If you're marking the fish tank up by 20%, it means you're looking to sell it at 120% of its original value.
Now, let's use a rule of three to calculate such percentage:
Thereby,
[tex]x=\frac{120\cdot35}{100}\rightarrow x=42[/tex]The selling price would be $42
solve the equation and check the solution:7x - 7 = 13 + 12x
we have the equation
7x - 7 = 13 + 12x
solve for x
Group terms
12x-7x=-7-13
Combine like terms
5x=-20
x=-20/5
x=-4Verify
substitute the value of x=-4 in the original expression
7(-4)-7=13+12(-4)
-28-7=13-48
-35=-35 -------> is ok
New York City mayor Michael made it his mission to reduce smoking in New York City. New York city’s adult smoking rate is 13.2%. In a random sample of 3932 New York City residents, how many of those people smoke? Round to the nearest integer
519 people smoked
Explanation
to figure out this we need to find teh 13.2 % of 3932
so
Step 1
Convert 13.2% to a decimal by removing the percent sign and dividing by 100
then
[tex]13.2\text{ \%}\rightarrow\frac{13.2}{100}\rightarrow0.132[/tex]Step 2
now, multyply the number by the percentage ( in decimal form),so
[tex]\begin{gathered} 13.2\text{ \% of 3932=0.132}\cdot3932=519.04 \\ \text{rounded} \\ 519 \end{gathered}[/tex]therefore, the answer is
519 people smoked
I hope this helps you
It takes 2000 bees 1 year to make 7 jars of honey. How long will it take 5000 bees to make 70 jars of honey?
If the bees are working at the same rate, the number of years taken to make 70 jars is 4 years.
What is the rate of jar making by a bee?
The rate at which a bee makes a jar is calculated as follows;
rate = 2000 bees / 7 Jars
rate = 285.71 b/J
The later of rate of the bees is calculated as follows;
rate = 5000 bees / 70 jars
rate = 71.42 b/J
If the bees were to maintain the first rate, the number of years taken to make 70 jars is calculated as follows;
number of years = (285.71) / (71.42) = 4 years
Learn more about rate of work here: https://brainly.com/question/1144815
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I’ve been stuck for a while and it logged me out:(
Solution
A polynomial is a function in the form of ; where n is non- negative integers which is known as the degree of polynomial. from this definition, it is clear that only option (2) √2 x -1 , is polynomial. because coefficient of variables ; √2, -1 are real number and also power of variable is non-negative integer.
I have selected the options , the ones I have ticked are polynomials, while the one cancelled are none polynomials:
Which expression is equivalent to 8 - (-5) ?O 8+50 -8 +(-5)O 8+-5O -5 +8
Answer:
The first option is correct
[tex]8+5[/tex]Explanation:
[tex]\begin{gathered} 8--5 \\ \\ 8+5 \\ \end{gathered}[/tex]Two negatives makes a positive.
PLEASE HELP I WILL MARK BRAINLIEST!!Which of the following equations is a linear function?A) 2x + 3y = 6B) y = x^2 + 1C) y=x^3D) x^2 + y^2 = 9
Given data:
The given sets of equations.
The polynomial in which degree of the variable is 1 is said to be linear expression.
The first option 2x+3y=6 is only linear function.
Thus, the option (A) is correct.
Type the correct answer in each box.1020PX1150Parallel lines pand gare cut by two non-parallel lines, mand n, as shown in the figure.►gmnThe value of xisdegrees, and the value of y isdegrees.ResetNext
EXPLANATION
Given the parallel lines that are cutted by two non-parallel lines, m and n, the supplementary angle to 102 degrees is by the supplementary angles theorem 180-102= 78 degrees.
By the alternate interior angles theorem, the value of x is 78 degrees.
Also, by the corresponding angles theorem, the value of y is 115 degrees.
A)what height was the basketball thrown from? B)what is the maximum height the basketball went ?C)after how many seconds did the basketball reach its maximum height?D)how many seconds did it take for the basketball to hit the ground ? make sure you look at the exact value in the graph?pleaseeeeeeeeeeeeeeee
We have the following:
The questions can be found thanks to the graph of the statement
A)what height was the basketball thrown from?
The graph starts at the point (0, 6) therefore the basketball was thrown from 6 feet height
B)what is the maximum height the basketball went ?
The highest point of the graph is (2, 10), therefore the maximum height is 10 ft
C)after how many seconds did the basketball reach its maximum height?
The highest point of the graph is (2, 10), therefore the time it reached this height was 2 seconds
D)how many seconds did it take for the basketball to hit the ground ? make sure you look at the exact value in the graph?
