The speed of the approaching smaller fish before lunch is 6m/s.
What is the speed?The entire distance that an object travels in a predetermined amount of time is the definition of speed.
Given that the speed v₁ of big fish is 1 m/s and mass m₁ is 6kg. The mass m₂ of small fish is 1 kg.
Both fish have linear momentum of,
p₁ = m₁v₁ + m₂v₂
Where,
p₁ is the initial linear momentum
v₂ is the speed of the small fish.
Since both fish are traveling in the same direction and v is their ultimate meeting velocity, the final linear momentum will be given as,
p₂ = (m₁ + m₂) v
Linear momentum is held constant hence,
p₁ = p₂
m₁v₁ + m₂v₂ = (m₁ + m₂) v
The fish's final speed will be zero because they stopped moving., so
m₁v₁ + m₂v₂ = 0
v₂ = - m₁v₁/m₂
v₂ = -6×1/1
v₂ = -6
The negative symbol indicates that the tiny fish are swimming against the current.
The speed of the approaching smaller fish before lunch is 6m/s.
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Compare and contrast oxygen-16 and
oxygen-17.
Answer:
oxygen 16 has 8 protons and 8 neutrons, oxygen 17 has 8 protons and 9 neutrons
Explanation:
isotope's number is equal to the sum of its protons and neutrons
Answer:Oxygen 16 is number 16 while oxygen 17 is number 17 and oxygen 16 is also oxygen like oxygen 17.
Explanation: Common Knowledge in my brain....
Now assume that a satellite of mass m is orbiting the earth at a distance r from the center of the earth with speed ve. A satellite of mass 2m is orbiting mars, also at a distance r from the center of mars, with a speed vm. What is the ratio tmte , the time it takes the satellite circling mars to make one revolution divided by the time it takes the satellite orbiting the earth to make one revolution? the mass of the earth is me and the mass of mars is mm.
The ratio of the time it takes the satellite circling mars to make one revolution divided by the time it takes the satellite orbiting the earth to make one revolution is (Rm/Re)^3/2.(Me/Mm)^1/2
The orbital velocity of the satellite is given by,
V = √(GM/R)
Where,
V is orbital velocity,
G is gravitational constant,
M is the mass of planet,
R is the distance from the centre of the planet to the satellite.
According to given condition,
Ve = √(GMe/Re)
Ve it the orbital velocity of earth,
Me is mass of the earth,
Re is the radius of the earth.
Also,
Vm = √(GMm/Rm)
Vm it the orbital velocity of mars,
Mm is mass of the mars,
Rm is the radius of the mars.
We know, time period of revolution,
T = distance/velocity
Time period od revolution of satelite of earth,
Te = 2πRe/√(GMe/Re)
Time period of revolution of satelite of mars,
Tm = 2πRm/√(GMm/Rm)
Now, dividing the time time period of revolution of mars by time period of revolution of earth,
Te/Tm = [2πRe/√(GMe/Re)]/[2πRm/√(GMm/Rm)]
Te/Tm = (Rm/Re)^3/2.(Me/Mm)^1/2
So the final ratio of both the time periods is (Rm/Re)^3/2.(Me/Mm)^1/2.
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Pls help me
I’m stuck I tried searching the internet but it didn’t work
According to the given statement A toy car that initially increases its speed, travels constant speed, and then decreases its speed.
The correct option is B.
Describe speed using an example:Speed, expressed in terms of meters per second, is the rate at which an object's location changes. An item moves one meter in one second, for instance, if it starts at the origin and moves three meters in three seconds. Simple division of time by distance yields the equation for speed.
What is a speed measurement tool?Speedometers are tools that show a car's speed and are frequently paired with odometers, which keep track of the distance driven.
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The complete question is-
A student performs an experiment in which the horizontal position of a toy car is recorded on ticker tape from a device that places dots on the tape in equal time intervals. The series of dots in the figure represents the motion of an object moving from the negative direction to the positive direction along the horizontal direction. The time interval between each recorded dot is 1s. Which of the following experiments could the student have conducted to create the data shown on the ticker tape?
