Answer:
[tex]y = 4.36[/tex]
Explanation:
Let the height of the ladder be L
[tex]L = 10[/tex]
Also:
Let [tex]x = distance\ from\ the\ base\ of\ the\ ladder[/tex]Let [tex]y = height\ of\ the\ base\ of\ the\ ladder[/tex]When the ladder leans against the wall, it forms a triangle and the length of the ladder forms the hypotenuse.
So, we have:
[tex]L^2 = x^2 + y^2[/tex] --- Pythagoras Theorem
When the base is 9ft from the wall, this means that:
[tex]x = 9[/tex]
Substitute 9 for x and 10 for L in [tex]L^2 = x^2 + y^2[/tex]
[tex]10^2 = 9^2 + y^2[/tex]
[tex]100 = 81 + y^2[/tex]
Make [tex]y^2[/tex] the subject
[tex]y^2 = 100 - 81[/tex]
[tex]y^2 = 19[/tex]
Make y the subject
[tex]y = \sqrt{19[/tex]
[tex]y = 4.36[/tex]
Hence, the true distance at that point is approximately 4.36ft
The true statement about the true distance between the top of the ladder and the ground when the base is 9 feets from the wall is - 9/√19
Let :
x = distance from base of ladder y = Length of ladderLadder forms a right angle triangle as it leans against the wall :
Hence, we have :
Opposite² + Adjacent² = hypotenus²x² + y² = 100Taking the implicit derivative of both sides:
2xdx/dt + 2ydy/dt = 0
xdx/dt + ydy/dt = 0
ydy/dt = - xdx/dt
dy/dt = (-xdx/dt) / y
When the ladder is 9 ft from the wall;
x = 981 + y² = 100
y² = 100 - 81 = 19
y = √19
Substituting into the equation :
dy/dt = -9(1)/√19
Hence, dy/dt = - 9/√19
Learn more : https://brainly.com/question/13511183
What causes us to see different phases of the moon?
Answer:
The phases of the moon are determined by its position in its orbit around the Earth and the Sun. The phases occur because, as the moon orbits the Earth, we see values on the side of the moon illuminated by the sun.
hope it helps!
The phases of the moon are determined by its position in its orbit around the Earth and the Sun. The phases occur because, as the moon orbits the Earth, we see values on the side of the moon illuminated by the sun.
What is moon illumination?
This is due to the fact that the moon is actually only partially lighted, having already reached its full brilliance.
The moon will be in the "Third quarter" phase if it is highest in the sky at sunrise.
This is due to the fact that the moon will rise at this position at midnight, reaching its maximum peak just before daybreak. This is because the moon is lighted more than its half illumination even though it is moving toward becoming the new moon at this position.
The phases of the moon are determined by its position in its orbit around the Earth and the Sun. The phases occur because, as the moon orbits the Earth, we see values on the side of the moon illuminated by the sun.
To learn more about moon illumination refer to the link:
brainly.com/question/20160684
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How many turns should a solenoid of cross-sectional area 3.0×10−2 m2 and length 0.24 m have if its inductance is to be 36 mH ?
Answer:
The number of turns of the solenoid is 478.7 turns.
Explanation:
Given;
area of the solenoid, A = 3.0 x 10⁻² m²
length of the solenoid, l = 0.24 m
inductance of the solenoid, L = 36 mH = 0.036 H
The number of turns of the solenoid is calculated as follows;
[tex]L = \frac{\mu N^2 A}{l} \\\\N^2 = \frac{Ll}{\mu A} \\\\N = \sqrt{\frac{Ll}{\mu A}} \\\\N = \sqrt{\frac{0.036 \ \times \ 0.24}{4\pi \times 10^{-7} \ \times \ 3.0 \times 10^{-2} }}\\\\N = 478.7 \ turns[/tex]
Therefore, the number of turns of the solenoid is 478.7 turns.
In the equation for Newton's 2nd Law
of Motion, F = ma, "a" represents
O area
O acceleration
atomic number
Answer:
In the formula, F = m×a, where a represents acceleration.