The ground would be when the value of y is equal to 0, therefore according to the point (5.162, 0) the time was 5.162 seconds
When a projectile is launched at an initial height of H feet above the ground at an angle of theta with the horizontal and initial velocity is Vo feet per second. the path of the projectile...
Given,
The initial height of H feet.
The initial velocity of the object is Vo.
The equation of the path of projectile is,
[tex]y=h+x\text{ tan }\theta-\frac{x^2}{2V_0\cos ^2\theta}_{}\text{ }[/tex]This is the expression of the projectle path.
Hence, the path of the projectile object is y = h + xtan(theta) - x²/2V₀²cos²(theta)
33Select the correct answer from each drop-down menu.A75°B40°AoIn the figure, line segment AB is parallel to line segment CD.СDdegreesThe measure of angle Cisdegrees, and the measure of angles Dis>254075ResetNext
Answer:
Angle C = 40 degrees
angle D = 75 degrees
Explanation:
From the information given,
Angle A = 75 degrees
Angle B = 40 degrees
AB is parallel to CD. This means that AD and BC are transversals.
Angles A and D have similar positions but they are opposite sides of the transversal. This means that they are alternate angles. Alternate angles are congruent. Thus,
angle D = 75 degrees
Angles B and C have similar positions but they are opposite sides of the transversal. This means that they are alternate angles. Alternate angles are congruent. Thus,
Angle C = 40 degrees
Explain why (-1)^n = 1 for any even number n.How is this possible? I thought it would equal -1. Does that mean the answer is "not possible"?
The expression (-1)^n means the number -1 multiplies itself n times.
So for example if n = 2, we have that:
[tex](-1)^2=(-1)\cdot(-1)=1[/tex]For n = 3, we have:
[tex](-1)^3=(-1)\cdot(-1)\cdot(-1)=1\cdot(-1)=-1[/tex]For n = 4:
[tex](-1)^4=(-1)^2\cdot(-1)^2=1\cdot1=1[/tex]We can see that the result alternates from -1 and 1, and when n is odd, the result is -1, and when n is even, the result is 1.
So for any even number n, the result will be 1.
The area of a rectangular garden is 289 square feet. The garden is to be enclosed by a stone wall costing $22 per linear foot. The interior wall is to be constructed with brick costing $9 per linear foot. Express the cost C, to enclose the garden and add the interior wall as a function of x.
the area of the rectangular garden is 289 square ft
so
[tex]x\times y=289[/tex]so the value of y is 289/x
the outer perimeter of the garden is 2(x+y)
now perimeter is 2(x+289/x)
it is given that the outer wall cost 22 $ per linear foot
so the total cost is
[tex]\begin{gathered} 22\times2(x+\frac{289}{x}) \\ 22\times(2x+\frac{578}{x}) \end{gathered}[/tex]it is given that the cost of an interior wall is 9 $
and the length of the interior wall is x
the total cost of the interior wall is 9x
so the total cost of the wall is 9x +22 (2x + 578/x).
and the correct answer is 9x +22 (2x + 578/x). option B.
you are standing 200 feet from a tall building . The angle from your feet to the top of the building is 51°.
the sum of angles in a triangle is 180
missing angle + 90 + 51 = 180
missing angle = 180 - 141
missing angle = 39 degrees.
in the triangle,
[tex]\frac{x}{200}=\tan 51[/tex]x = 200 tan51
x = 200 * 1.234
x = 246.97 ft apporx 247 ft
'so the length x = 247 ft
that is greater than 200
so the answer is
x > 200 ft
Identify the slope and y-intercept of equation 5x-3y=9
To identify the slope and y-intercept, we will take the given equation to its slope-intercept form:
[tex]y=mx+b,[/tex]where m is the slope and b is the y-intercept.
To take the equation to its slope-intercept form, we add 3y to the given equation:
[tex]\begin{gathered} 5x-3y+3y=9+3y, \\ 5x=9+3y\text{.} \end{gathered}[/tex]Now, we subtract 9, and get:
[tex]5x-9=3y\text{.}[/tex]Finally, dividing by 3, we get:
[tex]y=\frac{5}{3}x-3.[/tex]Therefore, the slope and y-intercept are:
[tex]\frac{5}{3},\text{ and -3 }[/tex]correspondingly.
Answer:
Slope:
[tex]\frac{5}{3}\text{.}[/tex]Y-intercept:
[tex]-3.[/tex]answer yes or no and explain why or why not.if a/5 = 8 + 9, does a/5 + 9 = 8 + 9?
Equations
We are given the following equation:
a/5 = 8+ 9
Adding 9 to both sides of the equation we have:
a/5 + 9 = 8 + 9 + 9
It's evident that a/5 + 9 is not equal to 8 + 9, but to 8+9+9 instead.