A toy car that initially increases its speed, travels at a constant speed, and then increases its speed again.
B-A toy car that initially increases its speed, travels at a constant speed, and then decreases its speed.
C-A toy car that initially decreases its speed, and then increases its speed.
D-A toy car that initially decreases its speed, travels at a constant speed, and then increases its speed.
During which time interval was the motion fastest? responses 1 h to 2 h 1 h to 2 h 2 h to 3 h 2 h to 3 h 3 h to 4 h 3 h to 4 h 4 h to 5 h
Answer: 1h
Explanation:
if a 3.0 kg toy is moving at 4.0 m/s then what would be kentic energy of the cart is moving twice as faster
It tells us that a toy has a mass of 3.0 kg, with a speed of 4.0 m/s.
We apply the following formula:
Ec = m * v²/2
We replace data and solve:
Ec = 3.0 kg* (4.0 m/s)²
Ec = 3.0 kg* 16 m²/s²/2
Ec = 48 kg * m²/s²/2
Ec = 24 kg * m²/s²
Ec = 24 N * m ========> Joules units
Ec = 24 J
The new cartia of the cart would be of 24 joules.What conditions must be met in order for work to be done?
Check all that apply.
A. The applied force must make the object move.
B. At least part of the applied force must be in the same direction as
the movement of the object.
c. The output force must be greater than the input force.
D. The work must be greater than the momentum. you
Answer: B) force must be in the same direction as movement
Explanation:
what is the magnitude of the acceleration aaa of the chair? what is the magnitude of the normal force fnfnf n acting on the chair? express your answers, separated by a comma, in meters per second squared and newtons to three significant figures.
535.1 Newton Force is the magnitude of the acceleration of the chair.
Fnet=Fp×cos35-F
=164×cos35-91
=43.34 N
a=Fnet/m
=43.34/45
=0.963 m/s^2
FN = mg + Fp×sin35
=45×9.8+164×sin35
=535.1 N
Newton is the abbreviation for the SI unit of absolute force known as newton (N). It is described as the amount of force required to accelerate a kilogram of mass by one meter per second. In the foot pound second system, one newton is equivalent to around 0.2248 pounds of force or 100,000 dyne in the centimeter gram second (CGS) system. The newton was given its name in of Sir Isaac Newton, whose second rule of motion outlines the modifications that a force may cause in a body motion.
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What is the focal length of a concave lens that forms an image with a xi value of -10.0 cm when an object is 35.0 cm from the lens?
Answer:
1 / f = 1 / object + 1 / image = 1 / 35 - 1 / 10 thin lens equation
f = o * i / (o + i)
f = -10 * 35 / (-10 + 35) = -350 / 25 = -14 cm
Johnny is driving North at 42 mph. Then drives west at 37 mph. What is the resultant velocity?
A) 55.9 mph North
B) 5 mph West
C) 55.9 mph Northwest
D) 79 mph Northwest
If Johnny is driving North at 42 miles per hour and drives west at 37 miles per hour, then the resultant velocity would be 55.9 mph north, therefore the correct answer is option A.
What is Velocity?The total displacement covered by any object per unit of time is known as velocity. It depends on the magnitude as well as the direction of the moving object.
As given in the problem Johnny is driving North at 42 mph. Then drives west at 37 mph.
The resultant velocity of the Jhonny = √ ( 42² + 37² )
= 55.97 miles per hour
Thus, the resultant velocity of Jhonny would be 55.9 mph north, therefore the correct answer is option A.
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three different-mass projectiles are launched at different angles of elevation from the top of a building. each particle has the same initial kinetic energy. which particle has the greatest kinetic energy just as it impacts with the ground?
The correct option is b. The one with the lowest mass.
An object's kinetic energy is determined by
k=1/2mv^2
where
m is the object's mass.
v is the object's speed.
The three missiles in this puzzle have varying masses but the same beginning kinetic energy.
