Answer:
2.5m
Explanation:
Speed/velocity = 0.5m/s
Time = 5s
speed = Distance/Time
Distance = Speed x Time
Distance = 0.5 x 5
Distance = 2.5m
The Demon Drop ride at the amusement park falls freely for 1.8 s after
starting from rest.
What is its displacement the end of 1.8 s?
Answer:
Explanation:
a = -g = -9.80 m/s squared
d o = 0
v o = 0
t = 1.8s
unkown:d = ?
v = ?
[Please help :^)]
Hello! I have a kinetic and potential energy project due soon, and I need to write a paragraph about that stuff, but I’m not really sure how to write the paragraph. If you can, please write a paragraph that I can rephrase and use. Thank you!!
Answer:
the potentail of kinetic and potential energy
Explanation:
first explain the concept of kinetic energy (what it is and what its used for) and give examples (cars, a basketball thrown across a hall, and airplane), and do the same with potential energy (the energy an object stores, example: a streched rubber band)
Can someone spell the word hi for me I’ll give you 30 points
Answer:
hi poop
Explanation:
"Hi"
its spelled with an H & an I :^
A 25 kg rock falls for 1.7 seconds. How many meters tall
was the building?
Description:
So if a 25 kg rock is falling 1.7 seconds.
2.7 + 1/2 9.8 m/s² 2.7 s)
= 35.72m²
Equations:
v = 0 m/s
a = 9.8 m/s²
t = 2.7
Answer: 35.72 m
Hope this helps.
A rock weighing 20 N (mass = 2 kg) is swung in a horizontal circle of radius 2 m at a constant speed of 6 m/s. What is the centripetal force acting on the rock?
A. 18 N
B. 360 N
C. 36 N
D. 180 N
Answer:
what do u need help with
Explanation:
B. 360 N
12. A rocket, initially at rest on the ground, accelerates vertically. It accelerates uniformly until it
reaches a speed of 900 m/s after 30 s. After this period of uniform acceleration, the rocket
engine cuts out. During the next 90 s, the upward speed of the rocket decreases uniformly to
zero.
speed
m/s
times
plot a speed-time graph for the rocket for the first 120 s of it's flight
Answer:
We kindly invite you to read carefully the explanation and check the image attached below.
Explanation:
According to this problem, the rocket is accelerated uniformly due to thrust during 30 seconds and after that is decelerated due to gravity. The velocity as function of initial velocity, acceleration and time is:
[tex]v_{f} = v_{o}+a\cdot (t-t_{o})[/tex] (1)
Where:
[tex]v_{o}[/tex] - Initial velocity, measured in meters per second.
[tex]v_{f}[/tex] - Final velocity, measured in meters per second.
[tex]a[/tex] - Acceleration, measured in meters per square second.
[tex]t_{o}[/tex] - Initial time, measured in seconds.
[tex]t[/tex] - Final time, measured in seconds.
Now we obtain the kinematic equations for thrust and free fall stages:
Thrust ([tex]v_{o} = 0\,\frac{m}{s}[/tex], [tex]a = 30\,\frac{m}{s^{2}}[/tex], [tex]t_{o} = 0\,s[/tex], [tex]0\,s\le t< 30\,s[/tex])
[tex]v = 30\cdot t[/tex] (2)
Free fall ([tex]v_{o} = 900\,\frac{m}{s}[/tex], [tex]a = -9.807\,\frac{m}{s}[/tex], [tex]t_{o} = 30\,s[/tex], [tex]30\,s \le t \le 120\,s[/tex])
[tex]v = 900-9.81\cdot (t-30)[/tex] (3)
Now we created the graph speed-time, which can be seen below.
The number of particles outside the nucleus in the neutral atom will always equal to…?