Answer: No
Laura, a sandwich maker, produces 80 sandwiches on average per day. How many sandwiches will she produce in pdays?Number of sandwiches =
Number of sandwiches = 80p
Explanation:Given:
Laura produces 80 sandwiches per day
To find:
The number of sandwiches that will be produced in p days
1 day = 80 sandwiches
p days = 80 × p
p days = 80p
This means that she will produce 80p number of sandwiches in p days
111. 12 people fit comfortably in a 5 feet by 5 feet area. Use this value to estimate the size of a crowd that is 25feet deep on both sides of the street along a 3-mile section of a parade route (Hint: 1 mile - 5 280 ft)
Answer:
The estimated crowd is of 380160 people.
Step-by-step explanation:
We solve this question applying a proportion on the following format:
People divided by area.
Let's do the drawing:
12 people fit comfortably in a 5 feet by 5 feet area.
So
12 people fitting in an area of 5*5 = 25 ft².
Area of the street:
3 miles = 3*5280 ft = 15840 ft
25 feet on both sides. So, the total area in which the crowd is sparsed is:
A = 15840*25*2= 792000 ft².
Now we apply the ratio:
People over area.
[tex]\frac{12}{25}=\frac{x}{792000}[/tex]Applying cross multiplication:
25x = 12*792000
x = (12*792000)/25
x = 380160
The estimated crowd is of 380160 people.
Puppets made by each puppeteer43ASCNumber of puppetsAsMYCol?0AlexKalinBruceMarcoMYPuppeteerProIf the mean of the data set is 3 puppets, find the number of puppets Marco made.ProTeapuppets
Remember that we can get the mean of a dataset by adding up each datum and dividing such sum by the number of data.
Now, let's call the number of puppets Marco made M
This way, we would have that:
[tex]\frac{1+4+3+M}{4}=3[/tex]Solving for M :
[tex]\begin{gathered} \frac{1+4+3+M}{4}=3 \\ \\ \rightarrow\frac{8+M}{4}=3 \\ \\ \rightarrow8+M=12\rightarrow M=12-8 \\ \Rightarrow M=4 \end{gathered}[/tex]Therefore, we can conclude that Marco made 4 puppets.
If y varies directly with x and y=12when.x=9 what is the value of x when y=36?
y varies directly with x
y=kx
y=12, x=9
12=k9
Solve for k:
12/9 =k
y= 12/9x
For y=36
36 = 12/9 x
Solve for x:
36 /(12/9)= x
27=x
x=27
if the radius of the circle is 5 units, find the arc length of RQ
The radius of the circle is r = 5 units.
The formula for the arc length of RQ is,
[tex]RQ=2\pi r\times(\frac{\theta}{360})[/tex]Substitute the values in the formula to obatin the arc length RQ.
[tex]\begin{gathered} RQ=2\pi\cdot5\cdot(\frac{142}{360}) \\ =12.391 \\ \approx12.39 \end{gathered}[/tex]So arc length of RQ is 12.39 units.
what is 1 5/8 + 2 1/3=
1 5/8 + 2 1/3
= 3 23/24
Explanation:1 5/8 + 2 1/3
= 1 + 2 + 5/8 + 1/3
= 3 + 23/24
= 3 23/24
3x + 9 ≤ 30answer the solution
EspañolAt a football game, a vender sold a combined total of 249 sodas and hot dogs. The number of sodas sold was 55 more than the number of hot dogs sold. Findthe number of sodas sold and the number of hot dogs sold.Number of sodas sold:Number of hot dogs sold:1Х5?
Given:
Vender sold a combined total of 249 sodas and hot dogs.
The number of sodas sold was 55 more than the number of hot dogs sold.
Let x and y be the number of sodas and hot dogs sold.
[tex]x+y=249\ldots\text{ (1)}[/tex][tex]x=y+55\ldots\text{ (2)}[/tex]Substitute equation (2) in (1)
[tex]y+55+y=249[/tex][tex]2y=249-55[/tex][tex]2y=194[/tex][tex]y=97[/tex][tex]x=97+55[/tex][tex]x=152[/tex]Number of sodas sold is 152.
Number of hot dogs sold is 97.
if you could please answer quickly my brainly app keeps crashing
In this case, we'll have to carry out several steps to find the solution.
Step 01:
Data:
diagram:
circle and chords
Step 02:
congruent chords:
Congruent chords are equidistant from the center of a circle.
x = 7 + 7
x = 14
The answer is:
x = 14
Make a scatter plot of the data. Scale the x-axis by ones and the y-axis by twos.
