Your quality ratings for this week are 88, 93, 70, 62 and 100 My average is

Answer:

Step-by-step explanation:

lol

By using the graph, the amount of snacks that the charity must sell if 10 seats are sold is equal to 40 snacks.

In order to graphically solve the equation, we would write an equation that models the situation by assigning variables to the cost of seats and cost of snacks, and then translate the word problem into algebraic equation as follows:

Since the seats cost $32 each and snacks cost an additional $8 each while the charity needs to raise $640, an equation that models the situation is given by;

32s + 8y = 640

By critically observing the graph, the charity must sell 40 snacks if 10 seats are sold.

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Answer:

10.41

Step-by-step explanation:

Given ,

To Find : Number of Fuel used

Let us take the Number of fuel used as 'x'

13.01 = x + 2.60

x = 13.01 - 2.60

x = 10.41

Hence, the fuel used by Lashonda is 10.41

Part A (decorator’s fee)

y = 0.12 x 1580

$189.6

Part B(tax)

y = 0.045 x 1580

$71.1

Part C(Total amount spent)

$1,580 + $189.6 + $71.1

$1840.7

A linear equation is an equation in which the highest power of the variable is always 1. It is also known as a one-degree equation. The standard form of a linear equation in one variable is of the form Ax + B = 0. Here, x is a variable, A is a coefficient and B is constant. The standard form of a linear equation in two variables is of the form Ax + By = C. Here, x and y are variables, A and B are coefficients and C is a constant.

Part A (the decorator’s fee)

12% of purchases = 0.12

y = 0.12 x 1580

Decorator's fee = $189.6

Part B (the tax)

4.5% Tax = 0.045

y = 0.045 x 1580

Tax = $71.1

Part C (Total amount spent)

Purchasing fee + Decorators fee + Tax

= $1,580 + $189.6 + $71.1

$1840.7

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Answer:

I'd say A, Adjacent

Step-by-step explanation:

I think its A because adjacent means together/along with, and these angles are next to each other.

The perimeter and area of the image:

(a)  3/2cm²

(b)  2/3cm²

(c)  3/8cm²

What is the perimeter of a trapezoid?

A trapezoid's perimeter is determined by adding the lengths of its four sides. The sum of the lengths of a trapezoid's four sides serves as the formula for the shape's perimeter.

Here,

We have to find the perimeter and area of the image when the trapezoid is dilated by a scale factor of (a) 2, (b) 3, and (c) 4.

(a)  Ratio 2: 1 of length

Perimeter = (2 + 5 + 3 +6)/2 = 8cm

Area = (1/2)×3×(6+2)/2×(1/2)² = 3/2cm²

(b) Ratio 3:1

Perimeter = (2 + 5 + 3 +6)/3 = 16/3cm

Area = (1/2)×3×(6+2)/2×(1/3)² = 2/3cm²

(c) Ratio 4:1

Perimeter = (2 + 5 + 3 +6)/4 = 4cm

Area = (1/2)×3×(6+2)/2×(1/4)² = 3/8cm²

Hence, The perimeter and area of the image: (a)  3/2cm², (b)  2/3cm², and (c)  3/8cm²

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Answer:

Step-by-step explanation:

is that the question? what do you mean by 3

Answer:

998

Step-by-step explanation:

Answer:

Step-by-step explanation:

The slope of a line perpendicular to a given line is the negative reciprocal of the slope of the given line. To find the slope of the line x - 6y = 24, we can rearrange the equation to the form y = (1/6)x + 4. So the slope of the line is 1/6.

The slope of a line perpendicular to this line would be the negative reciprocal of 1/6 which is -6

10,000 records have 30 predictor variables, each with 5% of the values missing, resulting in 15,000 missing values. The predictive model drops any row with even a single missing value, so 5,000 records would be dropped from the analysis.

1. There are 30 predictor variables.

2. Each variable has 5% of the values missing.

3. 5% of 10,000 records = 500 records.

4. 30 variables x 500 records = 15,000 missing values.

5. 10,000 records - 15,000 missing values = 5,000 records dropped from the analysis.