Answer:
2,8,8
Explanation:
im not sure really what you asking but is it this the shells
A 2.5 g marshmallow is placed in one end of a 40 cm pipe, as shown in the figure above. A person blows into the left end of the pipe to eject the marshmallow from the right end. The average net force exerted on the marshmallow while it is in the pipe is 0.7 N. The speed of the marshmallow as it leaves the pipe is most nearly
Answer:
15 m/s
Explanation:
Given:
F = 0.7N m = 0.25g = 0.0025kg x = 40cm = 0.4m [tex]v_{0}[/tex] = 0
Since F = ma, a = F/m = 0.7N/0.0025kg = 280m/[tex]s^{2}[/tex]
Using the Big Five, [tex]v ^{2} = v_0^{2} + 2ax[/tex], [tex]v = \sqrt{0 + 2*280m/s^2*0.4m} = \sqrt{216} m/s= 15m/s[/tex]
We have that for the Question it can be said that the speed of the marshmallow as it leaves the pipe is most nearly
v=15m/s
From the question we are told
A 2.5 g marshmallow is placed in one end of a 40 cm pipe, as shown in the figure above. A person blows into the left end of the pipe to eject the marshmallow from the right end. The average net force exerted on the marshmallow while it is in the pipe is 0.7 N. The speed of the marshmallow as it leaves the pipe is most nearly
Generally the equation for the acceleration is mathematically given as
[tex]a=\frac{Force}{mass}\\\\a=\frac{F}{m}\\\\Therefore\\\\a=\frac{0.75}{0.0025}\\\\a=280m/s^2\\\\[/tex]
Using Newtons
V^2=u^2+2as
V^2=2(280)*0.4
v=15m/s
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wo ships, one 200200 metres in length and the other 100100 metres in length, travel at constant but different speeds. When travelling in opposite directions, it takes 1010 seconds for them to completely pass each other. When travelling in the same direction, it takes 2525 seconds for them to completely pass each other. The speed of the faster ship, in metres per second, is
Answer:
The speed of the faster ship is 22.5 m/s
Explanation:
The length of the ships are;
Ship 1 = 200 m
Ship 2 = 100 m
The time it takes for the ships to completely cross each other when travelling in opposite directions = 10 seconds
The time it takes both ships to cross each other when travelling in the same direction = 25 seconds
Let x represent the speed of the first ship, ship 1, and y represent the speed of the second ship, ship, 2, we have;
(x + y) × 10 = 200 + 100 = 300
10·x + 10·y = 300...(1)
(x - y) × 20 = 200 + 100 = 300
20·x - 20·y = 300...(2)
Multiply equation (1) by 2, to get;
(x + y) × 10 × 2 = 300 × 2
20·x + 20·y = 600...(3)
Adding equation (1) to equation (3) gives;
20·x + 20·y + 20·x - 20·y = 600 + 300
40·x = 900
x = 900/40 = 22.5
x = 22.5
The speed of the first ship, ship 1 = x = 22.5 m/s
From equation (1), we have;
10·x + 10·y = 300
y = (300 - 10·x)/10 = (300 - 10×22.5)/10 = 7.5
y = 7.5
The speed of the second ship, ship 2 = y = 7.5 m/s
Therefore, the faster ship is ship 1 with a speed of 22.5 m/s
How much work is done when an 8 N force moves a block 7m ?
Answer:
W = 56J
Explanation:
in physics, Work is equal to F*s
then
W = 8N*7m
W = 56J
Why pendulum made of invar are used in clock?
Beacuse it is an alloy that is made up of nickel and iron that has low coefficient of thermal expansion.So, the length of the pendulum remains unaffected during changes in temperature.
Your boss at the Cut-Rate Cuckoo Clock Company asks you whatwould happen to the frequency of the angular SHM of the balancewheel if it had the same density and the same coil spring (thus thesame torsion constant), but all the balance wheel dimensions weremade one-third as great to save material.
a)By what factor would the frequency change?
b)Would the frequency increase or decrease by the factor foundin part (a)?
c)By what factor would the torsion constant need to be changedto make the smaller balance wheel oscillate at the originalfrequency?
d)Would the torsion constant need to be increased or decreasedby the factor found in part (c)?
Answer:
a) the factor between the frequencies is f ’/ f₀ = 9
b) the frequency increases f ’= 9 f₀
c) So that the frequency is equal to the initial one k ’= k₀ / 81
d) the torque constant must decrease
Explanation:
This is a simple harmonic motion, like angular velocity
w = [tex]\sqrt{\frac{k}{I} }[/tex]
where k is the torsion constant and I the moment of inertia of the flywheel.