The three projectiles will all have the same kinetic energy when they hit the ground because mechanical energy is conserved, assuming there is no air resistance (because the potential energy that they have lost is the same, since they have been launched from the same height, and they reach the same final altitude, the ground).
hence,
K1=k2=k3
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By 1335, mechanical ____ had first appeared in Milan, Italy, and then in other cities.
A) Robots
B) Power
C) Toys
D) Clocks
Mechanical robots had first appeared in Milan, Italy, and then in other cities.
Robots are machines, especially those that can be programmed by computers, that are capable of performing intricate sequences of tasks automatically. A robot can be directed by an internal control system or an external control device. Although some robots are built to resemble humans, most robots are task-performing machines that place a greater focus on bare utility than on expressive aesthetics.Robotics is the area of technology that deals with the development, manufacturing, use, and use of robots as well as the computer systems that control, sense, and process information for them. These technologies deal with automated devices that can replace people in hazardous settings or production processes or that are similar to people in terms of appearance, conduct, or cognition. The field of bio-inspired robotics has benefited from the inspiration of nature found in many of today's robots. Soft robotics, a more recent field of robotics, was also developed by these robots.To know more about robots
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a 7.0 g bullet is fired into a 1.5 kg ballistic pendulum. the bullet emerges from the block with a speed of 200 m/s, and the block rises to a maximum height of 11.7 cm. find the initial speed of the bullet.
the initial speed of the bullet: 520.31 m/sec
using the conservation of linear momentum we write
m1u1 + m2 u2 = m1 v1 + m2v2
where u1 and u2 are the initial velocities of masses m1 and m2\
where v1, and v2 are the final velocities of masses m1 and m2\
hence (.007) (u1) + 1.5(0) = 1.5(v2) + .007(200)
using the energy equation for the block alone we get
mgh = 1/2 m (v2[tex])^2[/tex]
hence 9.8(.0117) =.5 (v2[tex])^2[/tex]
hence v2= 1.494 m/sec
substitute it in 1
we get,
(.007) (u1) + 1.5(0) = 1.5(1.494 ) + .007(200)
u1 =initial speed of the bullet= 520.31 m/sec
What is Speed?The definition of speed can be given as a measure of the distance travelled by an object and the time needed to travel the distance. Simply put, it is a measure of how fast an object is moving, but it does not give direction. If we get direction by speed, it is called "velocity".
Speed can be calculated in science. The speed formula is a formula derived from science and is used to calculate different speeds. The formula for speed is:
[tex]Speed = \frac{Distance}{Time}[/tex]
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If a tenth planet were to be discovered with a sidereal period of 125 years, what would be the radius or the orbit (distance from the Sun)? In your answer you need to have the number in the first blank and the correct abbreviated units in the second blank.
From the computation and the use of the Kepler's law, the period of the orbit is period of the orbit is 25 AU.
What is Kepler's law?The term Kepler's law has to do with the relationship between the relationship between the period of the satellite and the radius of the orbit in which the satellite is found.
According to the Kepler's law, we know that the square of the period of the satellite is directly proportional to the cube of the radius of the orbit. Having said this, we need to find the radius of the orbit and we have been told from the question as we have it above that the period of the satellite that is under consideration is 125 years.
Now;
T^2 = r^3
Given that;
T = period
r = radius of the orbit
Then;
r = T^2/3
r = (125)^2/3
r = 25 Au
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A ball is thrown upward with an initial velocity of 20ft/s.
a ) What is the acceleration of the ball on its way up?
b ) what is the velocity of the ball at the very top of its path?
c) what is the acceleration of the ball on its way down?
Answer: the acceleration is 63737737ey
the velpcoty is is 7-922=2929
the acceleration down is 99102>2929<92
Explanation: because when the ball goes up it has to come down due to gravity, physics, and your very kind and nice mother. I hope this helped you! i bet you will ace this assignment.
line spectra from all regions of the electromagnetic spectrum, including the paschen series of infrared lines for hydrogen, are used by astronomers to identify elements present in the atmospheres of stars. calculate the wavelength of the photon emitted whe
The wavelength of the photon emitted when the hydrogen atom undergoes a transition from n = 5 to n = 3 is 1282 nm.
