10. ABC.Per=1200 NNet Force:Pit=600 NEngen-SONFrid=20 NPry=800 NPrax=800 NF50NWhich situation above would best describe free fall velocity?Which situation above would best describe a crane lifting an object?If situation C had a Fapp of 40N to the right, the net force on the object would beIf situation Chad Fapp of 20N to the right, the forces would be (balanced, unbalanced) and thehorizontal velocity would be (constant, + accelerating, - accelerating). Circle the correct terms

Given data

The mass of the toy car is m = 2 kg

The speed of the car is v = 3 m/s

The radius of the circular track is r = 2 m

The centripetal force is always in the same direction as that of the centripetal acceleration.

The centripetal acceleration direction is towards the center of the circle, towards west.

Therefore, the direction of the centripetal force points to the west direction.

Thus, the direction of the centripetal force at this instant is towards the west.

Given that the operating voltage is V = 120 V.

The initial temperature of the toaster is T1 = 20 degrees Celsius

The initial current in the coil is I1 = 1.5 A

The final current in the coil is I2 = 1.3 A

The thermal coefficient of resistivity for nichrome is

We have to find the final temperature of the coil, T2.

The initial resistance of the coil is

The final resistance of the coil is

The formula to calculate the final temperature of the coil is

Substituting the values, the final temperature will be

Thus, the final temperature is 360 degrees Celsius.

The mass on Earth is 91.1 kg

The weight on the Moon is 148 N

The weight on the Earth is 893 N

We need to apply the concept of force.

Weight=massxacceleartion

893=mass of man x acceleration of gravity on earth

893= mass x 9.8

mass = 91.1 kg

Therefore, the mass on earth is 91.1 kg.

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Answer:

the mass on Earth is 91.1 kg

Explanation:

We are given a car that is experiencing a centripetal force.

The formula for the force is given by:

Where "m" is the mass, "v" is the velocity and "r" is the radius. Now we solve for the mass, first by multiplying both sides by r:

Now we divide by the velocity squared:

Now we replace the known values:

Solving the operations:

Therefore, the mass is 1500 kg.

Given

v = 2.90 mi/h

x = 1.20 mi

vs = 2.0 mi/h

θ = 25°

Procedure

Part a)

Velocity of the boat with respect to water stream is given as

magnitude of the speed is given as

Part b)

Time to cross the river is given as:

Part c)

Distance moved by boat in downstream is given as

Part d)

In order to go straight, we must net speed along the stream must be zero

so we will have

b. insulator.

The others describe a type of transfer of energy

Answer:

b. p = mv

Explanation:

The momentum is the mass in motion, so it is calculated as the mass times the velocity. It means that the equation to calculate the momentum is

p = mv

Where m is the mass and v is the velocity of the object.

So, the answer is

b. p = mv

ANSWER:

39.1 km

STEP-BY-STEP EXPLANATION:

To better understand the problem, we make a sketch, like this:

Therefore, we can determine the distance east with the cosine function, like this:

The distance to the east is 39.1 km

Force = Mass * Acceleration = kg* m/s^2= MLT^-2

Distance = metres= L

Energy = MLT^-2 * L =ML^2T^-2

The range, R, of a projectile motion is directly proportional to the horizontal component of the initial velocity as given by the formula,

Where u_x is the horizontal component of the initial velocity and t is the time of flight of the projectile.

The range of a projectile is directly proportional to the square of the initial velocity as given by,

Thus the initial speed increases, the range of the projectile increases.

Lorentz magnetic force is the force exerted on a charged particle 'q' which moves with a velocity 'v' through a magnetic field B. The Lorentz forces exerted by moving charges on one another are not equal and opposite.

Given:

Charge, q = [tex]10^{-6}[/tex] C

Velocity, v = (3i + 4j) m/s

Magnetic field, B = 1i T.

To find: Magnetic force, F.

From Lorentz force law, the magnetic force is given by,

F = q × (v × B)

Substituting the given values,

F =  [tex]10^{-6}[/tex] × ((3i + 4j) × 1i)

Since i×i = 0, and j×i = k,

F =  [tex]10^{-6}[/tex] × 4k

∴ F = 4 × [tex]10^{-6}[/tex] k newtons.