Angular velocity and frequency are related
w = 2π f
we substitute
[tex]f= \frac{1}{2\pi } \sqrt{\frac{k}{I} }[/tex] (1)
We will use the subscript o for the system without change
f = [tex]\frac{1}{2\pi }[/tex] [tex]\sqrt{\frac{k}{I_{o} } }[/tex]
In the problem they indicate that the torsion constant remains constant, therefore we must analyze the moment of inertia, in general the flywheels are circular discs,
I = ½ M R²
Let's find the change when reducing the radius r ’= r / 3
Let's use the density
ρ = m ’/ V’
m ’= ρ V’
disk volume is
V = π r² e
suppose that the thickness is small and does not change, substitute
m ’= ρ π[tex](\frac{r}{3}) ^{2}[/tex] e = 1/9 m
Moment of inertia
I ’= ½ m’ r’²
I ’=[tex]\frac{1}{2}[/tex] [tex]\frac{1}{9}[/tex] m (\frac{r}{3}) ^{2} = 1/81 (½ m r²)
I ’= 1/81 Io
we substitute in equation 1
f ’= [tex]\frac{1}{2\pi }[/tex] \sqrt{\frac{k}{I} }
f ’= \frac{1}{2\pi } \sqrt{\frac{81k}{Io} }
f ’= 9 f₀
Let's analyze the questions
a) the factor between the frequencies is
f ’/ f₀ = 9
b) the frequency increases
f ’= 9 f₀
c) So that the frequency is equal to the initial one
k ’= k₀ / 81
d) the torque constant must decrease
a 0.3 kg arrow is fired from a bow with a kinetic energy of 82.0 J. what is its velocity?
Answer:
When the string of a bow and arrow is pulled from equilibrium, the elastic potential energy in the bow is converted to kinetic energy of the arrow when the string is released.
Kinetic energy of an arrow can be found by using the formula KE=(mv²)/450,240 where m = mass of the arrow in grains and v = velocity of the arrow in fps.
Two factors determine the amount of energy a bow can hold. Its draw weight is the amount of force required to draw the bow. A bow's draw weight increases the farther back you pull the string.
Does a stretched bow and arrow have energy?
An arrow held in a stretched bow also contains this stored energy. Specifically, the bow has elastic potential energy. When the bow is released, the arrow will move. ... When work is done on an object, the work may be converted into either kinetic or potential energy.
Explanation:
A 55 kg boy running at 2.0 m/s jumps onto a 2.0 kg skateboard. Calculate the
final velocity of the boy and the skateboard.
Answer:
The velocity of the boy and the skateboard is 24
ANYONE HELP ME PLEASE!
kinetic energy and potential energy are often considered to be forms of mechanical energy. list three other forms of energy and state a source for each.
Answer:
Kinetic energy is the energy in moving objects or mass. Examples include mechanical energy , electrical energy etc.
What is the latent heat of vaporization for water
When a material in liquid state is given energy, it changes its phase from liquid to vapor; the energy absorbed in this process is called heat of vaporization. The heat of vaporization of water is about 2,260 kJ/kg, which is equal to 40.8 kJ/mol. The vaporization is the opposite process of condensation.
hope this helped <3
Tomas wants to paint his bedroom. He goes to the store and buys two cans of paint.
Which simple machine would make it easier for him to open the cans?
A a lever
B. a pulley
C. an inclined plane
D. a wheel and axle
Answer:
I think the answer is c
Explanation:
I had this problem once
How can you warm up for baseball?
A cyclist travels at 7 m/s and has a mass of 75 kg. Calculate the kinetic energy of the
cyclist.
3,675 )
262.5
1,837.5)
525 )
Answer:
1837.5 JExplanation:
The kinetic energy of an object can be found by using the formula
[tex]k = \frac{1}{2} m {v}^{2} \\ [/tex]
m is the mass
v is the velocity
From the question we have
[tex]k = \frac{1}{2} \times 75 \times {7}^{2} \\ = 37.5 \times 49 \\ = 1837.5[/tex]
We have the final answer as
1837.5 JHope this helps you
Please answer ASAP for 29 points
Answer:
Explanation:
The answer is B. He needs to count backwards. So if it’s 800,700,600, and 500, you might get the answer right.