From the Rydberg's formula;
1/λ = R (1/[tex]n^{2} _{final}[/tex] - 1/[tex]n^{2} _{initial}[/tex])
R = 1.097 ×[tex]10^{7} m^{-1}[/tex]
nfinal = 3
ninitial = 5
Calculating the wavelength of the photon by substituting values, in equation 1/λ = R (1/[tex]n^{2} _{final}[/tex] - 1/[tex]n^{2} _{initial}[/tex]) , we get:
1/λ = 1.096776×[tex]10^{7} m^{-1}[/tex] (1/[tex]3^{2}[/tex] - 1/[tex]5^{2}[/tex])
1/λ = 1.096776×[tex]10^{7} m^{-1}[/tex] (1/9 - 1/25)
λ = 1.282 × [tex]10^{-6}[/tex] m
λ = 1282 nm
Therefore, the wavelength of the photon emitted when the hydrogen atom undergoes a transition from n = 5 to n = 3 is 1282 nm.
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1. A bike takes 9.0 seconds to decelerate to a stop over a distance of 30 meters. How fast was the bike traveling before the biker started to decelerate?
Answer:
Starting speed Vo = 6.7 m/s
Explanation:
Given:
t = 9.0 s
S = 30 m
___________
V₀ - ?
The path is numerically equal to the area of the figure lying under the velocity graph:
S = V₀* t / 2
Starting speed:
V₀ = 2*S / t = 2*30 / 9 ≈ 6.7 m/s
a winter storm that blows cold wind at least 56 km/hr and has falling or blowing snow that reduces visibility to less than 400 m for at least three hours is classified as a(n) blank . multiple choice question.
Wind speeds of above 56 kilometers per hour (35 miles per hour) are common during blizzards. These winds reduce visibility by causing a lot of snow to blow around in the air and close to the ground.
What is Blizzards?A blizzard is a severe snowstorm that lasts for a long time—typically at least three or four hours—and is marked by strong sustained winds and low visibility. When snow is not falling but rather loose snow on the ground is lifted and blasted by strong winds, the weather is called a "ground blizzard." A blizzard, according to the National Weather Service, is a storm with heavy snowfall or snow that is blowing, winds that are greater than 35 mph (56 kph), and visibility that is less than 14 mile (0.4 km) for at least three hours. There is no snow falling during some blizzards, known as ground blizzards.To learn more about Blizzards refer to:
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A force of 30.ON is acted on a block of mass 15.0kg placed on a horizontal surface but the boxdoes not move. Calculate the magnitude of the frictional force between the surfaces when theapplied force is along the horizontal and when it makes angle 60° with the horizontal.
We will have the following:
1. In the first case, we will calculate the normal force:
[tex]N=(15\operatorname{kg}\cdot9.8m/s^2)\Rightarrow N=147N[/tex]Then, we will have that the fricion coefficient will be:
[tex]\mu_f=\frac{30.0N}{147N}\Rightarrow\mu_f=\frac{10}{49}\Rightarrow\mu_f\approx0.20[/tex]So the magnitude of the friccional force when applied horizontally will be of 30.0N.
2. And the magnitude when applied horizontal but the block is on an inclined surface of 60°, we will have that:
[tex]F=(10/49)(15.0\operatorname{kg}\cdot9.8m/s^2)\cos (60)\Rightarrow F=15N[/tex]So, the friction force when the force is applied, is 15N.
after driving a portion of the route, the taptap is fully loaded with a total of 27 people including the driver, with an average mass of 70 kgkg per person. in addition, there are three 15- kgkg goats, five 3- kgkg chickens, and a total of 25 kgkg of bananas on their way to the market. assume that the springs have somehow not yet compressed to their maximum amount. how much are the springs compressed? enter the compression numerically in meters using two significant figures. view available hint(s)
When something, like a spring, is stretched, the added length is referred to as its extension.According to Hooke's law, as long as the limit of proportionality is not crossed, a spring's extension is directly proportionate to the force exerted.