The data set has 10,000 records and 30 predictor variables. Each variable has 5% of the values missing, so 500 records are missing for each variable. This results in 15,000 missing values spread randomly and independently throughout the data set. The analyst uses a predictive model that drops any row (record) with even a single missing value, so 5,000 records would be dropped from the analysis.

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Answer:

Step-by-step explanation:

x = 16

Answer:

x = 16

Step-by-step explanation:

If 3 · 16 = 48 Then x = 16

63.64% is the percentage of the area of the square.

The square is a 4 sided figure, each side of the square is equal and make a right angle.

The area of square having sided a unit can be given by a² square unit.

Given that,

The radius of the circle r =  1 in.

The area of the circle = π r² = π (1)² = π = 22/7 inch.

Also the area of square = 1/2 x (diameter)²

The diameter of the square = 2r = 2

Area = 1/2(2)² = 2 square in.

The required percentage = (2 / (22/7)) x 100 = (7 / 11) x 100 = 700 / 11 = 63.6363.

The percentage of the area of the square is 63.64%.

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The total members of the chess club at the school, given the number of teachers, can be found to be 25 students.

When the teachers joined the members of the chess club for a tournament, the number of members that Alan counted was 31 people which means that the number of members in the chess club would be this number, less the number of teachers.

The number of chess club students is therefore :

= Number of people counted by Alan - Number of teachers

= 31 - 6

= 25 members

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This statement is not always true. It's only true if f(x) and g(x) are both non-decreasing functions.

If f(x) and g(x) are non-decreasing functions, the inequality f(x) ≥ g(x) for a < x < b holds, meaning that the values of f(x) are always greater than or equal to the values of g(x) for x within the interval [a,b]. Since the derivative of a non-decreasing function is non-negative, it follows that f'(x) ≥ 0 and g'(x) ≥ 0 for all x in the interval [a,b], which implies f '(x) ≥ g'(x) for a < x < b.

However, if f(x) and g(x) are not non-decreasing functions, this statement is not true. The inequality f(x) ≥ g(x) for a < x < b does not necessarily imply that the derivatives f '(x) and g'(x) will also be greater than or equal for all x in the interval [a,b].

Therefore, This statement is not always true. It's only true if f(x) and g(x) are both non-decreasing functions.

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The graph attached represents a non proportional function

Like the name goes, a Linear graph is a straight line graph that represents a linear relationship with the equation of the form

y = mx + c

A relationship is proportionate if its graph is a line or ray that passes through the origin. in this case c = 0

It is not proportional if the line or graph does not go through the origin.

Additionally, if anything is not linear, it is not proportional.

The attached graph passed through point (0, 1) which is not the origin (0, 0) hence the graph is not a proportional relationship

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By algebra properties, the integer 975 is equivalent to rational expression 650 / (2 / 3).

Rational numbers are real numbers of the form m / n, where m and n are integers and n is a non-zero integer. In this problem we find a rational expression of the form (a / b) / (c / d), where a, b, c, d are also integers and b and d are non-zero integers.

This expression must be simplified into a rational number of the form m / n, this can be done by the following algebra property:

(a / b) / (c / d) = (a · d) / (b · c)

If we know that a = 6, b = 1, c = 2 and d = 3, then the resulting expression is:

650 / (2 / 3) = (650 / 1) / (2 / 3) = (650 ÷ 1) / (2 ÷ 3) = (650 × 3) / (1 × 2) = 1950 / 2 = 975 / 1 = 975

The rational expression 650 / (2 / 3) is equivalent to integer 975.

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Answer:

Step-by-step explanation:

12 is 40% of what number?

30.

what is 60% of 30?

18

boom

The average rate of change in concentration of B from t=0 s to t=282 s is equals to the 0.00440 M/s.