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M = mass of the boy = 55kg

V = initial velocity of the boy = 12 m/s

m= mass of stationary skateboard = 15kg

v= velocity os stationary sketeboard= 0 m/s

V' = velocity of the boy on the skateboard after collision

Conservation of momentum:

MV + mv = (M + m) V'

Replacing:

55 kg * 12 m/s + 15 kg *0 = (55 kg+ 15 ) V'

Solve for V´'

660 = 70 V´'

660/70 = V'

V'= 9.42 m/s

Answer:

Its a acceleration will increase

Explanation:

The force required to keep an object in a circular motion is given by

where v is the radial velocity and R is the radius of the object with mass m.

Now our question is what happens to the above equation as we decrease R?

We can see that as R decreases the quantity mv^2 /R increases (since R is getting smaller ).

Hence, we conclude that F increases. But what if F? it is the centripetal force.

Since centripetal force has increased, so has the quantity v^2 /R (called the acceleration ).

Meaning an increase in centripetal force implies an increase n acceleration.

Since in the answer choices we are not given the option to increase our centripetal force, the next best choice is to choose 'acceleration will increase. '

Answer:

Explanation:

Given:

m = 2.5 kg

V = 10 m/s

__________

Wk - ?

Wk = m·V² / 2

Wk = 2.5·10² / 2 = 125 J

To transmit the same amount of electricity, there is a 2.5 W power loss.

A power loss is the difference in power between a device, piece of equipment, pump set, or process' input and output (Pv). Pumps, equipment, and procedures, as well as electrical and electronic devices, turn this undesirable loss into heat.

Consumers receive electric energy in different units than what power plants create. A fraction of the units is lost in the distribution network. This difference between the distributed and created units is referred to as transmission and distribution loss.

According to Ohm's law, power can be defined as

P = VI

Here,

V = Voltage

I = Current

replacing

100kW = 10WI

I = [tex]\frac{100}{10}[/tex]

I = 10 Amp

Now we can find the resistance

R = [tex]\frac{P_{LOSS} }{I^{2} }[/tex]

Replacing,

R = [tex]\frac{1000}{10^{2} }[/tex]

R = 10Ω

In the second state when the voltage is 200kv, we have,

I = [tex]\frac{100*10^{3} }{200*10^{3} }[/tex]

I= [tex]\frac{100000}{200000}[/tex]

I= 0.5 A

Now power loss,

[tex]P_{t}[/tex] = [tex]I^{2}[/tex]R

[tex]P_{t}[/tex] = ([tex]0.5^{2}[/tex]) (10)

[tex]P_{t}[/tex] = 0.25 *10

[tex]P_{t}[/tex] =2.5 W

As a result, 2.5W is needed to transport the same amount of electricity.

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ANSWER

False

EXPLANATION

Sound waves travel by causing vibrations in particles in the direction of the wave and these vibrations can travel through any state of matter (solid, liquid, gas).

This means that if the vibrations occur faster, the sound waves can also be transmitted faster. On a warm day, the temperature is higher, which means that molecules of air vibrate faster, resulting in faster transmission of sound waves.

Therefore, it is false that sound travels faster on a cold day than on a warm day.

According to Law of Universal Gravitation, the graph between Force and distance is hyperbolic as the force depends sqaure of the distance. Therefore, the correct option is (4).

The speed is given as;

Here, d is the distance covered and t is the time.

Harry Hand covers a distance of 100 m (d_H) in 20 s (t_H). Therefore, the speed of the Harry Hand is,

Substituting all known values,

Now, Linda Hand covers a distance of 50 m (d_L) in 8.5 s (t_L). Therefore, the speed of Linda Hand is given as,

Substituting all known values,

Since the speed of Linda Hand is greater than Harry Hand (v_L>v_H). Therefore, Linda Hand is faster.

when sound wave go from small passages like the edge of a wall or from the slit of open door the sound wave diffracts.