Answer:
Force=mass times acceleration
Explanation:
What does it mean to say that an object is opaque?
A. It reflects all visible light.
B. It absorbs all visible light.
C. Light will not transmit through it.
O D. Light will transmit through it.
Answer:another answer is ”a light will not transmit thro it”
Explanation:
Ape.x answers
Suppose an automobile has a kinetic energy
of 2300 J.
When it moves with nine times the speed,
what will be its kinetic energy?
Answer in units of J.
Answer:
[tex]KE_{new}=186300 J[/tex]
Explanation:
Given:
[tex]KE=2300J[/tex] [tex]n=9[/tex]
[tex]v_{new}=n*v_{old}[/tex]
[tex]\frac{KE_{new}}{KE_{old}}=\frac{v^2_{new}}{v^2_{old}}=\frac{(n*v_{old})^2}{v^2_{old}}=n^2[/tex]
[tex]KE_{new}=n^2KE_{old}[/tex]
[tex]KE_{new}=(9)^2(2300)[/tex]
[tex]KE_{new}=186300 J[/tex]
Scientific notation
[tex]KE_{new}= 1.863*10^5 J[/tex]
Hope it helps
If magnet A can pick up 3 steel paperclips and magnet B can pick up 5 paperclips, which one is stronger
Answer:4
Explanation:
The clips are not affected by magnet strength
Violet light has a frequency of 7.26 × 1014 Hz and travels at a speed of 3.00 × 108 m/s.
Answer:
what's the question
........
Find the force between charges of +10.0 C and -50.0 C located 20.0 cm apart.
Answer: SI
Explanation:
A ring of charge with uniform charge density is completely enclosed in a hollow doughnut shape. An exact copy of the ring is completely enclosed in a hollow sphere. What is the ratio of the flux out of the doughnut shape to that of the sphere
Answer:
1:1
Explanation:
the sphere is an exact copy of the ring so the energy flux will be equivalent because they carry the same charge
True or False: A change of 1 pH unit represents a tenfold change in the
acidity of the solution.
Answer:
I was also going to ask same question edited:ok i found its true
How do gamma rays use electromagnetic waves to function....PLS HELP
Answer:
Gamma-rays have the smallest wavelengths and the most energy of any other wave in the electromagnetic spectrum. These waves are generated by radioactive atoms and in nuclear explosions.
Explanation:
Gamma-rays can kill living cells, a fact which medicine uses to its advantage, using gamma-rays to kill cancerous cells.
Hope this helps!
Brain-LIst?
50 Joules of work in 25 seconds. How much power did she use?
P(W) = E(J) / t(s)
50/25=2
a.
100 kg
20.While standing on a frictionless surface, a 100-ke student pushes against a 80-kg student. Which of the
following best describes the motion that will result?
The 80-ke student will accelerate away from the 100-kg
student, while the 100-kg student remains stationary.
b. The 100-kg student will accelerate away from the 80-kg
student, while the 80-kg student remains stationary.
c. Both students will accelerate away from each other, but
the 80-kg student will have a greater acceleration
d. Both students will accelerate away from each other, but
the 100-kg student will have a greater acceleration.
fectiones ace
Answer:
the correct answer is c, they will accelerate away from each other at different speeds. the 80kg will go faster due to less mass
A student with arms outstretched stands on a platform that is rotating with a constant angular speed. The student then pulls his arms inward. This will result in
Answer:
an increase in the angular speed due to the conservation of angular momentum principle.
Explanation:
From this question, this student has his arms outstretched and he is standing on a platform which is rotating with a constant angular speed.
When his arms are stretched, his moment of inertia I is increased.
Now as This student pulls his arms inwards, His moment of inertia I is going to decrease
Therefore, through the use of the conservation of angular momentum,
there would be an increase in angular speed.