Average rate of change in concentration is defined as the change in concentration divided by change in time , i.e , ∆c/∆t. Since we have provide the concentrations of reactant (A), we can determine the average change in A first. In first observation, Change in [A] = 0.410 - 0.720 M = - 0.310 M

Change in time = 141 s - 0 s = 141 s

rate of Change in concentration

= -0.310/141 = - 0.00220 M/s

In second observation, rate of change in concentration A =(0.100 - 0.410)/(282 - 141)

= - 0.310/141 = - 0.00220 M/s

Average Rate = - 0.310 M / 141s

= - 0.00220 M/s

here, negative sign indicating the [A] is decreasing over time.

To determine the average rate of change of B, we use the stoichiometry of the equation, A⟶2B

For every A that is used, 2 B's are produced (product). So, average rate of change of B = 2 x 0.00220

= +0.00440 M/s

(positive sign means B is being formed).

So, required average rate of change is 0.00440 M/s.

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Complete question:

determine the average rate of change in concentration of b from t=0 s to t=282 s. A⟶2B

Time (s). Concentration of A (M)

0. 0.720

141. 0.410

282. 0.100

Answer: x= [tex]5\frac{1}{2}[/tex]

Step-by-step explanation:

[tex]\frac{x}{6} = \frac{11}{12} \\x(12)=11(6)\\12x=66\\\frac{12x}{12} =\frac{66}{12} \\x=\frac{11}{2} \\x=5\frac{1}{2}[/tex]

(you should cross-multiply the numbers)

(if the numerator is greater than the denominator then you  

                      should leave the answer as a mixed fraction)

Answer:

x= 11/2 or 5.5

Step-by-step explanation:

x/6 = 11/12

LCM = 12

=12 × x/6 = 12 × 11/12

=2(x) = 11 Note. 6 goes into 12 "2" and 12 goes into 12 "1"

=2x = 11

=2x/2 11/2

x = 11/2 or 5.5.

we need for 500 grams of sugar, we can plug 500 into the equation for our value of s. This gives us f = 300 * 500/200 = 750 grams.

1. f = 300s/200

2. f = 300 * 500/200 = 750 grams

1. To write the equation, we can set up a ratio that compares the number of grams of flour to the number of grams of sugar. Since the recipe calls for 300 grams of flour for every 200 grams of sugar, we can set up the equation as f = 300s/200, where f is the number of grams of flour and s is the number of grams of sugar.

2. To find out how many grams of flour we need for 500 grams of sugar, we can plug 500 into the equation for our value of s. This gives us f = 300 * 500/200 = 750 grams.

To write the equation, we can set up a ratio that compares the number of grams of flour to the number of grams of sugar. Since the recipe calls for 300 grams of flour for every 200 grams of sugar, we can set up the equation as f = 300s/200, where f is the number of grams of flour and s is the number of grams of sugar.

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Answer:
750

Equation:
f = 3/2s

The end behavior of each function is defined as follows:

1. [tex]\sqrt{6x}[/tex]: as x -> ∞, f(x) -> ∞.

2. [tex]\sqrt{x - 5} - 6[/tex]: as x -> ∞, f(x) -> ∞.

3. [tex]-3\sqrt{x + 3} + 7[/tex]: as x -> ∞, f(x) -> -∞.

The end behavior of a function is given by the limit of the function is the input x goes to either negative infinity or positive infinity.

The functions in this problem are all variations of the square root function, which is defined only for non-negative numbers, and thus only the limit when x goes to infinity has to be considered.

As x goes to infinity, the square root goes to infinity, which already define the end behavior for items 1 and 2.

For item 3, the negative leading coefficient means that the function is reflected over the x-axis, assuming a negative value, and thus the end behavior is that the function goes to negative infinity.

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Answer:

i don't know

Step-by-step explanation:

The letters corresponding to the solutions are: x = 10, x = -3/2, x = -1/9, x = -6, x = 10/3 That gives you the letters "joke"1.  5x – 7 = 4x + 3.