So the 3rd option is correct option.

In memory, the process in which after reading your textbook, you are able to maintain the bold, key words in coded representations in a network of neurons in your brain is called storage.

In memory there are three phases. They are:

In the given scenario, the process in which converting the bold, key words to coded representations is encoding process. The process which maintains the coded representations in a network of neurons in your brain is storage. The process of remembering the information stored when needed is retrieval.

Therefore, in memory, this process is called Storage

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The velocity of the car between time 11 hr and 15 hr which is shown in the graph would be 4 m/s².

The direction of a body or object's movement is defined by its velocity. In its basic form, speed is a scalar quantity. In essence, velocity is a vector quantity. It is the speed at which distance changes. It is the displacement change rate.

We are given that,

Displacement of the car = Δx = (20km) - (4km) = 16 km

Time interval of the car = Δt = (15h)- (11h) = 4hours

v = dx/dt

dx = v dt

∫dx = ∫v dt

Δx = v Δt

v = Δx/Δt

Therefore, for get the value of velocity between the given time interval , putting the value in in above equation,

v = 16km/4hours

v = 4 km/hours

Thus, The velocity of the car between time 11 hr and 15 hr will be given as 4km/hours.

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The linear velocity of the ball whose angular velocity is 31.3 rad/s about the elbow joint will be 45.385 m/s.

Angular velocity is the rate of change of angular displacement with respect to time. Mathematically -

ω = dθ/dt

from this we can write -

dθ = ω dt

∫dθ = ω ∫dt

θ₂ - θ₁ = ω(t₂ - t₁)

Δθ = ω Δt

ω = Δθ/Δt

Given is a ball thrown from a net on the end of a stick by rotating the stick and forearm about the elbow. The angular velocity of the ball about the elbow joint is 31.3 rad/s and the ball is 1.45 m from the elbow joint.

The relation between linear velocity and the angular velocity of a body undergoing circular motion is given by -

v = rω

From this we can write -

ω = 31.3 rad/s

r = 1.45 m

Substituting the values -

v = rω

v = 1.45 x 31.3

v = 45.385 m/s

Therefore, the linear velocity of the ball whose angular velocity is 31.3 rad/s about the elbow joint will be 45.385 m/s.

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The wavelength, period and velocity are related by the equation:

where λ is the wavelength and T is the period. In this case the wavelength is 3.5 m and the period is 0.5 s; plugging these values we have:

Therefore, the speed of the wave is 7 m/s

The angle between the components x and y of a vector is given by:

once we know this we need to find in which quadrant the vector lies so we know how to calculate the correct direction.

Vector A lies in the fourth quadrant this means that we need to subtract theta to 360° in order to get the direction of the vector, then we have:

Therefore the direction of vector A is 343.61°

Vector B lies in the second quadrant, this means that we need to subtract theta (given by the first equation) to 180° in order to get the direction, then we have:

Therefore the direction of vector B is 105.26°

Let's find vector A+B:

Then we have that:

To find its magnitude we have to remember that the magnitude of any vector is given by:

Then for vector A+B we have:

Therefore the magnitude of vector A+B is 5.38 meters.

Vector A+B lies in the first quadrant, then its direction is given by the expression for theta, then we have:

Therefore the direction of vector A+B is 48.01°

The maximum static friction between two surfaces is greater than the kinetic friction between them.

If the wheels of a car get locked, the surface of the wheel slides through the floor and kinetic friction acts to stop the car.

If the wheels of the car don't get locked, they may turn fast enough to prevent the surface of the wheel from sliding through the floor and static friction acts on the car.

Since the force acting on the car with its wheel locked is less than the force acting on the car with the turning wheels, then, the stopping distance is greater for driver 1 than for diver 2.