If a wave is traveling at 200 m/s and it’s wavelength is 0.5 meters , what is the frequency of the wave
Answer:
400 Hz
Explanation:
The frequency of a sound wave is found by the velocity/wavelength. Therefore, f = v/wavelength = (200 m/s)/(0.5 m) = 400 Hz
I hope this helps! :)
A box slides to the right along a horizontal surface which is true about the friction force
It act perpendicular to the surface and is determined by the speed of the box
It is a force in the direction of the motion that allows the box to move
It is a force that is determined by the normal force in the acts in opposition to the direction of motion
It is a force that is determined by the surface area of contact and ask opposite the direction of motion
Answer:
It is a force in the direction of the motion that allows the box to move
Explanation:
which one is it, please help me, I will give brailiest
9. Which of these is equal to 7nm?
O 0.7m
O
0.007m
O 0.000007m
O 0.000000007m
Answer:
o.o7m bb
Explanation:
What single resistor could replace 20 Ω, 30 Ω and 50 Ω resistors which have been joined in series ?
Answer:
sine the resistors are connected in series, we could add the sum and that single value replaces the individual resistors in series. therefore, 100ohm resistor can do.
Fix this problem please.
Answer:
In my knowledge....
Option E.........
Explanation:
I have no doubts it is option E 350N
A plane is flying horizontally with speed
162 m/s at a height 3970 m above the ground,
when a package is dropped from the plane.
2
Neglecting air resistance, when the package hits the ground, the plane will be
1. directly above the package. 2. ahead of the package.
3. behind the package.
Answer:
2. ahead of the package.
Explanation:
Using y' - y = ut - 1/2gt², we find the time, t it takes the package to hit the ground. So, u = initial vertical velocity of package = 0 m/s, y = initial position of package = 3970 m, y' = final position of package = 0 m, g = acceleration due to gravity = 9.8 m/s².
Substituting the variables into the equation, we have
y' - y = ut - 1/2gt²
0 m - 3970 m = 0t - 1/2 × (9.8 m/s²)t²
-3970 m = -(4.9m/s²)t²
t² = -3970 m ÷ -4.9 m/s²
t² = 810.2 s²
t = √810.2 s²
t = 28.5 s
Using v = u' + at, we find the horizontal acceleration of the plane. Since the initial horizontal velocity of the package is that of the plane, u' = 162 m/s, v = 0 m/s since the package stops and t = 28.5 s when the package stops.
So, a = (v - u')/t
a = (0 m/s - 162 m/s)/28.5 s
a = -162 m/s/28.5 s
a = -5.68 m/s²
Using v² = u'² + 2as, we find the horizontal distance ,s where the package stops.
So, s = (v² - u'²)/2a
Substituting the values of the variables, we have
s = ((0 m/s)² - (162 m/s)²)/(2 × -5.68 m/s²)
= - 162 m²/s²/(-11.36 m/s²)
= 14.26 m
The horizontal distance d the plane moves after releasing the package is d = u't = 162 m/s × 28.5 s = 4617 m
Since d = 4617 m > s = 14.26 m, the plane would be ahead of the package when the package hits the ground.
Suppose that you wanted to use either conservation of momentum or conservation of kinetic energy to predict the outcome when a large car collides with a smaller car in a demolition derby. Which of the two quantities would be more appropriate for your calculation? Explain please.
Answer:
Conservation of momentum
Explanation:
Out of the two options given, the more appropriate one is the law of conservation of momentum. This is particularly so because momentum deals with the velocity or speed of the car while considering its mass. So, if a large car is to collide with another car, small one, then the momentum is what is considered. Energy on the other hand is talking about the work that is done, while the momentum considers the mass of the car while it is moving and considering its speed also
1) An object of mass (m=2.0 kg) is given an acceleration given by a=3.0 i +4.0j.
The magnitude of the applied force in (N) is:
By Newton's second law, the net force on the object is
F = m a
F = (2.0 kg) ((3.0 i + 4.0 j ) m/s²)
F = (6.0 i + 8.0 j ) N
which has a magnitude of
F = √((6.0 N)² + (8.0 N)²) = √(100 N²) = 10 N
1. Towards the end of a 400m race, Faisal and Edward are leading and are both running at 6m/s. While Faisal is 72m from the finish line Edward is 100m from the finish line. Realising this and to beat Faisal, Edward decides to accelerate uniformly at 0.2 m/s2 until the end of the race while Faisal keeps on the same constant speed. Does Edward succeed in beating Faisal?