Answer
Age of Car in years is represented as x
Avg. Miles per Gallon is represented as y
y = 0.97x + 1.214
Correlation Coefficient = 0.673
Explanation
Age of Car in years is represented as x
Avg. Miles per Gallon is represented as y
The datapoints are fed into a calculator and plotted with the datapoints also processed according to some formulas that'll be provided here
The first figure contains the data points and the regression data processed to be used to calaculate the required parameters.
The second attached image shows the plotted data and the line of best fit and the equation that best represents the relationship between the two parameters.
Then the last image shows the parameters used to calculate the equation of correlation and the correlation coefficient.
Hope this Helps!!!
I need help with this question please. Just do question 1 please. Also this is just apart of a homework practice
Answer:
P(x) = 1.3x² + 0.1x + 2.8
Explanation:
We need to find an equation that satisfies the relationship shown in the table. So, let's replace x by 2 and then compare whether the value of p(x) is 8.2 or not
P(x) = 1.3x³ + 0.1x² + 2.8x
P(2) = 1.3(2)³ + 0.1(2)² + 2.8(2)
P(2) = 16.4
Since P(2) is 16.4 instead of 8.2, this is not a correct option
P(x) = 1.3x² + 0.2x - 2.8
P(2) = 1.3(2)² + 0.2(2) - 2.8
P(2) = 2.8
Since 2.8 and 8.2 are distinct, this is not the correct option
P(x) = 2.3x² + 0.2x + 1.8
P(x) = 2.3(2)² + 0.2(2) + 1.8
P(x) = 11.4
Since 11.4 and 8.2 are distinct, this is not the correct option
P(x) = 1.3x² + 0.1x + 2.8
P(2) = 1.3(2)² + 0.1(2) + 2.8
P(2) = 8.2
Therefore, this is the polynomial function for the data in the table.
So, the answer is P(x) = 1.3x² + 0.1x + 2.8
Which description is paired with its correct expression?
O seven less than the quotient of two and a number squared, increased by six;
Onine times the difference of a number cubed and three, 9(n²-3)
7-+8
O eight more than the quotient of a number squared and four, decreased by seven;
Otwice the difference of a number cubed and eight, 27³-8
8+/-7
Answer:
seven less than the quotient of two and a number squared increased by six
7 - (2/n²) + 6
nine times the difference of a number cubed and three; 9(n³-3)
eight more than the quotient of a number squared and four, decreased by seven; 8 + (4 /n²) - 7
twice the difference of a number cubed and eight; 2 n³- 8
Step-by-step explanation:
west high schools population is 250 students fewer than twice the population of east high school. the two schools have a total of 2858 students. how many students attend east high school?
From properties of linear equation, 1036 students attend east high school.
What is linear equation?
An algebraic equation with simply a constant and a first-order (linear) term, such as y=mx+b, where m is the slope and b is the y-intercept, is known as a linear equation.
Let east high school have x students
West high school have 2x - 250
Total count of students from both the schools are 2858 students.
Then we get
x + 2x-250 = 2858
=> 3x - 250 = 2858
=> 3x = 2858 + 250
=> 3x = 3108
=> x = 3108/3
=> x = 1036
Therefore, 1036 students attend east high school.
To learn more about linear equation from the given link
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24. A rocket is launched into the air. Its height in feet, after x seconds, is given by the equation The starting height of the rocket is h(x)=-16x’ +300x + 20 The maximum height is The rocket hits the ground after seconds.
Well we just need to do the analise of the function h, so for the first question we need to know what is the value of h when x=0, so if we evaluate we see that
[tex]h(0)=-16(0)^2+300(0)^{}+20^{}=20^{}[/tex]So the first answer is that the start heigth of the rocket is 20.
Now for the second we need to do the derivate and see the critical ponit to know the maximum, we are going to calculate first the derivate, so
[tex]h^{\prime}(x)=-32x^{}+300[/tex]now we need to find the critical ponits so for this, we are going to see when h'(x) = 0, this meand when the derivate is equal to zero, so h'(x) = 0 when
[tex]\begin{gathered} -32x\text{ + 300 =0} \\ 300\text{ = 32x} \\ \frac{300}{32}=x \end{gathered}[/tex]to see if this critical poni is a maximum we need to calculate the secon derivate and see that the second derivate valued in 300/32 is smaller than 0, so
[tex]h^{\doubleprime}(x)\text{ = -32}[/tex]now when x= 300/32 we have that h''(x) is -32 because the second derivate is constant, in this case h''(300/32) < 0, because of this the answer is that 300/32 is the maximum, bur 300/32 = 75/8.