Wil-E-Coyote drops a bowling ball off a cliff to try to catch the Roadrunner. The cliff is 132m high. how far does it fall in the first 3.0 seconds
What is the tangential velocity of a record player which makes 11 revolutions in 20 seconds?
Answer:
The tangential velocity of a rotating object is:
v = r*w
where r is the radius, and w is the angular velocity.
w = 2*pi*f
where f is the frequency.
We know that the record plater does 11 revolutions in 20 seconds, then it does:
11 rev/20s = 0.55 rev/s = f
then we have:
w = 2*pi*0.55 s^-1 = 2*3.14*0.55 s^-1 = 3.454 s^-1
The radius of a record player is really variable, it is around 10 inches, so i will use r = 10in, which is the rotating part of the record player.
then the tangential velocity is:
v = 10in*3.454 s^-1 = 34.54 in/s
PLSS HELP ASAP
two trains are moving on parallel railways with the same direction. Width of first train is 200meters and
speed 36km/h, second - 400meters speed 108km/h. Find the time, when second train paasses first.
a) 40sec
b) 50sec
c) 60sec
d) 30sec
e) Osec
Answer:d) 30 sec
Explanation:
If the density of water is 1 gram/cm3, this means that the mass of 100 cm3of water should be
Answer:
100 g
Explanation:
Or 0.1 kilograms, just count
If the density of water is 1 g/cm³, the mass of 100cm³ of water should be 100g.
DENSITY:
The density of a substance is its mass in relation to its volume. According to this question, the density of water is 1 g/cm³. This means that for every 1g (mass) of water, there contains 1cm³ (volume) of solvent. Hence, for 100cm³ of water, there should be a mass of 100g of water considering the density of water.Learn more at: https://brainly.com/question/14940265?referrer=searchResults
A kilogram is a unit of mass and when multiplied by meters per second
squared which are the units of acceleration, it yields a derived unit known as a
Answer:
it yields a derived unit known as Newton, which is the unit of Force.
Explanation:
The formula for force is given by Newton's Second Law, which states that whenever an unbalanced force is applied to a body, it produces an acceleration in the body in the direction of force.
[tex]F = ma\\[/tex]
where, F = Force
m = mass
a = acceleration
Now, we substitute the respective S.I units of each quantity in equation:
F = Newton (N)
m = kilogram (kg)
a = acceleration = m/s²
Therefore,
[tex]N = (kg)(m/s^2)[/tex]
So, it is clear from above expression that:
When kilogram is multiplied by meter per second squared, it yields a derived unit known as Newton, which is the unit of Force.
Ans
2075 Set B Q.No. 90 A water reservoir fank of capacity
is situated at a height of 20 m from the water level. W
be the power of an electric motor to be used to fill the
3 hours? Efficiency of motor is 70%.
4. What does the law of gravity state ?
Answer:
every particle attracts every other particle in the universe with a force that is directly proportional to the product of their masses and inversely proportional to the square of the distance between their centers.
Explanation:
Answer: Newton's law of gravitation, states that any particle of matter in the universe attracts any other with a force varying directly as the product of the masses and inversely as the square of the distance between them
Explanation: More of a simple answer is a law stating that any two masses attract each other with a force equal to a constant (called the gravitational constant) multiplied by the product of the two masses and divided by the square of the distance between them.
An object is thrown into the air at 60m/s, straight up. What is its velocity at the highest point?
Explanation:
Whenever an object is at its highest point, the velocity and acceleration of the object is zero.
In which direction does the sun appear to move across the sky
Answer:east
Explanation:Earth rotates or spins toward the east, and that's why the Sun, Moon, planets, and stars all rise in the east and make their way westward across the sky.
Answer:
it rises east and moves west through out the day and sets west
21. For this table of data, how should the y-axis be labeled (with units)?
force applied (N)
2.5
3.2
4.8
5.4
5.5
6.3
7.6
8.2
displacement (m)
10.75
13.76
20.64
23.22
23.65
27.09
32.00
35.26
O displacement
Om
O force applied
O force applied (N)
O displacement (m)
ON
Answer:
The y-axis would be labeled with displacement (m)
Explanation:
The displacement is dependent on the force applied.
Labels should have what you measure and how your units of measure.
The x-axis would be labeleed with force applied (N)
The y-axis would be labeled with displacement (m)