Answer:
no
Explanation:
Faisal will finish the race in ...
(72 m)/(6 m/s) = 12 s
In order to beat Faisal, Edward's average speed in those 12 seconds must exceed ...
(100 m)/(12 s) = 8 1/3 m/s
To achieve that average speed, Edward's acceleration must be ...
(8 1/3 m/s -6 m/s)/(12 s/2) = 7/18 m/s² ≈ 0.3889 m/s²
Accelerating at only 0.2 m/s², Edward will not beat Faisal.
_____
Additional comment
When acceleration is uniform, the average speed is reached halfway through the period of acceleration.
HELP ASAP 100 POINTS NEED ANSWERED ASAP
Answer:
yes
Explanation:
Answer:
Hmm looks tricky
Explanation:
If a wave is traveling at 200 m/s and its wavelength is 0.5 meters, what is the frequency of the
wave?
The frequency of the wave = 400/s
Further explanationGiven
v=200 m/s
λ=0.5 m
Required
The frequency of the wave
Solution
Frequency (f): number of waves in one second
The frequency is inversely proportional to the wavelength
[tex]\tt f=\dfrac{v}{\lambda}\\\\f=\dfrac{200~m/s}{0.5~m}\\\\f=400/s[/tex]
Avi, a gymnast, weighs 40 kg. She is jumping on a trampoline that has a spring constant value of 176,400 StartFraction N over m EndFraction. If she compresses the trampoline 20 cm, how high should she reach? meters
Answer:
9
Explanation:
Answer:
9
Explanation:
Because its right!
In the Compton effect, the wavelength of the scattered photon is __________ the wavelength of the incident photon.
Answer:
he wavelength is different (greater) than the wavelength of the incident photon
Explanation:
The Compton effect is the scattering of a photon by an electron, this process is analyzed using the conservation of momentum, in which we assume that initially the electron is at rest and after the collision it recedes, therefore the energy of the incident photon decreases and consequently its wavelength changes
To complete the sentence we use the wavelength is different (greater) than the wavelength of the incident photon
A train traveling at 27.5 accelerates to 42.4 m s over 75.0 s What is the displacement of the train in this time period A train traveling at 27.5 m/s accelerates to 42.4 m/s over 75.0 s. What is the displacement of the train in this time period
Answer:
The displacement of the train in this time period is 2,616.86 m.
Explanation:
A Uniformly Varied Rectilinear Motion is Rectilinear because the mobile moves in a straight line, Uniformly because of there is a magnitude that remains constant (in this case the acceleration) and Varied because the speed varies, the final speed being different from the initial one.
In other words, a motion is uniformly varied rectilinear when the trajectory of the mobile is a straight line and its speed varies the same amount in each unit of time (the speed is constant and the acceleration is variable).
An independent equation of useful time in this type of movement is:
[tex]vf^{2} =vi^{2} +2*a*d[/tex] Expression A
where:
vf = final velocity vi = initial velocity a = acceleration d = distanceThe equation of velocity as a function of time in this type of movement is:
vf=vi + a*t
So the velocity can be calculated as: [tex]a=\frac{vf-vi}{t}[/tex]
In this case:
vf=42.4 m/svi=27.5 m/st=75 sReplacing in the definition of acceleration: [tex]a=\frac{42.4 m/s-27.5 m/s}{75 s}[/tex]
a=0.199 m/s²
Now, replacing in expression A:
[tex](42.4 m/s)^{2} =(27.5 m/s)^{2} +2*(0.199 m/s^{2}) *d[/tex]
Solving:
[tex]d= \frac{(42.4 m/s)^{2} - (27.5 m/s)^{2} }{2*(0.199 m/s^{2}) }[/tex]
d= 2,616.86 m
The displacement of the train in this time period is 2,616.86 m.
Hey v sauce here massive ti ts here there is many black wholes in space there is one in my A&& as well