Solve the problem ?
The ends of an extension spring connect to two devices.The hooks and loops on the extension springs store and compress energy.An extension spring delivers return force to connected mechanisms via hooks or loops.The no-load position is where tightly wrapped extension springs normally rest. Total mass refers to the combined weight of the shell, its structural and support equipment, and the heaviest load that may be conveyed.The spring's compression at the specified weight is 0.80cm.
"Your inquiry is incomplete because it appears to be lacking the information below,"
The taptap's spring has a k value of 2.4 104 N/m.
the settings provided;
Each of the 27 people weighs 69 kg.
Each of the three goats weighs 15 kg.
Each of the five hens weighs 3 kg.
The weight of the bananas is 25 kg
The taptap's total mass, which includes every passenger, is computed as;
the people's combined mass is 27 x 70 or 1960 kg.
The goats' combined mass is 3 x 15 =45 kg.
The birds' combined mass is equal to 5 x 3 = 15 kg.
The bananas weigh a total of 25 kilograms
The extension of the spring
= 1960×9.8/2.4×104
= 19208/24000
= 0.80 cm
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Whoever answers asap gets marked Brainliest! A hockey puck with a mass of 0.12 kg is traveling across the ice at a velocity of 150 m/s downfield. What is the momentum of the hockey puck?
P = 18 N
P = 18 kg * m/s
P = 8 * 10 - 4 kg * m/s
M = 18 kg * m/s
Answer:
Explanation:
Momentum = m * v = .12 * 150 = 18 kg m/s
Ida Haitarun is captain of the Varsity cross country team. During the after-school practice on Tuesday, he led the team on the following run from school to a nearby park. From the road, he ran at a 20 degree angle North of East for 8 miles. Determine how far east and how far north they are from where they started.
The displacement of the team is 2.74 miles due east and 7.52 miles due north from where they started.
What is the eastward displacement of the team?
The eastward displacement of Ida Haitarun and his team during the cross country race is calculated by forming a right triangle from the displacement of the team.
The angle of inclination of the displacement is calculated as follows;
θ = 90⁰ - 20⁰ = 70⁰ (above the horizontal)
The eastward displacement is the base of the triangle and it is calculated as follows;
cos θ = base / hypotenuse side
cos 70 = base / 8 miles
base = (8 miles) x (cos 70)
base = 2.74 miles
The northward displacement is calculated as follows;
sin θ = height / hypotenuse side
sin 70 = height / 8 miles
height = (8 miles) x (sin 70)
height = 7.52 miles
Thus, the team is 2.74 miles due east and 7.52 miles due north from where they started.
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What is the equation for calculating the electrical force, Fe1, between two charges?
The equation for calculating the electrical force between two charges is: F = Kq₁q₂ / d²
How to determine the equationConsidering the options given in the question, we can obtain the equation for calculating electrical force as shown.
Coulomb's law states as follow:
F = Kq₁q₂ / d²
Where
F is the electrical force of attraction / repulsion K is the electrical constant q₁ and q₂ are two point charges d is the distance apartWith the above equation, we can easily determine the force between two charges.
For example find the force between two charges of charge 1 C and 2 C which are 1.5 m apart.
We can obtain the force as follow:
Charge 1 (q₁) = 1 CCharge 2 (q₂) = 2 CElectric constant (K) = 9×10⁹ Nm²/C²Distance apart (r) = 1.5 mForce (F) =?F = Kq₁q₂ / d²
F = (9×10⁹ × 1 × 2) / (1.5)²
F = 18×10⁹ / 2.25
F = 8×10⁹ N
Thus, we can see clearly that the equation F = Kq₁q₂ / d² can be use to calculate the force between t two charges.