To solve for x, we can add 7 to both sides of the equation and subtract 4x from both sides:

5x - 7 + 7 = 4x + 3 + 7

5x = 4x + 10

x = 10

2.  6 + 2x = 7x - 9

To solve for x, we can add 9 to both sides of the equation, subtract 6 from both sides and divide both sides by -1:

6 + 2x + 9 = 7x - 9 + 9

2x = -3

x = -3/2

3. 8x + 1 = -8 - x

To solve for x, we can add x to both sides of the equation and add 8 to both sides:

8x + 1 + x = -8 - x + x + 8

9x + 1 = 0

x = -1/9

4. -5 + 12x = 18x + 7

To solve for x, we can subtract 12x from both sides of the equation and add 5 to both sides:

-5 + 12x - 12x = 18x + 7 - 12x

-5 = 6x + 7

x = -6

5.  -4x + 3 = 5x - 13 - x

To solve for x, we can add x to both sides of the equation, subtract 3 from both sides and divide both sides by -1:

-4x + 3 + x = 5x - 13 - x + x + 3

-3x = -10

x = 10/3

The letters corresponding to the solutions are: x = 10, x = -3/2, x = -1/9, x = -6, x = 10/3

That gives you the letters "joke"

Therefore, The letters corresponding to the solutions are: x = 10, x = -3/2, x = -1/9, x = -6, x = 10/3 That gives you the letters "joke"1.  5x – 7 = 4x + 3.

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Answer:

B

D

E

The first choice A appears to be a typo, so I can't comment on that

Step-by-step explanation:

Substitute x = 4 in each of the polynomials and see which ones end up with a value of 0. Since each of the polynomials is a multiplicative of expressions if any one of the individual expressions is 0 then the whole expression becomes 0

A. Unknown

B. 2x - 8 = 2 · 4 - 8 = 8 - 8 = 0. So this has a zero at (4,0)

C None of the individual expressions will result in  0. So not a correct choice

D x - 4 = 4 - 4 = 0 So this is a correct choice

E. In this case we have a 4-x term which is 4- 4 = 0; so correct choice

(111)₂ = (12)₅

The base of a number system refers to the total number of digits that are actually used in the given number system. The number system that has the base 'b' consists of its digits in the [0, b-1] range. This base of the number system is also known as the radix of a number system.

Given,

number 111 with base 2

To convert it into base 5 number we need to first convert it into decimal

(111)₂ = 1×2²+1×2¹+1×2⁰

(111)₂ = 4+2+1

(111)₂ = (7)₁₀

Now converting decimal to base 5, converting decimal numbers to base 5 is nearly as simple: just divide by 5.

(111)₂ = (12)₅

Hence, the number becomes (12)₅.

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The amount of sandwiches purchased in total is 27.

The term "system of equations" or "equation system" in mathematics refers to a finite set of equations for which common solutions are sought. A set of simultaneous equations is sometimes known as a system of equations or an equation system.

Let the sandwiches be represented as x.

Let the fries be represented as y and drinks be represented as z.

The total cost is given as $100, that is:

x + y + z = 100 (equation 1)

Drinks and fries' cost $73.27, this can be written as:

y + z = 73.27 (equation 2)

Substitute the value of y + z = 73.27 in equation 1:

x + 73.27 = 100

x = 100 - 73.27

x = 26.73

The total amount spent on sandwiches is $26.73.

One sandwich cost $0.99.

The number of sandwiches purchased in $26.73 is:

n = 26.73/ 0.99

n = 27

Hence, the total number of sandwiches purchased is 27.

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Answer: 35

Step-by-step explanation:

35*140%=49

The angle which corresponds the ∠8 is ∠4 as ∠8 and ∠4 are parallel to each other.

What are parallel lines ?

parallel lines can be defined as the lines which are equi distant from each other and these lines never interest to each other.

Given ,

from the figure

the parallel lines are l and m.

the angles ∠1,∠2,∠3,∠4,∠5,∠6,∠7,∠8.

∠1,∠2,∠3,∠4. are in one plane

and ∠5,∠6,∠7,∠8. are in another plane.

so the angle which corresponds the ∠8 is ∠4 as ∠8 and ∠4 are parallel to each other.

Hence ,  the angle which corresponds the ∠8 is ∠4 as ∠8 and ∠4 are parallel to each other.