Therefore, the answers are:

a) The stopping distance of driver 1 is greater than the stopping distance of driver 2.

b) The best explanation is:

3. Locked-up brakes lead to sliding (kinetic) friction, which is less than rolling (static) friction.

The velocity of the particle at 0 s and at 1.0 and the average velocity between 0 s and 1.0

a)[tex]\vec{V}(0)=0 m / s[/tex]

[tex]\vec{V}(1)=(8 \hat{\imath}+6 \hat{k}) m / s[/tex]

b)[tex](4 \hat{\imath}+2 \hat{k}) \mathrm{m} / \mathrm{s}[/tex]

This is further explained below.

Generally, the equation for the Position is mathematically given as

F(t) = 4.01²î - 3.0ĵ +2.03 km.

Therefore

[tex]\begin{aligned}&\vec{r}(t)=\left(4 t^2 \hat{l}-3 \hat{\jmath}+2 t^3 \hat{k}\right) m \\&\vec{V}(t)=\frac{d \vec{r}(t)}{d t}=\left(8 t \hat{\imath}+6 t^2 \hat{k}\right) m / s\end{aligned}[/tex]

For A

[tex]\begin{aligned}&\vec{V}(0)=0 m / s \\&\vec{V}(1)=(8 \hat{\imath}+6 \hat{k}) m / s\end{aligned}[/tex]

For B

[tex]\text { Average velocity } &=\frac{\text { Total displacement }}{\text { time interval }} \\[/tex]

[tex]=\frac{\vec{r}(1)-\vec{r}(0)}{1} \\&=4 \hat{\imath}-3 \hat{\jmath}+2 \hat{k}-\left(-3 \hat{\jmath}^{\prime}\right) \\&=(4 \hat{\imath}+2 \hat{k}) \mathrm{m} / \mathrm{s}\end{aligned}[/tex]

In conclusion, The speed of the particle at 0 seconds and at 1.0 seconds, as well as the average speed between 0 seconds and 1.0 seconds

a)[tex]\vec{V}(0)=0 m / s[/tex]

[tex]\vec{V}(1)=(8 \hat{\imath}+6 \hat{k}) m / s[/tex]

b)[tex](4 \hat{\imath}+2 \hat{k}) \mathrm{m} / \mathrm{s}[/tex]

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From the information given,

initial velocity of parachute = 198 ft/s

We want to convert 198 ft/s to m/s

Recall,

1 m = 3.3 ft

x m = 198 ft

By crossmultiplying, we have

3.3x = 198

x = 198/3.3

x = 60

Thus,

198 ft/s = 60 m/s

Rate = 60 m/s

To determine the distance that the parachute will fall in 10 seconds, we would apply one of Newton's equations of motion which is expressed as

s = ut + 1/2gt^2

where

s = distance covered

u = initial velocity

t = time

g = acceleration due to gravity and its value is - 9.8m/s^2

From the information given,

t = 10

u = 60

By substituting these values into the formula, we have

s = 60 x 10 - 1/2 x 9.8 x 10^2

s = 600 - 490

s = 110

The distance covered by the parachute in 10s is 110 m

We will have the following:

neutral object becomes charged by losing electrons.

If the car does not brake, its mechanical energy will be conserved along all its trajectory.

Then, the sum of the kinetic energy (K) of the car and its gravitational potential energy (U) will be the same for any two points in the trajectory:

The kinetic energy of an object with mass m and speed v is:

The gravitational potential energy of an object with mass m at a height h above a reference level, is:

Where g is the acceleration of gravity.

In the beginning, the car has a height of 10m and a speed of 10m/s. In the end, the car reaches the gas station at a height 15m and a unknown speed v.

Then, the initial speed and height are known, as well as the final height. Use the equation for the conservation of mechanical energy to isolate v_2, the unknown final speed of the car:

Replace v_1=10m/s, h_1=10m, h_2=15m and g=9.8m/s^2 to find the speed of the car as it reaches the gas station:

Therefore, the car's speed as it coasts into the gas station on the other side of the valley will be approximately 1.4 meters per second.

Yellow liquid:

Mass = 470 g

Volume = 450ml

Pink liquid

Mass= 570 g

Volume= 450ml

Volumes are equal (450ml) and masses are different (470g and 570g)

A. The liquids have the same volume and different masses.