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a cart with a mass of 2.0 kg is pulled across a level desk by a horizontal foirce of 4.0n. if the coeffiecient of kinetic friciton is 0.12 what is the acceleration of the cart
Answer:
The acceleration of the cart:
a = 0.82 m/s²
Explanation:
Given:
m = 2.0 kg
F = 4.0 N
μ = 0.12
g = 9.8 m/s²
___________
a - ?
Friction force:
Ff = μ·m·g
2 Newton's law:
m·a = F - Ff
The acceleration of the cart:
a = ( F - Ff) /m
a = F/m - (μ·m·g) / m
a = F/m - μ·g
a = 4.0 / 2.0 - 0.12·9.8 ≈ 0.82 m/s²
a lighthouse is located on a small island 5 km away from the nearest point p on a straight shoreline and its light makes seven revolutions per minute. how fast (in km/min) is the beam of light moving along the shoreline when it is 1 km from p? (round your answer to one decimal place.)
188.4 km/min is the beam of light moving along the shoreline.
The lighthouse is 5 km far away from the nearest Point P on a straight shoreline. This is often radius of the encirclement of the beam of light moving at 7 rpm.
At 7 rpm, One Circumference of the sunshine takes 70/7 = 10 seconds 2πr is= 2.π.5 km in 10 seconds or
In one second the beam covers 10π/10 = π km or 3.14 km/s.
Now, if the purpose P is 1 km away from the lighthouse, the Radius is reduced to 1 from 5 km,
Consequently The Angular displacement would remain the identical but the speed would be slower for one circumference i.e. 2πr in 10 seconds.
Or one second= (2π.1)/10
= .628π km
= π/10
= 3.14 km/s
By converting km/s into km/min
The answer will be = 188.4 km/min.
188.4 km/min fast (in km/min) is the beam of light moving along the shoreline when it is 1 km from point P.
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can someone help me !!
Answer: (A)
Explanation: the answer will be A because a force is acting on the block from the right side to the left side and another from the bottom upwards. So the two forces together will make the block move diagonally to the left. There is no force in the opposing direction of these two force. B is wrong as there is no force acting on the left side. C is wrong as there is no force acting downward. D is wrong as there is no force acting to the right and from above
remember that when dealing with collisions in 2-dimensions, momentum is conserved in each dimension. two pucks are sliding on a frictionless tabletop. block a (mass 3.94 kg) is moving to the east ( x direction) at 2.50 m/s. block b (mass 4.73 kg) is moving to the north ( y direction) at 3.00 m/s. assume the system to be both block a and block b. (note: it could be useful to make a drawing of the situation.) what is the x-component of the total momentum of the system before the collision?
The x-component of the total momentum of the system before the collision is 9.850 kgm/s.
P = MV
3.94 x 2.50 m/s = 9.850kgm/s.
The definition of momentum is "mass in motion." Since every item has mass, if it is moving, it must have momentum because its mass is in motion. The amount of motion and the speed of the motion are the two factors that determine how much momentum an item possesses. An object's linear momentum sometimes referred to as translational momentum or simply momentum is the product of its mass and velocity.
It has both a magnitude and a direction, making it a vector quantity. If an item has mass m and velocity v, then it has momentum p. Momentum can be defined as the amount of motion. Quantity may be quantified in this case since an object has momentum if it is traveling and mass.
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to negotiate a flat (unbanked) curve at a faster speed, a driver puts a couple of sand bags in his van aiming to increase the force of friction between the tires and the road. will the sand bags help?
Given the fact that the friction between the van and the road would increase, then the sand bags would help.
What is friction?The term friction has to do with the force that opposes the movement of an object on another. This in a sense implies that the frictional force is a resistive force. It can help to slow an object down and this is why the braking system of a car operates on the principle of friction.
Now, we are told that to negotiate a flat (unbanked) curve at a faster speed, a driver puts a couple of sand bags in his van aiming to increase the force of friction between the tires and the road.