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The error is [tex]12x^2 - 14x = - 26x^2[/tex] because 12x² and 14x are unlike terms, so we can not add them

To prevent it the dividend must be written as [tex]6x^3 + 0x^2 - 14x + 1[/tex]

Now, According to the question:

In the division, you must arrange the dividend according to the greatest power of the variable, and put 0 as a coefficient of the missing term to avoid adding, unlike terms.

Example:

If the dividend is [tex]3x^3 - 2x + 5[/tex], then you must write it as [tex]3x^3 + 0x^2 - 2x + 5[/tex]

Let us solve our question

∵ The dividend is [tex]6x^3[/tex] + 1 - 14x

→ You must arrange it from the greatest power of x

∴ The dividend is [tex]6x^3[/tex] - 14x + 1

∵ The term of x² is missing

→ Write it in the dividend with a coefficient of 0

∴ The dividend is  [tex]6x^3 + 0x^2 - 14x + 1[/tex]

The error is the adding of unlike terms

∵  [tex]6x^3[/tex]- 14x + 1 ÷ 3x + 6 = 2x² and [ [tex]6x^3[/tex] - 14x + 1 - [tex]6x^3[/tex] - ( [tex]6x^3[/tex] + [tex]12x^2[/tex])]

∵[tex][6x^3 - 14x + 1 - 6x^3 - (6x^3 + 12x^2)] = 6x^3 - 14x + 1 - 6x^3 - 12x^2[/tex]

∵ [tex]6x^3 - 14x + 1 - 6x^3 - 12x^2 = 0 - 12x^2 - 14x + 1[/tex]

∵[tex]0 - 12x^2 - 14x + 1 = -26x^2 + 1[/tex] ⇒ error

∴ The error is  -12x² - 14x = - 26x² because 12x² and 14x are unlike terms,

  so we can not add them

→ To prevent it, write 0 as a coefficient of the missing term

∵ The missing term is the term of x²

∴ Add to the dividend the term 0x²

∴ The dividend must be written as [tex]6x^3 + 0x^2 - 14x + 1[/tex]

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The value of y'' at the point where x=0 is[tex]9 e y^{\prime \prime}=\frac{1}{9 e}$[/tex] ([tex]e^{2}[/tex])

Differentiation is one of the two important concepts apart from integration. Differentiation is a method of finding the derivative of a function. Differentiation is a process, in maths, where we find the instantaneous rate of change in function based on one of its variables. The most common example is the rate change of displacement with respect to time, called velocity. The opposite of finding a derivative is anti-differentiation.

If x is a variable and y is another variable, then the rate of change of x with respect to y is given by dy/dx. This is the general expression of derivative of a function and is represented as f'(x) = dy/dx, where y = f(x) is any function.

[tex]$x y+9 e^y=9 e$[/tex]

at [tex]x =0[/tex]

[tex]$9 e^y=9 e$[/tex]

[tex]$y=1$[/tex]

[tex]$w \cdot r . t x$[/tex]

[tex]$\left(y+x y^{\prime}\right)+9 e^y y^{\prime}=0[/tex]

at [tex]x=0[/tex]

[tex]$1+9 e y^{\prime}=0$[/tex]

[tex]$y^{\prime}=-\frac{1}{9 e}$[/tex]

[tex]$--------$[/tex]

[tex]$\left(y+x y^{\prime}\right)+9 e^y y^{\prime}=0$[/tex]

[tex]y^{\prime}+x y^{\prime \prime}+y^{\prime}+9 e^y y^{\prime \prime}+9 e^y\left(y^{\prime}\right)^2=0[/tex]

at [tex]x=0[/tex]

[tex]2\left(-\frac{1}{9 e}\right)+9 e y^{\prime \prime}+9 e\left(-\frac{1}{9 e}\right)^2=0[/tex]

[tex]-\frac{2}{9 e}+9 e y^{\prime \prime}+\frac{1}{9 e}=0[/tex]

[tex]9 e y^{\prime \prime}=\frac{1}{9 e}$[/tex][tex]\left(e^2)\right[/tex]

Therefore, the value of y'' at point where x=0 is [tex]9 e y^{\prime \prime}=\frac{1}{9 e}$[/tex]  ([tex]e^{2}[/tex])

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