Now for the third question, we need to see the roots of h, so we need to see when h is zero, so for wich values of x we have that h(x) = 0, then
[tex]-16x^2+300x+20=0^{}[/tex]we can solve this with the quadratic equation to solve this kind of equations. This equation is
so we have that
[tex]\begin{gathered} x\text{ = }\frac{-300\text{ }\pm\sqrt[]{300^2\text{ -4(-16)20}}}{2(-16)} \\ x\text{ = }\frac{-300\text{ }\pm\sqrt[]{90000\text{ + 1280}}}{-32} \\ x\text{ = }\frac{-300\text{ }\pm\sqrt[]{91280}}{-32} \end{gathered}[/tex]the answer is x = (-300 - v/ 91280)/(-32) or x = (-300 + v/ 91280)/(-32) and this is equal to x = (300 + v/ 91280)/(32) or x = (300 - v/ 91280)/(32) if you prefer. We can also write the answer in a simpler way: x = (75 + v/ 5705)/(8) or x = (75 - v/ 5705)/(8), this is
[tex]x\text{ = }\frac{75\text{ }\pm\sqrt[]{5705}}{8}[/tex]Well we just need to do the analise of the function h, so for the first question we need to know what is the value of h when x=0, so if we evaluate we see that
[tex]h(0)=-16(0)^2+300(0)^{}+20^{}=20^{}[/tex]So the first answer is that the start heigth of the rocket is 20.
Now for the second we need to do the derivate and see the critical ponit to know the maximum, we are going to calculate first the derivate, so
[tex]h^{\prime}(x)=-32x^{}+300[/tex]now we need to find the critical ponits so for this, we are going to see when h'(x) = 0, this meand when the derivate is equal to zero, so h'(x) = 0 when
[tex]\begin{gathered} -32x\text{ + 300 =0} \\ 300\text{ = 32x} \\ \frac{300}{32}=x \end{gathered}[/tex]to see if this critical poni is a maximum we need to calculate the secon derivate and see that the second derivate valued in 300/32 is smaller than 0, so
[tex]h^{\doubleprime}(x)\text{ = -32}[/tex]now when x= 300/32 we have that h''(x) is -32 because the second derivate is constant, in this case h''(300/32) < 0, because of this the answer is that 300/32 is the maximum, bur 300/32 = 75/8.
Now for the third question, we need to see the roots of h, so we need to see when h is zero, so for wich values of x we have that h(x) = 0, then
[tex]-16x^2+300x+20=0^{}[/tex]we can solve this with the quadratic equation to solve this kind of equations. This equation is
so we have that
[tex]\begin{gathered} x\text{ = }\frac{-300\text{ }\pm\sqrt[]{300^2\text{ -4(-16)20}}}{2(-16)} \\ x\text{ = }\frac{-300\text{ }\pm\sqrt[]{90000\text{ + 1280}}}{-32} \\ x\text{ = }\frac{-300\text{ }\pm\sqrt[]{91280}}{-32} \end{gathered}[/tex]the answer is x = (-300 - v/ 91280)/(-32) or x = (-300 + v/ 91280)/(-32) and this is equal to x = (300 + v/ 91280)/(32) or x = (300 - v/ 91280)/(32) if you prefer. We can also write the answer in a simpler way: x = (75 + v/ 5705)/(8) or x = (75 - v/ 5705)/(8), this is
[tex]x\text{ = }\frac{75\text{ }\pm\sqrt[]{5705}}{8}[/tex]suppose that you have two square garden plots: One is 10’ x 10’ and the other is 15 x 15’. You want to cover both gardens with a 1 inch layer of mulch. If the 10 x 10 garden took 3 1/2 bags of mulch, could you calculate how many bags of mulch you need for the 15 x 15 garden by setting up the following proportion 3.5/10 = X/15. explain clearly why or why not. If the answer is no is there another proportion that you could set up? it may help you to make drawings of the Gardens
Answer:
Step-by-step explanation:
This question can be solved using a rule of three.
For each configuration, we need the perimeter and the amount of bags of mulch.
For a square of side s, the perimeter is P = 4s
If the 10 x 10 garden took 3 1/2 bags of mulch:
10x10 means that s = 10.
So the perimeter is:
P = 4*10 = 40
The number of bags of mulch is:
3 1/2 = 3 + (1/2) = 3 + 0.5 = 3.5
15 x 15 garden
15x15 means that s = 15.
The perimeter is: P = 4*s = 4*15 = 60.
The number of bags is X.
Now applying the rule of three:
With the number of bags and the perimeter.
3.5 bags - 40'
X bags - 60'
Now we apply cross multiplication:
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