The task is to determine if the sand bags would be of help. We have to note that the sand bags would help to increase the friction between the car and the road so it would definitely be of help.
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a large truck with mass 30m crashes into a small sedan with mass m. if the truck exerts a force f on the sedan, what force will the sedan exert on the truck? f30 f 2f 30f
If the truck exerts a force f on the sedan then Force f will exert on the truck.
According to newtons third law ,"every action have an equal and opposite
reaction".
If truck exerts a Force [tex]F_{ts}[/tex] on sedan then sedan will exert a force [tex]F_{st}[/tex] on truck and [tex]F_{ts}[/tex] = - [tex]F_{st}[/tex]
so, we can say that vehicle experiences a force of same magnitude.
given the truck exerts force on the sedan, so the sedan also exerts Force F on the truck.
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A car of mass 20kg moving with a velocity of 16m/s collide with a pedestrian moving at a velocity of 0.5m/s in the same direction calculate the magnitude of their common velocity if they move together after collision
The magnitude of their common velocity if they move together after collision is 12.9 m/s.
What is the final velocity after collision?
The final velocity after collision is calculated by applying the principle of conservation of linear momentum as shown below.
m₁u₁ + m₂u₂ = v(m₁ + m₂)
where;
m₁ is the mass of the carm₂ is the mass of the pedestrianu₁ is the initial velocity of the caru₂ is the initial velocity of the pedestrianv is the their common velocity after collision(20)(16) + (5)(0.5) = v(20 + 5)
322.5 = 25v
v = 322.5/25
v = 12.9 m/s
Thus, the car and the pedestrian moved together after the collision suggestion an inelastic collision.
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The complete question is below:
A car of mass 20kg moving with a velocity of 16m/s collide with a pedestrian moving at a velocity of 0.5m/s in the same direction calculate the magnitude of their common velocity if they move together after collision if the mass of the pedestrian is 5 kg.
If a car of mass 20 kg with a velocity of 16 m/s collides with a pedestrian, then the magnitude of common velocity, if they move after the collision of masses, is 12.9 m/s.
What is Collision?Any situation in which two or more bodies quickly exert forces on one other is referred to be a collision. The most common usage of the word "collision" relates to instances where two or more objects collide violently, while the scientific usage of the word does not refer to the amount of force involved.
According to the question, the given values are :
Mass of the car, m = 20 kg
The velocity of the car, u₁ = 16 m/s
The velocity of the pedestrian, u₂ = 0.5 m/s.
m₁ u₁ + m₂ u₂ = v (m₁ + m₂)
(20) × (16) + (5) × (0.5) = v(20 + 5)
322.5 = 25 × v
v = 322.5/25
v = 12.9 m/s
Hence, the magnitude of common velocity is 12.9 m/s.
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The complete question is :
A car of mass 20 kg moving with a velocity of 16 m/s collides with a pedestrian moving at a velocity of 0.5 m/s in the same direction, calculate the magnitude of their common velocity if they move together after a collision if the mass of the pedestrian is 5 kg.
Compare and contrast an active solar heating system with a radiator system
There are two types of solar system was there:
Active solar systemPassive solar system.What is solar system?One system that is energies with sunlight. In other words which convert the sun energy in other energy is called solar system. It made with silicon.
What is the difference between an active solar heating system with a radiator system?As we mentions earlier there are two types of solar system was their,
Active solar system.Passive solar system.Active solar system: This system made with silicon bar which excites by absorb the sunlight and excites by it. It can change energy between any energies and help others to grow more. It helps to make machines to make hot water and electricity and many more. It is not cost friendly. The costs for such custom systems range from $3,000 to $10,000 depending on the size of the space.
Passive solar system: This system is very much cost sufficient solar energy generator. This energy displace the extra things like electricity, natural gas, or other systems. It so cost friendly that by installing big windows and tress it can hold energy in day and release energy at night. This is called the radiator system as it radiates energy at night.
According to the discussion, this is the main difference between the an active solar heating system with a radiator system.
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