero ---INTERIOR--- the surface of an isolated conductor.
(b) The electric field is always zero ---INSIDE--- a perfect conductor.
(c) The charge density on the surface of an isolated, charged conductor is highest where the surface is ---MINOR---to)
16.An astronaut, visiting a newly discovered planet, finds the acceleration due to gravity by dropping an objectfrom a height of 1.0 meter and measuring how long it takes the object to hit the ground. If it takes the object0.8 seconds to hit the ground, what is the acceleration due to gravity on th
Answer:
g = 3.125 m/s²
Explanation:
To find the acceleration due to gravity we will use the second equation of motion:
[tex]h = V_{i}t + \frac{1}{2}gt^{2}\\[/tex]
where,
h = height = 1 m
Vi = initial speed object = 0 m/s (object is initially at rest)
t = time taken = 0.8 s
g = acceleration due to gravity = ?
Therefore,
[tex]1\ m = (0\ m/s)(0.8\ s)+\frac{1}{2}g(0.8\ s)^{2}\\\\\frac{2\ m}{0.64\ s^{2}} = g\\\\[/tex]
g = 3.125 m/s²
how can students earn a GED
Answer:
How Can You Earn Your GED?
You must be at least 16 years old to take the GED Test, and you must not be enrolled in high school. ...You must pass all four subject tests in the GED battery of tests, which means scoring at least a 145 on each test (New Jersey requires a score of at least 150 to pass).>Rules
You must be at least 16 years old to take the GED Test, and you must not be enrolled in high school. You should also meet state eligibility requirements for the amount of time you've been out of high school. In some states, you have to be out of high school for at least 60 consecutive days before you're allowed to take the test. Contact the program administrator in your state for more details.
You must pass all four subject tests in the GED battery of tests, which means scoring at least a 145 on each test (New Jersey requires a score of at least 150 to pass). Scores range from 100 to 200 on the 2014 version). A score of 165 on each test is the benchmark for college and career readiness, and you will receive an Honors distinction if you reach this score. The four tests take seven and a half hours total and are administered by computer. You don't have to take them all on the same day, but some states enforce specific time frames for completing the tests. Most questions are multiple choice, although there is also a mix of fill-in-the-blank, drag and drop, and select-an-area questions, as well as an essay question on the Reasoning Through Language Arts section.
If you don't pass a test the first time around, you can retake it, although different states have different requirements for people who need to retake GED tests (such as additional fees or proof of attending a preparation class). Testing accommodations are available for those with disabilities; you can sign up for them through your online account after you register. You usually have to pay to sign up for the tests, but the cost varies from state to state. After you take each test, you will receive your scores within 24 hours. Here are some more details about the score report.
Explanation:
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Two equal in magnitude, positive charges Q are fixed at distance 2d from each other. The third charge, of magnitude q and unknown sign is positioned very carefully into the midpoint on the line connecting the first two charges. Pick the statement which is correct:
a. The third charge will accelerate towards one of the charges.
b. The third charge will be in equilibrium and this equilibrium is stable.
c. The third charge will be in equilibrium and this equilibrium is unstable.
d. The third charge will be in equilibrium. This equilibrium is stable if charge is positive and unstable if charge is negative.
e. All these statements are wrong.
Answer:
the correct one is d
Explanation:
To answer which statement is correct, let's look for the force on the third charge
F = F₁₃ + F₂₃
force is electric force
F = [tex]k \frac{q_1 q_2}{r^2}[/tex]
In the exercise we are told that the distance between the two charges is 2d, therefore the distance of each charge to the third is x = d and the two falls have a car Q
F₁₃ = k q Q / d²
F₂₃ = k q Q / d²
suppose that charge 3 is positive for which the forces are repulsive
F = k q Q / d₂ - k q Q / d₂
F = 0
suppose that the charge 3 is negative for which the forces are of attraction
F = -k q Q / d₂ + k q Q / d₂
F = 0
We can see that regardless of the sign of charge 3 the forces on it are zero, so it has no acceleration, it is in equilibrium.
Let's analyze the type of equilibrium, for this we move the charge 3 towards one of the sides
charge 3 positive
the force towards the approaching side increases and the other decreases, therefore the load has a net force towards the center, in that case the equilibrium is stable
negative charge 3
The force towards the approaching side is stronger and more attractive and the other decreases, therefore it has an attractive net force that carries it towards the charge, it is closer, in this case the balance is unstable
To review the different answers, the correct one is d
Use one of the following formulas to solve distance:
speed=d/t
*Hint: You will have to manipulate the formula
At dinner you got mad and threw your burrito at a speed of 4 m/s. It flies for 18 seconds through the air. How much distance did the burrito
cover?
Answer:
72m
Explanation:
Given parameters:
Speed of the Burrito = 4m/s
Time = 18s
Unknown:
Distance covered by the flying Burrito = ?
Solution:
Speed is the rate of distance covered per unit of time.
Speed = [tex]\frac{distance}{time}[/tex]
Distance = Speed x time
So;
Distance = 18 x 4 = 72m
What is the relationship between mass and
potential energy?
An object initially at rest experiences an acceleration
of 1.4 m/s for 5.0 s and then travels at that
constant velocity for another 6.0 s.
Part A
What is the object's average velocity over the 11 s interval?
Answer:
1.4m/s
Explanation:
Average velocity is the total distance covered divided by the total time taken.
Average velocity = [tex]\frac{total distance }{time }[/tex]
Total time taken = 5s + 6s = 11s
The first distance covered = velocity x time = 1.4 x 5 = 7m
second distance covered = velocity x time = 1.4 x 6 = 8.4m
So;
Average velocity = [tex]\frac{7 + 8.4}{11}[/tex] = 1.4m/s
Brent is a crime scene investigator. Which two documents must he attach to every item of evidence?
With every item of evidence, Brent fills out a(n)
0, which includes the case number, description of the evidence, names of the suspect(s) and/or
victim(s), date and time and signatures of the investigator and witnesses. He also fills out the
document to ensure that the whereabouts of the
evidence is accounted for at all times.
WE
Reset
Next
Answer:
1. evidence log
2. chain of custody
Explanation:
plato
Evidence log and chain of custody are two documents must he attach to every item of evidence.
What are evidence logs and chain of custody?A chain of custody log is used to demonstrate that the integrity of the evidence was upheld from the time it was seized until it was produced in court. Chain of custody logs provides information on the collection, examination, and preservation of data for production.
Evidence logs keep track of the operations carried out when Event Data was being created. Together with the Evidence Records, they should be read. Evidence logs are compiled every day and consist of a series of entries, each of which describes a specific action.
Therefore, he should attach an evidence log and chain of custody to every item of evidence.
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Now complete your visual overview by identifying the known variables and the variables you must find. Assume charge 1 is located at the origin of the x axis and the positive x axis points to the right. Let x1, x2, and x3 denote the positions of charge 1, charge 2, and charge 3, respectively. Determine which of the following quantities are known and which are unknown.
Answer:
Explanation:
From the given information;
If we assume that charge 1 is located at the origin;
Then, using the visual overview for identification, we will realize that the known quantities are:
[tex]\mathbf{= q_1, \ q_2 , \ q_3, \ x_1 \ and \ x_2}[/tex]
However, provided that we do not know the exact location of [tex]x_3[/tex],
Then, the unknown quantity is [tex]\mathbf{ x_3}[/tex]
